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  • What Windows app can sort a huge XML file?

    - by Torben Gundtofte-Bruun
    I have some enormous XML-based configuration files, with 125000 lines in them. The problem is that they are auto-generated by the system I use, and "child" tags are in a random order within their respective parent tag. This means that a diff comparison is impossible. I want to recursively sort all tags within a parent tag by the value in name="". Some parent tags only appear once and don't have a name="" parameter; these should be sorted by the tag name itself. Once the files are sorted like this, they can be compared quite easily using normal tools. We are currently using ExamXML which can match unsorted XML files, but it fails because the files are too big. Is there an application that can do this? (Windows much preferred; Linux only as a last resort) I do not want to dive into development or XSLT jobs. I am thinking that someone must have made a simple sorting tool like this already - I just can't find it using Google. Update: With help from this site, I created a small package that I want to share: XML-Sorter_v0.3.zip Update: Follow-up question here.

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  • Login via XDMCP not possible to 12.04 from Squeeze box

    - by Joysn
    Can anybody tell me whats wrong with my 12.04/lightdm/XDMCP setup? i activated X11 remote via tcp and XDMCP on lightdm and restarted lightdm: [SeatDefaults] user-session=ubuntu greeter-session=unity-greeter xserver-allow-tcp=true [XDMCPServer] enabled=true whenever i try to login to the remove lightdm via Xephyr Xephyr -query <remote ip> :10 i get the following trace: SELinux: Disabled on system, not enabling in X server [dix] Could not init font path element /usr/share/fonts/X11/cyrillic, removing from list! Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. *** glibc detected *** Xephyr: free(): corrupted unsorted chunks: 0x08659088 *** ======= Backtrace: ========= /lib/i686/cmov/libc.so.6(+0x6af71)[0xb72b6f71] /lib/i686/cmov/libc.so.6(+0x6c7c8)[0xb72b87c8] /lib/i686/cmov/libc.so.6(cfree+0x6d)[0xb72bb8ad] Xephyr(Xfree+0x21)[0x81ddcd1] Xephyr(SrvXkbResizeKeyType+0x59e)[0x81ca01e] Xephyr[0x81ab8eb] Xephyr[0x81ac8c2] Xephyr[0x8088807] Xephyr[0x807c16a] /lib/i686/cmov/libc.so.6(__libc_start_main+0xe6)[0xb7262ca6] Xephyr[0x8061081] ======= Memory map: ======== 08048000-08204000 r-xp 00000000 fd:00 1148994 /usr/bin/Xephyr 08204000-08210000 rw-p 001bc000 fd:00 1148994 /usr/bin/Xephyr 08210000-08239000 rw-p 00000000 00:00 0 08496000-087ac000 rw-p 00000000 00:00 0 [heap] b5600000-b5621000 rw-p 00000000 00:00 0 b5621000-b5700000 ---p 00000000 00:00 0 b5762000-b588f000 rw-p 00000000 00:00 0 b588f000-b58b3000 r-xp 00000000 fd:00 50040 /usr/lib/libexpat.so.1.5.2 b58b3000-b58b5000 rw-p 00024000 fd:00 50040 /usr/lib/libexpat.so.1.5.2 b58d0000-b5ae4000 r-xp 00000000 fd:00 1212530 /usr/lib/dri/swrast_dri.so b5ae4000-b5ae9000 rw-p 00214000 fd:00 1212530 /usr/lib/dri/swrast_dri.so b5ae9000-b5af8000 rw-p 00000000 00:00 0 b5af8000-b5c24000 rw-s 00000000 00:04 1420132375 /SYSV00000000 (deleted) b5c24000-b5c28000 r-xp 00000000 fd:00 770089 /usr/lib/libXfixes.so.3.1.0 b5c28000-b5c29000 rw-p 00003000 fd:00 770089 /usr/lib/libXfixes.so.3.1.0 b5c29000-b5c31000 r-xp 00000000 fd:00 772923 /usr/lib/libXrender.so.1.3.0 b5c31000-b5c32000 rw-p 00007000 fd:00 772923 /usr/lib/libXrender.so.1.3.0 b5c32000-b5c3a000 r-xp 00000000 fd:00 49913 /usr/lib/libXcursor.so.1.0.2 b5c3a000-b5c3b000 rw-p 00007000 fd:00 49913 /usr/lib/libXcursor.so.1.0.2 b5c3b000-b5c58000 r-xp 00000000 09:02 466930 /lib/libgcc_s.so.1 b5c58000-b5c59000 rw-p 0001c000 09:02 466930 /lib/libgcc_s.so.1 b5c59000-b5c5b000 rw-p 00000000 00:00 0 b5c5b000-b7121000 r-xp 00000000 fd:00 49164 /usr/lib/libnvidia-glcore.so.256.53 b7121000-b7178000 rwxp 014c6000 fd:00 49164 /usr/lib/libnvidia-glcore.so.256.53 b7178000-b7188000 rwxp 00000000 00:00 0 b7188000-b7189000 r-xp 00000000 fd:00 49193 /usr/lib/tls/libnvidia-tls.so.256.53 b7189000-b718a000 rw-p 00000000 fd:00 49193 /usr/lib/tls/libnvidia-tls.so.256.53 b718a000-b718b000 rw-p 00000000 00:00 0 b718b000-b7190000 r-xp 00000000 fd:00 50172 /usr/lib/libfontenc.so.1.0.0 b7190000-b7191000 rw-p 00005000 fd:00 50172 /usr/lib/libfontenc.so.1.0.0 b7191000-b71a1000 r-xp 00000000 09:02 466849 /lib/libbz2.so.1.0.4 b71a1000-b71a2000 rw-p 00010000 09:02 466849 /lib/libbz2.so.1.0.4 b71a2000-b71b5000 r-xp 00000000 fd:00 52002 /usr/lib/libz.so.1.2.3.4 b71b5000-b71b6000 rw-p 00013000 fd:00 52002 /usr/lib/libz.so.1.2.3.4 b71b6000-b722a000 r-xp 00000000 fd:00 51162 /usr/lib/libfreetype.so.6.6.0 b722a000-b722e000 rw-p 00073000 fd:00 51162 /usr/lib/libfreetype.so.6.6.0 b722e000-b7246000 r-xp 00000000 fd:00 49652 /usr/lib/libxcb.so.1.1.0 b7246000-b7247000 rw-p 00017000 fd:00 49652 /usr/lib/libxcb.so.1.1.0 b7247000-b7248000 rw-p 00000000 00:00 0 b7248000-b724b000 r-xp 00000000 fd:00 54148 /usr/lib/libgpg-error.so.0.4.0 b724b000-b724c000 rw-p 00002000 fd:00 54148 /usr/lib/libgpg-error.so.0.4.0 b724c000-b738c000 r-xp 00000000 09:02 467095 /lib/i686/cmov/libc-2.11.3.so

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  • Sort List C# in arbitrary order

    - by Jasper
    I have a C# List I.E. List<Food> x = new List<Food> () ; This list is populated with this class Public class Food { public string id { get; set; } public string idUser { get; set; } public string idType { get; set; } //idType could be Fruit , Meat , Vegetable , Candy public string location { get; set; } } Now i have this unsorted List<Food> list ; which has I.E. 15 elements. There are 8 Vegetable Types , 3 Fruit Types , 1 Meat Types , 1 Candy Types I would sort this so that to have a list ordered in this way : 1° : Food.idType Fruit 2° : Food.idType Vegetables 3° : Food.idType Meat 4° : Food.idType Candy 5° : Food.idType Fruit 6° : Food.idType Vegetables 7° : Food.idType Fruit //Becouse there isnt more Meat so i insert the //next one which is Candy but also this type is empty //so i start from begin : Fruit 8° : Food.idType Vegetables 9° : Food.idType Vegetables // For the same reason of 7° 10 ° Food.idType Vegetables ...... .... .... 15 : Food.idType Vegetables I cant find a rule to do this. Is there a linq or List.Sort instruction which help me to order the list in this way? Update i changed the return value of idType and now return int type instead string so 1=Vegetable , 2=Fruit , 3=Candy 4=Meat

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  • Hibernate: order multiple one-to-many relations

    - by Markos Fragkakis
    I have a search screen, using JSF, JBoss Seam and Hibernate underneath. There are columns for A, B and C, where the relations are as follows: A (1< -- ) B (1< -- ) C A has a List< B and B has a List< C (both relations are one-to-many). The UI table supports ordering by any column (ASC or DESC), so I want the results of the query to be ordered. This is the reason I used Lists in the model. However, I got an exception that Hibernate cannot eagerly fetch multiple bags (it considers both lists to be bags). There is an interesting blog post here, and they identify the following solutions: Use @IndexColumn annotation (there is none in my DB, and what's more, I want the position of results to be determined by the ordering, not by an index column) Fetch lazily (for performance reasons, I need eager fetching) Change List to Set So, I changed the List to Set, which by the way is more correct, model-wise. First, if don't use @OrderBy, the PersistentSet returned by Hibernate wraps a HashSet, which has no ordering. Second, If I do use @OrderBy, the PersistentSet wraps a LinkedHashSet, which is what I would like, but the OrderBy property is hardcoded, so all other ordering I perform through the UI comes after it. I tried again with Sets, and used SortedSet (and its implementation, TreeSet), but I have some issues: I want ordering to take place in the DB, and not in-memory, which is what TreeSet does (either through a Comparator, or through the Comparable interface of the elements). Second, I found that there is the Hibernate annotation @Sort, which has a SortOrder.UNSORTED and you can also set a Comparator. I still haven't managed to make it compile, but I am still not convinced it is what I need. Any advice?

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  • Params order in Foo.new(params[:foo]), need one before the other (Rails)

    - by Jeena
    I have a problem which I don't know how to fix. It has to do with the unsorted params hash. I have a object Reservation which has a virtual time= attribute and a virtual eating_session= attribute when I set the time= I also want to validate it via an external server request. I do that with help of the method times() which makes a lookup on a other server and saves all possible times in the @times variable. The problem now is that the method times() needs the eating_session attribute to find out which times are valid, but rails sometimes calls the times= method first, before there is any eating_session in the Reservation object when I just do @reservation = Reservation.new(params[:reservation]) class ReservationsController < ApplicationController def new @reservation = Reservation.new(params[:reservation]) # ... end end class Reservation < ActiveRecord::Base include SoapClient attr_accessor :date, :time belongs_to :eating_session def time=(time) @time = times.find { |t| t[:time] == time } end def times return @times if defined? @times @times = [] response = call_soap :search_availability { # eating_session is sometimes nil :session_id => eating_session.code, # <- HERE IS THE PROBLEM :dining_date => date } response[:result].each do |result| @times << { :time => "#{DateTime.parse(result[:time]).strftime("%H:%M")}", :correlation_data => result[:correlation_data] } end @times end end I have no idea how to fix this, any help is apriciated.

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  • how to fix: ctags null expansion of name pattern "\1"

    - by bua
    Hi, As the title points I have problem with ctags when trying to parse user-defined language. Basically I've followed those instructions. The quickest and easiest way to do this is by defining a new language using the program options. In order to have Swine support available every time I start ctags, I will place the following lines into the file $HOME/.ctags, which is read in every time ctags starts: --langdef=swine --langmap=swine:.swn --regex-swine=/^def[ \t]*([a-zA-Z0-9_]+)/\1/d,definition/ The first line defines the new language, the second maps a file extension to it, and the third defines a regular expression to identify a language definition and generate a tag file entry for it. I've tried different flags: b,e for regex. My definition of tag is: --regex-q=/^[ \t]*[^[:space:]]*[:space:]*:[:space:]*{/\l/f,function/b When I replace \1 with anything else (ascii caracter set ), It works. the output is: (--regex-q=/^[ \t]*[^[:space:]]*[:space:]*:[:space:]*{/my function name/f,function/b) !_TAG_FILE_FORMAT 2 /extended format; --format=1 will not append ;" to lines/ !_TAG_FILE_SORTED 1 /0=unsorted, 1=sorted, 2=foldcase/ !_TAG_PROGRAM_AUTHOR Darren Hiebert /[email protected]/ !_TAG_PROGRAM_NAME Exuberant Ctags // !_TAG_PROGRAM_URL http://ctags.sourceforge.net /official site/ !_TAG_PROGRAM_VERSION 5.8 // my function name file.q /^.ras.getLocation:{[u]$/;" f my function name file.q /^.a.getResource:{[u; pass]$/;" f my function name file.q /^.a.init:{$/;" f my function name file.q /^.a.kill:{[u; force]$/;" f my function name file.q /^.asdf.status:{[what; u]$/;" f my function name file.q /^.pc:{$/;" f Why \1 doesn't work? (I've tried all 1-9)

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  • average case running time of linear search algorithm

    - by Brahadeesh
    Hi all. I am trying to derive the average case running time for deterministic linear search algorithm. The algorithm searches an element x in an unsorted array A in the order A[1], A[2], A[3]...A[n]. It stops when it finds the element x or proceeds until it reaches the end of the array. I searched on wikipedia and the answer given was (n+1)/(k+1) where k is the number of times x is present in the array. I approached in another way and am getting a different answer. Can anyone please give me the correct proof and also let me know whats wrong with my method? E(T)= 1*P(1) + 2*P(2) + 3*P(3) ....+ n*P(n) where P(i) is the probability that the algorithm runs for 'i' time (i.e. compares 'i' elements). P(i)= (n-i)C(k-1) * (n-k)! / n! Here, (n-i)C(k-1) is (n-i) Choose (k-1). As the algorithm has reached the ith step, the rest of k-1 x's must be in the last n-i elements. Hence (n-i)C(k-i). (n-k)! is the total number of ways of arranging the rest non x numbers, and n! is the total number of ways of arranging the n elements in the array. I am not getting (n+1)/(k+1) on simplifying.

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  • Quickest algorithm for finding sets with high intersection

    - by conradlee
    I have a large number of user IDs (integers), potentially millions. These users all belong to various groups (sets of integers), such that there are on the order of 10 million groups. To simplify my example and get to the essence of it, let's assume that all groups contain 20 user IDs (i.e., all integer sets have a cardinality of 100). I want to find all pairs of integer sets that have an intersection of 15 or greater. Should I compare every pair of sets? (If I keep a data structure that maps userIDs to set membership, this would not be necessary.) What is the quickest way to do this? That is, what should my underlying data structure be for representing the integer sets? Sorted sets, unsorted---can hashing somehow help? And what algorithm should I use to compute set intersection)? I prefer answers that relate C/C++ (especially STL), but also any more general, algorithmic insights are welcome. Update Also, note that I will be running this in parallel in a shared memory environment, so ideas that cleanly extend to a parallel solution are preferred.

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  • Java Bucket Sort on Strings

    - by Michael
    I can't figure out what would be the best way to use Bucket Sort to sort a list of strings that will always be the same length. An algorithm would look like this: For the last character position down to the first: For each word in the list: Place the word into the appropriate bucket by current character For each of the 26 buckets(arraylists) Copy every word back to the list I'm writing in java and I'm using an arraylist for the main list that stores the unsorted strings. The strings will be five characters long each. This is what I started. It just abrubdly stops within the second for loop because I don't know what to do next or if I did the first part right. ArrayList<String> count = new ArrayList<String>(26); for (int i = wordlen; i > 0; i--) { for (int j = 0; i < myList.size(); i++) myList.get(j).charAt(i) } Thanks in advanced.

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  • linq - how to sort a list

    - by Billy Logan
    Hello everyone, I have a linq query that populates a list of designers. since i am using the filters below my sorting is not functioning properly. My question is with the given code below how can i best sort this List after the fact or sort while querying? I have tried to sort the list after the fact using the following script but i receive a compiler error: List<TBLDESIGNER> designers = new List<TBLDESIGNER>(); designers = 'calls my procedure below and comes back with an unsorted list of designers' designers.Sort((x, y) => string.Compare(x.FIRST_NAME, y.LAST_NAME)); Query goes as follows: List<TBLDESIGNER> designer = null; using (SOAE strikeOffContext = new SOAE()) { //Invoke the query designer = AdminDelegates.selectDesignerDesigns.Invoke(strikeOffContext).ByActive(active).ByAdmin(admin).ToList(); } Delegate: public static Func<SOAE, IQueryable<TBLDESIGNER>> selectDesignerDesigns = CompiledQuery.Compile<SOAE, IQueryable<TBLDESIGNER>>( (designer) => from c in designer.TBLDESIGNER.Include("TBLDESIGN") orderby c.FIRST_NAME ascending select c); Filter ByActive: public static IQueryable<TBLDESIGNER> ByActive(this IQueryable<TBLDESIGNER> qry, bool active) { //Return the filtered IQueryable object return from c in qry where c.ACTIVE == active select c; } Filter ByAdmin: public static IQueryable<TBLDESIGNER> ByAdmin(this IQueryable<TBLDESIGNER> qry, bool admin) { //Return the filtered IQueryable object return from c in qry where c.SITE_ADMIN == admin select c; } Thanks in advance, Billy

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  • Natural problems to solve using closures

    - by m.u.sheikh
    I have read quite a few articles on closures, and, embarassingly enough, I still don't understand this concept! Articles explain how to create a closure with a few examples, but I don't see any point in paying much attention to them, as they largely look contrived examples. I am not saying all of them are contrived, just that the ones I found looked contrived, and I dint see how even after understanding them, I will be able to use them. So in order to understand closures, I am looking at a few real problems, that can be solved very naturally using closures. For instance, a natural way to explain recursion to a person could be to explain the computation of n!. It is very natural to understand a problem like computing the factorial of a number using recursion. Similarly, it is almost a no-brainer to find an element in an unsorted array by reading each element, and comparing with the number in question. Also, at a different level, doing Object-oriented programming also makes sense. So I am trying to find a number of problems that could be solved with or without closures, but using closures makes thinking about them and solving them easier. Also, there are two types to closures, where each call to a closure can create a copy of the environment variables, or reference the same variables. So what sort of problems can be solved more naturally in which of the closure implementations?

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  • What are the benefits of `while(condition) { //work }` and `do { //work } while(condition)`?

    - by Shaharyar
    I found myself confronted with an interview question where the goal was to write a sorting algorithm that sorts an array of unsorted int values: int[] unsortedArray = { 9, 6, 3, 1, 5, 8, 4, 2, 7, 0 }; Now I googled and found out that there are so many sorting algorithms out there! Finally I could motivate myself to dig into Bubble Sort because it seemed pretty simple to start with. I read the sample code and came to a solution looking like this: static int[] BubbleSort(ref int[] array) { long lastItemLocation = array.Length - 1; int temp; bool swapped; do { swapped = false; for (int itemLocationCounter = 0; itemLocationCounter < lastItemLocation; itemLocationCounter++) { if (array[itemLocationCounter] > array[itemLocationCounter + 1]) { temp = array[itemLocationCounter]; array[itemLocationCounter] = array[itemLocationCounter + 1]; array[itemLocationCounter + 1] = temp; swapped = true; } } } while (swapped); return array; } I clearly see that this is a situation where the do { //work } while(cond) statement is a great help to be and prevents the use of another helper variable. But is this the only case that this is more useful or do you know any other application where this condition has been used?

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  • Determining if an unordered vector<T> has all unique elements

    - by Hooked
    Profiling my cpu-bound code has suggested I that spend a long time checking to see if a container contains completely unique elements. Assuming that I have some large container of unsorted elements (with < and = defined), I have two ideas on how this might be done: The first using a set: template <class T> bool is_unique(vector<T> X) { set<T> Y(X.begin(), X.end()); return X.size() == Y.size(); } The second looping over the elements: template <class T> bool is_unique2(vector<T> X) { typename vector<T>::iterator i,j; for(i=X.begin();i!=X.end();++i) { for(j=i+1;j!=X.end();++j) { if(*i == *j) return 0; } } return 1; } I've tested them the best I can, and from what I can gather from reading the documentation about STL, the answer is (as usual), it depends. I think that in the first case, if all the elements are unique it is very quick, but if there is a large degeneracy the operation seems to take O(N^2) time. For the nested iterator approach the opposite seems to be true, it is lighting fast if X[0]==X[1] but takes (understandably) O(N^2) time if all the elements are unique. Is there a better way to do this, perhaps a STL algorithm built for this very purpose? If not, are there any suggestions eek out a bit more efficiency?

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  • How to Save data in txt file in MATLAB

    - by Jessy
    I have 3 txt files s1.txt, s2.txt, s3.txt.Each have the same format and number of data.I want to combine only the second column of each of the 3 files into one file. Before I combine the data, I sorted it according to the 1st column: UnSorted file: s1.txt s2.txt s3.txt 1 23 2 33 3 22 4 32 4 32 2 11 5 22 1 10 5 28 2 55 8 11 7 11 Sorted file: s1.txt s2.txt s3.txt 1 23 1 10 2 11 2 55 2 33 3 22 4 32 4 32 5 28 5 22 8 11 7 11 Here is the code I have so far: BaseFile ='s' n=3 fid=fopen('RT.txt','w'); for i=1:n %Open each file consecutively d(i)=fopen([BaseFile num2str(i)'.txt']); %read data from file A=textscan(d(i),'%f%f') a=A{1} b=A{2} ab=[a,b]; %sort the data according to the 1st column B=sortrows(ab,1); %delete the 1st column after being sorted B(:,1)=[] %write to a new file fprintf(fid,'%d\n',B'); %close (d(i)); end fclose(fid); How can I get the output in the new txt file in this format? 23 10 11 55 33 22 32 32 28 22 11 11 instead of this format? 23 55 32 22 10 33 32 11 11 22 28 11

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  • Determing if an unordered vector<T> has all unique elements

    - by Hooked
    Profiling my cpu-bound code has suggested I that spend a long time checking to see if a container contains completely unique elements. Assuming that I have some large container of unsorted elements (with < and = defined), I have two ideas on how this might be done: The first using a set: template <class T> bool is_unique(vector<T> X) { set<T> Y(X.begin(), X.end()); return X.size() == Y.size(); } The second looping over the elements: template <class T> bool is_unique2(vector<T> X) { typename vector<T>::iterator i,j; for(i=X.begin();i!=X.end();++i) { for(j=i+1;j!=X.end();++j) { if(*i == *j) return 0; } } return 1; } I've tested them the best I can, and from what I can gather from reading the documentation about STL, the answer is (as usual), it depends. I think that in the first case, if all the elements are unique it is very quick, but if there is a large degeneracy the operation seems to take O(N^2) time. For the nested iterator approach the opposite seems to be true, it is lighting fast if X[0]==X[1] but takes (understandably) O(N^2) time if all the elements are unique. Is there a better way to do this, perhaps a STL algorithm built for this very purpose? If not, are there any suggestions eek out a bit more efficiency?

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  • find the difference between two very large list

    - by user157195
    I have two large list(could be a hundred million items), the source of each list can be either from a database table or a flat file. both lists are of comparable sizes, both unsorted. I need to find the difference between them. so I have 3 scenarios: 1. List1 is a database table(assume each row simply have one item(key) that is a string), List2 is a large file. 2. Both lists are from 2 db tables. 3. both lists are from two files. in case 2, I plan to use: select a.item from MyTable a where a.item not in (select b.item form MyTable b) this clearly is inefficient, is there a better way? Another approach is: I plan to sort each list, and then walk down both of them to find the diff. If the list is from a file, I have to read it into a db table first, then use db sorting to output the list. Is the run time complexity still O(nlogn) in db sorting? either approach is a pain and seems would be very slow when the list involved has hundreds of millions of items. any suggestions?

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  • c++ quick sort running time

    - by chnet
    I have a question about quick sort algorithm. I implement quick sort algorithm and play it. The elements in initial unsorted array are random numbers chosen from certain range. I find the range of random number effects the running time. For example, the running time for 1, 000, 000 random number chosen from the range (1 - 2000) takes 40 seconds. While it takes 9 seconds if the 1,000,000 number chosen from the range (1 - 10,000). But I do not know how to explain it. In class, we talk about the pivot value can effect the depth of recursion tree. For my implementation, the last value of the array is chosen as pivot value. I do not use randomized scheme to select pivot value. int partition( vector<int> &vec, int p, int r) { int x = vec[r]; int i = (p-1); int j = p; while(1) { if (vec[j] <= x){ i = (i+1); int temp = vec[j]; vec[j] = vec[i]; vec[i] = temp; } j=j+1; if (j==r) break; } int temp = vec[i+1]; vec[i+1] = vec[r]; vec[r] = temp; return i+1; } void quicksort ( vector<int> &vec, int p, int r) { if (p<r){ int q = partition(vec, p, r); quicksort(vec, p, q-1); quicksort(vec, q+1, r); } } void random_generator(int num, int * array) { srand((unsigned)time(0)); int random_integer; for(int index=0; index< num; index++){ random_integer = (rand()%10000)+1; *(array+index) = random_integer; } } int main() { int array_size = 1000000; int input_array[array_size]; random_generator(array_size, input_array); vector<int> vec(input_array, input_array+array_size); clock_t t1, t2; t1 = clock(); quicksort(vec, 0, (array_size - 1)); // call quick sort int length = vec.size(); t2 = clock(); float diff = ((float)t2 - (float)t1); cout << diff << endl; cout << diff/CLOCKS_PER_SEC <<endl; }

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  • iPhone: Tracking/Identifying individual touches

    - by FlorianZ
    I have a quick question regarding tracking touches on the iPhone and I seem to not be able to come to a conclusion on this, so any suggestions / ideas are greatly appreciated: I want to be able to track and identify touches on the iphone, ie. basically every touch has a starting position and a current/moved position. Touches are stored in a std::vector and they shall be removed from the container, once they ended. Their position shall be updated once they move, but I still want to keep track of where they initially started (gesture recognition). I am getting the touches from [event allTouches], thing is, the NSSet is unsorted and I seem not to be able to identify the touches that are already stored in the std::vector and refer to the touches in the NSSet (so I know which ones ended and shall be removed, or have been moved, etc.) Here is my code, which works perfectly with only one finger on the touch screen, of course, but with more than one, I do get unpredictable results... - (void) touchesBegan:(NSSet*)touches withEvent:(UIEvent*)event { [self handleTouches:[event allTouches]]; } - (void) touchesEnded:(NSSet*)touches withEvent:(UIEvent*)event { [self handleTouches:[event allTouches]]; } - (void) touchesMoved:(NSSet*)touches withEvent:(UIEvent*)event { [self handleTouches:[event allTouches]]; } - (void) touchesCancelled:(NSSet*)touches withEvent:(UIEvent*)event { [self handleTouches:[event allTouches]]; } - (void) handleTouches:(NSSet*)allTouches { for(int i = 0; i < (int)[allTouches count]; ++i) { UITouch* touch = [[allTouches allObjects] objectAtIndex:i]; NSTimeInterval timestamp = [touch timestamp]; CGPoint currentLocation = [touch locationInView:self]; CGPoint previousLocation = [touch previousLocationInView:self]; if([touch phase] == UITouchPhaseBegan) { Finger finger; finger.start.x = currentLocation.x; finger.start.y = currentLocation.y; finger.end = finger.start; finger.hasMoved = false; finger.hasEnded = false; touchScreen->AddFinger(finger); } else if([touch phase] == UITouchPhaseEnded || [touch phase] == UITouchPhaseCancelled) { Finger& finger = touchScreen->GetFingerHandle(i); finger.hasEnded = true; } else if([touch phase] == UITouchPhaseMoved) { Finger& finger = touchScreen->GetFingerHandle(i); finger.end.x = currentLocation.x; finger.end.y = currentLocation.y; finger.hasMoved = true; } } touchScreen->RemoveEnded(); } Thanks!

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  • Is there some way to make variables like $a and $b in regard to strict?

    - by Axeman
    In light of Michael Carman's comment, I have decided to rewrite the question. Note that 11 comments appear before this edit, and give credence to Michael's observation that I did not write the question in a way that made it clear what I was asking. Question: What is the standard--or cleanest way--to fake the special status that $a and $b have in regard to strict by simply importing a module? First of all some setup. The following works: #!/bin/perl use strict; print "\$a=$a\n"; print "\$b=$b\n"; If I add one more line: print "\$c=$c\n"; I get an error at compile time, which means that none of my dazzling print code gets to run. If I comment out use strict; it runs fine. Outside of strictures, $a and $b are mainly special in that sort passes the two values to be compared with those names. my @reverse_order = sort { $b <=> $a } @unsorted; Thus the main functional difference about $a and $b--even though Perl "knows their names"--is that you'd better know this when you sort, or use some of the functions in List::Util. It's only when you use strict, that $a and $b become special variables in a whole new way. They are the only variables that strict will pass over without complaining that they are not declared. : Now, I like strict, but it strikes me that if TIMTOWTDI (There is more than one way to do it) is Rule #1 in Perl, this is not very TIMTOWDI. It says that $a and $b are special and that's it. If you want to use variables you don't have to declare $a and $b are your guys. If you want to have three variables by adding $c, suddenly there's a whole other way to do it. Nevermind that in manipulating hashes $k and $v might make more sense: my %starts_upper_1_to_25 = skim { $k =~ m/^\p{IsUpper}/ && ( 1 <= $v && $v <= 25 ) } %my_hash ;` Now, I use and I like strict. But I just want $k and $v to be visible to skim for the most compact syntax. And I'd like it to be visible simply by use Hash::Helper qw<skim>; I'm not asking this question to know how to black-magic it. My "answer" below, should let you know that I know enough Perl to be dangerous. I'm asking if there is a way to make strict accept other variables, or what is the cleanest solution. The answer could well be no. If that's the case, it simply does not seem very TIMTOWTDI.

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  • Week in Geek: New Security Flaw Confirmed for Internet Explorer Edition

    - by Asian Angel
    This week we learned how to use a PC to stay entertained while traveling for the holidays, create quality photo prints with free software, share links between any browser and any smartphone, create perfect Christmas photos using How-To Geek’s 10 best how-to photo guides, and had fun decorating Firefox with a collection of Holiday 2010 Personas themes. Photo by Repoort. Random Geek Links Photo by Asian Angel. Critical 0-Day Flaw Affects All Internet Explorer Versions, Microsoft Warns Microsoft has confirmed a zero-day vulnerability affecting all supported versions of Internet Explorer, including IE8, IE7 and IE6. Note: Article contains link to Microsoft Security Advisory detailing two work-arounds until a security update is released. Hackers targeting human rights, indie media groups Hackers are increasingly hitting the Web sites of human rights and independent media groups in an attempt to silence them, says a new study released this week by Harvard University’s Berkman Center for Internet & Society. OpenBSD: audits give no indication of back doors So far, the analyses of OpenBSD’s crypto and IPSec code have not provided any indication that the system contains back doors for listening to encrypted VPN connections. But the developers have already found two bugs during their current audits. Sophos: Beware Facebook’s new facial-recognition feature Facebook’s new facial recognition software might result in undesirable photos of users being circulated online, warned a security expert, who urged users to keep abreast with the social network’s privacy settings to prevent the abovementioned scenario from becoming a reality. Microsoft withdraws flawed Outlook update Microsoft has withdrawn update KB2412171 for Outlook 2007, released last Patch Tuesday, after a number of user complaints. Skype: Millions still without service Skype was still working to right itself going into the holiday weekend from a major outage that began this past Wednesday. Mozilla improves sync setup and WebGL in Firefox 4 beta 8 Firefox 4.0 beta 8 brings better support for WebGL and introduces an improved setup process for Firefox Sync that simplifies the steps for configuring the synchronization service across multiple devices. Chrome OS the litmus test for cloud The success or failure of Google’s browser-oriented Chrome OS will be the litmus test to decide if the cloud is capable of addressing user needs for content and services, according to a new Ovum report released Monday. FCC Net neutrality rules reach mobile apps The Federal Communications Commission (FCC) finally released its long-expected regulations on Thursday and the related explanations total a whopping 194 pages. One new item that was not previously disclosed: mobile wireless providers can’t block “applications that compete with the provider’s” own voice or video telephony services. KDE and the Document Foundation join Open Invention Network The KDE e.V. and the Document Foundation (TDF) have both joined the Open Invention Network (OIN) as licensees, expanding the organization’s roster of supporters. Report: SEC looks into Hurd’s ousting from HP The scandal surrounding Mark Hurd’s departure from the world’s largest technology company in August has officially drawn attention from the U.S. Securities and Exchange Commission. Report: Google requests delay of new Google TVs Google TV is apparently encountering a bit of static that has resulted in a programming change. Geek Video of the Week This week we have a double dose of geeky video goodness for you with the original Mac vs PC video and the trailer for the sequel. Photo courtesy of Peacer. Mac vs PC Photo courtesy of Peacer. Mac vs PC 2 Trailer Random TinyHacker Links Awesome Tools To Extract Audio From Video Here’s a list of really useful, and free tools to rip audio from videos. Getting Your iPhone Out of Recovery Mode Is your iPhone stuck in recovery mode? This tutorial will help you get it out of that state. Google Shared Spaces Quickly create a shared space and collaborate with friends online. McAfee Internet Security 2011 – Upgrade not worthy of a version change McAfee has released their 2011 version of security products. And as this review details, the upgrades are minimal when compared to their 2010 products. For more information, check out the review. 200 Countries Plotted Hans Rosling’s famous lectures combine enormous quantities of public data with a sport’s commentator’s style to reveal the story of the world’s past, present and future development. Now he explores stats in a way he has never done before – using augmented reality animation. Super User Questions Enjoy looking through this week’s batch of popular questions and answers from Super User. How to restore windows 7 to a known working state every time it boots? Is there an easy way to mass-transfer all files between two computers? Coffee spilled inside computer, damaged hard drive Computer does not boot after ram upgrade Keyboard not detected when trying to install Ubuntu 10.10 How-To Geek Weekly Article Recap Have you had a super busy week while preparing for the holiday weekend? Then here is your chance to get caught up on your reading with our five hottest articles for the week. Ask How-To Geek: Rescuing an Infected PC, Installing Bloat-free iTunes, and Taming a Crazy Trackpad How to Use the Avira Rescue CD to Clean Your Infected PC Eight Geektacular Christmas Projects for Your Day Off VirtualBox 4.0 Rocks Extensions and a Simplified GUI Ask the Readers: How Many Monitors Do You Use with Your Computer? One Year Ago on How-To Geek Here are more great articles from one year ago for you to read and enjoy during the holiday break. Enjoy Distraction-Free Writing with WriteMonkey Shutter is a State of Art Screenshot Tool for Ubuntu Get Hex & RGB Color Codes the Easy Way Find User Scripts for Your Favorite Websites the Easy Way Access Your Unsorted Bookmarks the Easy Way (Firefox) The Geek Note That “wraps” things up for this week and we hope that everyone enjoys the rest of their holiday break! Found a great tip during the break? Then be sure to send it in to us at [email protected]. Photo by ArSiSa7. Latest Features How-To Geek ETC How to Use the Avira Rescue CD to Clean Your Infected PC The Complete List of iPad Tips, Tricks, and Tutorials Is Your Desktop Printer More Expensive Than Printing Services? 20 OS X Keyboard Shortcuts You Might Not Know HTG Explains: Which Linux File System Should You Choose? HTG Explains: Why Does Photo Paper Improve Print Quality? Simon’s Cat Explores the Christmas Tree! [Video] The Outdoor Lights Scene from National Lampoon’s Christmas Vacation [Video] The Famous Home Alone Pizza Delivery Scene [Classic Video] Chronicles of Narnia: The Voyage of the Dawn Treader Theme for Windows 7 Cardinal and Rabbit Sharing a Tree on a Cold Winter Morning Wallpaper An Alternate Star Wars Christmas Special [Video]

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  • CodePlex Daily Summary for Sunday, May 23, 2010

    CodePlex Daily Summary for Sunday, May 23, 2010New ProjectsA2Command: Apple 2 port of CBM-Command (http://cbmcommand.codeplex.com)AgUnit: AgUnit is a plugin for Jetbrains ReSharper (R#) that allows you to run and debug Silverlight unit tests from within Visual Studio.BSonPosh Powershell Module: A collection of useful Powershell functions I have written and collected over the years. It is a Powershell v2 Module composed of mostly scripts.DB Restriker: Simple tool for lookup, parsing, searching some standard databases using wildcards and pattern recognition.Entity Framework Repository & Unit of Work Template: T4 Template for Entity Framework 4 for creating a data access layer using the repository and unit of work patterns. Designed to work well with dep...Fiction Catalog: A catalog project designed to store information about fictional literature.Giving a Presentation: Useful for people doing presentations, this application hides desktop icons, disables screensaver, closes chosen programs when presentation starts,...glueless: Glueless is a local message bus which allows architect to design highly decoupled systems and applications. Glueless is a step beyond dependency i...HtmlCodeIt: Take any code and format it so that it can be viewed properly on a web browser, blog post or website.just testproject :): just have a test!KanbanTaskboard: The aim of the project is to design and implement a functional prototype for visualizing and operating a multi-platform virtual "Kanban Taskboard”Life System: Life SystemOaSys Project: Project Oasys is a project that aims to help solve desertification. Scoring of pingPong Game: Scoring of pingPong GameSilverlight Web Comic: The Silverlight Web Comic makes easier for the people create your own comic with your own pictures o drawings, and add the globes of text like the ...TickSharp: C# Wrapper for http://TickSpot.com RESTful API.Traductor: El Traductor es una aplicación de escritorio para traducción de frases entre distintos idiomas basada en la plataforma Silverlight Out Of Browser y...WatchersNET.SkinObjects.ModulActionsMenu: Displays the Module Actions Menu as a Unsorted CSS Menu.xxfd1r4w96: testingNew ReleasesAgUnit: AgUnit 0.1: Initial release of AgUnit. Copy the extracted files from AgUnit-0.1.zip into the "Bin\Plugins\" folder of your ReSharper installation (default C:...ASP.NET MVC | SCAFFOLD: ASP.NET MVC SCAFFOLD - Beta 1.0: Release versão betaBizTalk Server 2006 Documenter: Documenter_v3.4.0.0: This is the new release of the documenter which has the following highlights Support for 64 bit systems Support for SxS scenarios (so now the sys...CassiniDev - Cassini 3.5/4.0 Developers Edition: CassiniDev 3.5.1 Beta 2- VS 2008 Replacement: The CassiniDev Visual Studio build is a fully compatibly Visual Studio 2008/2010 Development server drop-in replacement with all CassiniDev enhance...CBM-Command: 2010-05-22 Beta: Release Notes - 2010-05-22 BetaNew Features Simple text file viewer. Now when you use SHIFT-RETURN to open a file, it will ask if you want to view...Easy Validation: Documentation: Documentation for easyVal was created and presented at University of Texas at Austin in May of 2010.Entity Framework Repository & Unit of Work Template: 1.0: Initial ReleaseFrotz.NET: FrotzNet 1.0 beta: Many, many changes, including: - Got Adaptive Palette working for graphics - Got undo working - Implemented all zcodes - Added scripting as well as...Giving a Presentation: CTP: This release includes basic extensibility infrastructure and three extensions: hides desktop icons, disables screensaver, closes chosen programs wh...Gov 2.0 Kit: SharePoint 2010 MyPeeps Mysite Accelerators: SharePoint 2010 MyPeeps Mysite Accelerators. Attached are the installation and documentations files.HKGolden Express: HKGoldenExpress (Build 201005221900): New features: (None) Bug fix: Hong Kong special characters now can be posted without encoding problem. Improvements: (None) Other changes: (None) K...Intellibox - A WPF auto complete textbox search control: Beta 2: Updated the namespace of the Intellibox control from "System.Windows.Controls" to "FeserWard.Controls". Empty binding Path properties now work on...MDownloader: MDownloader-0.15.14.59111: Fixed DepositFile provider. Fixed FileFactory provider. Added simple fakeness detector (can check if .rar, .zip, .7z files have valid signature...Mute4: V1: Initial version of Mute4NLog - Advanced .NET Logging: Nightly Build 2010.05.22.003: Changes since the last build:No changes. Unit test results:Passed 191/191 (100%) Passed 191/191 (100%) Passed 214/214 (100%) Passed 216/216 (100%)...NSIS Autorun: NSIS Autorun 0.1.9: This release includes source code, executable binaries and example materials.Silverlight Gantt Chart: Silverlight Gantt Chart 1.3 (SL4): The latest release mainly makes the Gantt Chart useful in Silverlight 4 applications.SqlServerExtensions: V 0.2 beta: V 0.2 Beta release: New features available TrimStart - trim leading characters TrimEnd - trim trailing characters Remove - remove characters f...Traductor: Version 3.1: Nuevo en esta versión: El Traductor ahora permite escoger entre los motores de Microsoft y Google. El Text to Speech is es ahora habilitado por...VCC: Latest build, v2.1.30522.0: Automatic drop of latest buildVDialer Add-In for Outlook 2007 & 2010 - Dial your Vonage phone from Outlook: VDialer Add-In 1.0.3: This release adds new features related to Journal and use of Vonage API Changes in version 1.0.3 Added configurable option to automatically open J...WatchersNET.SkinObjects.ModulActionsMenu: ModulActionsMenu 01.00.00: First Release For Informations How To Install, the Skin Object Read the DocumentationMost Popular ProjectsCodeComment.NETRawrWBFS ManagerAJAX Control ToolkitMicrosoft SQL Server Product Samples: DatabaseSilverlight ToolkitWindows Presentation Foundation (WPF)patterns & practices – Enterprise LibraryPHPExcelMicrosoft SQL Server Community & SamplesMost Active ProjectsRawrpatterns & practices – Enterprise LibraryCaliburn: An Application Framework for WPF and Silverlightpatterns & practices: Windows Azure Security GuidanceCassiniDev - Cassini 3.5/4.0 Developers EditionGMap.NET - Great Maps for Windows Forms & PresentationNB_Store - Free DotNetNuke Ecommerce Catalog ModuleSQL Server PowerShell ExtensionsBlogEngine.NETCodeReview

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  • SortedDictionary and SortedList

    - by Simon Cooper
    Apart from Dictionary<TKey, TValue>, there's two other dictionaries in the BCL - SortedDictionary<TKey, TValue> and SortedList<TKey, TValue>. On the face of it, these two classes do the same thing - provide an IDictionary<TKey, TValue> interface where the iterator returns the items sorted by the key. So what's the difference between them, and when should you use one rather than the other? (as in my previous post, I'll assume you have some basic algorithm & datastructure knowledge) SortedDictionary We'll first cover SortedDictionary. This is implemented as a special sort of binary tree called a red-black tree. Essentially, it's a binary tree that uses various constraints on how the nodes of the tree can be arranged to ensure the tree is always roughly balanced (for more gory algorithmical details, see the wikipedia link above). What I'm concerned about in this post is how the .NET SortedDictionary is actually implemented. In .NET 4, behind the scenes, the actual implementation of the tree is delegated to a SortedSet<KeyValuePair<TKey, TValue>>. One example tree might look like this: Each node in the above tree is stored as a separate SortedSet<T>.Node object (remember, in a SortedDictionary, T is instantiated to KeyValuePair<TKey, TValue>): class Node { public bool IsRed; public T Item; public SortedSet<T>.Node Left; public SortedSet<T>.Node Right; } The SortedSet only stores a reference to the root node; all the data in the tree is accessed by traversing the Left and Right node references until you reach the node you're looking for. Each individual node can be physically stored anywhere in memory; what's important is the relationship between the nodes. This is also why there is no constructor to SortedDictionary or SortedSet that takes an integer representing the capacity; there are no internal arrays that need to be created and resized. This may seen trivial, but it's an important distinction between SortedDictionary and SortedList that I'll cover later on. And that's pretty much it; it's a standard red-black tree. Plenty of webpages and datastructure books cover the algorithms behind the tree itself far better than I could. What's interesting is the comparions between SortedDictionary and SortedList, which I'll cover at the end. As a side point, SortedDictionary has existed in the BCL ever since .NET 2. That means that, all through .NET 2, 3, and 3.5, there has been a bona-fide sorted set class in the BCL (called TreeSet). However, it was internal, so it couldn't be used outside System.dll. Only in .NET 4 was this class exposed as SortedSet. SortedList Whereas SortedDictionary didn't use any backing arrays, SortedList does. It is implemented just as the name suggests; two arrays, one containing the keys, and one the values (I've just used random letters for the values): The items in the keys array are always guarenteed to be stored in sorted order, and the value corresponding to each key is stored in the same index as the key in the values array. In this example, the value for key item 5 is 'z', and for key item 8 is 'm'. Whenever an item is inserted or removed from the SortedList, a binary search is run on the keys array to find the correct index, then all the items in the arrays are shifted to accomodate the new or removed item. For example, if the key 3 was removed, a binary search would be run to find the array index the item was at, then everything above that index would be moved down by one: and then if the key/value pair {7, 'f'} was added, a binary search would be run on the keys to find the index to insert the new item, and everything above that index would be moved up to accomodate the new item: If another item was then added, both arrays would be resized (to a length of 10) before the new item was added to the arrays. As you can see, any insertions or removals in the middle of the list require a proportion of the array contents to be moved; an O(n) operation. However, if the insertion or removal is at the end of the array (ie the largest key), then it's only O(log n); the cost of the binary search to determine it does actually need to be added to the end (excluding the occasional O(n) cost of resizing the arrays to fit more items). As a side effect of using backing arrays, SortedList offers IList Keys and Values views that simply use the backing keys or values arrays, as well as various methods utilising the array index of stored items, which SortedDictionary does not (and cannot) offer. The Comparison So, when should you use one and not the other? Well, here's the important differences: Memory usage SortedDictionary and SortedList have got very different memory profiles. SortedDictionary... has a memory overhead of one object instance, a bool, and two references per item. On 64-bit systems, this adds up to ~40 bytes, not including the stored item and the reference to it from the Node object. stores the items in separate objects that can be spread all over the heap. This helps to keep memory fragmentation low, as the individual node objects can be allocated wherever there's a spare 60 bytes. In contrast, SortedList... has no additional overhead per item (only the reference to it in the array entries), however the backing arrays can be significantly larger than you need; every time the arrays are resized they double in size. That means that if you add 513 items to a SortedList, the backing arrays will each have a length of 1024. To conteract this, the TrimExcess method resizes the arrays back down to the actual size needed, or you can simply assign list.Capacity = list.Count. stores its items in a continuous block in memory. If the list stores thousands of items, this can cause significant problems with Large Object Heap memory fragmentation as the array resizes, which SortedDictionary doesn't have. Performance Operations on a SortedDictionary always have O(log n) performance, regardless of where in the collection you're adding or removing items. In contrast, SortedList has O(n) performance when you're altering the middle of the collection. If you're adding or removing from the end (ie the largest item), then performance is O(log n), same as SortedDictionary (in practice, it will likely be slightly faster, due to the array items all being in the same area in memory, also called locality of reference). So, when should you use one and not the other? As always with these sort of things, there are no hard-and-fast rules. But generally, if you: need to access items using their index within the collection are populating the dictionary all at once from sorted data aren't adding or removing keys once it's populated then use a SortedList. But if you: don't know how many items are going to be in the dictionary are populating the dictionary from random, unsorted data are adding & removing items randomly then use a SortedDictionary. The default (again, there's no definite rules on these sort of things!) should be to use SortedDictionary, unless there's a good reason to use SortedList, due to the bad performance of SortedList when altering the middle of the collection.

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  • Double Linked List Insertion Sorting Bug

    - by house
    Hello, I have implemented an insertion sort in a double link list (highest to lowest) from a file of 10,000 ints, and output to file in reverse order. To my knowledge I have implemented such a program, however I noticed in the ouput file, a single number is out of place. Every other number is in correct order. The number out of place is a repeated number, but the other repeats of this number are in correct order. Its just strange how this number is incorrectly placed. Also the unsorted number is only 6 places out of sync. I have looked through my program for days now with no idea where the problem lies, so I turn to you for help. Below is the code in question, (side note: can my question be deleted by myself? rather my colleges dont thieve my code, if not how can it be deleted?) void DLLIntStorage::insertBefore(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->prev = nodeB->prev; newNode->next = nodeB; newNode->value = inValue; if(nodeB->prev==NULL) { this->front = newNode; } else { nodeB->prev->next = newNode; } nodeB->prev = newNode; } void DLLIntStorage::insertAfter(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->next = nodeB->next; newNode->prev = nodeB; newNode->value = inValue; if(nodeB->next == NULL) { this->back = newNode; } else { nodeB->next->prev = newNode; } nodeB->next = newNode; } void DLLIntStorage::insertFront(int inValue) { node *newNode; if(this->front == NULL) { newNode = new node(); this->front = newNode; this->back = newNode; newNode->prev = NULL; newNode->next = NULL; newNode->value = inValue; } else { insertBefore(inValue, this->front); } } void DLLIntStorage::insertBack(int inValue) { if(this->back == NULL) { insertFront(inValue); } else { insertAfter(inValue, this->back); } } ifstream& operator>> (ifstream &in, DLLIntStorage &obj) { int readInt, counter = 0; while(!in.eof()) { if(counter==dataLength) //stops at 10,000 { break; } in >> readInt; if(obj.front != NULL ) { obj.insertion(readInt); } else { obj.insertBack(readInt); } counter++; } return in; } void DLLIntStorage::insertion(int inValue) { node* temp; temp = this->front; if(temp->value >= inValue) { insertFront(inValue); return; } else { while(temp->next!=NULL && temp!=this->back) { if(temp->value >= inValue) { insertBefore(inValue, temp); return; } temp = temp->next; } } if(temp == this->back) { insertBack(inValue); } } Thankyou for your time.

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  • How can I implement the Gale-Shapley stable marriage algorithm in Perl?

    - by srk
    Problem : We have equal number of men and women.each men has a preference score toward each woman. So do the woman for each man. each of the men and women have certain interests. Based on the interest we calculate the preference scores. So initially we have an input in a file having x columns. First column is the person(men/woman) id. id are nothing but 0.. n numbers.(first half are men and next half woman) the remaining x-1 columns will have the interests. these are integers too. now using this n by x-1 matrix... we have come up with a n by n/2 matrix. the new matrix has all men and woman as their rows and scores for opposite sex in columns. We have to sort the scores in descending order, also we need to know the id of person related to the scores after sorting. So here i wanted to use hash table. once we get the scores we need to make up pairs.. for which we need to follow some rules. My trouble is with the second matrix of n by n/2 that needs to give information of which man/woman has how much preference on a woman/man. I need these scores sorted so that i know who is the first preferred woman/man, 2nd preferred and so on for a man/woman. I hope to get good suggestions on the data structures i use.. I prefer php or perl. Thank you in advance Hey guys this is not an home work. This a little modified version of stable marriage algorithm. I have working solution. I am only working on optimizing my code. more info: It is very similar to stable marriage problem but here we need to calculate the scores based on the interests they share. So i have implemented it as the way you see in the wiki page http://en.wikipedia.org/wiki/Stable_marriage_problem. my problem is not solving the problem. i solved it and can run it. I am just trying to have a better solution. so i am asking suggestions on the type of data structure to use. Conceptually I tried using an array of hashes. where the array index give the person id and the hash in it gives the id's <= score's in sorted manner. I initially start with an array of hashes. now i sort the hashes on values, but i could not store the sorted hashes back in an array.So just stored the keys after sorting and used these to get the values from my initial unsorted hashes. Can we store the hashes after sorting ? Can you suggest a better structure ?

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  • Program is not displaying output correctly

    - by Dave Lee
    My program is suppose to display information from a text file. The text file is here http://pastebin.com/qB6nX2x4 I cant find the problem in my program. I think it has to deal with the looping but im not sure. My program runs correctly but only displays the first line of text. Any help would be appreciated. #include <iostream> #include <string> #include <cstdlib> #include <fstream> using namespace std; int buildArrays(int A[],int B[],int C[]) { int i=0,num; ifstream inFile; inFile.open("candycrush.txt"); if(inFile.fail()) { cout<<"The candycrush.txt input file did not open"<<endl; exit(-1); } while(inFile) { inFile>>num; A[i]=num; inFile>>num; B[i]=num; inFile>>num; C[i]=num; i++; } inFile.close(); return i; } void printArrays( string reportTitle, int levelsArray[], int scoresArray[], int starsArray[], int numberOfLevels ) { cout<<endl; cout<<reportTitle<<endl; cout<<"Levels\tScores\tStars"<<endl; cout<<"---------------------"<<endl; for(int i=0;i<numberOfLevels;i++) { cout<<levelsArray[i]<<"\t"<<scoresArray[i]<<"\t"; for(int j=0;j<starsArray[j];j++) { cout<<"*"; } cout<<endl; } } void sortArrays( int levelsArray[], int scoresArray[], int starsArray[], int numberOfLevels ) { for(int i=0;i<numberOfLevels;i++) { for(int j=0;j<numberOfLevels;j++) { if(levelsArray[i]<levelsArray[j]) { int temp1=levelsArray[i]; int temp2=scoresArray[i]; int temp3=starsArray[i]; levelsArray[i]=levelsArray[j]; scoresArray[i]=scoresArray[j]; starsArray[i]=starsArray[j]; levelsArray[j]=temp1; scoresArray[j]=temp2; starsArray[j]=temp3; } } } } int main() { const int MAX=400; int levelsArray[MAX]; int scoresArray[MAX]; int starsArray[MAX]; int numberOfLevels=buildArrays(levelsArray,scoresArray,starsArray); printArrays( "Candy Crush UNSORTED Report", levelsArray, scoresArray, starsArray, numberOfLevels ); sortArrays( levelsArray, scoresArray, starsArray, numberOfLevels); printArrays( "Candy Crush SORTED Report", levelsArray, scoresArray, starsArray, numberOfLevels ); system("pause"); }

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