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• Multiple SiteMap: entries in robots.txt?

  - by user306942

  I have been searching around using Google but I can't find an answer to this question. A robots.txt file can contain the following line: Sitemap: http://www.mysite.com/sitemapindex.xml but is it possible to specify MULTIPLE sitemap index files in the robots.txt and have the search engines recognize that and crawl ALL of the sitemaps referenced in each sitemap index file? For example, will this work: Sitemap: http://www.mysite.com/sitemapindex1.xml Sitemap: http://www.mysite.com/sitemapindex2.xml Sitemap: http://www.mysite.com/sitemapindex3.xml

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• Limitation for google sitemap.xml file size

  - by Chakrapani

  can any one please let me know the memory limitation(MB) of google sitemap.xml file size.

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• Wrapping Arbitrary XML within XML

  - by Marc C

  I need to embed arbitrary (syntactically valid) XML documents within a wrapper XML document. The embedded documents are to be regarded as mere text, they do not need to be parseable when parsing the wrapper document. I know about the "CDATA trick", but I can't use that if the inner XML document itself contains a CDATA segment, and I need to be able to embed any valid XML document. Any advice on accomplishing this--or working around the CDATA limitation--would be appreciated.

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• Issue with sitemap in GWT

  - by Anusha

  I have an e-commerce website www.beyondtime.in, i have been constantly monitoring the google bot crawling on my website and my webmaster account. Lately, i have found two issues that i have not been able to understand and hence want your help. 1.) The Google Bots have been only crawling www.beyondtime.in/telecom.php this URL of my website, when the URL is not even valid. So, kindly help me understand what needs to be done to let Google crawl other pages of the website as well. 2.) The second question is about the Google Webmaster account, where i've submitted my sitmap with 227 URLs, but out of that only 156 have been indexed. Also none of the images of my website have been indexed by Google. So kindly help me with this as well. Thanks

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• XML Parsing from Non-XML Document

  - by Neel Basu

  in a xml/non-xml File there may exist some XML Block that I need to parse and replace with some other string.. The Scenario is something like this.. Some Text <cnt:use name="abc" call="xyz"> <cnt:param name="x" value="2" /> </cnt:use> Some Text There is no guarantee that the document is a proper XML document. (there may exist some unclosed Tags. or some other common mistakes that a Stupid people can make while typing HTML). so I can't use SAX or DOM. I can't even pass it to XSLT (am I right ?). So Whats the best way to extract the <cnt:*> part from the non-xml Document. and read it then replace with something else.

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• How to transport an XML fragment in an XML Document

  - by mrwayne

  Hi, I'm using an AJAX system on a web application, and for one of the objects i return, it needs to contain an xml fragment. Unfortunately, being AJAX, i'm sending the values back via XML already. So, at the moment, i have something that looks like this (ignoring the fact the tags arent perfect. <Transport> <Message> <Content><[CDATA...] XML Content in here </Cdata></Content> </Message> </Transport> This has worked pretty well for the last few years, however, now the XML content itself needs to contain its own CDATA tags and its causing me grief because you cannot nest CDATA sections. Is there another way to encode the 'XML Content' internally?

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• Programatically determining which node in an XML document caused validation against its XML Schema t

  - by jd1212

  My input is a well-formed XML document and a corresponding XML Schema document. What I would like to do is determine the location within the XML document that causes it to fail validation against the XML Schema document. I could not figure out how to do this using the standard validation approach in Java: SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = schemaFactory.newSchema(... /* the .xsd source */); Validator validator = schema.newValidator(); DocumentBuilderFactory ... DocumentBuilder ... Document document = DocumentBuilder.parse(... /* the .xml source */); try { validator.validate(new DOMSource(document)); ... } catch (SAXParseException e) { ... } I have toyed with the idea of getting at least the line and column number from SAXParseException, but they're always set to -1, -1 on validation error.

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• Free lightweight XML text editor to include with an application

  - by Heinzi

  Our application uses a XML configuation file. I thought that it would be nice to distribute some small, lightweight XML editor with our application that the user can use to edit the config file. Features should be: Small and lightweight (ideally, a small .exe that does not require installation), free, with license terms that permit distributing it with a commercial application, understands XML schemas (auto-completion, show validation errors). Does anyone know of such an editor?

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• Store XML,update record in XML,retrive a specific record in XML stored on BB device

  - by user469999

  I am writing a blackberry application where i want to store the data returned by a web service in my BB device.Earlier i was going to use SQLite for storing the data in mobile but as i googled and also did programming using SQLite and found that some BB devices dont support SQLite library and fail to create the database.Then i decided to keep the data returned by webservice in a XML format on my BB device. I just want to know is there any method or way in blackberry through which i can parse the data stored in xml,update it,or directly access a particular record stored in the xml instead of traversing the whole xml n times and finding the matched record. Please guide me as i am new to storing data in BB device.Is the approach which i am thinking to store data in XML right or shall i use something else Thanks in advance Yogesh Chaudhari

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• Linq to XML - update/alter the nodes of an XML Document

  - by knox

  Hello! If got 2 Questions: 1. I've sarted working around with Linq to XML and i'm wondering if it is possible to change a XML document via Linq. I mean, is there someting like XDocument xmlDoc = XDocument.Load("sample.xml"); update item in xmlDoc.Descendants("item") where (int)item .Attribute("id") == id ... 2. I already know how to create and add a new XMLElement by simply using xmlDoc.Element("items").Add(new XElement(......); but how can i remove a single entry. XML sample data: <items> <item id="1" name="sample1" info="sample1 info" web="" /> <item id="2" name="sample2" info="sample2 info" web="" /> </itmes>

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• Expose DB2 data as XML / Query DB2via XML

  - by Anthony Gatlin

  I have a client who has a sort of data warehouse stored in DB2. For a variety of reasons, the data must remain on this platform. The client is considering implementing an open-source CMS (Drupal) which runs in MySQL. The client needs to be able to execute a bunch of pre-defined queries against the DB2 database from the remote application. Drupal appears to interact well with XML data from other systems. It was suggested that we use something like XML-RPC to execute the queries against DB2. I am very familiar with SQL Server and pretty familiar with MySQL, but I have no experience with DB2 and no understanding of its capabilities or limitations. Is there any way that we can use something like XML, XML-RPC, or even http to initiate queries against a DB2 database? Any ideas are appreciated! Thank you!

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• Update XML element with LINQ to XML in VB.NET

  - by Bayonian

  Hi, I'm trying to update an element in the XML document below: Here's the code: Dim xmldoc As XDocument = XDocument.Load(theXMLSource1) Dim ql As XElement = (From ls In xmldoc.Elements("LabService") _ Where CType(ls.Element("ServiceType"), String).Equals("Scan") _ Select ls.Element("Price")).FirstOrDefault ql.SetValue("23") xmldoc.Save(theXMLSource1) Here's the XML file: <?xml version="1.0" encoding="utf-8"?> <!--Test XML with LINQ to XML--> <LabSerivceInfo> <LabService> <ServiceType>Copy</ServiceType> <Price>1</Price> </LabService> <LabService> <ServiceType>PrintBlackAndWhite</ServiceType> <Price>2</Price> </LabService> </LabSerivceInfo> But, I got this error message: Object reference not set to an instance of an object. Exception Details: System.NullReferenceException: Object reference not set to an instance of an object. Error line:ql.SetValue("23") Can you show me what the problem is? Thank you.

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• Diff 2 large XML files to produce a delta xml file

  - by aniln

  Need to be able to diff 2 large / very large XML files and produce the delta XML file. Also, as this process will be part of a larger automated process on below hardware / OS config. Machine hardware: sun4v OS version: 5.10 Processor type: sparc Hardware: SUNW,SPARC-Enterprise-T5220 Please let me know if there's an installable application on Solaris which can be called as part of a ksh script Example: Run driver_script.ksh Above script will have a line: xml_delta file1.xml file2.xml delta_file.xml where xml_delta is the installable application which produces the delta file after comparing file1.xml and file2.xml

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• Problem with develop of XML Schema based on an existent XML

  - by farhad

  Hello! I have a problem with the validation of this piece of XML: <?xml version="1.0" encoding="UTF-8"?> <i-ching xmlns="http://www.oracolo.it/i-ching"> <predizione> <esagramma nome="Pace"> <trigramma> <yang/><yang/><yang/> </trigramma> <trigramma> <yin/><yin/><yin/> </trigramma> </esagramma> <significato>Questa combinazione preannuncia <enfasi>boh</enfasi>, e forse anche <enfasi>mah, chissa</enfasi>.</significato> </predizione> <predizione> <esagramma nome="Ritorno"> <trigramma> <yang/><yin/> <yin/> </trigramma> <trigramma> <yin/><yin/><yin/> </trigramma> </esagramma> <significato>Si prevede con certezza <enfasi>qualcosa</enfasi>, <enfasi>ma anche <enfasi>no</enfasi></enfasi>.</significato> </predizione> </i-ching> This XML Schema was developed with Russian Dolls technique: <?xml version="1.0" encoding="UTF-8"?> <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.oracolo.it/i-ching" targetNamespace="http://www.oracolo.it/i-ching" > <xsd:element name="i-ching"> <xsd:complexType> <xsd:sequence> <xsd:element name="predizione" minOccurs="0" maxOccurs="64"> <xsd:complexType> <xsd:sequence> <xsd:element name="esagramma"> <xsd:complexType> <!-- vi sono 2 trigrammi --> <xsd:sequence> <xsd:element name="trigramma" minOccurs="2" maxOccurs="2"> <xsd:complexType> <xsd:sequence minOccurs="3" maxOccurs="3"> <xsd:choice> <xsd:element name="yang"/> <xsd:element name="yin"/> </xsd:choice> </xsd:sequence> </xsd:complexType> </xsd:element> </xsd:sequence> <xsd:attribute name="nome" type="xsd:string"/> </xsd:complexType> </xsd:element> <!-- significato: context model misto --> <xsd:element name="significato"> <xsd:complexType mixed="true"> <xsd:sequence> <xsd:element name="enfasi" type="xsd:string" minOccurs="0" maxOccurs="unbounded"/> </xsd:sequence> </xsd:complexType> </xsd:element> </xsd:sequence> </xsd:complexType> </xsd:element> </xsd:sequence> </xsd:complexType> </xsd:element> </xsd:schema> For exercise I have to develop an XML Schema to validate the previous XML. The problem is that oxygen says me this: cvc-complex-type.2.4.a: Invalid content was found starting with element 'predizione'. One of '{predizione}' is expected. Start location: 3:6 End location: 3:16 URL: http://www.w3.org/TR/xmlschema-1/#cvc-complex-type why? is it something wrong with my xml schema? thank you very much

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• Reading php generated XML in flash?

  - by AdonisSMU

  Here is part 1 of our problem (Loading a dynamically generated XML file as PHP in Flash). Now we were able to get Flash to read the XML file, but we can only see the Flash render correctly when tested(test movie) from the actual Flash program. However, when we upload our files online to preview the Flash does not render correctly, missing some vital information(thumbnails, titles, video etc..). Here is a link to the Flash file using a manually created XML file (The Flash renders correctly): http://www.gaban.com/stackoverflow/TEN_xml.html Here is the path to the manually created XML file: http://dev.touchstorm.com/ten_hpn_admin2/client_user2.xml Now here is the link to the Flash file using the PHP generated XML file (Renders incomplete): http://www.gaban.com/stackoverflow/TEN_php.html Path to the PHP generated file (exactly the same as the manually created one): http://dev.touchstorm.com/ten_hpn_admin2/client_user.php?id=2 Additional information: The SWF file exists on Domain 1 The XML & PHP file both exists on Domain 2 And the HTML file with the embed code lies on Domain 3 Wondering if this could be a crossdomain issue? We have one of those files in place on Domain 1 & 2 where we have access too, however for Domain 3 we can't have a crossdomain.xml file there. Here is the PHP code: $xml = new XMLWriter(); $xml->openMemory(); $xml->setIndent(true); $xml->setIndentString("\t"); $xml->startDocument(); $xml->startElement('data'); $xml->startElement('config'); $xml->startElement('hex'); $xml->writeCData('0x' . $widget_profile['background_color']); $xml->endElement(); $xml->startElement('width'); $xml->writeCData($widget_profile['width']); $xml->endElement(); $xml->startElement('height'); $xml->writeCData($widget_profile['height']); $xml->endElement(); $xml->startElement('fullscreen'); $xml->writeCData('false'); $xml->endElement(); $xml->startElement('special'); $xml->writeCData('false'); $xml->endElement(); $xml->startElement('specialName'); $xml->writeCData('Tools & Offers'); $xml->endElement(); $xml->startElement('specialLink'); $xml->writeCData('http://bettycrocker.com'); $xml->endElement(); $xml->startElement('client'); $xml->writeCData($widget_profile['site_url']); $xml->endElement(); $xml->endElement(); if (count($widget_content) > 0) { foreach ($widget_content as $tab) { $xml->startElement('tab'); $xml->writeAttribute('id', $tab['tabname']); if (count($tab['video']) > 0) { foreach ($tab['video'] as $video) { $video_sql = "select VID, flvdoname, title from video where VID='" . $video . "'"; $video_result = $howdini->query($video_sql); if ($video_result->rowCount() > 0) { foreach ($video_result as $video_row) { $video_row['flvdoname'] = substr($video_row['flvdoname'], 35, -4); $xml->startElement('vid'); $xml->writeAttribute('flv', $video_row['flvdoname']); $xml->writeAttribute('thumb', 'http://www.howdini.com/thumb/' . $video_row['VID'] . '.jpg'); $xml->writeAttribute('title', $video_row['title']); $xml->endElement(); } } } } $xml->endElement(); } } $xml->endElement(); $xml->endDocument(); header('Content-Type: text/xml; charset=UTF-8'); echo $xml->flush(); Thanks in advance for any answers! EDIT: I have included the change and now Firebug sees the XML. Now it's just not seeing the swf file but I can see the swf file in other parts of the page.

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• Serializing java objects with respect to xml schema loaded at runtime

  - by kohomologie

  I call an XML document three-layered if its structure is laid out as following: the root element contains some container elements (I'll call them entities), each of them has some simpleType elements inside (I'll call them properties). Something like that: <data> <spaceship> <number>1024</number> <name>KTHX</name> </spaceship> <spaceship> <number>1624</number> <name>LEXX</name> </spaceship> <knife> <length>10</length> </knife> </data> where spaceship is an entity, and number is a property. My problem is stated below: Given schema: an arbitrary xsd file describing a three-layered document, loaded at runtime. xmlDocument: an xml document conforming to the schema. Create A Map<String, Map <String, Object>> containing data from the xmlDocument, where first key corresponds to entity, second key correponds to this entity's property, and the value corresponds to this property's value, after casting it to a proper java type (for example, if the schema sets the property value to be xs:int, then it should be cast to Integer). What is the easiest way to achieve this result with existing libraries? P. S. JAXB is not really an option here. The schema might be arbitrary and unknown at compile-time. Also I wish to avoid an excessive use of reflection (associated with converting the beans to maps). I'm looking for something that would allow me to make the typecasts while xml is being parsed.

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• delete element from xml using LINQ

  - by Shishir

  Hello I've a xml file like: <starting> <start> <site>mushfiq.com</site> <site>mee.con</site> <site>ttttt.co</site> <site>jkjhkhjkh</site> <site>jhkhjkjhkhjkhjkjhkh</site> <site>dasdasdasdasdasdas</site> </start> </starting> Now I need to delete any ... and value will randomly be given from a textbox. Here is my code : XDocument doc = XDocument.Load(@"AddedSites.xml"); var deleteQuery = from r in doc.Descendants("start") where r.Element("site").Value == txt.Text.Trim() select r; foreach (var qry in deleteQuery) { qry.Element("site").Remove(); } doc.Save(@"AddedSites.xml"); If I put the value of first element in the textbox then it can delete it, but if I put any value of element except the first element's value it could not able to delete! I need I'll put any value of any element...as it can be 2nd element or 3rd or 4th and so on.... can anyone help me out? thanks in advanced!

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• Will ranking be affected with a mobile XML sitemap for a mobile site with canonical URLs?

  - by Emil Rasmussen

  We have a site with both a desktop version and a mobile version. Most of the content are the same and both versions have the same URL, but the HTML generated is device specific. Looking at Google's recommendations for smartphone-optimized sites, one could get the impression that the mobile xml sitemap is only for sites with different URLs. Will ranking be affected - negatively or positively - if we add a mobile xml sitemap that effectively will be a duplicate of the desktop sitemap?

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• Will ranking be affected with a mobile XML sitemap for a mobile site with the same URLs as the desktop site?

  - by Emil Rasmussen

  We have a site with both a desktop version and a mobile version. Most of the content are the same and both versions have the same URL, but the HTML generated is device specific. Looking at Google's recommendations for smartphone-optimized sites, one could get the impression that the mobile xml sitemap is only for sites with different URLs. Will ranking be affected - negatively or positively - if we add a mobile xml sitemap that effectively will be a duplicate of the desktop sitemap?

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• Should I submit my RSS feed as Google Sitemap?

  - by Svish

  I currently have no sitemap for a website I'm creating. I do have an RSS feed which includes the N latest updated posts on the site. It doesn't include everything on the site though, just blog posts. Creating a full sitemap would be a bit of a hassle I think. Should I submit the feed instead? Is there a difference between using a regular sitemap and a feed? Is it important to have a sitemap? What happens when you do/don't?

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• Should I include everything in the sitemap or only new content?

  - by Mee

  For a website with dynamic content (new content is constantly being added), should I only include the newest content in the sitemap or should I include everything (with a sitemap index)? What are the best practices for sitemaps esp. for large sites? Also, is there anyway to make google (and other search engines) only crawl the pages in the sitemap? Thanks Update: Also, any idea how stackoverflow handle this? I'd like to know but unfortunately (also understandingly) they have blocked access to their sitemap.

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• Encode double quotes inside XML element using LINQ to XML

  - by davekaro

  I'm parsing a string of XML into an XDocument that looks like this (using XDocument.Parse) <Root> <Item>Here is &quot;Some text&quot;</Item> </Root> Then I manipulate the XML a bit, and I want to send it back out as a string, just like it came in <Root> <Item>Here is &quot;Some text&quot;</Item> <NewItem>Another item</NewItem> </Root> However, what I am getting is <Root> <Item>Here is \"Some text\"</Item> <NewItem>Another item</NewItem> </Root> Notice how the double quotes are now escaped instead of encoded? This happens whether I use ToString(SaveOptions.DisableFormatting); or var stringWriter = new System.IO.StringWriter(); xDoc.Save(stringWriter, SaveOptions.DisableFormatting); var newXml = stringWriter.GetStringBuilder().ToString(); How can I have the double quotes come out as &quot; and not \"? UPDATE: Maybe this can explain it better: var origXml = "<Root><Item>Here is \"Some text&quot;</Item></Root>"; Console.WriteLine(origXml); var xmlDoc = System.Xml.Linq.XDocument.Parse(origXml); var modifiedXml = xmlDoc.ToString(System.Xml.Linq.SaveOptions.DisableFormatting); Console.WriteLine(modifiedXml); the output I get from this is: <Root><Item>Here is "Some text&quot;</Item></Root> <Root><Item>Here is "Some text"</Item></Root> I want the output to be: <Root><Item>Here is "Some text&quot;</Item></Root> <Root><Item>Here is "Some text&quot;</Item></Root>

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• Create XML File Using XML Schema

  - by metdos

  Is there any easy way to create at least a template XML file using XML Schema? My main interest is bounded by C++, but discussions of other programming languages are also welcome.By the way I also use QT framework.

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• Generating XML Documents from XML Schemas in C++

  - by metdos

  Is there any easy way to create at least a template XML file using XML Schema? My main interest is bounded by C++, but discussions of other programming languages are also welcome.By the way I also use QT framework.

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• save xml object so that elements are in sorted order in saved xml file

  - by scot

  Hi , I am saving a xml document object and it is saved in a xml file as shown below . <author name="tom" book="Fun-II"/> <author name="jack" book="Live-I"/> <author name="pete" book="Code-I"/> <author name="jack" book="Live-II"/> <author name="pete" book="Code-II"/> <author name="tom" book="Fun-I"/> instead i want to sort the content in document object so that when i persist the object it is saved by grouping authors then book name as below: <author name="jack" book="Live-I"/> <author name="jack" book="Live-II"/> <author name="pete" book="Code-I"/> <author name="pete" book="Code-II"/> <author name="tom" book="Fun-I"/> <author name="tom" book="Fun-II"/> I use apache xml beans..any ideas on how to achieve this? thanks.

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