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  • 7-zip archive with hard links?

    - by Steven Penny
    I see that tar respects hard links $ ln clonezilla.iso test.iso $ tar cfvvJ archive.tar.xz *.iso -rw-r--r-- Steven 111149056 2012-03-25 07:34 clonezilla.iso hrw-r--r-- Steven 0 2012-03-25 07:34 test.iso link to clonezilla.iso 7-Zip does not do this $ 7z a -mx=9 archive.7z *.iso $ ls -l -rw-r--r-- 1 Steven 212827496 Apr 17 07:40 archive.7z -rw-r--r-- 1 Steven 105073772 Apr 17 07:38 archive.tar.xz Is there a way to make 7-Zip respect hard links? gnu.org/software/tar/manual/html_node/hard-links

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  • Compiling zip component for PHP 5.2.11 in MAMP PRO

    - by Zlatoroh
    Helo I installed MAMP PRO on my Macbook Pro (10.6) some time ago. Now I would like to use zip functions in php. I found that I must add zip.so to my extension folder and edited php.ini. On my computer I have two different versions of PHP one in MAMP folder and other in user/lib which was pre-installed on my system. Now I wish to compile my zip library for MAMP version. I got zip sources for my version of PHP then in terminal called function /Applications/MAMP/bin/php5/bin/phpize so it uses mamp php version ./configure make then I moved compile zip.so to extensions/no-debug-non-zts-20060613. When MAMP is launched it returns this error: [11-Apr-2010 16:33:27] PHP Warning: PHP Startup: zip: Unable to initialize module Module compiled with module API=20090626, debug=0, thread-safety=0 PHP compiled with module API=20060613, debug=0, thread-safety=0 These options need to match in Unknown on line 0 Can some body explain to me how to do this the right way.

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  • Why is lua crashing after extracting zip files?

    - by Brian T Hannan
    I have the following code but it crashes every time it reaches the end of the function, but it successfully extracts all the files and puts them in the right location. require "zip" function ExtractZipAndCopyFiles(zipPath, zipFilename, destinationPath) local zfile, err = zip.open(zipPath .. zipFilename) -- iterate through each file insize the zip file for file in zfile:files() do local currFile, err = zfile:open(file.filename) local currFileContents = currFile:read("*a") -- read entire contents of current file local hBinaryOutput = io.open(destinationPath .. file.filename, "wb") -- write current file inside zip to a file outside zip if(hBinaryOutput)then hBinaryOutput:write(currFileContents) hBinaryOutput:close() end end zfile:close() end -- call the function ExtractZipAndCopyFiles("C:\\Users\\bhannan\\Desktop\\LUA\\", "example.zip", "C:\\Users\\bhannan\\Desktop\\ZipExtractionOutput\\") Why does it crash every time it reaches the end?

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  • Burn 30GB zip file to DVD

    - by Joel Coehoorn
    I have a zip 30GB zip file containing an archive a digital materials available in the school library that I want to burn to dvd. Of course, 30Gb is far too large for a single dvd and the content is already zipped. I'm open to ideas, but leaning towards suggestions that will help me automatically spread the file over multiple dvds, including a simple program to stitch it back together again later.

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  • In cygwin, why is there a lingering file filename.zip in a directory after running rm filename.zip?

    - by jonderry
    In cygwin in windows vista, I tried to remove a few zip files I created from the command line in cygwin. The rm finished without complaining, but there remains entries for these zip files in the directory, that cannot be opened or deleted, either in cygwin or vista. For example, ls -l shows the following after performing the rm: $ ls -l ls: cannot access submission.zip: No such file or directory ls: cannot access otherfile.zip: No such file or directory total 36 ??????????? ? ? ? ? ? submission.zip -rwx------ 1 username None 68 May 4 13:36 makefile ??????????? ? ? ? ? ? otherfile.zip ... What's causing this, and how can I fix it?

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  • 7-Zip Command Line Maximum Compression

    - by Steve Robathan
    I am writing a batch file to compress a folder using various archiving applications. Currently I also use 7-Zip but manually set up the parameters I would like to add 7-zip to my batch The folder concerned has many sub folders and I need to take this into account What is the command line for the following keeping folder structure?: Archive Format=7z Compression Level=Ultra Compression Method=LZMA Dictionary Size=512MB Word Size=273 Solid Archive Many thanks

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  • How do I batch rename a specific file inside multiple zip archives via the command line?

    - by user73469
    I have about 200+ shareware files in zip format that each contain a file called "FILE_ID.DIZ". I need to know how to rename each instance to lowercase "file_id.diz" without doing it manually - I've already gone that route and it's pretty time consuming. That file has to be lowercase because the BBS program I'm using ignores the FILE_ID.DIZ as a description since it is uppercase. If I manually change it to lowercase, the description is imported successfully. I know that rar has a renaming switch, but then I'd have to batch convert all of the zip files to rar, and then back to zip. I'm not ruling that out entirely, but it seems like the long way around to resolving this. I found the man page for "zip_rename", which looks like it might do the trick, but I have no idea how to actually implement it. I refuse to do this on a Windows machine - I just can't and won't do it... it's the principle ;). Anyway, thanks for your time!

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  • java.util.zip - ZipInputStream v.s. ZipFile

    - by lucho
    Hello, community! I have some general questions regarding the java.util.zip library. What we basically do is an import and an export of many small components. Previously these components were imported and exported using a single big file, e.g.: <component-type-a id="1"/> <component-type-a id="2"/> <component-type-a id="N"/> <component-type-b id="1"/> <component-type-b id="2"/> <component-type-b id="N"/> Please note that the order of the components during import is relevant. Now every component should occupy its own file which should be externally versioned, QA-ed, bla, bla. We decided that the output of our export should be a zip file (with all these files in) and the input of our import should be a similar zip file. We do not want to explode the zip in our system. We do not want opening separate streams for each of the small files. My current questions: Q1. May the ZipInputStream guarantee that the zip entries (the little files) will be read in the same order in which they were inserted by our export that uses ZipOutputStream? I assume reading is something like: ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis)); ZipEntry entry; while((entry = zis.getNextEntry()) != null) { //read from zis until available } I know that the central zip directory is put at the end of the zip file but nevertheless the file entries inside have sequential order. I also know that relying on the order is an ugly idea but I just want to have all the facts in mind. Q2. If I use ZipFile (which I prefer) what is the performance impact of calling getInputStream() hundreds of times? Will it be much slower than the ZipInputStream solution? The zip is opened only once and ZipFile is backed by RandomAccessFile - is this correct? I assume reading is something like: ZipFile zipfile = new ZipFile(argv[0]); Enumeration e = zipfile.entries();//TODO: assure the order of the entries while(e.hasMoreElements()) { entry = (ZipEntry) e.nextElement(); is = zipfile.getInputStream(entry)); } Q3. Are the input streams retrieved from the same ZipFile thread safe (e.g. may I read different entries in different threads simultaneously)? Any performance penalties? Thanks for your answers!

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  • Command to zip a directory using a specific directory as the root

    - by Slokun
    I'm writing a PHP script that downloads a series of generated files (using wget) into a directory, and then zips then up, using the zip command. The downloads work perfectly, and the zipping mostly works. I run the command: zip -r /var/www/oraviewer/rgn_download/download/fcst_20100318_0319.zip /var/www/oraviewer/rgn_download/download/fcst_20100318_0319 which yields a zip file with all the downloaded files, but it contains the full /var/www/oraviewer/rgn_download/download/ directories, before reaching the fcst_20100318_0319/ directory. I'm probably just missing a flag, or something small, from the zip command, but how do I get it to use fcst_20100318_0319/ as the root directory?

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  • Zipping increment file names using Zip Utils

    - by Peter
    Hello I've been using "Zip Utils" from http://www.codeproject.com/Articles/7530/Zip-Utils-clean-elegant-simple-C-Win32 to zip files and folders. the easy thing is if the file name is known i just need to do something like this HZIP hz; DWORD writ; hz = CreateZip(_T("filename\\image1.zip"),0); The problem is I get errors when trying to zip files by incrementing file names within a loop int i= 0; for(i=0; i<record; i++) { ZipAdd(hz,_T("doc"+i+1+".kml"), _T("filename\\doc"+i+1+".kml")); }

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  • php,codigniter, upload the zip file problem

    - by user345804
    function upload( &$data = array() ) { $config['upload_path'] = 'system/application/orginalimage/'; $config['allowed_types'] = 'gif|jpg|png|zip'; $config['allowed_type'] = 'application/zip'; $config['allowed_type'] = 'application/x-zip-compressed'; $config['allowed_type'] = 'application/x-compress'; $config['allowed_type'] = 'application/x-compressed'; $config['allowed_type'] = 'application/octet-stream'; $config['allowed_type'] = 'multipart/x-zip'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( $this->upload->do_upload( 'uploadimage')) { $data = $this->upload->data() ; return true ; } return false ; } uploading a zip file is not working help me

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  • 7-Zip many files from different folders?

    - by mafutrct
    I would like to add a large number of files with different names from different folders to a single 7-Zip archive using 7za.exe. This should be simple, but it turned out to be a major pain. I created a file that contains the paths (7za a out.7z @list.txt), but once there are too many (~100) files, it fails. Apparently the content of the argument file is pushed onto the command line buffer [Edit: This was likely a misinformation on my part, either way it was not the reason], which is far too small (the number of files to add is more than one million). Splitting the process up by adding the files one by one is not feasible due to the way 7za works: When adding the next file, it creates a copy of the archive, adds the file to the copy and finally replaces the original. This is terribly slow once the archive gets to a couple 100 MB in size. So far I am using a combination of the two approaches by adding a dozen files each time in a loop, but it is an unreliable hack and still very slow. Is there a better way to do it? I tried to use 7-Zip wrapper DLLs (I'm a C# programmer), but none of them worked reliably and I was repeatedly suggested to just use 7za instead.

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  • How can i zip files in Java and not include files paths

    - by Ignacio
    For example, i want to zip a file stored in /Users/me/Desktop/image.jpg I maded this method: public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){ // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // VER SI HAY QUE CREAR EL ROOT PATH boolean result = (new File(destinationDir)).mkdirs(); String zipFullFilename = destinationDir + "/" + zipFilename ; System.out.println(result); // Create the ZIP file ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename)); // Compress the files for (String filename: sourcesFilenames) { FileInputStream in = new FileInputStream(filename); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filename)); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); return true; } catch (IOException e) { return false; } } But when i extract the file, the unzipped files have the full path. I don't want the full path of each file in the zip i only want the filename. How can i made this?

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  • Windows zip error: Windows cannot complete the extraction. The destination file could not be created

    - by Snake Eyes
    I have a strange error in Windows 7 when I want to execute/open a file inside ZIP archive. I have two files: File1.dwg File2.dwg The archive is not corrupted ( I checked with 7zip utility ) When I double click on the any file inside ZIP (I opened ZIP with Windows Explorer), the error occured: Ok. If I open zip file with 7-zip or WinRAR every file could be opened(executed) without error and the AutoCAD is opened to see the dwg content. Why in Windows ZIP ? What points have I to see to manage/remove this error ? Thank you. UPDATE If I click Extract all from Windows ZIP, the error occured as unspecified error:

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  • How to troubleshoot if a zip file is valid or if it is big file size to be unzipped ?

    - by mireille raad
    Hello , I am trying to unzip a file with the size of 2GB I am getting the following error : unzip CLTE_C_08.zip Archive: CLTE_C_08.zip End-of-central-directory signature not found. Either this file is not a zipfile, or it constitutes one disk of a multi-part archive. In the latter case the central directory and zipfile comment will be found on the last disk(s) of this archive. unzip: cannot find zipfile directory in one of CLTE_C_08.zip or CLTE_C_08.zip.zip, and cannot find CLTE_C_08.zip.ZIP, period. After some googling, some people say that this error is because the file is too big, others say because file is corrupt, others say that it could be a not unix archive. So my question , how to find out if file is valid archive file on my Centos and what is the command/trick to uncompress big files ( if any ) Thanks in advance :)

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  • How to troubleshoot if a zip file is valid or if it is big file size to be unzipped ?

    - by mireille raad
    Hello , I am trying to unzip a file with the size of 2GB I am getting the following error : unzip CLTE_C_08.zip Archive: CLTE_C_08.zip End-of-central-directory signature not found. Either this file is not a zipfile, or it constitutes one disk of a multi-part archive. In the latter case the central directory and zipfile comment will be found on the last disk(s) of this archive. unzip: cannot find zipfile directory in one of CLTE_C_08.zip or CLTE_C_08.zip.zip, and cannot find CLTE_C_08.zip.ZIP, period. After some googling, some people say that this error is because the file is too big, others say because file is corrupt, others say that it could be a not unix archive. So my question , how to find out if file is valid archive file on my Centos and what is the command/trick to uncompress big files ( if any ) Thanks in advance :)

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  • PNGException "crc corruption" when attempting to create ImageIcon objects from ZIP archive

    - by Nathan Strong
    I've got a ZIP file containing a number of PNG images that I am trying to load into my Java application as ImageIcon resources directly from the archive. Here's my code: import java.io.*; import java.util.Enumeration; import java.util.zip.*; import javax.swing.ImageIcon; public class Test { public static void main( String[] args ) { if( args.length == 0 ) { System.out.println("usage: java Test.java file.zip"); return; } File archive = new File( args[0] ); if( !archive.exists() || !archive.canRead() ) { System.err.printf("Unable to find/access %s.\n", archive); return; } try { ZipFile zip = new ZipFile(archive); Enumeration <? extends ZipEntry>e = zip.entries(); while( e.hasMoreElements() ) { ZipEntry entry = (ZipEntry) e.nextElement(); int size = (int) entry.getSize(); int count = (size % 1024 == 0) ? size / 1024 : (size / 1024)+1; int offset = 0; int nread, toRead; byte[] buffer = new byte[size]; for( int i = 0; i < count; i++ ) { offset = 1024*i; toRead = (size-offset > 1024) ? 1024 : size-offset; nread = zip.getInputStream(entry).read(buffer, offset, toRead); } ImageIcon icon = new ImageIcon(buffer); // boom -- why? } zip.close(); } catch( IOException ex ) { System.err.println(ex.getMessage()); } } } The sizes reported by entry.getSize() match the uncompressed size of the PNG files, and I am able to read the data out of the archive without any exceptions, but the creation of the ImageIcon blows up. The stacktrace: sun.awt.image.PNGImageDecoder$PNGException: crc corruption at sun.awt.image.PNGImageDecoder.getChunk(PNGImageDecoder.java:699) at sun.awt.image.PNGImageDecoder.getData(PNGImageDecoder.java:707) at sun.awt.image.PNGImageDecoder.produceImage(PNGImageDecoder.java:234) at sun.awt.image.InputStreamImageSource.doFetch(InputStreamImageSource.java:246) at sun.awt.image.ImageFetcher.fetchloop(ImageFetcher.java:172) at sun.awt.image.ImageFetcher.run(ImageFetcher.java:136) sun.awt.image.PNGImageDecoder$PNGException: crc corruption at sun.awt.image.PNGImageDecoder.getChunk(PNGImageDecoder.java:699) at sun.awt.image.PNGImageDecoder.getData(PNGImageDecoder.java:707) at sun.awt.image.PNGImageDecoder.produceImage(PNGImageDecoder.java:234) at sun.awt.image.InputStreamImageSource.doFetch(InputStreamImageSource.java:246) at sun.awt.image.ImageFetcher.fetchloop(ImageFetcher.java:172) at sun.awt.image.ImageFetcher.run(ImageFetcher.java:136) Can anyone shed some light on it? Google hasn't turned up any useful information.

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  • How recovery zip password using CUDA (GPU) ?

    - by marc
    Welcome, How can i recovery zip password on linux using CUDA (GPU). From 2 day's i'm trying using "fcrackzip" but it's too slow. Few months back i saw some application that can use GPU / CUDA and get large performance boost in compare to CPU. If brute-force using cuda is not possible, please tell me what's the best application for dictionary attack, and where can i find best (largest) dictionary. Regards

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  • Best Secure Encryption for Zip Files via Linux

    - by Daniel
    I want to use highly secure encryption for zipped files via Linux/Ubuntu using a command line terminal, what is the best command line tool to get this job done? zip -e -P PASSWORD file1 file2 file3 file4 Or 7za a file.7z *.txt -pSECRET What encryption is used and how secure is it?

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  • How to crack a password protected zip file.

    - by Shadow Frunchak
    I recently downloaded a piece of software that came in a .ZIP archive, but the .EXE software inside of the archive had a password on it. The website that I would have gotten the password from closed a while ago. Because the executable is password protected it cannot be extracted. I'm on Windows 7 Home Premium, and I use winrar for my archives. So, I guess my question is is it possible to crack a password for a file within an archive without extracting it?

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