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  • unable to catch org.hibernate.StaleObjectStateException while deleting record that doesn't exists in database

    - by JAB
    My application has a delete user option. Now in order to check concurrency condition I tried the following use case opened application in chrome and firefox browser. deleted user in firefox now trying to delete the same user in chrome browser I get exception org.hibernate.StaleObjectStateException .. which is right .. since I am trying to delete an object which doesn't exists. But I am not able to catch this exception try{ getHibernateTemplate().delete(userObj); } catch (StaleObjectStateException e) { e.printStackTrace(); } How do i catch this exception ??

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  • Size of assosiation in Hibernate criteria.

    - by trnl
    Hello guys. I've faced with a problem when querying with Hibernate Criteria in Grails. Take a look: def visitors = Client.withCriteria{ visits{ use ( TimeCategory ) {between('date',date,date+1.month-1)} } sizeGe("visits",params.from) sizeLe("visits",params.to) fetchMode("visits", FM.JOIN) }; I need only those clients, which has number of visits in month between from and to bounds. But now size* restrictions is being applied to all visits. So if client has one visit in this month, and visit in previous month. And if I set from=2, this client will be in result. But it should not be there. Any help is appreciated. Thanks, Vova.

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  • When to use Hibernate?

    - by Ramo
    Hi All, I was asked in an interview this question so I answered with the following: -Better Performance: - Efficient queries. - 1st and 2nd level caching. - Good caching gives better scalability. - Good Database Portability: - Changing the DB is as easy as changing the dialect configuration. - Increased Developer Productivity: - Think only in object terms not in query language terms. But I also feel that systems fall in one of the below categories, and Hibernate may not be suited for all these cases, I'm interested in your thoughts about this, do you agree with me? please let me know when would use HB in the following case and why. Write Only Systems: Read Only Systems: Write Mostly Systems: Read Mostly Systems: Regards Ramo

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  • Hibernate Auto-Increment not working

    - by dharga
    I have a column in my DB that is set with Identity(1,1) and I can't get hibernate annotations to work for it. I get errors when I try to create a new record. In my entity I have the following. @GeneratedValue(strategy=GenerationType.IDENTITY, generator="native") @Column(name="SeqNo", unique=true, nullable=false) BigDecimal seqNo; But when I try to add a new record I get the following error. Cannot insert explicit value for identity column in table 'MemberSelectedOptions' when IDENTITY_INSERT is set to OFF. I don't want to set IDENTIY_INSERT to ON because I want the identity column in the db to manage the values. The SQL that is run is the following; where you can clearly see the insert. insert into dbo.MemberSelectedOptions (OptionStatusCd, EffectiveDate, TermDate, SelectionStatusDate, SysLstUpdtUserId, SysLstTrxDtm, SourceApplication, GroupId, MemberId, OptionId, SeqNo) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) What am I missing?

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  • Hibernate is performing unwanted SELECTs on call to saveOrUpdate

    - by digiarnie
    Let's say I have a House entity which maps to many Person entities. I then load an existing House which has 20 occupants. beginTransaction(); House house = houseDao.find(1L); commitTransaction(); Later in the code, I can then add a new Person to the House: ... List<Person> people = house.getPeople(); people.add(new Person("Dilbert")); .... When I make the call: session.saveOrUpdate(house); Hibernate performs 21 queries: 1 to SELECT the House and 20 to SELECT each existing Person in the House. I'm sure it's a small issue on my part, however, what should I do so that I can add a new Person to the house without having such a heavy hit on the database in this situation? This is all done within the same session.

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  • Querying my JPA provider (Hibernate) for a collection of <Id,Name> of an entity

    - by Ittai
    Hi, I have an entity which looks something like this: Id (PK) Name Other business properties and associations... I have the need for my DAL (JPA with hibernate as provider) to return a list of the entities which correlate to some constraints (or just return them all) but instead of returning the entities themselves I'd like to receive only the Id and the Name properties. I know this can be achieved with HQL/SQL (something like: select id,name from entity where...) but I don't want to go down that road. I was thinking of somehow defining the pair a compositioned part of the entity and thought that might help me but I'm not sure that's "legal" as the Id is the PK. The logic for this scenario is to have a textbox which asynchronously queries the web-service (and through it the DAL) for the relevant entities and once an entity is selected then it is loaded as a whole and shipped to the front-end. Would appreciate any feedback, Ittai

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  • Hibernate inserting into join table

    - by Karl
    I got several entities. Two of them got a many-to-many relation. When I do a bigger operation on these entities it fails with this exception: org.hibernate.exception.ConstraintViolationException: could not insert collection rows: I execute the operation i a @Transactional context. I don't do any explicit flushing i my daos. The flush is triggered by a query. In the queue are 15 elements (all of the same structure). one of them always fails (but it's always a different one (I checked) and always at a different position). Does anybody have a hint for me for what I might do wrong? My Mapping: @ManyToMany(targetEntity = CategoryImpl.class) protected Set<Category> categories = new HashSet<Category>();

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  • Why is hibernate returning a proxy object?

    - by predhme
    I have a service method that returns an object from the database. This method is called from numerous parts of the system. However, one particular method is getting a return type of ObjectClass_$$_javassist_somenumber as the type. Which is throwing things off. I call the service method exactly the same as everywhere else, so why would hibernate return the proxy as opposed to the natural object? I know there are ways to expose the "proxied" object, but I don't feel like I should have to do that. The query is simply hibernateTemplate.find("from User u where u.username = ?", username)

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  • Hibernate - One design problem

    - by Yatendra Goel
    I am learning Hibernate from the tutorial on JBoss website. I have a confusion in a code example located here. There is a Cat class code at 4.1. A simple POJO example. This Cat class has a reference to his mother as private Cat mother; Q1. If the class has an identifier property as id, then wouldn't it be better to store the cat's mother's id instead of cat's mother object. means instead of private Cat mother; wouldn't it be better to have private long motherId; `

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  • Hibernate Many-To-One Foreign Key Default 0

    - by user573648
    I have a table where the the parent object has an optional many-to-one relationship. The problem is that the table is setup to default the fkey column to 0. When selecting, using fetch="join", etc-- the default of 0 on the fkey is being used to try over and over to select from another table for the ID 0. Of course this doesn't exist, but how can I tell Hibernate to treat a value of 0 to be the same as NULL-- to not cycle through 20+ times in fetching a relationship which doesn't exist? <many-to-one name="device" lazy="false" class="Device" not-null="true" access="field" cascade="none" not-found="ignore"> <column name="DEVICEID" default="0" not-null="false"/>

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  • Force Hibernate To Save A Specific POJO

    - by user1695626
    I have some code calling a webservice and it returns an id. I am saving this id in the database using hibernate. I have a filter that opens the session and commits it, rolling back when any exception occurs within the contained code. Since there is no way to get back the id returned by the webservice I would like to save this in the database EVEN if there is an exception that occurred later on in the code. Is there anyway to do this using the same session?

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  • How do I use a custom select statement in Hibernate using the HibernateDaoSupport class

    - by Bill Leeper
    I am trying to write a custom select statement in Hibernate using the getHibernateTemplate() method. I am having problems with the resulting mapping. Example Code: List<User> users = getHibernateTemplate().find("Select user, sysdate as latestPost from User as user"); for (User user : users) { assertNotNull(users.name); } The goal of the above line is to eventually have a join where I get the max(date) of posts made by the user. The problem I am having is that the resulting users list is not a list of User objects and I get a class cast exception. Hopefully that is enough code. It is a greatly simplified version of my problem and a combination of snippets from various parts of my application.

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  • Hibernate Save Parent Only

    - by user239905
    Hi, I'm having an issue with Hibernate 3.2.5, where I have to save only the parent object in a one-to-many relationship. For example, I have a flower A, that can have many details. Firstly I want to save only the flower, and the details will be added later. This process throws an exception: not-null property references a null or transient value: com.juflora.bean.JFlora._floraSetBackref This is my code: JFlora flora = new JFlora(); flora.setTypeId(Integer.parseInt(type)); flora.setDescription(description); flora.setName(name); flora.setImage(image); flora.setFloraDetails(new HashSet()); session.save(flora); session.getTransaction().commit();

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  • Spring / Hibernate project with Tomcat and JQuery.

    - by Tiago
    Hi, I have a Dynamic Web Project that implements Spring and Hibernate using a Tomcat Server (v6). I'm lauching Tomcat with my Eclipse Galileo and I'm not getting any errors in the console but Tomcat is rendering my webpages randomly. The page just keep loading but without displaying anything, there's nothing on the console either. When I go in debug mode, it goes throught the right steps, everything seems alright. When I display the source code on the web browser (Firefox latest build) it shows me the right code that is needed to display the page I called. What am I not getting here? Plus when I stop Tomcat, it renders a part of the page. I'm wondering if JQuery could be the problem? The thing is that it's a collaborative project and that the others managed to run the web application in the most alright way. Please, share your experience with me.

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  • Can I bypass an intermediate object in hibernate

    - by Jherico
    I have top level entities TRACK, MEDIA_GROUP and MEDIA, each with an integer primary key. I also have a join table from TRACK to MEDIA_GROUP which is 1:1 and MEDIA has a FK column into MEDIA_GROUP. I'm trying to find a way in hibernate to map a collection of Media directly into the Track object, bypassing the creation of a MediaGroup object. Basically I want to turn this: TRACK <-> MEDIA_TRACK_MAP <-> MEDIA_GROUP <-> MEDIA into this: TRACK <-> MEDIA_TRACK_MAP <-> MEDIA But the join column between MEDIA_TRACK_MAP and MEDIA isn't the primary key of MEDIA.

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  • How to model a relationship that NHibernate (or Hibernate) doesn’t easily support

    - by MylesRip
    I have a situation in which the ideal relationship, I believe, would involve Value Object Inheritance. This is unfortunately not supported in NHibernate so any solution I come up with will be less than perfect. Let’s say that: “Item” entities have a “Location” that can be in one of multiple different formats. These formats are completely different with no overlapping fields. We will deal with each Location in the format that is provided in the data with no attempt to convert from one format to another. Each Item has exactly one Location. “SpecialItem” is a subtype of Item, however, that is unique in that it has exactly two Locations. “Group” entities aggregate Items. “LocationGroup” is as subtype of Group. LocationGroup also has a single Location that can be in any of the formats as described above. Although I’m interested in Items by Group, I’m also interested in being able to find all items with the same Location, regardless of which group they are in. I apologize for the number of stipulations listed above, but I’m afraid that simplifying it any further wouldn’t really reflect the difficulties of the situation. Here is how the above could be diagrammed: Mapping Dilemma Diagram: (http://www.freeimagehosting.net/uploads/592ad48b1a.jpg) (I tried placing the diagram inline, but Stack Overflow won't allow that until I have accumulated more points. I understand the reasoning behind it, but it is a bit inconvenient for now.) Hmmm... Apparently I can't have multiple links either. :-( Analyzing the above, I make the following observations: I treat Locations polymorphically, referring to the supertype rather than the subtype. Logically, Locations should be “Value Objects” rather than entities since it is meaningless to differentiate between two Location objects that have all the same values. Thus equality between Locations should be based on field comparisons, not identifiers. Also, value objects should be immutable and shared references should not be allowed. Using NHibernate (or Hibernate) one would typically map value objects using the “component” keyword which would cause the fields of the class to be mapped directly into the database table that represents the containing class. Put another way, there would not be a separate “Locations” table in the database (and Locations would therefore have no identifiers). NHibernate (or Hibernate) do not currently support inheritance for value objects. My choices as I see them are: Ignore the fact that Locations should be value objects and map them as entities. This would take care of the inheritance mapping issues since NHibernate supports entity inheritance. The downside is that I then have to deal with aliasing issues. (Meaning that if multiple objects share a reference to the same Location, then changing values for one object’s Location would cause the location to change for other objects that share the reference the same Location record.) I want to avoid this if possible. Another downside is that entities are typically compared by their IDs. This would mean that two Location objects would be considered not equal even if the values of all their fields are the same. This would be invalid and unacceptable from the business perspective. Flatten Locations into a single class so that there are no longer inheritance relationships for Locations. This would allow Locations to be treated as value objects which could easily be handled by using “component” mapping in NHibernate. The downside in this case would be that the domain model becomes weaker, more fragile and less maintainable. Do some “creative” mapping in the hbm files in order to force Location fields to be mapped into the containing entities’ tables without using the “component” keyword. This approach is described by Colin Jack here. My situation is more complicated than the one he describes due to the fact that SpecialItem has a second Location and the fact that a different entity, LocatedGroup, also has Locations. I could probably get it to work, but the mappings would be non-intuitive and therefore hard to understand and maintain by other developers in the future. Also, I suspect that these tricky mappings would likely not be possible using Fluent NHibernate so I would use the advantages of using that tool, at least in that situation. Surely others out there have run into similar situations. I’m hoping someone who has “been there, done that” can share some wisdom. :-) So here’s the question… Which approach should be preferred in this situation? Why?

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  • Hibernate criterion Projection alias not being used

    - by sbzoom
    Do Hibernate Projection aliases even work? I could swear it just doesn't. At least, it doesn't do what I would expect it to do. Here is the java: return sessionFactory.getCurrentSession().createCriteria( PersonProgramActivity.class ).setProjection( Projections.projectionList().add( Projections.alias( Projections.sum( "numberOfPoints" ), "number_of_points" ) ).add( Projections.groupProperty( "person.id" ) ) ).setFirstResult( start ).setFetchSize( size ).addOrder( Order.desc( "numberOfPoints" ) ).list(); Here is the SQL that it generates: select sum(this_.number_of_points) as y0_, this_.person_id as y1_ from PERSON_PROGRAM_ACTIVITY this_ group by this_.person_id order by this_.number_of_points desc It doesn't seem to use the alias at all. I would think setting the alias would mean that "sum(this_.number_of_points)" would be aliased as "number_of_points" and not "y0_". Is there some trick I am missing? Thanks.

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  • how to check if a data exist on a table using hibernate

    - by David
    im using hibernate with my jsp page and mySQL ,how can i do that select * from student wher userName = *** with HQL and how i chek if that username exist in 'Student' table ? in my sql i use that ResultSet resultat = statement.executeQuery(); if (resultat.next()) { ....} i try this Session hibernateSession = MyDB.HibernateUtil.currentSession(); hibernateSession.find("select xxx from Etudinat where p.Nom=xxxx"); thats give an exception so how can i do that ? i have a login form send me a username and password i want to chek if that username exist in the table Student to set the user on a session what is the safty way to do that

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  • Noob question about hibernate criteria

    - by Dimitri
    Hello, I have a class called User which has 2 properties : login/password. I am trying to authenticate a user in my application using hibernate criteria but my request doesn't work. [EDIT] The returned value is NULL. I have two users in my database for testing. Here is my code : @Override public User authenticate(String login, String password) throws NullPointerException { Session session = this.getSession(); User user = (User) session .createCriteria(User.class) .add( Restrictions.and( Property.forName("login").eq(login), Property.forName("password").eq(password) )).uniqueResult(); if (user == null){ throw new NullPointerException("User not found"); } return user; } Can someone tells me what is wrong with my code? Happy new Year 2011 !!

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  • Hibernate + Spring + session + cache

    - by andromeda
    We are using Hibernate with Spring for our Java application. We find out that when a session update something in database other sessions can not see the update. For example user1 get the account balance from database then user2 increase the balance , if user1 get the object another time he see the account balance before updating (seems that session use the value from its cache) but we want to get the updated object with new account balance. User1 use one session during all activity that is different from user2 session. Is any configuration to force to get the updated object from database? or any other help?

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  • Hibernate: delete many-to-many association

    - by Bar
    I have two tables with the many-to-many association. — DB fragment: loads Id Name sessions Id Date sessionsloads LoadId SessionId — Hibernate mapping fragments: /* loads.hbm.xml */ <set name="sessions" table="sessionsloads" inverse="true"> <key column="LoadId" /> <many-to-many column="SessionId" class="Session" /> </set> … /* sessions.hbm.xml */ <set name="loads" table="sessionsloads"> <key column="SessionId" /> <many-to-many column="LoadId" class="Load" /> </set> In order to remove one entry from the association table sessionsloads, I execute this code: Session session = sessionDao.getObject(sessionId); Load load = loadDao.getObject(loadId); load.getSessions().remove(session); loadDao.saveObject(load); But, after launching, this code change nothing. What's the right way to remove an association?

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  • Hibernate mysql groupe by day whith 0 entities

    - by Touhami
    I have this function i need to do that in sql (hibernate or mysql) or a java function that interpert the array of results select DAY(affaire.docCreationDate), count(affaire.docfullName) from CRMAffaireCode.AffaireClass as affaire where affaire.docfullName like 'CRMAffaire.Affaire%' and affaire.docCreationDate = '" + startDate + " 00:00:00' and affaire.docCreationDate <= '" + endDate + " 23:59:59' GROUP BY DAY(affaire.docCreationDate)" i have this entitie count in my table 2012-10-05 3 2012-10-06 0 2012-10-07 7 2012-10-08 13 2012-10-09 9 2012-10-10 0 2012-10-11 0 2012-10-12 3 the request return me this values 5 3 7 7 8 13 9 9 12 3 in this way i loose three lignes that have 0 as value, i need a request that return me this 5 3 6 0 7 7 8 13 9 9 10 0 11 0 12 3

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  • PostgreSQL, Ubuntu, NetBeans IDE (Part 3)

    - by Geertjan
    To complete the picture, let's use the traditional (that is, old) Hibernate mechanism, i.e., via XML files, rather than via the annotations shown yesterday. It's definitely trickier, with many more places where typos can occur, but that's why it's the old mechanism. I do not recommend this approach. I recommend the approach shown yesterday. The other players in this scenario include PostgreSQL, as outlined in the previous blog entries in this series. Here's the structure of the module, replacing the code shown yesterday: Here's the Employee class, notice that it has no annotations: import java.io.Serializable; import java.util.Date; public class Employees implements Serializable {         private int employeeId;     private String firstName;     private String lastName;     private Date dateOfBirth;     private String phoneNumber;     private String junk;     public int getEmployeeId() {         return employeeId;     }     public void setEmployeeId(int employeeId) {         this.employeeId = employeeId;     }     public String getFirstName() {         return firstName;     }     public void setFirstName(String firstName) {         this.firstName = firstName;     }     public String getLastName() {         return lastName;     }     public void setLastName(String lastName) {         this.lastName = lastName;     }     public Date getDateOfBirth() {         return dateOfBirth;     }     public void setDateOfBirth(Date dateOfBirth) {         this.dateOfBirth = dateOfBirth;     }     public String getPhoneNumber() {         return phoneNumber;     }     public void setPhoneNumber(String phoneNumber) {         this.phoneNumber = phoneNumber;     }     public String getJunk() {         return junk;     }     public void setJunk(String junk) {         this.junk = junk;     } } And here's the Hibernate configuration file: <?xml version="1.0"?> <!DOCTYPE hibernate-configuration PUBLIC       "-//Hibernate/Hibernate Configuration DTD 3.0//EN"     "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration>     <session-factory>         <property name="hibernate.connection.driver_class">org.postgresql.Driver</property>         <property name="hibernate.connection.url">jdbc:postgresql://localhost:5432/smithdb</property>         <property name="hibernate.connection.username">smith</property>         <property name="hibernate.connection.password">smith</property>         <property name="hibernate.connection.pool_size">1</property>         <property name="hibernate.default_schema">public"</property>         <property name="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</property>         <property name="hibernate.current_session_context_class">thread</property>         <property name="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</property>         <property name="hibernate.show_sql">true</property>         <mapping resource="org/db/viewer/employees.hbm.xml"/>     </session-factory> </hibernate-configuration> Next, the Hibernate mapping file: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC       "-//Hibernate/Hibernate Mapping DTD 3.0//EN"       "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping>     <class name="org.db.viewer.Employees"            table="employees"            schema="public"            catalog="smithdb">         <id name="employeeId" column="employee_id" type="int">             <generator class="increment"/>         </id>         <property name="firstName" column="first_name" type="string" />         <property name="lastName" column="last_name" type="string" />         <property name="dateOfBirth" column="date_of_birth" type="date" />         <property name="phoneNumber" column="phone_number" type="string" />         <property name="junk" column="junk" type="string" />             </class>     </hibernate-mapping> Then, the HibernateUtil file, for providing access to the Hibernate SessionFactory: import java.net.URL; import org.hibernate.cfg.AnnotationConfiguration; import org.hibernate.SessionFactory; public class HibernateUtil {     private static final SessionFactory sessionFactory;         static {         try {             // Create the SessionFactory from standard (hibernate.cfg.xml)             // config file.             String res = "org/db/viewer/employees.cfg.xml";             URL myURL = Thread.currentThread().getContextClassLoader().getResource(res);             sessionFactory = new AnnotationConfiguration().configure(myURL).buildSessionFactory();         } catch (Throwable ex) {             // Log the exception.             System.err.println("Initial SessionFactory creation failed." + ex);             throw new ExceptionInInitializerError(ex);         }     }         public static SessionFactory getSessionFactory() {         return sessionFactory;     }     } Finally, the "createKeys" in the ChildFactory: @Override protected boolean createKeys(List list) {     Session session = HibernateUtil.getSessionFactory().getCurrentSession();     Transaction transac = null;     try {         transac = session.beginTransaction();         Query query = session.createQuery("from Employees");         list.addAll(query.list());     } catch (HibernateException he) {         Exceptions.printStackTrace(he);         if (transac != null){             transac.rollback();         }     } finally {         session.close();     }     return true; } Note that Constantine Drabo has a similar article here. Run the application and the result should be the same as yesterday.

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  • How to write native SQL queries in Hibernate without hardcoding table names and fields?

    - by serg555
    Sometimes you have to write some of your queries in native SQL rather than hibernate HQL. Is there a nice way to avoid hardcoding table names and fields and get this data from existing mapping? For example instead of: String sql = "select user_name from tbl_user where user_id = :id"; something like: String sql = "select " + Hibernate.getFieldName("user.name") + " from " + Hibernate.getTableName(User.class) + " where " + Hibernate.getFieldName("user.id") + " = :id";

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  • How to connect ejb to hibernate in eclipse and glassfish server?

    - by agiles
    I am newer to ejb and hibernate and don't have any idea to how to link or connect those technologies mentioned above. I have just created individual module for ejb, hibernate and servlet. but I need to pass the data from servlet to ejb and then ejb to hibernate and store into MySql database. Problem for me, how to connect ejb to hibernate. I tried some ways and it couldn't work for me. Please someone help me. Thank you

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