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  • Deleting objects with FK constraints in Spring/Hibernate

    - by maxdj
    This seems like such a simple scenario to me, yet I cannot for the life of my find a solution online or in print. I have several objects like so (trimmed down): @Entity public class Group extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Set<HiringManager> managers = new HashSet<HiringManager>(); private List<JobOpening> jobs; @ManyToMany(fetch=FetchType.EAGER) @JoinTable( name="group_hiringManager", joinColumns=@JoinColumn(name="group_id"), inverseJoinColumns=@JoinColumn(name="hiringManager_id") ) public Set<HiringManager> getManagers() { return managers; } @OneToMany(mappedBy="group", fetch=FetchType.EAGER) public List<JobOpening> getJobs() { return jobs; } } @Entity public class JobOpening extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Group group; @ManyToOne @JoinColumn(name="group_id", updatable=false, nullable=true) public Group getGroup() { return group; } } @Entity public class HiringManager extends User { @ManyToMany(mappedBy="managers", fetch=FetchType.EAGER) public Set<Group> getGroups() { return groups; } } Say I want to delete a Group object. Now there are dependencies on it in the JobOpening table and in the group_hiringManager table, which cause the delete function to fail. I don't want to cascade the delete, because the managers have other groups, and the jobopenings can be groupless. I have tried overriding the remove() function of my GroupManager to remove the dependencies, but it seems like no matter what I do they persist, and the delete fails! What is the right way to remove this object?

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  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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  • Hibernate HQL m:n join problem

    - by smallufo
    I am very unfamiliar with SQL/HQL , and am currently stuck with this 'maybe' simple problem : I have two many-to-many Entities , with a relation table : Car , CarProblem , and Problem . One Car may have many Problems , One Problem may appear in many Cars, CarProblem is the association table with other properties . Now , I want to find Car(s) with specified Problem , how do I write such HQL ? All ids are Long type . I've tried a lot of join / inner-join combinations , but all in vain.. -- updated : Sorry , forget to mention : Car has many CarProblem Problem has many CarProblem Car and Problem are not directly connected in Java Object. -- update , java code below -- @Entity public class Car extends Model{ @OneToMany(mappedBy="car" , cascade=CascadeType.ALL) public Set<CarProblem> carProblems; } @Entity public class CarProblem extends Model{ @ManyToOne public Car car; @ManyToOne public Problem problem; ... other properties } @Entity public class Problem extends Model { other properties ... // not link to CarProblem , It seems not related to this problem // **This is a very stupid query , I want to get rid of it ...** public List<Car> findCars() { List<CarProblem> list = CarProblem.find("from CarProblem as cp where cp.problem.id = ? ", id).fetch(); Set<Car> result = new HashSet<Car>(); for(CarProblem cp : list) result.add(cp.car); return new ArrayList<Car>(result); } } The Model is from Play! framework , so these properties are all public .

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  • Adding JBoss repository to m2eclipse, no latest Hibernate version

    - by Robert
    I'm trying to add JBoss repository to m2eclipse, mainly for Hibernate. It seems to work, but it can't find the latest version of Hibernate (3.5.1), only 3.5.0beta. I looked at some other packages, and they all seem a couple of months behind. What could be causing this? I'm running latest m2eclipse, and i guess latest Eclipse (it just says 20100218-1602, eclipse people think it's funny to not include version in the about dialog), on ubuntu 9.10. This is my settings.xml <settings> <profiles> <profile> <id>jboss-maven2-release-repository</id> <activation> <activeByDefault>true</activeByDefault> </activation> <repositories> <repository> <id>jboss-maven2-release-repository</id> <url>http://repository.jboss.org/maven2</url> <releases> <enabled>true</enabled> </releases> <snapshots> <enabled>false</enabled> </snapshots> </repository> <repository> <id>jboss-snapshots</id> <url>http://snapshots.jboss.org/maven2</url> <releases> <enabled>false</enabled> </releases> <snapshots> <enabled>true</enabled> </snapshots> </repository> </repositories> <pluginRepositories> <pluginRepository> <id>jboss-releases</id> <url>http://repository.jboss.org/maven2</url> <releases> <enabled>true</enabled> </releases> <snapshots> <enabled>false</enabled> </snapshots> </pluginRepository> <pluginRepository> <id>jboss-snapshots</id> <url>http://snapshots.jboss.org/maven2</url> <releases> <enabled>false</enabled> </releases> <snapshots> <enabled>true</enabled> </snapshots> </pluginRepository> </pluginRepositories> </profile> </profiles>

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  • Tomcat/Hibernate Problem "SEVERE: Error listenerStart"

    - by JSteve
    I downloaded working example of hibernate (with maven) and installed it on my tomcat, it worked. Then I created a new web project in MyEclipse, added hibernate support and moved all source files (no jar) to this new project and fixed package/paths wherever was necessary. My servlets are responding correctly but when I add "Listener" in web.xml, tomcat returns error "Error ListenerStart" on startup and my application doesn't start. I've carefully checked all packages, paths and classes, they look good. Error message is also not telling anything more except these two words Here is complete tomcat startup log: 17-Jun-2010 12:13:37 PM org.apache.coyote.http11.Http11Protocol init INFO: Initializing Coyote HTTP/1.1 on http-8810 17-Jun-2010 12:13:37 PM org.apache.catalina.startup.Catalina load INFO: Initialization processed in 293 ms 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardService start INFO: Starting service Catalina 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardEngine start INFO: Starting Servlet Engine: Apache Tomcat/6.0.20 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardContext start SEVERE: Error listenerStart 17-Jun-2010 12:13:37 PM org.apache.catalina.core.StandardContext start SEVERE: Context [/addressbook] startup failed due to previous errors 17-Jun-2010 12:13:37 PM org.apache.coyote.http11.Http11Protocol start INFO: Starting Coyote HTTP/1.1 on http-8810 17-Jun-2010 12:13:37 PM org.apache.jk.common.ChannelSocket init INFO: JK: ajp13 listening on /0.0.0.0:8009 17-Jun-2010 12:13:37 PM org.apache.jk.server.JkMain start INFO: Jk running ID=0 time=0/22 config=null 17-Jun-2010 12:13:37 PM org.apache.catalina.startup.Catalina start INFO: Server startup in 446 ms My web.xml is: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <listener> <listener-class>addressbook.util.SessionFactoryInitializer</listener-class> </listener> <filter> <filter-name>Session Interceptor</filter-name> <filter-class>addressbook.util.SessionInterceptor</filter-class> </filter> <filter-mapping> <filter-name>Session Interceptor</filter-name> <servlet-name>Country Manager</servlet-name> </filter-mapping> <servlet> <servlet-name>Country Manager</servlet-name> <servlet-class>addressbook.managers.CountryManagerServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Country Manager</servlet-name> <url-pattern>/countrymanager</url-pattern> </servlet-mapping> </web-app> Can somebody either help me figure out what I am doing wrong? or point to some resource where I may get some precise solution of my problem?

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  • No improvement in speed when using Ehcache with Hibernate

    - by paddydub
    I'm getting no improvement in speed when using Ehcache with Hibernate Here are the results I get when i run the test below. The test is reading 80 Stop objects and then the same 80 Stop objects again using the cache. On the second read it is hitting the cache, but there is no improvement in speed. Any idea's on what I'm doing wrong? Speed Test: First Read: Reading stops 1-80 : 288ms Second Read: Reading stops 1-80 : 275ms Cache Info: elementsInMemory: 79 elementsInMemoryStore: 79 elementsInDiskStore: 0 JunitCacheTest public class JunitCacheTest extends TestCase { static Cache stopCache; public void testCache() { ApplicationContext context = new ClassPathXmlApplicationContext("beans-hibernate.xml"); StopDao stopDao = (StopDao) context.getBean("stopDao"); CacheManager manager = new CacheManager(); stopCache = (Cache) manager.getCache("ie.dataStructure.Stop.Stop"); //First Read for (int i=1; i<80;i++) { Stop toStop = stopDao.findById(i); } //Second Read for (int i=1; i<80;i++) { Stop toStop = stopDao.findById(i); } System.out.println("elementsInMemory " + stopCache.getSize()); System.out.println("elementsInMemoryStore " + stopCache.getMemoryStoreSize()); System.out.println("elementsInDiskStore " + stopCache.getDiskStoreSize()); } public static Cache getStopCache() { return stopCache; } } HibernateStopDao @Repository("stopDao") public class HibernateStopDao implements StopDao { private SessionFactory sessionFactory; @Transactional(readOnly = true) public Stop findById(int stopId) { Cache stopCache = JunitCacheTest.getStopCache(); Element cacheResult = stopCache.get(stopId); if (cacheResult != null){ return (Stop) cacheResult.getValue(); } else{ Stop result =(Stop) sessionFactory.getCurrentSession().get(Stop.class, stopId); Element element = new Element(result.getStopID(),result); stopCache.put(element); return result; } } } ehcache.xml <cache name="ie.dataStructure.Stop.Stop" maxElementsInMemory="1000" eternal="false" timeToIdleSeconds="5200" timeToLiveSeconds="5200" overflowToDisk="true"> </cache> stop.hbm.xml <class name="ie.dataStructure.Stop.Stop" table="stops" catalog="hibernate3" mutable="false" > <cache usage="read-only"/> <comment></comment> <id name="stopID" type="int"> <column name="STOPID" /> <generator class="assigned" /> </id> <property name="coordinateID" type="int"> <column name="COORDINATEID" not-null="true"> <comment></comment> </column> </property> <property name="routeID" type="int"> <column name="ROUTEID" not-null="true"> <comment></comment> </column> </property> </class> Stop public class Stop implements Comparable<Stop>, Serializable { private static final long serialVersionUID = 7823769092342311103L; private Integer stopID; private int routeID; private int coordinateID; }

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  • Hibernate - strange order of native SQL parameters

    - by Xorty
    Hello, I am trying to use native MySQL's MD5 crypto func, so I defined custom insert in my mapping file. <hibernate-mapping package="tutorial"> <class name="com.xorty.mailclient.client.domain.User" table="user"> <id name="login" type="string" column="login"></id> <property name="password"> <column name="password" /> </property> <sql-insert>INSERT INTO user (login,password) VALUES ( ?, MD5(?) )</sql-insert> </class> </hibernate-mapping> Then I create User (pretty simple POJO with just 2 Strings - login and password) and try to persist it. session.beginTransaction(); // we have no such user in here yet User junitUser = (User) session.load(User.class, "junit_user"); assert (null == junitUser); // insert new user junitUser = new User(); junitUser.setLogin("junit_user"); junitUser.setPassword("junitpass"); session.save(junitUser); session.getTransaction().commit(); What actually happens? User is created, but with reversed parameters order. He has login "junitpass" and "junit_user" is MD5 encrypted and stored as password. What did I wrong? Thanks EDIT: ADDING POJO class package com.xorty.mailclient.client.domain; import java.io.Serializable; /** * POJO class representing user. * @author MisoV * @version 0.1 */ public class User implements Serializable { /** * Generated UID */ private static final long serialVersionUID = -969127095912324468L; private String login; private String password; /** * @return login */ public String getLogin() { return login; } /** * @return password */ public String getPassword() { return password; } /** * @param login the login to set */ public void setLogin(String login) { this.login = login; } /** * @param password the password to set */ public void setPassword(String password) { this.password = password; } /** * @see java.lang.Object#toString() * @return login */ @Override public String toString() { return login; } /** * Creates new User. * @param login User's login. * @param password User's password. */ public User(String login, String password) { setLogin(login); setPassword(password); } /** * Default constructor */ public User() { } /** * @return hashCode * @see java.lang.Object#hashCode() */ @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((null == login) ? 0 : login.hashCode()); result = prime * result + ((null == password) ? 0 : password.hashCode()); return result; } /** * @param obj Compared object * @return True, if objects are same. Else false. * @see java.lang.Object#equals(java.lang.Object) */ @Override public boolean equals(Object obj) { if (this == obj) { return true; } if (obj == null) { return false; } if (!(obj instanceof User)) { return false; } User other = (User) obj; if (login == null) { if (other.login != null) { return false; } } else if (!login.equals(other.login)) { return false; } if (password == null) { if (other.password != null) { return false; } } else if (!password.equals(other.password)) { return false; } return true; } }

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  • Hibernate: Dirty Checking and Only Update of Dirty Attributes?

    - by jens
    Hello Experts, in "good old JDBC days" I wrote a lot of SQL Queries that did very targeted updates of only the "attributes/members" that were actually changed: For Example having an object with the following members: public String name; public String address; public Date date; If only date was changed in some Business Method I would only issue an SQL UPDATE for the date member. ==It seems however (thats my "impression" of hibernate) that when working with a standard Hibernate mapping (mapping the full class), even updates of only one single member lead to a full update of the object in SQL Statements generated by Hibernate. My Questions are: 1.) Is this observation correct, that hibernate DOES NOT intelligently check (in a fully mapped class), what member(s) where changed and then only issue updates for the specific changed members, but rather always will update (in the generated SQL Update Statement) all mapped members (of a class), even if they were not changed (in case the object is dirty due to one member being dirty...) 2.) What can I do to make Hibernate only update those members, that have been changed? I am searching for a solution to have hibernate only update the member that actually changed. (I know hibernate does some big work on doing dirty-checking, but as far as I know this dirtychecking is only relevant to identify if the object as whole is dirty, not what single member is dirty.) Thank you very much! Jens

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  • Single Table Per Class Hierarchy with an abstract superclass using Hibernate Annotations

    - by Andy Hull
    I have a simple class hierarchy, similar to the following: @Entity @Table(name="animal") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="animal_type", discriminatorType=DiscriminatorType.STRING) public abstract class Animal { } @Entity @DiscriminatorValue("cat") public class Cat extends Animal { } @Entity @DiscriminatorValue("dog") public class Dog extends Animal { } When I query "from Animal" I get this exception: "org.hibernate.InstantiationException: Cannot instantiate abstract class or interface: Animal" If I make Animal concrete, and add a dummy discriminator... such as @DiscriminatorValue("animal")... my query returns my cats and dogs as instances of Animals. I remember this being trivial with HBM based mappings but I think I'm missing something when using annotations. Can anyone help? Thanks!

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  • Detach an entity from a JPA persistence context (JPA 2.0 / Hibernate / EJB 3 / J2EE 6)

    - by Julien
    Hi, I wrote a stateless EJB method allowing to get an entity in "read-only" mode. The way to do this is to get the entity with the EntityManager then detach it (using the JPA 2.0 EntityManager). My code is the following: @PersistenceContext private EntityManager entityManager; public T getEntity(int entityId, Class<T> specificClass, boolean readOnly) throws Exception{ try{ T entity = (T)entityManager.find(specificClass, entityId); if (readOnly){ entityManager.detach(entity); } return entity; }catch (Exception e){ logger.error("", e); throw e; } } Getting the entity works fine, but the call to the detach method returns the following error: GRAVE: javax.ejb.EJBException at ... Caused by: java.lang.AbstractMethodError: org.hibernate.ejb.EntityManagerImpl.detach(Ljava/lang/Object;)V at com.sun.enterprise.container.common.impl.EntityManagerWrapper.detach(EntityManagerWrapper.java:973) at com.mycomp.dal.MyEJB.getEntity(MyEJB.java:37) I can't get more information and don't understand what the problem is... Could somebody help ?

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  • JPA/Hibernate and MySQL transaction isolation level

    - by armandino
    I have a native query that does a batch insert into a MySQL database: String sql = "insert into t1 (a, b) select x, y from t2 where x = 'foo'"; EntityTransaction tx = entityManager.getTransaction(); try { tx.begin(); int rowCount = entityManager.createNativeQuery(sql).executeUpdate(); tx.commit(); return rowCount; } catch(Exception ex) { tx.rollback(); log.error(...); } This query causes a deadlock: while it reads from t2 with insert .. select, another process tries to insert a row into t2. I don't care about the consistency of reads from t2 when doing an insert .. select and want to set the transaction isolation level to READ_UNCOMMITTED. How do I go about setting it in JPA backed by Hibernate?

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  • org.hibernate.MappingException: No Dialect mapping for JDBC type: 2002

    - by Moli
    Hi at all, I'm having a issue trying to get working a JPA nativeQuery. I'm having a org.hibernate.MappingException: No Dialect mapping for JDBC type: 2002 when a try to do a nativeQuery and get a geometry field type. I use oracle and org.hibernatespatial.oracle.OracleSpatial10gDialect. The geom fields is mapped as: @Column(name="geometry") @Type(type = "org.hibernatespatial.GeometryUserType") private Geometry geometry; List<Object> listFeatures= new LinkedList<Object>(); Query query= entityManager.createNativeQuery( "SELECT "+ slots +" , geometry FROM edtem_features feature, edtem_dades dada WHERE" + " feature."+ tematic.getIdGeomField() +" = dada."+ tematic.getIdDataField()+ " AND dada.capesid= "+ tematic.getCapa().getId() + " AND feature.geometriesid= "+ tematic.getGeometria().getId()); listFeatures.addAll( query.getResultList()); Anybody knows a solution? or how to force the type of the geometry to get wroking this... MANY Thanks in advance. Moli

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  • [hibernate - jpa ] good practices and bad practices

    - by blow
    Hi all, i have some questions about interaction with hibernate. openSession or getCurrentSession (without jta, thread insted)? How mix session operations with swing gui? Is good have something like this in a javabean class? public void actionPerformed(ActionEvent event) { // session code } Can i add methods to my entities that contains hql queries or is a bad practice? For example: // This method is in an entity MyOtherEntity.java class public int getDuration(){ Session session=HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); int sum=(Integer)session.createQuery("select sum(e.duration) as duration from MyEntity as e where e.myOtherEntity.id=:id group by e.name"). .setLong("id", getId()); .uniqueResult(); return sum; } In alternative how can i do this in a better and elegant way? Thanks.

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  • Bean is not instantiating while using hibernate interceptor

    - by amit sharma
    I am using hibernate interceptor with spring framework,but when i pass a bean reference of DAO class its not instantiating the bean. My interceptor class has: private IMyService myService; // and getters and setters while application-context.xml having entries: <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="entityInterceptor" ref="logInterceptor"></property> </bean> <bean name="logInterceptor" class="com.amit.project.Utility.TableLogInterceptor" > <property name="myService" ref="myService"/> </bean> <bean name="myService" class="com.amit.project.service.impl.MyService"> But my bean is not instantiating in class, showing null. entityInterceptor is not allowing to do that or anything else? plz suggest a way if anybody knows.

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  • Tips for resolving Hibernate/JPA EntityNotFoundException

    - by Damo
    I'm running into a problem with Hibernate where when trying to delete a group of Entities I encounter the following error: javax.persistence.EntityNotFoundException: deleted entity passed to persist: [com.locuslive.odyssey.entity.FreightInvoiceLine#<null>] These are not normally so difficult to track down as they are usually caused by an entity being deleted but not being removed from a Collection that it is a member of. In this case I have removed the entity from every list that I can think of (it's a complex datamodel). I've put JBoss logging into Trace and I can see the collections that are being cascaded. However I can't seem to find the Collection containing the entity that I'm deleting. Does anyone have any tips for resolving this particular Exception? Thanks.

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  • Unique items in Hibernate collections

    - by Rickard Lindberg
    I have defined a collection in Hibernate like this: ... public class Item { ... @ElementCollection List<Object> relatedObjects; } It creates a mapping table with colums item_id and object_id. The problem is that object_id seems to be unique. In other words I can not have two different items being related to the same object. But that is what I want. I would like the combination of item_id and object_id to be unique. How do I do that?

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  • NULL handling with subselect in Hibernate Criteria API

    - by Jens Schauder
    I'm constructing a Hibernate Criterion, using a subselect as follows DetachedCriteria subselect = DetachedCriteria.forClass(NhmCode.class, "sub"); // the subselect selecting the maximum 'validFrom' subselect.add(Restrictions.le("validFrom", new Date())); // it should be in the past (null needs handling here) subselect.add(Property.forName("sub.lifeCycle").eqProperty("this.id")); // join to owning entity subselect.setProjection(Projections.max("validFrom")); // we are only interested in the maximum validFrom Conjunction resultCriterion = Restrictions.conjunction(); resultCriterion.add(Restrictions.ilike(property, value)); // I have other Restrictions as well resultCriterion.add(Property.forName("validFrom").eq(subselect)); // this fails when validFrom and the subselect return NULL return resultCriterion; It works ok so far, but the restriction on the last line before the return statement is false when validFrom and subselect result in NULL. What I need is a version which handles this case as true. Possibly by applying a NVL or coalesce or similar. How do I do this?

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  • Postgresql 8.4 reading OID style BLOBs with Hibernate

    - by peter
    I am getting this weird case when querying Postgres 8.4 for some records with Blobs (of type OIDs) with Hibernate. The query does return all right but when my code wants to read the content of the BLOB with the simple code below, it gets 0 bytes back public static byte[] readBlob(Blob blob) throws Exception { InputStream is = null; try { is = blob.getBinaryStream(); return org.apache.commons.io.IOUtils.toByteArray(is); } finally { if (is != null) try { is.close(); } catch(Exception e) {} } } Funny think is that I am getting this behavior only since I've started adding more then one such records to the table. The underlying JDBC library is type 3 (postgresq 8.4-701). Can someone give me a hint as to how to solve this issue? Thanks Peter

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  • Hibernate configuration files not found by Axis2

    - by DanJo519
    I am writing a web service to be deployed on Tomcat using Axis2. I am using Hibernate3 to persist data between the web service and a MySQL database. When running the application through by IDE, the method I am exposing through Axis2 works as intended, however when I deploy the .aar to Tomcat, I receive a SOAP Error claiming that hibernate.cfg.xml cannot be found. However, inside the .aar, I clearly see that all the configuration file and all the mapping files are included. I have determined a workaround: If I place the resulting files from the Netbeans build/class folder into the axis2/WEB-INF/class folder, then the application works as expected. My question, then, is is there a better way to deploy my application so that Axis2 will pick up the configuration and mapping files through the deployed .aar without my manually having to copy the contents of the build/class folder into the axis2/WEB-INF/class folder?

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  • DAO, Spring and Hibernate

    - by EugeneP
    Correct me if anything is wrong. Now when we use Spring DAO for ORM templates, when we use @Transactional attribute, we do not have control over the transaction and/or session when the method is called externally, not within the method. Lazy loading saves resources - less queries to the db, less memory to keep all the collections fetched in the app memory. So, if lazy=false, then everything is fetched, all associated collections, that is not effectively, if there are 10,000 records in a linked set. Now, I have a method in a DAO class that is supposed to return me a User object. It has collections that represent linked tables of the database. I need to get a object by id and then query its collections. Hibernate "failed to lazily initialize a collection" exception occurs when I try to access the linked collection that this DAO method returns. Explain please, what is a workaround here?

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  • How to use DAOs with hibernate/jpa?

    - by Ari
    Assuming the DAO structure and component interaction described below, how should DAOs be used with persistence layers like hibernate and toplink? What methods should/shouldn't they contain? Would it be bad practice to move the code from the DAO directly to the service? For example, let's say that for every model we have a DAO (that may or may not implement a base interface) that looks something like the following: public class BasicDao<T> { public List<T> list() { ... } public <T> retrieve() { ... } public void save() { ... } public void delete() { ... } } Component interaction pattern is -- service DAO model

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  • Unit Testing Hibernate's Optimistic Locking (within Spring)

    - by Michal Bachman
    I'd like to write a unit test to verify that optimistic locking is properly set up (using Spring and Hibernate). I'd like to have the test class extend Spring's AbstractTransactionalJUnit4SpringContextTests. What I want to end up with is a method like this: @Test (expected = StaleObjectStateException.class) public void testOptimisticLocking() { A a = getCurrentSession().load(A.class, 1); a.setVersion(a.getVersion()-1); getCurrentSession().saveOrUpdate(a); getCurrentSession().flush(); fail("Optimistic locking does not work"); } This test fails. What do you recommend as a best practice? The reason I am trying to do this is that I want to transfer the version to the client (using a DTO). I want to prove that when the DTO is sent back to the server and merged with a freshly loaded entity, saving that entity will fail if it's been updated by somebody else in the meantime.

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  • Hibernate Validator - Using properties in the constraints xml

    - by Avi Y
    Hi, I have just started using hibernate validator. I am creating the constraints in an XML file(not annotations). The only problem I am having is that I would like to use properties inside the constraints. For example: <bean class="MyBean" > <constraint annotation="javax.validation.constraints.Min"> <element name="value">{myProperty}</element> </constraint> </bean> and I would like to define these properties in a separate file. Do you think that's possible? Any help would be appreciated.

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  • Hibernate Subquery and DetachedCriteria

    - by dawez
    I have created a DetachedCriteria that is retrieving estates that have the isApproved and isPublished set to true. It is defined in this way: DetachedCriteria activePublishedCriteria = DetachedCriteria.forClass(Estate.class) .add(Restrictions.eq("isApproved", true)) .add(Restrictions.eq("isPublished", true)) .setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY); I would like to reuse this criteria in some of the queries. In this case I would like to replace the isApproved and isPublished restrictions with the DetachedCriteria Criteria criteria = getSession().createCriteria(Estate.class) .createAlias("city", "c") .add(Restrictions.eq("c.id", cityID)) // the following 2 lines should be use the DetachedCriteria .add(Restrictions.eq("isApproved", true)) .add(Restrictions.eq("isPublished", true)) .setProjection(Projections.rowCount()); return (Integer) criteria.list().get(0); Is there a way to do this ? Tried to use .add.Subqueries.geAll(.... But cannot make it work properly. I could not find proper documentation on the Subqueries in Hibernate. Tips are welcomed.

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  • Spring/Hibernate/Junit example of testing DAO against HSQLDB

    - by Ryan P.
    Hi guys, I'm working on trying to implement a JUnit test to check the functionality of a DAO. (The DAO will create/read a basic object/table relationship in HSQLDB). The trouble I'm having is the persistence of the DAO (for the non-test code) is being completed through an in-house solution using Spring/Hibernate, which eliminates the usual *.hbm.xml templates that most examples I have found contain. Beacuse of this, I'm having some trouble understanding how to setup a JUnit test to implement the DAO to create/read (just very basic funtionality) to an in-memory HSQLDB. I have found a few examples, but the usage of the in-house persistence means I can't extend some of the classes the examples show (I can't seem to get the application-context.xml setup properly). Can anyone suggest any projects/examples I could take a look at (or any documentation) to further my understanding of the best way to implement this test functionality? I feel like this should be really simple, but I keep running into problems implementing the examples I have found. Thanks in advance!

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