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  • Django Admin Form for Many to many relationship

    - by Anand
    I have a many to many relationship between 2 tables Users an Domains. I have defined this relationship in the Domains class. So in the admin interface I see the Users when I am viewing Domains. But I do not see Domains when I am viewing Users. How can I achieve this.

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  • rails use counts in diferent views

    - by Oluf Nielsen
    Hello i guess this is going to be pretty noob question.. But.. I have an scaffold called list, which has_many :wishes. And with that information in my model, I can in my list view use this code <%=h @list.wishes.count % well now I have made an controller called statusboard.. And in that' I have 3 functions.. Or how to say it.. but it is Index, loggedin, loggedout.. And .. In loggedin and in the file #app/views/statusboard/loggedin.html.erb i want to display this.. Howdy {Username}, you have made {count lists} lists, and {count wishes} wishes here is that i figured i should write in my file.. Howdy {Username}, you have made <%=h @user.list.count % lists, and <%=h @user.wishes.count % wishes my list model is like this = class List < ActiveRecord::Base   attr_accessible :user_id, :name, :description   belongs_to :users   has_many :wishes end and my wish model is like this = class Wish < ActiveRecord::Base   attr_accessible :list_id, :name, :price, :link, :rating, :comment   belongs_to :list end and last my user model is like this = class User < ActiveRecord::Base   # Include default devise modules. Others available are:   # :token_authenticatable, :lockable and :timeoutable   devise :database_authenticatable, :registerable,# :confirmable,              :recoverable, :rememberable, :trackable, :validatable   # Setup accessible (or protected) attributes for your model   attr_accessible :email, :password, :password_confirmation   has_many :lists end i hope someone can help me :-)! / Oluf Nielsen

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  • Copying contents of a module

    - by Hulk
    If there exists an old data of a model say , query=Emp.objects.filter(pk=profile.id) Is there a easier way to copy the same values into the same model again.. Now that the id will be different so.. I have this requirement. Thanks..

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  • general database modeling and django specific modeling

    - by Shreko
    I'm wondering what is the best way to model something like the following. Lets say my company sells metal bars (parameters/fields are: length, profile_type, quantity etc.) of different profiles, where profiles may be pipe(pipe_diameter, wall_thickness) or hollow_rectangle(base, height, wall_thickness), or maybe some other profile with different parameters. Lets say maximum number of profiles would be 12, each profile having between 2-5 parameters. Should everything be in a single table like table_bars: id, length, quantity, profile_type, pipe_diameter, wall_thickness, base, height, etc.) where profile type would be (pipe, rectangle etc.) or should every shape have its own table with its own parameters and in table_bars keep only id, length, quantity profile_type and profile_id) and are there any django specific issues is multiple tables are the best answer? Thanks

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  • Hooking up Sproutcore frontend and custom Python backend

    - by Suvir
    Hello everyone, I am building a web-based application. The frontend has been designed in Sproutcore. For the backend, we have our own python API which handles all transactions with multiple databases. What is the best way to hook up the front-end with the back-end. AFAIK django is pretty monolithic (correct me if i am wrong) and it would be cumbersome if I dont use its native ORM...I would prefer a python-based solution..any ideas? thanks! Suvir

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  • Load django template from the database

    - by Björn Lindqvist
    Hello, Im trying to render a django template from a database outside of djangos normal request-response structure. But it appears to be non-trivial due to the way django templates are compiled. I want to do something like this: >>> s = Template.objects.get(pk = 123).content >>> some_method_to_render(s, {'a' : 123, 'b' : 456}) >>> ... the rendered output here ... How do you do this?

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  • [Django] Automatically Update Field when a Different Field is Changed

    - by Gordon
    I have a model with a bunch of different fields like first_name, last_name, etc. I also have fields first_name_ud, last_name_ud, etc. that correspond to the last updated date for the related fields (i.e. when first_name is modified, then first_name_ud is set to the current date). Is there a way to make this happen automatically or do I need to check what fields have changed each time I save an object and then update the related "_ud" fields. Thanks a lot!

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  • using distinct in django query

    - by Hulk
    There is a column as designation in the defaults table,How to get the distinct designation values from defaults table In the below the distinct applies on the id field, this need to be on designation field def = defaults.objects.filter(name=sc).distinct() And can some one explain what is flat=true condition Thanks..

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  • Can django's auth_user.username be varchar(75)?

    - by perrierism
    Django's auth_user.username field is 30 characters. That means you can't have auth_user.username store an email address. If you want to have users authenticate based on their email address it would seem you have to do some wonky stuff like writing your own authentication backend which authenticates based on (email, password) instead of (username, password) and furthermore, figuring out what you're going to put in the username field since it is required and it is a primary key. Do you put a hash in there, do you try to put the id in there... bleh! Why should you have to write all this code and consider edge cases simply because username is too small for your (farily common) purposes? Is there anything wrong with running alter table on auth_user to make username be varchar(75) so it can fit an email? What does that break if anything?

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  • Is there an OR filter? - Django

    - by RadiantHex
    Hi folks, is there any way of doing the following Unicorn.objects.or_filter(magical=True).or_filter(unicorn_length=15).or_filter(skin_color='White').or_filter(skin_color='Blue') where or_filter stands for an isolated match I remember using something similar but cannot find the function anymore! Help would be great! Thanks :)

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  • How can join two django querysets in one?

    - by diegueus9
    I need order a Queryset by date in desc order, but i need put in the end the objects at the end, I do this: qs1 = Model.objects.exclude(date=None).order_by('-date') qs2 = Model.objects.filter(date=None).order_by('-date') and my list is: l = list(qs1)+list(qs2) There is a more efficiently way for this?

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  • Best way to handle multiple tables to replace one big table in Rails? (e.g. 'Books1', 'Books2', etc.

    - by mikep
    Hello, I've decided to use multiple tables for an entity (e.g. Books1, Books2, Books3, etc.), instead of just one main table which could end up having a lot of rows (e.g. just Books). I'm doing this to try and to avoid a potential future performance drop that could come with having too many rows in one table. With that, I'm looking for a good way to handle this in Rails, mainly by trying to avoid loading a bunch of unused associations. (I know that I could use a partition for this, but, for now, I've decided to go the 'multiple tables' route.) Each user has their books placed into a specific table. The actual book table is chosen when the user is created, and all of their books go into the same table. I'm going to split the adds across the tables. The goal is to try and keep each table pretty much even -- but that's a different issue. One thing I don't particularly want to have is a bunch of unused associations in the User class. Right now, it looks like I'd have to do the following: class User < ActiveRecord::Base has_many :books1, :books2, :books3, :books4, :books5 end class Books1 < ActiveRecord::Base belongs_to :user end class Books2 < ActiveRecord::Base belongs_to :user end class Books3 < ActiveRecord::Base belongs_to :user end I'm assuming that the main performance hit would come in terms of memory and possibly some method call overhead for each User object, since it has to load all of those associations, which in turn creates all of those nice, dynamic model accessor methods like User.find_by_. But for each specific user, only one of the book tables would be usable/applicable, since all of a user's books are stored in the same table. So, only one of the associations would be in use at any time and any other has_many :bookX association that was loaded would be a waste. For example, with a user.id of 2, I'd only need books3.find_by_author('Author'), but the way I'm thinking of setting this up, I'd still have access to Books1..n. I don't really know Ruby/Rails does internally with all of those has_many associations though, so maybe it's not so bad. But right now I'm thinking that it's really wasteful, and that there may just be a better, more efficient way of doing this. So, a few questions: 1) Is there's some sort of special Ruby/Rails methodology that could be applied to this 'multiple tables to represent one entity' scheme? Are there any 'best practices' for this? 2) Is it really bad to have so many unused has_many associations for each object? Is there a better way to do this? 3) Does anyone have any advice on how to abstract the fact that there's multiple book tables behind a single books model/class? For example, so I can call books.find_by_author('Author') instead of books3.find_by_author('Author'). Thank you!

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  • Edit/show Primary Key in Django Admin

    - by emcee
    It appears Django hides fields that are flagged Primary Key from being displayed/edited in the Django admin interface. Let's say I'd like to input data in which I may or may not want to specify a primary key. How would I go about displaying primary keys in Django-admin, and how could I make specifying it optional? Many thanks in advance, beloved hive-mind.

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  • Is it possible to change the model name in the django admin site?

    - by luc
    Hello, I am translating a django app and I would like to translate also the homepage of the django admin site. On this page are listed the application names and the model class names. I would like to translate the model class name but I don't find how to give a user-friendly name for a model class. Does anybody know how to do that?

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  • Django updating db for selected ids

    - by Hulk
    In the following, New row values in DB are 6,8.They are the ids of a field I want to update these some other fields in the table based on these values row_newid=request.POST.get('row_updated_id') //Array row_newdata=request.POST.get('row_updated_data') //Array for newrow in row_newid: //how to update row_newdata for newrow values No for all the ids in row_newid how do i update row_newdata. row_newdata has the values 'a' and 'b' for example. thanks....

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  • Django: testing get query

    - by Brant
    Okay, so I am sick of writing this... res = Something.objects.filter(asdf=something) if res: single = res[0] else: single = None if single: # do some stuff I would much rather be able to do something like this: single = Something.objects.filter(asdf=something) if single: #do some stuff I want to be able to grab a single object without testing the filtered results. In other words, when i know there is either going to be 1 or 0 matching entries, I would like to jump right to that entry, otherwise just get a 'None'. The DoesNotExist error that goes along with .get does not always work so well when trying to compress these queries into a single line. Is there any way to do what I have described?

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  • Django RadioButtons with icons and not label?

    - by Asinox
    Hi guy's , i have an app that have 2 fields: company_name and logo, i'm displaying the companies like radiobutton in my Form from Model, but i want to show the logo company instead of the company label (company name) Any idea ? My forms: class RecargaForm(ModelForm): compania = forms.ModelChoiceField(queryset=Compania.objects.all(), initial=0 ,empty_label='None', widget=forms.RadioSelect()) class Meta: model = Recarga Thanks :)

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  • Django Admin Actions missing

    - by Andrew C
    One of my Django sites is missing the Django Admin Action bar shown here: http://docs.djangoproject.com/en/dev/ref/contrib/admin/actions/#ref-contrib-admin-actions There is no checkbox next to each row and no Action select box near the top of the page. This is happening on every model. I have several sites running Django 1.1, and they all show the Admin Actions, so it feels like a local configuration issue. Anyone seen this before?

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  • Tying in to Django Admin's Model History

    - by akdom
    The Setup: I'm working on a Django application which allows users to create an object in the database and then go back and edit it as much as they desire. Django's admin site keeps a history of the changes made to objects through the admin site. The Question: How do I hook my application in to the admin site's change history so that I can see the history of changes users make to their "content" ?

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  • Django model operating on a queryset

    - by jmoz
    I'm new to Django and somewhat to Python as well. I'm trying to find the idiomatic way to loop over a queryset and set a variable on each model. Basically my model depends on a value from an api, and a model method must multiply one of it's attribs by this api value to get an up-to-date correct value. At the moment I am doing it in the view and it works, but I'm not sure it's the correct way to achieve what I want. I have to replicate this looping elsewhere. Is there a way I can encapsulate the looping logic into a queryset method so it can be used in multiple places? I have this atm (I am using django-rest-framework): class FooViewSet(viewsets.ModelViewSet): model = Foo serializer_class = FooSerializer bar = # some call to an api def get_queryset(self): # Dynamically set the bar variable on each instance! foos = Foo.objects.filter(baz__pk=1).order_by('date') for item in foos: item.needs_bar = self.bar return items I would think something like so would be better: def get_queryset(self): bar = # some call to an api # Dynamically set the bar variable on each instance! return Foo.objects.filter(baz__pk=1).order_by('date').set_bar(bar) I'm thinking the api hit should be in the controller and then injected to instances of the model, but I'm not sure how you do this. I've been looking around querysets and managers but still can't figure it out nor decided if it's the best method to achieve what I want. Can anyone suggest the correct way to model this with django? Thanks.

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  • How to store an integer leaded by zeros in django

    - by Oscar Carballal
    Hello, I'm trying to store a number in django that looks like this: 000001 My problem is that if I type this inside an IntegerField it gets converted to "1" without the leading zeros. I've tried also with a DecimalField with the same result. How can I store the leading zeros whithout using a CharField? (I need to manipulate that number in it's integer form)

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  • Django unable to update model

    - by user292652
    i have the following function to override the default save function in a model match def save(self, *args, **kwargs): if self.Match_Status == "F": Team.objects.filter(pk=self.Team_one.id).update(Played=F('Played')+1) Team.objects.filter(pk=self.Team_two.id).update(Played=F('Played')+1) if self.Winner !="": Team.objects.filter(pk=self.Winner.id).update(Win=F('Win')+1, Points=F('Points')+3) else: return if self.Match_Status == "D": Team.objects.filter(pk=self.Team_one.id).update(Played=F('Played')+1, Draw = F('Draw')+1, Points=F('Points')+1) Team.objects.filter(pk=self.Team_two.id).update(Played=F('Played')+1, Draw = F('Draw')+1, Points=F('Points')+1) super(Match, self).save(*args, **kwargs) I am able to save the match model just fine but Team model does not seem to be updating at all and no error is being thrown. am i missing some thing here ?

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  • How do you handle the deletion of your model working with ViewModels and keeping them in sync ?

    - by Lisa
    Hello, these could be my entity relations: 1 Pupil has 1 Chair 1 Pupil has N Documents 1 Pupil has N Marks 1 Pupil has N IncidentReports etc... So with that sample I get 4 IEnumerable from my database put each into an ObservableCollection. Now I have 4 different Views each bound to one of those 4 collections. Lets assume I delete a single PupilViewModel in the AdministrationController which is the only View where I can delete a PupilViewModel. Now I have to inform 3 other Controller and their ObservableCollections about the one deleted PupilViewModel to keep the whole application synchronized... thats stupid somehow. Do you have any good advice on that scenario? AND it gets even worse. If I delete a schoolclass I have to sync the pupils everywhere AND the documents or incidentreports or marks... gush... o_O

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