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  • get foreign key objects in a single query - Django

    - by John
    Hi I have 2 models in my django code: class ModelA(models.Model): name = models.CharField(max_length=255) description = models.CharField(max_length=255) created_by = models.ForeignKey(User) class ModelB(models.Model): category = models.CharField(max_length=255) modela_link = models.ForeignKey(ModelA, 'modelb_link') functions = models.CharField(max_length=255) created_by = models.ForeignKey(User) Say ModelA has 100 records, all of which may or may not have links to ModelB Now say I want to get a list of every ModelA record along with the data from ModelB I would do: list_a = ModelA.objects.all() Then to get the data for ModelB I would have to do for i in list_a: i.additional_data = i.modelb_link.all() However this runs a query on every instance of i. Thus making 101 queries to run. Is there any way of running this all in just 1 query. Or at least less than the 101 queries. I've tried putting in ModelA.objects.select_related().all() but this didn't seem to have any effect. Thanks

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  • Count Records in Listing View

    - by 47
    I have these two models: class CommonVehicle(models.Model): year = models.ForeignKey(Year) series = models.ForeignKey(Series) engine = models.ForeignKey(Engine) body_style = models.ForeignKey(BodyStyle) ... class Vehicle(models.Model): objects = VehicleManager() stock_number = models.CharField(max_length=6, blank=False) vin = models.CharField(max_length=17, blank=False) common_vehicle = models.ForeignKey(CommonVehicle) .... What I want to do is to have a count of how many times a given CommonVehicle object is used in the Vehicle class. So far my attempts are giving me one number, which is a total of all the records. How can I have the count being the total appearances for each CommonVehicle

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  • How do I filter values in a Django form using ModelForm?

    - by malandro95
    I am trying to use the ModelForm to add my data. It is working well, except that the ForeignKey dropdown list is showing all values and I only want it to display the values that a pertinent for the logged in user. Here is my model for ExcludedDate, the record I want to add: class ExcludedDate(models.Model): date = models.DateTimeField() reason = models.CharField(max_length=50) user = models.ForeignKey(User) category = models.ForeignKey(Category) recurring = models.ForeignKey(RecurringExclusion) def __unicode__(self): return self.reason Here is the model for the category, which is the table containing the relationship that I'd like to limit by user: class Category(models.Model): name = models.CharField(max_length=50) user = models.ForeignKey(User, unique=False) def __unicode__(self): return self.name And finally, the form code: class ExcludedDateForm(ModelForm): class Meta: model = models.ExcludedDate exclude = ('user', 'recurring',) How do I get the form to display only the subset of categories where category.user equals the logged in user?

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  • How to reload Django models without losing my locals in an interactive session?

    - by Gj
    I'm doing some research with an interactive shell and using a Django app (shell_plus) for storing data and browsing it using the convenient admin. Occasionally I add or change some of the app models, and run a syncdb (or South migration when changing a model). The changes to the models don't take effect in my interactive session even if I re-import the app models. Thus I'm forced to restart the shell_plus and lose my precious locals() in the process. Is there any way to reload the models during a session? Thanks!!

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  • Can GMod/SFM models be converted to Unity GameObjects?

    - by Supuhstar
    Someone made a suite of GMod/SFM models available for free for people making games and videos in GMod and SFM. These are of type .dmx, .dx80.vtx, .dx90.vtx, .mdl, .phy, .sw.vtx, .vvd, .vmt, and .vtf. I fon't use GMod or SFM, so I don't know what these are, thus making it hard for me to manually convert them. Is there any way to change these into files Unity can recognize and use? I'd like to have an easy step from converting them, but I would also accept instructions on how to export them to generic mesh/skeleton/texture files, and then how to import and combine these in Unity.

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  • Any way to edit Warcraft MDX or MDL Animated models?

    - by Aralox
    I have been searching for a while for a way to get an animated mdl or mdx model into any 3D animating software (such as Blender), but so far have not had any success. I found a few methods of getting textured static mdx or mdl models into Blender/Milkshape/Hexagon, but no one seems to have written an importer that deals with the mdl/mdx model's keyframe animation. On that note, if anyone knows of a way of importing a keyframe-animated 3DS model into Blender, me and alot of people would appreciate it if you could let us know. Thanks for any help! :) PS: For anyone curious about static MDL or MDX - Blender, see here: http://wiki.blender.org/index.php/Extensions:2.6/Py/Scripts/Import-Export/WarCraft_MDL

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  • What is the difference from the push and pull development models?

    - by michelpm
    I was reading Extreme Programming Explained, Second Edition and in the chapter 11 "The Theory of Constraints" the authors talk about the old and obsolete "push" development model and the XP way, the "pull" development model. It looks like a quite important concept, but it takes only a very small paragraph and two images that are mere illustrations of the "waterfall" and iterative process, nothing specific about these models except by the image caption. I searched and it doesn't go any further about it in the rest of the book. I couldn't find any further explanations or discussions about it in the Internet either. If the only difference about those is that one is "waterfall" and the other is iterative, them why push and why pull? Does anyone understand what is really the difference between those two and give some good examples?

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  • Help with understanding generic relations in Django (and usage in Admin)

    - by saturdayplace
    I'm building a CMS for my company's website (I've looked at the existing Django solutions and want something that's much slimmer/simpler, and that handles our situation specifically.. Plus, I'd like to learn this stuff better). I'm having trouble wrapping my head around generic relations. I have a Page model, a SoftwareModule model, and some other models that define content on our website, each with their get_absolute_url() defined. I'd like for my users to be able to assign any Page instance a list of objects, of any type, including other page instances. This list will become that Page instance's sub-menu. I've tried the following: class Page(models.Model): body = models.TextField() links = generic.GenericRelation("LinkedItem") @models.permalink def get_absolute_url(self): # returns the right URL class LinkedItem(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') title = models.CharField(max_length=100) def __unicode__(self): return self.title class SoftwareModule(models.Model): name = models.CharField(max_length=100) description = models.TextField() def __unicode__(self): return self.name @models.permalink def get_absolute_url(self): # returns the right URL This gets me a generic relation with an API to do page_instance.links.all(). We're on our way. What I'm not sure how to pull off, is on the page instance's change form, how to create the relationship between that page, and any other extant object in the database. My desired end result: to render the following in a template: <ul> {% for link in page.links.all %} <li><a href='{{ link.content_object.get_absolute_url() }}'>{{ link.title }}</a></li> {% endfor%} </ul> Obviously, there's something I'm unaware of or mis-understanding, but I feel like I'm, treading into that area where I don't know what I don't know. What am I missing?

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  • Django Cannot set values on a ManyToManyField which specifies an intermediary model

    - by dana
    i am using a m2m and a through table, and when i was trying to save, my error was: Cannot set values on a ManyToManyField which specifies an intermediary model so, i've modified my code, so that when i save the form, to insert data into the 'through' table too.But now, i'm having another error. (i've bolded the lines where i think i am wrong) i have in models.py: class Classroom(models.Model): user = models.ForeignKey(User, related_name = 'classroom_creator') classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members", through = 'Membership') class Membership(models.Model): accept = models.BooleanField(User) date = models.DateTimeField(auto_now = True) classroom = models.ForeignKey(Classroom, related_name = 'classroom_membership') member = models.ForeignKey(User, related_name = 'user_membership') and in def save_classroom(request): if request.method == 'POST': form = ClassroomForm(request.POST, request.FILES, user = request.user) **classroom_instance = Classroom member_instance = Membership** if form.is_valid(): new_obj = form.save(commit=False) new_obj.user = request.user r = Relations.objects.filter(initiated_by = request.user) membership = Membership.objects.create(**classroom = classroom_instance, member = member_instance,date=datetime.datetime.now())** new_obj.save() form.save_m2m() return HttpResponseRedirect('/classroom/classroom_view/{{user}}/') else: form = ClassroomForm(user = request.user) return render_to_response('classroom/classroom_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to initialise okay the classroom_instance and menber_instance.My error os: Cannot assign "": "Membership.classroom" must be a "Classroom" instance. Thanks!

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  • Django: Applying Calculations To A Query Set

    - by TheLizardKing
    I have a QuerySet that I wish to pass to a generic view for pagination: links = Link.objects.annotate(votes=Count('vote')).order_by('-created')[:300] This is my "hot" page which lists my 300 latest submissions (10 pages of 30 links each). I want to now sort this QuerySet by an algorithm that HackerNews uses: (p - 1) / (t + 2)^1.5 p = votes minus submitter's initial vote t = age of submission in hours Now because applying this algorithm over the entire database would be pretty costly I am content with just the last 300 submissions. My site is unlikely to be the next digg/reddit so while scalability is a plus it is required. My question is now how do I iterate over my QuerySet and sort it by the above algorithm? For more information, here are my applicable models: class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Notes: I don't have "downvotes" so just the presence of a Vote row is an indicator of a vote or a particular link by a particular user.

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  • Django filters - Using an AllValuesFilter (with a LinkWidget) on a ManyToManyField

    - by magnetix
    This is my first Stack Overflow question, so please let me know if I do anything wrong. I wish to create an AllValues filter on a ManyToMany field using the wonderful django-filters application. Basically, I want to create a filter that looks like it does in the Admin, so I also want to use the LinkWidget too. Unfortunately, I get an error (Invalid field name: 'operator') if I try this the standard way: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class SignFilter(LinkOrderFilterSet): operator = django_filters.AllValuesFilter(widget=django_filters.widgets.LinkWidget) class Meta: model = Sign fields = ['operator'] I got around this by creating my own filter with the many to many relationship hard coded: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class MyFilter(django_filters.ChoiceFilter): @property def field(self): cd = {} for row in self.model.objects.all(): orgs = row.operator.select_related().values() for org in orgs: cd[org['id']] = org['name'] choices = zip(cd.keys(), cd.values()) list.sort(choices, key=lambda x:(x[1], x[0])) self.extra['choices'] = choices return super(AllValuesFilter, self).field class SignFilter(LinkOrderFilterSet): operator = MyFilter(widget=django_filters.widgets.LinkWidget) I am new to Python and Django. Can someone think of a more generic/elegant way of doing this?

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • django views question

    - by Hulk
    In my django views i have the following def create(request): query=header.objects.filter(id=a)[0] a=query.criteria_set.all() logging.debug(a.details) I get an error saying 'QuerySet' object has no attribute 'details' in the debug statement .What is this error and what should be the correct statemnt to query this.And the model corresponding to this is as follows where as the models has the following: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() Thanks..

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • Finding object count where a field is unique in Django

    - by Johnd
    I have a model that is something like this: class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() A user can submit many arguments, per case. I want to be able to say how many users have submitted side=true arguments. I mean if 1 user had 10 arguments and another user had 2 arguments (both side=true) I'd want the count to be 2, not 12.

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  • TCO Models: Oracle invites you to the next webcast dedicated to Partners on Oracle Hardware and Solutions

    - by mseika
    The Oracle Hardware and Solutions Webcast Series is a sequence of one-hour Sales-Oriented Web Seminars, dedicated to Oracle Partners. This is your opportunity to learn about Oracle's Servers, Storage and Solutions strategy and portfolio, and their business value for you and your customers. The next appointment is for Wednesday, June 22, at 9am UKT / 10am CET:Total Cost of Ownership Models Examples: How we can sell Oracle HW and SW together, with better TCO, and benefits for both Oracle and the Partner!with Ilkka Vanhanen, Business Development Manager, Oracle EMEA Hardware Strategy Organization, who will talk about:   Concrete examples of the HW/SW TCO Model   Understand the competitive advantage provided by Oracle-on-Oracle Solutions   How Partners get new business from Oracle-on-Oracle Solutions   How Oracle is changing the game in Enterprise IT   Key benefits for both SW Resellers and HW Resellers   To register click here , then click on the “Servers and Solutions Webcasts” tab.          

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  • When using MVVM, should you create new viewmodels, or swap out the models?

    - by ConditionRacer
    Say I have a viewmodel like this: public class EmployeeViewModel { private EmployeeModel _model; public Color BackgroundColor { get; set; } public Name { get { return _model.Name; } set { _model.Name = value; NotifyPropertyChanged(Name); } } } So this viewmodel binds to a view that displays an employee. The thing to think about is, does this viewmodel represent an employee, or a "displayable" employee. The viewmodel contains some things that are view specific, for instance the background color. There can be many employees, but only one employee view. With this in mind, when changing the displayed employee, does it make sense to create a new EmployeeViewModel and rebind to the view, or simply swap out the EmployeeModel. Is the distinction even important, or is it a matter of style? I've always leaned toward creating new viewmodels, but I am working on a project where the viewmodels are created once and the models are swapped out. I'm not sure how I feel about this, though it seems to work fine.

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  • Why the cucumber features keeps running even though it fails?

    - by Millisami
    Its a rails 2.3.5 app. I'm using the rspec and cucumber for testing. When I run autospec, it runs correctly with the warning (Not running features. To run features in autotest, set AUTOFEATURE=true.) as below: [~/rails_apps/automation (campaign)?] ? autospec (Not running features. To run features in autotest, set AUTOFEATURE=true.) (Not running features. To run features in autotest, set AUTOFEATURE=true.) loading autotest/rails_rspec /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/lib/ruby/1.8/pathname.rb:263: warning: `*' interpreted as argument prefix /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/bin/ruby /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/rspec-1.3.0/bin/spec --autospec /home/millisami/rails_apps/automation/spec/controllers/campaigns_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/board_spec.rb /home/millisami/rails_apps/automation/spec/models/user_spec.rb /home/millisami/rails_apps/automation/spec/models/campaign_spec.rb /home/millisami/rails_apps/automation/spec/controllers/outlets_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/boards_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_type_spec.rb /home/millisami/rails_apps/automation/spec/models/vendor_spec.rb /home/millisami/rails_apps/automation/spec/controllers/brands_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/vendors_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/dashboard_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/brand_spec.rb /home/millisami/rails_apps/automation/spec/helpers/dashboard_helper_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_spec.rb /home/millisami/rails_apps/automation/spec/models/client_spec.rb /home/millisami/rails_apps/automation/spec/controllers/clients_controller_spec.rb -O spec/spec.opts Now, as it suggests, when I run AUTOFEATURE=true autospec, the specs runs and the cuke features as well. But the problem is that it won't stop. It runs the features and runs them again and again in a loop. It doesn't stop after it fails. Is this due to the warning Warning: $KCODE is NONE as shown below?? [~/rails_apps/automation (campaign)?] ? AUTOFEATURE=true autospec loading autotest/cucumber_rails_rspec Warning: $KCODE is NONE. /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/treetop-1.4.5/lib/treetop/ruby_extensions/string.rb:31: warning: method redefined; discarding old indent /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/lib/ruby/1.8/pathname.rb:263: warning: `*' interpreted as argument prefix /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/activesupport-2.3.5/lib/active_support/core_ext/object/blank.rb:49: warning: method redefined; discarding old blank? /home/millisami/.rvm/rubies/ree-1.8.7-2010.01/bin/ruby /home/millisami/.rvm/gems/ree-1.8.7-2010.01/gems/rspec-1.3.0/bin/spec --autospec /home/millisami/rails_apps/automation/spec/controllers/campaigns_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/board_spec.rb /home/millisami/rails_apps/automation/spec/models/user_spec.rb /home/millisami/rails_apps/automation/spec/models/campaign_spec.rb /home/millisami/rails_apps/automation/spec/controllers/outlets_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/boards_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_type_spec.rb /home/millisami/rails_apps/automation/spec/models/vendor_spec.rb /home/millisami/rails_apps/automation/spec/controllers/brands_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/vendors_controller_spec.rb /home/millisami/rails_apps/automation/spec/controllers/dashboard_controller_spec.rb /home/millisami/rails_apps/automation/spec/models/brand_spec.rb /home/millisami/rails_apps/automation/spec/helpers/dashboard_helper_spec.rb /home/millisami/rails_apps/automation/spec/models/outlet_spec.rb /home/millisami/rails_apps/automation/spec/models/client_spec.rb /home/millisami/rails_apps/automation/spec/controllers/clients_controller_spec.rb -O spec/spec.opts

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  • Dynamic model choice field in django formset using multiple select elements

    - by Aryeh Leib Taurog
    I posted this question on the django-users list, but haven't had a reply there yet. I have models that look something like this: class ProductGroup(models.Model): name = models.CharField(max_length=10, primary_key=True) def __unicode__(self): return self.name class ProductRun(models.Model): date = models.DateField(primary_key=True) def __unicode__(self): return self.date.isoformat() class CatalogItem(models.Model): cid = models.CharField(max_length=25, primary_key=True) group = models.ForeignKey(ProductGroup) run = models.ForeignKey(ProductRun) pnumber = models.IntegerField() def __unicode__(self): return self.cid class Meta: unique_together = ('group', 'run', 'pnumber') class Transaction(models.Model): timestamp = models.DateTimeField() user = models.ForeignKey(User) item = models.ForeignKey(CatalogItem) quantity = models.IntegerField() price = models.FloatField() Let's say there are about 10 ProductGroups and 10-20 relevant ProductRuns at any given time. Each group has 20-200 distinct product numbers (pnumber), so there are at least a few thousand CatalogItems. I am working on formsets for the Transaction model. Instead of a single select menu with the several thousand CatalogItems for the ForeignKey field, I want to substitute three drop-down menus, for group, run, and pnumber, which uniquely identify the CatalogItem. I'd also like to limit the choices in the second two drop-downs to those runs and pnumbers which are available for the currently selected product group (I can update them via AJAX if the user changes the product group, but it's important that the initial page load as described without relying on AJAX). What's the best way to do this? As a point of departure, here's what I've tried/considered so far: My first approach was to exclude the item foreign key field from the form, add the substitute dropdowns by overriding the add_fields method of the formset, and then extract the data and populate the fields manually on the model instances before saving them. It's straightforward and pretty simple, but it's not very reusable and I don't think it is the right way to do this. My second approach was to create a new field which inherits both MultiValueField and ModelChoiceField, and a corresponding MultiWidget subclass. This seems like the right approach. As Malcolm Tredinnick put it in a django-users discussion, "the 'smarts' of a field lie in the Field class." The problem I'm having is when/where to fetch the lists of choices from the db. The code I have now does it in the Field's __init__, but that means I have to know which ProductGroup I'm dealing with before I can even define the Form class, since I have to instantiate the Field when I define the form. So I have a factory function which I call at the last minute from my view--after I know what CatalogItems I have and which product group they're in--to create form/formset classes and instantiate them. It works, but I wonder if there's a better way. After all, the field should be able to determine the correct choices much later on, once it knows its current value. Another problem is that my implementation limits the entire formset to transactions relating to (CatalogItems from) a single ProductGroup. A third possibility I'm entertaining is to put it all in the Widget class. Once I have the related model instance, or the cid, or whatever the widget is given, I can get the ProductGroup and construct the drop-downs. This would solve the issues with my second approach, but doesn't seem like the right approach.

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  • How to import classes into other classes within the same file in Python

    - by Chris
    I have the file below and it is part of a django project called projectmanager, this file is projectmanager/projects/models.py . Whenever I use the python interpreter to import a Project just to test the functionality i get a name error for line 8 that FileRepo() cannot be found. How Can I import these classes correctly? Ideally what I am looking for is each Project to contain multiple FileRepos which each contain and unknown number of files. Thanks for any assistance in advance. #imports from django.db import models from django.contrib import admin #Project is responsible for ensuring that each project contains all of the folders and file storage #mechanisms a project needs, as well as a unique CCL# class Project(models.Model): ccl = models.CharField(max_length=30) Techpacks = FileRepo() COAS = FileRepo() Shippingdocs = FileRepo() POchemspecs = FileRepo() Internalpos = FileRepo() Finalreports = FileRepo() Batchrecords = FileRepo() RFPS = FileRepo() Businessdev = FileRepo() QA = FileRepo() Updates = FileRepo() def __unicode__(self): return self.ccl #ProjectFile is the file object used by each FileRepo component class ProjectFile(models.Model): file = models.FileField(uploadto='ProjectFiles') def __unicode__(self): return self.file #FileRepo is the model for the "folders" to be used in a Project class FileRepo(models.Model): typeOf = models.CharField(max_length=30) files = models.ManyToManyField(ProjectFile) def __unicode__(self): return self.typeOf

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  • extending django usermodel

    - by imran-glt
    Hi i am trying to create a signup form for my django app. for this i have extended the user model. This is my Forms.py from contact.models import register from django import forms from django.contrib import auth class registerForm(forms.ModelForm): class Meta: model=register fields = ('latitude', 'longitude', 'status') class Meta: model = auth.models.User # this gives me the User fields fields = ('username', 'first_name', 'last_name', 'email') and this is my model.py from django.db import models from django.contrib.auth.models import User STATUS_CHOICES = ( ('Online', 'Online.'), ('Busy', 'Busy.'), ('AppearOffline', 'AppearOffline.'),) class register(models.Model): user = models.ForeignKey('auth.User', unique = True) latitude = models.DecimalField(max_digits=8, decimal_places=6) longitude = models.DecimalField(max_digits=8, decimal_places=6) status = models.CharField(max_length=8,choices=STATUS_CHOICES, blank= True, null=True) i dont know where i am making a mistake. the users passwords are not accepted at the login and the latitude and logitude are not saved against the created user user. i am fiarly new to django and dont know what to do any body have any solution .?

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  • django 1.1 beta issue

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • Why is Django reverse() failing with unicode?

    - by JeffS
    Here is a django models file that is not working as I would expect. I would expect the to_url method to do the reverse lookup in the urls.py file, and get a url that would correspond to calling that view with arguments supplied by the Arguments model. from django.db import models class Element(models.Model): viewname = models.CharField(max_length = 200) arguments = models.ManyToManyField('Argument', null = True, blank = True ) @models.permalink def to_url(self): d = dict( self.arguments.values_list('key', 'value') ) return (self.viewname, (), d) class Argument(models.Model): key = models.CharField(max_length=200) value = models.CharField(max_length=200) The value d ends up as a dictionary from a unicode string to another unicode string, which I believe, should work fine with the reverse() method that would be called by the permalink decorator, however, it results in: TypeError: reverse() keywords must be strings

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  • django admin gives warning "Field 'X' doesn't have a default value"

    - by noam
    I have created two models out of an existing legacy DB , one for articles and one for tags that one can associate with articles: class Article(models.Model): article_id = models.AutoField(primary_key=True) text = models.CharField(max_length=400) class Meta: db_table = u'articles' class Tag(models.Model): tag_id = models.AutoField(primary_key=True) tag = models.CharField(max_length=20) article=models.ForeignKey(Article) class Meta: db_table = u'article_tags' I want to enable adding tags for an article from the admin interface, so my admin.py file looks like this: from models import Article,Tag from django.contrib import admin class TagInline(admin.StackedInline): model = Tag class ArticleAdmin(admin.ModelAdmin): inlines = [TagInline] admin.site.register(Article,ArticleAdmin) The interface looks fine, but when I try to save, I get: Warning at /admin/webserver/article/382/ Field 'tag_id' doesn't have a default value

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