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  • Pretty-printing of numpy.array

    - by camillio
    Hello, I'm curious, whether there is any way to print formated numpy.arrays, e.g., in the way similar to this: x = 1.23456 print '%.3f' % x If I want to print the numpy.array of floats, it prints several decimals, often in 'scientific' format, which is rather hard to read even for low-dimensional arrays. However, numpy.array apparently has to be printed as a string, i.e., with %s. Is there any solution ready for this purpose? Many thanks in advance :-)

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  • Pulling data and printing it in an HTML table

    - by John
    Hello, From a MySQL table called "submission" containing the fields "loginid, submissionid, title, url, datesubmitted, displayurl", I would like to print an HTML table thats contains all "title" and corresponding "datesubmitted" where "loginid" equals "$profile." The code I am trying to use is below. It isn't working. Any ideas why it isn't working? Thanks in advance, John $profile = $_GET['profile']; $sqlStr = "SELECT loginid, submissionid, title, url, datesubmitted, displayurl FROM submission WHERE loginid = $profile ORDER BY datesubmitted DESC"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2">'.$row["datesubmitted"].'</a></td>'; echo '</tr>'; } echo "</table>";

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  • Printing double variable contents

    - by Adil
    I tried following code snippet and output is surprising me: #include <stdio.h> #include <math.h> int main() { double num; unsigned char ch; ch = 19; num = 1.0E+20 ; num += ch * 1.0E+18; printf("E18 = %lf \n",num); printf("E18 = %e \n",num); num = 11.0E+21 ; num += ch * 1.0E+19; printf("E19 = %lf <------\n",num); printf("E19 = %e <------\n",num); num = 11.0E+22 ; num += ch * 1.0E+20; printf("E20 = %lf\n",num); printf("E20 = %e\n",num); num = 11.0E+23 ; num += ch * 1.0E+21; printf("E21 = %lf\n",num); printf("E21 = %e\n",num); num = 11.0E+24 ; num += ch * 1.0E+22; printf("E22 = %lf <------\n",num); printf("E22 = %e <------\n",num); return 0; } The output of the program: E18 = 119000000000000000000.000000 E18 = 1.190000e+20 E19 = 11190000000000000524288.000000 <------ E19 = 1.119000e+22 <------ E20 = 111900000000000001048576.000000 E20 = 1.119000e+23 E21 = 1119000000000000044040192.000000 E21 = 1.119000e+24 E22 = 11189999999999999366660096.000000 <------ E22 = 1.119000e+25 <------ Why the data corrupted when printed while in exponent form its OK

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  • printing ant target execution time

    - by Nirmal Patel
    I want to print the execution time taken for each individual ANT target and its dependent targets. <target name="target1" depends="target2, target3"> .... </target> When run should show following output Target 2 - x seconds Target 3 - y seconds Target 1 - z seconds Any suggestions on how to achieve this?

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  • C# Printing Properties

    - by Mark
    I have a class like this with a bunch of properties: class ClassName { string Name {get; set;} int Age {get; set;} DateTime BirthDate {get; set;} } I would like to print the name of the property and it's value using the value's ToString() method and the Property's name like this: ClassName cn = new ClassName() {Name = "Mark", Age = 428, BirthData = DateTime.Now} cn.MethodToPrint(); // Output // Name = Mark, Age = 428, BirthDate = 12/30/2010 09:20:23 PM Reflection is perfectly okay, in fact I think it is probably required. I'd also be neat if it could somehow work on any class through some sort of inheritance. I'm using 4.0 if that matters.

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  • LaTeX printing only first two pages of a document

    - by Peter Flom
    I am working in LaTeX, and when I create a pdf file (using LaTeX button or pdfLaTeX button or using yap) the pdf has only the first two pages. No errors. It just stops. If I make the first page longer by adding text, it still stops at end of 2nd page. Any ideas? OK, responding to first comment, here is the code \documentclass{article} \title{Outline of Book} \author{Peter L. Flom} \begin{document} \maketitle \section*{Preface} \subsection*{Audience} \subsection*{What makes this book different?} \subsection*{Necessary background} \subsection*{How to read this book} \section{Introduction} \subsection{The purpose of logistic regression} \subsection{The need for logistic regression} \subsection{Types of logistic regression} \section{General issues in logistic regression} \subsection{Transforming independent and dependent variables} \subsection{Interactions} \subsection{Model selection} \subsection{Parameter estimates, confidence intervals, p values} \subsection{Summary and further reading} \section{Dichotomous logistic regression} \subsection{Introduction, theory, examples} \subsection{Exploratory plots and analysis} \subsection{Basic model fitting} \subsection{Advanced and special issues in model fitting} \subsection{Diagnostic and descriptive plots and analysis} \subsection{Traps and gotchas} \subsection{Power analysis} \subsection{Summary and further reading} \subsection{Exercises} \section{Ordinal logistic regression} \subsection{Introduction, theory, examples} \subsubsection{Introduction - what are ordinal variables?} \subsubsection{Theory of the model} \subsubsection{Examples for this chapter} \subsection{Exploratory plots and analysis} \subsection{Basic model fitting} \subsection{Advanced and special issues in model fitting} \subsection{Diagnostic and descriptive plots and analysis} \subsection{Traps and gotchas} \subsection{Power analysis} \subsection{Summary and further reading} \subsection{Exercises} \section{Multinomial logistic regression} \subsection{Introduction, theory, examples} \subsection{Exploratory plots and analysis} \subsection{Basic model fitting} \subsection{Advanced and special issues in model fitting} \subsection{Diagnostic and descriptive plots and analysis} \subsection{Traps and gotchas} \subsection{Power analysis} \subsection{Summary and further reading} \subsection{Exercises} \section{Choosing a model} \subsection{NOIR and its problems} \subsection{Linear vs. ordinal} \subsection{Ordinal vs. multinomial} \subsection{Summary and further reading} \subsection{Exercises} \section{Extensions and related models} \subsection{Other logistic models} \subsection{Multilevel models - PROC NLMIXED and GLIMMIX} \subsection{Loglinear models - PROC CATMOD} \section{Summary} \end{document} thanks Peter

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  • Printing Arrays from Structs

    - by Carlll
    I've been stumped for a few hours on an exercise where I must use functions to build up an array inside a struct and print it. In my current program, it compiles but crashes upon running. #define LIM 10 typedef char letters[LIM]; typedef struct { int counter; letters words[LIM]; } foo; int main(int argc, char **argv){ foo apara; structtest(apara, LIM); print_struct(apara); } int structtest(foo *p, int limit){ p->counter = 0; int i =0; for(i; i< limit ;i++){ strcpy(p->words[p->counter], "x"); //only filling arrays with 'x' as an example p->counter ++; } return; I do believe it's due to my incorrect usage/combination of pointers. I've tried adjusting them, but either an 'incompatible types' error is produced, or the array is seemingly blank } void print_struct(foo p){ printf(p.words); } I haven't made it successfully up to the print_struct stage, but I'm unsure whether p.words is the correct item to be calling. In the output, I would expect the function to return an array of x's. I apologize in advance if I've made some sort of grievous "I should already know this" C mistake. Thanks for your help.

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  • Printing elements out of list

    - by chavanak
    Hi, I have a certain check to be done and if the check satisfies, I want the result to be printed. Below is the code: import string import codecs import sys y=sys.argv[1] list_1=[] f=1.0 x=0.05 write_in = open ("new_file.txt", "w") write_in_1 = open ("new_file_1.txt", "w") ligand_file=open( y, "r" ) #Open the receptor.txt file ligand_lines=ligand_file.readlines() # Read all the lines into the array ligand_lines=map( string.strip, ligand_lines ) #Remove the newline character from all the pdb file names ligand_file.close() ligand_file=open( "unique_count_c_from_ac.txt", "r" ) #Open the receptor.txt file ligand_lines_1=ligand_file.readlines() # Read all the lines into the array ligand_lines_1=map( string.strip, ligand_lines_1 ) #Remove the newline character from all the pdb file names ligand_file.close() s=[] for i in ligand_lines: for j in ligand_lines_1: j = j.split() if i == j[1]: print j The above code works great but when I print j, it prints like ['351', '342'] but I am expecting to get 351 342 (with one space in between). Since it is more of a python question, I have not included the input files (basically they are just numbers). Can anyone help me? Cheers, Chavanak

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  • printing invoices

    - by stuarty
    Hi I have invoice data stored in SQL now I want to print those invoices, It would probably take me less than an hour to print them manually but that is not the point I want to do it programmatically using c# What is the quickest simplest way? Excel? Links to some examples? TIA Stuart

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  • Printing the exact content of a text file in java

    - by Benjamin
    I want to print the content of a simple text file in java exactly the way the text appears in the text file. The print out has the same content as the text file but the format is not the same. tabs and line breaks are ignored in the print out. Any help will be very much appreciated.

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  • Printing the exact content of a text file in java

    - by Benjamin
    I want to print the content of a simple text file in java exactly the way the text appears in the text file. The print out has the same content as the text file but the format is not the same. tabs and line breaks are ignored in the print out. Any help will be very much appreciated.

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  • java xml pretty printing - preserve empty elements and white pace

    - by javamonkey79
    Basically, I am looking for a java library that will take this: <foo><bar> </bar><baz>yadda</baz></foo> And pretty print it to this: <?xml version="1.0" encoding="UTF-8"?> <foo> <bar> </bar> <baz>yadda</baz> </foo> e.g. preserving whitespace AND blank elements The closest I have got was with dom4j like so: OutputFormat format = OutputFormat.createPrettyPrint(); format.setTrimText( false ); However, this does not honor the whitespace unless the element contains other character data. I'm not opposed to writing something on my own, but I would think this has already been done, why reinvent the wheel?

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  • printing sequence number of a sniffed packet

    - by scatman
    i am using pcap to create a packet sniffer. i have this tcp structure: typedef struct TSP_header{ unsigned short int sport; unsigned short int dport; unsigned int seqnum; unsigned int acknum; unsigned char reserved:4, offset:4; unsigned int tcp_res1:4, //little-endian tcph_hlen:4, //length of tcp header in 32-bit words tcph_fin:1, //Finish flag "fin" tcph_syn:1, //Synchronize sequence numbers to start a connection tcph_rst:1, //Reset flag tcph_psh:1, //Push, sends data to the application tcph_ack:1, //acknowledge tcph_urg:1, //urgent pointer tcph_res2:2; unsigned short int tcph_win; unsigned short int tcph_chksum; unsigned short int tcph_urgptr; }TSP_header; how can i print the sequence number? shou i use htons(sequence_number)?? coz it isn't working this way!!

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  • printing out prime numbers from array

    - by landscape
    I'd like to print out all prime numbers from an array with method. I can do it with one int but don't know how to return certain numbers from array. Thanks for help! public static boolean isPrime(int [] tab) { boolean prime = true; for (int i = 3; i <= Math.sqrt(tab[i]); i += 2) if (tab[i] % i == 0) { prime = false; break; } for(int i=0; i<tab.length; i++) if (( tab[i]%2 !=0 && prime && tab[i] > 2) || tab[i] == 2) { return true; } else { return false; } //return prime; } thanks both of you. Seems like its solved: public static void isPrime(int[] tab) { for (int i = 0; i < tab.length; i++) { if (isPrimeNum(tab[i])) { System.out.println(tab[i]); } } } public static boolean isPrimeNum(int n) { boolean prime = true; for (long i = 3; i <= Math.sqrt(n); i += 2) { if (n % i == 0) { prime = false; break; } } if ((n % 2 != 0 && prime && n > 2) || n == 2) { return true; } else { return false; } }

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  • Printing out this week's dates in perl

    - by ABach
    Hi folks, I have the following loop to calculate the dates of the current week and print them out. It works, but I am swimming in the amount of date/time possibilities in perl and want to get your opinion on whether there is a better way. Here's the code I've written: #!/usr/bin/env perl use warnings; use strict; use DateTime; # Calculate numeric value of today and the # target day (Monday = 1, Sunday = 7); the # target, in this case, is Monday, since that's # when I want the week to start my $today_dt = DateTime->now; my $today = $today_dt->day_of_week; my $target = 1; # Create DateTime copies to act as the "bookends" # for the date range my ($start, $end) = ($today_dt->clone(), $today_dt->clone()); if ($today == $target) { # If today is the target, "start" is already set; # we simply need to set the end date $end->add( days => 6 ); } else { # Otherwise, we calculate the Monday preceeding today # and the Sunday following today my $delta = ($target - $today + 7) % 7; $start->add( days => $delta - 7 ); $end->add( days => $delta - 1 ); } # I clone the DateTime object again because, for some reason, # I'm wary of using $start directly... my $cur_date = $start->clone(); while ($cur_date <= $end) { my $date_ymd = $cur_date->ymd; print "$date_ymd\n"; $cur_date->add( days => 1 ); } As mentioned, this works - but is it the quickest/most efficient/etc.? I'm guessing that quickness and efficiency may not necessarily go together, but your feedback is very appreciated.

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  • Printing a sideways triangle in java

    - by Will
    I'm trying to print a sideways triangle in java. If the user enters 5, the output should be: * *** ***** *** * If the user enters 6, the output should be: * *** ***** ***** *** * I've gotten it to work for the case when the user enters 5, 3, or 1 but my code seems to work for those three cases only. I was wondering if anyone could help me get my code working for more cases. Here it is: public void printArrow( int n ) { int asterisks = 1; for ( int i = 0; i <= n/2; i++ ) { for ( int j = i; j < asterisks; j++ ) { System.out.print( "*" ); } asterisks += 3; System.out.println(); } asterisks = asterisks / 2 - 2; for ( int i = 0; i < n/2; i++ ) { for ( int k = i; k < asterisks; k++ ) { System.out.print( "*" ); } if ( i == 1 ) { System.out.print( "*" ); } asterisks -= 2; System.out.println(); } }

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  • Printing HTML blocks

    - by Lem0n
    I have a page with a few tables that I want to be printable. I want the following behaviour: 1) Add a page break if the next table fits in a single page, but won't fit in the current page (because of other stuff already printed on this page) 2) Print the "table header" again in case it's needed to break a table (I guess it's the default behaviour) Any ideas specially on the first issue? Maybe some CSS can help? I'll give on example. I have a page with 4 tables. All of them with 10 lines, except the third one, with 50 lines. The first and second goes on the first page. Since the third one won't fit in the same page, but will fit in a page alone, it's printed on a page alone... and then the forth table is printed on the third page (in case it doesn't fit together in the second page). But, if the third page had 300 lines and would be broke anyway, it could have started to be print in the first page.

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  • Programmatically printing git revision and checking for uncommitted changes

    - by Andrew Grimm
    To ensure that my scientific analysis is reproducible, I'd like to programmatically check if there are any modifications to the code base that aren't checked in, and if not, print out what commit is being used. For example, if there are uncommitted changes, it should output Warning: uncommitted changes made. This output may not be reproducible. Else, produce Current commit: d27ec73cf2f1df89cbccd41494f579e066bad6fe Ideally, it should use "plumbing", not "porcelain".

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  • Printing Instance ID to NSLog?

    - by fuzzygoat
    In the dealloc method for a class how would I print out the ID (or some other unique identifier) for the instance being deallocated? - (void)dealloc { NSLog(@"_deallocing: ??"); [super dealloc]; } Is this possible? I am just trying to get a little more feedback in the console as an aid to learning. many thanks -gary-

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  • c printing string syntax

    - by user535256
    Hello guys, Just stuck on c syntax regarding strings. Say I have a string like (name[5]="peter";) in c say if I just wanted to print the last character of string or check the last character of the string, which in this case would be 'r' how can I do this? The way I was thinking does not seem to work name[5]="peter"; if(name[5]=="r") printf("last character of name is r"); Question: is there some sort of function to do this that can check one character of array, is a certain value, like name[5] is 'r' in string peter or likewise name[1] is 'n' Also how do I use printf to print that certain char, having problems using printf("last character of name is %s",name[5]) ??? Thanks

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  • printing reverse in singly link list using pointers

    - by theoneabhinav
    i have been trying this code. i think the logic is ok but the program terminates abruptly when the display_rev function is called here is code of display_rev void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } } here is my whole code #include<stdio.h> #include<stdlib.h> #include<ctype.h> #include<string.h> //Declarations=============================================================== typedef struct //employee record { int emp_id; char name[150]; char mob_no[11]; float salary; int proj[5]; struct emp_node *next; } emp_node; emp_node* add_rec(emp_node*); emp_node* create_db(emp_node*); emp_node* search_db(emp_node*, int); emp_node* delete_rec(emp_node*, int); void read_name(emp_node*); void read_mob(emp_node*); void display_db(emp_node*); void display_rec(emp_node*); void display_rev(emp_node*); void modify_rec(emp_node*); void swtch(emp_node*); //=========================================================================== int main() { char ans; emp_node *head = NULL; head = create_db(head); display_db(head); do { swtch(head); printf("\n\n\tDo you want to continue (y/n) : "); getchar(); scanf("%c", &ans); } while (ans == 'y' || ans == 'Y'); return 0; } //Definitions================================================================ emp_node* create_db(emp_node *head) //database creation { int i = 1, no; emp_node *p; printf("Enter number of employees:"); scanf("%d", &no); printf("\n\n"); head = (emp_node *) malloc(sizeof(emp_node)); head = add_rec(head); head->next = NULL; p = head; while (i < no) { p->next = (emp_node *) malloc(sizeof(emp_node)); p = p->next; p = add_rec(p); p->next = NULL; i++; } return head; } emp_node* add_rec(emp_node *p) //new record { int j; printf("\n\tEmployee ID : "); scanf("%d", &(p->emp_id)); printf("\n\tFirst Name:"); read_name(p); printf("\n\tMobile No.:"); read_mob(p); printf("\n\tSalary :"); scanf("%f", &(p->salary)); printf( "\n\tEnter \"1\" for the projects employee is working on, otherwise enter \"0\": \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1 && p->proj[j] != 0) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } printf("\n\n\n"); return p; } void read_name(emp_node *p) //validation for name { int j, len; scanf("%s", p->name); len = strlen(p->name); for (j = 0; j < len; j++) { if (!isalpha(p->name[j])) { printf( "\n\n\tInvalid name!!Can contain only characters. Please Re-enter.\n"); printf("\n\tName : "); read_name(p); } } } void read_mob(emp_node *p) //validation for mobile no. { int j; scanf("%s", p->mob_no); while (strlen(p->mob_no) != 10) { printf("\n\nInvalid Mobile No!!Please Re-enter"); printf("\n\n\tMobile No.:"); read_mob(p); } for (j = 0; j < 10; j++) { if (!(48 <= p->mob_no[j] && p->mob_no[j] <= 57)) { printf( "\n\nInvalid Mobile No!!Can contain only digits. Please Re-enter."); printf("\n\n\tMobile No.:"); read_mob(p); } } } void display_db(emp_node *head) //displaying whole database { emp_node *p; p = head; printf("\n\n\t\t****** EMPLOYEE DATABASE ******\n"); printf( "\n=============================================================================="); printf("\n Id.\t Name\t\t Mobile No\t Salary\t Projects\n"); while (p != NULL) { display_rec(p); p = p->next; printf("\n\n\n"); } printf( "\n=============================================================================="); } void swtch(emp_node *head) //function for menu and switch case { int cho, x; emp_node *p; printf("\n\n\t\t****** MENU ******"); printf( "\n\n\t1. insert Record\n\t2. Search Record\n\t3. Modify Record\n\t4. Delete Record\n\t5. Display Reverse\n\t6. Exit"); printf("\n\tWhich operation do you want to perform? "); scanf("%d", &cho); switch (cho) { case 1: p=head; while(p->next != NULL) p=p->next; p->next = (emp_node *) malloc(sizeof(emp_node)); p=p->next; p = add_rec(p); p->next = NULL; display_db(head); break; case 2: printf("\n\n\tEnter employee ID whose record is to be Searched :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else display_rec(p); break; case 3: printf("\n\n\tEnter employee ID whose record is to be modified :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else modify_rec(p); display_db(head); break; case 4: printf("\n\n\tEnter employee ID whose record is to be deleted :"); scanf("%d", &x); head = delete_rec(head, x); display_db(head); break; case 5: display_rev(head); case 6: exit(0); default: printf("Invalid Choice!! Please try again."); } } emp_node* search_db(emp_node *head, int id) //search database { emp_node *p = head; while (p != NULL) { if (p->emp_id == id) return p; p = p->next; } return NULL; } void display_rec(emp_node *p) //display a single record { int j; printf("\n %d", p->emp_id); printf("\t %10s", p->name); printf("\t %10s", p->mob_no); printf("\t %05.2f", p->salary); printf("\t "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } } void modify_rec(emp_node *p) //modifying a record { int j, cho; char ch1, edt; do { printf( "\n\t1. Name\n\t2. Email Address\n\t3. Mobile No.\n\t4. Salary\n\t5. Date of birth\n\t6. Projects\n"); printf("Enter your choice : "); scanf("%d", &cho); switch (cho) { case 1: printf("\n\tPrevious name:%s", p->name); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Name:"); read_name(p); } break; case 2: printf("\n\tPrevious Mobile No. : %s", p->mob_no); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Mobile No. :"); read_mob(p); } break; case 3: printf("\n\tPrevious salary is : %f", p->salary); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New salary:"); scanf("%f", &(p->salary)); } break; case 4: printf("the employee is currently working on project no. "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf( "\n\tEnter \"1\" for the projects employee is working on : \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } } break; default: printf("\n\nInvalid Choice!! Please Try again."); } printf("\n\nDo you want to edit any other fields ?(y/n)"); getchar(); scanf("%c", &edt); } while (edt == 'y' || edt == 'Y'); } emp_node* delete_rec(emp_node *head, int id) //physical deletion of record { emp_node *p = head, *q; if (head->emp_id == id) { head = head->next; free(p); return head; } else { q = p->next; while (q->emp_id != id) { p = p->next; q = q->next; } if (q->next == NULL) p->next = NULL; else p->next = q->next; free(q); return head; } } void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } }

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