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  • ?Oracle????SELECT????UNDO

    - by Liu Maclean(???)
    ????????Oracle?????(dirty read),?Oracle??????Asktom????????Oracle???????, ???undo??????????(before image)??????Consistent, ???????????????Oracle????????????? ????????? ??,??,Oracle?????????????RDBMS,???????????? ?????????2?????: _offline_rollback_segments or _corrupted_rollback_segments ?2?????????Oracle???????????ORA-600[4XXX]???????????????,???2??????Undo??Corruption????????????,?????2????????????????? ??????????????_offline_rollback_segments ? _corrupted_rollback_segments ?2?????: ???????(FORCE OPEN DATABASE) ????????????(consistent read & delayed block cleanout) ??????rollback segment??? ?????:???????Oracle????????,??????????2?????,?????????????!! _offline_rollback_segments ? _corrupted_rollback_segments ???????????: ??2???????Undo Segments(???/???)????????online ?UNDO$???????????OFFLINE??? ???instance??????????????????? ??????Undo Segments????????active transaction????????????dead??SMON???(????????SMON??(?):Recover Dead transaction) _OFFLINE_ROLLBACK_SEGMENTS(offline undo segment list)????(hidden parameter)?????: ???startup???open database???????_OFFLINE_ROLLBACK_SEGMENTS????Undo segments(???/???),?????undo segments????????alert.log???TRACE?????,???????startup?? ?????????????,?ITL?????undo segments?: ???undo segments?transaction table?????????????????? ???????????commit,?????CR??? ????undo segments????(???corrupted??,???missed??)???????????alert.log,??????? ?DML?????????????????????????????????CPU,????????????????????? _CORRUPTED_ROLLBACK_SEGMENTS(corrupted undo segment list)??????????: ?????startup?open database???_CORRUPTED_ROLLBACK_SEGMENTS????undo segments(???/???)???????? ???????_CORRUPTED_ROLLBACK_SEGMENTS???undo segments????????????commit,???undo segments???drop??? ??????????? ??????????????????,?????????????????? ??bootstrap???????????,?????????ORA-00704: bootstrap process failure??,???????????(???Oracle????:??ORA-00600:[4000] ORA-00704: bootstrap process failure????) ??????_CORRUPTED_ROLLBACK_SEGMENTS????????????????????,??????????????? Oracle???????TXChecker??????????? ???????2?????,??????????????_CORRUPTED_ROLLBACK_SEGMENTS?????SELECT????UNDO???????: SQL> alter system set event= '10513 trace name context forever, level 2' scope=spfile; System altered. SQL> alter system set "_in_memory_undo"=false scope=spfile; System altered. 10513 level 2 event????SMON ??rollback ??? dead transaction _in_memory_undo ?? in memory undo ?? SQL> startup force; ORACLE instance started. Total System Global Area 3140026368 bytes Fixed Size 2232472 bytes Variable Size 1795166056 bytes Database Buffers 1325400064 bytes Redo Buffers 17227776 bytes Database mounted. Database opened. session A: SQL> conn maclean/maclean Connected. SQL> create table maclean tablespace users as select 1 t1 from dual connect by level exec dbms_stats.gather_table_stats('','MACLEAN'); PL/SQL procedure successfully completed. SQL> set autotrace on; SQL> select sum(t1) from maclean; SUM(T1) ---------- 501 Execution Plan ---------------------------------------------------------- Plan hash value: 1679547536 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 3 | 3 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 3 | | | | 2 | TABLE ACCESS FULL| MACLEAN | 501 | 1503 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------ Statistics ---------------------------------------------------------- 1 recursive calls 0 db block gets 3 consistent gets 0 physical reads 0 redo size 515 bytes sent via SQL*Net to client 492 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processe ???????????,????current block, ????????,consistent gets??3? SQL> update maclean set t1=0; 501 rows updated. SQL> alter system checkpoint; System altered. ??session A?commit; ???? session: SQL> conn maclean/maclean Connected. SQL> SQL> set autotrace on; SQL> select sum(t1) from maclean; SUM(T1) ---------- 501 Execution Plan ---------------------------------------------------------- Plan hash value: 1679547536 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 3 | 3 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 3 | | | | 2 | TABLE ACCESS FULL| MACLEAN | 501 | 1503 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------ Statistics ---------------------------------------------------------- 0 recursive calls 0 db block gets 505 consistent gets 0 physical reads 108 redo size 515 bytes sent via SQL*Net to client 492 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed ?????? ?????????undo??CR?,???consistent gets??? 505 [oracle@vrh8 ~]$ ps -ef|grep LOCAL=YES |grep -v grep oracle 5841 5839 0 09:17 ? 00:00:00 oracleG10R25 (DESCRIPTION=(LOCAL=YES)(ADDRESS=(PROTOCOL=beq))) [oracle@vrh8 ~]$ kill -9 5841 ??session A???Server Process????,???dead transaction ????smon?? select ktuxeusn, to_char(sysdate, 'DD-MON-YYYY HH24:MI:SS') "Time", ktuxesiz, ktuxesta from x$ktuxe where ktuxecfl = 'DEAD'; KTUXEUSN Time KTUXESIZ KTUXESTA ---------- -------------------- ---------- ---------------- 2 06-AUG-2012 09:20:45 7 ACTIVE ???1?active rollback segment SQL> conn maclean/maclean Connected. SQL> set autotrace on; SQL> select sum(t1) from maclean; SUM(T1) ---------- 501 Execution Plan ---------------------------------------------------------- Plan hash value: 1679547536 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 3 | 3 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 3 | | | | 2 | TABLE ACCESS FULL| MACLEAN | 501 | 1503 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------ Statistics ---------------------------------------------------------- 0 recursive calls 0 db block gets 411 consistent gets 0 physical reads 108 redo size 515 bytes sent via SQL*Net to client 492 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed ????? ????kill?? ???smon ??dead transaction , ???????????? ?????undo??????? ????active?rollback segment??? SQL> select segment_name from dba_rollback_segs where segment_id=2; SEGMENT_NAME ------------------------------ _SYSSMU2$ SQL> alter system set "_corrupted_rollback_segments"='_SYSSMU2$' scope=spfile; System altered. ? _corrupted_rollback_segments ?? ???2?rollback segment, ????????undo SQL> startup force; ORACLE instance started. Total System Global Area 3140026368 bytes Fixed Size 2232472 bytes Variable Size 1795166056 bytes Database Buffers 1325400064 bytes Redo Buffers 17227776 bytes Database mounted. Database opened. SQL> conn maclean/maclean Connected. SQL> set autotrace on; SQL> select sum(t1) from maclean; SUM(T1) ---------- 94 Execution Plan ---------------------------------------------------------- Plan hash value: 1679547536 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 3 | 3 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 3 | | | | 2 | TABLE ACCESS FULL| MACLEAN | 501 | 1503 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------ Statistics ---------------------------------------------------------- 228 recursive calls 0 db block gets 29 consistent gets 5 physical reads 116 redo size 514 bytes sent via SQL*Net to client 492 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 4 sorts (memory) 0 sorts (disk) 1 rows processed SQL> / SUM(T1) ---------- 94 Execution Plan ---------------------------------------------------------- Plan hash value: 1679547536 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 3 | 3 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 3 | | | | 2 | TABLE ACCESS FULL| MACLEAN | 501 | 1503 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------ Statistics ---------------------------------------------------------- 0 recursive calls 0 db block gets 3 consistent gets 0 physical reads 0 redo size 514 bytes sent via SQL*Net to client 492 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed ?????? consistent gets???3,?????????????????,??ITL???UNDO SEGMENTS?_corrupted_rollback_segments????,???????????COMMIT??,????UNDO? ???????,?????????????????????????(????????????????????),????????????????? ???? , ?????

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  • Why doesn't interface inheritance work when writing shell extensions in c#?

    - by Factor Mystic
    According to this article about writing shell extensions in .Net, inheriting the shell interfaces as you might naturally do when writing code doesn't work. I've observed this in my own code as well. Doesn't work: public interface IPersist { // stuff specific only to IPersist } public interface IPersistFolder : IPersist { // stuff specific only to IPersistFolder } Does work: public interface IPersistFolder { // stuff specific to IPersist only // stuff specific to IPersistFolder only } The article notes this fact: Lo and behold, it worked! Notice that I've abandoned any idea that IPersistFolder is inherited from anything at all and just included the stubs from IPersist right in its definition. In all candor, I can't tell you why this is but it definitely works just fine and shouldn't give you any problems. So my I'll ask the question this guy didn't know; why didn't the original code work?

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  • Using a 64bit Linux kernel, can't see more than 4GB of RAM in /proc/meminfo

    - by Chris Huang-Leaver
    I'm running my new computer which has 8GB of RAM installed, which is visable from BIOS page, does not show in /proc/meminfo uname -a Linux localhost 3.0.6-gentoo #2 SMP PREEMPT Sat Nov 19 10:45:22 GMT-- x86_64 AMD Phenom(tm) II X4 955 Processor AuthenticAMD GNU/Linux The result of /proc/meminfo is as follows: (thans Andrey) MemTotal: 4021348 kB MemFree: 1440280 kB Buffers: 23696 kB Cached: 1710828 kB SwapCached: 4956 kB Active: 1389904 kB Inactive: 841364 kB Active(anon): 1337812 kB Inactive(anon): 714060 kB Active(file): 52092 kB Inactive(file): 127304 kB Unevictable: 32 kB Mlocked: 32 kB SwapTotal: 8388604 kB SwapFree: 8047900 kB Dirty: 0 kB Writeback: 0 kB AnonPages: 492732 kB Mapped: 47528 kB Shmem: 1555120 kB Slab: 267724 kB SReclaimable: 177464 kB SUnreclaim: 90260 kB KernelStack: 1176 kB PageTables: 12148 kB NFS_Unstable: 0 kB Bounce: 0 kB WritebackTmp: 0 kB CommitLimit: 10399276 kB Committed_AS: 3293896 kB VmallocTotal: 34359738367 kB VmallocUsed: 317008 kB VmallocChunk: 34359398908 kB AnonHugePages: 120832 kB HugePages_Total: 0 HugePages_Free: 0 HugePages_Rsvd: 0 HugePages_Surp: 0 Hugepagesize: 2048 kB DirectMap4k: 23552 kB DirectMap2M: 3088384 kB DirectMap1G: 1048576 kB I have tried using mem=8G as a kernel boot parameter, I read a post about setting HIGHMEM64G to yes, before realising that only applies to 32bit kernels. Trying dmindecode -t memory SMBIOS 2.7 present. Handle 0x0026, DMI type 16, 23 bytes Physical Memory Array Location: System Board Or Motherboard Use: System Memory Error Correction Type: Multi-bit ECC Maximum Capacity: 32 GB Error Information Handle: Not Provided Number Of Devices: 4 Handle 0x0028, DMI type 17, 34 bytes Memory Device Array Handle: 0x0026 Error Information Handle: Not Provided Total Width: 64 bits Data Width: 64 bits Size: 4096 MB Form Factor: DIMM Set: None Locator: DIMM0 Bank Locator: BANK0 Type: <OUT OF SPEC> Type Detail: Synchronous Speed: 1333 MHz Manufacturer: Manufacturer0 Serial Number: SerNum0 Asset Tag: AssetTagNum0 Part Number: Array1_PartNumber0 Rank: Unknown Handle 0x002A, DMI type 17, 34 bytes Memory Device Array Handle: 0x0026 Error Information Handle: Not Provided Total Width: Unknown Data Width: 64 bits Size: No Module Installed Form Factor: DIMM Set: None Locator: DIMM1 Bank Locator: BANK1 Type: Unknown Type Detail: Synchronous Speed: Unknown Manufacturer: Manufacturer1 Serial Number: SerNum1 Asset Tag: AssetTagNum1 Part Number: Array1_PartNumber1 Rank: Unknown Handle 0x002C, DMI type 17, 34 bytes Memory Device Array Handle: 0x0026 Error Information Handle: Not Provided Total Width: 64 bits Data Width: 64 bits Size: 4096 MB Form Factor: DIMM Set: None Locator: DIMM2 Bank Locator: BANK2 Type: <OUT OF SPEC> Type Detail: Synchronous Speed: 1333 MHz Manufacturer: Manufacturer2 Serial Number: SerNum2 Asset Tag: AssetTagNum2 Part Number: Array1_PartNumber2 Rank: Unknown Handle 0x002E, DMI type 17, 34 bytes Memory Device Array Handle: 0x0026 Error Information Handle: Not Provided Total Width: Unknown Data Width: 64 bits Size: No Module Installed Form Factor: DIMM Set: None Locator: DIMM3 Bank Locator: BANK3 Type: Unknown Type Detail: Synchronous Speed: Unknown Manufacturer: Manufacturer3 Serial Number: SerNum3 Asset Tag: AssetTagNum3 Part Number: Array1_PartNumber3 Rank: Unknown

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  • install software in linux as a non root user

    - by Aki
    Hi, What is the best way to install software in a linux machine if you dont have root permissions. I know that we can use few variables like PKG_CONFIG_PATH and switches like --prefix with configure to get a software installed in a local directory, but sometimes when there are recursive dependencies it is becoming tough for me to install all the packages manually. Is there a better automated way? Update: What i meant by recursive dependencies is: to install package A, i should install package B, which in turn requires package C to be installed

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  • resize image in asp.net

    - by alina
    I have this code to resize an image but the image doesn't look so good: public Bitmap ProportionallyResizeBitmap(Bitmap src, int maxWidth, int maxHeight) { // original dimensions int w = src.Width; int h = src.Height; // Longest and shortest dimension int longestDimension = (w > h) ? w : h; int shortestDimension = (w < h) ? w : h; // propotionality float factor = ((float)longestDimension) / shortestDimension; // default width is greater than height double newWidth = maxWidth; double newHeight = maxWidth / factor; // if height greater than width recalculate if (w < h) { newWidth = maxHeight / factor; newHeight = maxHeight; } // Create new Bitmap at new dimensions Bitmap result = new Bitmap((int)newWidth, (int)newHeight); using (Graphics g = Graphics.FromImage((System.Drawing.Image)result)) g.DrawImage(src, 0, 0, (int)newWidth, (int)newHeight); return result; }

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  • Can someone describe through code a practical example of backtracking with iteration instead of recursion?

    - by chrisapotek
    Recursion makes backtracking easy as it guarantees that you won't go through the same path again. So all ramifications of your path are visited just once. I am trying to convert a backtracking tail-recursive (with accumulators) algorithm to iteration. I heard it is supposed to be easy to convert a perfectly tail-recursive algorithm to iteration. But I am stuck in the backtracking part. Can anyone provide a example through code so myself and others can visualize how backtracking is done? I would think that a STACK is not needed here because I have a perfectly tail-recursive algorithm using accumulators, but I can be wrong here.

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  • T-Sql Modify Insert SProc To Update If Exists.

    - by Goober
    Scenario I have a stored procedure written in T-Sql that I use to insert data into a table as XML. Since the data gets updated regularly, I want the rows to be updated if they already exist (Aside from when the application is first run, they will always exist). Question Below is the code of my Insert Sproc, however I cannot seem to workout the Update side of the stored procedure & would appreciate some help. CODE set ANSI_NULLS ON set QUOTED_IDENTIFIER ON go ALTER PROCEDURE [dbo].[INS_Curve] ( @Curve varchar(MAX) ) AS DECLARE @handle int exec sp_xml_preparedocument @handle OUTPUT, @Curve INSERT INTO CurveDB..tblCurve(LoadID,BusinessDate, Factor) SELECT LoadID,BusinessDate, Factor FROM OPENXML(@handle, 'NewDataSet/Table1',2) WITH( LoadID int, BusinessDate DateTime, Factor float ) exec sp_xml_removedocument @handle

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  • How can I read this url in Rebol ?

    - by Rebol Tutorial
    when trying to read this kind of url URL: http://v4.lscache2.c.youtube.com/videoplayback?ip=0.0.0.0&sparams=id,expire,ip,ipbits,itag,algorithm,burst,factor,oc:U0dWSlhTVF9FSkNNNl9QTVhJ&algorithm=throttle-factor&itag=34&ipbits=0&burst=40&sver=3&expire=1275886800&key=yt1&signature=89195E808CB3FBBC7BDE7298A1DC0613D7987F00.D3064112E8F479C523F8DF4FBFDF392CE48167C2&factor=1.25&id=34e01ad39b34b5c9& I get this error read/binary url connecting to: v4.lscache2.c.youtube.com ** User Error: Error. Target url: http://v4.lscache2.c.youtube.com/videoplayback?ip=0.0.0.0&sparams=id,expire,ip,ipbits, itag,algorithm... ** Near: read/binary url

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  • How do you write an idiomatic Scala Quicksort function?

    - by Don Mackenzie
    I recently answered a question with an attempt at writing a quicksort function in scala, I'd seen something like the code below written somewhere. def qsort(l: List[Int]): List[Int] = { l match { case Nil => Nil case pivot::tail => qsort(tail.filter(_ < pivot)) ::: pivot :: qsort(tail.filter(_ >= pivot)) } } My answer received some constructive criticism pointing out that List was a poor choice of collection for quicksort and secondly that the above wasn't tail recursive. I tried to re-write the above in a tail recursive manner but didn't have much luck. Is it possible to write a tail recursive quicksort? or, if not, how can it be done in a functional style? Also what can be done to maximise the efficiency of the implementation? Thanks in advance.

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  • Getting Factors of a Number

    - by Dave
    Hi Problem: I'm trying to refactor this algorithm to make it faster. What would be the first refactoring here for speed? public int GetHowManyFactors(int numberToCheck) { // we know 1 is a factor and the numberToCheck int factorCount = 2; // start from 2 as we know 1 is a factor, and less than as numberToCheck is a factor for (int i = 2; i < numberToCheck; i++) { if (numberToCheck % i == 0) factorCount++; } return factorCount; }

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  • Please help optimizing a long running query (left outer join, with 2 subqueries)

    - by 46and2
    Hi all. The query I need help with is: SELECT d.bn, d.4700, d.4500, ... , p.`Activity Description` FROM ( SELECT temp.bn, temp.4700, temp.4500, .... FROM `tdata` temp GROUP BY temp.bn HAVING (COUNT(temp.bn) = 1) ) d LEFT OUTER JOIN ( SELECT temp2.bn, max(temp2.FPE) AS max_fpe, temp2.`Activity Description` FROM `pdata` temp2 GROUP BY temp2.bn ) p ON p.bn = d.bn; The ... represents other fields that aren't really important to solving this problem. The issue is on the the second subquery - it is not using the index I have created and I am not sure why, it seems to be because of the way TEXT fields are handled. The first subquery uses the index I have created and runs quite snappy, however an explain on the second shows a 'Using temporary; Using filesort'. Please see the indexes I have created in the below table create statements. Can anyone help me optimize this? By way of quick explanation the first subquery is meant to only select records that have unique bn's, the second, while it looks a bit wacky (with the max function there which is not being used in the result set) is making sure that only one record from the right part of the join is included in the result set. My table create statements are CREATE TABLE `tdata` ( `BN` varchar(15) DEFAULT NULL, `4000` varchar(3) DEFAULT NULL, `5800` varchar(3) DEFAULT NULL, .... KEY `BN` (`BN`), KEY `idx_t3010`(`BN`,`4700`,`4500`,`4510`,`4520`,`4530`,`4570`,`4950`,`5000`,`5010`,`5020`,`5050`,`5060`,`5070`,`5100`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 CREATE TABLE `pdata` ( `BN` varchar(15) DEFAULT NULL, `FPE` datetime DEFAULT NULL, `Activity Description` text, .... KEY `BN` (`BN`), KEY `idx_programs_2009` (`BN`,`FPE`,`Activity Description`(100)) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 Thanks!

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  • Why would using a Temp table be faster than a nested query?

    - by Mongus Pong
    We are trying to optimise some of our queries. One query is doing the following: SELECT t.TaskID, t.Name as Task, '' as Tracker, t.ClientID, (<complex subquery>) Date, INTO [#Gadget] FROM task t SELECT TOP 500 TaskID, Task, Tracker, ClientID, dbo.GetClientDisplayName(ClientID) as Client FROM [#Gadget] order by CASE WHEN Date IS NULL THEN 1 ELSE 0 END , Date ASC DROP TABLE [#Gadget] (I have removed the complex subquery, cos I dont think its relevant other than to explain why this query has been done as a two stage process.) Now I would have thought it would be far more efficient to merge this down into a single query using subqueries as : SELECT TOP 500 TaskID, Task, Tracker, ClientID, dbo.GetClientDisplayName(ClientID) FROM ( SELECT t.TaskID, t.Name as Task, '' as Tracker, t.ClientID, (<complex subquery>) Date, FROM task t ) as sub order by CASE WHEN Date IS NULL THEN 1 ELSE 0 END , Date ASC This would give the optimiser better information to work out what was going on and avoid any temporary tables. It should be faster. But it turns out it is a lot slower. 8 seconds vs under 5 seconds. I cant work out why this would be the case as all my knowledge of databases imply that subqueries would always be faster than using temporary tables. Can anyone explain what could be going on!?!?

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  • Are high powered 3D game engines better at 2D games than engines made for 2D

    - by Adam
    I'm a software engineer that's new to game programming so forgive me if this is a dumb question as I don't know that much about game engines. If I was building a 2D game am I better off going with an engine like Torque that looks like it's built for 2D, or would higher powered engines like Unreal, Source and Unity work better? I'm mainly asking if 2D vs 3D is a large factor in choosing an engine. For the purpose of comparison, let's eliminate variables by saying price isn't a factor (even though it probably is). EDIT: I should probably also mention that the game we're developing has a lot of RTS and RPG elements regarding leveling up

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  • Registrar with good security, DNS hosting, and DNSSEC and IPv6 resolvers?

    - by semenko
    I'm looking to move my domains away from GoDaddy, but I'm having a tough time finding anyone with comparable features at a (even remotely) similar price. I've looked at the usual suggestions (NameCheap, Gandi.net, etc.), but they all seem to lack many of the GoDaddy feature base. I'm looking for: DNSSEC IPv6 Resolvers (dig pdns01.domaincontrol.com AAAA; etc. ) SSL-Logins by default HTTP-only login cookies No stupid password restrictions Two-factor authentications No DNS record limits Rough DNS statistics (queries/day, etc.) Audit trails GoDaddy has all of these, except two-factor, for $3/month. See http://www.godaddy.com/domains/dns-hosting.aspx I can't seem to find any other registrar that supports even a few of these. Is there a registrar that offers comparable features? Or, barring that, a DNS hosting service that offers similar features? (AWS Route53 doesn't offer DNSSEC or IPv6)

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  • How do I compile lbflow 1.1?

    - by Ali.A
    After using "sh ./configure" command, I encountered another error during lbflow package installation (a scientific one). The sequence of operations is here with error: ./configure --disable-gts sudo make [sudo] password for alireza: make all-recursive make[1]: Entering directory `/home/alireza/lbflow-1.1' Making all in src make[2]: Entering directory `/home/alireza/lbflow-1.1/src' source='lbflow.cpp' object='lbflow-lbflow.o' libtool=no \ DEPDIR=.deps depmode=none /bin/bash ../depcomp \ g++ -DHAVE_CONFIG_H -I. -I. -I.. -c -o lbflow-lbflow.o `test -f 'lbflow.cpp' || echo './'`lbflow.cpp **../depcomp: line 432: exec: g++: not found** **make[2]: *** [lbflow-lbflow.o] Error 127 make[2]: Leaving directory `/home/alireza/lbflow-1.1/src' make[1]: *** [all-recursive] Error 1 make[1]: Leaving directory `/home/alireza/lbflow-1.1' make: *** [all] Error 2** Do you have any idea to troubleshoot this problem? (And please notice that i have installed both g++ and gcc. it says g++: not found, but i have installed g++ from Ubuntu Software Center!)

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  • Does it help to be core programmer of a product (meant for social good) for getting into a PhD program at a top university?

    - by Maddy.Shik
    Hey i am working upon a product as core developer which will be launched in USA market in few months if successful. Can this factor improve my chances for getting accepted into a PhD program at a top university (say top 20 in US)? Normally good universities like CMU, Standford, MIT, Cornell are more interested in student's profile like research work, undergraduate school, etc. I am now passed out from very good university it's ranked in top 20 of India only. Neither did I do research work till now. But being one of founding member of company and developing product for same, I want to know if this factor can help and to what extent.

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  • Why does multiplying texture coordinates scale the texture?

    - by manning18
    I'm having trouble visualizing this geometrically - why is it that multiplying the U,V coordinates of a texture coordinate has the effect of scaling that texture by that factor? eg if you scaled the texture coordinates by a factor of 3 ..then doesn't this mean that if you had texture coordinates 0,1 and 0,2 ...you'd be sampling 0,3 and 0,6 in the U,V texture space of 0..1? How does that make it bigger eg HLSL: tex2D(textureSampler, TexCoords*3) Integers make it smaller, decimals make it bigger I mean I understand intuitively if you added to the U,V coordinates, as that is simply an offset into the sampling range, but what's the case with multiplication? I have a feeling when someone explains this to me I'm going to be feeling mighty stupid

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  • Does it help to be core programmer of a product (product meant for social good ) for getting into Ph. D. in top university in USA say top 20?

    - by Maddy.Shik
    Hey i am working upon a product as core developer which will be launched in USA market in few months if successful. Can this factor improve my chance to get Ph.D. in good university(say top 20 in US). Normally good universities like CMU, standford, MIT, Cornell are more interested in student's profile like research work, under graduate school etc. I am not passed out from very good university its ranked in top 20 of India only. Neither did i do research work till now. But being one of founding member of company and developing product for same, i want to know if this factor can help and to what extent. For university with ranking lower than 20 what matters most is GRE General score and GPA but i guess top university must be appreciating a person's real efforts.

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  • PCF shadow shader math causing artifacts

    - by user2971069
    For a while now I used PCSS for my shadow technique of choice until I discovered a type of percentage closer filtering. This method creates really smooth shadows and with hopes of improving performance, with only a fraction of texture samples, I tried to implement PCF into my shader. This is the relevant code: float c0, c1, c2, c3; float f = blurFactor; float2 coord = ProjectedTexCoords; if (receiverDistance - tex2D(lightSampler, coord + float2(0, 0)).x > 0.0007) c0 = 1; if (receiverDistance - tex2D(lightSampler, coord + float2(f, 0)).x > 0.0007) c1 = 1; if (receiverDistance - tex2D(lightSampler, coord + float2(0, f)).x > 0.0007) c2 = 1; if (receiverDistance - tex2D(lightSampler, coord + float2(f, f)).x > 0.0007) c3 = 1; coord = (coord % f) / f; return 1 - (c0 * (1 - coord.x) * (1 - coord.y) + c1 * coord.x * (1 - coord.y) + c2 * (1 - coord.x) * coord.y + c3 * coord.x * coord.y); This is a very basic implementation. blurFactor is initialized with 1 / LightTextureSize. So the if statements fetch the occlusion values for the four adjacent texels. I now want to weight each value based on the actual position of the texture coordinate. If it's near the bottom-right pixel, that occlusion value should be preferred. The weighting itself is done with a simple bilinear interpolation function, however this function takes a 2d vector in the range [0..1] so I have to convert my texture coordinate to get the distance from my first pixel to the second one in range [0..1]. For that I used the mod operator to get it into [0..f] range and then divided by f. This code makes sense to me, and for specific blurFactors it works, producing really smooth one pixel wide shadows, but not for all blurFactors. Initially blurFactor is (1 / LightTextureSize) to sample the 4 adjacent texels. I now want to increase the blurFactor by factor x to get a smooth interpolation across maybe 4 or so pixels. But that is when weird artifacts show up. Here is an image: Using a 1x on blurFactor produces a good result, 0.5 is as expected not so smooth. 2x however doesn't work at all. I found that only a factor of 1/2^n produces an good result, every other factor produces artifacts. I'm pretty sure the error lies here: coord = (coord % f) / f; Maybe the modulo is not calculated correctly? I have no idea how to fix that. Is it even possible for pixel that are further than 1 pixel away?

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  • What if we run out of stack space in C# or Python?

    - by dotneteer
    Supposing we are running a recursive algorithm on a very large data set that requires, say, 1 million recursive calls. Normally, one would solve such a large problem by converting recursion to a loop and a stack, but what if we do not want to or cannot rewrite the algorithm? Python has the sys.setrecursionlimit(int) method to set the number of recursions. However, this is only part of the story; the program can still run our of stack space. C# does not have a equivalent method. Fortunately, both C# and Python have option to set the stack space when creating a thread. In C#, there is an overloaded constructor for the Thread class that accepts a parameter for the stack size: Thread t = new Thread(work, stackSize); In Python, we can set the stack size by calling: threading.stack_size(67108864) We can then run our work under a new thread with increased stack size.

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  • Oracle NoSQL Database Exceeds 1 Million Mixed YCSB Ops/Sec

    - by Charles Lamb
    We ran a set of YCSB performance tests on Oracle NoSQL Database using SSD cards and Intel Xeon E5-2690 CPUs with the goal of achieving 1M mixed ops/sec on a 95% read / 5% update workload. We used the standard YCSB parameters: 13 byte keys and 1KB data size (1,102 bytes after serialization). The maximum database size was 2 billion records, or approximately 2 TB of data. We sized the shards to ensure that this was not an "in-memory" test (i.e. the data portion of the B-Trees did not fit into memory). All updates were durable and used the "simple majority" replica ack policy, effectively 'committing to the network'. All read operations used the Consistency.NONE_REQUIRED parameter allowing reads to be performed on any replica. In the past we have achieved 100K ops/sec using SSD cards on a single shard cluster (replication factor 3) so for this test we used 10 shards on 15 Storage Nodes with each SN carrying 2 Rep Nodes and each RN assigned to its own SSD card. After correcting a scaling problem in YCSB, we blew past the 1M ops/sec mark with 8 shards and proceeded to hit 1.2M ops/sec with 10 shards.  Hardware Configuration We used 15 servers, each configured with two 335 GB SSD cards. We did not have homogeneous CPUs across all 15 servers available to us so 12 of the 15 were Xeon E5-2690, 2.9 GHz, 2 sockets, 32 threads, 193 GB RAM, and the other 3 were Xeon E5-2680, 2.7 GHz, 2 sockets, 32 threads, 193 GB RAM.  There might have been some upside in having all 15 machines configured with the faster CPU, but since CPU was not the limiting factor we don't believe the improvement would be significant. The client machines were Xeon X5670, 2.93 GHz, 2 sockets, 24 threads, 96 GB RAM. Although the clients had 96 GB of RAM, neither the NoSQL Database or YCSB clients require anywhere near that amount of memory and the test could have just easily been run with much less. Networking was all 10GigE. YCSB Scaling Problem We made three modifications to the YCSB benchmark. The first was to allow the test to accommodate more than 2 billion records (effectively int's vs long's). To keep the key size constant, we changed the code to use base 32 for the user ids. The second change involved to the way we run the YCSB client in order to make the test itself horizontally scalable.The basic problem has to do with the way the YCSB test creates its Zipfian distribution of keys which is intended to model "real" loads by generating clusters of key collisions. Unfortunately, the percentage of collisions on the most contentious keys remains the same even as the number of keys in the database increases. As we scale up the load, the number of collisions on those keys increases as well, eventually exceeding the capacity of the single server used for a given key.This is not a workload that is realistic or amenable to horizontal scaling. YCSB does provide alternate key distribution algorithms so this is not a shortcoming of YCSB in general. We decided that a better model would be for the key collisions to be limited to a given YCSB client process. That way, as additional YCSB client processes (i.e. additional load) are added, they each maintain the same number of collisions they encounter themselves, but do not increase the number of collisions on a single key in the entire store. We added client processes proportionally to the number of records in the database (and therefore the number of shards). This change to the use of YCSB better models a use case where new groups of users are likely to access either just their own entries, or entries within their own subgroups, rather than all users showing the same interest in a single global collection of keys. If an application finds every user having the same likelihood of wanting to modify a single global key, that application has no real hope of getting horizontal scaling. Finally, we used read/modify/write (also known as "Compare And Set") style updates during the mixed phase. This uses versioned operations to make sure that no updates are lost. This mode of operation provides better application behavior than the way we have typically run YCSB in the past, and is only practical at scale because we eliminated the shared key collision hotspots.It is also a more realistic testing scenario. To reiterate, all updates used a simple majority replica ack policy making them durable. Scalability Results In the table below, the "KVS Size" column is the number of records with the number of shards and the replication factor. Hence, the first row indicates 400m total records in the NoSQL Database (KV Store), 2 shards, and a replication factor of 3. The "Clients" column indicates the number of YCSB client processes. "Threads" is the number of threads per process with the total number of threads. Hence, 90 threads per YCSB process for a total of 360 threads. The client processes were distributed across 10 client machines. Shards KVS Size Clients Mixed (records) Threads OverallThroughput(ops/sec) Read Latencyav/95%/99%(ms) Write Latencyav/95%/99%(ms) 2 400m(2x3) 4 90(360) 302,152 0.76/1/3 3.08/8/35 4 800m(4x3) 8 90(720) 558,569 0.79/1/4 3.82/16/45 8 1600m(8x3) 16 90(1440) 1,028,868 0.85/2/5 4.29/21/51 10 2000m(10x3) 20 90(1800) 1,244,550 0.88/2/6 4.47/23/53

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  • How can I test a parser for a bespoke XML schema?

    - by Greg B
    I'm parsing a bespoke XML format into an object graph using .NET 4.0. My parser is using the System.XML namespace internally, I'm then interrogating the relevant properties of XmlNodes to create my object graph. I've got a first cut of the parser working on a basic input file and I want to put some unit tests around this before I progress on to more complex input files. Is there a pattern for how to test a parser such as this? When I started looking at this, my first move was to new up and XmlDocument, XmlNamespaceManager and create an XmlElement. But it occurs to me that this is quite lengthy and prone to human error. My parser is quite recursive as you can imagine and this might lead to testing the full system rather than the individual units (methods) of the system. So a second question might be What refactoring might make a recursive parser more testable?

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  • Faking Display tree (Sprite) parent child relationships with rasters (BitmapData) in ActionScript 3

    - by Arthur Wulf White
    I am working with Rasters (bitmapData) and blliting (copypixels) in a 2d-game in actionscript 3. I like how you can move a sprite and it moves all it's children, and you can simultaneously move the children creating an interesting visual effect. I do not want to use rotation or scaling however cause I do not know how that can be done without hampering with performance. So I'm not simulating Sprite parent-child behavior and sticking to the movement on the (x, y) axis. What I am planning to do is create a class called RasterContainer which extends bitmapData that has a vector of children of type Raster(extending bitmapData), now I am planning to implement recursive rendering in RasterContainer, that basically copyPixels every child, only changing their (x, y) offset to reflect their parent's offset. My question is, has this been implemented in an existing framework? Is this a good plan? Do I expect a serious performance hit for using recursive methods this way?

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  • Samba user does not have folder read permission

    - by user289455
    I have set up a special user for read only samba shares. I set him up in Samba and as a system user. I shared a couple of folders but that user cannot access them. I know samba is working because I also shared them with the main user of the system which is an admin account and it works fine. How can I allow this user to have read permissions on all the directories I want to share without changing anything for any other users of the system? For example, I don't want to give him ownership of any of the files/directories. Just ongoing recursive read access. ongoing recursive is important. If someone adds a file or directory, I still want him to automatically be able to read it.

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  • Help with Boost Spirit ASTs

    - by Decmac04
    I am writing a small tool for analyzing simple B Machine substitutions as part of a college research work. The code successfully parse test inputs of the form mySubst := var1 + var2. However, I get a pop-up error message saying "This application has requested the Runtime to terminate it in an unusual way. " In the command prompt window, I get an "Assertion failed message". The main program is given below: // BMachineTree.cpp : Defines the entry point for the console application. // /*============================================================================= Copyright (c) 2010 Temitope Onunkun =============================================================================*/ /////////////////////////////////////////////////////////////////////////////// // // UUsing Boost Spririt Trees (AST) to parse B Machine Substitutions. // /////////////////////////////////////////////////////////////////////////////// #define BOOST_SPIRIT_DUMP_PARSETREE_AS_XML #include <boost/spirit/core.hpp> #include <boost/spirit/tree/ast.hpp> #include <boost/spirit/tree/tree_to_xml.hpp> #include "BMachineTreeGrammar.hpp" #include <iostream> #include <stack> #include <functional> #include <string> #include <cassert> #include <vector> #if defined(BOOST_SPIRIT_DUMP_PARSETREE_AS_XML) #include <map> #endif // Using AST to parse B Machine substitutions //////////////////////////////////////////////////////////////////////////// using namespace std; using namespace boost::spirit; typedef char const* iterator_t; typedef tree_match<iterator_t> parse_tree_match_t; typedef parse_tree_match_t::tree_iterator iter_t; //////////////////////////////////////////////////////////////////////////// string evaluate(parse_tree_match_t hit); string eval_machine(iter_t const& i); vector<string> dx; string evaluate(tree_parse_info<> info) { return eval_machine(info.trees.begin()); } string eval_machine(iter_t const& i) { cout << "In eval_machine. i->value = " << string(i->value.begin(), i->value.end()) << " i->children.size() = " << i->children.size() << endl; if (i->value.id() == substitution::leafValueID) { assert(i->children.size() == 0); // extract string tokens string leafValue(i->value.begin(), i->value.end()); dx.push_back(leafValue.c_str()); return leafValue.c_str(); } // else if (i->value.id() == substitution::termID) { if ( (*i->value.begin() == '*') || (*i->value.begin() == '/') ) { assert(i->children.size() == 2); dx.push_back( eval_machine(i->children.begin()) ); dx.push_back( eval_machine(i->children.begin()+1) ); return eval_machine(i->children.begin()) + " " + eval_machine(i->children.begin()+1); } // else assert(0); } else if (i->value.id() == substitution::expressionID) { if ( (*i->value.begin() == '+') || (*i->value.begin() == '-') ) { assert(i->children.size() == 2); dx.push_back( eval_machine(i->children.begin()) ); dx.push_back( eval_machine(i->children.begin()+1) ); return eval_machine(i->children.begin()) + " " + eval_machine(i->children.begin()+1); } else assert(0); } // else if (i->value.id() == substitution::simple_substID) { if (*i->value.begin() == (':' >> '=') ) { assert(i->children.size() == 2); dx.push_back( eval_machine(i->children.begin()) ); dx.push_back( eval_machine(i->children.begin()+1) ); return eval_machine(i->children.begin()) + "|->" + eval_machine(i->children.begin()+1); } else assert(0); } else { assert(0); // error } return 0; } //////////////////////////////////////////////////////////////////////////// int main() { // look in BMachineTreeGrammar for the definition of BMachine substitution BMach_subst; cout << "/////////////////////////////////////////////////////////\n\n"; cout << "\t\tB Machine Substitution...\n\n"; cout << "/////////////////////////////////////////////////////////\n\n"; cout << "Type an expression...or [q or Q] to quit\n\n"; string str; while (getline(cin, str)) { if (str.empty() || str[0] == 'q' || str[0] == 'Q') break; tree_parse_info<> info = ast_parse(str.c_str(), BMach_subst, space_p); if (info.full) { #if defined(BOOST_SPIRIT_DUMP_PARSETREE_AS_XML) // dump parse tree as XML std::map<parser_id, std::string> rule_names; rule_names[substitution::identifierID] = "identifier"; rule_names[substitution::leafValueID] = "leafValue"; rule_names[substitution::factorID] = "factor"; rule_names[substitution::termID] = "term"; rule_names[substitution::expressionID] = "expression"; rule_names[substitution::simple_substID] = "simple_subst"; tree_to_xml(cout, info.trees, str.c_str(), rule_names); #endif // print the result cout << "Variables in Vector dx: " << endl; for(vector<string>::iterator idx = dx.begin(); idx < dx.end(); ++idx) cout << *idx << endl; cout << "parsing succeeded\n"; cout << "result = " << evaluate(info) << "\n\n"; } else { cout << "parsing failed\n"; } } cout << "Bye... :-) \n\n"; return 0; } The grammar, defined in BMachineTreeGrammar.hpp file is given below: /*============================================================================= Copyright (c) 2010 Temitope Onunkun http://www.dcs.kcl.ac.uk/pg/onun Use, modification and distribution is subject to the Boost Software License, Version 1.0. (See accompanying file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt) =============================================================================*/ #ifndef BOOST_SPIRIT_BMachineTreeGrammar_HPP_ #define BOOST_SPIRIT_BMachineTreeGrammar_HPP_ using namespace boost::spirit; /////////////////////////////////////////////////////////////////////////////// // // Using Boost Spririt Trees (AST) to parse B Machine Substitutions. // /////////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////// // // B Machine Grammar // //////////////////////////////////////////////////////////////////////////// struct substitution : public grammar<substitution> { static const int identifierID = 1; static const int leafValueID = 2; static const int factorID = 3; static const int termID = 4; static const int expressionID = 5; static const int simple_substID = 6; template <typename ScannerT> struct definition { definition(substitution const& ) { // Start grammar definition identifier = alpha_p >> (+alnum_p | ch_p('_') ) ; leafValue = leaf_node_d[ lexeme_d[ identifier | +digit_p ] ] ; factor = leafValue | inner_node_d[ ch_p( '(' ) >> expression >> ch_p(')' ) ] ; term = factor >> *( (root_node_d[ch_p('*') ] >> factor ) | (root_node_d[ch_p('/') ] >> factor ) ); expression = term >> *( (root_node_d[ch_p('+') ] >> term ) | (root_node_d[ch_p('-') ] >> term ) ); simple_subst= leaf_node_d[ lexeme_d[ identifier ] ] >> root_node_d[str_p(":=")] >> expression ; // End grammar definition // turn on the debugging info. BOOST_SPIRIT_DEBUG_RULE(identifier); BOOST_SPIRIT_DEBUG_RULE(leafValue); BOOST_SPIRIT_DEBUG_RULE(factor); BOOST_SPIRIT_DEBUG_RULE(term); BOOST_SPIRIT_DEBUG_RULE(expression); BOOST_SPIRIT_DEBUG_RULE(simple_subst); } rule<ScannerT, parser_context<>, parser_tag<simple_substID> > simple_subst; rule<ScannerT, parser_context<>, parser_tag<expressionID> > expression; rule<ScannerT, parser_context<>, parser_tag<termID> > term; rule<ScannerT, parser_context<>, parser_tag<factorID> > factor; rule<ScannerT, parser_context<>, parser_tag<leafValueID> > leafValue; rule<ScannerT, parser_context<>, parser_tag<identifierID> > identifier; rule<ScannerT, parser_context<>, parser_tag<simple_substID> > const& start() const { return simple_subst; } }; }; #endif The output I get on running the program is: ///////////////////////////////////////////////////////// B Machine Substitution... ///////////////////////////////////////////////////////// Type an expression...or [q or Q] to quit mySubst := var1 - var2 parsing succeeded In eval_machine. i->value = := i->children.size() = 2 Assertion failed: 0, file c:\redmound\bmachinetree\bmachinetree\bmachinetree.cpp , line 114 I will appreciate any help in resolving this problem.

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