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  • Regular Expression .net flavor

    - by user1440109
    Dont ask how this works but currently it does ("^\|(.?)\|*$")....kinda. This removes all extra pipes...part one....I have searched all over no anwser yet. I am using VB2011 beta...asp web form......vb coding though! I want to capture special character pipe (|) which is used to seperate words...i.e. car|truck|van|cycle problem is users lead with, trail with, use multiple, and use spaces before and after...i.e. |||car||truck | van || cycle. another example: george bush|micheal jordon|bill gates|steve jobs <-- this would be correct but when I do remove space it takes correct space out. so I want to get rid of whitespace leading, trailing, any space before | and space after | and only allow one pipe (|)....in between alphanumeric of course.

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  • Regular expressions in c++ STL

    - by Radek Šimko
    Is there any native library in STL which is tested and works without any extra compiler options? I tried to use <regex>, but the compiler outputs this: In file included from /usr/include/c++/4.3/regex:40, from main.cpp:5: /usr/include/c++/4.3/c++0x_warning.h:36:2: error: #error This file requires compiler and library support for the upcoming ISO C++ standard, C++0x. This support is currently experimental, and must be enabled with the -std=c++0x or -std=gnu++0x compiler options.

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  • Use regular expressions with Glib

    - by Sébastien
    Hello, I would like to find all comment blocks(/*...*/) but the function g_regex_match_full always returns true. Here is the code : // Create the regex. start_block_comment_regex = g_regex_new("/\*.*\*/", G_REGEX_OPTIMIZE, 0, &regex_error); //Search the regex; if(TRUE == g_regex_match_full(start_block_comment_regex, current_line, -1, 0, 0, &match_info, &regex_error)) { }

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  • Why this C# Regular Expression crashes my program?

    - by robert_d
    using System; using System.IO; using System.Net; using System.Text.RegularExpressions; namespace Working { class Program4 { static string errorurl = "http://www.realtor.ca/propertyDetails.aspx?propertyId=8692663"; static void Main(string[] args) { string s; s = getWebpageContent(errorurl); s = removeNewLineCharacters(s); getFields(s); Console.WriteLine("End"); } public static void getFields(string html) { Match m; string fsRE = @"ismeasurement.*?>.*?(\d+).*?sqft"; m = Regex.Match(html, fsRE, RegexOptions.IgnoreCase); } private static string removeNewLineCharacters(string str) { string[] charsToRemove = new string[] { "\n", "\r" }; foreach (string c in charsToRemove) { str = str.Replace(c, ""); } return str; } static string getWebpageContent(string url) { WebClient client = new WebClient(); client.Headers.Add("user-agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705;)"); Stream data = client.OpenRead(url); StreamReader reader = new StreamReader(data); string s = reader.ReadToEnd(); data.Close(); reader.Close(); return s; } } } This program hangs. It runs correctly when I remove RegexOptions.IgnoreCase option or when I remove call to removeNewLineCharacters() function. Could someone tell me what is going on, please?

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  • Perl Regular expression remove double tabs, line breaks, white spaces

    - by Scoox
    Hi guys, I want to write a perl script that removes double tabs, line breaks and white spaces. What I have so far is: $txt=~s/\r//gs; $txt=~s/ +/ /gs; $txt=~s/\t+/\t/gs; $txt=~s/[\t\n]*\n/\n/gs; $txt=~s/\n+/\n/gs; But, 1. It's not beautiful. Should be possible to do that with far less regexps. 2. It just doesn't work and I really do not know why. It leaves some double tabs, white spaces and empty lines (i.e. lines with only a tab or whitespace) I could solve it with a while, but that is very slow and ugly. Any suggestions?

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  • How to process this string via regular expression

    - by iiduce
    my string style like this: expression1/field1+expression2*expression3+expression4/field2*expression5*expression6/field3 a real style mybe like this: computer/(100)+web*mail+explorer/(200)*bbs*solution/(300) "+" and "*" represent operator "computer","web"...represent expression (100),(200) represent field num . field num may not exist. I want process the string to this: /(100)+web*+explorer/(200)bbs/(300) rules like this: if expression length is more than 3 and its field is not (200), then add brackets to it.

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  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

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  • help for writting a regular expression in javascript

    - by Majesty
    Hi guys... I want to write a javascrpit code with .Split() that split a string with structure described below: The input: W1...Wn=S1...||...Sm||Sj...Sk|Y1...Yn=D1...Di||Dm...Dn|... The Output: W1...Wn=S1...||...Sm||Sj...Sk Y1...Yn=D1...Di||Dm...Dn ... I've seen the question that split this string: a=aa|b=b||b|c=cc . but my question is general case of that question. please help me... Thanks...

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  • .Net Regular Expression

    - by xzerox
    Alright so I want to grab the information on a website thats between [usernames] and [/usernames] I know how to get the string but how would I use regex to only have the information in the middle. Remember I am going to be having more then one thing on the page.

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  • parse string with regular exression

    - by llamerr
    I trying to parse this string: $right = '34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4]'; with following regexp: const word = '(\d{3}\d{2}\)S{0,1}\([^\)]*\)S{0,1}\[[^\]]*\])'; preg_match('/'.word.'{1}(?:\s{1}([+-]{1})\s{1}'.word.'){0,}/', $right, $matches); print_r($matches); i want to return array like this: Array ( [0] => 34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4] [1] => 34601)S(1,6)[2] [2] => - [3] => 34601)(11)[2] [4] => + [5] => 34601)(3)[2,4] ) but i return only following: Array ( [0] => 34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4] [1] => 34601)S(1,6)[2] [2] => + [3] => 34601)(3)[2,4] ) i think, its becouse of [^)]* or [^]]* in the word, but how i should correct regexp for matching this in another way? i tryied to specify it: \d+(?:[,#]\d+){0,} so word become const word = '(\d{3}\d{2}\)S{0,1}\(\d+(?:[,#]\d+){0,}\)S{0,1}\[\d+(?:[,#]\d+){0,}\])'; but it gives nothing

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  • Selectively search and replace certain lines using a regular expression

    - by eneveu
    I have a file containing a lot of SQL statements, such as: CREATE TABLE "USER" ( "ID" INTEGER PRIMARY KEY, "NAME" CHARACTER VARYING(50) NOT NULL, "AGE" INTEGER NOT NULL ); COPY "USER" (id, name, age) FROM stdin; 1 Skywalker 19 2 Kenobi 57 I want the column names in the COPY statements to be uppercased and quoted: COPY "USER" ("ID", "NAME", "AGE") FROM stdin; Using sed, I found the following regexp: sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' It does replace the column names, but it is not selective enough, and replaces other words in the file: ~/test]$sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' star_wars_example CREATE TABLE "USER" ( "ID" INTEGER PRIMARY "KEY", "NAME" CHARACTER VARYING("50")NOT "NULL", "AGE" INTEGER NOT NULL ); COPY "USER" ("ID", "NAME", "AGE") FROM stdin; 1 Skywalker 19 2 Kenobi 57 To avoid this problem, I want sed to only apply my regexp to the lines starting with COPY and ending with FROM stdin;. I have looked into lookahead / lookbehind, but they are not supported in sed. They seem to be supported in super-sed, but I am currently using Cygwin (Windows is mandatory here...) and it does not seem available in the package list. Is there a way to force sed to only consider specific line? I've considered piping my file through grep before applying sed, but other lines will then disappear from the output. Am I missing something obvious? It would be great if the answer was easily applicable on a default Cygwin install. I guess I could try installing super-sed on cygwin, but I'd like to know if there are more obvious ideas

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  • How to with extract url from tweet using Regular Expressions

    - by neutreno
    Ok so i'm executing the following line of code in javascript RegExp('(http:\/\/t.co\/)[a-zA-Z0-9\-\.]{8}').exec(tcont); where tcont is equal to some string like 'Test tweet to http://t.co/GXmaUyNL' (the content of a tweet obtained by jquery). However it is returning, in the case above for example, 'http://t.co/GXmaUyNL,http://t.co/'. This is frustracting because I want the url without the bit on the end - after and including the comma. Any ideas why this is appearing? Thanks

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  • How to implement a timer for regular events?

    - by Torben Jonas
    I would like to implement some timers into my application. My goal is to provide an easy way to execute some function every x seconds/minutes so I thought about implementing a 1 sec, 5 sec and 15 seconds timer. The first thing i would like to update every 1 second is the built in clock (don't know if there is any other solution in c#, used this method in c++) Another use would be e.g. a sync function etc. which shall be executed every xx seconds. My question is if there are any useful tutorials on this topic? It is the first time that I would like to implement such an timer system into one of my applications and I do not know if there are any things I have to keep in mind. Thank you in advance for any answer :)

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  • Regular Expression to match IP address + wildcard

    - by Ed Woodcock
    Hey guys I'm trying to use a RegularexpressionValidator to match an IP address (with possible wildcards) for an IP filtering system. I'm using the following Regex: "([0-9]{1,3}\\.|\\*\\.){3}([0-9]{1,3}|\\*){1}" Which works fine when running it in LINQPad with Regex.Matches, but doesn't seem to work when I'm using the validator. Does anyone have a suggestion as to either a better Regex or why it would work in test but not in situ? Cheers, Ed

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  • Regular expression test can't decide between true and false (JavaScript)

    - by nw
    I get this behavior in both Chrome (Developer Tools) and Firefox (Firebug). Note the regex test returns alternating true/false values: > var re = /.*?\bbl.*\bgr.*/gi; undefined > re /.*?\\bbl.*\\bgr.*/gi > re.test("Blue-Green"); true > re.test("Blue-Green"); false > re.test("Blue-Green"); true > re.test("Blue-Green"); false However, testing the same regex as a literal: > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true I can't explain this and it's making debugging very difficult. Can anyone explain this behavior?

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  • regular expresson of variables

    - by Kevinniceguy
    what is re of string of 0 and 1 that contain an even number of zeros and even number of ones..... its not or in the middle....its an and...and even number of ones so i got something like (1*01*01*)*(0*10*10*)* does it look good?

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  • Regular Expression issue

    - by Christian Sciberras
    I have the following URL structure which I need to match to and get the particular id from: /group/subgroup/id-name In short, I need to translate a URL like the following: /Blue Products/Dark Blue/5-Blue_Jelly To: /?pagename=Blue Products&model=5 IMPORTANT: I don't need to match group, I already have group. Example code: <?php foreach($cats as $cat) $cmd->rewrite('/\/'.$cat.'\/unused\/(ID)-unused\//','/?pagename='.$cat.'&model=%ID%'); ?> Edit: This is the completed code: if($groups->count()){ $names=array(); foreach($groups->rows as $row) $names[]=preg_quote($row->group); $names=implode('|',$names); $regex='('.$names.')/([^/]+)/([0-9]{1,})-([^/]+)/?$'; CmsHost::cms()->rewrite_url($regex,'index.php?pagename=Products',true); }

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  • JavaScript Regular expressions, match and replace link

    - by Thoman
    Hello please help me <html> <body> http://domainname.com/abc/xyz.zip http://domainname2.com/abc/xyz.zip </body> </html> I want replace with link and out put like <html> <body> <a href="http://domainname.com/abc/xyz.zip">http://domainname.com/abc/xyz.zip</a> <a href="http://domainname2.com/abc/xyz.zip">http://domainname2.com/abc/xyz.zip</a> </body> </html> Great Thank

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  • How to get only a filename (not full path) into $1, using the PERL, regular expressions

    - by Scott
    I want to keep only the filenames (not full paths) and add the filename to some bbcode. Here is the HTML to be converted: <a href=/path/to/full/image.jpg rel=prettyPhoto><img rel=prettyPhoto src=/path/to/thumb/image.jpg /></a> Notice I cannot have rel="foo" (no double quotes).. Here is what I have in PERL, to perform the conversion: s/\<a href=(.+?)\ rel=prettyPhoto\>\<img rel=prettyPhoto src=(.+?) \/>\<\/a\>/\[box\]$1\[\/box\]/gi; This converts the HTML to: [box]/path/to/image.jpg[/box] But this is what I want as a result: [box]image.jpg[/box] The HTML must remain the same. So how do I change my PERL so that $1 contains only the filename?

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