Search Results

Search found 5414 results on 217 pages for 'regular'.

Page 30/217 | < Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >

  • Regular Expression to Match YouTube Watch URL

    - by dododedodonl
    Hi, I've got this regex (I'm not good at it) /http://www.youtube.com/watch?v=[a-zA-Z0-9_]/i it has to match any youtube watch url (because youtube always redirects to that domain)... It should match http://www.youtube.com/watch?v=iMXCqgWjpL8 but it doesn't. Can someone help me? Regard, dodo

    Read the article

  • Regular expressions in c++ STL

    - by Radek Šimko
    Is there any native library in STL which is tested and works without any extra compiler options? I tried to use <regex>, but the compiler outputs this: In file included from /usr/include/c++/4.3/regex:40, from main.cpp:5: /usr/include/c++/4.3/c++0x_warning.h:36:2: error: #error This file requires compiler and library support for the upcoming ISO C++ standard, C++0x. This support is currently experimental, and must be enabled with the -std=c++0x or -std=gnu++0x compiler options.

    Read the article

  • perl regular expressions substitution/replacement using variables with special characters

    - by user961627
    Okay I've checked previous similar questions and I've been juggling with different variations of quotemeta but something's still not right. I have a line with a word ID and two words - the first is the wrong word, the second is right. And I'm using a regex to replace the wrong word with the right one. $line = "ANN20021015_0104_XML_16_21 A$xAS A$xASA"; @splits = split("\t",$line); $wrong_word = quotemeta $splits[1]; $right_word = quotemeta $splits[2]; print $right_word."\n"; print $wrong_word."\n"; $line =~ s/$wrong_word\t/$right_word\t/g; print $line; What's wrong with what I'm doing? Edit The problem is that I'm unable to retain the complete words - they get chopped off at the special characters. This code works perfectly fine for words without special characters. The output I need for the above example is: ANN20021015_0104_XML_16_21 A$xASA A$xASA But what I get is ANN20021015_0104_XML_16_21 A A Because of the $ character.

    Read the article

  • Regular Expression .net flavor

    - by user1440109
    Dont ask how this works but currently it does ("^\|(.?)\|*$")....kinda. This removes all extra pipes...part one....I have searched all over no anwser yet. I am using VB2011 beta...asp web form......vb coding though! I want to capture special character pipe (|) which is used to seperate words...i.e. car|truck|van|cycle problem is users lead with, trail with, use multiple, and use spaces before and after...i.e. |||car||truck | van || cycle. another example: george bush|micheal jordon|bill gates|steve jobs <-- this would be correct but when I do remove space it takes correct space out. so I want to get rid of whitespace leading, trailing, any space before | and space after | and only allow one pipe (|)....in between alphanumeric of course.

    Read the article

  • Regular Expression Help

    - by WizardsSleeve
    Hi There, Does anyone have a regurlar expression available which only accepts dates in the format dd/mm/yy but also has strict checking to make sure that the date is valid, including leap year support? I am coding in vb.net and am struggling to work this one out. Many Thanks

    Read the article

  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

    Read the article

  • Regular expression: who's greedier?

    - by polygenelubricants
    My primary concern is with the Java flavor, but I'd also appreciate information regarding others. Let's say you have a subpattern like this: (.*)(.*) Not very useful as is, but let's say these two capture groups (say, \1 and \2) are part of a bigger pattern that matches with backreferences to these groups, etc. So both are greedy, in that they try to capture as much as possible, only taking less when they have to. My question is: who's greedier? Does \1 get first priority, giving \2 its share only if it has to? What about: (.*)(.*)(.*) Let's assume that \1 does get first priority. Let's say it got too greedy, and then spit out a character. Who gets it first? Is it always \2 or can it be \3? Let's assume it's \2 that gets \1's rejection. If this still doesn't work, who spits out now? Does \2 spit to \3, or does \1 spit out another to \2 first?

    Read the article

  • Regular expression test can't decide between true and false (JavaScript)

    - by nw
    I get this behavior in both Chrome (Developer Tools) and Firefox (Firebug). Note the regex test returns alternating true/false values: > var re = /.*?\bbl.*\bgr.*/gi; undefined > re /.*?\\bbl.*\\bgr.*/gi > re.test("Blue-Green"); true > re.test("Blue-Green"); false > re.test("Blue-Green"); true > re.test("Blue-Green"); false However, testing the same regex as a literal: > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true I can't explain this and it's making debugging very difficult. Can anyone explain this behavior?

    Read the article

  • Vibration after regular intervals

    - by umar
    I have a beep system which gives you four beeps. One beep after a second for one second. However If its silent mode i want the vibrator to do the same, vibrate for 1 second 4 times after 1 second. This is the code I am using long[] pattern = new long[2]; pattern[0] = 10; pattern [1] = 30; switch (am.getRingerMode()) { case AudioManager.RINGER_MODE_VIBRATE: vibe.vibrate(pattern, 0); break; case AudioManager.RINGER_MODE_NORMAL: soundsOn(mp); break; Kindly how can i do what i want to do Best Regards

    Read the article

  • Perl Regular expression remove double tabs, line breaks, white spaces

    - by Scoox
    Hi guys, I want to write a perl script that removes double tabs, line breaks and white spaces. What I have so far is: $txt=~s/\r//gs; $txt=~s/ +/ /gs; $txt=~s/\t+/\t/gs; $txt=~s/[\t\n]*\n/\n/gs; $txt=~s/\n+/\n/gs; But, 1. It's not beautiful. Should be possible to do that with far less regexps. 2. It just doesn't work and I really do not know why. It leaves some double tabs, white spaces and empty lines (i.e. lines with only a tab or whitespace) I could solve it with a while, but that is very slow and ugly. Any suggestions?

    Read the article

  • Selectively search and replace certain lines using a regular expression

    - by eneveu
    I have a file containing a lot of SQL statements, such as: CREATE TABLE "USER" ( "ID" INTEGER PRIMARY KEY, "NAME" CHARACTER VARYING(50) NOT NULL, "AGE" INTEGER NOT NULL ); COPY "USER" (id, name, age) FROM stdin; 1 Skywalker 19 2 Kenobi 57 I want the column names in the COPY statements to be uppercased and quoted: COPY "USER" ("ID", "NAME", "AGE") FROM stdin; Using sed, I found the following regexp: sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' It does replace the column names, but it is not selective enough, and replaces other words in the file: ~/test]$sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' star_wars_example CREATE TABLE "USER" ( "ID" INTEGER PRIMARY "KEY", "NAME" CHARACTER VARYING("50")NOT "NULL", "AGE" INTEGER NOT NULL ); COPY "USER" ("ID", "NAME", "AGE") FROM stdin; 1 Skywalker 19 2 Kenobi 57 To avoid this problem, I want sed to only apply my regexp to the lines starting with COPY and ending with FROM stdin;. I have looked into lookahead / lookbehind, but they are not supported in sed. They seem to be supported in super-sed, but I am currently using Cygwin (Windows is mandatory here...) and it does not seem available in the package list. Is there a way to force sed to only consider specific line? I've considered piping my file through grep before applying sed, but other lines will then disappear from the output. Am I missing something obvious? It would be great if the answer was easily applicable on a default Cygwin install. I guess I could try installing super-sed on cygwin, but I'd like to know if there are more obvious ideas

    Read the article

  • parse string with regular exression

    - by llamerr
    I trying to parse this string: $right = '34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4]'; with following regexp: const word = '(\d{3}\d{2}\)S{0,1}\([^\)]*\)S{0,1}\[[^\]]*\])'; preg_match('/'.word.'{1}(?:\s{1}([+-]{1})\s{1}'.word.'){0,}/', $right, $matches); print_r($matches); i want to return array like this: Array ( [0] => 34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4] [1] => 34601)S(1,6)[2] [2] => - [3] => 34601)(11)[2] [4] => + [5] => 34601)(3)[2,4] ) but i return only following: Array ( [0] => 34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4] [1] => 34601)S(1,6)[2] [2] => + [3] => 34601)(3)[2,4] ) i think, its becouse of [^)]* or [^]]* in the word, but how i should correct regexp for matching this in another way? i tryied to specify it: \d+(?:[,#]\d+){0,} so word become const word = '(\d{3}\d{2}\)S{0,1}\(\d+(?:[,#]\d+){0,}\)S{0,1}\[\d+(?:[,#]\d+){0,}\])'; but it gives nothing

    Read the article

  • Regular Expression to match IP address + wildcard

    - by Ed Woodcock
    Hey guys I'm trying to use a RegularexpressionValidator to match an IP address (with possible wildcards) for an IP filtering system. I'm using the following Regex: "([0-9]{1,3}\\.|\\*\\.){3}([0-9]{1,3}|\\*){1}" Which works fine when running it in LINQPad with Regex.Matches, but doesn't seem to work when I'm using the validator. Does anyone have a suggestion as to either a better Regex or why it would work in test but not in situ? Cheers, Ed

    Read the article

  • .Net Regular Expression

    - by xzerox
    Alright so I want to grab the information on a website thats between [usernames] and [/usernames] I know how to get the string but how would I use regex to only have the information in the middle. Remember I am going to be having more then one thing on the page.

    Read the article

  • help for writting a regular expression in javascript

    - by Majesty
    Hi guys... I want to write a javascrpit code with .Split() that split a string with structure described below: The input: W1...Wn=S1...||...Sm||Sj...Sk|Y1...Yn=D1...Di||Dm...Dn|... The Output: W1...Wn=S1...||...Sm||Sj...Sk Y1...Yn=D1...Di||Dm...Dn ... I've seen the question that split this string: a=aa|b=b||b|c=cc . but my question is general case of that question. please help me... Thanks...

    Read the article

  • ExtJS combobox acting like regular select

    - by bensiu
    Hi, I try to use ComboBox on FormPanel, it is defined like this: xtype: 'combo', name: 'Reasons', store: new Ext.data.ArrayStore({ id: 0, fields: [ 'myId', 'displayText' ], data: [ [ 1, 'Reason 1' ], [ 2, 'Second Reason' ], [ 3, 'Something else' ] ] }), typeAhead: false, mode: 'local', valueField: 'myId', displayField: 'displayText', allowBlank: false, editable: false, forceSelection: true I would like to act like a ordinary select element, when I have editable as false I not able to re-select anymore, when as true ( default ) I need to remove selection ( by backspace or delete ) in order to re-select. What else I should turn off in order to downgrade combobox to select or shpuld I consider to use other component instead ?

    Read the article

  • JavaScript Regular expressions, match and replace link

    - by Thoman
    Hello please help me <html> <body> http://domainname.com/abc/xyz.zip http://domainname2.com/abc/xyz.zip </body> </html> I want replace with link and out put like <html> <body> <a href="http://domainname.com/abc/xyz.zip">http://domainname.com/abc/xyz.zip</a> <a href="http://domainname2.com/abc/xyz.zip">http://domainname2.com/abc/xyz.zip</a> </body> </html> Great Thank

    Read the article

  • Regular Expression - Capture and Replace Select Sequences

    - by Chad
    Take the following file... ABCD,1234,http://example.com/mpe.exthttp://example/xyz.ext EFGH,5678,http://example.com/wer.exthttp://example/ljn.ext Note that "ext" is a constant file extension throughout the file. I am looking for an expression to turn that file into something like this... ABCD,1234,http://example.com/mpe.ext ABCD,1234,http://example/xyz.ext EFGH,5678,http://example.com/wer.ext EFGH,5678,http://example/ljn.ext In a nutshell I need to capture everything up to the urls. Then I need to capture each URL and put them on their own line with the leading capture. I am working with sed to do this and I cannot figure out how to make it work correctly. Any ideas?

    Read the article

  • Regular Expression problem

    - by Yatendra Goel
    I want a regex to find the following types of strings: http://anything.abc.tld http://anything.abc.tld/ where abc - abc always remains abc anything - it could be any string tld - it could be any tld (top-level-domain) like .com .net .co.in .co.uk etc. Note: The url must not contain any other thing at the end, means http://anything.abc.tld/xyz is not acceptable.

    Read the article

< Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >