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  • regular expressions: ignoring certain chars globally

    - by shi kui
    Consider it that '_'s in a number doesn't change that number's value so 1000==1_000==10_00. The Problem: given numbers like 1_244_23 1412_2 1_1111 etc..., how could I decide whether certain number appears in that collection? For example: 1244_23 yes, 11_111 yes, 1412_1 no. How could using regex to solve this? I mean, if I could tell the regex engine just ignore these '_''s when matching then this problem becomes trivial? How could I do so?

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  • How do I not include part of a regular expression

    - by Axilus
    I'm pretty new to using regexes and I can figure out how I would go about extracted a specific number from a string. Suppose the string was any amount of whitespace or random text and somewhere within it is this, "Value: $1000.00." In order to retrieve that value I am currently using this: string value = Convert.ToString(Regex.Match(BodyContent, @"Value:[ \t]*\$?\d*(\.[0-9]{2})?", RegexOptions.Singleline)); So the variable 'value' now has, "Value: $1000.00" stored in it. My question is, using Regex is there a way to use 'Value:' to find the number value but only store the actual number value (i.e. 1000.00) in the 'value' variable?

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  • ExtJS combobox acting like regular select

    - by bensiu
    Hi, I try to use ComboBox on FormPanel, it is defined like this: xtype: 'combo', name: 'Reasons', store: new Ext.data.ArrayStore({ id: 0, fields: [ 'myId', 'displayText' ], data: [ [ 1, 'Reason 1' ], [ 2, 'Second Reason' ], [ 3, 'Something else' ] ] }), typeAhead: false, mode: 'local', valueField: 'myId', displayField: 'displayText', allowBlank: false, editable: false, forceSelection: true I would like to act like a ordinary select element, when I have editable as false I not able to re-select anymore, when as true ( default ) I need to remove selection ( by backspace or delete ) in order to re-select. What else I should turn off in order to downgrade combobox to select or shpuld I consider to use other component instead ?

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  • perl regular expressions substitution/replacement using variables with special characters

    - by user961627
    Okay I've checked previous similar questions and I've been juggling with different variations of quotemeta but something's still not right. I have a line with a word ID and two words - the first is the wrong word, the second is right. And I'm using a regex to replace the wrong word with the right one. $line = "ANN20021015_0104_XML_16_21 A$xAS A$xASA"; @splits = split("\t",$line); $wrong_word = quotemeta $splits[1]; $right_word = quotemeta $splits[2]; print $right_word."\n"; print $wrong_word."\n"; $line =~ s/$wrong_word\t/$right_word\t/g; print $line; What's wrong with what I'm doing? Edit The problem is that I'm unable to retain the complete words - they get chopped off at the special characters. This code works perfectly fine for words without special characters. The output I need for the above example is: ANN20021015_0104_XML_16_21 A$xASA A$xASA But what I get is ANN20021015_0104_XML_16_21 A A Because of the $ character.

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  • string substitution regular expression not working in tcl

    - by Puneet Mittal
    i am trying to replace all the special characters including white space, hyphen, etc, to underscore, from a string variable in tcl. I wrote the code below but it doesn't seem to be working. set varname $origVar puts "Variable Name :>> $varname" if {$varname != ""} { regsub -all {[\s-\]\[$^?+*()|\\%&#]} $varname "_" $newVar } puts "New Variable :>> $newVar" one issue is that, instead of replacing the string in $varname, it is replacing the data inside $origVar. No idea why, and also i read the example code (for proper syntax) in my tcl book and according to that it should be something like this regsub -all {[\s-][$^?+*()|\\%&#]} $varname "_" newVar so i used the same syntax but it didn't work and gave the same result as modifying the $origVar instead of required $varname value.

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  • Regular Expression - Capture and Replace Select Sequences

    - by Chad
    Take the following file... ABCD,1234,http://example.com/mpe.exthttp://example/xyz.ext EFGH,5678,http://example.com/wer.exthttp://example/ljn.ext Note that "ext" is a constant file extension throughout the file. I am looking for an expression to turn that file into something like this... ABCD,1234,http://example.com/mpe.ext ABCD,1234,http://example/xyz.ext EFGH,5678,http://example.com/wer.ext EFGH,5678,http://example/ljn.ext In a nutshell I need to capture everything up to the urls. Then I need to capture each URL and put them on their own line with the leading capture. I am working with sed to do this and I cannot figure out how to make it work correctly. Any ideas?

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  • PHP regular expression subpattern behaviour

    - by codecowboy
    I want to match both the src and title attributes of an image tag: pattern: <img [^>]*src=["|\']([^"|\']+["|\'])|title=["|\']([^"|\']+) target: <img src="http://someurl.jpg" class="quiz_caption" title="Caption goes here!"> This pattern gives me one unwanted match, title="content", and the match I actually want which is the value between the quotes after the word 'title', i.e 'content'. So, my matches are: <img src="http://someurl.jpg http://someurl.jpg title="Caption goes here!" Caption goes here! Is there a way to avoid the third of these matches? I'm using PCRE in PHP 5.2.x

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  • Perl Regular Expression [] for <>

    - by bmucklow
    So I am trying to read an XML file into a string in Perl and send it as part of a SOAP message. I know this is not ideal as there are methods for SOAP sending files, however, I am limited to having to use the SOAP that is set up, and it is not set up for sending with file support. Therefore I need to parse out the markup tags < and replace them with []. What is the best way to do this?

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  • Php regular expression to match a div

    - by Thoman
    Hello This is mycode <?php /** * @author Joomlacoders * @copyright 2010 */ $url="http://urlchecker.net/html/demo.html"; $innerHtml=file_get_contents($url); //echo $innerHtml; preg_match_all("{\<div id='news-id-.*d'\>(.*)\</div\>}",$innerHtml,$matches); //<div id='news-id-160346'> var_dump($matches); ?> I want find all content in div id='news-id-160346'. Please help me

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  • Regular Expression: Allow letters, numbers, and spaces (with at least one letter or number)

    - by makeee
    I'm currently using this regex ^[A-Z0-9 _]*$ to accept letters, numbers, spaces and underscores. I need to modify it to require at least one number or letter somewhere in the string. Any help would be appreciated! This would be for validating usernames for my website. I'd actually like to support as many characters as I can, but just want to ensure that I prevent code injection and that characters will display fine for all users. So I'm definately open to regex validation suggestions that would support a wider set of characters.

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  • VB.net Regular Expression

    - by xzerox
    Alright so I want to grab the information on a website thats between [usernames] and [/usernames] I know how to get the string but how would I use regex to only have the information in the middle. Remember I am going to be having more then one thing on the page.

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  • ruby parametrized regular expression

    - by astropanic
    I have a string like "{some|words|are|here}" or "{another|set|of|words}" So in general the string consists of an opening curly bracket,words delimited by a pipe and a closing curly bracket. What is the most efficient way to get the selected word of that string ? I would like do something like this: @my_string = "{this|is|a|test|case}" @my_string.get_column(0) # => "this" @my_string.get_column(2) # => "is" @my_string.get_column(4) # => "case" What should the method get_column contain ?

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  • javascript validate zip regular expression

    - by phil
    It's not working. Probably it's syntax error, but I can't figure it out. <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <script> pattern=/^[0-9]{5}$/; if (!pattern.test($('#zip').val)) {$('#zip').append($('<p>',{html: zip is invalid}));} </script> zip (US only): <input type="text" name='zip' id='zip' maxlength="5">

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  • Regular Expressions - Match all alphanumeric characters except individual numbers

    - by imaginonic
    I would like to create a RegEx to match only english alphanumeric characters but ignore (or discard) isolated numbers in Ruby (and if possible in JS too). Examples: 1) I would like the following to be matched: 4chan 9gag test91323432 asf5asdfaf35edfdfad afafaffe But not: 92342424 343424 34432 and so on.. The above is exactly what I would want. 2) However, I would be really thankful if someone could also include French letters like: é ë ê (These are just few examples of many) 1) is my priority, it's totally okay if 2) is impossible or difficult to implement. Sorry, my regex skills aren't that great (hence this question!) Thank you.

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  • Java regular expression: how to include '-'

    - by changed
    I am using this pattern and matching a string. String s = "//name:value /name:value"; if (s.matches("(//?\\s*\\w+:\\w+\\s*)+")) { // it fits } This works properly. But if I want to have a string like "/name-or-address:value/name-or-address:value" which has this '-' in second part, it doesn't work. I am using \w to match A-Za-z_, but how can I include - in that?

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  • Javascript: regular expression

    - by Dmitry Nesteruk
    I need to replace a substring from some string. I've already created corrected code for doing it. But I amn't sure is it best way. Please, see code below: var str = 'test ruby,ruby on rails,ruby,' var substr = 'ruby'; var reg = new RegExp(',' + substr + ',|^' + substr + ',', 'gi'); str.replace(reg, ','); //returns "test ruby,ruby on rails,"

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  • Can you help with regular expressions in Java?

    - by Matt
    I have a bunch of strings which may of may not have random symbols and numbers in them. Some examples are: contains(reserved[j])){ close(); i++){ letters[20]=word I want to find any character that is NOT a letter, and replace it with a white space, so the above examples look like: contains reserved j close i letters word What is the best way to do this?

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  • Match a comma followed by a newline with a regular expression

    - by MarathonStudios
    I have a comma delimited list I want to import into a database, and in some cases the last item is blank: item1, item2, item3 item1, item2, item1, item2, I'd like to replace all of these empty columns with a placeholder value using a regexp item1, item2, item3 item1, item2, PLACEHOLDER item1, item2, PLACEHOLDER I tried preg_replace("/,\n/", ",PLACEHOLDER\n",$csv);, but this isn't working. Anyone know what regexp would work for this?

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