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  • Add console.profile statements to JavaScript/jQuery code on the fly.

    - by novogeek
    Hi folks, We have a thick client app using jQuery heavily and want to profile the performance of the code using firebug's console.profile API. The problem is, I don't want to change the code to write the profile statements. Take this example: var search=function(){ this.init=function(){ console.log('init'); } this.ajax=function(){ console.log('ajax'); //make ajax call using $.ajax and do some DOM manipulations here.. } this.cache=function(){ console.log('cache'); } } var instance=new search(); instance.ajax(); I want to profile my instance.ajax method, but I dont want to add profile statements in the code, as that makes it difficult to maintain the code. I'm trying to override the methods using closures, like this: http://www.novogeek.com/post/2010/02/27/Overriding-jQueryJavaScript-functions-using-closures.aspx but am not very sure how I can achieve. Any pointers on this? I think this would help many big projects to profile the code easily without a big change in code. Here is the idea. Just run the below code in firebug console, to know what I'm trying to achieve. var search=function(){ this.init=function(){ console.log('init'); } this.ajax=function(){ console.log('ajax'); //make ajax call using $.ajax and do some DOM manipulations here.. } this.cache=function(){ console.log('cache'); } } var instance=new search(); $.each(instance, function(functionName, functionBody){ (function(){ var dup=functionBody functionBody=function(){ console.log('modifying the old function: ',functionName); console.profile(functionName); dup.apply(this,arguments); console.profileEnd(functionName); } })(); console.log(functionName, '::', functionBody()); }); Now what I need is, if i say instance.ajax(), I want the new ajax() method to be called, along with the console.profile statements. Hope I'm clear with the requirement. Please improvise the above code. Regards, Krishna, http://www.novogeek.com

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  • Connection to mysql works through php but not through a form submission?

    - by Legend
    I have a download.php file that connects to a remote mysql database. If I run it using php download.php it works fine. But if I create another php file form.php and then submit the form to this download.php, it complains the following: Can't connect to MySQL server on '<IP_ADDRESS>' (13) Does anyone know why this might be happening? I can't see a reason why this works directly but fails to work upon form submission...

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  • How to create a reusable form using COCOA bindings.

    - by Juliano Sott
    hi. I want to make a user interface in which the user can edit two objects at the same time. The main window would have a vertical split view and a form on each side of the view. The problem is that the two forms are identical and I don't want to duplicate the view components in the interface builder. I want to create the form one time and add a reference to it in each side of the split view, each one using a different object source. I could use a NSForm, but the form is not a simple grid of outputTexts and inputText. They have a master table, and diverse kinds of inputs types, like combos, in the detail. How do I create the reusable form using the interface builder? Or how can I do it programmatically? Do I have to create a subclass of NSView and add the individual components in the code? Thanks, Juliano

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  • How do I theme Form API buttons in Drupal?

    - by larssg
    The default output from Drupal's Form API is: <input id="edit-submit" class="form-submit" type="submit" value="Save" name="op"/> How do I theme that so I get: <button id="edit-submit" class="form-submit" type="submit"> <span>Save</span> </button> I need the inner span-tag so I can use the sliding doors CSS technique. I guess I need to override theme_button($element) from form.inc but my attempts so far have been unsuccessful.

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    How to make the use of hidden variables as array for consecutive submission of data so that they can be used to display the records list. I have a form with 4 text fields and a file upload field.. as i submit he form it should get appended to the list which needs to be displayed below the form, such that these values are NOT stored in the DB.. So in this case how can i use the post array to collect the data and display in the list below?

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  • How do you hide an image tag based on an ajax response?

    - by Chris
    What is the correct jquery statement to replace the "//Needed magic" comments below so that the image tags are hidden or unhidden based on the AJAX responses? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>JQuery</title> <style type="text/css"> .isSolvedImage{ width: 68px; height: 47px; border: 1px solid red; cursor: pointer; } </style> <script src="_js/jquery-1.4.2.min.js" type="text/javascript"> </script> </head> <body> <div id='true1.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <div id='false1.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <div id='true2.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <div id='false2.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <script type="text/javascript"> $(function(){ var getDivs = 0; //iterate div with class isSolvedImage $("div.isSolvedImage").each(function() { alert('div id--'+this.id); // send ajax requrest $.get(this.id, function(data) { // check if ajax response is 1 alert('div id--'+this.url+'--ajax response--'+data); if(data == 1){ alert('div id--'+this.url+'--Unhiding image--'); //Needed magic //Show image if data==1 } else{ alert('div id--'+this.url+'--Hiding image--'); //Needed magic //Hide image if data!=1 } }); }); }); </script> </body> </html>

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  • My choice of fieldname for CakePHP's form helper is not working properly, why?

    - by grokker
    Hi, I'm creating an AJAX form. The problem is when I'm trying to create a input form with formhelper, my input's name attribute is not correctly renedered in the view. Here's my code: $form->input('MainAttribute.'.$i.'.SubAttribute.'.$j.'.score', array('label' => '', 'options' => $scores)); I created it that way because I want SubAttribute to be inside MainAttribute. When I inspect the HTML, the name attribute of the form is cutted of like: name="data[SuperMainAttribute]" How can I specify the name attribute to the one that I'm planning on doing? (e.g. data[MainAttribute][0][SubAttribute][0][score])

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  • How to avoid raising an event to a closed form?

    - by Steve Dignan
    I'm having trouble handling the scenario whereby an event is being raised to a closed form and was hoping to get some help. Scenario (see below code for reference): Form1 opens Form2 Form1 subscribes to an event on Form2 (let's call the event FormAction) Form1 is closed and Form2 remains open Form2 raises the FormAction event In Form1.form2_FormAction, why does this return a reference to Form1 but button1.Parent returns null? Shouldn't they both return the same reference? If we were to omit step 3, both this and button1.Parent return the same reference. Here's the code I'm using... Form1: public partial class Form1 : Form { public Form1 () { InitializeComponent(); } private void button1_Click ( object sender , EventArgs e ) { // Create instance of Form2 and subscribe to the FormAction event var form2 = new Form2(); form2.FormAction += form2_FormAction; form2.Show(); } private void form2_FormAction ( object o ) { // Always returns reference to Form1 var form = this; // If Form1 is open, button1.Parent is equal to form/this // If Form1 is closed, button1.Parent is null var parent = button1.Parent; } } Form2: public partial class Form2 : Form { public Form2 () { InitializeComponent(); } public delegate void FormActionHandler ( object o ); public event FormActionHandler FormAction = delegate { }; private void button1_Click ( object sender , EventArgs e ) { FormAction( "Button clicked." ); } } Ideally, I would like to avoid raising events to closed/disposed forms (which I'm not sure is possible) or find a clean way of handling this in the caller (in this case, Form1). Any help is appreciated.

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  • How to use JSON response in the form of JSTL?

    - by HariKrishna
    I am getting JSON response,now i need to construct a table using this response.The table may be contain more than one record and i know one way of doing this is using Jstl tags but not JSON response.Here is my jsp code <div id="divHideAllergies" class="clone"> <div class="copy"> <div class="col-md-12"> <div class="portlet box carrot "> <div class="portlet-title"> <div class="caption"> <i class="fa fa-medkit"></i> Allergies </div> </div> <div class="portlet-body form"> <div class="form-body"> <div class="form-group"> <label class="control-label col-md-3">Allergy Type:</label> <div class="col-md-9"> <div class="input-group"> <span class="input-group-addon"><i class="fa fa-medkit"></i></span> <select class="form-control" id="allergy_type"> <option selected value="">--Select One--</option> <option value="Drug">Drug</option> <option value="Environmental">Environmental</option <option value="Food">Food</option> </select> </div> </div> </div> <div class="form-group"> <label class="control-label col-md-3">Allergic to:</label> <div class="col-md-9"> <div class="input-group"> <span class="input-group-addon"><i class="fa fa-medkit"></i></span> <input type="text" class="form-control" name="first name" id="allergy_to"/> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div>

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  • Making IE "forget" information entered in form when using back button.

    - by typoknig
    I have a page with a form where many of the fields are populated from variables passed in the URL. Those fields are disabled (NON-EDITABLE) and are only there for the user to view. The remaining fields require user input and are NOT disabled (EDITABLE). When the form is submitted a confirmation page comes up. It may be the case that the user needs to submit several of these forms where the NON-EDITABLE information is identical from form to form, so being able to go back to the form page from the confirmation page would save a lot of time. The way I want this to work is when a user presses the back button all the NON-EDITABLE fields are populated, but the EDITABLE fields are blank. This is what Firefox is doing, but IE8 is does not "forget" what has been entered in the EDITABLE fields. To disable the cache the following appears at the beginning of my page AND at the end of my page. <head> <meta http-equiv="Pragma" content="no-cache"/> <meta http-equiv="Cache-Control" content="no-store"/> <head/> What more must I do to make IE forget what was entered in the EDITABLE fields when the back button is pressed? All of my pages are generated with PHP if that matters. EDIT: It appears to me that this is a problem of IE caching my page even though I have told it not to. Are my meta tags correct? Do I need to do something else to prevent IE from caching my page?

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  • How to check if a thread is busy in C#?

    - by Sam
    I have a Windows Forms UI running on a thread, Thread1. I have another thread, Thread2, that gets tons of data via external events that needs to update the Windows UI. (It actually updates multiple UI threads.) I have a third thread, Thread3, that I use as a buffer thread between Thread1 and Thread2 so that Thread2 can continue to update other threads (via the same method). My buffer thread, Thread3, looks like this: public class ThreadBuffer { public ThreadBuffer(frmUI form, CustomArgs e) { form.Invoke((MethodInvoker)delegate { form.UpdateUI(e); }); } } What I would like to do is for my ThreadBuffer to check whether my form is currently busy doing previous updates. If it is, I'd like for it to wait until it frees up and then invoke the UpdateUI(e). I was thinking about either: a) //PseudoCode while(form==busy) { // Do nothing; } form.Invoke((MethodInvoker)delegate { form.UpdateUI(e); }); How would I check the form==busy? Also, I am not sure that this is a good approach. b) Create an event in form1 that will notify the ThreadBuffer that it is ready to process. // psuedocode List<CustomArgs> elist = new List<CustomArgs>(); public ThreadBuffer(frmUI form, CustomArgs e) { from.OnFreedUp += from_OnFreedUp(); elist.Add(e); } private form_OnFreedUp() { if (elist.count == 0) return; form.Invoke((MethodInvoker)delegate { form.UpdateUI(elist[0]); }); elist.Remove(elist[0]); } In this case, how would I write an event that will notify that the form is free? and c) an other ideas?

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  • this.Dispose() Don't release memory used by Form after Closing it .

    - by Ehab Sutan
    Hello, in C# Application. I've a windows form application in which clicking certain button make object from a 2nd Form. On closing this 2nd From by user Memory used by this form not released (from Task Manager). I Tried using this.dispose() on exit button ,tried this.close() , tried form2 =null in the main code ,and tried clearing all controls from this form by code before Disposing and every time the clicks the button memory usage by the application increases more and memory used by previous instance not released. What shall i use to solve this problem ?

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  • how do I get the form data in a javascript object so I can send it as the data parameter of an $.aja

    - by user281180
    How to return json after form.submit()? <form id="NotificationForm" action="<%=Url.Action("Edit",new{Action="Edit"}) %>" method="post" enctype="multipart/form-data" onsubmit='getJsonRequestAfterSubmittingForm(this); return false;'> <%Html.RenderPartial("IndexDetails", Model);%> </form> $.ajax({ url: '<%=Url.Action("Edit","Notification") %>', type: "POST", dataType: 'json', data: $("#NotificationForm").submit(), contentType: "application/json; charset=utf-8", success: function(result) { if (result.Result == true) { alert("ghjghsgd"); } }, error: function(request, status, error) { $("#NotSelectedList").html("Error: " & request.responseText); } });

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  • .NET grouping forms so that pulling up the primary form shows all other forms?

    - by toasteroven
    I have an app that can open up some other forms at the user's request, and they're set to not show in the taskbar. The problem is, if one of the secondary windows becomes hidden by another app, switching to the primary window only brings that form to the forefront. Is there a good way to "group" the forms so that giving any of them focus brings the whole group to the front? I tried calling BringToFront() on each form in the primary form's Activated event, but that also gives the secondary forms focus, making it impossible to interact with the primary form.

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  • django - where to clean extra whitespace from form field inputs?

    - by Westerley
    I've just discovered that Django doesn't automatically strip out extra whitespace from form field inputs, and I think I understand the rationale ('frameworks shouldn't be altering user input'). I think I know how to remove the excess whitespace using python's re: #data = re.sub('\A\s+|\s+\Z', '', data) data = data.strip() data = re.sub('\s+', ' ', data) The question is where should I do this? Presumably this should happen in one of the form's clean stages, but which one? Ideally, I would like to clean all my fields of extra whitespace. If it should be done in the clean_field() method, that would mean I would have to have a lot of clean_field() methods that basically do the same thing, which seems like a lot of repetition. If not the form's cleaning stages, then perhaps in the model that the form is based on? Thanks for your help! W.

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  • Given a user control with a form containing validation can I validate entirely server side?

    - by JoshBaltzell
    We have an existing User Control that was built to dynamically generate a web form for an end user. This form includes required field validators, custom validators that use server side code and Regular Expression validatiors. We now have a need to use all these validators to verify that all the needed data is entered when using a separate ordering process that cannot be validated in the same way, but has the same validation requirements before it is added to the database. I would like to use this user control to validate the input by passing it all the values and checking the validation summary. The only way I know how to do this is to render it to a page on the client side and trigger the form submit. Is there any way to populate and validate a web form entirely on the server side?

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  • C# - How to prevent fullscreen form covering the taskbar?

    - by Dodi300
    Hello. Does anyone know how I can prevent my C# winform covering/going on top of the taskbar? My form's border style has been set to "FixedToolWindow" which seems to cause this. I thought about reducing the height of the form, when the user makes the form maximized, but that wouldn't work as people may have different size taskbars. Any ideas? Thanks.

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  • .net: How do you feed a winform after clicking on a row of a datagridview of search form?

    - by odiseh
    I have a winform which is responsible for doing a search by some conditions that users enters and then selects the records from a Database. The search form has a data grid view which shows the result. After searching, user clikcs on a row of the datagridview and then another form (for example frmShowDetails) will be displayed. My question is when displaying frmShowDetails, what are your suggestions to send the id of selected row to frmShowDetails in order to feed it to show data in .net? Do you use form property or a private mariable which sets by only form constructor? Thank you

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  • What to use instead of if(isset($_POST['submit'])) for this.form.submit()?

    - by paracaudex
    I want to run a particular block of PHP if the user submits a form. It works if I use a submit button with name="submit" and: <?php if(isset($_POST['submit'])) { code to run } ?> I don't know anything about javascript, and I want the code to run if the user changes a dropdown menu. If I make the first line of the dropdown <select name="dropdownname" onchange="this.form.submit()"> the form appears (I haven't tested it) to submit if the user changes the dropdown choice. However, if I do this, the if(isset($_POST['submit'])) PHP code doesn't run. Is there a PHP if statement I can write that will respond to the form being submitted even though it's being submitted by a change in the dropdown and not a submit button?

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  • how can i hide the main form when it log out! ??

    - by Azka
    when i click onto login button, login page appears and when i enter the user id and password it proceeds to main form.. but.. when i log out, the main form appears and the controls transfer back to the log in page.. ... i need to hide that main form when it log outs.. ?? is it clear now??

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