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  • How to optimize this user ranking query

    - by James Simpson
    I have 2 databases (users, userRankings) for a system that needs to have rankings updated every 10 minutes. I use the following code to update these rankings which works fairly well, but there is still a full table scan involved which slows things down with a few hundred thousand users. mysql_query("TRUNCATE TABLE userRankings"); mysql_query("INSERT INTO userRankings (userid) SELECT id FROM users ORDER BY score DESC"); mysql_query("UPDATE users a, userRankings b SET a.rank = b.rank WHERE a.id = b.userid"); In the userRankings table, rank is the primary key and userid is an index. Both tables are MyISAM (I've wondered if it might be beneficial to make userRankings InnoDB).

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  • SQL using sum to count results of multiple subqueries

    - by asdas
    I have a table with 2 columns: integer and var char. I am given only the integer values but need to do work on the var char (string) values. Given an integer, and a list of other integers (no overlap), I want to find the string for that single integer. Then I want to take that string and do the INSTR command with that string, and all the other strings for all the other integers. Then I want the sum of all the INSTR so the result is one number. So lets say I have int x, and list y=[y0, y1, y2]. I want to do 3 INSTR commands like SUM(INSTR(string for x, string for y0), INSTR(string for x, string for y1), INSTR(string for x, string for y2)) I think im going in the wrong direction, this is what I have. Im not good with sub queries. SELECT SUM ( SELECT INSTR ( SELECT string FROM pages WHERE int=? LIMIT 1, ( SELECT string FROM pages WHERE id=? OR id=? OR id=? LIMIT 3 ) ) )

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  • 1.6 or 1.7: Browser side Java version for Oracle VM console

    - by katsumii
    I noticed one of the recent FAQ in OVM forum is about console.OTN Discussion Forums : Oracle VM Server for x86vnc console not running on Oracle VM 3.1.1 One of the variable for running console is Java version. I myself hit the bug below on Windows with JDK1.7 This is Windows only bug. I had success with JDK1.7 on Linux.Bug ID: 7191616 javaws.exe crashes when starting jnlp filejnlp file provided in the steps to reproduce always crashes javaws.exe in Java 7 Update 6.No problems in Update 4

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  • MySQL Connect in Only 5 Days – Some Fun Stuff!

    - by Bertrand Matthelié
    72 1024x768 Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} We’ve recently blogged about the various MySQL Connect sessions focused on MySQL Cluster, InnoDB, the MySQL Optimizer and MySQL Replication. But we also wanted to draw your attention to some great opportunities to network and have fun! That’s also part of what makes a good conference... MySQL Connect Reception San Francisco Hilton - Continental Ballroom 6:30 p.m.–8:30 p.m. A great opportunity to network with Oracle’s MySQL engineers, partners having a booth in the exhibition hall and just about everyone at MySQL Connect. Long time MySQL users will see many familiar faces, and new users will be able to build valuable relationships. A must attend reception for sure! Taylor Street Open House 7:00 p.m.–9:00 p.m. After two intense days at MySQL Connect, you’ll get the chance to relax and continue networking at the Taylor Street Café Open House on Sunday evening. Perhaps recharging batteries for a full week at Oracle OpenWorld… The Oracle OpenWorld Music Festival Starting on Sunday eve and running through the entire duration of Oracle OpenWorld, the first Oracle OpenWorld Musical Festival features some of today’s breakthrough musicians. It’s five nights of back-to-back performances in the heart of San Francisco. Registered Oracle conference attendees get free admission, so remember your badge when you head to a show. More information here. You can check out the full MySQL Connect program here as well as in the September edition of the MySQL newsletter. Not registered yet? You can still save US$ 300 over the on-site fee – Register Now!

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  • New Worklist features on 12.1.3

    - by Vijay Shanmugam
    Following new Worklist features are available on E-Business Suite 12.1.3 via Patch 13646173. Ability to view comments on top of a notification If an action is performed on a notification such as Reassign, Request for Information or Provide Information, the recipient of the notification will see who performed the last action and the associated comment on top of the notification. Reassigning a request for information notification If an approver requests more information on a notification from it's submitter, the submitter now has two options Answer Request for More Information Transfer Request for More Information If the submitter thinks the requested information can be provided by another user, he/she can transfer the request to the other user. Please note that only Transfer is supported for Request for More Information. Once transferred, the submitter cannot access the notification and provide the requested information. Use actual sent date when reassigning a notification The Sent field in notification header always showed the date on which the notification was first created. If the notification was later reassigned, the Sent date was not updated to show the last action date. This caused problems in following scenario Approval notification was sent to JACK on 01-JAN-2012 JACK waited for 10 days before reassigning to JILL on 10-JAN-2012 JILL does not see the notification as sent on 10-JAN-2012, instead sees it as sent on 01-JAN-2012 Although the notification was originally created on 01-JAN-2012, it was sent to JILL only on 10-JAN-2012 The enhancement now shows the correct sent date in Worklist and Notification Details page. Figure 1 - Depicts all the above 3 features Related Action History for response required notification So far it was possible to embed Action History of an response-required notification into another FYI notification using #RELATED_HISTORY attribute (Please refer to Workflow Developer Guide for details about this attribute). The enhancement now enables developers to embed Action History of one response-required notification into another response-required notification. To embed Action History of one response-required notification into another, create message attribute #RELATED_HISTORY. To this attribute set a value during run-time in the following format. {TITLE}[ITEM_TYPE:ITEM_KEY]PROCESS_NAME:ACTIVITY_LABEL_NAMEThe TITLE, ITEM_TYPE and ITEM_KEY are optional values. TITLE is used as Related Action History header title. If TITLE is not present, then a default title "Related Action History" is shown. If ITEM_TYPE is present and ITEM_KEY is not, For Example: {TITLE}[ITEM_TYPE]PROCESS_NAME:ACTIVITY_LABEL_NAME , the Related Action History is populated from parent item type of the current item. If both ITEM_TYPE and ITEM_KEY is present, For Example: {TITLE}[ITEM_TYPE:ITEM_KEY]PROCESS_NAME:ACTIVITY_LABEL_NAME , the Related Action History is populated from that specific instance activity. Figure 2 - Depicts Related Action History feature

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  • "No database selected" even when db clearly selected

    - by Someone
    One of my webpages gets a recurring error: "No database selected", even though the DB is selected. Right about now it's a 50-50 chance whether the page will load just fine, or whether I receive this error. After one or two reloads, the page works again. I am including the exact same connection file on my other pages, and I don't have this problem. What could be the cause of this? I'm using ensim pro for webhosting. TIA.

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  • Oracle Primavera Partner Programs

    - by mark.kromer
    Here is the slide presentation with only the slides that can be shared at this time, for our Oracle Primavera partner programs focusing on expanding P6's workflows and reporting capabilities. By leveraging Oracle's BPM & BI Publisher products, you can build exciting new workflow & enhanced reports to expand the capabilities of Primavera applications.

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  • Help with grasping (INNER?) JOIN

    - by Greenie
    I'm having trouble building a query. I can do what I want in 3 different queries. SELECT id FROM table1 WHERE url LIKE '%/$downloadfile' put that in $url_id SELECT item_id FROM table2 WHERE rel_id = '$url_id'" put that in $item_id SELECT rel_id FROM table2 WHERE rel_id = '$item_id' AND field_id = '42'" put that in $user_id But from reading examples on joins and inner joins I think there's a more elegant way. I cant wrap my brain around writing a better query (but would like to) I can describe how it should go: table1 fields: id, url table2 fields item_id, rel_id, field_id I know the last part of table1.url (LIKE '%/$filename') with that I select table1.id. table1.id is equal to one entry in table2.rel_id. So get that and select the table2.item_id. In table2 there is another entry which has the same table2.item_id and it will have a table2.field_id = '42' And finally the value I need is the table2.rel_id where the table2.field_id was 42. I will fetch that value and put it in $user_id Can this be done with one query using joins/inner joins?

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  • How do I echo out something different when reached last row?

    - by Josh Brown
    I am wanting to not echo out the comma at the end of the echo after the last row. How can I do that? Here is my code: <?php header("Content-type: application/json"); echo '{"points":['; mysql_connect("localhost", "user", "password"); mysql_select_db("database"); $q = "SELECT venues.id, venues.lat, venues.lon, heat_indexes.temperature FROM venues, heat_indexes WHERE venues.id = heat_indexes.venue_id"; $res = mysql_query($q) or die(mysql_error()); while ($point = mysql_fetch_assoc($res)) { echo $point['lat'] . "," . $point['lon'] . "," . $point['temperature'] . ","; } mysql_free_result($res); echo ']}'; ?>

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  • mysql_real_escape_string() just makes an empty string?

    - by James P
    I am using a jQuery AJAX request to a page called like.php that connects to my database and inserts a row. This is the like.php code: <?php // Some config stuff define(DB_HOST, 'localhost'); define(DB_USER, 'root'); define(DB_PASS, ''); define(DB_NAME, 'quicklike'); $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die('ERROR: ' . mysql_error()); $sel = mysql_select_db(DB_NAME, $link) or die('ERROR: ' . mysql_error()); $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg'])); $timeStamp = time(); if(empty($likeMsg)) die('ERROR: Message is empty'); $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; $result = mysql_query($sql, $link) or die('ERROR: ' . mysql_error()); echo mysql_insert_id(); mysql_close($link); ?> The problematic line is $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg']));. It seems to just return an empty string, and in my database under the like_message column all I see is blank entries. If I remove mysql_real_escape_string() though, it works fine. Here's my jQuery code if it helps. $('#like').bind('keydown', function(e) { if(e.keyCode == 13) { var likeMessage = $('#changer p').html(); if(likeMessage) { $.ajax({ cache: false, url: 'like.php', type: 'POST', data: { likeMsg: likeMessage }, success: function(data) { $('#like').unbind(); writeLikeButton(data); } }); } else { $('#button_container').html(''); } } }); All this jQuery code works fine, I've tested it myself independently. Any help is greatly appreciated, thanks.

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  • Critical Patch Update for October 2012 Now Available

    - by Steven Chan (Oracle Development)
    The Critical Patch Update (CPU) for October 2012 was released on July 16, 2012. Oracle strongly recommends applying the patches as soon as possible. The Critical Patch Update Advisory is the starting point for relevant information. It includes a list of products affected, pointers to obtain the patches, a summary of the security vulnerabilities, and links to other important documents. Supported products that are not listed in the "Supported Products and Components Affected" Section of the advisory do not require new patches to be applied. Also, it is essential to review the Critical Patch Update supporting documentation referenced in the Advisory before applying patches, as this is where you can find important pertinent information. The Critical Patch Update Advisory is available at the following location: Oracle Technology Network The next four Critical Patch Update release dates are: January 15, 2013 April 16, 2013 July 16, 2013 October 15, 2013 E-Business Suite Releases 11i and 12 Reference Oracle E-Business Suite Releases 11i and 12 Critical Patch Update Knowledge Document (October 2012) (Note 1486535.1)

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  • I could use some help with my SQL command

    - by SuperSpy
    I've got a database table called 'mesg' with the following structure: receiver_id | sender_id | message | timestamp | read Example: 2 *(«me)* | 6 *(«nice girl)* | 'I like you, more than ghoti' | yearsago | 1 *(«seen it)* 2 *(«me)* | 6 *(«nice girl)* | 'I like you, more than fish' | now | 1 *(«seen it)* 6 *(«nice girl)* | 2 *(«me)* | 'Hey, wanna go fish?' | yearsago+1sec | 0 *(«she hasn't seen it)* It's quite a tricky thing that I want to achieve. I want to get: the most recent message(=ORDER BY time DESC) + 'contact name' + time for each 'conversation'. Contact name = uname WHERE uid = 'contact ID' (the username is in another table) Contact ID = if(sessionID*(«me)*=sender_id){receiver_id}else{sender_id} Conversation is me = receiver OR me = sender For example: From: **Bas Kreuntjes** *(« The message from bas is the most recent)* Hey $py, How are you doing... From: **Sophie Naarden** *(« Second recent)* Well hello, would you like to buy my spam? ... *(«I'll work on that later >p)* To: **Melanie van Deijk** *(« My message to Melanie is 3th)* And? Did you kiss him? ... That is a rough output. QUESTION: Could someone please help me setup a good SQL command. This will be the while loup <?php $sql = "????"; $result = mysql_query($sql); while($fetch = mysql_fetch_assoc($result)){ ?> <div class="message-block"> <h1><?php echo($fetch['uname']); ?></h1> <p><?php echo($fetch['message']); ?></p> <p><?php echo($fetch['time']); ?></p> </div> <?php } ?> I hope my explanation is good enough, if not, please tell me. Please don't mind my English, and the Dutch names (I am Dutch myself) Feel free to correct my English UPDATE1: Best I've got until now: But I do not want more than one conversation to show up... u=user table m=message table SELECT u.uname, m.message, m.receiver_uid, m.sender_uid, m.time FROM m, u WHERE (m.receiver_uid = '$myID' AND u.uid = m.sender_uid) OR (m.sender_uid = '$myID' AND u.uid = m.receiver_uid) ORDER BY time DESC;

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  • Oracle’s Primavera Inspire for SAP: Aligning Business Priorities with Project Priorities

    Oracle’s Primavera Inspire for SAP integrates schedule, financial and resource information between Oracle’s Primavera project portfolio management applications and SAP’s enterprise resource planning solutions. Join Tracy Bowman, Principal Product Manager and learn how Primavera Inspire for SAP can help utilities and oil and gas companies’ complete projects on-time and within budget by providing them with a single access point for all project and portfolio related information.

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  • SQL SELECT across two tables

    - by Brett Spurrier
    Hi there, I am a little confused as to how to approach this SQL query. I have two takes (equal number of records), and I would like to return a column with which is the division between the two. In other words, here is my not-working-correctly query: SELECT( (SELECT v FROM Table1) / (SELECT DotProduct FROM Table2) ); How would I do this? All I want it a column where each row equals the same row in Table1 divided by the same row in Table2. The resulting table should have the same number of rows, but I am getting something with a lot more rows than the original two tables. I am at a complete loss. Any advice?

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  • The Benefits of Oracle's Compliance Architecture

    Fred chats with Deborah Hamilton, Senior Compliance Product Marketing Director at Oracle about what the Oracle Compliance Architecture is, how customers are benefiting from its integrated approach to compliance - of technology, people and processes - and how it helps with organizations meet multiple compliance mandates.

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  • A better way to delete a list of elements from multiple tables

    - by manyxcxi
    I know this looks like a 'please write the code' request, but some basic pointer/principles for doing this the right way should be enough to get me going. I have the following stored procedure: CREATE PROCEDURE `TAA`.`runClean` (IN idlist varchar(1000)) BEGIN DECLARE EXIT HANDLER FOR NOT FOUND ROLLBACK; DECLARE EXIT HANDLER FOR SQLEXCEPTION ROLLBACK; DECLARE EXIT HANDLER FOR SQLWARNING ROLLBACK; START TRANSACTION; DELETE FROM RunningReports WHERE run_id IN (idlist); DELETE FROM TMD_INDATA_INVOICE WHERE run_id IN (idlist); DELETE FROM TMD_INDATA_LINE WHERE run_id IN (idlist); DELETE FROM TMD_OUTDATA_INVOICE WHERE run_id IN (idlist); DELETE FROM TMD_OUTDATA_LINE WHERE run_id IN (idlist); DELETE FROM TMD_TEST WHERE run_id IN (idlist); DELETE FROM RunHistory WHERE id IN (idlist); COMMIT; END $$ It is called by a PHP script to clean out old run history. It is not particularly efficient as you can see and I would like to speed it up. The PHP script gathers the ids to remove from the tables with the following query: $query = "SELECT id, stop_time FROM RunHistory WHERE config_id = $configId AND save = 0 AND NOT(stop_time IS NULL) ORDER BY stop_time"; It keeps the last five run entries and deletes all the rest. So using this query to bring back all the IDs, it determines which ones to delete and keeps the 'newest' five. After gathering the IDs it sends them to the stored procedure to remove them from the associated tables. I'm not very good with SQL, but I ASSUME that using an IN statement and not joining these tables together is probably the least efficient way I can do this, but I don't know enough to ask anything but "how do I do this better?" If possible, I would like to do this all in my stored procedure using a query to gather all the IDs except for the five 'newest', then delete them. Another twist, run entries can be marked save (save = 1) and should not be deleted. The RunHistory table looks like this: CREATE TABLE `TAA`.`RunHistory` ( `id` int(11) NOT NULL auto_increment, `start_time` datetime default NULL, `stop_time` datetime default NULL, `config_id` int(11) NOT NULL, [...] `save` tinyint(1) NOT NULL default '0', PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=0 DEFAULT CHARSET=utf8;

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  • How Can i Create This Complicated Query ?

    - by mTuran
    Hi, I have 3 tables: projects, skills and project_skills. In projects table i hold project's general data. Second table skills i hold skill id and skill name also i have projects_skills table which is hold project's skill relationships. Here is scheme of tables: CREATE TABLE IF NOT EXISTS `project_skills` ( `project_id` int(11) NOT NULL, `skill_id` int(11) NOT NULL, KEY `project_id` (`project_id`), KEY `skill_id` (`skill_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci; CREATE TABLE IF NOT EXISTS `projects` ( `id` int(11) NOT NULL AUTO_INCREMENT, `employer_id` int(11) NOT NULL, `project_title` varchar(100) COLLATE utf8_turkish_ci NOT NULL, `project_description` text COLLATE utf8_turkish_ci NOT NULL, `project_budget` int(11) NOT NULL, `project_allowedtime` int(11) NOT NULL, `project_deadline` datetime NOT NULL, `total_bids` int(11) NOT NULL, `average_bid` int(11) NOT NULL, `created` datetime NOT NULL, `active` tinyint(1) NOT NULL, PRIMARY KEY (`id`), KEY `created` (`created`), KEY `employer_id` (`employer_id`), KEY `active` (`active`), FULLTEXT KEY `project_title` (`project_title`,`project_description`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=3 ; CREATE TABLE IF NOT EXISTS `skills` ( `id` int(11) NOT NULL AUTO_INCREMENT, `category` int(11) NOT NULL, `name` varchar(100) COLLATE utf8_turkish_ci NOT NULL, `seo_name` varchar(100) COLLATE utf8_turkish_ci NOT NULL, `total_projects` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `seo_name` (`seo_name`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=224 ; I want to select projects with related skill names. I think i have to use JOIN but i don't know how can i do. Thanks

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  • Oracle moves to Java technology to embedded middleware

    - by hinkmond
    Here's another article pointing out our move to Java Embedded Middleware with our launch of Oracle Java Embedded Suite 7.0 See: Oracle moves to Java embedded middleware Here's a quote: At the JavaOne Embedded conference, a wafer thin embedded device that was smaller than a Ritz cracker was loaded up with the Java Embedded Suite. I like that: "a wafer thin embedded device". Just one thin wafer. Reminds me of the scene from Monty Python's, The Meaning of Life. "Better?" Hinkmond

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  • Oracle’s Visual CRM Solution

    Visual CRM adds the powerful visualization and document centric collaboration capabilities of Oracle’s AutoVue to Oracle’s best-in-class CRM solutions. By introducing a visual aspect to call center, field service, and ordering processes, Visual CRM helps teams provide faster responses to customer issues, optimize field service performance, and shorten ordering cycles while minimizing order errors.With Visual CRM, organizations can achieve improved customer service levels and field service operations which help drive margin, top line revenue, and customer retention.

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  • Commercial web application--scalable database design

    - by Rob Campbell
    I'm designing a set of web apps to track scientific laboratory data. Each laboratory has several members, each of whom will access both their own data and that of their laboratory as a whole. Many typical queries will thus be expected to return records of multiple members (e.g. my mouse, joe's mouse and sally's mouse). I think I have the database fairly well normalized. I'm now wondering how to ensure that users can efficiently access both their own data and their lab's data set when it is mixed among (hopefully) a whole ton of records from other labs. What I've come up with so far is that most tables will end with two fields: user_id and labgroup_id. The WHERE clause of any SELECT statement will include the appropriate reference to one of the id fields ("...WHERE 'labroup_id=n..." or "...WHERE user_id=n..."). My questions are: Is this an approach that will scale to 10^6 or more records? If so, what's the best way to use these fields in a query so that it most efficiently searches the relevant subset of the database? e.g. Should the first step in querying be to create a temporary table containing just the labgroup's data? Or will indexing using some combination of the id, user_id, and labroup_id fields be sufficient at that scale? I thank any responders very much in advance.

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  • The MySQL Community talks in Japan, Tokyo

    - by Lenka Kasparova
    There will be 2 community meetups in Tokyo in Japan scheduled for June 2014. Please check and join following:  MySQL Casual Talks vol.6 Date: June 11th, 2014 Time: 19:00 Place: Oracle office, Oracle Aoyama Center, 2-5-8 Kita-Aoyama, Minato-ku, Tokyo, Japan More info & Registration MySQL Cluster Casual Talk #2 Date: June 25th, 2014 Time: 19:00 Place: GMO Yours, Cerulean Tower 11F, Shibuya-kuy, Tokyo, Japan More info & registration

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  • UK Oracle User Group Event: Trends in Identity Management

    - by B Shashikumar
    As threat levels rise and new technologies such as cloud and mobile computing gain widespread acceptance, security is occupying more and more mindshare among IT executives. To help prepare for the rapidly changing security landscape, the Oracle UK User Group community and our partners at Enline/SENA have put together an User Group event in London on Apr 19 where you can learn more from your industry peers about upcoming trends in identity management. Here are some of the key trends in identity management and security that we predicted at the beginning of last year and look how they have turned out so far. You have to admit that we have a pretty good track record when it comes to forecasting trends in identity management and security. Threat levels will grow—and there will be more serious breaches:   We have since witnessed breaches of high value targets like RSA and Epsilon. Most organizations have not done enough to protect against insider threats. Organizations need to look for security solutions to stop user access to applications based on real-time patterns of fraud and for situations in which employees change roles or employment status within a company. Cloud computing will continue to grow—and require new security solutions: Cloud computing has since exploded into a dominant secular trend in the industry. Cloud computing continues to present many opportunities like low upfront costs, rapid deployment etc. But Cloud computing also increases policy fragmentation and reduces visibility and control. So organizations require solutions that bridge the security gap between the enterprise and cloud applications to reduce fragmentation and increase control. Mobile devices will challenge traditional security solutions: Since that time, we have witnessed proliferation of mobile devices—combined with increasing numbers of employees bringing their own devices to work (BYOD) — these trends continue to dissolve the traditional boundaries of the enterprise. This in turn, requires a holistic approach within an organization that combines strong authentication and fraud protection, externalization of entitlements, and centralized management across multiple applications—and open standards to make all that possible.  Security platforms will continue to converge: As organizations move increasingly toward vendor consolidation, security solutions are also evolving. Next-generation identity management platforms have best-of-breed features, and must also remain open and flexible to remain viable. As a result, developers need products such as the Oracle Access Management Suite in order to efficiently and reliably build identity and access management into applications—without requiring security experts. Organizations will increasingly pursue "business-centric compliance.": Privacy and security regulations have continued to increase. So businesses are increasingly look for solutions that combine strong security and compliance management tools with business ready experience for faster, lower-cost implementations.  If you'd like to hear more about the top trends in identity management and learn how to empower yourself, then join us for the Oracle UK User Group on Thu Apr 19 in London where Oracle and Enline/SENA product experts will come together to share security trends, best practices, and solutions for your business. Register Here.

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  • How to select parent row only if has at least one child?

    - by Matt McCormick
    I have a simple one-to-many relationship. I would like to select rows from the parent only when they have at least one child. So, if there are no children, then the parent row is not returned in the result set. Eg. Parent: +--+---------+ |id| text | +--+---------+ | 1| Blah | | 2| Blah2 | | 3| Blah3 | +--+---------+ Children +--+------+-------+ |id|parent| other | +--+------+-------+ | 1| 1 | blah | | 2| 1 | blah2 | | 3| 2 | blah3 | +--+------+-------+ I want the results to be: +----+------+ |p.id|p.text| +----+------+ | 1 | Blah | | 2 | Blah2| +----+------+

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