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  • GROUP BY ID range?

    - by d0ugal
    Given a data set like this; +-----+---------------------+--------+ | id | date | result | +-----+---------------------+--------+ | 121 | 2009-07-11 13:23:24 | -1 | | 122 | 2009-07-11 13:23:24 | -1 | | 123 | 2009-07-11 13:23:24 | -1 | | 124 | 2009-07-11 13:23:24 | -1 | | 125 | 2009-07-11 13:23:24 | -1 | | 126 | 2009-07-11 13:23:24 | -1 | | 127 | 2009-07-11 13:23:24 | -1 | | 128 | 2009-07-11 13:23:24 | -1 | | 129 | 2009-07-11 13:23:24 | -1 | | 130 | 2009-07-11 13:23:24 | -1 | | 131 | 2009-07-11 13:23:24 | -1 | | 132 | 2009-07-11 13:23:24 | -1 | | 133 | 2009-07-11 13:23:24 | -1 | | 134 | 2009-07-11 13:23:24 | -1 | | 135 | 2009-07-11 13:23:24 | -1 | | 136 | 2009-07-11 13:23:24 | -1 | | 137 | 2009-07-11 13:23:24 | -1 | | 138 | 2009-07-11 13:23:24 | 1 | | 139 | 2009-07-11 13:23:24 | 0 | | 140 | 2009-07-11 13:23:24 | -1 | +-----+---------------------+--------+ How would I go about grouping the results by day 5 records at a time. The above results is part of the live data, there is over 100,000 results rows in the table and its growing. Basically I want to measure the change over time, so want to take a SUM of the result every X records. In the real data I'll be doing it ever 100 or 1000 but for the data above perhaps every 5. If i could sort it by date I would do something like this; SELECT DATE_FORMAT(date, '%h%i') ym, COUNT(result) 'Total Games', SUM(result) as 'Score' FROM nn_log GROUP BY ym; I can't figure out a way of doing something similar with numbers. The order is sorted by the date but I hope to split the data up every x results. It's safe to assume there are no blank rows. Doing it above with the data you could do multiple selects like; SELECT SUM(result) FROM table LIMIT 0,5; SELECT SUM(result) FROM table LIMIT 5,5; SELECT SUM(result) FROM table LIMIT 10,5; Thats obviously not a very good way to scale up to a bigger problem. I could just write a loop but I'd like to reduce the number of queries.

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  • Create a nested list

    - by sico87
    How would I create a nested list, I currently have this public function getNav($cat,$subcat){ //gets all sub categories for a specific category if(!$this->checkValue($cat)) return false; //checks data $query = false; if($cat=='NULL'){ $sql = "SELECT itemID, title, parent, url, description, image FROM p_cat WHERE deleted = 0 AND parent is NULL ORDER BY position;"; $query = $this->db->query($sql) or die($this->db->error); }else{ //die($cat); $sql = "SET @parent = (SELECT c.itemID FROM p_cat c WHERE url = '".$this->sql($cat)."' AND deleted = 0); SELECT c1.itemID, c1.title, c1.parent, c1.url, c1.description, c1.image, (SELECT c2.url FROM p_cat c2 WHERE c2.itemID = c1.parent LIMIT 1) as parentUrl FROM p_cat c1 WHERE c1.deleted = 0 AND c1.parent = @parent ORDER BY c1.position;"; $query = $this->db->multi_query($sql) or die($this->db->error); $this->db->store_result(); $this->db->next_result(); $query = $this->db->store_result(); } return $query; } public function getNav($cat=false, $subcat=false){ //gets a list of all categories form this level, if $cat is false it returns top level nav if($cat==false || strtolower($cat)=='all-products') $cat='NULL'; $ds = $this->data->getNav($cat, $subcat); $nav = $ds ? $ds : false; $html = ''; //create html if($nav){ $html = '<ul>'; //var_dump($nav->fetch_assoc()); while($row = $nav->fetch_assoc()){ $url = isset($row['parentUrl']) ? $row['parentUrl'].'/'.$row['url'] : $row['url']; $current = $subcat==$row['url'] ? ' class="current"' : ''; $html .= '<li'.$current.'><a href="/'.$url.'/">'.$row['title'].'</a></li>'; } $html .='</ul>'; } return $html; } The sql returns parents and children, for each parent I need the child to nest in a list.

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  • True Excel Templates for BI Publisher

    - by Annemarie Provisero
    ADVISOR WEBCAST: True Excel Templates for BI Publisher PRODUCT FAMILY: EBS/ATG/BI Publisher July 12, 2011 at 7am PT, 8 am MT, 10 am ET This one-hour session is recommended for technical and functional users who want to learn how to code Excel formatted layouts for use with BI Publisher to generate binary Excel output. TOPICS WILL INCLUDE: Creating a simple template Formatting Dates Creating Functions A short, live demonstration (only if applicable) and question and answer period will be included. Oracle Advisor Webcasts are dedicated to building your awareness around our products and services. This session does not replace offerings from Oracle Global Support Services. Click here to register for this session ------------------------------------------------------------------------------------------------------------- The above webcast is a service of the E-Business Suite Communities in My Oracle Support. For more information on other webcasts, please reference the Oracle Advisor Webcast Schedule.Click here to visit the E-Business Communities in My Oracle Support Note that all links require access to My Oracle Support.

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  • FORBES.COM: Oracle's message is loud & clear – “we've got the cloud”

    - by Richard Lefebvre
    In a two-part series on Oracle's cloud strategy, Bob Evans reports on the October 4 meeting where Wall Street analysts questioned Mark Hurd and Safra Catz about the company's positioning for the shift to cloud computing. Check out Bob's related Forbes.com piece "The Dumbest Idea of 2013," in response to the preposterous chatter that Larry Ellison and Oracle don't "get" the cloud. His powerful six-point argument unravels our competitors' spin. Read the "Dumbest Idea."

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  • mysqli real_escape_string problem

    - by tridat
    When im inserting to the database on my dev server the text goes in fine, for example "that's" is "that's" in the db. when uploading the exact same code to production server (hosted on a reseller account at bluehost) "that's" becomes "that\'s", im not double escaping, its exactly the same code, what could be the issue here?

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  • Enable Seamless Transformation and Effective Adoption of Change with Oracle User Productivity Kit

    Organizations go through continuous transformation and change - whether it is through mergers and acquisitions, standardizations of systems, a rollout of a new application or business process improvements. With Oracle User Productivity Kit, project teams can capture and deploy best practices to streamline efficiency, reduce cost, and ensure successful change adoption. Discover how organizations can leverage the multiple outputs of Oracle UPK for all phases of the project from blueprinting/design/configuration to testing/training/go-live as well as maintenance and support.

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  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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  • MySQL error problem

    - by comma
    I keep getting the error listed below but it only says line 1 what does this mean and how do I fix it? Here is the error I keep getting? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 here is the code. if (isset($_POST['info_submitted'])) { $user_id = '5'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); $skill = $_POST['skill']; $experience = $_POST['experience']; $year = $_POST['year']; if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, year) VALUES ('" . $skill . "', '" . $experience . "', '" . $year . "')"); } if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND year='" . $year . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; if (!mysqli_query($mysqli, $query2)) { print mysqli_error($mysqli); return; } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE learned_skills JOIN users_skills ON (users_skills.skill_id = learned_skills.id) SET skill = '$skill', experience = '$experience', year = '$year'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } }

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  • Squid - Logging to MySQL without empty rows/skipped records?

    - by Lee Ward
    I'm trying to figure out how to make Squid proxy log to MySQL. I know ACL order is pretty important but I'm not sure if I understand exactly what ACLs are or do, it's difficult to explain, but hopefully you'll see where I'm going with this as you read! I have created the lines to make Squid interact with a helper in squid.conf as follows: external_acl_type mysql_log %LOGIN %SRC %PROTO %URI php /etc/squid3/custom/mysql_lg.php acl ex_log external mysql_log http_access allow ex_log The external ACL helper (mysql_lg.php) is a PHP script and is as follows: error_reporting(0); if (! defined(STDIN)) { define("STDIN", fopen("php://stdin", "r")); } $res = mysql_connect('localhost', 'squid', 'testsquidpw'); $dbres = mysql_select_db('squid', $res); while (!feof(STDIN)) { $line = trim(fgets(STDIN)); $fields = explode(' ', $line); $user = rawurldecode($fields[0]); $cli_ip = rawurldecode($fields[1]); $protocol = rawurldecode($fields[2]); $uri = rawurldecode($fields[3]); $q = "INSERT INTO logs (id, user, cli_ip, protocol, url) VALUES ('', '".$user."', '".$cli_ip."', '".$protocol."', '".$uri."');"; mysql_query($q) or die (mysql_error()); if ($fault) { fwrite(STDOUT, "ERR\n"); }; fwrite(STDOUT, "OK\n"); } The configuration I have right now looks like this: ## Authentication Handler auth_param ntlm program /usr/bin/ntlm_auth --helper-protocol=squid-2.5-ntlmssp auth_param ntlm children 30 auth_param negotiate program /usr/bin/ntlm_auth --helper-protocol=squid-2.5-basic auth_param negotiate children 5 # Allow squid to update log external_acl_type mysql_log %LOGIN %SRC %PROTO %URI php /etc/squid3/custom/mysql_lg.php acl ex_log external mysql_log http_access allow ex_log acl localnet src 172.16.45.0/24 acl AuthorizedUsers proxy_auth REQUIRED acl SSL_ports port 443 acl Safe_ports port 80 # http acl Safe_ports port 21 # ftp acl Safe_ports port 443 # https acl CONNECT method CONNECT acl blockeddomain url_regex "/etc/squid3/bl.acl" http_access deny blockeddomain deny_info ERR_BAD_GENERAL blockeddomain # Deny requests to certain unsafe ports http_access deny !Safe_ports # Deny CONNECT to other than secure SSL ports http_access deny CONNECT !SSL_ports # Allow the internal network access to this proxy http_access allow localnet # Allow authorized users access to this proxy http_access allow AuthorizedUsers # FINAL RULE - Deny all other access to this proxy http_access deny all From testing, the closer to the bottom I place the logging lines the less it logs. Oftentimes, it even places empty rows in to the MySQL table. The file-based logs in /var/log/squid3/access.log are correct but many of the rows in the access logs are missing from the MySQL logs. I can't help but think it's down to the order I'm putting lines in because I want to log everything to MySQL, unauthenticated requests, blocked requests, which category blocked a specific request. The reason I want this in MySQL is because I'm trying to have everything managed via a custom web-based frontend and want to avoid using any shell commands and access to system log files if I can help it. The end result is to make it as easy as possible to maintain without keeping staff waiting on the phone whilst I add a new rule and reload the server! Hopefully someone can help me out here because this is very much a learning experience for me and I'm pretty stumped. Many thanks in advance for any help!

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  • How to use Insert .. select, with conditional vars from insert

    - by WmasterJ
    I have two separate tables both with user id columns uid. I want to take a value from all users in one table and insert it into the correct row for the correct user in the other table. INSERT INTO users2 (picture) SELECT pv.value FROM profile_values as pv, users2 as u WHERE pv.uid = u.uid AND pv.fid = 31 AND users2.uid=u.uid; But it's not working because i seem not to have access to users2.uid inside of the select statement. How would I accomplish this?

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  • UPMC Picks Oracle Identity Management

    - by Naresh Persaud
    UPMC, a $10-billion integrated global health enterprise, has selected Oracle as a key technology partner in UPMC’s $100-million analytics initiative designed to help “unlock the secrets of human health and disease” by consolidating and analyzing data from 200 separate sources across UPMC’s far-flung network.As part of the project UPMC also selected Oracle Identity Management to secure the interaction and insure regulatory compliance. Read complete article here. As healthcare organizations create new services on-line to provide better care Identity Management can provide a foundation for collaboration.

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  • The Benefits of Oracle's Reporting Tool, XML Publisher

    During this session, Cliff speaks with Mike Tobin, IT Manager, Oracle Apps Development and Architecture for Qualcomm and Tim Dexter EML Publisher Group Product Manager for Oracle about what XML Publisher is, the business need or reporting headache this solution solves for organizations.

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  • How to Reenable Apple Java 6 Plug-in for Mac EBS Users

    - by Steven Chan (Oracle Development)
    Apple's Java for OS X 2012-006 update uninstalled the Apple-provide Java applet plug-in from all Mac web browsers. Mac OS X users running Java-based applications are instructed to download the latest version of the Java 7 applet plug-in from Oracle. For more information about Oracle's Java 7 for Mac, see: Mac Java 7 FAQ: Install, Remove, Revert, Configure, Sys Req (Java.com) We're currently certifying Oracle E-Business Suite with Mac desktops running Java 7. We have identified some compatibility issues and are working with the Java team on fixes right now. Until that certification is completed, EBS users on Mac platforms can follow these instructions from Apple to ensure continued access to the E-Business Suite: Java for OS X 2012-006: How to re-enable the Apple-provided Java SE 6 applet plug-in and Web Start functionality (Apple.com) Related Articles Planning Bulletin for JRE 7: What EBS Customers Can Do Today

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  • Oracle Applications Empower the Green Enterprise

    Eco-Efficiency, Eco-Innovation, Eco-Transparency -- what does it all mean? Learn about the growing interest and need for green, sustainability solutions and how Oracle can help you gain an Eco-Advantage in this conversation with Rich Kroes, Director Oracle Product Strategy.

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  • How to get count of another table in a left join

    - by Sinan
    I have multiple tables post id Name 1 post-name1 2 post-name2 user id username 1 user1 2 user2 post_user post_id user_id 1 1 2 1 post_comments post_id comment_id 1 1 1 2 1 3 I am using a query like this: SELECT post.id, post.title, user.id AS uid, username FROM `post` LEFT JOIN post_user ON post.id = post_user.post_id LEFT JOIN user ON user.id = post_user.user_id ORDER BY post_date DESC It works as intended. However I would like the get the number of comments for each post too. So how can i modify the this query so I can get the count of comments. Any ideas?

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  • Invalid SQL Query

    - by svovaf
    I have the next query that in my opinion is a valid one, but I keep getting error telling me that there is a proble on "WHERE em.p4 = ue.p3" - Unknown column 'ue.p3' in 'where clause'. This is the query: SELECT DISTINCT ue.p3 FROM table1 AS ue INNER JOIN table2 AS e ON ue.p3 = e.p3 WHERE EXISTS( SELECT 1 FROM ( SELECT (COUNT(*) >= 1) AS MinMutual FROM table4 AS smm WHERE smm.p1 IN ( SELECT sem.p3 FROM table3 AS sem INNER JOIN table2 AS em ON sem.p3 = em.p3 WHERE em.p4 = ue.p3 AND sem.type = 'friends' AND em.p2 = 'normal' ) AND smm.p5 IN ( 15000,15151 ) ) AS Mutual WHERE Mutual.MinMutual = TRUE) LIMIT 11 If I execute the sub-query which is inside the EXISTS function, everything is O.K. PLEASE HELP!

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  • Friday Tips #34

    - by Chris Kawalek
    Happy Friday! I wanted to take the opportunity this week to not give out a tip per se, but to point you to a really fantastic white paper that you might have missed. It's called What It Takes to Deploy and Manage a Private Cloud with Oracle VM. The paper is filled with useful information and it's written in a really entertaining style, tackling the IT challenges of a friendly systems administrator named Dave. It gives a great overview of application-driven virtualization and covers Oracle VM, Oracle VM Templates, Oracle VM Storage Connect, and Oracle Enterprise Manager. Read the white paper What It Takes to Deploy and Manage a Private Cloud with Oracle VM. See you next week! -Chris 

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  • Get current updated column name to use in a trigger

    - by Serge
    Is there a way to actually get the column name that was updated in order to use it in a trigger? Basically I'm trying to have an audit trail whenever a user inserts or updates a table (in this case it has to do with a Contact table) CREATE TRIGGER `after_update_contact` AFTER UPDATE ON `contact` FOR EACH ROW BEGIN INSERT INTO user_audit (id_user, even_date, table_name, record_id, field_name, old_value, new_value) VALUES (NEW.updatedby, NEW.lastUpdate, 'contact', NEW.id_contact, [...]) END How can I get the name of the column that's been updated and from that get the OLD and NEW values of that column. If multiple columns have been updated in a row or even multiple rows would it be possible to have an audit for each update?

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  • Optimising (My)SQL Query

    - by Simon
    I usually use ORM instead of SQL and I am slightly out of touch on the different JOINs... SELECT `order_invoice`.*, `client`.*, `order_product`.*, SUM(product.cost) as net FROM `order_invoice` LEFT JOIN `client` ON order_invoice.client_id = client.client_id LEFT JOIN `order_product` ON order_invoice.invoice_id = order_product.invoice_id LEFT JOIN `product` ON order_product.product_id = product.product_id WHERE (order_invoice.date_created >= '2009-01-01') AND (order_invoice.date_created <= '2009-02-01') GROUP BY `order_invoice`.`invoice_id` The tables/ columns are logically names... it's an shop type application... the query works... it's just very very slow... I use the Zend Framework and would usually use Zend_Db_Table_Row::find(Parent|Dependent)Row(set)('TableClass') but I have to make lots of joins and I thought it'll improve performance by doing it all in one query instead of hundreds... Can I improve the above query by using more appropriate JOINs or a different implementation? Many thanks.

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  • Killing Mysql processes staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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