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  • I need to sort php jquery gallery script alphabetically

    - by David Cahill
    know nothing about php, but I have this script that reads a folder and displays a thumbnail gallery, problem is it dosent display alphabetically. Have searched the net and seen that sort does this but have no idea where to start any help would be much appreciated. heres the script $sitename = $row_wigsites['id']; $directory = 'sites/'.$sitename.'/pans'; $allowed_types=array('jpg','jpeg','gif','png'); $file_parts=array(); $ext=''; $title=''; $i=0; $dir_handle = @opendir($directory) or die("There is an error with your image directory!"); while ($file = readdir($dir_handle)) { if($file=='.' || $file == '..') continue; $file_parts = explode('.',$file); $ext = strtolower(array_pop($file_parts)); $title = implode('.',$file_parts); $title = htmlspecialchars($title); $nomargin=''; if(in_array($ext,$allowed_types)) { if(($i+1)%4==0) $nomargin='nomargin'; echo ' <div class="pic '.$nomargin.'" style="background:url('.$directory.'/'.$file.') no-repeat 50% 50%;"> <a href="'.$directory.'/'.$file.'" title="Panoramic Stills taken at '.$title.'°" rel="pan1" target="_blank">'.$title.'</a> </div>'; $i++; } } closedir($dir_handle);

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  • Parse error: syntax error, unexpected T_STRING in...

    - by rabidmachine9
    I' making this class to catch twitter posts but I get the error : Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/classTest/Twitter.php on line 29 I cant find what's wrong...any ideas? class TwitterGrub{ function twitterCapture($user = 'myUsername',$password = 'myPass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum){ $xml = this->twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class='curvebox'>".$xml->status[$i]->text."</div>"; } } }

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  • Mimic Coldfusion's debug output in PHP?

    - by TekiusFanatikus
    I'm trying to mimic Coldfusion's debug output in PHP. Here's an example of what it looks like (ie. Execution Time section): I've turned to XDebug. Ideally, the exception stack error output would be what I'd be looking for. However, it only shows up when an exception occurs. I also tried something like (in our CMS-ish app) this (original question here): $content.= "<?php xdebug_start_trace('e:/xdebug/trace');?>"; $content.= "<?php require('".$page['file_'.LG]."'); ?>"; $content.= "<?php xdebug_stop_trace();?>"; ... $content.= "<?php echo readfile('e:/xdebug/trace.xt');?>"; However, I get an insane, browser crashing HTML table dropped at the bottom of page. Not very efficient. My php.ini config: xdebug.trace_format = 2 xdebug.collect_vars = 1 xdebug.collect_params = 4 xdebug.dump_globals = 1 xdebug.dump.SERVER = 'REQUEST_URI' xdebug.show_local_vars = 1 xdebug.show_mem_delta = 1 I'm just wondering if someone has already done something similar?

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  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • Getting a UIImage from MySQL using PHP and jSON

    - by Daniel
    I'm developing a little news reader that retrieves the info from a website by doing a POST request to a URL. The response is a jSON object with the unread-news. E.g. the last news on the App has a timeStamp of "2013-03-01". When the user refreshes the table, it POSTS "domain.com/api/api.php?newer-than=2013-03-01". The api.php script goes to the MySQL database and fetches all the news posted after 2013-03-01 and prints them json_encoded. This is // do something to get the data in an array echo $array_of_fetched_data; for example the response would be [{"title": "new app is coming to the market", "text": "lorem ipsum dolor sit amet...", image: XXX}] the App then gets the response and parses it, obtaining an NSDictionary and adds it to a Core Data db. NSDictionary* obtainedNews = [NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error]; My question is: How can I add an image to the MySQL database, store it, pass it using jSON trough a POST HTTP Request and then interpret it as an UIImage. It's clear that to store an UIImage in CoreData, they must be transform into/from NSData. How can I pass the NSData back and forth to a MySQL db using php and jSON? How should I upload the image to the db? (Serialized, as a BLOB, etc)

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  • Display all feeds using simplexml_load() using PHP

    - by Jean
    Hello, I want to loop to get all feeds, but displaying only one $url = "http://localhost/feeds/feeds.rss"; $xml = simplexml_load_file($url); foreach($xml->item as $result){ echo $result->description."<br>"; } RSS Feed is - <channel> <title>/</title> <link>/</link> <atom:link type="application/rss+xml" href="/" rel="self"/> <description>/</description> <language>/</language> <ttl>/</ttl> <item> <title>/</title> <description>/</description> <pubDate>/</pubDate> <guid>/</guid> <link>/</link> </item> <item> <title>/</title> <description>/</description> <pubDate>/</pubDate> <guid>/</guid> <link>/</link> </item> </channel> Thanks Jean

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  • How do I return the value of the owner and id attributes respectively from an XML result set using P

    - by pharma_joe
    I am using PHP to iterate over the following result set, the aim is to build a hyperlink for each result using a foreach loop. I have stored the XML result in $images, and have constructed this loop: foreach ($images as $image) { //Build link to each photo returned //base URL $flickrPhotoUrl = 'http://www.flickr.com/photos/'; //Append user ID $flickrPhotoUrl .= ""; echo $flickrPhotoUrl; } Here is a sample result from Flickr: <photos page="1" pages="10982" perpage="10" total="109813"> <photo id="4616840471" owner="47823583@N03" secret="1b83173bc0" server="4013" farm="5" title="Strawberry Bears" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616612597" owner="12658756@N08" secret="f626214382" server="4059" farm="5" title="Yarn Chef Minestrone - Grickle Grass" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616469567" owner="26284268@N00" secret="6911a66838" server="4022" farm="5" title="P5130121.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617076736" owner="26284268@N00" secret="8b990acba4" server="4047" farm="5" title="P5130106.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616470013" owner="26284268@N00" secret="44600b3836" server="4036" farm="5" title="P5130125.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616466147" owner="26284268@N00" secret="554eab8667" server="4052" farm="5" title="P5130116.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617082398" owner="26284268@N00" secret="4a2b663442" server="3350" farm="4" title="P5130118.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617078272" owner="26284268@N00" secret="357737017b" server="4013" farm="5" title="P5130109.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617081446" owner="26284268@N00" secret="1f87726497" server="4048" farm="5" title="P5130117.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617077676" owner="26284268@N00" secret="77ca9f754a" server="3330" farm="4" title="P5130108.JPG" ispublic="1" isfriend="0" isfamily="0"></photo>

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • Update successful notice with pure css and a close button

    - by Crays
    Hi guys, i've seen websites that allow you to say update your profile and when the stuff is done, they'll stay in the same page or redirect you to another and with a fancy notice that says "Update successful. click here to close" with a lowered opacity black background and a box in the middle with the text within. I've got most of the stuff, the lowred opacity black background, the middle box with the text and even the click here to close function. But how i did the "Click here to close" function is by using a link. Let's say after updating the profile, my script redirect me to index.php?update=successful then i use $update = $_GET['update']; if ($update == "successful") { echo '<div id="BlackScreen"><p id="MiddleBox">You\'ve successfully update your status!<br><span class="close"><a class="menu" href="index.php">Click to close. </a></span></div></div>'; } so that the lowered opacity background div will be gone, but is there another way to do this? Any tips please?

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  • jquery getjson works fine in mac, and fails in windows

    - by viper
    this code loads the data jQuery.ajax({ type: "GET", url: "getOptionsJson.php", cache: false, dataType: "json", data: "config_id="+config_id, success: function(json) { jQuery.extend(dataArr, json.ajax); jQuery.extend(opts, json.ajax2); printResult(config_id); }, error: function() { alert('Error. Please try again'); location.reload(); } }); this code generates it <?php header('Content-type: application/javascript'); echo json_encode(array( "ajax" => array(1 => "test", 2 => "test 2"), "ajax2" => array(1 => "test 3", 2 => "test 4") ); ?> when im working on mac, everything goes fine, but today i tried it on widnows, and it doesnt work. the code flows like its success, but opts and dataArr are null i tried all headers (application/json, text/html, etc) i checked if getOptionsJson.php is called correctly via mail function filnally firebug says that im getting response, but theres no content and file is just 1kb i tried even changing datatype to xml, still fails ie gives a hint, it says 'there's error on site' which reffers to 127 line of jquery file any idea?

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  • Ajax div can't access address bar variable

    - by Elaine Adams
    Can someone please advise me on how my Ajax div can get an address bar variable. The usual way just doesn't work. My address bar currently looks like this: http://localhost/social3/browse/?locationName=Cambridge Usually, I would use a little php and do this: $searchResult = $_POST['locationName']; echo $searchResult; But because I'm in an Ajax div, I can't seem to get to the variable. Do I need to add some JavaScript wizardry to my Ajax coding? (I have little knowledge of this) My Ajax: <script> window.onload = function () { var everyone = document.getElementById('everyone'), searching = document.getElementById('searching'), searchingSubmit = document.getElementById('searchingSubmit'); everyone.onclick = function() { loadXMLDoc('indexEveryone'); everyone.className = 'filterOptionActive'; searching.className = 'filterOption'; } searching.onclick = function() { loadXMLDoc('indexSearching'); searching.className = 'filterOptionActive'; everyone.className = 'filterOption'; } searchingSubmit.onclick = function() { loadXMLDoc('indexSearchingSubmit'); } function loadXMLDoc(pageName) { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("leftCont").innerHTML=xmlhttp.responseText; } } function get_query(){ var url = location.href; var qs = url.substring(url.indexOf('?') + 1).split('&'); for(var i = 0, result = {}; i < qs.length; i++){ qs[i] = qs[i].split('='); result[qs[i][0]] = decodeURIComponent(qs[i][1]); } return result; } xmlhttp.open("GET","../browse/" + pageName + ".php?user=" + get_query()['user'],true); xmlhttp.send(); } } </script> <!-- ends ajax script -->

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  • php convert european datetime to mysql datetime

    - by Mathlight
    I'm really stuck with this problem. I've got an datetime string like this: 28-06-14 11:01:00 I'm trying to convert it to 2014-06-28 11:01:00 so that i can insert it into the database ( with field type datetime. I've tryed multiple things like this: $datumHolder = new DateTime($data['datum'], new DateTimeZone('Europe/Amsterdam')); $datum1 = $datumHolder -> format("Y-m-d H:i:s"); $datum2 = date( 'Y-m-d', strtotime(str_replace('-', '/', $data['datum']) ) ); $datum3 = DateTime::createFromFormat( 'Y-m-d-:Hi:s', $data['datum']); This is the output i get: datum1: 2028-06-14 11:01:00 datum2: 1970-01-01 And i get an error for datum3: echo "datum3: " . $datum3->format( 'Y-m-d H:i:s'); . '<br />'; Call to a member function format() on a non-object So my question is very clear... What am I doing wrong / how to get this working? Thanks in advantage guys! I know that this question is asked many, many times... But whatever i try, i can't get it working...

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  • PHP for loop isn't looping after APC installation

    - by BoRo
    So I installed APC and i all of the sudden my for loops only run once and increment the value then stops. I dont get what's going on, it worked fine before APC was installed. Any Suggestions? EDIT: I managed to narrow it down to the increment. for some reason if I have an array let's say string[], and have the for loop list through the values like with string[$i] It only does it for the first one, I can manually echo/print out the array elements to check if the array is the problem but all elements have the appropriate data/values. EDIT #2: Well the code looks something like (it scrapes a page for images and gets some data from it): $str = explode('<div class="images" align="center">',$str); for($i=1;$i<11;$i++){ $url3 = $str[$i]; $url3 = extstr3($url3,'class="filename">','</div>'); $urlname = extstr3($url3,'<a href="','</a>'); $name = extstr3($urlname,'target="_blank">','.jpg'); $url3 = extstr3($url3,'<a href="','" target="_blank">'); $name = str_replace ('_', ' ', $name); . . .

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  • Convert charset in mysql query

    - by Yousf
    Hi, I have a question about converting charset from inside mysql query. I have a 2 databases. One for the website (joomla), the other for forum (IPB). I am doing query from inside joomla, which by default have "SET NAMES UTF8". I want to query a table inside the forum databases. A table called "ibf_topics". This table has latin1 encoding. I do the following to select anything from the not-utf8 table. //convert connection to handle latin1. $query = "SET NAMES latin1"; $db->setQuery($query); $db->query(); $query = "select id, title from other_database.ibf_topics"; $db->setQuery($query); $db->query(); //read result into an array. //return connection to handle UTF8. $query = "SET NAMES UTF8"; $db->setQuery($query); $db->query(); After that, when I want to use the selected tile, I use the following: echo iconv("CP1256", "UTF-8", $topic['title']) The question is, is there anyway to avoid all this hassle? For now, I can't change forum database to UTF8 and I can't change joomla database to latin1 :S

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  • PHP MySQLi isn't letting me alter a table (adding a new column)

    - by asdasd
    Well thats pretty much it. This is my query: $query = 'ALTER TABLE permissions ADD '.$name.' INT NOT NULL DEFAULT \'0\''; Where $name is already checked to exist with only lower case alpha letters, and not more than 20 length. Im just starting this out with very simple names. The next 4 lines of code after that one are: if($stmt = $db -> prepare($query)) { $success = $stmt -> execute(); $stmt -> close(); if(!$success) echo 'ERROR: Unsuccessful query: ',$db->error,PHP_EOL; } And I get back, every time ERROR: Unsuccessful query: And no error message. Is there a way to get more error messages so I can see what is failing? I can add new columns through phpmyadmin, but that really doesnt help me at all. The $db is fine, i do lots of stuff before and after this one section. It is only adding new column to the table that fails. side question: prepare() rejected my query every time when i tried to make those 2 variables, the $name and the 0 value as ? ? prepared statement values. Thats why they are in the real query and not bound later. If i could change that too I would like that.

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  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

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  • Getting an non-object error in my php script

    - by Disowned
    Hey I was trying to call a script to made some changes to an html file, however when I run the script it tells me that it's making a call to a non-object. Obviously I did something wrong, but what? Here's the script. /*Dom controllers*/ $dom = new DOMDocument(); $dom->loadHTML('index.html'); $id = $dom->getElementById('contact_us'); $p = $dom->appendChild(new DOMElement('p')); $op = $dom->getElementsByTagName('p'); /* Dem POST vars used by dat Ajax mah ziggen, yeah boi*/ if (isset($_POST['Home']) && isset($_POST['About']) && isset($_POST['Contact']) && isset($_POST['sexyText'])){ $home = $_POST['Home']; $about = $_POST['About']; $contact = $_POST['Contact']; $text = $_POST['sexyText']; trim($home); trim($about); trim($contact); trim($text); } function post(){ global $dom, $id, $home, $about, $contact, $text, $textp, $p, $op; $textp = $dom->createTextNode($text); $p->appendChild($textp); $id->replaceChild($p, $op); $dom->saveHTMLFile('index.html'); } post(); echo 1; ?> The error happens at the replaceChild function.

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  • php - create columns from mysql list

    - by user271619
    I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

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  • authorise user from mysql database

    - by Jacksta
    I suck at php, and cant find the error here. The script gets 2 variables "username" and "password" from a html from then check them against a MySQL databse. When I run this I get the follow error "Query was empty" <? if ((!$_POST[username]) || (!$_POST[password])) { header("Location: show_login.html"); exit; } $db_name = "testDB"; $table_name = "auth_users"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $slq = "SELECT * FROM $table_name WHERE username ='$_POST[username]' AND password = password('$_POST[password]')"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = mysql_num_rows($result); if ($num != 0) { $msg = "<p>Congratulations, you're authorised!</p>"; } else { header("Location: show_login.html"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Secret Area</title> </head> <body> <? echo "$msg"; ?> </body> </html>

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  • Any suggestions to improve my PDO connection class?

    - by Scarface
    Hey guys I am pretty new to pdo so I basically just put together a simple connection class using information out of the introductory book I was reading but is this connection efficient? If anyone has any informative suggestions, I would really appreciate it. class PDOConnectionFactory{ public $con = null; // swich database? public $dbType = "mysql"; // connection parameters public $host = "localhost"; public $user = "user"; public $senha = "password"; public $db = "database"; public $persistent = false; // new PDOConnectionFactory( true ) <--- persistent connection // new PDOConnectionFactory() <--- no persistent connection public function PDOConnectionFactory( $persistent=false ){ // it verifies the persistence of the connection if( $persistent != false){ $this->persistent = true; } } public function getConnection(){ try{ $this->con = new PDO($this->dbType.":host=".$this->host.";dbname=".$this->db, $this->user, $this->senha, array( PDO::ATTR_PERSISTENT => $this->persistent ) ); // carried through successfully, it returns connected return $this->con; // in case that an error occurs, it returns the error; }catch ( PDOException $ex ){ echo "We are currently experiencing technical difficulties. We have a bunch of monkies working really hard to fix the problem. Check back soon: ".$ex->getMessage(); } } // close connection public function Close(){ if( $this->con != null ) $this->con = null; } }

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  • PHP - uninitialized array offset

    - by kimmothy16
    Hey everyone, I am using PHP to create a form with an array of fields. Basically you can add an unlimited number of 'people' to the form and each person has a first name, last name, and phone number. The form requires that you add a phone number for the first person only. If you leave the phone number field blank on any others, the handler file is supposed to be programmed to use the phone number from the first person. So, my fields are: person[] - a hidden field with a value that is this person's primary key. fname[] - an input field lname[] - an input field phone[] - an input field my form handler looks like this: $people = $_POST['person'] $counter = 0; foreach($people as $person): if(phone[$counter] == '') { // use $phone[0]'s phone number } else { // use $phone[$counter] number } $counter = $counter + 1; endforeach; PHP doesn't like this though, it is throwing me an Notice: Uninitialized string offset error. I debugged it by running the is_array function on people, fname, lname, and phone and it returns true to being an array. I can also manually echo out $phone[2], etc. and get the correct value. I've also ran is_int on the $counter variable and it returned true, so I'm unsure why this isn't working as intended? Any help would be great!

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  • Can anyone get app-engine plugin working with Grails on mac os x?

    - by tim
    I have been trying for 4 days to get app-engine and grails working together on my mac to no avail. I am using latest groovy/grails and appengine sdk versions. Im following the app-engine plugin step by step on the grails site.. http://grails.org/plugin/app-engine Groovy Version: 1.7.1 JVM: 1.5.0_22 Grails 1.3.0.RC1 echo $APPENGINE_HOME reveals /Users/markstim/appengine-java-sdk-1.3.2 I perform the following steps 1. grails create-app myapp 2. cd myapp; grails list-plugins reveals hibernate 1.3.0.RC1 -- Hibernate for Grails tomcat 1.3.0.RC1 -- Apache Tomcat plugin for Grails add the following line to Config.groovy google.appengine.application="myapp" install the plugin for app-engine grails install-plugin app-engine and answer 'jpa' when asked (no errors yet) installed plugins list now looks like app-engine 0.8.9 -- Grails AppEngine plugin gorm-jpa 0.7.1 -- GORM-JPA Plugin then grails run-app and get this error as the server is coming up... [java] WARNING: Nested in org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'pluginManager' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is org.codehaus.groovy.grails.exceptions.NewInstanceCreationException: Could not create a new instance of class [GormJpaGrailsPlugin]!: [java] java.lang.NoClassDefFoundError: org.grails.jpa.JpaPluginSupport then if i navigate to localhost:8080 I get HTTP ERROR: 503 Problem accessing /myapp. Reason: SERVICE_UNAVAILABLE Powered by Jetty://

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  • Dynamically including multiple files within php for image descriptions

    - by Steve Jones
    Working on implementing image descriptions to a php run gallery and can't seem to figure out how to call each text file for each individual image. //total number of images $total = 77; //max number of thumbnails per page $max = 9; //what image do we want to start from? $startcount = $_GET["start"]; //if there is not a defined starting image, we start with the first if(empty($startcount)) { $startcount = 0; } //start off the loop at 1 $loop = 1; //start the loop while($loop <= $max) { //for the picture labels $num = $startcount + $loop; if($num > $total) { $num = $num - 1; break; } // Add class="last" to every third list item if(is_int($num / 3)) { $last = ' class="last"'; } else { $last = ""; } //the code for the image echo ' <li'.$last.'><a href="images/portfolio/pic-'.$num.'.jpg" rel="milkbox[gall1]"><img src="images/portfolio/thumbs/pic-'.$num.'-thumb.jpg" width="256" height="138" alt="Thumbnail of image '.$num.'" /></a><div>'.$num.'</div></li>'; I see that I can call the text files by number using '.$num.' (I have 77 individual text files with a phrase in each) but how do I tell it to call the files?

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  • how to use a PHP Constant that gets pulled from a database

    - by Ronedog
    Can you read out the name of a PHP constant from a database and use it inside of a php variable, to display the value of the constant for use in a menu? For example here's what I'm trying to accomplish In SQL: select menu_name AS php_CONSTANT where menu_id=1 the value returned would be L_HOME which is the name of a CONSTANT in a php config page. The php config page looks like this define('L_HOME','Home'); and gets loaded before the database call. The php usage would be $db_returned_constant which has a value of L_HOME that came from the db call, then I would place this into a string such as $string = '<ul><li>' . $db_returned_constant . '</li></ul>' and thus return a string that looks like $string = '<ul><li><a href="#" onclick="path_from_db">Home</a></li></ul>'. To sum up what I'm trying to do Load a config file based on the language preference query the db to return the menu name, which is the name of a CONSTANT in the config file loaded in step one, and also retrieve the menu_link which is used in the "onclick" event. Use a php variable to hold the name of the CONSTANT Place the variable into a string that gets echo'd out to create the menu displaying the value of the CONSTANT. I hope this makes enough sense...is it even possible to use a constant like this? Thanks.

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  • SELECT SUM PHP MySQL problem

    - by user345426
    This is driving me nuts! Below you will find my PHP/MySQL code but I will post the direct mySQL statement here: SELECT SUM( ot.value ) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP( o.date_purchased ) >=1262332800 AND UNIX_TIMESTAMP( o.date_purchased ) <=1264924800 AND o.sales_rep_id = '2' When I execute this statement inside of phpMyAdmin I get the sum for ot.value which is associated to "msa". Although, when I run my php code it does not return a value. Anyone see the problem? // works in phpMyAdmin but not displaying during PHP execution! $monthly_sales_amount_sql = "SELECT SUM(ot.value) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP(o.date_purchased) >= $start_timestamp AND UNIX_TIMESTAMP(o.date_purchased) <= $end_timestamp AND o.sales_rep_id = '" . $sales_rep_id "'"; $result = mysql_query($monthly_sales_amount_sql); $row = mysql_fetch_assoc($result); echo "MSA: " . $row['msa'] . "<BR><BR>";

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