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  • php - create columns from mysql list

    - by user271619
    I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

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  • Jquery Sorting by Letter

    - by Batfan
    I am using jquery to sort through a group of paragraph tags (kudos to Aaron Harun). It pulls the value "letter" (a letter) from the url string and displays only paragraphs that start with that letter. It hides all others and also consolidates the list so that there are no duplicates showing. See the code: var letter = '<?php echo(strlen($_GET['letter']) == 1) ? $_GET['letter'] : ''; ?>' function finish(){ var found_first = []; jQuery('p').each(function(){ if(jQuery(this).text().substr(0,1).toUpperCase() == letter){ if(found_first[jQuery(this).text()] != true){ jQuery(this).addClass('current-series'); found_first[jQuery(this).text()] = true; }else{ jQuery(this).hide(); } } else{ jQuery(this).hide();} }) } Been working with this all day and I have 2 Questions on this: Is there a way to get it to ignore the word 'The', if it's first? For example, if a paragraph starts with 'The Amazing', I would like it to show up on the 'A' page, not the 'T' page, like it currently is. Is there a way to have a single page for (all) numbers? For example, the url to the page would be something similar to domain.com/index.php?letter=0 and this would show only the paragraph tags that start with a number, any number. I can currently do this with single numbers but, I would like 1 page for all numbers.

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  • cURL + HTTP_POST, keep getting 500 error. Has no idea?

    - by mysqllearner
    Okay, I want to make a HTTP_POST using cURL to a SSL site. I already imported the certificate to my server. This is my code: $url = "https://www.xxx.xxx"; $post = "";# all data that going to send $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $post); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE); curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0'); $exe = curl_exec($ch); $getInfo = curl_getinfo($ch); if ($exe === false) { $output = "Error in sending"; if (curl_error($ch)){ $output .= "\n". curl_error($ch); } } else if($geInfo['http_code'] != 777){ $output = "No data returned. Error: " . $geInfo['http_code']; if (curl_error($ch)){ $output .= "\n". curl_error($ch); } } curl_close($c); echo $output; It keep returned "500". Based on w3schools, 500 means Internal Server Error. Is my server having problem? How to solve/troubleshoot this?

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  • Zend Framework Form Element Validators - validate a field even if not required

    - by Jeremy Hicks
    Is there a way to get a validator to fire even if the form element isn't required? I have a form where I want to validate the contents of a texbox (make sure not empty) if the value of another form element, which is a couple of radio buttons, has a specific value selected. Right now I'm doing this by overriding the isValid() function of my form class and it works great. However, I'd like to move this to either its on validator or use the Callback validator. Here's what I have so far, but it never seems to get called unless I change the field to setRequired(true) which I don't want to do at all times, only if the value of the other form element is set to a specific value. // In my form class's init function $budget = new Zend_Form_Element_Radio('budget'); $budget->setLabel('Budget') ->setRequired(true) ->setMultiOptions($options); $budgetAmount = new Zend_Form_Element_Text('budget_amount'); $budgetAmount->setLabel('Budget Amount') ->setRequired(false) ->addFilter('StringTrim') ->addValidator(new App_Validate_BudgetAmount()); //Here is my custom validator (incomplete) but just testing to see if it even gets called. class App_Validate_BudgetAmount extends Zend_Validate_Abstract { const STRING_EMPTY = 'stringEmpty'; protected $_messageTemplates = array( self::STRING_EMPTY => 'please provide a budget amount' ); public function isValid($value) { echo 'validating...'; var_dump($value); return true; } }

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  • PHP MySQLi isn't letting me alter a table (adding a new column)

    - by asdasd
    Well thats pretty much it. This is my query: $query = 'ALTER TABLE permissions ADD '.$name.' INT NOT NULL DEFAULT \'0\''; Where $name is already checked to exist with only lower case alpha letters, and not more than 20 length. Im just starting this out with very simple names. The next 4 lines of code after that one are: if($stmt = $db -> prepare($query)) { $success = $stmt -> execute(); $stmt -> close(); if(!$success) echo 'ERROR: Unsuccessful query: ',$db->error,PHP_EOL; } And I get back, every time ERROR: Unsuccessful query: And no error message. Is there a way to get more error messages so I can see what is failing? I can add new columns through phpmyadmin, but that really doesnt help me at all. The $db is fine, i do lots of stuff before and after this one section. It is only adding new column to the table that fails. side question: prepare() rejected my query every time when i tried to make those 2 variables, the $name and the 0 value as ? ? prepared statement values. Thats why they are in the real query and not bound later. If i could change that too I would like that.

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  • Somewhat lost with jquery + php + json

    - by Luis Armando
    I am starting to use the jquery $.ajax() but I can't get back what I want to...I send this: $(function(){ $.ajax({ url: "graph_data.php", type: "POST", data: "casi=56&nada=48&nuevo=98&perfecto=100&vales=50&apenas=70&yeah=60", dataType: "json", error: function (xhr, desc, exceptionobj) { document.writeln("El error de XMLHTTPRequest dice: " + xhr.responseText); }, success: function (json) { if (json.error) { alert(json.error); return; } var output = ""; for (p in json) { output += p + " : " + json[p] + "\n"; } document.writeln("Results: \n\n" + output); } }); }); and my php is: <?php $data = $_POST['data']; function array2json($data){ $json = $data; return json_encode($json); } ?> and when I execute this I come out with: Results: just like that I used to have in the php a echo array2json statement but it just gave back gibberish...I really don't know what am I doing wrong and I've googled for about 3 hours just getting basically the same stuff. Also I don't know how to pass parameters to the "data:" in the $.ajax function in another way like getting info from the web page, can anyone please help me? Edit I did what you suggested and it prints the data now thank you very much =) however, I was wondering, how can I send the data to the "data:" part in jQuery so it takes it from let's say user input, also I was checking the php documentation and it says I'm allowed to write something like: json_encode($a,JSON_HEX_TAG|JSON_HEX_APOS|JSON_HEX_QUOT|JSON_HEX_AMP) however, if I do that I get an error saying that json_encode accepts 1 parameter and I'm giving 2...any idea why? I'm using php 5.2

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  • Update successful notice with pure css and a close button

    - by Crays
    Hi guys, i've seen websites that allow you to say update your profile and when the stuff is done, they'll stay in the same page or redirect you to another and with a fancy notice that says "Update successful. click here to close" with a lowered opacity black background and a box in the middle with the text within. I've got most of the stuff, the lowred opacity black background, the middle box with the text and even the click here to close function. But how i did the "Click here to close" function is by using a link. Let's say after updating the profile, my script redirect me to index.php?update=successful then i use $update = $_GET['update']; if ($update == "successful") { echo '<div id="BlackScreen"><p id="MiddleBox">You\'ve successfully update your status!<br><span class="close"><a class="menu" href="index.php">Click to close. </a></span></div></div>'; } so that the lowered opacity background div will be gone, but is there another way to do this? Any tips please?

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  • PHP/Javascript: Need help removing line break from code

    - by Josh K
    I am trying to get names from a .txt file. I am using file('filename.txt') but if i use a php for loop to try and trim the names, it comes out on multiple lines: This is the actual line that prints the javascript (NOTE: I am going to be putting these names into a select box, if you can fix the problem at hand the rest of the code should work so unless you a big problem with it you don't need to comment) <?php for($i=1; $i < 27; $i++){ echo "selbox.options[selbox.options.length] = new Option('".lines[$i]."','".$lines[$i]."');\n"; } ?> Heres how it comes out on the browser: selbox.options[selbox.options.length] = new Option('Djamal ABDOUN ','First1 Last1 '); selbox.options[selbox.options.length] = new Option('Chadli AMRI ','First2 Last2 '); I need those to be on one line so i dont get a unterminated string literal js error Any ideas on what i can do here? EDIT: Oh i should probably mention, the $lines var is initiated like this: $lines = file('filename.txt'); and inside that file i have formatted like this First1 Last1 First2 Last2 First3 Last3 etc. and i hit delete after each Last name until the next first name is touching, then hit enter to put it on a new line (Editor is notepad++)

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  • jQuery UI Autocomplete and CodeIgniter

    - by Kere Puki
    I am trying to implement a simple autocomplete script using jQuery UI and CodeIgniter 2 but my model keeps telling me there is an undefined variable so I dont know if my setup is right. My view $(function() { $("#txtUserSuburb").autocomplete({ source: function(request, response){ $.ajax({ url: "autocomplete/suggestions", data: { term: $("#txtUserSuburb").val() }, dataType: "json", type: "POST", success: function(data){ response(data); } }); }, minLength: 2 }); }); My controller function suggestions(){ $this->load->model('autocomplete_model'); $term = $this->input->post('term', TRUE); $rows = $this->autocomplete_model->getAutocomplete($term); echo json_encode($rows); } My Model function getAutocomplete() { $this->db->like('postcode', $term, 'after'); $query = $this->db->get('tbl_postcode'); $keywords = array(); foreach($query->result() as $row){ array_push($keywords, $row->postcode); } return $keywords; } There arent any errors except it doesn't seem to be passing the $term variable to the model.

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  • php form submit and the resend infromation screen

    - by Para
    Hello, I want to ask a best practice question. Suppose I have a form in php with 3 fields say name, email and comment. I submit the form via POST. In PHP I try and insert the date into the database. Suppose the insertion fails. I should now show the user an error and display the form filled in with the data he previously inserted so he can correct his error. Showing the form in it's initial state won't do. So I display the form and the 3 fields are now filled in from PHP with echo or such. Now if I click refresh I get a message saying "Are you sure you want to resend information?". OK. Suppose after I insert the data I don't carry on but I redirect to the same page but with the necessary parameters in the query string. This makes the message go away but I have to carry 3 parameters in the query string. So my question is: How is it better to do this? I want to not carry around lots of parameters in the query string but also not get that error. How can this be done? Should I use cookies to store the form information.

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  • hy i dont get the check value in check box?

    - by udaya
    Hi I have a check box when check that check box the id corresponding to the check box is placed on a text box ... but when there is only single value in the database i cant get the check value why? here is my code <? if(isset($AcceptFriend)) {?> <form action="<?=site_url()?>friends/Accept_Friend" name="orderform" id="orderform" method="post" style="background:#CCCC99"> <input type="text" name="chId" id="chId" > <table border="0" height="50%" id="chkbox" width="50%" > <tr> <? foreach($AcceptFriend as $row) {?> <tr> <td>Name</td><td><?=$row['dFrindName'].'</br>';?></td> <td> <input type="checkbox" name="checkId" id="checkId" value="<? echo $row['dMemberId']; ?>" onClick="get_check_value()" ></td> </tr> <? }}?> </tr> <tr> <td width="10px"><input type="submit" name="submit" id="submit" class="buttn" value="AcceptFriend"></td></tr> </table> </form> This is the script i am using function get_check_value() { var c_value = ""; for (var i=0; i < document.orderform.checkId.length; i++) { if (document.orderform.checkId[i].checked) { c_value = c_value + document.orderform.checkId[i].value + "\n"; } } alert(c_value); document.getElementById('chId').value= c_value; }

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  • Perl: How do I capture Chinese input via SCIM with STDIN?

    - by KCArpe
    Hi, I use SCIM on Linux for Chinese and Japanese language input. Unfortunately, when I try to capture input using Perl's STDIN, the input is crazy. As roman characters are typed, SCIM tries to guess the correct final characters. ^H (backspace) codes are used to delete previously suggested chars on the command line. (As you type, SCIM tries to guess final Asian chars and displays them.) However, these backspace chars are shown literally as ^H and not interpreted correctly. Example one-liner: perl -e 'print "Chinese: "; my $s = <STDIN>; print $s' When I enable SCIM Chinese or Japanese language input, as I type, e.g., nihao = ??, here is the result: ?^H?^H?^H?^H?^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H?? At the very end of this string, you can see "??" (nihao/hello). At a normal bash prompt, if I type nihao (with Chinese enabled), the results is perfect. This has something to do with interpretation of backspace chars (or control chars) during Perl's STDIN. The same thing happens when using command 'read' in Bash. Witness: read -p 'Chinese: ' s && echo $s Cheers, Kevin

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  • How to keep form items selected after post request?

    - by Ole Jak
    I have a simple html form. On php page. A simple list is placed on form. I submit this form (selected list items) to this page so it gives me page refresh. I want items which were POSTED to be selected after form was submited. How to do such thing? For my form I use such code: <form action="FormPage.php" method="post"> <select id="Streams" class="multiselect ui-widget-content ui-corner-all" multiple="multiple" name="Streams[]"> <?php $query = " SELECT s.streamId, s.userId, u.username FROM streams AS s JOIN user AS u ON s.userId = u.id LIMIT 0 , 30 "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ echo '<option value="' , $row['streamId'] , '"> ' , $row['username'] , ' (' , $row['streamId'] ,')' ,'</option> '; } ?> </select> <br/> <input type="submit" class="ui-state-default ui-corner-all" name="submitForm" id="submitForm" value="Play Stream from selected URL's!"/> </fieldset> </form>

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  • Why is my long polling code for a notification system not updating in real time? PHP MYSQL

    - by tjones
    I am making a notification system similar to the red notification on facebook. It should update the number of messages sent to a user in real time. When the message MYSQL table is updated, it should instantly notify the user, but it does not. There does not seem to be an error inserting into MYSQL because on page refresh the notifications update just fine. I am essentially using code from this video tutorial: http://www.screenr.com/SNH (which updates in realtime if a data.txt file is changed, but it is not written for MYSQL like I am trying to do) Is there something wrong with the below code: **Javascript** <script type="text/javascript"> $(document).ready(function(){ var timestamp = null; function waitForMsg(){ $.ajax({ type: "GET", url: "getData.php", data: "userid=" + userid, async: true, cache: false, success: function(data){ var json = eval('(' + data + ')'); if (json['msg'] != "") { $('.notification').fadeIn().html(json['msg']); } setTimeout('waitForMsg()',30000); }, error: function(XMLHttpRequest, textStatus, errorThrown){ setTimeout('waitForMsg()',30000); } }); } waitForMsg(); </script> <body> <div class="notification"></div> **PHP*** <?php if ($_SERVER['REQUEST_METHOD'] == 'GET' ) { $userid = $_GET['userid']; include("config.php"); $sql="SELECT MAX(time) FROM notification WHERE userid='$userid'"; $result = mysql_query($sql); $row = mysql_fetch_assoc($result); $currentmodif = $row['MAX(time)']; $s="SELECT MAX(lasttimeread) FROM notificationsRead WHERE submittedby='$userid'"; $r = mysql_query($s); $rows = mysql_fetch_assoc($r); $lasttimeread = $rows['MAX(lasttimeread)']; while ($currentmodif <= $lasttimeread) { usleep(10000); clearstatcache(); $currentmodif = $row['MAX(time)']; } $response = array(); $response['msg'] = You have new messages; echo json_encode($response); } ?>

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  • [PHP] Weird problem with dynamic method invocation

    - by Rolf
    Hi everyone, this time, I'm facing a really weird problem. I've the following code: $xml = simplexml_load_file($this->interception_file); foreach($xml->children() as $class) { $path = str_replace('__CLASS_DIR__',CLASS_DIR,$class['path']); if(!is_file($path)) { throw new Exception('Bad configuration: file '.$path.' not found'); } $className = pathinfo($path,PATHINFO_FILENAME); foreach($class as $method) { $method_name = $method['name']; $obj = new $className(); var_dump(in_array($method_name,get_class_methods($className)));exit; echo $obj->$method_name();### not a method ??? } } As you can see, I get the class name and method name from an XML file. I can create an instance of the class without any problem. The var_dump at the end returns true, that means $method_name (which has 2 optional parameters) is a method of $className. BUT, and I am pretty sure the syntax is correct, when I try: $obj-$method_name() I get: Fatal error: Method name must be a string If you have any ideas, pleaaaaase tell me :) Thanks in advance, Rolf

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  • CakePHP Observe field for validation check(already exists)

    - by deck john
    i have already user observe field in cakephp 1.3 Now i want to do the same thing in cakephp 2.0 I have one form.there is a one field named email. When user insert email. onblur there is a popup one message that displays "email already exists" or "right" for that i have write below code in my projects. the below code is my add file code <?php $options = array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exist'); echo $this->ajax->observeField('UserEmailId',array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exists')); ?> In my controller i have created one function like public function is_exist($id = null) { $result = "yes"; $this->set('existdata',$result); } i have also created is_exists.ctp fiel in view/uers. i dont know why its not working. i did the same thing in Cakephp 1.3 and its working file but not in cakephp 2.0 can anyone tell me how i implement this ? thanks in advance

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  • How do I return the value of the owner and id attributes respectively from an XML result set using P

    - by pharma_joe
    I am using PHP to iterate over the following result set, the aim is to build a hyperlink for each result using a foreach loop. I have stored the XML result in $images, and have constructed this loop: foreach ($images as $image) { //Build link to each photo returned //base URL $flickrPhotoUrl = 'http://www.flickr.com/photos/'; //Append user ID $flickrPhotoUrl .= ""; echo $flickrPhotoUrl; } Here is a sample result from Flickr: <photos page="1" pages="10982" perpage="10" total="109813"> <photo id="4616840471" owner="47823583@N03" secret="1b83173bc0" server="4013" farm="5" title="Strawberry Bears" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616612597" owner="12658756@N08" secret="f626214382" server="4059" farm="5" title="Yarn Chef Minestrone - Grickle Grass" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616469567" owner="26284268@N00" secret="6911a66838" server="4022" farm="5" title="P5130121.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617076736" owner="26284268@N00" secret="8b990acba4" server="4047" farm="5" title="P5130106.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616470013" owner="26284268@N00" secret="44600b3836" server="4036" farm="5" title="P5130125.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4616466147" owner="26284268@N00" secret="554eab8667" server="4052" farm="5" title="P5130116.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617082398" owner="26284268@N00" secret="4a2b663442" server="3350" farm="4" title="P5130118.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617078272" owner="26284268@N00" secret="357737017b" server="4013" farm="5" title="P5130109.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617081446" owner="26284268@N00" secret="1f87726497" server="4048" farm="5" title="P5130117.JPG" ispublic="1" isfriend="0" isfamily="0"></photo> <photo id="4617077676" owner="26284268@N00" secret="77ca9f754a" server="3330" farm="4" title="P5130108.JPG" ispublic="1" isfriend="0" isfamily="0"></photo>

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  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

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  • Need a better way to execute console commands from python and log the results

    - by Wim Coenen
    I have a python script which needs to execute several command line utilities. The stdout output is sometimes used for further processing. In all cases, I want to log the results and raise an exception if an error is detected. I use the following function to achieve this: def execute(cmd, logsink): logsink.log("executing: %s\n" % cmd) popen_obj = subprocess.Popen(\ cmd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE) (stdout, stderr) = popen_obj.communicate() returncode = popen_obj.returncode if (returncode <> 0): logsink.log(" RETURN CODE: %s\n" % str(returncode)) if (len(stdout.strip()) > 0): logsink.log(" STDOUT:\n%s\n" % stdout) if (len(stderr.strip()) > 0): logsink.log(" STDERR:\n%s\n" % stderr) if (returncode <> 0): raise Exception, "execute failed with error output:\n%s" % stderr return stdout "logsink" can be any python object with a log method. I typically use this to forward the logging data to a specific file, or echo it to the console, or both, or something else... This works pretty good, except for three problems where I need more fine-grained control than the communicate() method provides: stdout and stderr output can be interleaved on the console, but the above function logs them separately. This can complicate the interpretation of the log. How do I log stdout and stderr lines interleaved, in the same order as they were output? The above function will only log the command output once the command has completed. This complicates diagnosis of issues when commands get stuck in an infinite loop or take a very long time for some other reason. How do I get the log in real-time, while the command is still executing? If the logs are large, it can get hard to interpret which command generated which output. Is there a way to prefix each line with something (e.g. the first word of the cmd string followed by :).

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  • Formating a table date field from the Model in Codeigniter

    - by Landitus
    Hi, I', trying to re-format a date from a table in Codeigniter. The Controller is for a blog. I was succesfull when the date conversion happens in the View. I was hoping to convert the date in the Model to have things in order. Here's the date conversion as it happens in the View. This is inside the posts loop: <?php foreach($records as $row) : ?> <?php $fdate = "%d <abbr>%M</abbr> %Y"; $dateConv = mdate($fdate, mysql_to_unix($row->date)); ?> <div class="article section"> <span class="date"><?php echo $dateConv ;?></span> ... Keeps going ... This is the Model: class Novedades_model extends Model { function getAll() { $this->db->order_by('date','desc'); $query = $this->db->get('novedades'); if($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } } return $data; } } How can I convert the date in the Model? Can I access the date key and refactor it?

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  • Problems with my JS array undefined x 7

    - by Dave
    I have an array im trying to loop through to create a new type of array specific to my current page. My array looks like this: //$_SESSION['data'] = Array ( [0] => 1 [1] => 0 [2] => Tom [8] => 1 [4] => 1 [5] => Array ( [7] => Array ( [0] => Andrew [1] => 1 [2] => 1 [4] => 0 [5] => avatar.jpg [6] => 1 ) ) [6] => Array ( [0] => 1 [1] => 2 ) ) So in my JS file i have this: var stats = <? echo $_SESSION['data'][5]); ?> ; //this is the array my_data = new Array(); for(var key in stats){ if(key in my_data){} else { //prevent double entry my_data[key] = new Array(); my_data[key][0] = stats[key][6]; my_data[key][1] = stats[key][5]; my_data[key][2] = stats[key][2]; my_data[key][3] = stats[key][0]; } } console.log(my_data); Now in console.log i get this : [undefined × 7, Array[4] 0: "1" 1: "avatar.jpg" 2: "1" 3: "Andrew" length: 4 __proto__: Array[0] ] I'm wondering why it is saying undefined x7?

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  • Dynamically including multiple files within php for image descriptions

    - by Steve Jones
    Working on implementing image descriptions to a php run gallery and can't seem to figure out how to call each text file for each individual image. //total number of images $total = 77; //max number of thumbnails per page $max = 9; //what image do we want to start from? $startcount = $_GET["start"]; //if there is not a defined starting image, we start with the first if(empty($startcount)) { $startcount = 0; } //start off the loop at 1 $loop = 1; //start the loop while($loop <= $max) { //for the picture labels $num = $startcount + $loop; if($num > $total) { $num = $num - 1; break; } // Add class="last" to every third list item if(is_int($num / 3)) { $last = ' class="last"'; } else { $last = ""; } //the code for the image echo ' <li'.$last.'><a href="images/portfolio/pic-'.$num.'.jpg" rel="milkbox[gall1]"><img src="images/portfolio/thumbs/pic-'.$num.'-thumb.jpg" width="256" height="138" alt="Thumbnail of image '.$num.'" /></a><div>'.$num.'</div></li>'; I see that I can call the text files by number using '.$num.' (I have 77 individual text files with a phrase in each) but how do I tell it to call the files?

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  • Parse error: syntax error, unexpected T_STRING in...

    - by rabidmachine9
    I' making this class to catch twitter posts but I get the error : Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/classTest/Twitter.php on line 29 I cant find what's wrong...any ideas? class TwitterGrub{ function twitterCapture($user = 'myUsername',$password = 'myPass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum){ $xml = this->twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class='curvebox'>".$xml->status[$i]->text."</div>"; } } }

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  • DOM manipulation in PHP

    - by bluedaniel
    Hello everyone, Im trying to use the DOM in PHP to do a pretty specific job and Ive got no luck so far, the objective is to take a string of HTML from a Wordpress blog post (from the DB, this is a wordpress plugin). And then out of that HTML replace <div id="do_not_edit">old content</div>" with <div id="do_not_edit">new content</div>" in its place. Saving anything above and below that div in its structure. Then save the HTML back into the DB, should be simple really, I have read that a regex wouldnt be the right way to go here so Ive turned to the DOM instead. The problem is I just cant get it to work, cant extract the div or anything. Help me!! UPDATE The HTML coming out of the wordpress table looks like: Congratulations on finding us here on the world wide web, we are on a mission to create a website that will show off your culinary skills better than any other website does. <div id="do_not_edit">blah blah</div> We want this website to be fun and easy to use, we strive for simple elegance and incredible functionality.We aim to provide a 'complete package'. By this we want to create a website where people can meet, share ideas and help each other out. After several different (incorrect) workings all Ive got below is: $content = ($wpdb->get_var( "SELECT `post_content` FROM $wpdb->posts WHERE ID = {$article[post_id]}" )); $doc = new DOMDocument(); $doc->validateOnParse = true; $doc->loadHTMLFile($content); $element = $doc->getElementById('do_not_edit'); echo $element;

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  • 500 internal server error at form connection

    - by klox
    hi..all..i've a problem i can't connect to database what's wrong with my code?this is my code: $("#mod").change(function() { var barcode; barCode=$("#mod").val(); var data=barCode.split(" "); $("#mod").val(data[0]); $("#seri").val(data[1]); var str=data[0]; var matches=str.match(/(EE|[EJU]).*(D)/i); $.ajax({ type:"post", url:"process1.php", data:"value="+matches+"action=tunermatches", cache:false, async:false, success: function(res){ $('#rslt').replaceWith( "<div id='value'><h6>Tuner range is" + res + " .</h6></div>" ); } }); }); and this is my process file: switch(postVar('action')) { case 'tunermatches' : tunermatches(postVar('tuner')); break; function tunermatches($tuner)){ $Tuner=mysql_real_escape_string($tuner); $sql= "SELECT remark FROM settingdata WHERE itemname="Tuner_range" AND itemdata="$Tunermatches"; $res=mysql_query($sql); $dat=mysql_fetch_array($res,MYSQL_NUM); if($dat[0]>0) { echo $dat[0]; } mysql_close($dbc); }

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