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  • Most efficient way to make an activity log

    - by Nathan
    I am making a "recent activity" tab to profiles on my site and I also am going to have a log for moderators to see everything that happens on the site. This would require making an activity log of some sort. I just don't know what would be better. I have 2 options: Make a table called "activity" and then every time someone does something, add a record to it with the type of action, user id, timestamp, etc. Problem: table could get very long. Join all 3 tables (questions, answers, answer_comments) and then somehow show all these on the page in the order in which the action was taken. Problem: this would be extremely hard because I have no clue how I could make it say "John commented on an answer on Question Title Here" by just joining 3 tables. Does anyone know of a better way of making an activity log in this situation? I am using PHP and MySQL. If this is either too inefficient or hard I will probably just forget the Recent Activity tab on profiles but I still need an activity log for moderators. Here's some SQL that I started making for option 2, but this would not work because there is no way of detecting whether the action is a comment, question, or answer when I echo the info in a while loop: SELECT q.*, a.*, ac.* FROM questions q JOIN answers a ON a.questionid = q.qid JOIN answer_comments ac ON c.answerid = a.ans_id WHERE q.user = $userid AND a.userid = $userid AND ac.userid = $userid ORDER BY q.created DESC, a.created DESC, ac.created DESC Thanks in advance for any help!

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  • Use jQuery's dataTable plugin with a nested Ajax call

    - by mrr0ng
    I am trying to use a nested ajax call to populate a table, and once the table is built, use jQuery's dataTable plugin to pretty it up. The problem I am running into is an order of operations question. When do I call the dataTable function so that I can be assured that the table is built AFTER the values are populated? When I try the following code, the dataTable is created before the rows are built. <script type="text/javascript"> $(document).ready(function() { $.ajax({ url:"http://totalrockregistration.com/feeds/bands.php", dataType:"jsonp", success: function(jsonData){ $.each(jsonData.bands, function(i,bands){ if (bands.barID == "<?php echo $_GET["barID"]; ?>"){ var songIdFromBandJson = bands.song; var bandNameFromJson = bands.name; var bandScoreFromJson = bands.score; $.ajax({ url:"http://totalrockregistration.com/feeds/songs.php", dataType:"jsonp", success: function(songsJsonData){ $.each(songsJsonData.songs, function(i,songs){ if (songIdFromBandJson == songs.id){ var songName=(songs.name); $("#leaderBoardTable tbody").append("<tr><td>"+bandNameFromJson+"</td><td>"+bandScoreFromJson+"</td><td>"+songName+"</td></tr>"); } }); } }); } }); makeLeaderTable(); }, }); function makeLeaderTable(){ $('#leaderBoardTable').dataTable({ "aaSorting": [[ 1, "desc" ]], "iDisplayLength": 50 }); } }); </script>

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  • md5_file() not working with IP addresses?

    - by Rob
    Here is my code relating to the question: $theurl = trim($_POST['url']); $md5file = md5_file($theurl); if ($md5file != '96a0cec80eb773687ca28840ecc67ca1') { echo 'Hash doesn\'t match. Incorrect file. Reupload it and try again'; When I run this script, it doesn't even output an error. It just stops. It loads for a bit, and then it just stops. Further down the script I implement it again, and it fails here, too: while($row=mysql_fetch_array($execquery, MYSQL_ASSOC)){ $hash = @md5_file($row['url']); $url = $row['url']; mysql_query("UPDATE urls SET hash='" . $hash . "' WHERE url='" . $url . "'") or die("MYSQL is indeed gay: ".mysql_error()); if ($hash != '96a0cec80eb773687ca28840ecc67ca1'){ $status = 'down'; }else{ $status = 'up'; } mysql_query("UPDATE urls SET status='" . $status . "' WHERE url='" . $url . "'") or die("MYSQL is indeed gay: ".mysql_error()); } And it checks all the URL's just fine, until it gets to one with an IP instead of a domain, such as: http://188.72.215.195/config.php In which, again, the script then just loads for a bit, and then stops. Any help would be much appreciated, if you need any more information just ask.

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  • possible to make codeigniter work with another framework?

    - by ajsie
    the situation is this. my client (who also is a programmer) asks me to develop an address book (with mysql database) with a lot of functions. then he can interact with some class methods i provide for him. kinda like an API. the situation is that the address book application is getting bigger and bigger, and i feel like its way better to use CodeIgniter to code it with MVC. i wonder if i can use codeigniter, then in some way give him the access to controller methods. eg. in a controller there are some functions u can call with the web browser. public function create_contact($information) {..} public function delete_contact($id) {..} public function get_contact($id) {..} however, these are just callable from web browser. how can i let my client have access to these functions like an API? then in his own application he can use: $result = $address_book-create_contact($information); if($result) { echo "Success"; } $contact = $address_book-get_contact($id); is this possible? cause i just know how to access the controller methods with the webbrowser. and i guess its not an option for him to use header(location) to access them. all suggestions to make this possible are welcomed! thanks

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  • decoding jquery json data in php

    - by Mac Taylor
    hey guys recenlty i made a script to move objects and save the orders now i have a little to do to finish this script everything works fine , just one question : how can i save not numeric data in my json script this is my script : function updateWidgetData(){ var items=[]; $('.widget-title').each(function(){ var weightId=$(this).attr('id'); $('.column').each(function(){ var columnId=$(this).attr('id'); $('.widget', this).each(function(i){ var collapsed=0; if($(this).find('.widget-inside').css('display')=="none") collapsed=1; //Create Item object for current panel var item={ id: $(this).attr('id'), collapsed: collapsed, order : i, column: columnId, weight: weightId }; //Push item object into items array items.push(item); }); }); }); //Assign items array to sortorder JSON variable var sortorder={ items: items }; //Pass sortorder variable to server using ajax to save state $.post('updatePanels.php', 'data='+$.toJSON(sortorder), function(response){ if(response=="success") $("#console").html('<div class="success">Saved</div>').hide().fadeIn(1000); setTimeout(function(){ $('#console').fadeOut(1000); }, 2000); }); } and this is my php script : $data=json_decode($_POST["data"]); foreach($data->items as $item) { //Extract column number for panel $col_id=preg_replace('/[^\d\s]/', '', $item->column); //Extract id of the panel $widget_id=preg_replace('/[^\d\s]/', '', $item->id); $sql="UPDATE widgets SET column_id='$col_id', sort_no='".$item->order."', collapsed='".$item->collapsed."' WHERE id='".$widget_id."'"; mysql_query($sql) or die('Error updating widget DB'); } echo "success"; everything works fine till i use numeric value for columns' id but i need non numeric values forexample id='columnr' i want to extract r but i cant get it right any help plz !?

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  • Redirecting Pages with PHP causing problems

    - by psp
    I have a page which has a link to a php page which takes data from $_GET and updates a database. After that it returns the user to the homepage with: header("Location: http://localhost/"); The thing is that this seems to "interrupt" the mysql part of the code. If I remove this redirect, everything in the database is updated, but when I put it back, nothing gets updated... This is the database update code, I am using a class of mine as a mysql wrapper: $conn->where('hash',$data1['hash']); $conn->update(TABLE_ITEMS,$newData1); $conn->where('hash',$data2['hash']); $conn->update(TABLE_ITEMS,$newData2); Notes: -There is no text or echo()'s on the page and no space before the <?php tag Order of Code: Data received from $_SESSION and $_GET Data processed and placed into arrays Data placed into mysql database header(); used to redirect page Code <?php require_once('config.php'); import(); if ( isset ( $_GET['g'] ) && isset ( $_SESSION['itemA'] ) && isset ( $_SESSION['itemB'] ) ) { $itemA = $_SESSION['gameA']; $itemB = $_SESSION['gameB']; $newData1 = processData($itemA); $newData2 = processData($itemB); $conn->update(TABLE_ITEMS,$newData1); $conn->update(TABLE_ITEMS,$newData2); header('Location: http://localhost/'); } else { header('Location: http://localhost/'); }

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  • How can I execute a Java program within a php script?

    - by user450775
    I am writing a simple web upload script. The goal is to upload a file using php, and then calling a java program to process this file. I have done the work for uploading the file, but I cannot get a java program to be successfully run from within the php script. I have tried exec(), shell_exec(), and system() with no results. For the command, I have used "java Test", "java < directory /Test", "/usr/bin/java < directory /Test", I have even set up the application as a jar file with no results. The actual line of code I have used is: echo shell_exec("java Test"); Usually there is no output. However, if I have just shell_exec("java"), then the last line of the help from java ("show splash screen with specified image") is displayed, which shows that the command has been executed. If I use, for example, shell_exec("whoami") I get "nobody" returned, which is correct. The only thing the java file does is create a file so that I can see that the application has been successfully run (the application runs successfully if I run it on the command line). I have set the permissions for the java file to 777 to rule out any possibility of permission errors. I have been struggling with this for a while trying all sorts of options with no results - the file is never created (the file is created with an absolute path so it's not being created and I just can't find the file). Does anyone have any ideas? Thanks.

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  • PHP & HTML Purifier Error: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

    - by TaG
    I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem? I get the following error. on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given line 22 is. if (mysqli_num_rows($dbc) == 0) { Here is the php code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

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  • Logging in with sha1() encryption.

    - by Samir Ghobril
    Hey guys, I added this to my sign up code : $password=mysql_real_escape_string(sha1($_POST['password'])); and now it inserts the password into the database while its encrypted. But signing in doesn't seem to work anymore. Here is the login code. function checklogin($username, $password){ global $mysqli; $password=sha1($password); $result = $mysqli->prepare("SELECT * FROM users WHERE username = ? and password=?"); $result->bind_param("ss", $username, $password); $result->execute(); if($result != false){ $dbArray=$result->fetch(); if(!$dbArray){ echo '<p class="statusmsg">The username or password you entered is incorrect, or you haven\'t yet activated your account. Please try again.</p><br/><input class="submitButton" type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; if(isset($_POST['remember'])){ setcookie("jmuser",$username,time()+60*60*24*356); setcookie("jmpass",$password ,time()+60*60*24*356); } redirect(); }

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  • Trying to join two independent forms

    - by user248959
    Hi, i'm trying to join two independent forms (login and register) in the same page. My idea is (just looking at the signin form): Create an action that shows both forms (partials): public function executeLoginAndRegister(sfWebRequest $request){ $this->form_signin = $this->getUser()->getAttribute('form_signin'); } Each partial calls to its action: form action="php? echo url_for('@sf_guard_signin') ?" method="post" In the actions i write this code public function executeSignin($request) { //... $this->form = new $MyFormclass(); if ($this->form->isValid()) { //... }else{ // save the form to show the error messages. $this-&gt;getUser()-&gt;setAttribute('form_signin', $this-&gt;form); return $this-&gt;forward('sfGuardAuth', 'loginAndRegister'); } } It works, but, for example, if i execute LoginAndRegister and submit incorrectly the signin form and I go to another page and then return to LoginAndRegister, i will find the submiting error messages... If i execute LoginAndRegister and submit incorrectly the signin form and open another browser tab, i will find the submiting error messages in the signin form of the second tab... Any idea? any better approach?

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  • Insert names into table if not already existing

    - by John
    I am trying to build an application that allows users to submit names to be added to a db table (runningList). Before the name is added tho, I would like to check firstname and lastname against another table (controlList). It must exist in (controlList) or reply name not valid. If the name is valid I would like to then check firstname and lastname against (runningList) it make sure it isnt already there. If it isnt there, then insert firstname & lastname. If it is there, reply name already used. Below is code that worked before I tried to add the test against the controlList, I somehow broke it altogether while trying to add the extra step. if (mysql_num_rows(mysql_query('SELECT * FROM runninglist WHERE firstname=\'' .$firstname . '\' AND lastname=\'' . $lastname . '\' LIMIT 1')) == 0) { $sql="INSERT INTO runninglist (firstname, lastname) VALUES ('$_POST[firstname]','$_POST[lastname]')"; } else { echo "This name has been used."; } Any direction would be appreciated. Thanx John

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  • problem with include in PHP

    - by EquinoX
    I have a php file called Route.php which is located on: /var/www/api/src/fra/custom/Action and the file I want to include is in: /var/www/api/src/fra/custom/ So what I have inside route php is an absolute path to the two php file I want to include: <?php include '/var/www/api/src/frapi/custom/myneighborlists.php'; include '/var/www/api/src/frapi/custom/mynodes.php'; ............ ........... ?> These two file has an array of large amount of size that I want to use in Route.php. When I do vardump($global) it just returns NULL. What am I missing here? UPDATE: I did an echo on the included file and it prints something, so therefore it is included.. however I can't get access that array... when I do a vardump on the array, it just returns NULL! I did add a global $myarray inside the function in which I want to access the array from the other php file Sample myneighborlists.php: <?php $myarray = array( 1=> array(3351=>179), 2=> array(3264=>172, 3471=>139), 3=> array(3467=>226), 4=> array(3309=>211, 3469=>227), 5=> array(3315=>364, 3316=>144, 3469=>153), 6=> array(3305=>273, 3309=>171), 7=> array(3267=>624, 3354=>465, 3424=>411, 3437=>632), 8=> array(3302=>655, 3467=>212), 9=> array(3305=>216, 3306=>148, 3465=>505), 10=> array(3271=>273, 3472=>254), 11=> array(3347=>273, 3468=>262), 12=> array(3310=>237, 3315=>237)); ?>

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  • Problem with configure script

    - by cube
    I am running into a problem with the ./configure script for ffmpeg. My linux environment uses busybox, which only allows for limited set of linux commands. One command which is used in the ffmpeg ./configure script is mktemp -u, the problem here is the busybox for linux does not recognize the -u switch as valid, so it complains about it and breaks the configure process. This is the relevant code in ./configure which uses the mktemp -u command: if ! check_cmd type mktemp; then # simple replacement for missing mktemp # NOT SAFE FOR GENERAL USE mktemp(){ echo "${2%XXX*}.${HOSTNAME}.${UID}.$$" } fi tmpfile(){ tmp=$(mktemp -u "${TMPDIR}/ffconf.XXXXXXXX")$2 && (set -C; exec > $tmp) 2>/dev/null || die "Unable to create temporary file in $TMPDIR." append TMPFILES $tmp eval $1=$tmp } I am not good with bash scripting at all, so I was wondering if anyone one had an idea on how I can force this configure script to not use mktemp -u and use the 'replacement' alternative option that is available in as per the snippet above. Thanks. btw... simply removing the -u switch does not work. Nor does replacing it with -t, or -p. I believe the mktemp has to be bypassed completely.

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  • Display attribute from XML using PHP

    - by user560411
    Hello. I need to display the id attribute of CD from the following XML file. I display correctly everything except the id. Any help would be appreciate. display code <?php $doc = new DOMDocument(); $doc->load( 'insert.xml' ); $CATEGORIES = $doc->getElementsByTagName( "CD" ); foreach( $CATEGORIES as $CD ) { $TITLES = $CD->getElementsByTagName( "TITLE" ); $TITLE = $TITLES->item(0)->nodeValue; $BANDS= $CD->getElementsByTagName( "BAND" ); $BAND= $BANDS->item(0)->nodeValue; $YEARS = $CD->getElementsByTagName( "YEAR" ); $YEAR = $YEARS->item(0)->nodeValue; echo "<b>$TITLE - $BAND - $YEAR\n</b><br>"; } ?> XML <?xml version="1.0" encoding="utf-8"?> <MY_CD> <CATEGORIES> <CD id="3231"> <TITLE>NEVER MIND THE BOLLOCKS</TITLE> <BAND>SEX PISTOLS</BAND> <YEAR>1977</YEAR> </CD> <CD id="2453"> <TITLE>NEVERMIND</TITLE> <BAND>NIRVANA</BAND> <YEAR>1991</YEAR> </CD> </CATEGORIES> </MY_CD>

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  • Linux: Find all symlinks of a given 'original' file? (reverse 'readlink')

    - by sdaau
    Hi all, Consider the following command line snippet: $ cd /tmp/ $ mkdir dirA $ mkdir dirB $ echo "the contents of the 'original' file" > orig.file $ ls -la orig.file -rw-r--r-- 1 $USER $USER 36 2010-12-26 00:57 orig.file # create symlinks in dirA and dirB that point to /tmp/orig.file: $ ln -s $(pwd)/orig.file $(pwd)/dirA/ $ ln -s $(pwd)/orig.file $(pwd)/dirB/lorig.file $ ls -la dirA/ dirB/ dirA/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:57 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:57 orig.file -> /tmp/orig.file dirB/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:58 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:58 lorig.file -> /tmp/orig.file At this point, I can use readling to see what is the 'original' (well, I guess the usual term here is either 'target' or 'source', but those in my mind can be opposite concepts as well, so I'll just call it 'original') file of the symlinks, i.e. $ readlink -f dirA/orig.file /tmp/orig.file $ readlink -f dirB/lorig.file /tmp/orig.file ... However, what I'd like to know is - is there a command I could run on the 'original' file, and find all the symlinks that point to it? In other words, something like (pseudo): $ getsymlinks /tmp/orig.file /tmp/dirA/orig.file /tmp/dirB/lorig.file Thanks in advance for any comments, Cheers!

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  • How can I achieve this kind of relationship (inheritance, composition, something else)?

    - by Tim
    I would like to set up a foundation of classes for an application, two of which are person and student. A person may or may not be a student and a student is always a person. The fact that a student “is a” person led me to try inheritance, but I can't see how to make it work in the case where I have a DAO that returns an instance of person and I then want to determine if that person is a student and call student related methods for it. class Person { private $_firstName; public function isStudent() { // figure out if this person is a student return true; // (or false) } } class Student extends Person { private $_gpa; public function getGpa() { // do something to retrieve this student's gpa return 4.0; // (or whatever it is) } } class SomeDaoThatReturnsPersonInstances { public function find() { return new Person(); } } $myPerson = SomeDaoThatReturnsPersonInstances::find(); if($myPerson->isStudent()) { echo 'My person\'s GPA is: ', $myPerson->getGpa(); } This obviously doesn't work, but what is the best way to achieve this effect? Composition doesn't sond right in my mind because a person does not “have a” student. I'm not looking for a solution necessarily but maybe just a term or phrase to search for. Since I'm not really sure what to call what I'm trying to do, I haven't had much luck. Thank you!

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  • Change post form data function into curl

    - by QLiu
    Hello Guys, In the old way in our website, when users clicks “logout” button. It runs a post form function; which will pass parameters (logout, sn) to external sites to execute “logout” function. Like: I do not want the users jump to the external site, therefore, i use curl to post data. (because we are in different domain, i guess Ajax request doesnot work ) Post the same data to execute logout function in external site. // create cURL resource $URL = "http://bswi.development.intra.local/"; //Initl curl $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $URL); // Load in the destination URL curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); //Normal HTTP request, not SSL curl_setopt($ch, CURLOPT_POSTFIELDS, "logout=1"); // receive server response ... curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_exec ($ch); echo $content; curl_close ($ch); Do u think i am going in the right direction?

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  • jQuery slider to load content one at a time

    - by Barrett
    I have a slider that load all of my content at once. Into a div. Like so: external page.php $get_users = mysql_query("SELECT * FROM user WHERE id!='$user_id'"); while ($rows = mysql_fetch_assoc($get_users)) { $id = $rows['id']; $firstname = $rows['firstname']; $display_info .= ' <div class="f_outer" id="' . $id . '"> <div class="f_name likeu">' . $firstname . '</div> </div>'; } echo $display_info; I call this page from my find.php page using bxslider Here is my find.php page below. <script type="text/javascript"> $(function() { var slider = $("#slider1").bxSlider(); $("#slider-like").live('click', function() { slider.goToNextSlide(); return false; }); }); </script> <div id="slider-like>Yes</div> <div id="slider1"> <?PHP include ("external.php"); ?> </div> So what I get is all of my .f_outer div on the find.php page. I have hundreds of user and they will all be loaded at once. I would like to only load one slide at a time. So when I click #slider-like it load one of my dive from my external page.

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  • A logical problem with two tables

    - by Luke
    Hey guys, I created a list for fixtures. $result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date"); $i = 1; $d = "Start"; while ($row = mysql_fetch_assoc($result)) { $odate = $row['date']; $date=date("F j Y", $row['date']); echo "<p>Fixture $i - $d to $date</p>"; } As you can see from the query, the date is displayed from the fixtures table. The way my system works is that when a fixture is "played", it is removed from this table. Therefore when the entire round of fixtures are complete, there wont be any dates for that round in this table. They will be in another table. Is there anyway I can run an other query for dates at the same time, and display only dates from the fixtures table if there isnt a date in the results table? "SELECT * FROM ".TBL_CONF_RESULTS." WHERE compid = '$_GET[id]' && type2 = '2' ORDER BY date" That would be the second query!

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  • gems, bundle command, and ruby not found in new terminal window

    - by user3579987
    So I installed ruby with rvm, ran a bundle install and installed a bunch of gems, etc. It all works just fine in the original terminal window I did all of this in but I opened up a new terminal window and now I'm getting errors like bundle: command not found and gem command not found. I tried doing a symbolic link for the gem command but then when I do gem list it displays a much shorter list of my local gems and not at all the ones I need for bundle install. Is there something I need to do to configure bash or rvm so that it recognizes that I did indeed install all the gems I have installed? name@crunchbang:~/ug_research_portal$ which gem /home/name/.rvm/rubies/ruby-2.1.1/bin/gem name@crunchbang:~/ug_research_portal$ which ruby /home/name/.rvm/rubies/ruby-2.1.1/bin/ruby And in ~/.bashrc: GEM_HOME="/home/name/.rvm/gems/ruby-2.1.1" GEMGLOBAL_HOME="/home/ name/.rvm/gems/ruby-2.1.1@global" export PATH=$PATH:$GEM_HOME/bin:$GEMGLOBAL_HOME/bin:$HOME/.rvm/bin Edit: Looks like my $PATH is somehow wrong? bash: /home/name/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/bin:/bin:/usr/local/games:/usr/games:/home/name/.rvm/gems/ruby-2.1.1/bin:/home/name/.rvm/gems/ruby-2.1.1@global/bin:/home/name/.rvm/bin/: No such file or directory which is odd since ls for /home/name/.rvm/bin and /home/name/.rvm/gems/ruby-2.1.1@global/bin and /home/name/.rvm/gems/ruby-2.1.1/bin work just fine Psych, I was just doing $PATH instead of echo "$PATH" which was giving me the No such file or directory error. The original problem still stands though.

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  • 3 small PHP errors I cannot decipher

    - by Dave
    *Notice: Use of undefined constant _ - assumed '_' in /.../uploader.php on line 45* Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Notice: Undefined index: approve in /.../uploader.php on line 81 Line 81 - the second last line here $query = sprintf("INSERT INTO `$db_name`.`the_table` (`id` , `name` , `photo` , `email` , `date` , `code` , `subscribe` , `approve` , `created` ) VALUES ( NULL , '%s', '%s', '%s', '%s', '%s', '%s', '1', CURRENT_TIMESTAMP );", mysql_real_escape_string($_POST['name']), mysql_real_escape_string($newname), mysql_real_escape_string($_POST['email']), mysql_real_escape_string($date), mysql_real_escape_string($_POST['code']), mysql_real_escape_string($subscribe), mysql_real_escape_string($_POST['approve']) ); Warning: Cannot modify header information - headers already sent by (output started at /.../uploader.php:45) in/.../uploader.php on line 102 Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Line 102 - the third line here if ($success == 'Done') { $page = 'uploader'; header('Location: ./thanks.php'); } else { echo "error"; }

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  • Difficulty Inserting from HTML form into MySQL (created in Workbench)

    - by Chaya Cooper
    I created a MySQL database in Workbench 5.2.35 for purposes of storing and using information submitted in html forms but I'm having difficulty inserting records from the html form. The relevant SQL script was saved as Demo2.sql, the schema is C2F, and the table is customer_info. I wasn't sure if that was the problem, so I tried replacing the database name (Demo2) with the schema name, but that didn't work either. My html file includes: form action="insert.php" method="post" The insert.php file states: ?php $con = mysql_connect("localhost","root","****"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Demo2", $con); $sql="INSERT INTO customer_info(fname, lname, user, password, reminder, answer) VALUES ('$_POST[fname]','$_POST[lname]','$_POST[user]','$_POST[password]','$_POST[reminder]','$_POST[answer]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ? I've also tried INSERT INTO c2f.customer_info(fname, lname, etc. and INSERT INTO 'c2f'.'customer_info'

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • Can I automate a loop query based on category with the page's title?

    - by jordaninternets
    To explain further, I need to get a page to display posts from a specific category. I want to automate this process so I don't have to make a template for each category. How would I do that? (keep in mind the person I'm building this is for has no coding experience.) The only way I could think off from the top of my head is to use the title or slug. So if the category is named the same thing as the slug, could I filter by category using the slug? Maybe this isn't the best way... what should I do? This is what I came up with, but it doesn't work, I'm sure due to improper use on may part, but I've been pouring over the WP codex and Google with no avail to tell me my problem. <?php $paged = (get_query_var('paged')) ? get_query_var('paged') : 1; $args= array( 'orderby' => 'date', 'order' => 'ASC', 'paged' => $paged, 'category_name' => echo the_title('\'','\'',) ); query_posts($args); ?>

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  • how to disable an onclick event?

    - by user1819709
    <form id="QandA" action="<?php echo htmlentities($action); ?>" method="post"> <table id="question"> <tr> <td colspan="2"> <a onclick="return plusbutton();"> <img src="Images/plussign.jpg" width="30" height="30" alt="Look Up Previous Question" class="plusimage" id="mainPlusbutton" name="plusbuttonrow"/> </a> <span id="plussignmsg">(Click Plus Sign to look up Previous Questions)</span> </td> </tr> </table> </form> In the code above I am able to replace an image with another image when the if statement is met. But my problem is that when the image is replaced, it does not disable the on click event. My question is that when the image is replaced, how do I disable the onclick event onclick="return plusbutton();?

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