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  • How to split up a long list using \n

    - by pypy
    Here is a long string that I convert to a list so I can manipulate it, and then join it back together. I am having some trouble being able to have an iterator go through the list and when the iterator reach, let us say every 5th object, it should insert a '\n' right there. Here is an example: string = "Hello my name is Josh I like pizza and python I need this string to be really really long" string = string.split() # do the magic here string = ' '.join(string) print(string) Output: Hello my name is Josh I like pizza and python I need this string to be really really long Any idea how i can achieve this? I tried using: for words in string: if words % 5 == 0: string.append('\n') but it doesn't work. What am I missing?

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  • converting ID to column name and also replacing NULL with last known value.

    - by stackoverflowuser
    TABLE_A Rev ChangedBy ----------------------------- 1 A 2 B 3 C TABLE_B Rev Words ID ---------------------------- 1 description_1 52 1 history_1 54 2 description_2 52 3 history_2 54 Words column datatype is ntext. TABLE_C ID Name ----------------------------- 52 Description 54 History OUTPUT Rev ChangedBy Description History ------------------------------------------------ 1 A description_1 history_1 2 B description_2 history_1 3 C description_2 history_2 Description and History column will have the previous known values if they dont have value for that Rev no. i.e. Since for Rev no. 3 Description does not have an entry in TABLE_B hence the last known value description_2 appears in that column for Rev no. 3 in the output.

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  • Can not search my company howto blog site anylonger... i can only search my mysites and users...

    - by Worldunix
    I have a Howto company Blog site that i post to for my clients to access for help. For some reason it has stopped letting anyone search on it. I can search for Mysites or users. But when you drop down the tab to search: This Site: "blog site name" you get the following reply: No results matching your search were found. Check your spelling. Are the words in your query spelled correctly? Try using synonyms. Maybe what you're looking for uses slightly different words. Make your search more general. Try more general terms in place of specific ones. Try your search in a different scope. Different scopes can have different results. I have tried the following command: from the Index server net stop osearch net start osearch iisreset /noforce But still not able to search a local blog site I can only search for users and Sites. please help Don

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  • How do I do proximity search in Oracle right?

    - by hko19
    Oracle's NEAR operator for full text search returns a score based on the proximity of two or more query terms. For example: near((dog, bite), 6) matches if 'dog' and 'bite' occurs within 6 words. What if I'd like it to match if either 'dog' or 'cat' or any other type of animal occurs within 6 words of the word 'bite'? I tried: near(((dog OR cat OR animal), bite), 6) but I got: NEAR operand not a phrase, equivalence or another NEAR expression Rather than expanding all possible combination into multiple NEAR and 'or' them together, what is the proper way to write such query?

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  • Mod_rewrite works on local, not on remote, version?

    - by TylerT
    I have this site. Let's call it htp://www.mysite.com I have a rewrite rule to change htp://www.mysite.com/?q=words%20etc/0/10 into http://www.mysite.com/words%20etc/0/10 (or http://www.mysite.com//0/10 or http://www.mysite.com/0/10) .htaccess:ErrorDocument 404 htp://www.mysite.com/404.html options +FollowSymlinks rewriteEngine on rewriteCond %{REQUEST_URI} !-f rewriteCond %{REQUEST_URI} !-d rewriteCond %{REQUEST_URI} !index\.php rewriteRule ^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$ index.php/%{THE_REQUEST} [NC] Now, this works on my local apache 2.2.11 server, no errors. However on my host's apache 1.3.41 server, I get the following error: [Sat Mar 5 21:42:14 2011] [alert] [client [ip]] /home/_/public_html/mysite.com/.htaccess: RewriteRule: cannot compile regular expression '^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$'\n I imagine it's something quirky about the apache version as other sites on this host use mod_rewrite without a hitch. I've tried removing the +followSymlinks line, even the rewrite engine line. I haven't tried removing the conditions cause I don't think I should have to, I'm probably wrong.

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  • Using excel, how can I count the number of cells in a column containing the text "true" or "false"?

    - by Jay Elston
    I have a spreadsheet that has a column of cells where each cell contains a single work. I would like to count the occurrences of some words. I can use the COUNTIF function for most words, but if the word is "true" or "false", I get 0. A B 1 apples 2 2 true 0 3 false 0 4 oranges 1 5 apples In the above spreadsheet table, I have these formulas in cells B1, B2, B3 and B4: =COUNTIF(A1:A5,"apples") =COUNTIF(A1:A5,"true") =COUNTIF(A1:A5,"false") =COUNTIF(A1:A5,"oranges) As you can see, I can count apples, but not true or false. I have also tried this: =COUNTIF(A1:A5,TRUE) But that does not work either. Note -- I am using Excel 2007.

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  • 'Scanner' does not name a type error in g++

    - by Max
    Hi. I'm trying to compile code in g++ and I get the following errors: In file included from scanner.hpp:8, from scanner.cpp:5: parser.hpp:14: error: ‘Scanner’ does not name a type parser.hpp:15: error: ‘Token’ does not name a type Here's my g++ command: g++ parser.cpp scanner.cpp -Wall Here's parser.hpp: #ifndef PARSER_HPP #define PARSER_HPP #include <string> #include <map> #include "scanner.hpp" using std::string; class Parser { // Member Variables private: Scanner lex; // Lexical analyzer Token look; // tracks the current lookahead token // Member Functions <some function declarations> }; #endif and here's scanner.hpp: #ifndef SCANNER_HPP #define SCANNER_HPP #include <iostream> #include <cctype> #include <string> #include <map> #include "parser.hpp" using std::string; using std::map; enum { // reserved words BOOL, ELSE, IF, TRUE, WHILE, DO, FALSE, INT, VOID, // punctuation and operators LPAREN, RPAREN, LBRACK, RBRACK, LBRACE, RBRACE, SEMI, COMMA, PLUS, MINUS, TIMES, DIV, MOD, AND, OR, NOT, IS, ADDR, EQ, NE, LT, GT, LE, GE, // symbolic constants NUM, ID, ENDFILE, ERROR }; class Token { public: int tag; int value; string lexeme; Token() {tag = 0;} Token(int t) {tag = t;} }; class Num : public Token { public: Num(int v) {tag = NUM; value = v;} }; class Word : public Token { public: Word() {tag = 0; lexeme = "default";} Word(int t, string l) {tag = t; lexeme = l;} }; class Scanner { private: int line; // which line the compiler is currently on int depth; // how deep in the parse tree the compiler is map<string,Word> words; // list of reserved words and used identifiers // Member Functions public: Scanner(); Token scan(); string printTag(int); friend class Parser; }; #endif anyone see the problem? I feel like I'm missing something incredibly obvious.

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  • What is on the 68000 stack when classic MacOS enters a program?

    - by John Källén
    I'm trying to understand an old classic Mac application's entry point. I've disassembled the first CODE resource (not CODE#0, which is the jump table). The code refers to some variables off the stack: a word at 0004(A7), an array of long words of starting at 000C(A7) whose length is the value at 0004(A7), and a final long word beyond that array that seems to be a pointer to a character string. The array of long words looks like strings at first glance, so it looks superficially like we're dealing with an (int argc, char ** argv) situation, except the "argv" array is inline in the stack frame. What should a program be expecting on its stack / registers when it first gets called by the Mac OS?

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  • Regular Expression for accurate word-count using JavaScript

    - by Haidon
    I'm trying to put together a regular expression for a JavaScript command that accurately counts the number of words in a textarea. One solution I had found is as follows: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\b\w+\b/).length -1; But this doesn't count any non-Latin characters (eg: Cyrillic, Hangul, etc); it skips over them completely. Another one I put together: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\s+/g).length -1; But this doesn't count accurately unless the document ends in a space character. If a space character is appended to the value being counted it counts 1 word even with an empty document. Furthermore, if the document begins with a space character an extraneous word is counted. Is there a regular expression I can put into this command that counts the words accurately, regardless of input method?

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  • Access outer class from inner class: Why is it done this way?

    - by Vuntic
    So most of us know how to access an outer class from an inner class. Searches with those words give oodles of answered questions on that topic. But what I want to know is why the syntax is the way it is. Example: public class A { private class B { public void c() {A.this.d();} } public void d() {System.out.println("You've called d()! Go, you!");} } Why is it A.this.d()? It looks like this is a static field of class A, but... * am confused * Forgive me if this is a repeat; like I said, searches with those words give how-answers.

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  • Minimum 4 Characters or Show Nothing - PHP

    - by ali
    Hi, I want to show up only words with minimum 4 Characters, actually I can limit the hits and show only words with min. 100 hits - but how can I set a min. character length? thank you! function sm_list_recent_searches($before = '', $after = '', $count = 20) { // List the most recent successful searches. global $wpdb, $table_prefix; $count = intval($count); $results = $wpdb->get_results( "SELECT `terms`, `datetime` FROM `{$table_prefix}searchmeter_recent` WHERE 100 < `hits` ORDER BY `datetime` DESC LIMIT $count"); if (count($results)) { foreach ($results as $result) { echo '<a href="'. get_settings('home') . '/search/' . urlencode($result->terms) . '">'. htmlspecialchars($result->terms) .'</a>'.", "; } } }

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  • Simple interlinear gloss: aligned bilingual paragraph

    - by D W
    An interlinear gloss can be used to layout a translation of a document. http://en.wikipedia.org/wiki/Interlinear_gloss Usually this is done word-by-word or morpheme-by-morpheme. However, I would like to do this in a different way, translating entire paragraphs at a time. http://www.optimnem.co.uk/learning/spanish/three-little-pigs.php For now I am not interested in taking into account the order of words or phrases that change order between languages. That is, I don't mind if the words in the paragraph are not aligned or if the length of one paragraph is much longer than the other, causing an overhanging line. As far as I can tell, the following packages do not meet my needs: covingtn.sty cgloss4e.sty gb4e.sty lingmacros.sty - shortex

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  • How can I reference only a portion of a TextArea's htmlText block?

    - by Charles Shoults
    I have a number of very poor-quality pdf documents that look like 80's photocopies, which I'm rebuilding in Flash (Flex Builder 3 MXML application), representing paragraphs of text in TextAreas so that selected portions can be bold or italic, or whatever I need. I need a way to apply toolTips or event listeners to individual words within the block of text to link those words to a glossary. I'm perfectly happy to create a definition panel that is populated and made visible with a mouseOver, but don't know how to do it to just a portion of the text. Is there a good / clean / easy way to do this?

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  • iPhone: different icon for homescreen and App Store

    - by arne_
    I would like to know if the app icon on the iPhone can be slightly different than the one shown in a large version in Apple's App Store. It was discussed in short here: http://stackoverflow.com/questions/28551/tips-for-a-successful-appstore-submission/266657#266657 But I wanted to make sure if anyone has more experience with that. To give an example: The New York Times has many words incorporated in its app icon (see http://itunes.apple.com/de/app/nytimes/id284862083?mt=8). Would it be okay to have a full black colored background without the words in the small/homescreen version of the icon?

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  • Java - Optimize finding a string in a list

    - by Mark
    I have an ArrayList of objects where each object contains a string 'word' and a date. I need to check to see if the date has passed for a list of 500 words. The ArrayList could contain up to a million words and dates. The dates I store as integers, so the problem I have is attempting to find the word I am looking for in the ArrayList. Is there a way to make this faster? In python I have a dict and mWords['foo'] is a simple lookup without looping through the whole 1 million items in the mWords array. Is there something like this in java? for (int i = 0; i < mWords.size(); i++) { if ( word == mWords.get(i).word ) { mLastFindIndex = i; return mWords.get(i); } }

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  • Using `.index()` on repeating letters

    - by Yarden
    I'm building a function that builds a dictionary with words, such as: {'b': ['b', 'bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'bi': ['bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birt': ['birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birthda': ['birthda', 'birthday'], 'birthday': ['birthday'], 'birth': ['birth', 'birthd', 'birthda', 'birthday'], 'birthd': ['birthd', 'birthda', 'birthday'], 'bir': ['bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday']} This is what it looks like: def add_prefixs(word, prefix_dict): lst=[] for letter in word: n=word.index(letter) if n==0: lst.append(word[0]) else: lst.append(word[0:n]) lst.append(word) lst.remove(lst[0]) for elem in lst: b=lst.index(elem) prefix_dict[elem]=lst[b:] return prefix_dict It works great for words like "birthday", but when I have a letter that repeats itself, I have a problem... for example, "hello". {'h': ['h', 'he', 'he', 'hell', 'hello'], 'hell': ['hell', 'hello'], 'hello': ['hello'], 'he': ['he', 'he', 'hell', 'hello']} I know it's because of the index (python chooses the index of the first time the letter appears) but I do not know how to solve it. Yes, this is my homework and I'm really trying to learn from you guys :)

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  • Select rows where column LIKE dictionary word

    - by Gerve
    I have 2 tables: Dictionary - Contains roughly 36,000 words CREATE TABLE IF NOT EXISTS `dictionary` ( `word` varchar(255) NOT NULL, PRIMARY KEY (`word`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Datas - Contains roughly 100,000 rows CREATE TABLE IF NOT EXISTS `datas` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `hash` varchar(32) NOT NULL, `data` varchar(255) NOT NULL, `length` int(11) NOT NULL, `time` int(11) NOT NULL, PRIMARY KEY (`ID`), UNIQUE KEY `hash` (`hash`), KEY `data` (`data`), KEY `length` (`length`), KEY `time` (`time`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=105316 ; I would like to somehow select all the rows from datas where the column data contains 1 or more words. I understand this is a big ask, it would need to match all of these rows together in every combination possible, so it needs the best optimization. I have tried the below query, but it just hangs for ages: SELECT `datas`.*, `dictionary`.`word` FROM `datas`, `dictionary` WHERE `datas`.`data` LIKE CONCAT('%', `dictionary`.`word`, '%') AND LENGTH(`dictionary`.`word`) > 3 ORDER BY `length` ASC LIMIT 15 I have also tried something similar to the above with a left join, and on clause that specified the like statement.

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  • Best way in Python to determine all possible intersections in a matrix?

    - by ssweens
    So if I have a matrix (list of lists) of unique words as my column headings, document ids as my row headings, and a 0 or 1 as the values if the word exists in that particular document. What I'd like to know is how to determine all the possible combinations of words and documents where more than one word is in common with more than one document. So something like: [[Docid_3, Docid_5], ['word1', 'word17', 'word23']], [[Docid_3, Docid_9, Docid_334], ['word2', 'word7', 'word23', 'word68', 'word982']], and so on for each possible combination. Would love a solution that provides the complete set of combinations and one that yields only the combinations that are not a subset of another, so from the example, not [[Docid_3, Docid_5], ['word1', 'word17']] since it's a complete subset of the first example. I feel like there is an elegant solution that just isn't coming to mind and the beer isn't helping. Thanks.

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  • How to change word recognition in vim spell?

    - by David
    I like that vim 7.0 supports spell checking via :set spell, and I like that it by default only checks comments and text strings in my C code. But I wanted to find a way to change the behavior so that vim will know that when I write words containing underscores, I don't want that word spell checked. The problem is that I often will refer to variable or function names in my comments, and so right now vim thinks that each piece of text that isn't a complete correct word is a spelling error. Eg. /* The variable proj_abc_ptr is used in function do_func_stuff' */ Most of the time, the pieces seperated by underscores are complete words, but other times they are abbreviations that I would prefer not to add to a word list. Is there any global way to tell vim to include _'s as part of the word when spell checking?

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