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  • Java Operator Precedence Comparison

    - by Andrew
    Does java have a built-in method to compare precedence of two operators? For example, if I have a char '/' and a char '+' is there a method I can call that compares the two and returns true/false if the first is greater than the second (e.g. true)?

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  • Problem compiling c++ in CodeGear

    - by Carlos
    I have written a C++ program for a University assignment. I used Netbeans 6.8 running on my Mac and the code runs smoothly, no warnings, errors or problems/bugs. However when compiling and running on a Windows computer using CodeGear RAD Studio 2009 (C++ Builder) am getting several errors. [BCC32 Error] main.cpp(51): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(62): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(67): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(112): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(121): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(130): E2093 'operator==' not implemented in type 'string' for arguments of the same type [BCC32 Error] main.cpp(133): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(139): E2094 'operator<<' not implemented in type 'ostream' for arguments of type 'string' [BCC32 Error] main.cpp(153): E2094 'operator<<' not implemented in type 'fstream' for arguments of type 'string' [BCC32 Error] main.cpp(199): E2094 'operator>>' not implemented in type 'fstream' for arguments of type 'string' [BCC32 Error] main.cpp(219): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(231): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(240): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(262): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' [BCC32 Error] main.cpp(264): E2094 'operator>>' not implemented in type 'istream' for arguments of type 'string' These are the header files am using #include <iostream> #include <fstream> #include <cmath> #include <stdio> #include <windows> //I added this one just to check and still does not work (I didnt have it on Netbeans/Mac) using namespace std; Any ideas what is producing the errors and how can I fix it?

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  • Source operator doesn't work in if construction in bash

    - by Igor
    Hello, I'd like to include a config file in my bash script with 2 conditions: 1) the config file name is constructed on-the-fly and stored in variable, and 2) in case if config file doesn't exist, the script should fail: config.cfg: CONFIGURED=yes test.sh: #!/bin/sh $CFG=config.cfg echo Source command doesn't work here: [ -f $CFG ] && ( source $CFG ) || (echo $CFG doesnt exist; exit 127) echo $CONFIGURED echo ... but works here: source $CFG echo $CONFIGURED What's wrong in [...] statement?

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  • == Operator and operands

    - by rahul
    I want to check whether a value is equal to 1. Is there any difference in the following lines of code Evaluated value == 1 1 == evaluated value in terms of the compiler execution

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  • new operator in DllMain of MFC Extension Dll

    - by Picaro De Vosio
    Hi, Dll best practices document from Microsoft available Here recommends avoiding use of memory management function from the dynamic C Run-Time (CRT) within DllMain. But DllMain function of MFC Extension DLL is dynamically allocating the memory for CDynLinkLibrary in the code snippet available at MSDN "http://msdn.microsoft.com/en-us/library/1btd5ea3%28v=VS.80%29.aspx". Is it a violation of Dll Best Practices or ok to use in MFC extension DLL? thanks

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  • Using sizeof operator on a typedef-ed struct

    - by sskanitk
    This might be something too obvious. However, I couldn't find the specific answer though many stackoverflow threads talk about different aspects of this. typedef struct _tmp { unsigned int a; unsigned int b; } tmp; int main() { int c=10; if (c <= sizeof tmp) { printf("less\n"); } else { printf("more\n"); } return 0; } I compile this prog as - g++ -lstdc++ a.cpp I get an error - expected primary-expression before ‘)’ token I think I am missing something very obvious and straightforward. But can't seem to pinpoint it :-/ Thanks!

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  • and or operator in validates_presence_of of a Ruby on Rails model

    - by user284194
    I have an entry.rb model and I'm trying to make a semi-complicated validation. I want it to require one or more of the following fields: phone, phone2, mobile, fax, email or website. How would you write the intended code? Would something like this work? validates_presence_of :phone and or :phone2 and or :mobile and or :fax and or :email and or :website

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  • problem with QDataStream & QDataStream::operator>> ( char *& s )

    - by yan bellavance
    QFile msnLogFile(item->data(Qt::UserRole).toString()); QDataStream logDataStream; if(msnLogFile.exists()){ msnLogFile.open(QIODevice::ReadOnly); logDataStream.setDevice(&msnLogFile); QByteArray logBlock; logDataStream >> logBlock; } This code doesnt work. The QByte that results is empty. Same thing if I use a char* . Oddely enough the same code works in another program. Im tying to find the difference between both. This works if i use int,uint, quint8, etc

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  • splat operator in groovy?

    - by IttayD
    def foo(map, name) { println(map) } foo("bar", hi: "bye") will print [hi:bye] Now I have a previous map that I wish to pass along to foo. In pseudo code, something like: def otherMap = [hi: "world"] foo("bar", hi: "bye", otherMap*) So that it prints [hi:world] This doesn't work of course. Also, trying to pass just the map mixes the order of arguments: def otherMap = [hi: "world"] foo("bar", otherMap) will print bar How can I fix this?

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  • Does Java have a .new operator?

    - by chickeninabiscuit
    I came across this code today whilst reading Accelerated GWT (Gupta) - page 151. public static void getListOfBooks(String category, BookStore bookStore) { serviceInstance.getBooks(category, bookStore.new BookListUpdaterCallback()); } public static void storeOrder(List books, String userName, BookStore bookStore) { serviceInstance.storeOrder(books, userName, bookStore.new StoreOrderCallback()); } What are those new operators doing there? I've never seen such syntax, can anyone explain?

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  • Updating rows using "in" operator in "where" clause

    - by doublep
    Hi. I stumbled upon SQL behavior I don't understand. I needed to update several rows in a table at once; started with just finding them: SELECT * FROM some_table WHERE field1 IN (SELECT ...) This returned a selection of about 60 rows. Now I was pretty confident I got the subquery right, so I modified the first part only: UPDATE some_table SET field2 = some_value WHERE field1 IN (SELECT ...) In other words, this was exactly as the first query after the WHERE. However, it resulted in 0 rows updated, whereas I would expect those 60. Note that the statement above would change field2, i.e. I verified that some_value was not present in the selected rows. The subquery was a modestly complicated SQL piece with 2 (different) tables, 1 view, joins and its own WHERE clause. In case this matters, it happened with Oracle Database 10g. So, the question is, why UPDATE didn't touch the rows returned by SELECT?

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  • Parenthesis operator in C. What is the effect in the following code

    - by Andre
    Hi everyone, I was playing with a macro to enable/disable traces when I came out with the following code when the macro is disabled: int main { ("Hello world"); } This code is valid and I got the desired effect (nothing happens when the macro is disabled) but I couldn't figure out what exactly is happening. Is the compiler seeing the parenthesis as a "nameless" method declaration? To make it clearer the code is : #ifdef TRACE #define trace printf("%s %d -> ",__FILE__, __LINE__);printf else #define trace #endif int main { trace("Hello world"); } Thanks in advance.

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  • PG::Error: ERROR: operator does not exist: integer ~~ unknown

    - by rsvmrk
    I'm making a search-function in a Rails project with Postgres as db. Here's my code def self.search(search) if search find(:all, :conditions => ["LOWER(name) LIKE LOWER(?) OR LOWER(city) LIKE LOWER(?) OR LOWER(address) LIKE LOWER(?) OR (venue_type) LIKE (?)", "%#{search}%", "%#{search}%", "%#{search}%", "%#{search}%"]) else find(:all) end end But my problem is that "venue_type" is an integer. I've made a case switch for venue_type def venue_type_check case self.venue_type when 1 "Pub" when 2 "Nattklubb" end end Now to my question: How can I find something in my query when venue_type is an int?

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  • C: switch case with logical operator

    - by Er Avinash Singh
    While I am new to c and want help in this program my code is : #include<stdio.h> #include<conio.h> void main(){ int suite=2; switch(suite) { case 1||2: printf("hi"); case 3: printf("byee"); default: printf("hello"); } printf("I thought somebody"); getche(); } I am working in turbo c and it shows no error and the output is helloI thought somebody Please, let me know how is this working ??? note :- here break is not the case as I intentionally left them.

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  • SQL AND operator not working properly

    - by Chandana De Silva
    I have following two tables LandParcels Table Blockid ParcelNo storPri ======= ======== ======= 52000105 3 State 52000105 4 Private 52000105 5 State Actions Table Blockid ParcelNo ActionTaken ======= ======== =========== 52000105 3 Received 52000105 3 Send to Computer 52000105 4 Received 52000105 5 Received I want to find the records Received but not Send to Computer Here is my query select l.blockid, l.parcelno from landparcels l left join actions ac on l.blockid = ac.blockid and l.parcelno = ac.parcelno where ac.actiontaken = 'Received' and ac.actiontaken <> 'Send to Computer' and ac.blockid = 52000105 The result is Blockid ParcelNo ======= ======== 52000105 3 52000105 4 52000105 5 I want ParcelNo 4 and 5

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  • Is the ruby operator ||= intelligent?

    - by brad
    I have a question regarding the ||= statement in ruby and this is of particular interest to me as I'm using it to write to memcache. What I'm wondering is, does ||= check the receiver first to see if it's set before calling that setter, or is it literally an alias to x = x || y This wouldn't really matter in the case of a normal variable but using something like: CACHE[:some_key] ||= "Some String" could possibly do a memcache write which is more expensive than a simple variable set. I couldn't find anything about ||= in the ruby api oddly enough so I haven't been able to answer this myself. Of course I know that: CACHE[:some_key] = "Some String" if CACHE[:some_key].nil? would achieve this, I'm just looking for the most terse syntax.

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  • How does the " is " operator work internally

    - by JDMX
    I want to compare the type of an object to a type to see if they are the same. I do not have the object, just the type of the object. I can do type1 == type2 and get general equality I can have a recursive loop where I repeat the above step for type1.BaseType until the BaseType is null. I can do type1.GetInterface( type2.FullName ) != null to check if type2 is an interface of type1 If I put it all together, I get if ( type2.IsInterface ) return type1.GetInterface( type2.FullName ) != null; while ( type1 != null ) { if ( type1 == type2 ) return true; type1 = type1.BaseType; } return false; Is that all the is keyword is. I cannot find the right keyword to plug into the Reflector search to find the function and a google search on "is" was not really helpful

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  • Strange behavior of std::cout &operator<<...

    - by themoondothshine
    Hey ppl, I came across something weird today, and I was wondering if any of you here could explain what's happening... Here's a sample: #include <iostream> #include <cassert> using namespace std; #define REQUIRE_STRING(s) assert(s != 0) #define REQUIRE_STRING_LEN(s, n) assert(s != 0 || n == 0) class String { public: String(const char *str, size_t len) : __data(__construct(str, len)), __len(len) {} ~String() { __destroy(__data); } const char *toString() const { return const_cast<const char *>(__data); } String &toUpper() { REQUIRE_STRING_LEN(__data, __len); char *it = __data; while(it < __data + __len) { if(*it >= 'a' && *it <= 'z') *it -= 32; ++it; } return *this; } String &toLower() { REQUIRE_STRING_LEN(__data, __len); char *it = __data; while(it < __data + __len) { if(*it >= 'A' && *it <= 'Z') *it += 32; ++it; } return *this; } private: char *__data; size_t __len; protected: static char *__construct(const char *str, size_t len) { REQUIRE_STRING_LEN(str, len); char *data = new char[len]; std::copy(str, str + len, data); return data; } static void __destroy(char *data) { REQUIRE_STRING(data); delete[] data; } }; int main() { String s("Hello world!", __builtin_strlen("Hello world!")); cout << s.toLower().toString() << endl; cout << s.toUpper().toString() << endl; cout << s.toLower().toString() << endl << s.toUpper().toString() << endl; return 0; } Now, I had expected the output to be: hello world! HELLO WORLD! hello world! HELLO WORLD! but instead I got this: hello world! HELLO WORLD! hello world! hello world! I can't really understand why the second toUpper didn't have any effect.

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  • Shift operator in Java bizarre program output

    - by Umesh Kacha
    I came across the following program and it behaving in unexpected manner. public class ShiftProgram { public static void main(String[] args) { int i = 0; while(-1 << i != 0) i++; System.out.println(i); } } If we think about this program output, when it reaches 32 while loop condition should return false and terminate and it should print 32. If you ran this program, it does not print anything but goes into an infinite loop. Any idea whats going on? Thank you in advance.

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  • using 'or' operator not working for menu

    - by John Wilkes
    In my code here, I have a CSS class called "active" which I use if the $_GET['page'] == tutorials, php, mysql, etc... The problem is, even if the 'page' variable is not equal to any of these values, the Tutorials button in this case is still active for some reason. Any ideas why this would be happening? Am I using the 'or' (||) operand incorrectly? <?php if($_GET['page'] == 'tutorials' || 'php' || 'mysql' || 'html' || 'css' || 'js') { ?> <li class="active"> <?php } else { ?> <li> <?php } ?> <a href="index.php?page=tutorials">Tutorials</a> <ul> <li><a href="index.php?page=php">PHP</a></li> <li><a href="index.php?page=mysql">MySQL</a></li> <li><a href="index.php?page=html">HTML</a></li> <li><a href="index.php?page=css">CSS</a></li> <li><a href="index.php?page=js">JS</a></li> </ul> </li>

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  • Using the AND and NOT Operator in Python

    - by NoahClark
    Here is my custom class that I have that represents a triangle. I'm trying to write code that checks to see if self.a, self.b, and self.c are greater than 0, which would mean that I have Angle, Angle, Angle. Below you will see the code that checks for A and B, however when I use just self.a != 0 then it works fine. I believe I'm not using & correctly. Any ideas? Here is how I am calling it: print myTri.detType() class Triangle: # Angle A To Angle C Connects Side F # Angle C to Angle B Connects Side D # Angle B to Angle A Connects Side E def __init__(self, a, b, c, d, e, f): self.a = a self.b = b self.c = c self.d = d self.e = e self.f = f def detType(self): #Triangle Type AAA if self.a != 0 & self.b != 0: return self.a #If self.a > 10: #return AAA #Triangle Type AAS #elif self.a = 0: #return AAS #Triangle Type ASA #Triangle Type SAS #Triangle Type SSS #else: #return unknown

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  • Why does the Ternary\Conditional operator seem significantly faster

    - by Jodrell
    Following on from this question, which I have partially answered. I compile this console app in x64 Release Mode, with optimizations on, and run it from the command line without a debugger attached. using System; using System.Diagnostics; class Program { static void Main() { var stopwatch = new Stopwatch(); var ternary = Looper(10, Ternary); var normal = Looper(10, Normal); if (ternary != normal) { throw new Exception(); } stopwatch.Start(); ternary = Looper(10000000, Ternary); stopWatch.Stop(); Console.WriteLine( "Ternary took {0}ms", stopwatch.ElapsedMilliseconds); stopwatch.Start(); normal = Looper(10000000, Normal); stopWatch.Stop(); Console.WriteLine( "Normal took {0}ms", stopwatch.ElapsedMilliseconds); if (ternary != normal) { throw new Exception(); } Console.ReadKey(); } static int Looper(int iterations, Func<bool, int, int> operation) { var result = 0; for (int i = 0; i < iterations; i++) { var condition = result % 11 == 4; var value = ((i * 11) / 3) % 5; result = operation(condition, value); } return result; } static int Ternary(bool condition, in value) { return value + (condition ? 2 : 1); } static int Normal(int iterations) { if (condition) { return = 2 + value; } return = 1 + value; } } I don't get any exceptions and the output to the console is somthing close to, Ternary took 107ms Normal took 230ms When I break down the CIL for the two logical functions I get this, ... Ternary ... { : ldarg.1 // push second arg : ldarg.0 // push first arg : brtrue.s T // if first arg is true jump to T : ldc.i4.1 // push int32(1) : br.s F // jump to F T: ldc.i4.2 // push int32(2) F: add // add either 1 or 2 to second arg : ret // return result } ... Normal ... { : ldarg.0 // push first arg : brfalse.s F // if first arg is false jump to F : ldc.i4.2 // push int32(2) : ldarg.1 // push second arg : add // add second arg to 2 : ret // return result F: ldc.i4.1 // push int32(1) : ldarg.1 // push second arg : add // add second arg to 1 : ret // return result } Whilst the Ternary CIL is a little shorter, it seems to me that the execution path through the CIL for either function takes 3 loads and 1 or 2 jumps and a return. Why does the Ternary function appear to be twice as fast. I underdtand that, in practice, they are both very quick and indeed, quich enough but, I would like to understand the discrepancy.

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