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  • jqGrid: sort by index

    - by David__
    I am having trouble getting a column to sort by an index other than the 'name' value. In this case I am trying to sort the aggregation type column (values are days of the week) by the week order, rather than alphanumeric order. To do this I added an index column ('Aggregation type-index') that has the days of week an integers. However with this configuration, it fails to sort that column by index or name. Can someone point me the err in my ways? I posted all the js and css that is on the page, because I am also having two other issues, that if you notice the problem great, otherwise I'll keep hunting. I want to be able to enable the column reodering and be able to resize the grid (Both shown at http://trirand.com/blog/jqgrid/jqgrid.html under the new in 3.6 tab). Both options are not working either. <link rel="stylesheet" type="text/css" href="/static/latest_ui/themes/base/jquery.ui.all.css"/> <link rel="stylesheet" type="text/css" media="print" href="/static/css/print.css"/> <script src="/static/js/jquery-1.7.2.min.js" type="text/javascript"></script> <script src="/static/latest_ui/ui/jquery.ui.core.js"></script> <script src="/static/latest_ui/ui/jquery.ui.widget.js"></script> <script src="/static/latest_ui/ui/jquery.ui.position.js"></script> <script src="/static/latest_ui/ui/jquery.ui.button.js"></script> <script src="/static/latest_ui/ui/jquery.ui.menu.js"></script> <script src="/static/latest_ui/ui/jquery.ui.menubar.js"></script> <script src="/static/latest_ui/ui/jquery.ui.tabs.js"></script> <script src="/static/latest_ui/ui/jquery.ui.datepicker.js"></script> <script src="/static/js/custom.js"></script> <link rel="stylesheet" type="text/css" media="all" href="/static/css/custom_style.css" /> <link rel="stylesheet" type="text/css" media="all" href="/static/css/custom_colors.css" /> <link rel="stylesheet" type="text/css" media="screen" href="/static/css/ui.jqgrid.css" /> <body> <table id="grid_reports"></table> <div id='pager'></div> </body> <script src="/static/latest_ui/ui/jquery.ui.resizable.js"></script> <script src="/static/latest_ui/ui/jquery.ui.sortable.js"></script> <script src="/static/js/grid.locale-en.js" type="text/javascript"></script> <script src="/static/js/jquery.jqGrid.min.js" type="text/javascript"></script> <script src="/static/js/jqGrid_src/grid.jqueryui.js"></script> <script> $(function() { jQuery("#grid_reports").jqGrid({ sortable: true, datatype: "local", height: 500, width: 300, colNames:['Series', 'Agg Type', 'Days'], colModel:[{'index': 'By series', 'align': 'left', 'sorttype': 'text', 'name': 'By series', 'width': 65}, {'index': 'Aggregation type-index', 'align': 'left', 'sorttype': 'int', 'name': 'Aggregation type', 'width': 75}, {'index': 'Days since event', 'align': 'center', 'sorttype': 'text', 'name': 'Days since event', 'width': 50}], rowNum:50, pager: '#pager', sortname: 'Aggregation type', sortorder: 'desc', altRows: true, rowList:[20,50,100,500,10000], viewrecords: true, gridview: true, caption: "Report for 6/19/12" }); jQuery("#grid_reports").navGrid("#pager",{edit:false,add:false,del:false}); jQuery("#grid_reports").jqGrid('gridResize',{minWidth:60,maxWidth:2500,minHeight:80, maxHeight:2500}); var mydata = [{'Days since event': 132, 'Aggregation type': 'Date=Fri', 'By series': 'mean', 'Aggregation type-index': 5}, {'DIM at event': 178, 'Aggregation type': 'Date=Thu', 'By series': 'mean', 'Aggregation type-index': 4}, {'DIM at event': 172, 'Aggregation type': 'Date=Wed', 'By series': 'mean', 'Aggregation type-index': 3}, {'DIM at event': 146, 'Aggregation type': 'Date=Tue', 'By series': 'mean', 'Aggregation type-index': 2}, {'DIM at event': 132, 'Aggregation type': 'Date=Sat', 'By series': 'mean', 'Aggregation type-index': 6}, {'DIM at event': 162, 'Aggregation type': 'Date=Mon', 'By series': 'mean', 'Aggregation type-index': 1}, {'DIM at event': 139, 'Aggregation type': 'Date=Sun', 'By series': 'mean', 'Aggregation type-index': 0}]; for(var i=0;i<=mydata.length;i++) jQuery("#grid_reports").jqGrid('addRowData',i+1,mydata[i]); }); </script>

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  • How is counting sort a stable sort?

    - by eSKay
    Suppose my input is (a,b and c to distinguish between equal keys) 1 6a 8 3 6b 0 6c 4 My counting sort will save as (discarding the a,b and c info!!) 0(1) 1(1) 3(1) 4(1) 6(3) 8(1) which will give me the result 0 1 3 4 6 6 6 8 So, how is this stable sort? I am not sure how it is "maintaining the relative order of records with equal keys." Please explain.

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  • How to sort an NSMutableArray List of objects in alphabetical order.

    - by Madan Mohan
    Hi guys, I have an object with different values that is name,nameid, lifebeging,lifeEndiging .... etc, for loop { Search *Obj=[artistslist objectAtIndex:i];// here i will get name, ids, other value for each objcet } 0 obj.name= //string values1 get from parser 1 obj.name= //string values1 2 obj.name= //string values1 3 obj.name= //string values1 4 obj.name= //string values1 I am getting values in the artistList then i need to sort only by name not other feilds when i use this below statement [artistsList sortUsingSelector:@selector(NSOrderedAscending:)]; i am getting exception here ,it is not working.

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  • Indexing vs. no indexing when inserting records

    - by jbu
    I have a few questions about whether or not it would be best to not use indexing. BACKGROUND: My records have a timestamp attribute, and the records will be inserted in order of their timestamps (i.e., inserted chronologically). QUESTIONS: If I DON'T use indexing is it typical for the database to insert the records in the order that they were inserted? If answer to #1 is yes, when I do a "SELECT .. WHERE timestamp X" type query will the database be efficient at it, or will it have to go through every single record since it isn't indexed? I would assume if there were no index, the database would not "know" that the records were inserted in sorted order and could not, therefore, make use of sorted property of the database. I assume a clustered index would be best for these types of records & their inserts. Please let me know what you guys think. Thanks, jbu

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  • Working out global tab order algorithmically?

    - by Mrgreen
    We have a proprietry system where we can configure fields on indiviual forms. However these fields have a global tab order (we cannot specify for a specific form). We have a bunch of forms (35 in total) which share a lot of different fields. Each form has a specific tab/edit order that needs to be configured. Example: Form 1 has fields A,B,C,D in that order. Form 2 has fields E,F,G,A in that order. Form 3 has fields E,B,H,I in that order. The global tab orders would be E,F,G,A,B,C,D,H,I Notice how A needs to come before B yet after G. Is there any easy way to work this out using the tab order lists for each form? I need to merge this tab order information into a single global tab order list. I have over 200 fields in total and it is near impossible to do by hand.

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  • C# .NET: Ascending comparison of a SortedDictionary?

    - by Rosarch
    I'm want a IDictionary<float, foo> that returns the larges values of the key first. private IDictionary<float, foo> layers = new SortedDictionary<float, foo>(new AscendingComparer<float>()); class AscendingComparer<T> : IComparer<T> where T : IComparable<T> { public int Compare(T x, T y) { return -y.CompareTo(x); } } However, this returns values in order of the smallest first. I feel like I'm making a stupid mistake here. Just to see what would happen, I removed the - sign from the comparator: public int Compare(T x, T y) { return y.CompareTo(x); } But I got the same result. This reinforces my intuition that I'm making a stupid error.

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  • JAVA: Sort ArrayList<ArrayList<Integer>> on multiple columns

    - by Bob
    First, I did do my homework searching before posting here. My requirement seems to be slightly different compared to questions posted out there. I have a matrix like ArrayList<ArrayList<Integer>> in the following form | id1 | id2 | score | |-----|-----|-------| | 1 | 3 | 95% | | 1 | 2 | 100% | | 1 | 4 | 85% | | 1 | 5 | 95% | | 2 | 10 | 80% | | 2 | 15 | 99% | I want to sort the matrix column-wise (first using score, then the id1). I already have the id1 in a sorted manner. That means I also need to sort all records with the same id1 first by using score, second by the id2. The reason for doing this is to create a ranking of the id2 in each id1. The result for the above example would be: | q_id | d_id | rank | score | |------|------|------|-------| | 1 | 2 | 1 | 100% | | 1 | 3 | 2 | 95% | | 1 | 5 | 3 | 95% | | 1 | 4 | 4 | 85% | | 2 | 15 | 1 | 99% | | 2 | 10 | 2 | 80% | How can I achieve this in Java using some built-in methods of collections?

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  • Sort List C# in arbitrary order

    - by Jasper
    I have a C# List I.E. List<Food> x = new List<Food> () ; This list is populated with this class Public class Food { public string id { get; set; } public string idUser { get; set; } public string idType { get; set; } //idType could be Fruit , Meat , Vegetable , Candy public string location { get; set; } } Now i have this unsorted List<Food> list ; which has I.E. 15 elements. There are 8 Vegetable Types , 3 Fruit Types , 1 Meat Types , 1 Candy Types I would sort this so that to have a list ordered in this way : 1° : Food.idType Fruit 2° : Food.idType Vegetables 3° : Food.idType Meat 4° : Food.idType Candy 5° : Food.idType Fruit 6° : Food.idType Vegetables 7° : Food.idType Fruit //Becouse there isnt more Meat so i insert the //next one which is Candy but also this type is empty //so i start from begin : Fruit 8° : Food.idType Vegetables 9° : Food.idType Vegetables // For the same reason of 7° 10 ° Food.idType Vegetables ...... .... .... 15 : Food.idType Vegetables I cant find a rule to do this. Is there a linq or List.Sort instruction which help me to order the list in this way? Update i changed the return value of idType and now return int type instead string so 1=Vegetable , 2=Fruit , 3=Candy 4=Meat

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  • access following entry in a form_for, and switch a value between two entry of my DB

    - by Sylario
    I am displaying a list of articles. I sort my articles by the param order, and i want, when displaying the list of article to be able to "move" them up or down. In php i do everything with a for browsing my array of results and inside the for i go to the next index to find where i am in the list, and with wich other article i must swap my order. I can do that in the script displaying the edit page and then in the script executing the update. In rails i have only my form_for in my erb. How can i : Know if my entry is the last one or the first one(display only V for the first, ^ for the last and V^ for the rest) Update my DB entry by switching the order value between the article that i want to lower, raise, and the one he is taking the place.

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  • JQuery tablesorter problem

    - by Don
    Hi, I'm having a couple of problems with the JQuery tablesorter plugin. If you click on a column header, it should sort the data by this column, but there are a couple of problems: The rows are not properly sorted (1, 1, 2183, 236) The total row is included in the sort Regarding (2), I can't easily move the total row to a table footer, because the HTML is generated by the displaytag tag library over which I have limited control. Regarding (1), I don't understand why the sort doesn't work as I've used exactly the same JavaScript shown in the simplest example in the tablesorter tutorials. In fact, there's only a single line of JS code, which is: <body onload="jQuery('#communityStats').tablesorter();"> Thanks in advance, Don

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  • Array Unique in two dimentional array in PHP

    - by Kaiser
    Hi I have an array that looks like this : Array ( [0] => Array ( [x] => 01 [y] => 244 ) [1] => Array ( [x] => 02 [y] => 244 ) [2] => Array ( [x] => 03 [y] => 244 ) [3] => Array ( [x] => 04 [y] => 243 ) [4] => Array ( [x] => 05 [y] => 243 ) [5] => Array ( [x] => 05 [y] => 244 ) [6] => Array ( [x] => 06 [y] => 242 ) [7] => Array ( [x] => 06 [y] => 243 ) [8] => Array ( [x] => 07 [y] => 243 ) [9] => Array ( [x] => 08 [y] => 243 ) [10] => Array ( [x] => 09 [y] => 242 ) [11] => Array ( [x] => 10 [y] => 244 ) [12] => Array ( [x] => 12 [y] => 243 ) [13] => Array ( [x] => 13 [y] => 243 ) [14] => Array ( [x] => 13 [y] => 243 ) [15] => Array ( [x] => 15 [y] => 243 ) ) x represent days and y values of a certain variable. I would like to display an array of unique days x ( last element ) and values y pragmatically. for example day 6 I have two y values but I want to display only the last one ( 243 ). Thanks for help

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • Array Unique in two dimensional array in PHP

    - by Kaiser
    Hi I have an array that looks like this : Array ( [0] => Array ( [x] => 01 [y] => 244 ) [1] => Array ( [x] => 02 [y] => 244 ) [2] => Array ( [x] => 03 [y] => 244 ) [3] => Array ( [x] => 04 [y] => 243 ) [4] => Array ( [x] => 05 [y] => 243 ) [5] => Array ( [x] => 05 [y] => 244 ) [6] => Array ( [x] => 06 [y] => 242 ) [7] => Array ( [x] => 06 [y] => 243 ) [8] => Array ( [x] => 07 [y] => 243 ) [9] => Array ( [x] => 08 [y] => 243 ) [10] => Array ( [x] => 09 [y] => 242 ) [11] => Array ( [x] => 10 [y] => 244 ) [12] => Array ( [x] => 12 [y] => 243 ) [13] => Array ( [x] => 13 [y] => 243 ) [14] => Array ( [x] => 13 [y] => 243 ) [15] => Array ( [x] => 15 [y] => 243 ) ) x represent days and y values of a certain variable. I would like to display an array of unique days x ( last element ) and values y pragmatically. for example day 6 I have two y values but I want to display only the last one ( 243 ). Thanks for help

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  • How to get MAX value of a version-number (varchar) column in T-SQL

    - by Ogre Psalm33
    I have a table defined like this: Column: Version Message Type: varchar(20) varchar(100) ---------------------------------- Row 1: 2.2.6 Message 1 Row 2: 2.2.7 Message 2 Row 3: 2.2.12 Message 3 Row 4: 2.3.9 Message 4 Row 5: 2.3.15 Message 5 I want to write a T-Sql query that will get message for the MAX version number, where the "Version" column represents a software version number. I.e., 2.2.12 is greater than 2.2.7, and 2.3.15 is greater than 2.3.9, etc. Unfortunately, I can't think of an easy way to do that without using CHARINDEX or some complicated other split-like logic. Running this query: SELECT MAX(Version) FROM my_table will yield the erroneous result: 2.3.9 When it should really be 2.3.15. Any bright ideas that don't get too complex?

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  • Bucket sort for integers

    - by rafael
    Could anybody help me with bucket sort algorithm for integers ? It's often mistake when people say they have this algorithm, but this is counting sort ! Maybe it works similar, but it is something different. I hope you will help mi find the right way, 'cause now I have no idea (Cormen's book and Wikipedia are not so helpful). Thanks in advance for all your respones.

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  • Time complexity for Search and Insert operation in sorted and unsorted arrays that includes duplicat

    - by iecut
    1-)For sorted array I have used Binary Search. We know that the worst case complexity for SEARCH operation in sorted array is O(lg N), if we use Binary Search, where N are the number of items in an array. What is the worst case complexity for the search operation in the array that includes duplicate values, using binary search?? Will it be the be the same O(lg N)?? Please correct me if I am wrong!! Also what is the worst case for INSERT operation in sorted array using binary search?? My guess is O(N).... is that right?? 2-) For unsorted array I have used Linear search. Now we have an unsorted array that also accepts duplicate element/values. What are the best worst case complexity for both SEARCH and INSERT operation. I think that we can use linear search that will give us O(N) worst case time for both search and delete operations. Can we do better than this for unsorted array and does the complexity changes if we accepts duplicates in the array.

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  • sort associative array in awk - help?

    - by Richard
    Hi all, I have an associative array in awk that gets populated like this... chr_count[$3]++ When I try to print my chr_counts I use this: for (i in chr_count) { print i,":",chr_count[i]; } But not surprisingly, the order of i is not sorted in any way. Is there an easy way to iterate over the sorted "keys" of chr_count?

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  • jQuery sortable (how to customize the clickable area inside the sortable box)

    - by cvack
    I have this jQuery code: $(".right_box_holder").sortable({ update : function () { var order = $('.right_box_holder').sortable('serialize'); $.get("right_menu_functions.php?change_sortorder&"+order); } }); and this HTML code: <div class='right_box_holder'> <div class='right_box' id='box_0'> // sort box 0 </div> <div class='right_box' id='box_1'> // sort box 1 </div> <div class='right_box' id='box_2'> // sort box 2 </div> </div> As it is now, I can click anywhere inside .right_box and move it. I want to disable this and make a button / icon inside .right_box which the user have to click on to drag the box. Is this possible?

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  • Sort a data grid based on a specified column.

    - by o vamsi krishna
    Developed a winform project using VB 2008. I'm using a .xls sheet as source. My appln has 7 columns and unspecified rows. I want to sort all the columns based on a specified column and allot a serial number as per the sorted order. If two items in the specified column are same we should consider another column for the equal items and sort them in that order. plz help me in this issue.

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  • LINQ OrderBy: best search results at top of results list

    - by p.campbell
    Consider the need to search a list of Customer by both first and last names. The desire is to have the results list sorted by the Customer with the most matches in the search terms. FirstName LastName ---------- --------- Foo Laurie Bar Jackson Jackson Bro Laurie Foo Jackson Laurie string[] searchTerms = new string[] {"Jackson", "Laurie"}; //want to find those customers with first, last or BOTH names in the searchTerms var matchingCusts = Customers .Where(m => searchTerms.Contains(m.FirstName) || searchTerms.Contains(m.LastName)) .ToList(); /* Want to sort for those results with BOTH FirstName and LastName matching in the search terms. Those that match on both First and Last should be at the top of the results, the rest who match on one property should be below. */ return matchingCusts.OrderBy(m=>m); Desired Sort: Jackson Laurie (matches on both properties) Foo Laurie Bar Jackson Jackson Bro Laurie Foo How can I achieve this desired functionality with LINQ and OrderBy / OrderByDescending?

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  • Getting Serial Port Information in C#

    - by Jim Fell
    I have some code that loads the serial ports into a combo-box: List<String> tList = new List<String>(); comboBoxComPort.Items.Clear(); foreach (string s in SerialPort.GetPortNames()) { tList.Add(s); } tList.Sort(); comboBoxComPort.Items.Add("Select COM port..."); comboBoxComPort.Items.AddRange(tList.ToArray()); comboBoxComPort.SelectedIndex = 0; I would like to add the port descriptions (similar to what are shown for the COM ports in the Device Manager) to the list and sort the items in the list that are after index 0 (solved: see above snippet). Does anyone have any suggestions for adding the port descriptions? I am using Microsoft Visual C# 2008 Express Edition (.NET 2.0). Any thoughts you may have would be appreciated. Thanks.

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