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  • (Django) Trim whitespaces from charField

    - by zardon
    How do I strip whitespaces (trim) from the end of a charField in Django? Here is my Model, as you can see I've tried putting in clean methods but these never get run. I've also tried doing name.strip(), models.charField().strip() but these do not work either. Is there a way to force the charField to trim automatically for me? Thanks. class Employee(models.Model): """(Workers, Staff, etc)""" name = models.CharField(blank=True, null=True, max_length=100) # This never gets run def clean_variable(self): data = self.cleaned_data['variable'].strip() return data def __unicode__(self): return self.name class Meta: verbose_name_plural = 'Employees' # This never gets run either class EmployeesForm(forms.ModelForm): class Meta: model = Employee def clean_description(self): #if not self.cleaned_data['description'].strip(): # raise forms.ValidationError('Your error message here') self.cleaned_data['name'].strip()

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  • in django am facing url problem.....

    - by dpaksp
    am using django.0.97 version i have model called profile in that i have few fields eg like name ,email...ects and it's backend also ready..i.e database . and all users profile is created...i have given all permission to all users. when i login ,click on profile..i able to see list of all user name thr when i click on it ,it's goin to model page where i can edit the user profile..instead of that i want to navigate to a template when i can display the user details ,i have set the URl for it so that when url of that type request comes it should call a view from view it will call my template to display user details,.....the problem is it's not calling my view.... i think my problem is brief....if any information still required ?? pls ask me....and help me

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  • Override Django inlineformset_factory has_changed() to always return True

    - by John
    Hi, I am using the django inlineformset_factory function. a = get_object_or_404(ModelA, pk=id) FormSet = inlineformset_factory(ModelA, ModelB) if request.method == 'POST': metaform = FormSet (instance=a, data=request.POST) if metaform.is_valid(): f = metaform.save(commit=False) for instance in f: instance.updated_by = request.user instance.save() else: metaform = FormSet(instance=a) return render_to_response('nodes/form.html', {'form':metaform}) What is happening is that if I change any of the data then everything works ok and all the data gets updated. However if I don't change any of the data then the data is not updated. i.e. only entries which are changed go through the for loop to be saved. I guess this makes sense as there is no point saving data if it has not changed. However I need to go through and save every object in the form regardless of whether it has any changes on not. So my question is how do I override this so that it goes through and saves every record whether it has any changes or not? Hope this makes sense Thanks

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  • Django: query spanning multiple many-to-many relationships

    - by Brant
    I've got some models set up like this: class AppGroup(models.Model): users = models.ManyToManyField(User) class Notification(models.Model): groups_to_notify = models.ManyToManyField(AppGroup) The User objects come from django's authentication system. Now, I am trying to get all the notifications pertaining to the groups that the current user is a part of. I have tried.. notifications = Notification.objects.filter(groups_to_notify=AppGroup.objects.filter(users=request.user)) But that gives an error: more than one row returned by a subquery used as an expression Which I suppose is because the groups_to_notify is checking against several groups. How can I grab all the notifications meant for the user based on the groups he is a part of?

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  • Django test client gets 301 redirection when accessing url

    - by Michal Klich
    I am writing unittests for django views. I have observed that one of my views returns redirection code 301, which is not expected. Here is my views.py mentioned earlier. def index(request): return render(request, 'index.html', {'form': QueryForm()}) def query(request): if request.is_ajax(): form = QueryForm(request.POST) return HttpResponse('valid') Below is urls.py. urlpatterns = patterns('', url(r'^$', 'core.views.index'), url(r'^query/$', 'core.views.query') ) And unittest that will fail. def so_test(self): response = self.client.post('/') self.assertEquals(response.status_code, 200) response = self.client.post('/query', {}) self.assertEquals(response.status_code, 200) My question is: why there is status 301 returned?

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  • ModelName(django.contrib.auth.models.User) vs ModelName(models.Model)

    - by amr.negm
    I am developing a django project. I created some apps, some of those are related to User model, for instance, I have a feeds app that handles user feeds, and another app that deals with extra user data like age, contacts, and friends. for each of these, I created a table that should be connected to the User model, which I using for storing and authenticating users. I found two ways to deal with this issue. One, is through extending User model to be like this: ModelName(User): friends = models.ManyToMany('self') ..... Two, is through adding a foreign key to the new table like this: ModelName(models.Model): user = models.ForeignKey(User, unique=True) friends = friends = models.ManyToMany('self') ...... I can't decide which to use in which case. in other words, what are the core differences between both?

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  • Setting a preferred item of a many-to-one in Django

    - by Mike DeSimone
    I'm trying to create a Django model that handles the following: An Item can have several Names. One of the Names for an Item is its primary Name, i.e. the Name displayed given an Item. (The model names were changed to protect the innocent.) The models.py I've got looks like: class Item(models.Model): primaryName = models.OneToOneField("Name", verbose_name="Primary Name", related_name="_unused") def __unicode__(self): return self.primaryName.name class Name(models.Model): item = models.ForeignKey(Item) name = models.CharField(max_length=32, unique=True) def __unicode__(self): return self.name class Meta: ordering = [ 'name' ] The admin.py looks like: class NameInline(admin.TabularInline): model = Name class ItemAdmin(admin.ModelAdmin): inlines = [ NameInline ] admin.site.register(Item, ItemAdmin) It looks like the database schema is working fine, but I'm having trouble with the admin, so I'm not sure of anything at this point. My main questions are: How do I explain to the admin that primaryName needs to be one of the Names of the item being edited? Is there a way to automatically set primaryName to the first Name found, if primaryName is not set, since I'm using inline admin for the names?

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  • Django admin proper urls inside listview

    - by hinnye
    Hi, My current target is to give users the chance to download CSV files from the admin site of my application. I successfully managed to create an additional column in the model's list view this way: def doc_link(self): return '<a href="files/%s">%s</a>' % (self.output, self.output) doc_link.allow_tags = True This shows the file name and creates the link, but sadly - because it's inside my 'searches' view - it has an URL: my_site/my_app/searches/files/13.csv. This is my problem, I would like to have my files stored in the admin media directory, like this: http://my_site/media/files/13.csv Does somebody know how to give url which points "outer" from the model's directory? Maybe somehow tell Django to use the ADMIN_MEDIA_PREFIX in the link? I'd really appreciate any help, thanks!

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  • Saving data in a inherited django model

    - by aldeano
    I'm building an app to save data and some calculations made with those datas, the idea is keep the data in one model and the calculations in other. So, the models are like this: class FreshData(models.Model): name = models.CharField(max_length=20) one = models.IntegerField() two = models.IntegerField() def save(self, *args, **kwargs): Calculations() Calculations.three = self.one + self.two super(FreshData, self).save(*args, **kwargs) Calculations.save() class Calculations(FreshData): three = models.IntegerField() I've got a valueerror pointing out "self.one" and "self.two" as without value. I keep the idea in witch my design is wrong and django has a simpler way to store related data.

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  • Django: Site-Wide URL Prefix

    - by Tom
    I've built a Django site that will live at the root when it's live. Right now it's functioning perfectly at the IP address. For testing purposes, the client has pointed a proxy url at it, but the url has /folder/path in it, so none of the URL patterns match. I put (/folder/path)? into all the url patterns so they now respond, but all of the links are broken because I'm using the {% url %} tag and while the url patterns will match the optional path, they don't include it in that tag. Clearly I can just hard-code /folder/path into all of my urls (well, into all of the url includes) until testing is complete, but is there a better way to do this?

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  • Django model class and custom property

    - by dArignac
    Howdy - today a weird problem occured to me: I have a modle class in Django and added a custom property to it that shall not be saved into the database and therefore is not represent in the models structure: class Category(models.Model): groups = models.ManyToManyField(Group) title = defaultdict() Now, when I'm within the shell or writing a test and I do the following: c1 = Category.objects.create() c1.title['de'] = 'german title' print c1.title['de'] # prints "german title" c2 = Category.objects.create() print c2.title['de'] # prints "german title" <-- WTF? It seems that 'title' is kind of global. If I change title to a simple string it works as expected, so it has to do something with the dict? I also tried setting title as a property: title = property(_title) But that did not work, too. So, how can I solve this? Thank you in advance! enter code here

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  • Django 1.2: Dates in admin forms don't work with Locales (I10N=True)

    - by equalium
    I have an application in Django 1.2. Language is selectable (I18N and Locale = True) When I select the english lang. in the site, the admin works OK. But when I change to any other language this is what happens with date inputs (spanish example): Correctly, the input accepts the spanish format %d/%m/%Y (Even selecting from the calendar, the date inserts as expected). But when I save the form and load it again, the date shows in the english form: %Y-%m-%d The real problem is that when I load the form to change any other text field and try to save it I get an error telling me to enter a valid date, so I have to write all dates again or change the language in the site to use the admin. I haven't specified anything for DATE_INPUT_FORMATS in settings nor have I overridden forms or models. Surely I am missing something but I can't find it. Can anybody give me a hint?

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  • get foreign key objects in a single query - Django

    - by John
    Hi I have 2 models in my django code: class ModelA(models.Model): name = models.CharField(max_length=255) description = models.CharField(max_length=255) created_by = models.ForeignKey(User) class ModelB(models.Model): category = models.CharField(max_length=255) modela_link = models.ForeignKey(ModelA, 'modelb_link') functions = models.CharField(max_length=255) created_by = models.ForeignKey(User) Say ModelA has 100 records, all of which may or may not have links to ModelB Now say I want to get a list of every ModelA record along with the data from ModelB I would do: list_a = ModelA.objects.all() Then to get the data for ModelB I would have to do for i in list_a: i.additional_data = i.modelb_link.all() However this runs a query on every instance of i. Thus making 101 queries to run. Is there any way of running this all in just 1 query. Or at least less than the 101 queries. I've tried putting in ModelA.objects.select_related().all() but this didn't seem to have any effect. Thanks

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  • Django Template - Convert python list into a javascript object

    - by amcashcow
    I am working on a django / python website I have a page where I want to display a table of search results The list of results is passed in to the template as normal I also want to make this list of objects accessible to the javascript code My first solution was just create another view that returned json format. But each page load required calling the query twice. So then I tried only downloading the data using the json view and printing the table using javascript. but this is also not desirable as now the presentation layer is mixed into the javascript code. is there a way to create a javascript object from the python list as the page is rendered?

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  • Django: Converting an entire Model into a single dictionary

    - by LarrikJ
    Is there a good way in Django to convert an entire model to a dictionary? I mean, like this: class DictModel(models.Model): key = models.CharField(20) value = models.CharField(200) DictModel.objects.all().to_dict() ... with the result being a dictionary with the key/value pairs made up of records in the Model? Has anyone else seen this as being useful for them? Thanks. Update I just wanted to add is that my ultimate goal is to be able to do a simple variable lookup inside a Template. Something like: {{ DictModel.exampleKey }} With a result of DictModel.objects.get(key__exact=exampleKey).value Overall, though, you guys have really surprised me with how helpful allof your responses are, and how different the ways to approach it can be. Thanks a lot.

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  • Django Testing: Faking User Creation

    - by Ygam
    I want to better write this test: def test_profile_created(self): self.client.post(reverse('registration_register'), data={ 'username':'ygam', 'email':'[email protected]', 'password1':'ygam', 'password2':'ygam' }) """ Test if a profile is created on save """ user = User.objects.get(username='ygam') self.assertTrue(UserProfile.objects.filter(user=user).exists()) and I just came upon this code on django-registration tests that does not actually "create" the user: def test_registration_signal(self): def receiver(sender, **kwargs): self.failUnless('user' in kwargs) self.assertEqual(kwargs['user'].username, 'bob') self.failUnless('request' in kwargs) self.failUnless(isinstance(kwargs['request'], WSGIRequest)) received_signals.append(kwargs.get('signal')) received_signals = [] signals.user_registered.connect(receiver, sender=self.backend.__class__) self.backend.register(_mock_request(), username='bob', email='[email protected]', password1='secret') self.assertEqual(len(received_signals), 1) self.assertEqual(received_signals, [signals.user_registered]) However he used a custom function for this "_mock_request": class _MockRequestClient(Client): def request(self, **request): environ = { 'HTTP_COOKIE': self.cookies, 'PATH_INFO': '/', 'QUERY_STRING': '', 'REMOTE_ADDR': '127.0.0.1', 'REQUEST_METHOD': 'GET', 'SCRIPT_NAME': '', 'SERVER_NAME': 'testserver', 'SERVER_PORT': '80', 'SERVER_PROTOCOL': 'HTTP/1.1', 'wsgi.version': (1,0), 'wsgi.url_scheme': 'http', 'wsgi.errors': self.errors, 'wsgi.multiprocess':True, 'wsgi.multithread': False, 'wsgi.run_once': False, 'wsgi.input': None, } environ.update(self.defaults) environ.update(request) request = WSGIRequest(environ) # We have to manually add a session since we'll be bypassing # the middleware chain. session_middleware = SessionMiddleware() session_middleware.process_request(request) return request def _mock_request(): return _MockRequestClient().request() However, it may be too long of a function for my needs. I want to be able to somehow "fake" the account creation. I have not much experience on mocks and stubs so any help would do. Thanks!

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  • Komodo Edit 5.2 Django Template Syntax Error - Info: <head> previously mentioned

    - by Lance McNearney
    I am using Komodo Edit 5.2 for editing html and Django template files. It always shows a single syntax error inside the first {% block %} area on the first tag of my template. For example: {% extends "base.html" %} {% load i18n %} {% block title %}Hello{% endblock %} {% block content %} <p>Hello</p> <-- Syntax error on this single line <p>Other lines have no errors</p> {% endblock %} {% block footer %} <p>No errors here</p> {% endblock %} The syntax error given is: Info: <head> previously mentioned I know for a fact that the error has nothing to do with my <head> tag since it occurs in the base template and in child templates (and the IDE isn't smart enough to process the base templates when in a child, etc.) All of my html tags are closed properly and everything validates for XHTML strict. This forum post mentions a similar problem but offers no solution (and may be specific to Smarty syntax highlighting). Any ideas on how to resolve this error (or disable it from being shown)?

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  • django-mptt: how to successfully move nodes around

    - by Parand
    django-mptt seems determined to drive me out of my mind. I'm trying to do something relatively simple: I'm going to delete a node, and need to do something reasonable with the node's children. Namely, I'd like to move them up one level so they're children of their current parent's parent. That is, if the tree looks like: Root | Grandpa | Father | | C1 C2 I'm going to delete Father, and would like C1 and C2 to be children of Grandpa. Here's the code I'm using: class Node(models.Model): first_name = models.CharField(max_length=80, blank=True) parent = models.ForeignKey('self', null=True, blank=True, related_name='children') def reparent_children(self, parent): print "Reparenting" for child in self.get_children(): print "Working on", child.first_name, "to parent", parent.email parent = Node.objects.get(id=parent.id) child.move_to(parent, 'last-child') child.save() So I'd call: father.reparent_children(grandpa) father.parent = None father.save() This works - almost. The children report their parents as Grandpa: c1.parent == grandpa # True Grandpa counts C1 and C2 among its children c1 in grandpa.children.all() # True However, Root disowns these kids. c1.get_root() == father # c1's root is father, instead of Root c1 in root.get_descendants() # False How do I get the children to move and their root not get corrupted?

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  • Limiting choices from an intermediary ManyToMany junction table in Django

    - by Matthew Rankin
    Background I've created three Django models—Inventory, SalesOrder, and Invoice—to model items in inventory, sales orders for those items, and invoices for a particular sales order. Each sales order can have multiple items, so I've used an intermediary junction table—SalesOrderItems—using the through argument for the ManyToManyField. Also, partial billing of a sales orders is allowed, so I've created a ForeignKey in the Invoice model related to the SalesOrder model, so that a particular sales order can have multiple invoices. Here's where I deviate from what I've normally seen. Instead of relating the Invoice model to the Item model via a ManyToManyField, I've related the Invoice model to the SalesOrderItem intermediary junction table through the intermediary junction table InvoiceItem. I've done this because it better models reality—our invoices are tied to sales orders and can only include items that are tied to that sales order as opposed to any item in inventory. I will admit that it does seem strange having the intermediary junction table of a ManyToManyField related to the intermediary junction table of another ManyToManyField. Question How can I limit the choices available for the invoice_items in the Invoice model to just the sales_order_items of the SalesOrder model for that particular Invoice? (I tried using limit_choices_to= {'sales_order': self.invoice.sales_order}) as part of the item = models.ForeignKey(SalesOrderItem) in the InvoiceItem model, but that didn't work. Am I correct in thinking that limiting the choices for the invoice_items should be handled in the model instead of in a form? Code class Item(models.Model): item_num = models.SlugField(unique=True) default_price = models.DecimalField(max_digits=10, decimal_places=2, blank=True, null=True) class SalesOrderItem(models.Model): item = models.ForeignKey(Item) sales_order = models.ForeignKey('SalesOrder') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class SalesOrder(models.Model): customer = models.ForeignKey(Party) so_num = models.SlugField(max_length=40, unique=True) sales_order_items = models.ManyToManyField(Item, through=SalesOrderItem) class InvoiceItem(models.Model): item = models.ForeignKey(SalesOrderItem) invoice = models.ForeignKey('Invoice') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class Invoice(models.Model): invoice_num = models.SlugField(max_length=25) sales_order = models.ForeignKey(SalesOrder) invoice_items = models.ManyToManyField(SalesOrderItem, through='InvoiceItem')

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  • Left Join with a OneToOne field in Django

    - by jamida
    I have 2 tables, simpleDB_all and simpleDB_some. The "all" table has an entry for every item I want, while the "some" table has entries only for some items that need additional information. The Django models for these are: class all(models.Model): name = models.CharField(max_length=40) important_info = models.CharField(max_length=40) class some(models.Model): all_key = models.OneToOneField(all) extra_info = models.CharField(max_length=40) I'd like to create a view that shows every item in "all" with the extra info if it exists in "some". Since I'm using a 1-1 field I can do this with almost complete success: allitems = all.objects.all() for item in allitems: print item.name, item.important_info, item.some.extra_info but when I get to the item that doesn't have a corresponding entry in the "some" table I get a DoesNotExist exception. Ideally I'd be doing this loop inside a template, so it's impossible to wrap it around a "try" clause. Any thoughts? I can get the desired effect directly in SQL using a query like this: SELECT all.name, all.important_info, some.extra_info FROM all LEFT JOIN some ON all.id = some.all_key_id; But I'd rather not use raw SQL.

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  • Custom template for Django's comments application does not display fields

    - by Jannis
    Hi, I want to use django.contrib.comments in a blogging application and customize the way the form is displayed. My problem is that I can't get the fields to display although displaying the hidden fields works just fine. I had a look at the docs and compared it with the regular way of displaying forms but honestly I don't know why the following doesn't work out: {% get_comment_form for comments_object as form %} <form action="{% comment_form_target %}" method="POST"> […] {% for hidden in form.hidden_fields %} {{ hidden }} {% endfor %} {% for field in form.fields %} {{field}} {% endfor %} […] </form> The output looks like this: <form action="/comments/post/" method="POST"> <input type="hidden" name="content_type" value="flatpages.flatpage" id="id_content_type" /> <input type="hidden" name="object_pk" value="1" id="id_object_pk" /> <input type="hidden" name="timestamp" value="1269522506" id="id_timestamp" /> <input type="hidden" name="security_hash" value="ec4…0fd" id="id_security_hash" /> content_type object_pk timestamp security_hash name email url comment honeypot […] </form> </div> Can you tell me what I'm doing wrong? Thanks in advance

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  • Django: how to cleanup form fields and avoid code duplication

    - by Alexander Konstantinov
    Quite often I need to filter some form data before using it (saving to database etc.) Let's say I want to strip whitespaces and replace repeating whitespaces with a single one in most of the text fields, in many forms. It's not difficult to do this using clean_<fieldname> methods: # Simplified model with two text fields class MyModel(models.Model): title = models.CharField() description = models.CharField() # Model-based form class MyForm(forms.ModelForm): class Meta: model = MyModel def clean_title(self): title = self.cleaned_data['title'] return re.sub(r'\s{2,}', ' ', title.strip()) def clean_description(self): description = self.cleaned_data['description'] return re.sub(r'\s{2,}', ' ', description.strip()) It does exactly what I need, and has a nice side effect which I like: if user enters only whitespaces, the field will be considered empty and therefore invalid (if it is required) and I don't even have to throw a ValidationError. The obvious problem here is code duplication. Even if I'll create some function for that, say my_text_filter, I'll have to call it for every text field in all my forms: from myproject.filters import my_text_filter class MyForm(forms.ModelForm): class Meta: model = MyModel def clean_title(self): return my_text_filter(self.cleaned_data['title']) def clean_description(self): return my_text_filter(self.cleaned_data['description']) The question: is there any standard and simple way in Django (I use version 1.2 if that matters) to do this (like, for example, by adding property validators = {'title': my_text_filter, 'description': my_text_filter} to MyModel), or at least some more or less standard workaround? I've read about form validation and validators in the documentation, but couldn't find what I need there.

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  • Practiaal rules for Django MiddleWare ordering?

    - by o_O Tync
    The official documentation is a bit messy: 'before' & 'after' are used for ordering MiddleWare in a tuple, but in some places 'before'&'after' refers to request-response phases. Also, 'should be first/last' are mixed and it's not clear which one to use as 'first'. I do understand the difference.. however it seems to complicated for a newbie in Django. Can you suggest some correct ordering for builtin MiddleWare classes (assuming we enable all of them) and — most importantly — explain WHY one goes before/after other ones? here's the list, with the info from docs I managed to find: UpdateCacheMiddleware Before those that modify 'Vary:' SessionMiddleware, GZipMiddleware, LocaleMiddleware GZipMiddleware Before any MW that may change or use the response body After UpdateCacheMiddleware: Modifies 'Vary:' ConditionalGetMiddleware Before CommonMiddleware: uses its 'Etag:' header when USE_ETAGS=True SessionMiddleware After UpdateCacheMiddleware: Modifies 'Vary:' Before TransactionMiddleware: we don't need transactions here LocaleMiddleware, One of the topmost, after SessionMiddleware, CacheMiddleware After UpdateCacheMiddleware: Modifies 'Vary:' After SessionMiddleware: uses session data CommonMiddleware Before any MW that may change the response (it calculates ETags) After GZipMiddleware so it won't calculate an E-Tag on gzipped contents Close to the top: it redirects when APPEND_SLASH or PREPEND_WWW CsrfViewMiddleware AuthenticationMiddleware After SessionMiddleware: uses session storage MessageMiddleware After SessionMiddleware: can use Session-based storage XViewMiddleware TransactionMiddleware After MWs that use DB: SessionMiddleware (configurable to use DB) All *CacheMiddleWare is not affected (as an exception: uses own DB cursor) FetchFromCacheMiddleware After those those that modify 'Vary:' if uses them to pick a value for cache hash-key After AuthenticationMiddleware so it's possible to use CACHE_MIDDLEWARE_ANONYMOUS_ONLY FlatpageFallbackMiddleware Bottom: last resort Uses DB, however, is not a problem for TransactionMiddleware (yes?) RedirectFallbackMiddleware Bottom: last resort Uses DB, however, is not a problem for TransactionMiddleware (yes?) (I will add suggestions to this list to collect all of them in one place)

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  • Django forms: how to dynamically create ModelChoiceField labels

    - by Henri
    I would like to create dynamic labels for a forms.ModelChoiceField and I'm wondering how to do that. I have the following form class: class ProfileForm(forms.ModelForm): def __init__(self, data=None, ..., language_code='en', family_name_label='Family name', horoscope_label='Horoscope type', *args, **kwargs): super(ProfileForm, self).__init__(data, *args, **kwargs) self.fields['family_name'].label = family_name_label . . self.fields['horoscope'].label = horoscope_label self.fields['horoscope'].queryset = Horoscope.objects.all() class Meta: model = Profile family_name = forms.CharField(widget=forms.TextInput(attrs={'size':'80', 'class': 'contact_form'})) . . horoscope = forms.ModelChoiceField(queryset = Horoscope.objects.none(), widget=forms.RadioSelect(), empty_label=None) The default labels are defined by the unicode function specified in the Profile definition. However the labels for the radio buttons created by the ModelChoiceField need to be created dynamically. First I thought I could simply override ModelChoiceField as described in the Django documentation. But that creates static labels. It allows you to define any label but once the choice is made, that choice is fixed. So I think I need to adapt add something to init like: class ProfileForm(forms.ModelForm): def __init__(self, data=None, ..., language_code='en', family_name_label='Family name', horoscope_label='Horoscope type', *args, **kwargs): super(ProfileForm, self).__init__(data, *args, **kwargs) self.fields['family_name'].label = family_name_label . . self.fields['horoscope'].label = horoscope_label self.fields['horoscope'].queryset = Horoscope.objects.all() self.fields['horoscope'].<WHAT>??? = ??? Anyone having any idea how to handle this? Any help would be appreciated very much.

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  • Django Template For Loop Removing <img> Self-Closing

    - by Zack
    Django's for loop seems to be removing all of my <img> tag's self-closing...ness (/>). In the Template, I have this code: {% for item in item_list %} <li> <a class="left" href="{{ item.url }}">{{ item.name }}</a> <a class="right" href="{{ item.url }}"> <img src="{{ item.icon.url }}" alt="{{ item.name }} Logo." /> </a> </li> {% endfor %} It outputs this: <li> <a class="left" href="/some-url/">This is an item</a> <a class="right" href="/some-url/"> <img src="/media/img/some-item.jpg" alt="This is an item Logo."> </a> </li> As you can see, the <img> tag is no longer closed, and thus the page doesn't validate. This isn't a huge issue since it'll still render properly in all browsers, but I'd like to know how to solve it. I've tried wrapping the whole for loop in {% autoescape off %}...{% endautoescape %} but that didn't change anything. All other self-closed <img> tags in the document outside the for loop still properly close.

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