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  • File and Printer Sharing Port issue in Windows 7 64 bit

    - by Mohit
    So, This is totally weird and I could not find any way to fix it. In simple words after the diagnosis this what is happening. On a windows 7 64 bit box, Whenever I am trying to access a server using file share. It is trying to connect to port 80 http on the place of 445. I observed that using WireShark. Telnet to 445 works. Any clue how to fix this. Scanned the machine using Malware bytes, Symantec and MS live essentials . I dont want to recreate the whole machine again. Please help me here. Regards Mohit Thakral

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  • How to repair a broken .EXE file association

    - by Pointy
    After (hopefully) scrubbing viruses out of a Windows 7 installation (after deciding not to simply run over the laptop repeatedly with my car), I've got everything almost back to normal. The only lingering issue I have is that for my non-admin users, the ".exe" file extension doesn't work. That is, clicking on the various desktop application links results in a "How do you want to open this?" dialog. I've been through the alleged registry fixing from "winhelponline" and that had absolutely no effect. I've tried running "assoc" for the affected users, but it reports the .exe association to be "exefile" even though it persistently does not work. Right-clicking on a desktop icon and then choosing "start" does successfully open an application, but that's clearly a terrible situation. For my admin user, things seem to work fine. What do I need to do to get things working?

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  • downloaded zip file returns zero has 0 bytes as size

    - by Yaw Reuben
    I have written a Java web application that allows a user to download files from a server. These files are quite large and so are zipped together before download. It works like this: 1. The user gets a list of files that match his/her criteria 2. If the user likes a file and wants to download he/she selects it by checking a checkbox 3. The user then clicks "download" 4. The files are then zipped and stored on a server 5. The user this then presented with a page which contains a link to the downloadable zip file 6. However on downloading the zip file the file that is downloaded is 0 bytes in size I have checked the remote server and the zip file is being created properly, all that is left is to serve the file the user somehow, can you see where I might be going wrong, or suggest a better way to serve the zip file. The code that creates the link is: <% String zipFileURL = (String) request.getAttribute("zipFileURL"); %> <p><a href="<% out.print(zipFileURL); %> ">Zip File Link</a></p> The code that creates the zipFileURL variable is: public static String zipFiles(ArrayList<String> fileList, String contextRootPath) { //time-stamping Date date = new Date(); Timestamp timeStamp = new Timestamp(date.getTime()); Iterator fileListIterator = fileList.iterator(); String zipFileURL = ""; try { String ZIP_LOC = contextRootPath + "WEB-INF" + SEP + "TempZipFiles" + SEP; BufferedInputStream origin = null; zipFileURL = ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"; FileOutputStream dest = new FileOutputStream(ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"); ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream( dest)); // out.setMethod(ZipOutputStream.DEFLATED); byte data[] = new byte[BUFFER]; while(fileListIterator.hasNext()) { String fileName = (String) fileListIterator.next(); System.out.println("Adding: " + fileName); FileInputStream fi = new FileInputStream(fileName); origin = new BufferedInputStream(fi, BUFFER); ZipEntry entry = new ZipEntry(fileName); out.putNextEntry(entry); int count; while ((count = origin.read(data, 0, BUFFER)) != -1) { out.write(data, 0, count); } origin.close(); } out.close(); } catch (Exception e) { e.printStackTrace(); } return zipFileURL; }

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  • linux/shell: change a file's modify timestamp relatively?

    - by index
    My Canon camera produces files like IMG_1234.JPG and MVI_1234.AVI. It also timestamps those files. Unfortunately during a trip to another timezone several cameras were used, one of which did not have the correct time zone set - meta data mess.. Now I would like to correct this. Proposed algorithm: 1 read file's modify date 2 add delta, i.e. hhmmss (preferred: change timezone) 3 write new timestamp Unless someone knows a tool or a combination of tools that do the trick directly, maybe one could simplify the calculation using epoch time (seconds since ..) and whip up a shell script. Any help appreciated!

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  • Using Terminal Services 'query' in batch file

    - by dboarman-FissureStudios
    I have a batch file that checks several of our servers for a user. From the command: query user %userID% /server:ServerName I want to capture the output before it goes to the screen. Is there a way to redirect the output to a variable? The basic gist of what I want to accomplish is this - we iterate through our servers: query user %userID% /server:Server1 query user %userID% /server:Server2 query user %userID% /server:Server3 query user %userID% /server:Server4 Instead of outputting a message that the user could not be found on a specific server, I would like for it to only notify me if it finds the user on a server.

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  • OS X Snow Leopard, change file permissions on copy

    - by Francesco K
    I work with OS X, Snow Leopard and need to allow users to make copies of files (templates) located in a read-only repository for subsequent editing. The repository is located on a separate physical drive mounted to the OS X boot volume. As this is a shared computer in a school environment, all users access the machine via a single login ("user_local"). Whether using POSIX permissions or ACLs, the use case requires the file permissions to change from "read" to "read write" as they get copied to the "user_local" home directory. Googling around has not yielded anything that would indicate that this is possible via the Snow Leopard permission system. Question 1: Is this in fact possible via the permission system? If so, how? Question 2: If not possible, how would one go about solving this problem? I imagine this to be a fairly common use case so there must be a workable solution for it out there. Thanks.

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  • Vaadin: Downloaded file has whole path as file name

    - by javydreamercsw
    I have a download action implemented on my Vaadin application but for some reason the downloaded file has the original file's full path as the file name. Any idea? You can see the code on this post. Edit: Here's the important part of the code: package com.bluecubs.xinco.core.server.vaadin; import com.bluecubs.xinco.core.server.XincoConfigSingletonServer; import com.vaadin.Application; import com.vaadin.terminal.DownloadStream; import com.vaadin.terminal.FileResource; import java.io.*; import java.net.URLEncoder; import java.util.UUID; import java.util.logging.Level; import java.util.logging.Logger; import java.util.zip.CRC32; import java.util.zip.CheckedInputStream; /** * * @author Javier A. Ortiz Bultrón<[email protected]> */ public class FileDownloadResource extends FileResource { private final String fileName; private File download; private File newFile; public FileDownloadResource(File sourceFile, String fileName, Application application) { super(sourceFile, application); this.fileName = fileName; } protected void cleanup() { if (newFile != null && newFile.exists()) { newFile.delete(); } if (download != null && download.exists() && download.listFiles().length == 0) { download.delete(); } } @Override public DownloadStream getStream() { try { //Copy file to directory for downloading InputStream in = new CheckedInputStream(new FileInputStream(getSourceFile()), new CRC32()); download = new File(XincoConfigSingletonServer.getInstance().FileRepositoryPath + System.getProperty("file.separator") + UUID.randomUUID().toString()); newFile = new File(download.getAbsolutePath() + System.getProperty("file.separator") + fileName); download.mkdirs(); OutputStream out = new FileOutputStream(newFile); newFile.deleteOnExit(); download.deleteOnExit(); byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); out.close(); final DownloadStream ds = new DownloadStream( new FileInputStream(newFile), getMIMEType(), fileName); ds.setParameter("Content-Disposition", "attachment; filename=" + URLEncoder.encode(fileName, "utf-8")); ds.setCacheTime(getCacheTime()); return ds; } catch (final FileNotFoundException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } catch (IOException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } } } I already debugged and verified that fileName only contains the file's name not the whole path.

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  • VSFTPD uploaded file permissions

    - by Katafalkas
    Let me first say that there are loads of topics regarding this, and I am sure i have seen them all by now. Still non of the solutions seem to help. I installed vsftpd. created a user ftp-data. Now I need that files uploaded by user ftp-data would have 755 permissions. Solving this should be as easy as adding: local_umask=002 file_open_mode=0755 but that did not help, then I have tried a number of variations of this, still did not help. The I added: chmod_enable=YES still did not help. At the moment I think that I am missing something very simple and obvious, just cant find it. Maybe someone could help me to find what I am missing. This is my config file: anonymous_enable=NO local_enable=YES write_enable=YES local_umask=002 anon_upload_enable=NO anon_mkdir_write_enable=NO dirmessage_enable=NO xferlog_enable=YES connect_from_port_20=YES xferlog_file=/var/log/xferlog listen=YES local_root=/var/www/ftp-gallery pam_service_name=vsftpd userlist_enable=YES tcp_wrappers=YES

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  • Unlock file on Windows Server 2003 by remote desktop without rebooting

    - by BalusC
    We've several Windows Server 2003 machines running, each with its own purposes. There are scheduled jobs which synchronizes some files over SFTP using WinSCP. Very sometimes a newly copied file is left locked in the "inbox" folder without any reason. The machine's own background task (programmed in Java) can't move it to the "processed" folder anymore after processing it. Manually moving it only yields the well known error message Cannot move [filename]: it is being used by another person or program. The only resort is to reboot the machine, but we would of course like to avoid that. Any suggestions? I tried Unlocker which works fine locally at WinXP, but doesn't work at those Win2K3 machines by remote desktop (unlock option doesn't show up in rightclick context menu). I tried Process Explorer as well as described in this blog article, but it caused the server to crash (not sure if that's because it's executed through remote desktop).

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  • How to remove $data stream from file in windows 8

    - by chris.w.mclean
    Windows for a while now has added an additional hidden stream to files that were downloaded from the internet. If you attempted to use these files, you'd get all kinds of odd behavior as windows was detecting this additional stream and then preventing the app / exe from getting all sorts of security clearance. But in previous versions of windows you could right click on a file, go to properties then click 'Unblock' which removed the extra stream. Windows 8 seems to be doing the additional streams trick, but I haven't yet found a way to remove them using the win 8 UI. Anyone know how to do this?

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  • Why might a file only be partially uploaded?

    - by letseatfood
    Why might a file only be partially uploaded? I am improving error-handling in my PHP file upload script and am trying to figure out how to handle UPLOAD_ERR_PARTIAL properly. Should I prompt the user to try uploading the file again, or should I inform them that there is a more severe problem which is preventing them from uploading a possibly legitimate file? Thanks!

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  • java ..from one java file comple other java file

    - by dpaksp
    here is my case ...i have one xxxxxx.java file when comple and run the file i get output as yyyyyy.java file .....but i need yyyyyy.class file i.e is from xxxxxx.java file should automatically compile it output file and get yyyyyy.class...is this can be done in java thanks

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  • android - pre-allocate space for a file before downloading it

    - by android developer
    how can i create a pre-allocated file on android? something like a sparse file ? i need to make an applicaton that will download a large file , and i want to avoid having an out-of-space error while the download is commencing . my solution needs to support resuming and writing to both internal and external storage. i've tried what is written here: Create file with given size in Java but none of the solutions there didn't work for some reason.

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  • How to enable an active/active file server cluster in windows 2008 r2 Enterprise

    - by Phygg
    I've just created a cluster for my file servers in Windows 2008 R2 Ent SP1 environment. The goal - an Active/Active cluster for web server data How do I go about telling the cluster to be active for both nodes? Do I have to tell the cluster to be active/active? Here is a link to the instructions I followed when configuring the failover cluster. http://technet.microsoft.com/en-us/library/ff182326(WS.10).aspx So if anyone can help me to grasp the concept or maybe I'm way off and I need a node that is not active along with 2 active nodes to do this, I would appreciate it.

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  • Python timed file upload

    - by Ali
    I have a python script that accepts a file from the user and saves it. Is it possible to not upload the file immediately but to que it up and when the server has less load to upload it then. Can this be done by transferring the file to the browsers storage area or taking the file from the Harddrive and transferring to the User's RAM?

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  • Schedule a batch file with parameters containing spaces

    - by Danilo Brambilla
    Hi, I need to schedule a task in Windows Server 2003 that executes this script that deletes files older that n days in the specified folder. The script needs 3 parameters: %1 path to folder where files need to be deleted %2 file names (es. *.log) %3 number of days @echo off forfiles -p %1 -s -m %2 -d -%3 -c "cmd /c del /q @path" The script works fine if the first parameter has no spaces inside. This is an example of parameters that work: "C:\Program Files\SCRIPT\DeleteFilesOlderThanXDays.cmd" N:\FOLDER\FOLDER *.zip 60 This is an example that does not work: "C:\Program Files\SCRIPT\DeleteFilesOlderThanXDays.cmd" N:\Program Files\LOG *.zip 60 This does not work too: "C:\Program Files\SCRIPT\DeleteFilesOlderThanXDays.cmd" "N:\Program Files\LOG" *.zip 60 I think it would be a quotes problem but I can't figure out the solution. I'd like not to insert values directly into the script if possible Thank you all for help

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  • Can't access network share with name defined in hosts file

    - by Einar Egilsson
    I have a network share on a machine that I can only reach by IP address. I then defined an alias for the IP in my hosts file so I could use that instead of the IP but then I can't log on to the share, I just get the logon prompt again and again. So basically this: \\172.17.0.48\SomeShare works but this \\myalias\SomeShare doesn't. myalias is defined in c:\windows\system32\drivers\etc\hosts as 172.17.0.48 myalias And I can use the alias for remote desktop without problems. Can anyone tell me why this doesn't work for fileshares?

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  • how to identify a file is a text file or other using c#.net

    - by bjh Hans
    I need to access a file as text file and want to process it later. But before I fetch it how I can identify a file that I am taking is a text file only. If file is in another format my whole code interpret wrongly. I want to access and process only text file. Currently i am using: StreamReader objReader = new StreamReader(filePath); How can I do so in C# .NET?

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  • Run disk error check on NTFS file?

    - by paulius_l
    I have a feeling that my system hard drive is dying. Benchmark kind of enforces it. Here is the benchmark of my system hard drive during low system activity: And here is the benchmark of backup drive: Furthermore, there are some files which I just can't touch because I get CRC errors and the hard drive activity spikes to 100% with operating speeds less than 1 MB/s while working with such files. I haven't yet tried swapping SATA cable as I have read this might cause the problems. Anyway, I would like to run some tests on specific clustsers where those files I am interested in are stored. I don't want to do the full chkdsk because it takes a very long time. I would like to either find the utility which executes the disk check directly on the clusters where the file belongs or a couple utilities where one tells me the cluster locations and another can check just those locations. How do I check and possibly fix disk errors where the files I am interested in are stored? Edit: S.M.A.R.T. info:

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  • "remote file operation failed" on Hudson

    - by Aveen
    I am running a Windows slave for Husdon 1.337 (Linux master). When running a project on the Windows node, it fails with the following message: Building remotely on winTestSlave Checking out a fresh workspace because there's no workspace at C:\hudson\***\ejb remote file operation failed It did work yesterday and I have not upgraded Hudson or changed its configurations (or the slave's configurations) in any way. I establish the connection between the slave and the master by running the following command on a cygwim prompt on the slave: java -jar slave.jar -jnlpUrl http://myserver/computer/winTestSlave/slave-agent.jnlp I saw the issue http://issues.hudson-ci.org/browse/HUDSON-5374 and did as instructed in the work-around but that did not work. I also tried with a newer version of slave.jar (version 1.356) but that did not work either. Does anyone please have any idea of how to fix this? I really cannot find more information anywhere else!

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  • [PHP] Read and write to a file while keeping lock

    - by Znarkus
    Hi! I am making a simple page load counter by storing the current count in a file. This is how I want to do this: Lock the file Read the current count Increment it Write new count Unlock file/close it Can this be done? As I understand it, the file can't be written to without losing the lock. The only way I have come up with to tackle this, is to write a character using "r+" mode, and then counting characters.

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  • Slow write speeds on new Gigabit home file server

    - by Ryan Holder
    So I finally got all my parts delivered to setup a home file/backup server this week. It's currently running Ubuntu Server and I'm using Samba to share files on my network. The server currently has a 2TB WD Green drive in it connected to a Asus M5A78L-M This is then connected via CAT6a to my new Gigabit switch (TP-Link TL-SG1005D). My home desktop is then also connected to this switch and again also through CAT6a cable. Currently when transfering files I will get a perfect 100MB/s read from the server to my Windows machine. When copying from my Windows machine to the server I get around 30/38MB/s. I know this drive is capable is faster speeds so would anybody have an idea of where the bottleneck is? Any help would be greatly appreciated :) EDIT: I have found ftp's write speed is much closer to what my Samba read speed is so I'm going to give it a guess that is a software problem rather than hardware

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