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  • Search a string in a file and write the matched lines to another file in Java

    - by Geeta
    For searching a string in a file and writing the lines with matched string to another file it takes 15 - 20 mins for a single zip file of 70MB(compressed state). Is there any ways to minimise it. my source code: getting Zip file entries zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while (entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if (entry.isDirectory()) { continue; } searchString(Thread.currentThread(),entry.getName(), new BufferedInputStream (zipFile.getInputStream(entry)), Out_File, search_string, stats); } zipFile.close(); Searching String public void searchString(Thread CThread, String Source_File, BufferedInputStream in, File outfile, String search, String stats) throws IOException { int count = 0; int countw = 0; int countl = 0; String s; String[] str; BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); System.out.println(CThread.currentThread()); while ((s = br2.readLine()) != null) { str = s.split(search); count = str.length - 1; countw += count; //word count if (s.contains(search)) { countl++; //line count WriteFile(CThread,s, outfile.toString(), search); } } br2.close(); in.close(); } -------------------------------------------------------------------------------- public void WriteFile(Thread CThread,String line, String out, String search) throws IOException { BufferedWriter bufferedWriter = null; System.out.println("writre thread"+CThread.currentThread()); bufferedWriter = new BufferedWriter(new FileWriter(out, true)); bufferedWriter.write(line); bufferedWriter.newLine(); bufferedWriter.flush(); } Please help me. Its really taking 40 mins for 10 files using threads and 15 - 20 mins for a single file of 70MB after being compressed. Any ways to minimise the time.

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  • Read quicktime movie from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\\TEMP\\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using embed or object tag to read the media stream from the response? Here is my code in the servlet: public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getParameter("location"); uploadFile(response); } private void uploadFile(HttpServletResponse response) { File transferFile = new File("C:/TEMP/captured.mov"); FileInputStream in = null; try { in = new FileInputStream(transferFile); } catch (FileNotFoundException e) { System.out.println("File not found"); } try { System.out.println("in byes i s" + in.available()); } catch (IOException e) { } DataOutputStream responseStream = null; try { responseStream = new DataOutputStream(response.getOutputStream()); } catch (IOException e) { System.out.println("Io exception"); } try { Util.copyStream(in, responseStream); } catch (CopyStreamException e) { System.out.println("copy Stream exception"); } try { responseStream.flush(); } catch (IOException e) { } try { responseStream.close(); } catch (IOException e) { } } And here is html page as Ryan suggested: <embed SRC="http://localhost:7101/movies/transferservlet" WIDTH=100 HEIGHT=196 AUTOPLAY=true CONTROLLER=true LOOP=false PLUGINSPAGE="http://www.apple.com/quicktime/"> Any ideas?

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  • Django install on a shared host, .htaccess help

    - by redconservatory
    I am trying to install Django on a shared host using the following instructions: docs.google.com/View?docid=dhhpr5xs_463522g My problem is with the following line on my root .htaccess: RewriteRule ^(.*)$ /cgi-bin/wcgi.py/$1 [QSA,L] When I include this line I get a 500 error with almost all of my domains on this account. My cgi-bin directory is home/my-username/public_html/cgi-bin/ The wcgi.py file contains: #!/usr/local/bin/python import os, sys sys.path.insert(0, "/home/username/django/") sys.path.insert(0, "/home/username/django/projects") sys.path.insert(0, "/home/username/django/projects/newprojects") import django.core.handlers.wsgi os.chdir("/home/username/django/projects/newproject") # optional os.environ['DJANGO_SETTINGS_MODULE'] = "newproject.settings" def runcgi(): environ = dict(os.environ.items()) environ['wsgi.input'] = sys.stdin environ['wsgi.errors'] = sys.stderr environ['wsgi.version'] = (1,0) environ['wsgi.multithread'] = False environ['wsgi.multiprocess'] = True environ['wsgi.run_once'] = True application = django.core.handlers.wsgi.WSGIHandler() if environ.get('HTTPS','off') in ('on','1'): environ['wsgi.url_scheme'] = 'https' else: environ['wsgi.url_scheme'] = 'http' headers_set = [] headers_sent = [] def write(data): if not headers_set: raise AssertionError("write() before start_response()") elif not headers_sent: # Before the first output, send the stored headers status, response_headers = headers_sent[:] = headers_set sys.stdout.write('Status: %s\r\n' % status) for header in response_headers: sys.stdout.write('%s: %s\r\n' % header) sys.stdout.write('\r\n') sys.stdout.write(data) sys.stdout.flush() def start_response(status,response_headers,exc_info=None): if exc_info: try: if headers_sent: # Re-raise original exception if headers sent raise exc_info[0], exc_info[1], exc_info[2] finally: exc_info = None # avoid dangling circular ref elif headers_set: raise AssertionError("Headers already set!") headers_set[:] = [status,response_headers] return write result = application(environ, start_response) try: for data in result: if data: # don't send headers until body appears write(data) if not headers_sent: write('') # send headers now if body was empty finally: if hasattr(result,'close'): result.close() runcgi() Only I changed the "username" to my username...

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  • Java Socks Proxy Socket Error

    - by Ionut Ungureanu
    I am trying to create a http request through a SOCKS (v4 / v5) proxy in Java. After reading about socks communication protocol on WikiPedia, I have put togheter this piece of code: Socket sock = new Socket(); InetSocketAddress remoteProxyAddress = new InetSocketAddress(proxy ip, proxy port); sock.connect(remoteProxyAddress, connTimeout); InputStream in = sock.getInputStream(); OutputStream out = sock.getOutputStream(); out.write(0x04); out.write(0x01); out.write((endpoint.getPort() >> 8) & 0xff); out.write((endpoint.getPort() >> 0) & 0xff); out.write(endpoint.getAddress().getAddress()); out.write(0x0); out.flush(); And here comes the part where I read from the proxy server. The problem is that the response is always "-1". I have tried the proxy on Firefox and it works perfect. So... the problem is in my app. Can anyone help me? Thanks!

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  • How to use IO.popen to write-to and read-from a child process?

    - by mackenir
    I am running net share from a ruby script to delete a windows network share. If files on the share are in use, net share will ask the user if they want to go ahead with the deletion, so my script needs to inspect the output from the command, and write out Y if it detects that net share is asking it for input. In order to be able to write out to the process I open it with access flags "r+". When attempting to write to the process with IO#puts, I get an error: Errno::EPIPE: Broken pipe What am I doing wrong here? (The error occurs on the line net_share.puts "Y") (The question text written out by net share is not followed by a newline, so I am using IO#readpartial to read in the output.) def delete_network_share share_path command = "net share #{share_path} /DELETE" net_share = IO.popen(command, "r+") text = "" while true begin line = net_share.readpartial 1000 #read all the input that's available rescue EOFError break end text += line if text.scan("Do you want to continue this operation? (Y/N)").size > 0 net_share.puts "Y" net_share.flush #probably not needed? end end net_share.close end

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  • Struts 2 discard cache header

    - by Dewfy
    I have strange discarding behavior of struts2 while setting cache option for my image. I'm trying to put image from db to be cached on client side To render image I use ( http://struts.apache.org/2.x/docs/how-can-we-display-dynamic-or-static-images-that-can-be-provided-as-an-array-of-bytes.html ) where special result type render as follow: public void execute(ActionInvocation invocation) throws Exception { ...//some preparation HttpServletResponse response = ServletActionContext.getResponse(); HttpServletRequest request = ServletActionContext.getRequest(); ServletOutputStream os = response.getOutputStream(); try { byte[] imageBytes = action.getImage(); response.setContentType("image/gif"); response.setContentLength(imageBytes.length); //I want cache up to 10 min Date future = new Date(((new Date()).getTime() + 1000 * 10*60l)); ; response.addDateHeader("Expires", future.getTime()); response.setHeader("Cache-Control", "max-age=" + 10*60 + ""); response.addHeader("cache-Control", "public"); response.setHeader("ETag", request.getRequestURI()); os.write(imageBytes); } catch(Exception e) { response.sendError(HttpServletResponse.SC_NOT_FOUND); } os.flush(); os.close(); } But when image is embedded to page it is always reloaded (Firebug shows code 200), and neither Expires, nor max-age are presented in header Host localhost:9090 Accept image/png,image/*;q=0.8,*/*;q=0.5 Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Referer http://localhost:9090/web/result?matchId=1 Cookie JSESSIONID=4156BEED69CAB0B84D950932AB9EA1AC; If-None-Match /web/_srv/teamcolor Cache-Control max-age=0 I have no idea why it is dissapered, may be problem in url? It is forms with parameter: http://localhost:9090/web/_srv/teamcolor?loginId=3

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  • create and write to a text file in vb.net

    - by woolardz
    I'm creating a small vb.net application, and I'm trying trying to write a list of results from a listview to a text file. I've looked online and found the code to open the save file dialog and write the text file. When I click save on the save file dialog, I receive an IOException with the message "The process cannot access the file 'C:\thethe.txt' because it is being used by another process." The text file is created in the correct location, but is empty. The application quits at this line "Dim fs As New FileStream(saveFileDialog1.FileName, FileMode.OpenOrCreate, FileAccess.Write)" Thanks in advance for any help. Private Sub btnSave_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnSave.Click Dim myStream As Stream Dim saveFileDialog1 As New SaveFileDialog() saveFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" saveFileDialog1.FilterIndex = 2 saveFileDialog1.RestoreDirectory = True If saveFileDialog1.ShowDialog() = DialogResult.OK Then myStream = saveFileDialog1.OpenFile() If (myStream IsNot Nothing) Then Dim fs As New FileStream(saveFileDialog1.FileName, FileMode.OpenOrCreate, FileAccess.Write) Dim m_streamWriter As New StreamWriter(fs) m_streamWriter.Flush() 'Write to the file using StreamWriter class m_streamWriter.BaseStream.Seek(0, SeekOrigin.Begin) 'write each row of the ListView out to a tab-delimited line in a file For i As Integer = 0 To Me.ListView1.Items.Count - 1 m_streamWriter.WriteLine(((ListView1.Items(i).Text & vbTab) + ListView1.Items(i).SubItems(0).ToString() & vbTab) + ListView1.Items(i).SubItems(1).ToString()) Next myStream.Close() End If End If End Sub

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  • Real Time Sound Captureing J2ME

    - by Abdul jalil
    i am capturing sound in J2me and send these bytes to remote system, i then play these bytes on remote system.five second voice is capture and send to remote system. i get the repeated sound again .i am making a sound messenger please help me where i am doing wrong i am using the follown code . String remoteTimeServerAddress="192.168.137.179"; sc = (SocketConnection) Connector.open("socket://"+remoteTimeServerAddress+":13"); p = Manager.createPlayer("capture://audio?encoding=pcm&rate=11025&bits=16&channels=1"); p.realize(); RecordControl rc = (RecordControl)p.getControl("RecordControl"); ByteArrayOutputStream output = new ByteArrayOutputStream(); OutputStream outstream =sc.openOutputStream(); rc.setRecordStream(output); rc.startRecord(); p.start(); int size=output.size(); int offset=0; while(true) { Thread.currentThread().sleep(5000); rc.commit(); output.flush(); size=output.size(); if(size0) { recordedSoundArray=output.toByteArray(); outstream.write(recordedSoundArray,0,size); } output.reset(); rc.reset(); rc.setRecordStream(output); rc.startRecord(); }

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  • How can I handle unread push notifications in iOS?

    - by Bartserk
    I have a iOS 5.1 application that registers to the APNS service to receive notifications. The register is successful and I receive the notifications correctly. The problem comes when I try to handle the notifications. Once the application is running, the method didReceiveRemoteNotification in the AppDelegate is called correctly and so the notification is handled as intended. This, however, only happens when the application is running on the foreground. However, when the application is running on the background or is simply stopped, that method is not called. I've read that you should add some lines to the method didFinishLaunchingWithOptions method to obtain the notification from the userInfo dictionary, and handle it. This works just fine, but ONLY when the application is opened by clicking on the notification at the Notification Center. This means that if you open the application by clicking on its badge, or simply by changing context if you were running it on the background, the app never realises that a notification came in. Additionally, if more than one notification was received, we can only handle one of them at once by clicking on the Notification Center, which is a pain :-) Is there any way to read the pending notifications in the Notification Center? I know there is a way to flush them using the method cancelAllLocalNotifications but I haven't found a way to just read them. And I really need to handle all of them. I thought of implementing a communication protocol with the third-party notification server to retrieve the information again when the application comes to the foreground, but since the information is already in the operating system I would find it strange if it's impossible to access it somehow. So, does anybody know a way to do it? Thanks in advance.

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  • Android: Resolution issue while saving image into gallery

    - by Luca D'Amico
    I've managed to programmatically take a photo from the camera, then display it on an imageview, and then after pressing a button, saving it on the Gallery. It works, but the problem is that the saved photo are low resolution.. WHY?! I took the photo with this code: Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE); startActivityForResult(cameraIntent, CAMERA_PIC_REQUEST); Then I save the photo on a var using : protected void onActivityResult(int requestCode, int resultCode, Intent data) { if (requestCode == CAMERA_PIC_REQUEST) { thumbnail = (Bitmap) data.getExtras().get("data"); } } and then after displaying it on an imageview, I save it on the gallery with this function: public void SavePicToGallery(Bitmap picToSave, File savePath){ String JPEG_FILE_PREFIX= "PIC"; String JPEG_FILE_SUFFIX= ".JPG"; String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date()); String imageFileName = JPEG_FILE_PREFIX + timeStamp + "_"; File filePath = null; try { filePath = File.createTempFile(imageFileName, JPEG_FILE_SUFFIX, savePath); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } FileOutputStream out = null; try { out = new FileOutputStream(filePath); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } picToSave.compress(CompressFormat.JPEG, 100, out); try { out.flush(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } try { out.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } //Add the pic to Android Gallery String mCurrentPhotoPath = filePath.getAbsolutePath(); MediaScannerConnection.scanFile(this, new String[] { mCurrentPhotoPath }, null, new MediaScannerConnection.OnScanCompletedListener() { public void onScanCompleted(String path, Uri uri) { } }); } I really can't figure out why it lose so much quality while saved.. Any help please ? Thanks..

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  • How do I nicely manage many localhost web site URIs with IIS7

    - by Simeon
    I'm having trouble setting up a clean development environment with all the web sites I'm working on. I'm working on up to 40 different web sites, and at least 5 of them simultaneously. I need them all to be in a site root, for URL management to work with all CMSes. My first attempt was to use increasing port numbers for them, beginning with localhost:1000 and working upwards. Unfortunately, it took a great deal of looking up which port belonged to which web site, and it was very irritating. My second try was mapping the irritating ports to real words using the hosts file. So I ended up with localhost.tele2, localhost.ikea, localhost.volvo etc. Unfortunately, this takes a long time to set up (cleaning and adding to the hosts file, setting web site with highest port number in IIS etc.) and regularly I have to flush the DNS cache in order to get some sites working that I've added/removed from the hosts file. So how do I organize a lot of web sites in IIS7 nicely? Perhaps I've missed a very clever method that you're using.

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  • python os.mkfifo() for Windows

    - by user302099
    Hello. Short version (if you can answer the short version it does the job for me, the rest is mainly for the benefit of other people with a similar task): In python in Windows, I want to create 2 file objects, attached to the same file (it doesn't have to be an actual file on the hard-drive), one for reading and one for writing, such that if the reading end tries to read it will never get EOF (it will just block until something is written). I think in linux os.mkfifo() would do the job, but in Windows it doesn't exist. What can be done? (I must use file-objects). Some extra details: I have a python module (not written by me) that plays a certain game through stdin and stdout (using raw_input() and print). I also have a Windows executable playing the same game, through stdin and stdout as well. I want to make them play one against the other, and log all their communication. Here's the code I can write (the get_fifo() function is not implemented, because that's what I don't know to do it Windows): class Pusher(Thread): def __init__(self, source, dest, p1, name): Thread.__init__(self) self.source = source self.dest = dest self.name = name self.p1 = p1 def run(self): while (self.p1.poll()==None) and\ (not self.source.closed) and (not self.source.closed): line = self.source.readline() logging.info('%s: %s' % (self.name, line[:-1])) self.dest.write(line) self.dest.flush() exe_to_pythonmodule_reader, exe_to_pythonmodule_writer =\ get_fifo() pythonmodule_to_exe_reader, pythonmodule_to_exe_writer =\ get_fifo() p1 = subprocess.Popen(exe, shell=False, stdin=subprocess.PIPE, stdout=subprocess.PIPE) old_stdin = sys.stdin old_stdout = sys.stdout sys.stdin = exe_to_pythonmodule_reader sys.stdout = pythonmodule_to_exe_writer push1 = Pusher(p1.stdout, exe_to_pythonmodule_writer, p1, '1') push2 = Pusher(pythonmodule_to_exe_reader, p1.stdin, p1, '2') push1.start() push2.start() ret = pythonmodule.play() sys.stdin = old_stdin sys.stdout = old_stdout

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  • java url connection, wait for data being sent through the outputstream

    - by Mateu
    I'm writting a java class that tests uploading speed connection to a server. I want to check how many data can be send in 5 seconds. I've written a class which creates a URL, creates a connection, and sends data trough the outPutStream. There is a loop where I writte data to the stream for 5 seconds. However I'm not able to see when data has been send (I writte data to the output stream, but data is not send yet). How can I wait untill data is really sent to the server? Here goes my code (which does not work): URL u = new URL(url) HttpURLConnection uc = (HttpURLConnection) u.openConnection(); uc.setDoOutput(true); uc.setDoInput(true); uc.setUseCaches(false); uc.setDefaultUseCaches(false); uc.setRequestMethod("POST"); uc.setRequestProperty("Content-Type", "application/octet-stream"); uc.connect(); st.start(); // Send the request OutputStream os = uc.getOutputStream(); //This while is incorrect cause it does not wait for data beeing sent while (st.getElapsedTime() < miliSeconds) { os.write(buffer); os.flush(); st.addSize(buffer.length); } os.close(); Thanks

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  • .NET, ASHX, "Server cannot append header after HTTP headers have been sent" after sending PDF Streem

    - by Inturbidus
    I visit my ASHX file, and it outputs a PDF perfectly. If I visit the very same ASHX with a different query string (I append DateTime.Now.Ticks to the end each visit), and I get this error: Server cannot append hader after HTTP headers have been sent. My code is below: copy.CloseStream = false; document.Close(); var r = context.Response; r.ExpiresAbsolute = DateTime.Now; r.BufferOutput = true; r.ContentType = "application/pdf"; r.AppendHeader("Content-Type", r.ContentType); r.AppendHeader("Content-disposition", "inline; filename=" + context.Server.UrlEncode(formType.File_Name)); r.BinaryWrite(copyStream.ToArray()); r.StatusCode = 200; r.End(); originalReader.Close(); copy.CloseStream = true; copy.Close(); There is no other place in this code that headers are sent. You are seeing the entire interaction with the Response object. I've tried to use r.Flush(); and r.End(); I've also tried not sending them if they are already there, but this causes other issues.

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  • Fluent NHibernate - How to map the foreign key column as a property

    - by Steve
    I am sure this is a straightforward question but consider the following: I have a reference between company and sector as follows: public class Company { public Guid ID { get; set; } public Sector Sector { get; set; } public Guid SectorID { get; set; } } public class Sector { public Guid ID { get; set; } public string Name { get; set; } } Ok. What I want is the SectorID of the Company object to be populated after I go: (new Company()).Sector = new Sector() { Name="asdf" } and do a flush. The mapping I am using kindly creates an additional column in the database called Sector_Id in the Company table, but this is not available as a property on Company. I want the SectorID property to be filled. The mapping i am currently using in the CompanyMap is References(c = c.Sector).Cascade.All(); Does anyone have any ideas?

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  • Incorrect component when querying immediately after insert using NHibernate

    - by Am
    I have the following mapping for my table in MySql: <class name="Tag, namespace" table="tags" > <id name="id" type="Int32" unsaved-value="0"> <generator class="native"></generator> </id> <property name="name" type="String" not-null="true"></property> <component name="record_dates" class="DateMetaData, namespace" > <property name="created_at" type="DateTime" not-null="true"></property> <property name="updated_at" type="DateTime" not-null="true"></property> </component> </class> As you see the record_dates property is defined as a component field of type DateMetaDate. Both created_at and updated_at fields in 'tags' table are updated via triggers. Thus I can insert a new record like such: var newTag = new Tag() { name = "some string here" } Int32 id = (Int32)Session.Save(tag); Session.Flush(); ITag t = Session.Get<Tag>(id); ViewData["xxx"] = t.name; // -----> not null ViewData["xxx"] = t.record_dates.created_at; // -----> is null However when querying the same record back immediately after it was inserted the record_dates field ends up null even though in the table those fields have got values. Can any one please point out why the Session.Get ignores getting everything back from the table? is it because it caches the newly created record for which the records_dates is null? If so how can it be told to ignore the cached version?

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  • how do I get a new line, after using float:left?

    - by codeman73
    What I am trying to do is have rows of images, 6 images in each row. Some of these images need to have another image floating on top of them (flush with the lower-right corner). I was able to get that to work from this thread: http://stackoverflow.com/questions/48474/how-do-i-position-one-image-on-top-of-another-in-html However, now I'm unable to get the new row after the 6th image. Neither <BR> or <P> create a new line. They simply push the next image down several pixels, but the image is still in the same line. It seems like the float style is interfering with the <BR> and/or <P>. I tried using different styles for the image that starts a new row, like float:none and display:block, but neither worked. The odd thing is that the new line starts after the 7th image. Here's what I'm using so far: <style type="text/css"> .containerdiv { float: left; position: relative; } .containerdivNewLine { float: none; display: block; position: relative; } .cornerimage { position: absolute; bottom: 0; right: 0; } </style> <div class="containerdiv"> <img border="0" height="188" src="myImg" width="133" /> <img class="cornerimage" height="140" src="imageOnTop" width="105" /> </div> For the 7th image, when I'm trying to start a new row, I'm simply replacing the 'containerdiv' class with 'containerdivNewLine'.

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  • How to append new elements to Xml from stream

    - by Wololo
    I have a method which returns some xml in a memory stream private MemoryStream GetXml() { XmlWriterSettings settings = new XmlWriterSettings(); settings.Indent = true; using (MemoryStream memoryStream = new MemoryStream()) { using (XmlWriter writer = XmlWriter.Create(memoryStream, settings)) { writer.WriteStartDocument(); writer.WriteStartElement("root"); writer.WriteStartElement("element"); writer.WriteString("content"); writer.WriteEndElement(); writer.WriteEndElement(); writer.WriteEndDocument(); writer.Flush(); } return memoryStream; } } In this example the format of the xml will be: <?xml version="1.0" encoding="utf-8"?> <root> <element>content</element> </root> How can i insert a new element under the root e.g <?xml version="1.0" encoding="utf-8"?> <root> <element>content</element> ----->New element here <------ </root>

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  • problem finding a header with a c++ makefile

    - by Max
    Hi. I've started working with my first makefile. I'm writing a roguelike in C++ using the libtcod library, and have the following hello world program to test if my environment's up and running: #include "libtcod.hpp" int main() { TCODConsole::initRoot(80, 50, "PartyHack"); TCODConsole::root->printCenter(40, 25, TCOD_BKGND_NONE, "Hello World"); TCODConsole::flush(); TCODConsole::waitForKeypress(true); } My project directory structure looks like this: /CppPartyHack ----/libtcod-1.5.1 # this is the libtcod root folder --------/include ------------libtcod.hpp ----/PartyHack --------makefile --------partyhack.cpp # the above code (while we're here, how do I do proper indentation? Using those dashes is silly.) and here's my makefile: SRCDIR = . INCDIR = ../libtcod-1.5.1/include CFLAGS = $(FLAGS) -I$(INCDIR) -I$(SRCDIR) -Wall CC = gcc CPP = g++ .SUFFIXES: .o .h .c .hpp .cpp $(TEMP)/%.o : $(SRCDIR)/%.cpp $(CPP) $(CFLAGS) -o $@ -c $< $(TEMP)/%.o : $(SRCDIR)/%.c $(CC) $(CFLAGS) -o $@ -c $< CPP_OBJS = $(TEMP)partyhack.o all : partyhack partyhack : $(CPP_OBJS) $(CPP) $(CPP_OBJS) -o $@ -L../libtcod-1.5.1 -ltcod -ltcod++ -Wl,-rpath,. clean : \rm -f $(CPP_OBJS) partyhack I'm using Ubuntu, and my terminal gives me the following errors: max@max-desktop:~/Desktop/Development/CppPartyhack/PartyHack$ make g++ -c -o partyhack.o partyhack.cpp partyhack.cpp:1:23: error: libtcod.hpp: No such file or directory partyhack.cpp: In function ‘int main()’: partyhack.cpp:5: error: ‘TCODConsole’ has not been declared partyhack.cpp:6: error: ‘TCODConsole’ has not been declared partyhack.cpp:6: error: ‘TCOD_BKGND_NONE’ was not declared in this scope partyhack.cpp:7: error: ‘TCODConsole’ has not been declared partyhack.cpp:8: error: ‘TCODConsole’ has not been declared make: * [partyhack.o] Error 1 So obviously, the makefile can't find libtcod.hpp. I've double checked and I'm sure the relative path to libtcod.hpp in INCDIR is correct, but as I'm just starting out with makefiles, I'm uncertain what else could be wrong. My makefile is based off a template that the libtcod designers provided along with the library itself, and while I've looked at a few online makefile tutorials, the code in this makefile is a good bit more complicated than any of the examples the tutorials showed, so I'm assuming I screwed up something basic in the conversion. Thanks for any help.

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  • MySQL Can Connect Remotely but not Locally

    - by A Wizard Did It
    This is a weird problem and I'm not sure what's going on. I installed MySQL on a linux box I have running Ubuntu 10.04 LTS. I can access mysql via SSH mysql -p and perform all my commands that way. I added a user, and I can use AddedUser to connect remotely from my machine, but not from the local machine. It makes no sense to me... SELECT host, user FROM mysql.user Yields: +-----------+------------------+ | host | user | +-----------+------------------+ | % | AddedUser | | 127.0.0.1 | root | | li241-255 | root | | localhost | debian-sys-maint | | localhost | root | +-----------+------------------+ Problem is I'm developing on this machine using Node.js, and I can't connect locally from the server using the same username. I've tried FLUSH PRIVILEGES but that seems to have no effect. I know it's not Node.js because I'm using the same code on another database and it's working in that environment. Edit This is the error node is giving me. node.js:50 throw e; // process.nextTick error, or 'error' event on first tick ^ Error: ECONNREFUSED, Connection refused at Stream._onConnect (net.js:687:18) at IOWatcher.onWritable [as callback] (net.js:284:12) Edit 2 I have the right port & server as best I can tell. My /etc/mysql/my.cnf contains this: port = 3306 socket = /var/run/mysqld/mysqld.sock My MySQL object contains: { host: 'localhost', port: 3306, user: 'removed', password: 'removed', database: '', typeCast: true, flags: 260047, maxPacketSize: 16777216, charsetNumber: 192, debug: false, ending: false, connected: false, _greeting: null, _queue: [], _connection: null, _parser: null, server: 'ExternalIpAddress' } Possibly useful? netstat -ln | grep mysql unix 2 [ ACC ] STREAM LISTENING 1016418 /var/run/mysqld/mysqld.sock

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  • Weird behavior with windows startup C#

    - by FrieK
    Hi, I've created an application with the option to start on Windows startup. First I did this via the Registry, like this: private void RunOnStartup(bool RunOnStartup) { Microsoft.Win32.RegistryKey key = Microsoft.Win32.Registry.CurrentUser.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true); if (RunOnStartup) { key.SetValue(ProgramTitle, System.Windows.Forms.Application.ExecutablePath.ToString()); } else { key.DeleteValue(ProgramTitle, false); } } And this worked, but not correctly. It started the .exe but with the same behavior as it was a new one with the default 'config.xml' it needs. Which is obviously wrong. I did not manage to find out what was wrong, so I tried it differently: create a shortcut in the Startup folder. Couldn't go wrong I figured, I mean, it's just a shortcut right? I used this code: private void RunOnStartup(bool RunOnStartup) { string startup = Environment.GetFolderPath(Environment.SpecialFolder.Startup) + "\\"+ProgramTitle+".url"; if (RunOnStartup) { using (StreamWriter writer = new StreamWriter(startup)) { string app = System.Reflection.Assembly.GetExecutingAssembly().Location; writer.WriteLine("[InternetShortcut]"); writer.WriteLine("URL=file:///" + app); writer.WriteLine("IconIndex=0"); string icon = app.Replace('\\', '/'); writer.WriteLine("IconFile=" + icon); writer.Flush(); } } else { if (File.Exists(startup)) { File.Delete(startup); } } } And this worked as well, it started, but with the same behavior. So my question is, does anyone have any idea how this happens? Any help is much appreciated! Thanks

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  • IndexOutOfRangeException when a stream is a multiple of the buffer size

    - by dnord
    I don't have a lot of experience with streams and buffers, but I'm having to do it for a project, and I'm stuck on an exception being thrown when the stream I'm reading is a multiple of the buffer size I've chosen. Let me show you: My code starts by reading bufferSize (100, let's say) bytes from the stream: numberOfBytesRead = DataReader.GetBytes(0, index, output, 0, bufferSize); Then, I loop through a while loop: while (numberOfBytesRead == bufferSize) { BufferWriter.Write(output); BufferWriter.Flush(); index += bufferSize; numberOfBytesRead = DataReader.GetBytes(0, index, output, 0, bufferSize); } ... and, once we get to a non-bufferSize read, we know we've hit the end of the stream and can move on. But if the bufferSize is 100, and the stream is 200, we'll read positions 0-99, 100-199, and then the attempt to read 200-299 errors out. I'd like it if it returned 0, but it throws an error. What I'm doing to handle that is, well, a try-catch: catch (System.IndexOutOfRangeException) numberOfBytesRead = 0; ...which ends the loop, and successfully finishes the thing, but we all know I don't want to control code flow with error handling. Is there a better (more standard?) way to handle stream reading when the stream length is unknown? This seems like a small wrinkle in a fairly reasonable strategy for reading streams, but I just don't know if I've got it wrong or what. The specifics of this (which I've cleaned up a little bit for posting) are a MySqlDataReader hitting a LARGEBLOB column. It's working whenever the buffer is larger than the number of returned bytes, or when the number of returned bytes is not a multiple of bufferSize. Because we don't, in that case, throw an IndexOutOfRangeException.

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  • download file, without saving in server

    - by lolalola
    Hi, Or possible for users to download the file without saving it on the server? I am getting data from the database, and I want to save them .doc (MS Word) file. if(isset($_POST['save'])) { $file = "new_file2.doc"; $stringData = "Text text text text...."; //This data put in new Word file $fh = fopen($file, 'w'); fwrite($fh, $stringData); fclose($fh); header('Content-Description: File Transfer'); header('Content-type: application/msword'); header('Content-Disposition: attachment; filename="'.$file.'"'); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . filesize($file)); ob_clean(); flush(); readfile($file); unlink($file); exit; } How should the code look like without this: " $fh = fopen($file, 'w'); fwrite($fh, $stringData); fclose($fh);" and this "unlink($file);" I hope to understand what I need enter code here

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  • How to proceed jpeg Image file size after read--rotate-write operations in Java?

    - by zamska
    Im trying to read a JPEG image as BufferedImage, rotate and save it as another jpeg image from file system. But there is a problem : after these operations I cannot proceed same file size. Here the code //read Image BufferedImage img = ImageIO.read(new File(path)); //rotate Image BufferedImage rotatedImage = new BufferedImage(image.getHeight(), image.getWidth(), BufferedImage.TYPE_3BYTE_BGR); Graphics2D g2d = (Graphics2D) rotatedImage.getGraphics(); g2d.rotate(Math.toRadians(PhotoConstants.ROTATE_LEFT)); int height=-rotatedImage.getHeight(null); g2d.drawImage(image, height, 0, null); g2d.dispose(); //Write Image Iterator iter = ImageIO.getImageWritersByFormatName("jpeg"); ImageWriter writer = (ImageWriter)iter.next(); // instantiate an ImageWriteParam object with default compression options ImageWriteParam iwp = writer.getDefaultWriteParam(); try { FileImageOutputStream output = null; iwp.setCompressionMode(ImageWriteParam.MODE_EXPLICIT); iwp.setCompressionQuality(0.98f); // an integer between 0 and 1 // 1 specifies minimum compression and maximum quality File file = new File(path); output = new FileImageOutputStream(file); writer.setOutput(output); IIOImage iioImage = new IIOImage(image, null, null); writer.write(null, iioImage, iwp); output.flush(); output.close(); writer.dispose(); Is it possible to access compressionQuality parameter of original jpeg image in the beginning. when I set 1 to compression quality, the image gets bigger size. Otherwise I set 0.9 or less the image gets smaller size. How can i proceed the image size after these operations? Thank you,

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  • Gradual memory leak and slowdown in loop

    - by Benji XVI
    I have a simple foundation tool that exports every frame of a movie as a .tiff file. Here is the relevant code: NSString* movieLoc = [NSString stringWithCString:argv[1]]; QTMovie *sourceMovie = [QTMovie movieWithFile:movieLoc error:nil]; int i=0; while (QTTimeCompare([sourceMovie currentTime], [sourceMovie duration]) != NSOrderedSame) { // save image of movie to disk NSAutoreleasePool *arp = [[NSAutoreleasePool alloc] init]; NSString *filePath = [NSString stringWithFormat:@"/somelocation_%d.tiff", i++]; NSData *currentImageData = [[sourceMovie currentFrameImage] TIFFRepresentation]; [currentImageData writeToFile:filePath atomically:NO]; NSLog(@"%@", filePath); [sourceMovie stepForward]; [arp release]; } [pool drain]; return 0; As you can see, in order to prevent very large memory buildups with the various transparently-autoreleased variables in the loop, we create, and flush, an autoreleasepool with every run through the loop. However, over the course of stepping through a movie, the amount of memory used by the program still gradually increases, and the speed at which frames are processed drops precipitously. (From ~0.5 seconds per frame at the start, to ~2 seconds per frame by the 250th frame.) The only thing I can think can be causing the gradual memory leak is a buildup of the NSAutoreleasePool objects themselves. Am I right in thinking they will only be deallocated when the outer pool is released? If so, is there a better memory management solution here? Creating a pool every run through the loop seems a little hacky. And if not, what is causing the slow memory leak? (It is not NSStrings, and much too slow to be NSImages or NSDatas.) And what could be causing the slowdown?

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