MUL instruction help
- by Tanner Babcock
I've read a few tutorials and examples, but I cannot wrap my head around how the MUL instruction works. I've used ADD and SUB without problems. So apparently this instruction multiplies its operand by the value in a register. What register (eax, ebp, esp, etc.) is multiplied by the first operand? And what register is the result stored in, so I can move it to the stack? Sorry, I'm just learning x86 assembly.
When I try to compile this line...
mull $9
I get, "Error: suffix or operands invalid for 'mul'". Can anyone help me out? Thanks.
EDIT: OK Madhur, I replaced "mull" with "mul" and I'm still getting the same error. Here's the whole source.
.globl _main
_main:
pushl %ebp
movl %esp, %ebp
subl $8, %esp
movl $7, %eax
mul $9
movl %eax, (%esp)
call _putchar
xorl %eax, %eax
leave
ret
