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  • Turn off email notification from abrt (Automatic Bug Reporting Tool)

    - by Banjer
    I'm configuring CentOS 6.2 and have seen a few "[abrt] full crash report" emails. I understand that abrt is useful for creating crash dumps and what not, so I don't want to disable the service, I just would like to stop getting the crash report emails. I probably have to add something to the config file in /etc/abrt/abrt.conf. I can't seem to find anything in my searches. Any idea? Thanks. Edit: Here is my abrt.conf, which is rather simple. [root@myhost~]# cat /etc/abrt/abrt.conf # Enable this if you want abrtd to auto-unpack crashdump tarballs which appear # in this directory (for example, uploaded via ftp, scp etc). # Note: you must ensure that whatever directory you specify here exists # and is writable for abrtd. abrtd will not create it automatically. # #WatchCrashdumpArchiveDir = /var/spool/abrt-upload # Max size for crash storage [MiB] or 0 for unlimited # MaxCrashReportsSize = 1000 # Specify where you want to store coredumps and all files which are needed for # reporting. (default:/var/spool/abrt) # #DumpLocation = /var/spool/abrt And a listing of /etc/abrt: [root@myhost~]# ls -la /etc/abrt total 32 drwxr-xr-x. 3 root root 4096 Apr 13 06:14 . drwxr-xr-x. 97 root root 12288 Apr 13 03:50 .. -rw-r--r--. 1 root root 527 Dec 13 22:50 abrt-action-save-package-data.conf -rw-r--r--. 1 root root 572 Dec 13 22:50 abrt.conf -rw-r--r--. 1 root root 175 Dec 13 22:50 gpg_keys drwxr-xr-x. 2 root root 4096 Apr 13 06:13 plugins [root@myhost~]# ls -la /etc/abrt/plugins/ total 12 drwxr-xr-x. 2 root root 4096 Apr 13 06:13 . drwxr-xr-x. 3 root root 4096 Apr 13 06:14 .. -rw-r--r--. 1 root root 278 Dec 13 22:50 CCpp.conf Actually all of those conf files above are only a few lines and do not mention anything about mail, email, or notifications.

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  • NFS-Root not working when booting over PXE

    - by Randy
    I am desperately trying to get a diskless client running over PXE-Boot using a NFS-Share as a root file system. I did this before some years ago but for some reason I am stucked at this since days. The TFTP-Server itself is running fine and booting a netinstaller works also fine. The kernel and initrd are loaded also but the bootprocess stops with this (screenshot) kernel panic. I'm using the squeeze standard i386-Kernel and I have prepared the initrd with this config: MODULES=most BUSYBOX=y KEYMAP=n COMPRESS=gzip BOOT=nfs DEVICE= NFSROOT=auto I also tried MODULES=netboot with the same outcome. My PXE-configuration looks like this: LABEL linux KERNEL diskless/debian-default/vmlinuz-2.6.32-5-686 APPEND root=/dev/nfs initrd=diskless/debian-default/vmlinuz-2.6.32-5-686 nfsroot=192.168.140.2:/storage/nfs-boot-images/default-squeeze ip=dhcp rw Furthermore I have captured the network communication of the client via tcpdump and learned that the client isn't even trying to connect to the NFS-share. Does anybody has got an idea what is going wrong here?

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  • public key infrastructure - distribute bad root certificates

    - by iamrohitbanga
    Suppose a hacker launches a new Linux distro with firefox provided with it. Now a browser contains the certificates of the root certification authorities of PKI. Because firefox is a free browser anyone can package it with fake root certificates. Can this be used to authenticate some websites. How? Many existing linux distros are mirrored by people. They can easily package software containing certificates that can lead to such attacks. Is the above possible? Has such an attack taken place before?

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  • SUDO YUM not found

    - by ThomasReggi
    I am running a Amazon ec2 instance on amazon's linux. Whenever I run anything sudo yum it give me this: sudo: yum: command not found ec2-user$ rpm -qf /usr/bin/yum yum-3.2.29-30.24.amzn1.noarch ec2-user$ which yum /usr/bin/yum which yum while in root gives: root$ which yum /usr/bin/which: no yum in (/sbin:/bin:/usr/sbin:/usr/bn:/usr/local/bin:/opt/aws/bin) This is a new ec2 instance two days old. When I first logged in I ran sudo yum update and everything wen't well. What changed?

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  • Cannot WMI Query root\MSCluster namespace as Local Admin

    - by Matt Zuberko
    I'm trying to use WMI Explorer to query the root\MSCluster namespace on various hosts to obtain cluster resource group and resource object data. I can access the namespace with no issue on Win2K3 cluster nodes but am getting an access denied error attempting to connect to Win2K8 and Win2K8R2 nodes. I can access the root\cimv2 namespace with no issue, just the MSCluster namespace even though I am a local Admin. Is there a feature setting, local security policy or server role I have to be a member of to access the namespace? Thank you!

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  • NTFS-3G is only mounting external drives as read-only

    - by Phanto
    I'm currently running RHEL 5.5, and I installed the ntfs-3g utility from here: http://www.tuxera.com/community/ntfs-3g-download/. I have also followed their instructions for auto-mounting NTFS USB drives here: http://www.tuxera.com/community/ntfs-3g-faq/#plugandplay. The problem I'm experiencing is that ntfs-3g is automatically mounting as root. In order for me to obtain write support, I need to navigate to the mounted device as root, and perform write actions with elevated privileges. Is there a way to mount USB NTFS volumes automatically without needing to sudo every write command? Thanks!

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  • MySQL can't access root account or reset with mysqladmin

    - by glumptious
    So if I type mysql -u root I'm supposedly logged in, however upon trying to create or access a database I get this lovely error: ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'test1'. I haven't the foggiest idea why after logging in as root it's trying access DB's as ''@'localhost' and it's driving me a bit crazy right now. Possibly related, when I try to set the root password I get the error mysqladmin: Can't turn off logging; error: 'Access denied; you need (at least one of) the SUPER privilege(s) for this operation'. I've tried removing mysql-server via running apt-get purge mysql-server and then reinstalling with no luck. This is running Ubuntu Server 12.10 64-bit and mysql is indeed running. --Edit-- I wonder if perhaps there is no root user. So I try to start MySQL with --skip-grant-tables and the create the root user but then I'm given this: ERROR 1290 (HY000): The MySQL server is running with the --skip-grant-tables option so it cannot execute this statement. Fun fun fun fun fun.

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  • Problem with building tree bottom up

    - by Esmond
    Hi, I have problems building a binary tree from the bottom up. THe input of the tree would be internal nodes of the trees with the children of this node being the leaves of the eventual tree. So initially if the tree is empty the root would be the first internal node. Afterwards, The next internal node to be added would be the new root(NR), with the old root(OR) being one of the child of NR. And so on. The problem i have is that whenever i add a NR, the children of the OR seems to be lost when i do a inOrder traversal. This is proven to be the case when i do a getSize() call which returns the same number of nodes before and after addNode(Tree,Node) Any help with resolving this problem is appreciated edited with the inclusion of node class code. both tree and node classes have the addChild methods because i'm not very sure where to put them for it to be appropriated. any comments on this would be appreciated too. The code is as follows: import java.util.*; public class Tree { Node root; int size; public Tree() { root = null; } public Tree(Node root) { this.root = root; } public static void setChild(Node parent, Node child, double weight) throws ItemNotFoundException { if (parent.child1 != null && parent.child2 != null) { throw new ItemNotFoundException("This Node already has 2 children"); } else if (parent.child1 != null) { parent.child2 = child; child.parent = parent; parent.c2Weight = weight; } else { parent.child1 = child; child.parent = parent; parent.c1Weight = weight; } } public static void setChild1(Node parent, Node child) { parent.child1 = child; child.parent = parent; } public static void setChild2(Node parent, Node child) { parent.child2 = child; child.parent = parent; } public static Tree addNode(Tree tree, Node node) throws ItemNotFoundException { Tree tree1; if (tree.root == null) { tree.root = node; } else if (tree.root.getSeq().equals(node.getChild1().getSeq()) || tree.root.getSeq().equals(node.getChild2().getSeq())) { Node oldRoot = tree.root; oldRoot.setParent(node); tree.root = node; } else { //form a disjoint tree and merge the 2 trees tree1 = new Tree(node); tree = mergeTree(tree, tree1); } System.out.print("addNode2 = "); if(tree.root != null ) { Tree.inOrder(tree.root); } System.out.println(); return tree; } public static Tree mergeTree(Tree tree, Tree tree1) { String root = "root"; Node node = new Node(root); tree.root.setParent(node); tree1.root.setParent(node); tree.root = node; return tree; } public static int getSize(Node root) { if (root != null) { return 1 + getSize(root.child1) + getSize(root.child2); } else { return 0; } } public static boolean isEmpty(Tree Tree) { return Tree.root == null; } public static void inOrder(Node root) { if (root != null) { inOrder(root.child1); System.out.print(root.sequence + " "); inOrder(root.child2); } } } public class Node { Node child1; Node child2; Node parent; double c1Weight; double c2Weight; String sequence; boolean isInternal; public Node(String seq) { sequence = seq; child1 = null; c1Weight = 0; child2 = null; c2Weight = 0; parent = null; isInternal = false; } public boolean hasChild() { if (this.child1 == null && this.child2 == null) { this.isInternal = false; return isInternal; } else { this.isInternal = true; return isInternal; } } public String getSeq() throws ItemNotFoundException { if (this.sequence == null) { throw new ItemNotFoundException("No such node"); } else { return this.sequence; } } public void setChild(Node child, double weight) throws ItemNotFoundException { if (this.child1 != null && this.child2 != null) { throw new ItemNotFoundException("This Node already has 2 children"); } else if (this.child1 != null) { this.child2 = child; this.c2Weight = weight; } else { this.child1 = child; this.c1Weight = weight; } } public static void setChild1(Node parent, Node child) { parent.child1 = child; child.parent = parent; } public static void setChild2(Node parent, Node child) { parent.child2 = child; child.parent = parent; } public void setParent(Node parent){ this.parent = parent; } public Node getParent() throws ItemNotFoundException { if (this.parent == null) { throw new ItemNotFoundException("This Node has no parent"); } else { return this.parent; } } public Node getChild1() throws ItemNotFoundException { if (this.child1 == null) { throw new ItemNotFoundException("There is no child1"); } else { return this.child1; } } public Node getChild2() throws ItemNotFoundException { if (this.child2 == null) { throw new ItemNotFoundException("There is no child2"); } else { return this.child2; } } }

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  • Running cronjob in the odd-numbered days

    - by Spacedust
    I'm currently running my MySQL backup script on every day of the week: 0 1 * * 1 sh /root/mysql_monday.sh 0 1 * * 2 sh /root/mysql_tuesday.sh 0 1 * * 3 sh /root/mysql_wednesday.sh 0 1 * * 4 sh /root/mysql_thursday.sh 0 1 * * 5 sh /root/mysql_friday.sh 0 1 * * 6 sh /root/mysql_saturday.sh 0 1 * * 0 sh /root/mysql_sunday.sh Now I would like to keep backups for one week more so two weeks in total just to be more secure. For example: I though I can create one backup file on monday in the even days and then again in the odd-numbered days. For even days I can just use: 0 1 */2 * 1 sh /root/mysql_monday_even.sh 0 1 */2 * 2 sh /root/mysql_tuesday_even.sh 0 1 */2 * 3 sh /root/mysql_wednesday_even.sh 0 1 */2 * 4 sh /root/mysql_thursday_even.sh 0 1 */2 * 5 sh /root/mysql_friday_even.sh 0 1 */2 * 6 sh /root/mysql_saturday_even.sh 0 1 */2 * 0 sh /root/mysql_sunday_even.sh But what about the odd-numbered days ?

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  • Unmounted root partition

    - by Jack
    My server running Debian lenny has just had a power cut recently and its come back up with the root partition in read only mode. I tried to remount the filesystem in read write mode with mount -n -o remount,rw / which then gave the output mount: block device /dev/hda1 is write-protected, mounting read-only. But now the root filesystem isn't mounted at all so I can't run anything to mount the partition again or any other command for that matter such as shutdown because /bin/ isn't there. Is there anything I can do remotely?

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  • Installing MoinMoin -wiki to my user directory on a server with no root access

    - by deiga
    Hello all, I posted this on webapps, but they told me to come here :) I've been trying to install MoinMoin -wiki on this webserver, where I have no root access. The server doesn't support wsgi, but it does support cgi/fcgi/etc. I've scoured google for a simple guide on how to accomplish this, but the only guides I found were from the year 2004 or so. Other guides always assumed that one has root access. So can anyone link a good tutorial for my question or just help me out here? Your help is appreciated :) P.S. Sorry if this is the wrong stack -page

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  • LUKS-Encrypted Root Partition in Ubuntu 9.04

    - by Martindale
    I have a LUKS-encrypted root partition that I have installed Ubuntu 9.04 to. I have of course placed /boot on a separate ext2 partition, and my boot loader loads and functions correctly. However, I can't seem to get my initrd to load the LUKS-encrypted root using the appropriate /dev/mapper/ address. What hooks and scripts do I need to add to get this to function correctly, and what is the correct way to regenerate my initrd? I can CHROOT into this install, and everything works fine - but I just can't seem to get it to actually boot. Help!

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  • How to resize root LVM partition in Fedora without LiveCD or Rebooting

    - by Cerin
    I have a virtual machine that recently had its disk image increased from 20GB to 50GB, and fdisk -l verifies that the VM can see this new size. Now I need to resize my root LVM partition to fill the extra 30GB. I've found several articles about resizing LVM, but the few that cover resizing the root partition all claim you need to boot from a LiveCD. Is there any way to do this without taking down the server? The server is critical, so I'd like to minimize downtime.

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  • PHP-FPM runs PHP scripts as root

    - by fwalch
    I have a web server setup using nginx and PHP-FPM listening on a Unix socket. In my php-fpm.conf, I have specified user = www group = www When I run ps aux, I can see that the php-fpm worker processes run as www; the php-fpm master process runs as root. However, I noticed that PHP scripts are executed as root; at least that's the output of echo get_current_user(); What can I do to run scripts as the www user? How can this even happen if the worker processes run as www?

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  • reset root password in mysql without access to mysql table

    - by Rik89
    I am having an issue on OS X 10.7.5 as I used to use MAMP but for .htaccess issues I am now using my own compiled local server from a long time ago, the problem is i forgot the root password for mysql. I have tried updating the password through terminal using mysql -u root, but I get this error message - ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) Thanks Ric

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • Linux Directory Access Problem: Permission Denied """In Root"""

    - by RBA
    Hi, When login through root on HP-tru Unix server, I am trying to access a directory, it is saying "Permission Denied".. Also, an sh file is also not able to execute through same root access.. I have checked the permission of the directory as well as for sh file through ls-ltr.. It is also fine.. Root System rwx-rwx-rwx-- What could be the possible cause, and how to correct it.. Thanks.

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  • Our server hosting provider asked for our root password

    - by Andreas Larsson
    I work at a company that develops and hosts a small business critical system. We have an "Elastic cloud server" from a professional hosting provider. I recently got an email from them saying that they've had some problems with their backup solution and that they needed to install a new kernel. And they wanted us to send them the root password so they could do this work. I know that the email came from them. It's not [email protected] or anything like that. I called them and asked them about this, and they were like "yep, we need the password to do this". It just seems odd to send the root password over email like this. Do I have any reason to be concerned?

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  • can i use hadoop cloudera without root access?

    - by in_the_cloud
    a bit of a binary question (okay, not excatly) - but was wondering if one is able to configure cloudera / hadoop to run at the nodes without root shell access to the node computers (although i can setup ssh passwordless login)? appears from their instructions that root access is needed, at yet i found a hadoop wiki which suggest root access might not be needed ? http://wiki.apache.org/nutch/NutchHadoopTutorial

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  • .htaccess redirect root directory and subpages with parameters

    - by wali
    I am having difficulty trying to redirect a root directory while at the same time redirect pages in a sub directory to a different URL. For example: http://test.example.com/olddir/sub/page.php?v=one to http://test.example.com/new/one while also redirecting the any request to the root of the olddir folder. I have tried RewriteCond %{QUERY_STRING} v=one RewriteRule ^/olddir/sub/page.php /new/? [R=301] and RedirectMatch /oldir "test.example.com" RedirectMatch /olddir/sub/page.php?v=one "test.example.com/new/one" Any help at this point will be extremely appreciated...Thanks!

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  • Technical non-terminating condition in a loop

    - by Snarfblam
    Most of us know that a loop should not have a non-terminating condition. For example, this C# loop has a non-terminating condition: any even value of i. This is an obvious logic error. void CountByTwosStartingAt(byte i) { // If i is even, it never exceeds 254 for(; i < 255; i += 2) { Console.WriteLine(i); } } Sometimes there are edge cases that are extremely unlikeley, but technically constitute non-exiting conditions (stack overflows and out-of-memory errors aside). Suppose you have a function that counts the number of sequential zeros in a stream: int CountZeros(Stream s) { int total = 0; while(s.ReadByte() == 0) total++; return total; } Now, suppose you feed it this thing: class InfiniteEmptyStream:Stream { // ... Other members ... public override int Read(byte[] buffer, int offset, int count) { Array.Clear(buffer, offset, count); // Output zeros return count; // Never returns -1 (end of stream) } } Or more realistically, maybe a stream that returns data from external hardware, which in certain cases might return lots of zeros (such as a game controller sitting on your desk). Either way we have an infinite loop. This particular non-terminating condition stands out, but sometimes they don't. A completely real-world example as in an app I'm writing. An endless stream of zeros will be deserialized into infinite "empty" objects (until the collection class or GC throws an exception because I've exceeded two billion items). But this would be a completely unexpected circumstance (considering my data source). How important is it to have absolutely no non-terminating conditions? How much does this affect "robustness?" Does it matter if they are only "theoretically" non-terminating (is it okay if an exception represents an implicit terminating condition)? Does it matter whether the app is commercial? If it is publicly distributed? Does it matter if the problematic code is in no way accessible through a public interface/API? Edit: One of the primary concerns I have is unforseen logic errors that can create the non-terminating condition. If, as a rule, you ensure there are no non-terminating conditions, you can identify or handle these logic errors more gracefully, but is it worth it? And when? This is a concern orthogonal to trust.

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