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• Expanded securityadmin

  - by user80652

  I'm aware that sysadmin is documented as the server role necessary for creating logins (SQL/Windows-integrated); nevertheless, I'm tasked to find out if there's any other server role (built-in or otherwise) that can be used. To be specific, I'm looking to setup one or two logins with access to create logins, create [database] users, assign users to [database] roles. Potentially reset passwords, but most of the logins are Windows-integrated and it's not necessary. Cannot have access to data at all, nor can these logins have rights to update tables nor create/update roles. Seems my only options so far are to set these 2 logins with securityadmin server role and for the specific databases, configure with db_securityadmin and db_accessadmin... but this configuration doesn't allow for creating logins.

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• Stringly typed values table in sql, is there a better way to do this? (we're using MSSQL)

  - by Jason Hernandez

  We have have a table layout with property names in one table, and values in a second table, and items in a third. (Yes, we're re-implementing tables in SQL.) We join all three to get a value of a property for a specific item. Unfortunately the values can have multiple data types double, varchar, bit, etc. Currently the consensus is to stringly type all the values and store the type name in the column next to the value. tblValues DataTypeName nvarchar Is there a better, cleaner way to do this?

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• Count, inner join

  - by Urosh

  I have two tables: DRIVER (Driver_Id,First name,Last name,...) PARTICIPANT IN CAR ACCIDENT (Participant_Id,Driver_Id-foreign key,responsibility-yes or no,...) Now, I need to find out which driver participated in accident where responsibility is 'YES', and how many times. I did this: Select Driver_ID, COUNT (Participant.Driver_ID)as 'Number of accidents' from Participant in car accident where responsibility='YES' group by Driver_ID order by COUNT (Participant.Driver_ID) desc But, I need to add drivers first and last name from the first table(using inner join, I suppose). I don't know how, because it is not contained in either an aggregate function or the GROUP BY clause. Please help :)

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• Quicktabs with AJAX Views

  - by Primus202

  I'm working in Drupal 7 with the quicktabs and views modules. I have a great looking tabbed set of tables filled with data. However, despite all the views having AJAX turned on, trying to do a column sort (or use the pager I imagine though currently there is not enough content to require one) causes the page to reload with a new URL instead of simply reloading the view in question. I found on Drupal some fixes for this problem but all seem to be in Drupal 6. Anyone have a patch for 7?

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• Please help me out in fetching the desired result from below given DB table structure of MySQL..

  - by OM The Eternity

  Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

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• Select products with users

  - by Ploppe

  I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

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• Oracle Sql: how to substract rows from one table from another only once

  - by slyder07

  I'm working for a university project, and I have the following question: I have 2 tables in a Oracle DB... I need to select those rows from table1, which are not included in table2... But the main problem is that I need to exclude that rows from table2 wich was selected once... For example: Table1 Table2 ResultTable id | Number | Letter id | Number | Letter id | Number | Letter _____________________ _____________________ _____________________ 1 4 S 1 6 G 2 2 P 2 2 P 2 8 B 3 5 B 3 5 B 3 4 S 4 4 S 4 4 S 4 1 A 6 2 P 5 1 A 5 1 H 6 2 P 6 2 X So, how you see it, if one row from Table1 has a "twin" in Table2, they both are excluded. Hope I was explicit enough. Sorry for my bad English. Thanks.

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• How to display a border-bottom only if table cells are not empty (CSS)

  - by Polarpro

  Hey there, I've got a Filemaker calculation that generates an HTML page with several tables. If the calculation results in values for certain fields the result would be <table> <tr><td>Example value 1</td></tr> <tr><td>Example value 2</td></tr> ... </table> If the calculation finds no values to be displayed, the result would simply be <table> </table> In the first case, I want to the table to display a border at the bottom (or any other horizontal line); in the second case, I don't want to display a border at the bottom. I cannot find a way to get this done using a CSS... Thanks in adavance :-)

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• How do i use SQL Server 2008? With Visual Studios?

  - by acidzombie24

  Its a two part question. How do i use SQL Server 2008? With Visual Studios? I started up a dummy project and with server explorer i tried with create new sql server database and add connection using my computer name (it came from a dropdown) as the server location. When i tried to create the database 'TestDB1' i got an error. I dont understand why. Its a fresh install and i have restarted the comp a few times since then. I havent messed with visual studios or the servers or even the control options to disable anything that would have been automatic. So whats with this? -edit- My goals are 1) create a database. 2) Be able to see all the database that exist on the server 3) execute sql queries in the ide 4) be able to browse tables. I dont need all of these but as many possible would be nice.

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• Traversing ORM relationships returns duplicate results

  - by NKing253

  I have 4 tables -- store, catalog_galleries, catalog_images, and catalog_financials. When I traverse the relationship from store --> catalog_galleries --> catalog_images in other words: store.getCatalogGallery().getCatalogImages() I get duplicate records. Does anyone know what could be the cause of this? Any suggestions on where to look? The store table has a OneToOne relationship with catalog_galleries which in turn has a OneToMany relationship with catalog_images and an eager fetch type. The store table also has a OneToMany relationship with catalog_financials.

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• Should I split this model and table?

  - by regedarek

  I would like to create simple ResumeBank app. Issue: As user I would like to add only two Resumes. Forms for this both Resumes are different with only two fields. Resumes have 12 the same attributes but 2 are diferent. Question: Should I split that Resume model and tables to ex: PolishResume and EnglishResume, polish_remsumes and english_remsumes? Or maybe should I use STI and create PolishResume < Resume and use one table. What are disadvantages of splitting option?

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• Concurrency handling

  - by Lijo

  Hi, Suppose, I am about to start a project using ASP.NET and SQL Server 2005. I have to design the concurrency requirement for this application. I am planning to add a TimeStamp column in each table. While updating the tables I will check that the TimeStamp column is same, as it was selected. Will this approach be suffice? Or is there any shortcomings for this approach under any circumstances? Please advice. Thanks Lijo

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• Oracle: Difference in execution plans between databases

  - by Will

  Hello, I am comparing queries my development and production database. They are both Oracle 9i, but almost every single query has a completely different execution plan depending on the database. All tables/indexes are the same, but the dev database has about 1/10th the rows for each table. On production, the query execution plan it picks for most queries is different from development, and the cost is somtimes 1000x higher. Queries on production also seem to be not using the correct indexes for queries in some cases (full table access). I have ran dbms_utility.analyze schema on both databases recently as well in the hopes the CBO would figure something out. Is there some other underlying oracle configuration that could be causing this? I am a developer mostly so this kind of DBA analysis is fairly confusing at first..

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• error defining foreign key PhpMyAdmin

  - by Ngounou lassale

  I am new to PhpMyAdmin. I will like to create a foreign key for my tables. In fact i have create tableI with this structures(A as int(11) autoincrement, B as varchar) TableII ( A_2 as int(11) auto increment, B_2 as varchar, A as int(11). I have declared A as an index in tableII, now when i go to relationship view to precise A as a foreign key i always have this error Erreur lors de la création de la clé étrangère sur ID_Ville (vérifiez le type des colonnes) Erreur ALTER TABLE tb_quartier ADD FOREIGN KEY ( ID_Ville ) REFERENCES ingenieris2.tb_ville ( ID_Ville ) ON DELETE RESTRICT ; Please Help thanks!

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• PHP Booking timeslot

  - by boyee007

  Im developing a php booking system based on timeslot for daily basis. Ive set up 4 database tables! Bookslot (which store all the ids - id_bookslot, id_user, id_timeslot) Timeslot (store all the times on 15 minutes gap ex: 09:00, 09:15, 09:30, etc) Therapist (store all therapist details) User (store all the members detail) ID_BOOKSLOT ID_USER ID_THERAPIST ID_TIMESLOT 1 10 1 1 (09:00) 2 11 2 1 (09:00) 3 12 3 2 (09:15) 4 15 3 1 (09:00) Now, my issue is, it keep showing repeation for timeslot when i want echoing the data for example: thera a thera b thera c ------------------------------------------------- 09:00 BOOKED available available 09:00 available BOOKED available 09:00 available available BOOKED 09:15 available BOOKED available as you can see, 09:00 showing three times, and i want something like below thera a thera b thera c ------------------------------------------------- 09:00 BOOKED BOOKED BOOKED 09:15 available BOOKED available There might be something wrong with joining the table or else. The code to join the table $mysqli->query("SELECT * FROM bookslot RIGHT JOIN timeslot ON bookslot.id_timeslot = timeslot.id_timeslot LEFT JOIN therapist ON bookslot.id_therapist = therapist.id_therapist" if anyone have the solution for this system, please help me out and i appriciate it much!

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• how to join on varchar(32) and binary(16) columns in sybase?

  - by Paul Sanwald

  I want to join two tables on a UUID. table A's UUID is represented as varchar(32). table B's UUID is represented as binary(16). what's the best way to join a varchar to a binary column? I've tried using some sybase functions for this, but I'm getting different results and unsure of why: select hextobigint('0x000036ca4c4c11d88b8dcd1344cdb512') 3948051912944290701 select convert(bigint,0x000036ca4c4c11d88b8dcd1344cdb512) -2877434794219274240 what am I missing about convert and hextobigint? I must be misundstanding at least one of these functions. thanks for your help!

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• many-to-many relationship in CI (not using ORM)

  - by Ross

  I'm implementing a categories system in my CI app and trying to work out the best way of working with many to many relationships. I'm not using an ORM at this stage, but could use say Doctrine if necessary. Each entry may have multiple categories. I have three tables (simplified) Entries: entryID, entryName Categories: categoryID, categoryname Entry_Category: entryID, categoryID my CI code returns a record set like this: entryID, entryName, categoryID, categoryName but, as expected with Many-to-Many relationships, each "entry" is repeated for each "category". What would the best way to "group" the categories so that when I output the results, I am left with something like: Entry Name Appears in Category: Foo, Bar rather than: Entry Name Appears in Category: Foo Entry Name Appears in Category: Bar I believe the option is to track if the post ID matches a previous entry, and if so, store the respective category, and output it as one, rather than several, but am unsure of how to do this in CI. thanks for any pointers (I appreciate this is may be a vague/complex question without a better knowledge of the system).

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• MySQL: Select remaining rows

  - by Bjork24

  I've searched everywhere for this, but I can't seem to find a solution. Perhaps I'm using the wrong terms. Either way, I'm turning to good ol' trusty S.O. to help my find the answer. I have two tables, we'll call them 'tools' and 'installs' tools = id, name, version installs = id, tool_id, user_id The 'tools' table records available tools, which are then installed by a user and recorded in the 'installs' table. Selecting the installed tools are simple enough: SELECT tools.name FROM tools LEFT JOIN installs ON tools.id = installs.tool_id WHERE user_id = 99 ; How do I select the remaining tools -- the ones that have yet to be installed by user #99? I'm sorry if this is painfully obvious, but I just can't seem to figure it out! Thanks for the help!

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• PHP "You have () new comments on your clip", how?

  - by user292516

  Hello. I want to do a function to my users, so on index.php there is e.g: You have 2 new comments on your clip How should i do this? I mean i want ideas to do this the easiest way. Table for the videos is member_videos, and tables for the comment is member_videocomments, a comment inside the table is connected by their "videoID", which is the id of the column in member_videos. Should i do the classic, making a field, which all is 0, until it has been seen by the user its 1 or what should i do.

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• Show the specific field on mysql table based on active date

  - by mrjimoy_05

  Suppose that I have 3 tables: A) Table UsrHeader ----------------- UsrID | UsrName ----------------- 1 | Abc 2 | Bcd B) Table UsrDetail ------------------------------- UsrID | UsrLoc | Date ------------------------------- 1 | LocA | 10 Aug 2012 1 | LocB | 15 Aug 2012 2 | LocA | 10 Aug 2012 C) Table Trx ----------------------------- TrxID | TrxDate | UsrID ----------------------------- 1 | 10 Aug 2012 | 1 2 | 16 Aug 2012 | 1 3 | 11 Aug 2012 | 2 What I want to do is to show the table like: --------------------------------------- TrxID | TrxDate | UsrID | UsrLoc --------------------------------------- 1 | 10 Aug 2012 | 1 | LocA 2 | 16 Aug 2012 | 1 | LocB 3 | 11 Aug 2012 | 2 | LocA Notice that there is one user but different location. That's based on the UsrDetail table that the user on a specified date has moved to another location. So, it should be show the user specific location on that date on every transaction. I have try this code but it is no luck: SELECT trx.TrxID, trx.TrxDate, trx.UsrID, User.UsrName, User.UsrLoc FROM trx INNER JOIN ( SELECT UsrHeader.UsrID, UsrHeader.UsrName, UserDetail.UsrLoc FROM UsrHeader INNER JOIN ( SELECT UsrDetail.UsrID, UsrDetail.UsrLoc, UsrDetail.Date FROM UsrDetail ) AS UserDetail ON UserDetail.UsrID = UsrHeader.UsrID ) AS User ON User.UsrID = trx.UsrID AND trx.TrxDate >= User.Date How to do that? Thanks..

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• Delete rows out of table that is innerjoined and unioned with 2 others

  - by jonathan

  We have 3 tables (table1, table2, table3), and I need to delete all the rows from table1 that have the same ID in table2 OR table3. To see a list of all of these rows I have this code: ( select table2.ID, table2.name_first, table2.name_last, table2.Collected from table2 inner join table1 on table1.ID = table2.ID where table2.Collected = 'Y' ) union ( select table3.ID, table3.name_first, table3.name_last, table3.Collected from table3 inner join table1 on table1.ID = table3.ID where table3.Collected = 'Y' ) I get back about 200 rows. How do I delete them from table1? I don't have a way to test if my query will work, so I'm nervous about modifying something I found online and potentially deleting data (we do have backups, but I'd rather not test out their integrity). TIA!

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• MySQL query to find the most popular value in a column joined by another value in a second table

  - by Budove

  I have two tables: users: user_id, user_zip settings: user_id, pref_ex_loc I need to find the single most popular 'pref_ex_loc' from the settings table based on a particular user_zip, which will be specified as the variable $userzip. Here is the query that I have now and obviously it doesn't work. $popularexloc = "SELECT pref_ex_loc, user_id COUNT(pref_ex_loc) AS countloc FROM settings FULL OUTER JOIN users ON settings.user_id = users.user_id WHERE users.user_zip='$userzip' GROUP BY settings.pref_ex_loc ORDER BY countloc LIMIT 1"; $popexloc = mysql_query($popularexloc) or die('SQL Error :: '.mysql_error()); $exlocrow = mysql_fetch_array($popexloc); $mostpopexloc=$exlocrow[0]; echo '<option value="'.$mostpopexloc.'">'.$mostpopexloc.'</option>'; What am I doing wrong here? I'm not getting any kind of error from this either.

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• Normalization two types of customers into one table

  - by JDewzy

  I am trying to model a sales situation where you can sell to a person or to a business with a contact person. I cannot figure out the proper way to do this. It seems like 2 tables would be incorrect. But how do I model a Customer table that can be a business or a person? Would I just have a boolean for "business" and an additional "business_name" field that would default to Null. But then I have to do an if/then on the columns and that seems like poor design. Any advice, direction, or links is appreciated.

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• Reading input from a text file, omits the first and adds a nonsense value to the end?

  - by Greenhouse Gases

  Hi there When I input locations from a txt file I am getting a peculiar error where it seems to miss off the first entry, yet add a garbage entry to the end of the link list (it is designed to take the name, latitude and longitude for each location you will notice). I imagine this to be an issue with where it starts collecting the inputs and where it stops but I cant find the error!! It reads the first line correctly but then skips to the next before adding it because during testing for the bug it had no record of the first location Lisbon though whilst stepping into the method call it was reading it. Very bizarre but hopefully someone knows the issue. Here is firstly my header file: #include <string> struct locationNode { char nodeCityName [35]; double nodeLati; double nodeLongi; locationNode* Next; void CorrectCase() // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = this->nodeCityName[0], letVal; int n = 1; // variable for name index from second letter onwards if((this->nodeCityName[0] >90) && (this->nodeCityName[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter this->nodeCityName[0] = firstLetVal; } while(n <= MAX_SIZE - 1) { if((this->nodeCityName[n] >= 65) && (this->nodeCityName[n] <= 90)) { letVal = this->nodeCityName[n] + 32; this->nodeCityName[n] = letVal; } n++; } //cityNameInput = this->nodeCityName; } }; class Locations { private: int size; public: Locations(){ }; // constructor for the class locationNode* Head; //int Add(locationNode* Item); }; And here is the file containing main: // U08221.cpp : main project file. #include "stdafx.h" #include "Locations.h" #include <iostream> #include <string> #include <fstream> using namespace std; int n = 0,x, locationCount = 0, MAX_SIZE = 35; string cityNameInput; char targetCity[35]; bool acceptedInput = false, userInputReq = true, match = false, nodeExists = false;// note: addLocation(), set to true to enable user input as opposed to txt file locationNode *start_ptr = NULL; // pointer to first entry in the list locationNode *temp, *temp2; // Part is a pointer to a new locationNode we can assign changing value followed by a call to Add locationNode *seek, *bridge; void setElementsNull(char cityParam[]) { int y=0, count =0; while(cityParam[y] != NULL) { y++; } while(y < MAX_SIZE) { cityParam[y] = NULL; y++; } } void addLocation() { temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it if(!userInputReq) // bool that determines whether user input is required in adding the node to the list { cout << endl << "Enter the name of the location: "; cin >> temp->nodeCityName; temp->CorrectCase(); setElementsNull(temp->nodeCityName); cout << endl << "Please enter the latitude value for this location: "; cin >> temp->nodeLati; cout << endl << "Please enter the longitude value for this location: "; cin >> temp->nodeLongi; cout << endl; } temp->Next = NULL; //set to NULL as when one is added it is currently the last in the list and so can not point to the next if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list if(!userInputReq){ cout << "Location sucessfully added to the database! There are " << locationCount << " location(s) stored" << endl; } } void populateList(){ ifstream inputFile; inputFile.open ("locations.txt", ios::in); userInputReq = true; temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it do { inputFile.get(temp->nodeCityName, 35, ' '); setElementsNull(temp->nodeCityName); inputFile >> temp->nodeLati; inputFile >> temp->nodeLongi; setElementsNull(temp->nodeCityName); if(temp->nodeCityName[0] == 10) //remove linefeed from input { for(int i = 0; temp->nodeCityName[i] != NULL; i++) { temp->nodeCityName[i] = temp->nodeCityName[i + 1]; } } addLocation(); } while(!inputFile.eof()); userInputReq = false; cout << "Successful!" << endl << "List contains: " << locationCount << " entries" << endl; cout << endl; inputFile.close(); } bool nodeExistTest(char targetCity[]) // see if entry is present in the database { match = false; seek = start_ptr; int letters = 0, letters2 = 0, x = 0, y = 0; while(targetCity[y] != NULL) { letters2++; y++; } while(x <= locationCount) // locationCount is number of entries currently in list { y=0, letters = 0; while(seek->nodeCityName[y] != NULL) // count letters in the current name { letters++; y++; } if(letters == letters2) // same amount of letters in the name { y = 0; while(y <= letters) // compare each letter against one another { if(targetCity[y] == seek->nodeCityName[y]) { match = true; y++; } else { match = false; y = letters + 1; // no match, terminate comparison } } } if(match) { x = locationCount + 1; //found match so terminate loop } else{ if(seek->Next != NULL) { bridge = seek; seek = seek->Next; x++; } else { x = locationCount + 1; // end of list so terminate loop } } } return match; } void deleteRecord() // complete this { int junction = 0; locationNode *place; cout << "Enter the name of the city you wish to remove" << endl; cin >> targetCity; setElementsNull(targetCity); if(nodeExistTest(targetCity)) //if this node does exist { if(seek == start_ptr) // if it is the first in the list { junction = 1; } if(seek != start_ptr && seek->Next == NULL) // if it is last in the list { junction = 2; } switch(junction) // will alter list accordingly dependant on where the searched for link is { case 1: start_ptr = start_ptr->Next; delete seek; --locationCount; break; case 2: place = seek; seek = bridge; delete place; --locationCount; break; default: bridge->Next = seek->Next; delete seek; --locationCount; break; } } else { cout << targetCity << "That entry does not currently exist" << endl << endl << endl; } } void searchDatabase() { char choice; cout << "Enter search term..." << endl; cin >> targetCity; if(nodeExistTest(targetCity)) { cout << "Entry: " << endl << endl; } else { cout << "Sorry, that city is not currently present in the list." << endl << "Would you like to add this city now Y/N?" << endl; cin >> choice; /*while(choice != ('Y' || 'N')) { cout << "Please enter a valid choice..." << endl; cin >> choice; }*/ switch(choice) { case 'Y': addLocation(); break; case 'N': break; default : cout << "Invalid choice" << endl; break; } } } void printDatabase() { temp = start_ptr; // set temp to the start of the list do { if (temp == NULL) { cout << "You have reached the end of the database" << endl; } else { // Display details for what temp points to at that stage cout << "Location : " << temp->nodeCityName << endl; cout << "Latitude : " << temp->nodeLati << endl; cout << "Longitude : " << temp->nodeLongi << endl; cout << endl; // Move on to next locationNode if one exists temp = temp->Next; } } while (temp != NULL); } void nameValidation(string name) { n = 0; // start from first letter x = name.size(); while(!acceptedInput) { if((name[n] >= 65) && (name[n] <= 122)) // is in the range of letters { while(n <= x - 1) { while((name[n] >=91) && (name[n] <=97)) // ERROR!! { cout << "Please enter a valid city name" << endl; cin >> name; } n++; } } else { cout << "Please enter a valid city name" << endl; cin >> name; } if(n <= x - 1) { acceptedInput = true; } } cityNameInput = name; } int main(array<System::String ^> ^args) { //main contains test calls to functions at present cout << "Populating list..."; populateList(); printDatabase(); deleteRecord(); printDatabase(); cin >> cityNameInput; } The text file contains this (ignore the names, they are just for testing!!): Lisbon 45 47 Fattah 45 47 Darius 42 49 Peter 45 27 Sarah 85 97 Michelle 45 47 John 25 67 Colin 35 87 Shiron 40 57 George 34 45 Sean 22 33 The output omits Lisbon, but adds on a garbage entry with nonsense values. Any ideas why? Thank you in advance.

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• SQL SERVER – World Shapefile Download and Upload to Database – Spatial Database

  - by pinaldave

  During my recent, training I was asked by a student if I know a place where he can download spatial files for all the countries around the world, as well as if there is a way to upload shape files to a database. Here is a quick tutorial for it. VDS Technologies has all the spatial files for every location for free. You can download the spatial file from here. If you cannot find the spatial file you are looking for, please leave a comment here, and I will send you the necessary details. Unzip the file to a folder and it will have the following content. Then, download Shape2SQL tool from SharpGIS. This is one of the best tools available to convert shapefiles to SQL tables. Afterwards, run the .exe file. When the file is run for the first time, it will ask for the database properties. Provide your database details. Select the appropriate shape files and the tool will fill up the essential details automatically. If you do not want to create the index on the column, uncheck the box beside it. The screenshot below is simply explains the procedure. You also have to be careful regarding your data, whether that is GEOMETRY or GEOGRAPHY. In this example,  it is GEOMETRY data. Click “Upload to Database”. It will show you the uploading process. Once the shape file is uploaded, close the application and open SQL Server Management Studio (SSMS). Run the following code in SSMS Query Editor. USE Spatial GO SELECT * FROM dbo.world GO This will show the complete map of world after you click on Spatial Results in Spatial Tab. In Spatial Results Set, the Zoom feature is available. From the Select label column, choose the country name in order to show the country name overlaying the country borders. Let me know if this tutorial is helpful enough. I am planning to write a few more posts about this later. Note: Please note that the images displayed here do not reflect the original political boundaries. These data are pretty old and can probably draw incorrect maps as well. I have personally spotted several parts of the map where some countries are located a little bit inaccurately. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Add-On, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Spatial, SQL Tips and Tricks, SQL Utility, T SQL, Technology

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