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  • Count numbers in words.

    - by bachchan
    I need an assembler 8080 software which counts words (delimited by space) which have more than two number in it. Example : this sh0uld b3 l1ke th1s would print : 0 words but Example : this sh0uld b3 l1k3 th1s f000k would print : 2 words <- word l1k3 contain number 1,3 and f000k number 0,0,0 the output should be displayer in hexadecimal format (optional)

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  • Logic: Best way to sample & count bytes of a 100MB+ file

    - by Jami
    Let's say I have this 170mb file (roughly 180 million bytes). What I need to do is to create a table that lists: all 4096 byte combinations found [column 'bytes'], and the number of times each byte combination appeared in it [column 'occurrences'] Assume two things: I can save data very fast, but I can update my saved data very slow. How should I sample the file and save the needed information? Here're some suggestions that are (extremely) slow: Go through each 4096 byte combinations in the file, save each data, but search the table first for existing combinations and update it's values. this is unbelievably slow Go through each 4096 byte combinations in the file, save until 1 million rows of data in a temporary table. Go through that table and fix the entries (combine repeating byte combinations), then copy to the big table. Repeat going through another 1 million rows of data and repeat the process. this is faster by a bit, but still unbelievably slow This is kind of like taking the statistics of the file. NOTE: I know that sampling the file can generate tons of data (around 22Gb from experience), and I know that any solution posted would take a bit of time to finish. I need the most efficient saving process

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  • Inventory count in CakePHP

    - by metrobalderas
    We are developing an inventory tracking system. Basically we've got an order table in which orders are placed. When an order is payed, the status changes from 0 to 1. This table has multiple children in another table order_items. This is the main structure. CREATE TABLE order( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, user_id INT UNSIGNED, status INT(1), total INT UNSIGNED ); CREATE TABLE order_items( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, order_id INT UNSIGNED, article_id INT UNSIGNED, size enum('s', 'm', 'l', 'xl'), quantity INT UNSIGNED ); Now, we've got a stocks table with similar architecture for the acquisitions. This is the structure. CREATE TABLE stock( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, article_id INT UNSIGNED ); CREATE TABLE stock_items( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, stock_id INT UNSIGNED, size enum('s', 'm', 'l', 'xl'), quantity INT(2) ); The main difference is that stocks has no status field. What we are looking for is a way to sum each article size from stock_items, then sum each article size from order_items where Order.status = 1 and substract both these items to find our current inventory. This is the table we want to get from a single query: Size | Stocks | Sales | Available s | 10 | 3 | 7 m | 15 | 13 | 2 l | 7 | 4 | 3 Initially we thought abouth using complex find conditions, but perhaps that's the wrong approach. Also, since it's not a direct join, it turns out to be quite hard. This is the code we have to retrieve the stock's total for each item. function stocks_total($id){ $find = $this->StockItem->find('all', array( 'conditions' => array( 'StockItem.stock_id' => $this->find('list', array('conditions' => array('Stock.article_id' => $id))) ), 'fields' => array_merge( array( 'SUM(StockItem.cantidad) as total' ), array_keys($this->StockItem->_schema) ), 'group' => 'StockItem.size', 'order' => 'FIELD(StockItem.size, \'s\', \'m\' ,\'l\' ,\'xl\') ASC' )); return $find; } Thanks.

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  • MySQL Query to get count of unique values?

    - by RD
    Hits Table: hid | lid | IP 1 | 1 | 123.123.123.123 2 | 1 | 123.123.123.123 3 | 2 | 123.123.123.123 4 | 2 | 123.123.123.123 5 | 2 | 123.123.123.124 6 | 2 | 123.123.123.124 7 | 3 | 123.123.123.124 8 | 3 | 123.123.123.124 9 | 3 | 123.123.123.124 As you can see, there following are the unique hits for the various lid: lid 1: 1 unique hit lid 2: 2 unique hits lid 3: 1 unique hit So basically, I need a query that will return the following: lid | uhits | 1 | 1 | 2 | 2 | 3 | 1 | Anybody know how to get that?

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  • Getting the System tick count with basic C++?

    - by Donal Rafferty
    I essentially want to reconstruct the getTickCount() windows function so I can use it in basic C++ without any non standard libraries or even the STL. (So it complies with the libraries supplied with the Android NDK) I have looked at clock() localtime time But I'm still unsure whether it is possible to replicate the getTickCount windows function with the time library. Can anyone point me in the right direction as to how to do this or even if its possible?

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  • I can't Distinct, Sum, or Count from 3 tables with group clauses

    - by Rio Inggit Dharmawangsa
    I'm still learning linq, now i'm getting confused. I need data for report from 3 tables, I get the result, but it's duplicate. I have used distinct but it's not working, n I need data to be sum still not working. Here is my query, can somebody explain what's wrong? var report= (from u in myDb.TBL_TRANSAKSI_MKN_MNMs.AsEnumerable() where u.TGL_TRANSAKSI.Value.Date.Equals(dateTimePicker1.Value.Date) join l in myDb.TBL_DETAIL_TRANSAKSIs.AsEnumerable() on u.ID_NOTA equals l.ID_NOTA join m in myDb.TBL_MKN_MNMs.AsEnumerable() on l.ID_MKN_MNM equals m.ID_MKN_MNM group new { u, l, m } by new { m.NAMA_MKN_MNM, m.HARGA_JUAL, u.TGL_TRANSAKSI, l.ID_MKN_MNM, u.USERNAME, l.Jumlah } into grp select new { MakanMinum = grp.Key.NAMA_MKN_MNM, HargaJual = grp.Key.HARGA_JUAL, Stok = grp.Sum(groupedthing => groupedthing.l.Jumlah), Tanggal = grp.Key.TGL_TRANSAKSI, Jumlah =(grp.Key.HARGA_JUAL * grp.Sum(groupedthing => groupedthing.l.Jumlah)), Total = grp.Sum(grouptotal => grp.Key.HARGA_JUAL * grp.Sum(groupedthing => groupedthing.l.Jumlah)), Username = grp.Key.USERNAME }).Distinct();

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  • PHP Count the lenght of each value in a array/string (tags)

    - by 2by
    Users writing an article have the option to write some tags, tags are written like this: tag1, tag2, tag3 So tags are stored like: $tags = "tag1, tag2, tag3"; I want to make sure, every tag has a minimum of 3 characters, so i need to validate the tags. I have tried this: $tagsstring = explode(",", $tags); $tagslength = array_map('strlen', $tagsstring); if (min($tagslength) < 3) { echo "Error... Each tag has to be at least 3 characters."; } It seems to work, sometimes... But of you write: tag1, df It wont give an error. Any suggestions?

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  • MySQL query with 2 COUNT() of other tables with where conditions

    - by Isern Palaus
    Hello, I've a table called sports that contains a list of list of sports, other called seasons that contains the seasons for a specific sport and competitions that have the competitions of a specific sport and season. I need one MySQL query to print the list of sports with how much seasons and competitions has each. My tables structure: sports +--------------------+------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------------+------------------+------+-----+---------+----------------+ | id | int(10) unsigned | NO | PRI | NULL | auto_increment | | name | varchar(32) | NO | | NULL | | | slug | varchar(45) | NO | | NULL | | | description | varchar(128) | NO | | NULL | | +--------------------+------------------+------+-----+---------+----------------+ seasons +--------------------+------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------------+------------------+------+-----+---------+----------------+ | id | int(10) unsigned | NO | PRI | NULL | auto_increment | | id_sport | int(10) unsigned | NO | MUL | NULL | | | name | varchar(32) | NO | | NULL | | | slug | varchar(32) | NO | | NULL | | +--------------------+------------------+------+-----+---------+----------------+ competitions +--------------------+------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------------+------------------+------+-----+---------+----------------+ | id | int(10) unsigned | NO | PRI | NULL | auto_increment | | id_season | int(10) unsigned | NO | MUL | NULL | | | name | varchar(32) | NO | | NULL | | | slug | varchar(64) | NO | | NULL | | | description | varchar(128) | YES | | NULL | | +--------------------+------------------+------+-----+---------+----------------+ The result of my query needs to contain: sports.*, total_seasons (SUM of seasons where seasons.id_sport=sports.id) and total_competitions (SUM of competitions where competitions.id_season=seasons.id AND seasons.id_sport=sports.id). Thank you in advance!

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  • Rails 3 ActiveRecord group_by sort by count

    - by Craig
    The following view code generates a series of links with totals (as expected): <% @jobs.group_by(&:employer_name).sort.each do |employer, jobs| %> <%= link_to employer, jobs_path() %> <%= "(#{jobs.length})" %> <% end %> However, when I refactor the view's code and move the logic to a helper, the code doesn't work as expect. view: <%= employer_filter(@jobs_clone) %> helper: def employer_filter(jobs) jobs.group_by(&:employer_name).sort.each do |employer,jobs| link_to employer, jobs_path() end end The following output is generated: <Job:0x10342e628>#<Job:0x10342e588>#<Job:0x10342e2e0>Employer A#<Job:0x10342e1c8>Employer B#<Job:0x10342e0d8>Employer C#<Job:0x10342ded0>Employer D# What am I not understanding? At first blush, the code seems to be equivalent.

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  • count specific things within a code in c++

    - by shap
    can anyone help me make this more generalised and more pro? #include <fstream> #include <iostream> #include <string> #include <vector> using namespace std; int main() { // open text file for input: string file_name; cout << "please enter file name: "; cin >> file_name; // associate the input file stream with a text file ifstream infile(file_name.c_str()); // error checking for a valid filename if ( !infile ) { cerr << "Unable to open file " << file_name << " -- quitting!\n"; return( -1 ); } else cout << "\n"; // some data structures to perform the function vector<string> lines_of_text; string textline; // read in text file, line by while (getline( infile, textline, '\n' )) { // add the new element to the vector lines_of_text.push_back( textline ); // print the 'back' vector element - see the STL documentation cout << lines_of_text.back() << "\n"; } cout<<"OUTPUT BEGINS HERE: "<<endl<<endl; cout<<"the total capacity of vector: lines_of_text is: "<<lines_of_text.capacity()<<endl; int PLOC = (lines_of_text.size()+1); int numbComments =0; int numbClasses =0; cout<<"\nThe total number of physical lines of code is: "<<PLOC<<endl; for (int i=0; i<(PLOC-1); i++) //reads through each part of the vector string line-by-line and triggers if the //it registers the "//" which will output a number lower than 100 (since no line is 100 char long and if the function does not //register that character within the string, it outputs a public status constant that is found in the class string and has a huge value //alot more than 100. { string temp(lines_of_text [i]); if (temp.find("//")<100) numbComments +=1; } cout<<"The total number of comment lines is: "<<numbComments<<endl; for (int j=0; j<(PLOC-1); j++) { string temp(lines_of_text [j]); if (temp.find("};")<100) numbClasses +=1; } cout<<"The total number of classes is: "<<numbClasses<<endl;

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  • Count double palindromes in given int sequence

    - by jakubmal
    For a given int sequence check number of double palindromes, where by double palindrome we mean sequence of two same palindromes without break between them. So for example: in 1 0 1 1 0 1 we have 1 0 1 as a palindrome which appears 2 times without a break, in 1 0 1 5 1 0 1 we have 1 0 1 but it's separated (apart from the other palindromes in these sequences) Problem example test data is: 3 12 0 1 1 0 0 1 1 0 0 1 1 0 12 1 0 1 0 1 0 1 0 1 0 1 0 6 3 3 3 3 3 3 with answers 8 0 9 Manacher is obvious for the begging, but I'm not sure what to do next. Any ideas appreciated. Complexity should be below n^2 I guess. EDIT: int is here treated as single element of alphabet

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  • SQL - sub count

    - by Andy Clarke
    Hi I've got some SQL ... SELECT AdviceNo, Registration FROM tblSalesDetail that produces something like ... ADV00001, ABC123 ADV00001, CDE564 ADV00002, FGE432 ADV00003, HUY789 ADV00003, MJS532 ADV00003, JFY428 Can anyone tell me how I'd adjust it to see the following please? ADV00001, ABC123, 1 ADV00001, CDE564, 2 ADV00002, FGE432, 1 ADV00003, HUY789, 1 ADV00003, MJS532, 2 ADV00003, JFY428, 3

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  • Rails 3 Order By Count on has_many :through

    - by goo
    I have an application where I can list Items and add tags to each Item. The models Items and Tags are associated like this: class Item < ActiveRecord::Base has_many :taggings has_many :tags, :through => :taggings end class Tagging < ActiveRecord::Base belongs_to :item belongs_to :tag end class Tag < ActiveRecord::Base has_many :taggings has_many :items, :through => :taggings end So, this many-to-many relationship allows me to set n tags for each Item, and the same tag can be used several times. I'd like to list all tags ordered by the number of items associated with this tag. More used tags, shows first. Less used, last. How can I do that? Regards.

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  • how to use google analytics to count clicks on a button

    - by vfix
    Hi everyone, I have google analytics on my site. One page has a button which when pressed executes some javascript. It would be nice to monitor the number of hits the button receives when people come to this page. Can anybody suggest the easiest way to achieve this with google analytics ? Are there any best practices to do this ? thanks

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  • php - How do I count occurences of items in an array

    - by Steven
    take this array: Array ( [#twitterwhites] => 0 [#lufc] => 0 [#FOOTBALL] => 0 [#Liverpool] => 0 [#liverpool] => 0 [#ESPN] => 0 [#LUFC] => 0 [#cafc] => 0 [#cafc] => 0 [#ocra] => 0 [#nra] => 0 [#2nd] => 0 [#secondamendment] => 0 [#SCR] => 0 [#TC500] => 0 [#cpfc] => 0 [#MOT] => 0 ) I want to return a result like this: #liverpool = 2 #cafc = 2 #LUFC = 1 ETC ETC How do I do it?

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  • why can't I call methods on a for-yield expression?

    - by 1984isnotamanual
    Say I have some scala code like this: // outputs 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 println( squares ) def squares = { val s = for ( count <- 1 to 10 ) yield { count * count } s.mkString(", "); } Why do I have to use the temporary val s? I tried this: def squares = for ( count <- 1 to 10 ) yield { count * count }.mkString(", ") That fails to compile with this error message: error: value mkString is not a member of Int def squares = for ( count <- 1 to 10 ) yield { count * count }.mkString(", ") Shouldn't mkString be called on the collection returned by the for loop?

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  • Calculations on the iteration count in for loop in Ruby 1.8.7

    - by user1805035
    I was playing around with Ruby and Latex to create a color coding set. I'm more than a novice with C++, but haven't looked at Ruby until now. So, still learning a lot of coding. I have the following block of code below. When attempting to run this, band1 = 1e+02. I've tried band1 = (BigDecimal(i) * 100).to_f thinking maybe there was some odd floating point issue. This is just me trying anything though as an integer multiplied by an integer should create an integer, if I'm still thinking correctly. I've tried a variety of other things as well (things that I can do in C++, but this ain't C++), but to no avail. (1..9).each do |i| #Band 1 (0..9).each do |j| #Band 2 (0..11).each do |k| #Band 3 #Band 3 Start #these are the colors of the resistor bands b1 = $c_band12[i] b2 = $c_band12[j] b3 = $c_band3[k] b4 = "Gold" oms = ((i*100) + (j*10)) * $mult[k] band1 = i*100 band2 = j band3 = $mult[k] end end end Not sure what I'm missing. Should I be using .each_with_index through these iterations? I've tried this: (1..9).each_with_index {|i, indexi| #Band 1 (0..9).each_with_index {|j, indexj| #Band 2 (0..11).each_with_index {|k, indexk| #Band 3 #Band 3 Start #these are the colors of the resistor bands b1 = $c_band12[i] b2 = $c_band12[j] b3 = $c_band3[k] b4 = "Gold" oms = ((i*100) + (j*10)) * $mult[k] band1 = indexk * 100 and I get the same answer. I can't see why 1*100 should equate to such a large number? Thank you, AT

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  • Determining child count of path

    - by sqlnewbie
    I have a table whose 'path' column has values and I would like to update the table's 'child_count' column so that I get the following output. path | child_count --------+------------- | 5 /a | 3 /a/a | 0 /a/b | 1 /a/b/c | 0 /b | 0 My present solution - which is way too inefficient - uses a stored procedure as follows: CREATE FUNCTION child_count() RETURNS VOID AS $$ DECLARE parent VARCHAR; BEGIN FOR parent IN SELECT path FROM my_table LOOP DECLARE tokens VARCHAR[] := REGEXP_SPLIT_TO_ARRAY(parent, '/'); str VARCHAR := ''; BEGIN FOR i IN 2..ARRAY_LENGTH(tokens, 1) LOOP UPDATE my_table SET child_count = child_count + 1 WHERE path = str; str := str || '/' || tokens[i]; END LOOP; END; END LOOP; END; $$ LANGUAGE plpgsql; Anyone knows of a single UPDATE statement that does the same thing?

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  • Count if with two criteria excel vba

    - by Manasa J
    can some one help me create a macro for the following Data.The values in GradeA,GradeB etc.. columns need to be populated by checking sheet1 ColumnB(Student Name) and columnH(Grade).I need both row wise and Column wise total. Student GradeA GradeB GradeC GradeD GradeE GrandTotal Std1 1 0 2 0 0 3 Std2 0 0 0 1 1 2 Std3 1 0 1 0 0 2 Std4 0 2 0 3 0 5 Std5 0 1 2 1 0 4 Std6 1 0 2 0 2 5 Grnd 3 3 7 5 3 21

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