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  • How can I write an excel formula to do row based calculations; where certain conditions need to be met?

    - by BDY
    I am given: An excel sheet contains around 200 tasks (described in rows 2-201 in Column A). Each task can be elegible for a max of two projects (There are 4 projects in total, called "P1-P4" - drop down lists in Columns B and D); and this with a specific %-rate allocation (columns C & E - Column C refers to the Project Column B, and Column E refers to the Project in Column D). Column F shows the amount of work days spent on each task. Example in row 2: Task 1 (Column A); P1 (Column B) ; 80% (Column C) ; P3 (Column D) ; 20% (Column E) ; 3 (Column F) I need to know the sum of the working days spent on Project P3 respecting the %-rate for elegibility. I know how to calculate it for each Task (each Row) - e.g. for Task 1: =IF(B2="P3";C2*F2)+IF(D2="P3";E2*F2) However instead of repeating this for each task, I need a formula that adds them all together. Unfortunately the following formula shows me an error: =IF(B2:B201="P3";C2:C201*F2:F201)+IF(D2:D201="P3";E2:E201*F2:F201) Can anyone help please? Thank you!!

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  • Goldtouch USB Keyboard reverses keystrokes in fast typing -- expected?

    - by Justin Grant
    I am running into an odd keyboard problem: some key combinations end up reversed (e.g. "pl" ends up being emitted as "lp") when I'm typing quickly. The problematic ones are the key combos I hit with two adjacent fingers on my right hand-- in other words, the combos I can hit the fastest. No idea how fast is "fastest", but I guess around 50-150 msecs gap between them. I'm trying to track down whether this represents a failed keyboard, an inherent limitation of my Goldtouch USB keyboards, or a software problem on my Windows 7 Lenovo T500. I use a PS/2 version of the same Goldtouch keyboard at home with no problems. I've tried another USB keyboard with my laptop and can't repro the problem. I've also used this keyboard on other laptops without a problem. According to this SU thread, USB keyboards have higher latency than PS/2 keyboards-- up to 30 msecs. I find it hard to imagine that I can type key combos faster than 50 msecs, probably more like 100-150. Anyone encountered this problem with this or another keyboard? If so, how did you fix it? Any idea if there's a "keyboard log" or some way to diagnose the problem inside Windows?

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  • Website has become slower on a VPS, was much fast on a shared host. What's wrong?

    - by Arpit Tambi
    My shared host suspended my website stating system overload, so I moved my website to a VPS which has 4GB RAM. But for some reason the website has become very slow. This is the vmstat output - procs -----------memory---------- ---swap-- -----io---- --system-- -----cpu------ r b swpd free buff cache si so bi bo in cs us sy id wa st 1 0 0 3050500 0 0 0 0 0 1 0 0 0 0 100 0 0 Here's the Apache Benchmark output for a STATIC html page I ran on the server itself - Benchmarking www.ask-oracle.com (be patient)...apr_poll: The timeout specified has expired (70007) Total of 20 requests completed Update: Server Config: List item Centos 5.6 4 cores cpu 4 GB RAM LAMP stack with APC Wordpress Only one website It takes almost double time to load now, same website was much fast on shared hosting. I know I need to tweak some settings but have no clue where to start from? I have already tried to optimize apache, mysql etc. Update 2: CPU usage is low, see uptime output: 11:09:02 up 7 days, 21:26, 1 user, load average: 0.09, 0.11, 0.09 Update 3: When I load any webpage, browser shows "Waiting" for a long time and then page loads quickly. So I suspect server can accept only limited connections and holds extra connections in a waiting state. How to check this? Update 4: Following is the output on executing netperf TCP STREAM TEST from 0.0.0.0 (0.0.0.0) port 0 AF_INET to localhost.localdomain (127.0.0.1) port 0 AF_INET Recv Send Send Socket Socket Message Elapsed Size Size Size Time Throughput bytes bytes bytes secs. 10^6bits/sec 87380 16384 16384 10.00 9615.40 [root@ip-118-139-177-244 j3ngn5ri6r01t3]# Here are the Apache MPM settings from httpd.conf, do they look okay? <IfModule worker.c> StartServers 5 MaxClients 100 MinSpareThreads 50 MaxSpareThreads 250 ThreadsPerChild 125 MaxRequestsPerChild 10000 ServerLimit 100 </IfModule>

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  • Fast extraction of a time range from syslog logfile?

    - by mike
    I've got a logfile in the standard syslog format. It looks like this, except with hundreds of lines per second: Jan 11 07:48:46 blahblahblah... Jan 11 07:49:00 blahblahblah... Jan 11 07:50:13 blahblahblah... Jan 11 07:51:22 blahblahblah... Jan 11 07:58:04 blahblahblah... It doesn't roll at exactly midnight, but it'll never have more than two days in it. I often have to extract a timeslice from this file. I'd like to write a general-purpose script for this, that I can call like: $ timegrep 22:30-02:00 /logs/something.log ...and have it pull out the lines from 22:30, onward across the midnight boundary, until 2am the next day. There are a few caveats: I don't want to have to bother typing the date(s) on the command line, just the times. The program should be smart enough to figure them out. The log date format doesn't include the year, so it should guess based on the current year, but nonetheless do the right thing around New Year's Day. I want it to be fast -- it should use the fact that the lines are in order to seek around in the file and use a binary search. Before I spend a bunch of time writing this, does it already exist?

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  • Distinct Count of Customers in a SCD Type 2 in #DAX

    - by Marco Russo (SQLBI)
    If you have a Slowly Changing Dimension (SCD) Type 2 for your customer and you want to calculate the number of distinct customers that bought a product, you cannot use the simple formula: Customers := DISTINCTCOUNT( FactTable[Customer Id] ) ) because it would return the number of distinct versions of customers. What you really want to do is to calculate the number of distinct application keys of the customers, that could be a lower number than the number you’ve got with the previous formula. Assuming that a Customer Code column in the Customers dimension contains the application key, you should use the following DAX formula: Customers := COUNTROWS( SUMMARIZE( FactTable, Customers[Customer Code] ) ) Be careful: only the version above is really fast, because it is solved by xVelocity (formerly known as VertiPaq) engine. Other formulas involving nested calculations might be more complex and move computation to the formula engine, resulting in slower query. This is absolutely an interesting pattern and I have to say it’s a killer feature. Try to do the same in Multidimensional…

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  • Calculating for leap year [migrated]

    - by Bradley Bauer
    I've written this program using Java in Eclipse. I was able to utilize a formula I found that I explained in the commented out section. Using the for loop I can iterate through each month of the year, which I feel good about in that code, it seems clean and smooth to me. Maybe I could give the variables full names to make everything more readable but I'm just using the formula in its basic essence :) Well my problem is it doesn't calculate correctly for years like 2008... Leap Years. I know that if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) then we have a leap year. Maybe if the year is a leap year I need to subtract a certain amount of days from a certain month. Any solutions, or some direction would be great thanks :) package exercises; public class E28 { /* * Display the first days of each month * Enter the year * Enter first day of the year * * h = (q + (26 * (m + 1)) / 10 + k + k/4 + j/4 + 5j) % 7 * * h is the day of the week (0: Saturday, 1: Sunday ......) * q is the day of the month * m is the month (3: March 4: April.... January and Feburary are 13 and 14) * j is the century (year / 100) * k is the year of the century (year %100) * */ public static void main(String[] args) { java.util.Scanner input = new java.util.Scanner(System.in); System.out.print("Enter the year: "); int year = input.nextInt(); int j = year / 100; // Find century for formula int k = year % 100; // Find year of century for formula // Loop iterates 12 times. Guess why. for (int i = 1, m = i; i <= 12; i++) { // Make m = i. So loop processes formula once for each month if (m == 1 || m == 2) m += 12; // Formula requires that Jan and Feb are represented as 13 and 14 else m = i; // if not jan or feb, then set m to i int h = (1 + (26 * (m + 1)) / 10 + k + k/4 + j/4 + 5 * j) % 7; // Formula created by a really smart man somewhere // I let the control variable i steer the direction of the formual's m value String day; if (h == 0) day = "Saturday"; else if (h == 1) day = "Sunday"; else if (h == 2) day = "Monday"; else if (h == 3) day = "Tuesday"; else if (h == 4) day = "Wednesday"; else if (h == 5) day = "Thursday"; else day = "Friday"; switch (m) { case 13: System.out.println("January 1, " + year + " is " + day); break; case 14: System.out.println("Feburary 1, " + year + " is " + day); break; case 3: System.out.println("March 1, " + year + " is " + day); break; case 4: System.out.println("April 1, " + year + " is " + day); break; case 5: System.out.println("May 1, " + year + " is " + day); break; case 6: System.out.println("June 1, " + year + " is " + day); break; case 7: System.out.println("July 1, " + year + " is " + day); break; case 8: System.out.println("August 1, " + year + " is " + day); break; case 9: System.out.println("September 1, " + year + " is " + day); break; case 10: System.out.println("October 1, " + year + " is " + day); break; case 11: System.out.println("November 1, " + year + " is " + day); break; case 12: System.out.println("December 1, " + year + " is " + day); break; } } } }

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  • Thinking in DAX: Counting Products in the Current Status with PowerPivot

    - by AlbertoFerrari
    One of my readers came to me with an interesting formula to compute in PowerPivot. Even if I don’t normally post about very specific scenarios, I think this time it is interesting to write a blog post since the formula can be easily created, if you think at it in DAX, while it is very hard if you are still approaching it with an MDX or SQL mindset. Thinking in DAX is something that comes after a lot of formula authoring, something that all BI professionals should strive for, as Vertipaq in the new...(read more)

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  • formatting a column based on another columns cell TEXT not value in excel

    - by lisa
    I have dates that are running off a formula in that column based on information it is collecting from other worksheets. I have another column that lists text answers based on a different formula that that column is running. It is a customer list that runs with names going down page and multiple columns of information for each client running across page What i want to do is: If column j says "paid" then turn column m - same row - a color or border or something I will repeat this formula for the various things that j can say, just cant figure out how to make conditional formatting read j to change m. To complicate things, in addition to the formula running to collect the date in m, there is also a conditional format set up for m that changes the color of the cells after a certain date. I want to be able to keep that formula, in addition to the one that you are assisting with...i will use highlighting, or something different to avoid any conflicts.

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  • MySql ODBC connection in VB6 on WinXP VERY slow. Other machines on same network are fast.

    - by Matthew
    Hi All, I have a VB6 application that has been performing very well. Recently, we upgraded our server to a Windows 2003 server. Migration of the databases and shares went well and we experienced no problems. Except one. And it has happened at multiple sites. I use the MySQL ODBC 5.1 connector to point to my MySQL database. On identical machines (as far as I can tell, they are client machines not ours), access to the DB is lightning fast on all but one computer. They use the same software and have the same connection strings. And I'm sure it's not the program, but the ODBC connection. When I press the 'Test Connection' button in the ODBC connection string window, it can take up to 10 seconds on the poorly performing machine to respond with a success. All the other computers are instantaneous. I have tried using ip address versus the machine name in the UDL, no change. I enabled option 256, which sped it up initially, but it's slow again. Most of the time on a restart the program will be fast for an hour or so then go slow again with the option 256 enabled. Frankly, I am out of ideas and willing to entertain any and all ideas or suggestions. This is getting pretty frustrating. Anyone ever experience anything like this?

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  • Using jQuery delay() with separate elements

    - by boomturn
    I want to fake a simple animation on page load by sequentially revealing several pngs, each appearing instantly but with unique, precisely timed delay before the next one. Using the latest version of jQuery (1.4.2 at writing), which provides a delay method. My first (braindead) impulse was: $('#image1').show('fast').delay(800); $('#image2').show('fast').delay(1200); $('#image3').show('fast'); Of course all come up simultaneously. jQuery doc examples refer to a single item being chained, not handling multiple items. OK... try again using nested callbacks from show(): $('#image1').show('fast', function() { $('#image2').show('fast', function() { $('#image3').show('fast', function() { }); }); }); Looks ugly (imagine doing 10, also wonder what processor hit would be) but hey, it works sequentially! Without delay though. So... chain delay() after show() using a callback function from it (not even sure if it supports one): $('#image1').show('fast').delay(800, function() { $('#image2').show('fast').delay(1200, function() { $('#image3').show('fast'); }); }); Hm. Opposite result of what I thought might happen: the callback works, but still no delay. So... should I be using some combination of queue and delay instead of nested callbacks? jQuery doc examples for queue again only use one element for example. Guessing this would involve using a custom queue, but am uncertain how to implement this. Or maybe I'm missing a simple way? (For a simple problem!)

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  • jQuery - making sure content is loaded before it's faded in?

    - by Kenny Bones
    Hi, Nick Craver really helped me out alot with this code in this thread http://stackoverflow.com/questions/2743443/jquery-can-someone-help-stitching-jquery-code-with-ajaxcomplete/2743791#2743791 And it is working. But I notice that there's a small delay after I've clicked a link and before the content is actually loaded. It's not very intense content that's loaded either so I think it's got something to do with the order which things happen in the script. The original code looks like this: $('.dynload').live('click', function(){ var toLoad = $(this).attr('href')+' #content'; $('#content').fadeOut('fast',loadContent); $('#ajaxloader').fadeIn('normal'); function loadContent() { $('#content').load(toLoad,'',showNewContent()) } function showNewContent() { $('#content').fadeIn('fast',hideLoader()); //Cufon.replace('h1, h2, h3, h4, .menuwrapper', { fontFamily: 'advent'}); } function hideLoader() { $('#ajaxloader').fadeOut('normal'); } return false; }); The new code looks like this: $(function() { $('.dynload').live('click', function(){ $('#ajaxloader').fadeIn('fast'); $('#ajaxloaderfridge').fadeIn('fast'); var href = this.href + ' #content'; $('#content').fadeOut('fast',function() { $(this).load(href,'', function(data) { createMenus(); $('#ajaxloader').fadeOut('fast'); $('#ajaxloaderfridge').fadeOut('fast'); $('#content').fadeIn('fast'); Cufon.replace('h1, h2, h3, h4, .menuwrapper', { fontFamily: 'advent'}); }); }); return false; }); }); $(createMenus); function createMenus() { $('#kontrollpanel .slidepanels').kwicks({ min : 42, spacing : 3, isVertical : true, sticky : true, event : 'click' }); } In the original code, #content is faded out, then the function "loadContent" is started. Which is basically what is happening in the new script as well isn't it? And when I was using the old code, the content just faded out and faded in really fast and smooth and with no small pause delay before the content arrived.

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  • MongoDB vs. Redis vs. Cassandra for a fast-write, temporary row storage solution

    - by Mark Bao
    Hi there, I'm building a system that tracks and verifies ad impressions and clicks. This means that there are a lot of insert commands (about 90/second average, peaking at 250) and some read operations, but the focus is on performance and making it blazing-fast. The system is currently on MongoDB, but I've been introduced to Cassandra and Redis since then. Would it be a good idea to go to one of these two solutions, rather than stay on MongoDB? Why or why not? Thank you

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  • Fast ArgumentNullException with attributes. It is possible?

    - by Fraga
    Hi. Is there any fast way to verify null arguments via attributes or something? Convert this: public void Method(type arg1,type arg2,type arg3) { if (arg1== null) throw new ArgumentNullException("arg1"); if (arg2== null) throw new ArgumentNullException("arg2"); if (arg3== null) throw new ArgumentNullException("arg3"); //Business Logic } Into something like this: [VerifyNullArgument("arg1","arg2","arg3")] public void Method(type arg1,type arg2,type arg3) { //Business Logic } Ideas? thanks guys.

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  • How fast are EC/2 nodes between each other?

    - by tesmar
    Hi, I am looking to setup Amazon EC/2 nodes on rails with Riak. I am looking to be able to sync the riak DBs and if the cluster gets a query, to be able to tell where the data lies and retrieve it quickly. In your opinion(s), is EC/2 fast enough between nodes to query a Riak DB, return the results, and get them back to the client in a timely manner? I am new to all of this, so please be kind :)

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  • How can I represent a line of music notes in a way that allows fast insertion at any index?

    - by chairbender
    For "fun", and to learn functional programming, I'm developing a program in Clojure that does algorithmic composition using ideas from this theory of music called "Westergaardian Theory". It generates lines of music (where a line is just a single staff consisting of a sequence of notes, each with pitches and durations). It basically works like this: Start with a line consisting of three notes (the specifics of how these are chosen are not important). Randomly perform one of several "operations" on this line. The operation picks randomly from all pairs of adjacent notes that meet a certain criteria (for each pair, the criteria only depends on the pair and is independent of the other notes in the line). It inserts 1 or several notes (depending on the operation) between the chosen pair. Each operation has its own unique criteria. Continue randomly performing these operations on the line until the line is the desired length. The issue I've run into is that my implementation of this is quite slow, and I suspect it could be made faster. I'm new to Clojure and functional programming in general (though I'm experienced with OO), so I'm hoping someone with more experience can point out if I'm not thinking in a functional paradigm or missing out on some FP technique. My current implementation is that each line is a vector containing maps. Each map has a :note and a :dur. :note's value is a keyword representing a musical note like :A4 or :C#3. :dur's value is a fraction, representing the duration of the note (1 is a whole note, 1/4 is a quarter note, etc...). So, for example, a line representing the C major scale starting on C3 would look like this: [ {:note :C3 :dur 1} {:note :D3 :dur 1} {:note :E3 :dur 1} {:note :F3 :dur 1} {:note :G3 :dur 1} {:note :A4 :dur 1} {:note :B4 :dur 1} ] This is a problematic representation because there's not really a quick way to insert into an arbitrary index of a vector. But insertion is the most frequently performed operation on these lines. My current terrible function for inserting notes into a line basically splits the vector using subvec at the point of insertion, uses conj to join the first part + notes + last part, then uses flatten and vec to make them all be in a one-dimensional vector. For example if I want to insert C3 and D3 into the the C major scale at index 3 (where the F3 is), it would do this (I'll use the note name in place of the :note and :dur maps): (conj [C3 D3 E3] [C3 D3] [F3 G3 A4 B4]), which creates [C3 D3 E3 [C3 D3] [F3 G3 A4 B4]] (vec (flatten previous-vector)) which gives [C3 D3 E3 C3 D3 F3 G3 A4 B4] The run time of that is O(n), AFAIK. I'm looking for a way to make this insertion faster. I've searched for information on Clojure data structures that have fast insertion but haven't found anything that would work. I found "finger trees" but they only allow fast insertion at the start or end of the list. Edit: I split this into two questions. The other part is here.

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