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  • How do I use command line and wmctrl to make a window larger than the screen to get a huge screenshot?

    - by Mnebuerquo
    I use a program which makes a large image which I have to scroll to view. The program has no way to save the image, and I have no access to the source to modify it. The only way I have to get the image from the program is by screenshot. My goal is to save the full size image without having to piece together individual screenshots. I'm using this script to try taking a screenshot: #!/bin/bash window=$(wmctrl -l | grep "Program$" | awk '{print $1}') wmctrl -v -i -r $window -e '0,0,0,6030,5828' wmctrl -i -a $window import -window $window ~/Desktop/screenshot.png This uses wmctrl to get the window id ($window) for a window named "Program". It then tries to resize the window to the desired dimensions. It uses imagemagick (import) to save a screenshot.png on the user's Desktop. All of this works except the resize step. I can resize the window using wmctrl -r -e, but sizes greater than the screen size don't work. I'm using Ubuntu 10.04 and the Gnome Desktop. I run two monitors, but I've tried this with one of them disabled. Is there a way to resize the window larger than my screen to get a huge screenshot?

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  • How do I escape spaces in command line in Windows without using quotation marks?

    - by David
    For example what is the alternative to this command without quotation marks: CD "c:\Documents and Settings" The full reason I don't want to use quotation marks is that this command DOES work: SVN add mypathname\*.* but this command DOES NOT work : SVN add "mypathname\*.*" The problem being when I change mypathname for a path with spaces in it I need to quote the whole thing. For example: SVN add "c:\Documents and Settings\username\svn\*.*" But when I try this I get the following error message: svn: warning: 'c:\Documents and Settings\username\svn\*.*' not found

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  • Determine the architecture of a Mac from the command line or script?

    - by Brian Postow
    I'm writing a shell script, and I need to know the archetecture, ie PPC or Intel. Back in the day, there was a program /bin/arch that told you, but my mac doesn't seem to have it... Is there an easy way I can do this? Grep for something in a logfile? call some other program that spits that out as a side effect? It would be nice to know what OS Version I'm running too, but that may not be necessary. thanks

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  • Can a mapped network drive be reconnected from the command line?

    - by Stephen Jennings
    On a daily basis I find myself in the Windows command prompt needing to access a network drive that is mapped but disconnected. I have yet to find a command that will reconnect this drive without unmapping and remapping (which leads to a password guessing game, since I don't own these computers). I would also like to be able to script this so every night the drive is reconnected if it has become disconnected somehow. The fastest solution I currently have is to: Type "start." to open explorer, Alt-D to focus the address bar, type the drive letter I want and press enter, and wait for it to display the drive contents, then finally, close explorer and go back to the command prompt. I know it's a minor inconvenience, but I'm often doing this through a slow VNC or PCAnywhere connection where doing anything through GUI is awful, so I'm just wondering if there's a better solution.

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  • Programmatic, script-based, or command line method to change starting program for user on Windows Server 2000/2003?

    - by Joe Majsterski
    I have written an app that we want to distribute to a large number of customers to be used as the shell program when they log onto their server with a particular admin account. I have figured out how to change the starting program by going to Administrative Tools->Computer Management->System Tools->Local Users and Groups->Users, selecting the properties for the user, going to the Environment tab, and changing the program file name under "Starting program" to my new app. But is there a way I could do this with some code that could be sent out and run on all these servers?

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  • Is there a win32 command line tabifier that supports ... `read details` (revised)?

    - by user55542
    I use an editor that allows me to type in a command to run. In order to see the output without having to redirect it to a file, I precede the command with "cmd /k," which leaves an open cmd.exe window. So I'd like to find a way to catch the call to cmd.exe and pass it onto an application that tabifies cmd.exe, a terminal emulator as it's called. The desired result would be similar to what happens in a tabbed editor, when that editor is to open some file, it does so in another tab, and not in another window. While in a given situation it may be easier to modify the command to redirect output to display in the editor itself, in general it would be more helpful if I could find a way to catch all such calls into one window.

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  • chromium-browser --proxy-server debugging

    - by user3678068
    Many places online have pointed out to configure chromium proxy via command can be achieve with the following line chromium-browser --proxy-server=[username]:[password]@[host]:[port] but I got this result on every request. Here's the output in the command line right after executing the previous command. (They do not appear to be relevant. There are no new command line output when I try to visit a page) libGL error: failed to authenticate magic 30 libGL error: failed to load driver: vboxvideo ATTENTION: default value of option force_s3tc_enable overridden by environment. [29551:29551:0606/160459:ERROR:sandbox_linux.cc(268)] InitializeSandbox() called with multiple threads in process gpu-process I have double checked that the proxy credential works with the foxyproxy chrome plugin. What else can I try to figure this out? [Edit] Going to chrome://net-internals/#proxy and reading "Effective proxy settings" if I do chromium-browser with no flags, I get Use DIRECT connections. Source: GSETTINGS if chromium-browser --proxy-server=[host]:[port], I get a message box requesting to login, and under "Effective proxy settings": Proxy server: [host]:[port] if chromium-browser --proxy-server=[user]:[pass]@[host]:[port], "Effective proxy settings" shows: Use DIRECT connections

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  • For Programmers familiar with ACM API? Drawing Initials [closed]

    - by user71992
    Possible Duplicate: For Programmers familiar with ACM API? Drawing Initials I came across an exercise (in the book "The Art and Science of Java" by Eric Roberts) that requires using only GArc and GLine classes to create a lettering library which draws your initials on the canvas. This should be made independent of the GLabel class. I'd like to know the correct approach to use in solving this problem. I'm not sure what I have so far is good enough (I'm thinking it's too long). The questions requires that I use a good Top-Down approach. Here's my code so far: //Passes letters to GLetter objects and draws them on the canvas package artScienceJavaExercises.chapter8; import acm.program.*; //import acm.graphics.*; public class DrawInitials extends GraphicsProgram{ public void init(){ resize(400,400); } public void run(){ //String let = readLine("Letter?: "); letter = new GLetter("l"); add(letter, (getWidth()-letter.getWidth()*2)/2, (getHeight()-letter.getHeight())/2); add(new GLetter("o"), (letter.getX()+letter.getWidth()), letter.getY()); } private GLetter letter; } //GLetter Class package artScienceJavaExercises.chapter8; import acm.graphics.*; import java.awt.*; public class GLetter extends GCompound{ private static final int ONE_THIRD = 30; private static final int ROW_2_HEIGHT = 40; private GArc[] arc = new GArc[4]; private GLine[] line = new GLine[24]; public GLetter(String s){ line[0] = new GLine(0,0, ONE_THIRD, 0); line[1] = new GLine(ONE_THIRD,0, ONE_THIRD*2, 0); line[2] = new GLine(ONE_THIRD*2,0, ONE_THIRD*3, 0); line[3] = new GLine(0,0, 0,ONE_THIRD); line[4] = new GLine(ONE_THIRD,0, ONE_THIRD, ONE_THIRD); line[5] = new GLine(ONE_THIRD*2,0, ONE_THIRD*2, ONE_THIRD); line[6] = new GLine(ONE_THIRD*3,0, ONE_THIRD*3, ONE_THIRD); line[7] = new GLine(0,ONE_THIRD, ONE_THIRD*2, ONE_THIRD); line[8] = new GLine(ONE_THIRD,ONE_THIRD, ONE_THIRD*2, ONE_THIRD); line[9] = new GLine(ONE_THIRD*2,ONE_THIRD, ONE_THIRD*3, ONE_THIRD); line[10] = new GLine(0,ONE_THIRD, 0, ONE_THIRD+ROW_2_HEIGHT); line[11] = new GLine(ONE_THIRD, ONE_THIRD, ONE_THIRD, ONE_THIRD+ROW_2_HEIGHT); line[12] = new GLine(ONE_THIRD*2,ONE_THIRD, ONE_THIRD*2, ONE_THIRD+ROW_2_HEIGHT); line[13] = new GLine(ONE_THIRD*3,ONE_THIRD, ONE_THIRD*3, ONE_THIRD+ROW_2_HEIGHT); line[14] = new GLine(0, ONE_THIRD+ROW_2_HEIGHT, ONE_THIRD, ONE_THIRD+ROW_2_HEIGHT); line[15] = new GLine(ONE_THIRD, ONE_THIRD+ROW_2_HEIGHT, ONE_THIRD*2, ONE_THIRD+ROW_2_HEIGHT); line[16] = new GLine(ONE_THIRD*2, ONE_THIRD+ROW_2_HEIGHT, ONE_THIRD*3, ONE_THIRD+ROW_2_HEIGHT); line[17] = new GLine(0, ONE_THIRD+ROW_2_HEIGHT, 0, ONE_THIRD*2+ROW_2_HEIGHT); line[18] = new GLine(ONE_THIRD, ONE_THIRD+ROW_2_HEIGHT, ONE_THIRD, ONE_THIRD*2+ROW_2_HEIGHT); line[19] = new GLine(ONE_THIRD*2, ONE_THIRD+ROW_2_HEIGHT, ONE_THIRD*2, ONE_THIRD*2+ROW_2_HEIGHT); line[20] = new GLine(ONE_THIRD*3, ONE_THIRD+ROW_2_HEIGHT, ONE_THIRD*3, ONE_THIRD*2+ROW_2_HEIGHT); line[21] = new GLine(0,ONE_THIRD*2+ROW_2_HEIGHT, ONE_THIRD, ONE_THIRD*2+ROW_2_HEIGHT); line[22] = new GLine(ONE_THIRD, ONE_THIRD*2+ROW_2_HEIGHT, ONE_THIRD*2, ONE_THIRD*2+ROW_2_HEIGHT); line[23] = new GLine(ONE_THIRD*2,ONE_THIRD*2+ROW_2_HEIGHT, ONE_THIRD*3, ONE_THIRD*2+ROW_2_HEIGHT); for(int i = 0; i<line.length; i++){ add(line[i]); line[i].setColor(Color.BLACK); line[i].setVisible(false); } arc[0] = new GArc(getWidth(), getHeight(), 106.699, 49.341); arc[1] = new GArc(getWidth(), getHeight(), 23.96, 49.341); arc[2] = new GArc(getWidth(), getHeight(), -23.96, -49.341); arc[3] = new GArc(0,0,getWidth(), getHeight(), -106.699, -49.341); for(int i = 0; i<arc.length; i++){ add(arc[i],0,0); arc[i].setColor(Color.BLACK); arc[i].setVisible(false); } paintLetter(s); } private void paintLetter(String s){ if (s.equalsIgnoreCase("l")){ turnOn(line[3]); turnOn(line[10]); turnOn(line[17]); turnOn(line[21]); turnOn(line[22]); turnOn(line[23]); } else if(s.equalsIgnoreCase("o")){ for(int i = 0; i<4; ++i){ turnOn(arc[i]); } turnOn(line[1]); turnOn(line[10]); turnOn(line[13]); turnOn(line[22]); } } private void turnOn(GObject g){ g.setVisible(true); } } I created a class (GLetter.java) with arrays for GArc and GLine objects. They are positioned in certain ways thereby turning certain Glines and/or GArcs on or off (changing visiblity) would create a pattern for a letter. This Gletter uses the if/else statements to determine which pattern to create - this makes me feel my code is too long. There is another class (DrawInitials.java) that simulates a GraphicsProgram and allows the user to pass certain letters as arguments to the GLetter object. I've used 'L' and 'O' as examples. However, I posted this because I'm not sure I'm using the right approach. That's why I need your help. I feel MY CODE IS TOO LONG! The code above is not the complete project...it only draws letters 'L' and 'O' for now.

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  • How to get distance from point to line with distinction between side of line?

    - by tesselode
    I'm making a 2d racing game. I'm taking the nice standard approach of having a set of points defining the center of the track and detecting whether the car is off the track by detecting its distance from the nearest point. The nicest way I've found of doing this is using the formula: d = |Am + Bn + C| / sqrt(A^2 + B^2) Unfortunately, to have proper collision resolution, I need to know which side of the line the car is hitting, but I can't do that with this formula because it only returns positive numbers. So my question is: is there a formula that will give me positive or negative numbers based on which side of the line the point is on? Can I just get rid of the absolute value in the formula or do I need to do something else?

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  • What Scripting Program would you choose to recover deleted and missing files?

    - by Steven Graf
    For a private project I'm looking for a command line tool to scan and recover files. I'm working on Gnome 3 (but I could also change my OS if it helps reaching my goal) and must be able to find and recover files on attached devices with formats such as NTFS, Fat32, MAC OS Extended and ext3. Is there a command line script to cover all of them or do I need to use different programs to reach my goal? can you recommend command line tools for these kind of tasks? is one of you willing and able to show me some examples and teach me further?

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  • How to clean launch a GUI app via the Terminal (so it doesn't wait for termination)?

    - by Peter.O
    Some GUI apps launch cleanly via the Terminal command line. Some don't, and they cause the Terminal to wait for the app to terminate. ...and even then, some don't "release" the command line. The mysterious ampersand "&" suffix, seems to cause the terminal to put the process into the background... (but I'm not sure what happens there). Is there a way to launch an app via the Terminal, so that there is no "hang on" effect? ... just like launching something via F2. I'd like to have the command line available again, immediately (without something still in the background and writing out system message in the terminal).

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  • Formatting Dates, Times and Numbers in ASP.NET

    Formatting is the process of converting a variable from its native type into a string representation. Anytime you display a DateTime or numeric variables in an ASP.NET page, you are formatting that variable from its native type into some sort of string representation. How a DateTime or numeric variable is formatted depends on the culture settings and the format string. Because dates and numeric values are formatted differently across cultures, the .NET Framework bases its formatting on the specified culture settings. By default, the formatting routines use the culture settings defined on the web server, but you can indicate that a particular culture be used anytime you format. In addition to the culture settings, formatting is also affected by a format string, which spells out the formatting details to apply. The .NET Framework contains a bounty of format strings. There are standard format strings, which are typically a single letter that applies detailed formatting logic. For example, the "C" format specifier will format a numeric type as a currency value; the "Y" format specifier displays the month name and four-digit year of the specified DateTime value. There are also custom format strings, which display a apply a very specific formatting rule. These custom format strings can be put together to build more intricate formats. For instance, the format string "dddd, MMMM d" displays the full day of the week name followed by a comma followed by the full name of the month followed by the day of the month. For more involved formatting scenarios, where neither the standard or custom format strings cut the mustard, you can always create your own formatting extension methods. This article explores the standard format strings for dates, times and numbers and includes a number of custom formatting methods I've created and use in my own projects. There's also a demo application you can download that lets you specify a culture and then shows you the output for the standard format strings for the selected culture. Read on to learn more! Read More >

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  • SQL SERVER – Solution – Generating Zero Without using Any Numbers in T-SQL

    - by pinaldave
    SQL Server MVP and my friend My friend Madhivanan has asked very interesting question on his blog regarding How to Generate Zero without using Any Numbers in T-SQL. He has demonstrated various methods how one can generate Zero. When I posted note regarding how one he has generated Zero without using number in my blog post for Free Online Training, blog readers have come up with few very interesting answers. I really found them very interesting and here I am listing them with due credit. Special mention to Andery.ca as the answer Andery provided is the one, I myself come up with after very first look and that is why I had left the same as hint in the original article. anil try this select count(cast(null as int)) or any false condition select count(*) where ‘a’=’b’ Varinder Sandhu It seems every currency symbol that SQL Server supports. Return the same value as zero i tried some as select € select ¥ select £ Andrey.ca select count(*)-count(*) Vinay Kumar Another way for generate zero. select Ascii(‘Y’)-Ascii(‘Y’) OR select LEN(”) I like Madhivanan’s answer. and it was awesome. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, Readers Contribution, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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  • Fibonacci numbers in F#

    - by BobPalmer
    As you may have gathered from some of my previous posts, I've been spending some quality time at Project Euler.  Normally I do my solutions in C#, but since I have also started learning F#, it only made sense to switch over to F# to get my math coding fix. This week's post is just a small snippet - spefically, a simple function to return a fibonacci number given it's place in the sequence.  One popular example uses recursion: let rec fib n = if n < 2 then 1 else fib (n-2) + fib(n-1) While this is certainly elegant, the recursion is absolutely brutal on performance.  So I decided to spend a little time, and find an option that achieved the same functionality, but used a recursive function.  And since this is F#, I wanted to make sure I did it without the use of any mutable variables. Here's the solution I came up with: let rec fib n1 n2 c =    if c = 1 then        n2    else        fib n2 (n1+n2) (c-1);;let GetFib num =    (fib 1 1 num);;printfn "%A" (GetFib 1000);; Essentially, this function works through the sequence moving forward, passing the two most recent numbers and a counter to the recursive calls until it has achieved the desired number of iterations.  At that point, it returns the latest fibonacci number. Enjoy!

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  • PHP rand function (or not so rand)

    - by Badr Hari
    I was testing PHP rand function to write on a image. Of course the output shows that it's not so random. The code I used: <?php header('Content-Type: image/png'); $lenght = 512; $im = imagecreatetruecolor($lenght, $lenght); $blue = imagecolorallocate($im, 0, 255, 255); for ($y = 0; $y < $lenght; $y++) { for ($x = 0; $x < $lenght; $x++) { if (rand(0,1) == 0) { imagesetpixel($im, $x, $y, $blue); } } } imagepng($im); imagedestroy($im); ?> My question is, if I use image width/lenght (variable $lenght in this example) number like 512, 256 or 1024, it is very clear that it's not so random. When I change the variable to 513 for an example, it is so much harder for human eye to detect it. Why is that? What is so special about these numbers? 512: 513: Edit: I'm running xampp on Windows to test it.

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  • Circle-Line Collision Detection Problem

    - by jazzdawg
    I am currently developing a breakout clone and I have hit a roadblock in getting collision detection between a ball (circle) and a brick (convex polygon) working correctly. I am using a Circle-Line collision detection test where each line represents and edge on the convex polygon brick. For the majority of the time the Circle-Line test works properly and the points of collision are resolved correctly. Collision detection working correctly. However, occasionally my collision detection code returns false due to a negative discriminant when the ball is actually intersecting the brick. Collision detection failing. I am aware of the inefficiency with this method and I am using axis aligned bounding boxes to cut down on the number of bricks tested. My main concern is if there are any mathematical bugs in my code below. /* * from and to are points at the start and end of the convex polygons edge. * This function is called for every edge in the convex polygon until a * collision is detected. */ bool circleLineCollision(Vec2f from, Vec2f to) { Vec2f lFrom, lTo, lLine; Vec2f line, normal; Vec2f intersectPt1, intersectPt2; float a, b, c, disc, sqrt_disc, u, v, nn, vn; bool one = false, two = false; // set line vectors lFrom = from - ball.circle.centre; // localised lTo = to - ball.circle.centre; // localised lLine = lFrom - lTo; // localised line = from - to; // calculate a, b & c values a = lLine.dot(lLine); b = 2 * (lLine.dot(lFrom)); c = (lFrom.dot(lFrom)) - (ball.circle.radius * ball.circle.radius); // discriminant disc = (b * b) - (4 * a * c); if (disc < 0.0f) { // no intersections return false; } else if (disc == 0.0f) { // one intersection u = -b / (2 * a); intersectPt1 = from + (lLine.scale(u)); one = pointOnLine(intersectPt1, from, to); if (!one) return false; return true; } else { // two intersections sqrt_disc = sqrt(disc); u = (-b + sqrt_disc) / (2 * a); v = (-b - sqrt_disc) / (2 * a); intersectPt1 = from + (lLine.scale(u)); intersectPt2 = from + (lLine.scale(v)); one = pointOnLine(intersectPt1, from, to); two = pointOnLine(intersectPt2, from, to); if (!one && !two) return false; return true; } } bool pointOnLine(Vec2f p, Vec2f from, Vec2f to) { if (p.x >= min(from.x, to.x) && p.x <= max(from.x, to.x) && p.y >= min(from.y, to.y) && p.y <= max(from.y, to.y)) return true; return false; }

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  • Finding maximum number of congruent numbers

    - by Stefan Czarnecki
    Let's say we have a multiset (set with possible duplicates) of integers. We would like to find the size of the largest subset of the multiset such that all numbers in the subset are congruent to each other modulo some m 1. For example: 1 4 7 7 8 10 for m = 2 the subsets are: (1, 7, 7) and (4, 8, 10), both having size 3. for m = 3 the subsets are: (1, 4, 7, 7, 10) and (8), the larger set of size 5. for m = 4 the subsets are: (1), (4, 8), (7, 7), (10), the largest set of size 2. At this moment it is evident that the best answer is 5 for m = 3. Given m we can find the size of the largest subset in linear time. Because the answer is always equal or larger than half of the size of the set, it is enough to check for values of m upto median of the set. Also I noticed it is necessary to check for only prime values of m. However if values in the set are large the algorithm is still rather slow. Does anyone have any ideas how to improve it?

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  • Permission denied error when trying to install with wubi

    - by badri
    I run into problem when tried to install Ubuntu 11.04 on Windows 7 using wubi installer . It downloads the image for sometime and ends up with the error that says Permission denied: for more details see the log file In the log it seems to be like DownloadError: Problem connecting to tracker - urlopen error (10060, 'Operation timed out') but my network is good and I checked it. Tried using wubi several times, but ends up with same problem. Log content: 10-08 16:56 DEBUG TaskList: ### Finished get_metalink 10-08 16:56 DEBUG TaskList: New task download 10-08 16:56 DEBUG TaskList: ### Running download... 10-08 16:56 DEBUG btdownloader: downloading http://releases.ubuntu.com/11.04/ubuntu-11.04-desktop-amd64.iso.torrent > C:\ubuntu\install\ubuntu-11.04-desktop-amd64.iso 10-08 18:02 ERROR TaskList: Traceback (most recent call last): File "\lib\bittorrent\RawServer.py", line 229, in listen_forever File "\lib\wubi\backends\common\btdownloader.py", line 70, in error_callback DownloadError: Traceback (most recent call last): File "\lib\bittorrent\RawServer.py", line 221, in listen_forever File "\lib\bittorrent\Rerequester.py", line 96, in fail File "\lib\wubi\backends\common\btdownloader.py", line 70, in error_callback DownloadError: Problem connecting to tracker - urlopen error (10060, 'Operation timed out') Traceback (most recent call last): File "\lib\wubi\backends\common\tasklist.py", line 197, in __call__ File "\lib\wubi\backends\common\btdownloader.py", line 79, in download File "\lib\bittorrent\download.py", line 303, in download File "\lib\bittorrent\RawServer.py", line 256, in listen_forever File "\lib\wubi\backends\common\btdownloader.py", line 70, in error_callback DownloadError: Traceback (most recent call last): File "\lib\bittorrent\RawServer.py", line 229, in listen_forever File "\lib\wubi\backends\common\btdownloader.py", line 70, in error_callback DownloadError: Traceback (most recent call last): File "\lib\bittorrent\RawServer.py", line 221, in listen_forever File "\lib\bittorrent\Rerequester.py", line 96, in fail File "\lib\wubi\backends\common\btdownloader.py", line 70, in error_callback DownloadError: Problem connecting to tracker - urlopen error (10060, 'Operation timed out') 10-08 18:02 ERROR TaskList: Non fatal error Traceback (most recent call last): File "\lib\bittorrent\RawServer.py", line 229, in listen_forever File "\lib\wubi\backends\common\btdownloader.py", line 70, in error_callback DownloadError: Traceback (most recent call last): File "\lib\bittorrent\RawServer.py", line 221, in listen_forever File "\lib\bittorrent\Rerequester.py", line 96, in fail File "\lib\wubi\backends\common\btdownloader.py", line 70, in error_callback DownloadError: Problem connecting to tracker - urlopen error (10060, 'Operation timed out') in task download 10-08 18:02 DEBUG TaskList: ### Finished download 10-08 18:02 ERROR TaskList: [Errno 13] Permission denied: u'C:\\ubuntu\\install\\ubuntu-11.04-desktop-amd64.iso' Traceback (most recent call last): File "\lib\wubi\backends\common\tasklist.py", line 197, in __call__ File "\lib\wubi\backends\common\backend.py", line 492, in get_iso File "\lib\wubi\backends\common\backend.py", line 347, in download_iso OSError: [Errno 13] Permission denied: u'C:\\ubuntu\\install\\ubuntu-11.04-desktop-amd64.iso' 10-08 18:02 DEBUG TaskList: # Cancelling tasklist 10-08 18:02 DEBUG TaskList: # Finished tasklist 10-08 18:02 ERROR root: [Errno 13] Permission denied: u'C:\\ubuntu\\install\\ubuntu-11.04-desktop-amd64.iso' Traceback (most recent call last): File "\lib\wubi\application.py", line 57, in run File "\lib\wubi\application.py", line 131, in select_task File "\lib\wubi\application.py", line 157, in run_installer File "\lib\wubi\backends\common\tasklist.py", line 197, in __call__ File "\lib\wubi\backends\common\backend.py", line 492, in get_iso File "\lib\wubi\backends\common\backend.py", line 347, in download_iso OSError: [Errno 13] Permission denied: u'C:\\ubuntu\\install\\ubuntu-11.04-desktop-amd64.iso'

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  • Ubuntu Server 12 not spawning a serial ttyS0 when running on Xen

    - by segfaultreloaded
    I have this problem on more than one host, so the specific hardware is not an issue. Bare metal Ubuntu 12 is not creating a login process on the only serial port, in the default configuration. The serial port works correctly with the firmware. It works correctly with Grub2. I have even connected the serial line to 2 different external client boxes, so the problem is neither the hardware nor the remote client. When finally booted, the system fails to create the login process. root@xenpro3:~# ps ax | grep tty 1229 tty4 Ss+ 0:00 /sbin/getty -8 38400 tty4 1233 tty5 Ss+ 0:00 /sbin/getty -8 38400 tty5 1239 tty2 Ss+ 0:00 /sbin/getty -8 38400 tty2 1241 tty3 Ss+ 0:00 /sbin/getty -8 38400 tty3 1245 tty6 Ss+ 0:00 /sbin/getty -8 38400 tty6 1403 tty1 Ss+ 0:00 /sbin/getty -8 38400 tty1 1996 pts/0 S+ 0:00 grep --color=auto tty root@xenpro3:~# dmesg | grep tty [ 0.000000] Command line: BOOT_IMAGE=/vmlinuz-3.2.0-30-generic root=/dev/mapper/xenpro3-root ro console=ttyS0,115200n8 [ 0.000000] Kernel command line: BOOT_IMAGE=/vmlinuz-3.2.0-30-generic root=/dev/mapper/xenpro3-root ro console=ttyS0,115200n8 [ 0.000000] console [ttyS0] enabled [ 2.160986] serial8250: ttyS0 at I/O 0x3f8 (irq = 4) is a 16550A [ 2.203396] serial8250: ttyS1 at I/O 0x2f8 (irq = 3) is a 16550A [ 2.263296] 00:08: ttyS0 at I/O 0x3f8 (irq = 4) is a 16550A [ 2.323102] 00:09: ttyS1 at I/O 0x2f8 (irq = 3) is a 16550A root@xenpro3:~# uname -a Linux xenpro3 3.2.0-30-generic #48-Ubuntu SMP Fri Aug 24 16:52:48 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux root@xenpro3:~# I have tried putting a ttyS0.conf file in /etc/initab, which solves the problem bare metal but I still cannot get the serial port to work when booting Ubuntu on top of Xen, as domain 0. My serial line output looks like this, when booting Xen /dev/ttyS0 at 0x03f8 (irq = 4) is a 16550A * Exporting directories for NFS kernel daemon... [ OK ] * Starting NFS kernel daemon [ OK ] SSL tunnels disabled, see /etc/default/stunnel4 [ 18.654627] XENBUS: Unable to read cpu state [ 18.659631] XENBUS: Unable to read cpu state [ 18.664398] XENBUS: Unable to read cpu state [ 18.669248] XENBUS: Unable to read cpu state * Starting Xen daemons [ OK ] mountall: Disconnected from Plymouth At this point, the serial line is no longer connected to a process. Xen itself is running just fine. Dmesg gives me a long list of [ 120.236841] init: ttyS0 main process ended, respawning [ 120.239717] ttyS0: LSR safety check engaged! [ 130.240265] init: ttyS0 main process (1631) terminated with status 1 [ 130.240294] init: ttyS0 main process ended, respawning [ 130.242970] ttyS0: LSR safety check engaged! which is no surprise because I see root@xenpro3:~# ls -l /dev/ttyS? crw-rw---- 1 root tty 4, 64 Nov 7 14:04 /dev/ttyS0 crw-rw---- 1 root dialout 4, 65 Nov 7 14:04 /dev/ttyS1 crw-rw---- 1 root dialout 4, 66 Nov 7 14:04 /dev/ttyS2 crw-rw---- 1 root dialout 4, 67 Nov 7 14:04 /dev/ttyS3 crw-rw---- 1 root dialout 4, 68 Nov 7 14:04 /dev/ttyS4 crw-rw---- 1 root dialout 4, 69 Nov 7 14:04 /dev/ttyS5 crw-rw---- 1 root dialout 4, 70 Nov 7 14:04 /dev/ttyS6 crw-rw---- 1 root dialout 4, 71 Nov 7 14:04 /dev/ttyS7 crw-rw---- 1 root dialout 4, 72 Nov 7 14:04 /dev/ttyS8 crw-rw---- 1 root dialout 4, 73 Nov 7 14:04 /dev/ttyS9 If I manually change the group of /dev/ttyS0 to dialout, it gets changed back. I have made no changes to the default udev rules, so I cannot see where this problem is coming from. Sincerely, John

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  • VB.NET - Read lines from command line to Windows form possible?

    - by Yiu Korochko
    Hey Overflow, I have an application which serves as a user interface for a spartan/command line program. I have the program running on a separate process, and my application monitors it to see if it is responding and how mush CPU it is utilising. Now I have a list of files in my program (listbox) which are to be sent to the application, which happens fine. But I want to be able to read text from the com-line so as to determine when the first file has been processed. Com-line says one of "selecting settings", "unsupported format" and "cannot be fixed". What I want to be able to do is when it says one of these three things, remove item(0) in listbox1. Is this possible? I thought of programming an event which handles com_exe.print or something or other, if possible.

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  • How do I Send Email from the Command Line?

    - by Joseph Pecoraro
    I would like to quickly send email from the command line. I realize there are probably a number of different ways to do this. I'm looking for a simple way to do this from a linux terminal (likely a bash shell but anything should do) and an alternative way to do this on Windows. I want to be able to whip up an email right on the command line or have the flexibility to pipe the message into the command line program. How would you go about doing this? If you have small scripts that would be fine as well. Thanks in advance.

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