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  • How can I programmatically change my windows domain password?

    - by Deestan
    In other words, how to change my password without going through the "CTRL-ALT-DEL - Change Password" interface. By programmatically I mean via a command-line tool, C# via a .NET library, COM-invocation via Python, ... whatever doesn't involve any manual steps, really. The "NET USER" command is ineligible, as it requires me to run with domain administrator privileges.

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  • I'm trying to understand hash tables - can someone explain it to me - clearly?

    - by Stevo
    I want to understand the correct use and implementation of hash tables in php (sorry). I read somewhere that an in-experienced programmer created a hash table and then iterated through it. Now, I understand why that is wrong but I haven't quite got the full knowledge to know if my understanding is correct (if you know what I mean). So could someone explain to me how to implement a hash table in php (presumably an associative array) and perhaps more importantly, how to access the values 'with a hash' and what that actually means?

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  • htaccess on remote server issues - password prompt not accepting input

    - by pying saucepan
    EDIT: I will contact the university about my problem after labor day weekend, but I thought if someone knew a quick fix that I haven't tried, or if the problem has an obvious fix then I could hope to try my luck here, thanks! TLDR: Sorry its a long post, I thought I should be... thorough. I am having a common issue (found a dead thread through google with no solution to the same problem) with the prompt to enter in a username and password via htaccess rights, but this prompt will keep popping up asking for a username and password when trying to access my home directory on my university's server which has the .htaccess and .htpasswd files. It does not matter if I enter in correct or incorrect credentials, the prompt will keep asking me for input without displaying my home directory. Ever since I have included these ht files I have never once been able to get past the username/password no matter what I have tried, save for removing them from the directory I am trying to access (my top level directory that I own). This kind of served my original goal of making the top level directory inaccessible to casual users, but if I wanted to use this method on other places, I would want it to work as intended. And I also like it when computers do what I wish they would, so any help is appreciated. Some things I have tried: Changing the file/directory access rights: they told me to try these commands if people can't access my files cd ~/public_html find ./ -type d -exec chmod 755 {} \; find ./ -type f -exec chmod 644 {} \; enter in the single character name/pw at least twenty times in a row, no cheddar. so I changed directory with cd ~ in hopes that this would be my home directory, since my home directory contains the "public_html" directory, so logic tells me that the ~ tilde symbol is the top level directory that I have ownership of. Then I did those two commands to change the rights on the files inside, I am still having no luck. How I got to this point: I have been following the instructions given to me through my university's website for setting up my little directory. A link on how they describe how to password protect the home directory is given below: "Protect Web Directories" instructions I have everything in order except for one small detail that I feel probably does not matter. I am on windows and so I am using winSCP to remote control my allocated server space. The small detail is that as the instructions indicate (on step 3) that I should use the command htpasswd -c .htpasswd {username} where {username} is my folder that holds my allocated server space. But this command requires further input through the terminal, and unfortunately winSCP does not offer this kind of functionality. So I looked up some basic instructions on using htaccess and it is formatted correctly such that the .htaccess file appears as follows: AuthType Basic AuthName "Verify" AuthUserFile /correctpath/.htpasswd require valid-user and this file is in the root directory for my server space as well as the .htpasswd file which has only this data inside: username:password I know for sure that these two files must be formatted correctly, at least according to their tutorial, because before my path was incorrectly formatted via including some curly { braces } without knowing the correct way to do this at first. And the password prompt that shows up when accessing my directory responded by loading an error page indicating to contact OSU admin or something not important. But now that I have everything like it 'should' be. I know this because when I enter in my credentials "username and password" the prompt pops up for my username and password again and again whether or not I enter in correct information. The only exception is that if I click cancel it will direct me to a page saying that I need to enter in a username and password. Note that I am very inexperienced at server-related buisness, two days ago I couldn't have told you what a website actually consists of. So, if you use some technical jargon I may or may not need to look it up and get back to you before I actually understand what you mean, but I am a quick learner and it probably wont matter.

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  • Why am I asked for default's keyring at startup?

    - by Nicoco
    I'm prompted for default's keyring at every boot since 11.10 upgrade, even though I don't see any application I have needing at startup (I have no wifi, and disabled gwibber-service) How can I know which application is requesting it ? How can I disable it ? I can't even move any window until I enter the password, and sometimes entering the password even crashes X (bug reported here : https://bugs.launchpad.net/ubuntu/+source/xserver-xorg-input-evdev/+bug/882955)

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  • Google Sync brings back Login Keyring from previous distro: How to remove?

    - by Mridul Malpotra
    I previously had Ubuntu 12.04 and had my Login Keyring set to a password that I don't remember and am not able to guess. I changed my Linux version to Mint 15 Cinnamon recently, but everytime I sync my Google account with my browser, the Login Keyring keeps coming back. I tried the /Preferences/Password method but there is no file as such which is created. Also, .gnome2 folder doesn't have any keyring file. How can I make the box go away for all?

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  • The algorithm used to generate recommendations in Google News?

    - by Siddhant
    Hi everyone. I'm study recommendation engines, and I went through the paper that defines how Google News generates recommendations to users for news items which might be of their interest, based on collaborative filtering. One interesting technique that they mention is Minhashing. I went through what it does, but I'm pretty sure that what I have is a fuzzy idea and there is a strong chance that I'm wrong. The following is what I could make out of it :- Collect a set of all news items. Define a hash function for a user. This hash function returns the index of the first item from the news items which this user viewed, in the list of all news items. Collect, say "n" number of such values, and represent a user with this list of values. Based on the similarity count between these lists, we can calculate the similarity between users as the number of common items. This reduces the number of comparisons a lot. Based on these similarity measures, group users into different clusters. This is just what I think it might be. In Step 2, instead of defining a constant hash function, it might be possible that we vary the hash function in a way that it returns the index of a different element. So one hash function could return the index of the first element from the user's list, another hash function could return the index of the second element from the user's list, and so on. So the nature of the hash function satisfying the minwise independent permutations condition, this does sound like a possible approach. Could anyone please confirm if what I think is correct? Or the minhashing portion of Google News Recommendations, functions in some other way? I'm new to internal implementations of recommendations. Any help is appreciated a lot. Thanks!

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  • windows 7 file explorer preview window and password protected word docs

    - by Carbonara
    When using the windows 7 explorer with the preview pane open you get a little preview of a file when you click on it. This includes Word and Excel spreadsheets etc. My problem is if the Word doc is password protected clicking on it in explorer automatically asks for the password to display its preview. It does this if you single or double clicking on it. You then get an empty Word instance running (which allows it to display the preview) and another instance of Word with your actual file and you're asked for the password twice in total. This is annoying and untidy. Is there a way of stopping the preview pane from wanting to display password protected documents and thus not asking for the password to display a preview?

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  • ssh login successful, but scp password gives me "Permission denied"

    - by YANewb
    I'm trying to get some blogging software up on an organizational remote server. I tried to set up a SSH Key but was having problems and decided that getting the blog up and running was more important than dealing with the SSH Key issue, so I ssh-keygen -R remoteserver.com. Now I can successfully login with ssh -v [email protected] and the correct password. Once logged in I can move around and read any file and directory that I should be able to read. But when I try to edit an existing -rw-r--r-- file with VIM, it shows up as read-only, if I try to edit permissions I get chmod: file.ext: Operation not permitted, and if I try to scp a new file from my local machine I'm prompted for the remote user's password, and then get scp: /home/path/to/file.ext: Permission denied. Since I didn't have any of these problems before I tried to set up the ssh key, I suspect these anomalies are a side effect of that, but I don't know how to troubleshoot this. So what does a foolish server-newb, such as myself, need to do to get edit capability back as a remote user? Addendum 1: My userids are different between my local machine and the remote server. For ssh I ssh -v [email protected]. if I whoami I get remoteuser For scp I scp file.ext [email protected]:/path/to/file.ext from the local directory with file.ext while logged in as the local user. if I whoami I get localuser The ls -l for two different files I've tried scp: -rw-r--r--@ 1 localuser localgroup 20 Feb 11 21:03 phpinfo.php -rw-r--r-- 1 root localgroup 4 Feb 11 22:32 test.txt The ls -l for the file I've tried to VIM: -rw-r--r-- 1 remoteuser remotegroup 76 Jul 27 2009 info.txt Addendum 2: In the past I've set up ssh-keys for git repositories. I don't want to completely destroy them, so in an attempt to follow a deer's train of thinking I renamed my ~/.ssh/ to ~/.ssh-bak/, then tested the different types of access. The abridged version of the terminal commands and results is below; I think everything is working until the 8th line from the end. localcomputer:~ localuser$ ssh -v [email protected] OpenSSH_5.2p1, OpenSSL 0.9.8l 5 Nov 2009 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to remoteserver.com [###.###.###.###] port 22. debug1: Connection established. debug1: identity file /Users/localuser/.ssh/identity type -1 debug1: identity file /Users/localuser/.ssh/id_rsa type -1 debug1: identity file /Users/localuser/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p2 FreeBSD-20110503 debug1: match: OpenSSH_5.8p2 FreeBSD-20110503 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.2 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY The authenticity of host 'remoteserver.com (###.###.###.###)' can't be established. RSA key fingerprint is ##:##:##:##:##:##:##:##:##:##:##:##:##:##:##:##. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added 'remoteserver.com,###.###.###.###' (RSA) to the list of known hosts. debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /Users/localuser/.ssh/identity debug1: Trying private key: /Users/localuser/.ssh/id_rsa debug1: Trying private key: /Users/localuser/.ssh/id_dsa debug1: Next authentication method: password [email protected]'s password: debug1: Authentication succeeded (password). debug1: channel 0: new [client-session] debug1: Requesting [email protected] debug1: Entering interactive session. Last login: Sun Feb 12 18:00:54 2012 from 68.69.164.123 FreeBSD 6.4-RELEASE-p8 (VKERN) #1 r101746: Mon Aug 30 10:34:40 MDT 2010 [remoteuser@remoteserver /home]$ ls -l total ### -rw-r--r-- 1 remoteuser remotegroup 76 Aug 12 2009 info.txt [remoteuser@remoteserver /home]$ vim info.txt ~ {at the bottom of the VIM screen it tells me it's [read only]} [remoteuser@remoteserver /home]$ whoami remoteuser [remoteuser@remoteserver /home]$ logout debug1: client_input_channel_req: channel 0 rtype exit-status reply 0 debug1: client_input_channel_req: channel 0 rtype [email protected] reply 0 debug1: channel 0: free: client-session, nchannels 1 Connection to remoteserver.com closed. Transferred: sent 3872, received 12496 bytes, in 107.4 seconds Bytes per second: sent 36.1, received 116.4 debug1: Exit status 0 localcomputer:localdirectory name$ scp -v phpinfo.php [email protected]:/home/www/remotedirectory/phpinfo.php Executing: program /usr/bin/ssh host remoteserver.com, user remoteuser, command scp -v -t /home/www/remotedirectory/phpinfo.php OpenSSH_5.2p1, OpenSSL 0.9.8l 5 Nov 2009 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to remoteserver.com [###.###.###.###] port 22. debug1: Connection established. debug1: identity file /Users/localuser/.ssh/identity type -1 debug1: identity file /Users/localuser/.ssh/id_rsa type -1 debug1: identity file /Users/localuser/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p2 FreeBSD-20110503 debug1: match: OpenSSH_5.8p2 FreeBSD-20110503 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.2 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'remoteserver.com' is known and matches the RSA host key. debug1: Found key in /Users/localuser/.ssh/known_hosts:1 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /Users/localuser/.ssh/identity debug1: Trying private key: /Users/localuser/.ssh/id_rsa debug1: Trying private key: /Users/localuser/.ssh/id_dsa debug1: Next authentication method: password [email protected]'s password: debug1: Authentication succeeded (password). debug1: channel 0: new [client-session] debug1: Requesting [email protected] debug1: Entering interactive session. debug1: Sending command: scp -v -t /home/www/remotedirectory/phpinfo.php Sending file modes: C0644 20 phpinfo.php Sink: C0644 20 phpinfo.php scp: /home/www/remotedirectory/phpinfo.php: Permission denied debug1: client_input_channel_req: channel 0 rtype exit-status reply 0 debug1: channel 0: free: client-session, nchannels 1 debug1: fd 0 clearing O_NONBLOCK debug1: fd 1 clearing O_NONBLOCK Transferred: sent 1456, received 2160 bytes, in 0.6 seconds Bytes per second: sent 2322.3, received 3445.1 debug1: Exit status 1

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  • Escape a ! in the password parameter of wget

    - by Dave
    I'm trying to execute something like this: wget --user=foo --password=bar! url The ! in the password is causing problems. I've tried escaping it with \, as in --password=bar\! I've tried encapsulating in single and double quotes. I put the password in a separate file and tried --password=cat pass.txt Each time, I get a 403 Forbidden. Using -d, I see that the SSL handshake is successful. On the Windows command line, the command works. My assumption is that I need to escape the ! differently, but I don't know how else.

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  • Forgot password to development database

    - by ninja08
    I've created a database using terminal while following along with a tutorial. Although I had a lot of trouble getting the databases to install. Now after finally getting it to work I changed a few things, actually just the name of the database using the rake command to just "next". The password should be 'secret password'. How can I change the password or find out what it is or change it? It doesn't seem to be edited my databases.yml file with the password, especially since it still just says 'root' as username with now password in there.

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  • sudo prompts for password over ssh

    - by Joe Watkins
    I have sudo set up for a shell script as follows on "hostname" (sudo -l output): (suser) NOPASSWD: /path/script* sudoers content is: myuser ALL=(suser) NOPASSWD: /path/script* this works fine, so I can run the following, logged in locally on hostname, without need for password: sudo -u suser /path/script however, when I use ssh (with keys set up, so no password require) to login and run, as follows: ssh hostname sudo -u suser /path/script I get prompted for a password, and when the password is entered I get: Sorry, user myuser is not allowed to execute '/path/script' as suser on hostname. Why? NB the following does not prompt for password at any point: $ ssh hostname $ sudo -u suser /path/script

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  • NIS AD password synch for new accounts

    - by user135004
    I have a Win2k3R2 DC with NIS. All is working well but its no longer synching the passwords for new accounts. When creating a new AD user, NIS does its thing and sends its Unix account to the synched linux server. It's doing everything its supposed to do but not the users password to the server (getent passwd returns the ABCD!efgh12345$67890 password for the new account). Thinking that password synchronization is not working, I changed the password of an existing working account and it synchs the new password. If I delete a new or old AD user, it deletes it on the linked linux server as well. All this tells me that NIS is doing its thing (at least with existing accounts) No updates have been installed on the DC. I am not even sure where to start here.

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  • login as rsh in rhel 6 without entering password

    - by cartmancakes
    I need to be able to login to a RHEL 6 server using rsh (please don't flame me about security, it's irrelevant in this particular instance) as root without having to enter a password. My procedure for setting this up works great in RHEL 5.x, but does not work in RHEL 6. I suspect this has something to do with PAM, but I'm inexperienced with how to use PAM. Can someone help me with this? /etc/pam.d/rsh auth required pam_rhosts.so auth required pam_nologin.so account include common-account password include common-password session required pam_loginuid.so session include common-session /etc/pam.d/rlogin auth required pam_nologin.so auth [user_unknown=ignore success=ok ignore=ignore auth_err=die default=bad] pam_securetty.so auth sufficient pam_rhosts.so auth include common-auth auth required pam_mail.so account include common-account password include common-password session required pam_loginuid.so session include common-session Thanks!

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  • Running a command line app with sudo and password automatically on OS X startup

    - by Designer023
    I need to run an app at startup/login on my mac. I want it to launch in the background and start doing it's work without interrupting me or me having to start it up because I invariably forget and then when I need it, it wasn't running! I have tried using AppleScript to tell Terminal to run it and type my password in, but it ends up opening multiple Terminal windows and not working. Ideally I need a script that I can just add to the user login items and it will run for me. The app has no way of taking a password argument either and it has a password as well as the sudo! I need a solution that can either be done as an applescript (which can be made into an executable) or i need a commandline script but I have no idea about them. This is the manual code I type $ sudo serverStatus password:123456 password:serverpass My AppleScript: tell application Terminal activate do shell script "sudo serverStatus" delay 5 do shell script "123456" delay 2 do shell script "serverpass" end tell

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  • Windows 7 file explorer preview window and password protected word documents

    - by Carbonara
    When using the Windows 7 Explorer with the preview pane open you get a little preview of a file when you click on it. This includes Word, Excel spreadsheets, etc. My problem is if the Word document is password protected. Clicking on it in Explorer automatically asks for the password to display its preview. It does this if you single or double clicking on it. You then get an empty Word instance running (which allows it to display the preview) and another instance of Word with your actual file and you're asked for the password twice in total. This is annoying and untidy. Is there a way of stopping the preview pane from wanting to display password protected documents and thus not asking for the password to display a preview?

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  • Password format not liked by installer

    - by Box293
    I'm installing Chargeback and I get to the database-related information page (step 5 on page 17 of the users guide). Using a Windows account (it is an administrator of the server and I am logged on as that user) Username: DOMAIN\ServiceVMware-CB Password: #$%UuuU2u (this isn't the password but it does start with #$% and is the same length and case) I click the Test Connected and it returns back OK. I click Next and then I am given a warning telling me that the account does not have the right permissions. Check that it has log on as a service etc etc etc. I quit the installer. I change the password in the domain to Uuuuuu3 I reboot the server I restart the server The installer has no problems with the newer password. I'm not fussed either way, I'm just trying to save someone else the pain and perhaps the allowed password format could be added to the documentation. BTW I am using Server 2008 SP2 x64 with SQL Express 2005 x64.

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  • Password Management for Oracle WebLogic customers

    - by Anthony Shorten
    One of the most common requests for enhancements I get across my desk is that customers wish to allow end users to change their passwords from our products. Now, typically password management is not in the realm of individual applications but it is an infrastructure requirement, so we don't usually add this to our roadmaps by default. The issue is that with the vast range of security stores that can be used with our product line across the Web Application Servers we support, it is almost impossible to come up with a generic enough API to work across them. If you have a specific security store on a specific Web Application Server platform then there are simpler solutions. There are a number of ways of implementing this without providing functionality specific functionality: Oracle sells Identity Management software that offers common API's to manage passwords. You can purchase those products and link to the password change dialog in those products using Navigation Keys. If you are a customer using Oracle WebLogic, then there is a sample JSP's that can be linked to provide this functionality under Oracle TechNet (registration required) under Code Samples (project S20). These can be added as a Navigation Key to complete the functionality. This will allow end users to manage their own passwords. Obviously these are all samples and should be treated as customizations when you implement them. If you wish to understand Navigation Keys, then look at the Oracle Utilities Application Framework Integration Guidelines (Doc Id: 789060.1) available from My Oracle Support.

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  • Tale of an Encrypted SSIS Package in msdb and a Lost Password

    - by Argenis
      Yesterday a Developer at work asked for a copy of an SSIS package in Production so he could work on it (please, dear Reader – withhold judgment on Source Control – I know!). I logged on to the SSIS instance, and when I went to export the package… Oops. I didn’t have that password. The DBA who uploaded the package to Production is long gone; my fellow DBA had no idea either - and the Devs returned a cricket sound when queried. So I posed the obligatory question on #SQLHelp and a bunch of folks jumped in – some to help and some to make fun of me (thanks, @SQLSoldier @crummel4 @maryarcia and @sqljoe). I tried their suggestions to no avail…even ran some queries to see if I could figure out how to extract the package XML from the system tables in msdb:   SELECT CAST(CAST(p.packagedata AS varbinary(max)) AS varchar(max)) FROM msdb.dbo.sysssispackages p WHERE p.name = 'LePackage'   This just returned a bunch of XML with encrypted data on it:  I knew there was a job in SQL Agent scheduled to execute the package, and when I tried to look at details on the job step I got the following: Not very helpful. The password had to be saved somewhere, but where?? All of a sudden I remembered that there was a system table I hadn’t queried yet: SELECT sjs.command FROM msdb.dbo.sysjobs sj JOIN msdb.dbo.sysjobsteps sjs ON sj.job_id = sjs.job_id WHERE sj.name = 'Run LePackage' The result: “Well, that’s really secure”, I thought to myself. Cheers, -Argenis

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  • How can I check if a user has written his username and password correctly?

    - by Sergio Tapia
    I'm using a Linq-to-SQL class called Scans.dbml. In that class I've dragged a table called Users (username, password, role) onto the graphic area and now I can access User object via a UserRepository class: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace Scanner.Classes { public class UserRepository { private ScansDataContext db = new ScansDataContext(); public User getUser(string username) { return db.Users.SingleOrDefault(x => x.username == username); } public bool exists(string username) { } } } Now in my Login form, I want to use this Linq-to-SQL goodness to do all the data related activities. UserRepository users = new UserRepository(); private void btnLogin_Click(object sender, EventArgs e) { loginToSystem(); } private void loginToSystem() { if (users.getUser(txtUsername.Text)) { } //If txtUsername exists && User.password == Salt(txtPassword) //then Show.MainForm() with User.accountType in constructor to set permissions. } I need help with verifying that a user exists && that that users.password is equal to SALT(txtpassword.text). Any guidance please?

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  • Tool to compute SHA256 Tree Hash

    - by Benjamin
    I've started using AWS Glacier, and noticed that it hashes the files using an algorithm called SHA-256 Tree Hash. To my surprise, this algorithm is different from SHA-256, so I can't use the tools I'm used to, to compare hashes and verify file integrity. Do you know a Windows tool, if possible integrated in the context menu, to compute the SHA-256 Tree Hash of a file? I'd also accept a Linux command-line tool, as a second choice :-)

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