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  • How to configure ubuntu ldap client to get password policies from server?

    - by Rafaeldv
    I have a ldap server on CentOS, 389-ds. I configured the client, ubuntu 12.04, to authenticate on that base and it works very well. But it don't gets the password policies from server. For example, if i set the policy to force user to change the password on first login, ubuntu ignores it and logs him in, always. How can i setup the client to get the policies? Here are the client files: /etc/nsswitch.conf passwd: files ldap group: files ldap shadow: files ldap hosts: files mdns4_minimal [NOTFOUND=return] dns mdns4 networks: files protocols: db files services: db files ethers: db files rpc: db files netgroup: nis sudoers: ldap files common-auth auth [success=2 default=ignore] pam_unix.so nullok_secure auth [success=1 default=ignore] pam_ldap.so use_first_pass auth requisite pam_deny.so auth required pam_permit.so auth optional pam_cap.so common-account account [success=2 new_authtok_reqd=done default=ignore] pam_unix.so account [success=1 default=ignore] pam_ldap.so account requisite pam_deny.so account required pam_permit.so common-password password requisite pam_cracklib.so retry=3 minlen=8 difok=3 password [success=2 default=ignore] pam_unix.so obscure use_authtok try_first_pass sha512 password [success=1 user_unknown=ignore default=die] pam_ldap.so use_authtok try_first_pass password requisite pam_deny.so password required pam_permit.so password optional pam_gnome_keyring.so common-session session [default=1] pam_permit.so session requisite pam_deny.so session required pam_permit.so session optional pam_umask.so session required pam_unix.so session optional pam_ldap.so session optional pam_ck_connector.so nox11 session optional pam_mkhomedir.so skel=/etc/skel umask=0022 /etc/ldap.conf base dc=a,dc=b,dc=c uri ldaps://a.b.c/ ldap_version 3 rootbinddn cn=directory manager pam_password md5 sudoers_base ou=SUDOers,dc=a,dc=b,dc=c pam_lookup_policy yes pam_check_host_attr yes nss_initgroups_ignoreusers avahi,avahi-autoipd,backup,bin,colord,daemon,games,gnats,hplip,irc,kernoops,libuuid,lightdm,list,lp,mail,man,messagebus,news,proxy,pulse,root,rtkit,saned,speech-dispatcher,sshd,sync,sys,syslog,usbmux,uucp,whoopsie,www-data /etc/ldap/ldap.conf BASE dc=a,dc=b,dc=c URI ldaps://a.b.c/ ssl on use_sasl no tls_checkpeer no sudoers_base ou=SUDOers,dc=a,dc=b,dc=c sudoers_debug 2 pam_lookup_policy yes pam_check_host_attr yes pam_lookup_policy yes pam_check_host_attr yes TLS_CACERT /etc/ssl/certs/ca-certificates.crt TLS_REQCERT never

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  • Character encoding issues when generating MD5 hash cross-platform

    - by rogueprocess
    This is a general question about character encoding when using MD5 libraries in various languages. My concern is: suppose I generate an MD5 hash using a native Python string object, like this: message = "hello world" m = md5() m.update(message) Then I take a hex version of that MD5 hash using: m.hexdigest() and send the message & MD5 hash via a network, let's say, a JMS message or a HTTP request. Now I get this message in a Java program in the form of a native Java string, along with the checksum. Then I generate an MD5 hash using Java, like this (using the Commons Codec library): String md5 = org.apache.commons.codec.digest.DigestUtils.DigestUtils.md5Hex(s) My feeling is that this is wrong because I have not specified character encodng at either end. So the original hash will be based on the bytes of the Python version of the string; the Java one will be based on the bytes of the Java version of the string , these two byte sequences will often not be the same - is that right? So really I need to specify "UTF-8" or whatever at both ends right? (I am actually getting an intermittent error in my code where the MD5 checksum fails, and I suspect this is the reason - but because it's intermittent, it's difficult to say if changing this fixes it or not. ) Thank you!

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  • MySQL Unique hash insertion

    - by Jesse
    So, imagine a mysql table with a few simple columns, an auto increment, and a hash (varchar, UNIQUE). Is it possible to give mysql a query that will add a column, and generate a unique hash without multiple queries? Currently, the only way I can think of to achieve this is with a while, which I worry would become more and more processor intensive the more entries were in the db. Here's some pseudo-php, obviously untested, but gets the general idea across: while(!query("INSERT INTO table (hash) VALUES (".generate_hash().");")){ //found conflict, try again. } In the above example, the hash column would be UNIQUE, and so the query would fail. The problem is, say there's 500,000 entries in the db and I'm working off of a base36 hash generator, with 4 characters. The likelyhood of a conflict would be almost 1 in 3, and I definitely can't be running 160,000 queries. In fact, any more than 5 I would consider unacceptable. So, can I do this with pure SQL? I would need to generate a base62, 6 char string (like: "j8Du7X", chars a-z, A-Z, and 0-9), and either update the last_insert_id with it, or even better, generate it during the insert. I can handle basic CRUD with MySQL, but even JOINs are a little outside of my MySQL comfort zone, so excuse my ignorance if this is cake. Any ideas? I'd prefer to use either pure MySQL or PHP & MySQL, but hell, if another language can get this done cleanly, I'd build a script and AJAX it too. Thanks!

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  • How to automatically add user account *and* password with a Bash script

    - by ModernCarpentry
    I need to have the ability to create user accounts on my Linux ( Fedora 10 ) and automatically assign a password via a bash script ( or otherwise, if need be ). It's easy to create the user via Bash eg: [whoever@server ]# /usr/sbin/useradd newuser But is it possible to assign a password in Bash, something functionally similar to this (but automated): [whoever@server ]# passwd newuser Changing password for user testpass. New UNIX password: Retype new UNIX password: passwd: all authentication tokens updated successfully. [whoever@server ]#

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  • Hash Map Usage and Idea

    - by Anand
    Hi, I have been working in Java for the last 6 months and have been using Hash Maps What is the basic idea of a Hash Map ? I am using it as it easy for me to store so much data with direct key references rather than having to iterate through an arraylist ? Where is the power of Hash Map seen ? What is the scientific idea behind this data structure ?

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  • good __eq__, __lt__, ..., __hash__ methods for image class?

    - by Marten Bauer
    I create the following class: class Image(object): def __init__(self, extension, data, urls=None, user_data=None): self._extension = extension self._data = data self._urls = urls self._user_data = user_data self._hex_digest = hashlib.sha1(self._data).hexDigest() Images should be equal when all values are equal. Therefore I wrote: def __eq__(self, other): if isinstance(other, Image) and self.__dict__ == other.__dict__: return True return False def __ne__(self, other): return not self.__eq__(other) def __lt__(self, other): return self.__dict__ < other.__dict__ ... But how should the __hash__ method look like? Equal Images should return equal hashes... def __hash__(self): # won't work !?! return hash(self.__dict__) Is the way I try to use __eq__, __ne__, __lt__, __hash__, ... recommend?

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  • Turning a nested hash structure into a non-nested hash structure - is this the cleanest way to do it

    - by knorv
    Assume a nested hash structure %old_hash .. my %old_hash; $old_hash{"foo"}{"bar"}{"zonk"} = "hello"; .. which we want to "flatten" (sorry if that's the wrong terminology!) to a non-nested hash using the sub &flatten(...) so that .. my %h = &flatten(\%old_hash); die unless($h{"zonk"} eq "hello"); The following definition of &flatten(...) does the trick: sub flatten { my $hashref = shift; my %hash; my %i = %{$hashref}; foreach my $ii (keys(%i)) { my %j = %{$i{$ii}}; foreach my $jj (keys(%j)) { my %k = %{$j{$jj}}; foreach my $kk (keys(%k)) { my $value = $k{$kk}; $hash{$kk} = $value; } } } return %hash; } While the code given works it is not very readable or clean. My question is two-fold: In what ways does the given code not correspond to modern Perl best practices? Be harsh! :-) How would you clean it up?

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  • Sort by values from hash table - Ruby

    - by Adnan
    Hello, I have the following hash of countries; COUNTRIES = { 'Albania' => 'AL', 'Austria' => 'AT', 'Belgium' => 'BE', 'Bulgaria' => 'BG', ..... } Now when I output the hash the values are not ordered alphabetically AL, AT, BE, BG ....but rather in a nonsense order (at least for me) How can I output the hash having the values ordered alphabetically?

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  • [Haskell]Curious about the Hash Table problem

    - by astamatto
    I read that hash tables in haskell are crippled ( citation: http://flyingfrogblog.blogspot.com/2009/04/more-on-haskells-hash-table-problems.html ) and since i like haskell it worried me. Since the blog-post one year has passed and im curious, The hash table problem in haskell was "fixed" in the traditional compilers? (like ghc) ps: I love stack overflow, im a long time visitor but only today i decided to try to post a question.

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  • Cleaning up code - flatten a nested hash structure

    - by knorv
    The following Perl sub flattens a nested hash structure: sub flatten { my $hashref = shift; my %hash; my %i = %{$hashref}; foreach my $ii (keys(%i)) { my %j = %{$i{$ii}}; foreach my $jj (keys(%j)) { my %k = %{$j{$jj}}; foreach my $kk (keys(%k)) { my $value = $k{$kk}; $hash{$kk} = $value; } } } return %hash; } While the code works it is not very readable or clean. My question is two-fold: In what ways does it not correspond to modern Perl best practices? How would you clean it up?

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  • Combine hash values in C#

    - by Chris
    I'm creating a generic object collection class and need to implement a Hash function. I can obviously (and easily!) get the hash values for each object but was looking for the 'correct' way to combine them to avoid any issues. Does just adding, xoring or any basic operation harm the quality of the hash or am I going to have to do something like getting the objects as bytes, combining them and then hashing that? Cheers in advance

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  • How can I marshal a hash with arrays?

    - by tuner
    What should I do to marshal an hash of arrays? The following code only prints {}. s = Hash.new s.default = Array.new s[0] << "Tigger" s[7] << "Ruth" s[7] << "Puuh" data = Marshal.dump(s) ls = Marshal.restore( data ) p ls If the hash doesn't contain an array it is restored properly.

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  • Hash value in the manifest file.

    - by satishtech
    Hello, Im tring to create a manifest for my own.dll, i took the manifest file from C:\WINDOWS\WinSxS\Manifests for example. In that, below tag was one of the line.<file name="msvcr90.dll" hashalg="SHA1" hash="e0dcdcbfcb452747da530fae6b000d47c8674671"> In above tag, hash value was assigned with 40 character. Here comes my doubt, 1) hash value was auto generated, if not, whats it points to?

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  • Win2k3 password Authentication using LDAP in VC++

    - by user001
    Hi, I need to implement the Win2k3 password validation policy. As my application resides on Win2k3 cane we validate the password directly with windows domain password by using LDAP. This is because application design does not want to store 8/more password entry into DB and validate new password against that. As Windows already does same thing and using LDAP we can lookup into windows server. Can any one please let me know LDAP API to fulfill above requirement in VC++.

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  • How do I access a value of a nested Perl hash?

    - by st
    I am new to Perl and I have a problem that's very simple but I cannot find the answer when consulting my Perl book. When printing the result of Dumper($request); I get the following result: $VAR1 = bless( { '_protocol' => 'HTTP/1.1', '_content' => '', '_uri' => bless( do{\(my $o = 'http://myawesomeserver.org:8081/counter/')}, 'URI::http' ), '_headers' => bless( { 'user-agent' => 'Mozilla/5.0 (X11; U; Linux i686; en; rv:1.9.0.4) Gecko/20080528 Epiphany/2.22 Firefox/3.0', 'connection' => 'keep-alive', 'cache-control' => 'max-age=0', 'keep-alive' => '300', 'accept' => 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8', 'accept-language' => 'en-us,en;q=0.5', 'accept-encoding' => 'gzip,deflate', 'host' => 'localhost:8081', 'accept-charset' => 'ISO-8859-1,utf-8;q=0.7,*;q=0.7' }, 'HTTP::Headers' ), '_method' => 'GET', '_handle' => bless( \*Symbol::GEN0, 'FileHandle' ) }, 'HTTP::Server::Simple::Dispatched::Request' ); How can I access the values of '_method' ('GET') or of 'host' ('localhost:8081'). I know that's an easy question, but Perl is somewhat cryptic at the beginning.

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  • Collision free hash function for a specific data structure

    - by Max
    Is it possible to create collision free hash function for a data structure with specific properties. The datastructure is int[][][] It contains no duplicates The range of integers that are contained in it is defined. Let's say it's 0..1000, the maximal integer is definitely not greater than 10000. Big problem is that this hash function should also be very fast. Is there a way to create such a hash function? Maybe at run time depending on the integer range?

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  • in ruby, how do you make this nested hash work?

    - by David
    this one creates an error: @settings = { :tab1 => { :name => { :required => true }, :description } } need to change :descrpition to :description = {}, but i don't have any values for :description so i want it to remain as is (without the empty = {}) Would you show me the best way to handle this kind of situation? thanks in advance

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  • How can I merge several hashes into one hash in Perl?

    - by Nick
    In Perl, how do I get this: $VAR1 = { '999' => { '998' => [ '908', '906', '0', '998', '907' ] } }; $VAR1 = { '999' => { '991' => [ '913', '920', '918', '998', '916', '919', '917', '915', '912', '914' ] } }; $VAR1 = { '999' => { '996' => [] } }; $VAR1 = { '999' => { '995' => [] } }; $VAR1 = { '999' => { '994' => [] } }; $VAR1 = { '999' => { '993' => [] } }; $VAR1 = { '999' => { '997' => [ '986', '987', '990', '984', '989', '988' ] } }; $VAR1 = { '995' => { '101' => [] } }; $VAR1 = { '995' => { '102' => [] } }; $VAR1 = { '995' => { '103' => [] } }; $VAR1 = { '995' => { '104' => [] } }; $VAR1 = { '995' => { '105' => [] } }; $VAR1 = { '995' => { '106' => [] } }; $VAR1 = { '995' => { '107' => [] } }; $VAR1 = { '994' => { '910' => [] } }; $VAR1 = { '993' => { '909' => [] } }; $VAR1 = { '993' => { '904' => [] } }; $VAR1 = { '994' => { '985' => [] } }; $VAR1 = { '994' => { '983' => [] } }; $VAR1 = { '993' => { '902' => [] } }; $VAR1 = { '999' => { '992' => [ '905' ] } }; to this: $VAR1 = { '999:' => [ { '992' => [ '905' ] }, { '993' => [ { '909' => [] }, { '904' => [] }, { '902' => [] } ] }, { '994' => [ { '910' => [] }, { '985' => [] }, { '983' => [] } ] }, { '995' => [ { '101' => [] }, { '102' => [] }, { '103' => [] }, { '104' => [] }, { '105' => [] }, { '106' => [] }, { '107' => [] } ] }, { '996' => [] }, { '997' => [ '986', '987', '990', '984', '989', '988' ] }, { '998' => [ '908', '906', '0', '998', '907' ] }, { '991' => [ '913', '920', '918', '998', '916', '919', '917', '915', '912', '914' ] } ]};

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  • Calculate sum of objects for each unique object property in Ruby

    - by macek
    I was helping with an answer in this question and it sparked a question of my own. Pie is an object that has a pieces array made of of PiePiece objects. Each PiePiece has a flavor attribute How do I create a hash that looks like this: # flavor => number of pieces { :cherry => 3 :apple => 1 :strawberry => 2 } This works, but I think it could be improved def inventory hash = {} pieces.each do |p| hash[p.flavor] ||= 0 hash[p.flavor] += 1 end hash end Any ideas?

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