Hi,
I have a div tag, nested with many span and div tags inside it.
now i want a regularexpression in javascript which will strip the div and the content inside it.
thanks in advance..
Hi ,
I am finding Email ids in mu project, where I am preprocessing the input using some RegularExpression.
RegExpPhone6.RegComp("[\[\{\(][ -]?[s][h][i][f][t][ -]?[+-][2][ -]?[\]\}\)]");
Here while I am compiling i am getting a warning msg like
Warning 39 warning C4129: ')' : unrecognized character escape sequence
How can i resolve this ?
Why this is occuring and Where will it affect?
Kindly help me...
Hi
I am trying to use the following regularexpression to check whether a string is a positive number with either zero decimal places, or 2:
^\d+(\.(\d{2}))?$
When I try to match this using preg_match, I get the error:
Warning: preg_match(): No ending delimiter '^' found in /Library/WebServer/Documents/lib/forms.php on line 862
What am I doing wrong?
I'm working on a new Java project and therefore im reading the already existing code. On a very important part of the code if found the following regex expression and i can't really tell what they are doing. Anybody can explain in plain english what they do??
1)
[^,]*|.+(,).+
2)
(\()?\d+(?(1)\))
Hello,
I have a simple problem on .xhtml page. This expression is not working :-
<a href="Photos.jsf?albumId=#{item.albumId}&blogId=#{PhotoAlbumsCommonBean.blogId}">
photos
</a>
I get this error :-
Error Parsing /Common/PhotoAlbums.xhtml: Error Traced[line: 20] The reference to entity "blogId" must end with the ';' delimiter.
& is causing some kind of error. Thanks in advance :)
How would I write a regularexpression (C#) which will check a given string to see if any of its characters are characters OTHER than the following:
a-z
A-Z
Æ æ Å å Ø ø - '
Thanks!
Hi,
i need to check a string that should contain only ABCDEFG characters, in any sequence and with only 7 characters. Please let me know the correct way of using regularexpression.
as corrently i am using
String abs = "ABPID";
if(!Pattern.matches("[[ABCDEFG]", abs))
System.out.println("Error");
i am using the following code which works when i use the String abcdefg but for other cases it fails. please help me out.
Imagine I have the following:
inFile = "/adda/adas/sdas/hello.txt"
# that instruction give me hello.txt
Name = inFile.name.split("/") [-1]
# that one give me the name I want - just hello
Name1 = Name.split(".") [0]
Is there any chance to simplify that doing the same job in just one expression?
I got a headache looking for this:
How do you use s/// in an expression as opposed to an assignment. To clarify what I mean, I'm looking for a perl equivalent of python's re.sub(...) when used in the following context:
newstring = re.sub('ab', 'cd', oldstring)
The only way I know how to do this in perl so far is:
$oldstring =~ s/ab/cd/;
$newstring = $oldstring;
Note the extra assignment.
I'm writing an application that displays data using Google Earth.
In certain situations, it would be more convenient if, rather than displaying satellite images, the surface of the earth would look more like the 'regular map' on Google Maps.
Is this possible?
The lack of expression trees in Compact Framework has bugged me for some time now, but I haven't really looked for a solution.
Today, I've found a blog post about an alternative System.Linq.Expressions built on top of Mono System.Core and used e.g. by db4o (you can find it here).
My question is - have you used this library and if so, what were your experiences with it (especially regarding performance)?
Which regularexpression can I use to match (allow) any kind of letter from any language
I need to match any letter including any diacritics (e.g. á, ü, ñ, etc.)
and exlude any kind of symbol (math symbols, currency signs, dingbats, box-drawing characters, etc.) and punctuation characters.
I've tried using
\p{L}\p{M}*
but it doesn't work.
I have this situation(Java code):
1) a string such as : "A wild adventure" should match.
2) a string with adjacent repeated words: "A wild wild adventure" shouldn't match.
With this regular expression: .* \b(\w+)\b\s*\1\b.* i can match strings containing adjacent repeated words.
How to reverse the situation i.e how to match strings which do not contain adjacent repeat words
I already know the basics of RegEx but I'm not sure where to go from here, I'm looking for both a good and above all easy to understand guide but I am also looking for things to use RegEx's for, it's all well and good reading about it but if you never use them then they will not stick in your mind.
I have already found regular-expressions.info but I'm sure there are more.
I want regularexpression that checks
that the string doesnt start with an
empty space.
Some what like this i want to do :
Is the below ValidationExpression right for it :
string ValidationExpression = @"/^[^ ]/";
if (!String.IsNullOrEmpty(GroupName) && !Regex.IsMatch(GroupName, ValidationExpression))
{
}
I am trying to write a regularexpression for somethin like
s1 = I am at Boston at Dowtown
s2 = I am at Miami
I am interested in the words after at eg: Boston, Downtown, Miami
I have not been successful in creating a regex for that. Somethin like
> .*? (at \w+)+.*
gives just Boston in s1 (Downtown is missed). it just matches the first "at" Any suggestions
I have a string of names like this "J. Smith; B. Jones; O. Henry"
I can match all but the last name with
\w+.*?;
Is there a regularexpression that will match all the names, including the last one?
I know you can generate all permutations from a list, using glob or Algorithm::Permute for example - but how do you generate all possible permutations from a regular expression?
i want to do like:
@perms = permute( "/\s[A-Z][0-9][0-9]/" );
sub permute( $regex ) {
# code - put all permutations of above regex in a list
return @list;
}
I have a string something like this:
"2014-01-23 09:13:45|\"10002112|TR0859657|25-DEC-2013>0000000000000001\"|10002112"
I would like to split by pipe apart from anything wrapped in double quotes so I have something like (similar to how csv is done):
[0] => 2014-01-23 09:13:45
[1] => 10002112|TR0859657|25-DEC-2013>0000000000000001
[2] => 10002112
I would like to know if there is a regularexpression that can do this?
Hi
Please help me with a regularexpression to validate the following format
dd/mm
This is for validating a Birthday field and the year is not required.
Thanks
I've got (To) [a-z]+ as regularexpression and I've got sentence:
To kot dziki pies.
And If I compile it I will retrieve To kot.
So what can I do to rtrieve only word after (only kot) "To" instead of "To kot"
I have a regularexpression, links = re.compile('<a(.+?)href=(?:"|\')?((?:https?://|/)[^\'"]+)(?:"|\')?(.*?)>(.+?)</a>',re.I).findall(data)
to find links in some html, it is taking a long time on certain html, any optimization advice?
One that it chokes on is http://freeyourmindonline.net/Blog/
Hi folks!
I read the german article about "Make" on Wikipedia and found the following 2 lines:
.c.o:
$(CC) $(CFLAGS) -c -o $@ $<
Why is the dependency expression left out and why does the target use a double file extension?
I need regularexpression to match braces correct e.g for every open one close one
abc{abc{bc}xyz} I need it get all it from {abc{bc}xyz} not get {abc{bc} I tried this
({.*?})
In one of the StackOverflow Podcasts (the one where guys were discussing data generation for testing DBs -- either #11 or #12), Jeff mentioned something like "reverse regular expressions", which are used exactly for that purpose: given a regex, produce a string which will eventually match said regex.
What is the correct term for this whole concept? Is this a well-known concept?