Search Results

Search found 8593 results on 344 pages for 'regular expression'.

Page 35/344 | < Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >

  • Regular expression (PCRE) for url matching

    - by zerkms
    The input: we get some plain text as input string and we have to highlighight all urls there with {url For some time i've used regex taken from http://flanders.co.nz/2009/11/08/a-good-url-regular-expression-repost/, which i modified several times, but it's built for another issue - to check whether the whole input string is an url or no. So, what regex do you use in such issues?

    Read the article

  • SQLite user_version() expression

    - by ralf.w.
    how can I get user_version into an expression (for SELECT or WHERE) ? I would also appreciate any clue to how to save ANY global variable in SQLite. Does anyone know of such an extension (dll) ? BTW: I know that PRAGMA user_version; gives me the right answer, but I cannot use that inside a WHERE-clause !

    Read the article

  • A regular expression question

    - by Hellnar
    Hello, I am in dire need of a such regular expression where my alphabet is made up of 0s and 1s. Now I need a language that accepts all words as long as it has three 0s. IE: 000 10001 0001 1000 10000101

    Read the article

  • Regular expression for a list of numbers without other characters

    - by JamesW
    I need a regular expression for a list of numbers in a text box with carriage returns and line feeds, but no other characters. e.g. 1234 5678 5874 3478 I have this: Regex(@"\d\r\n${0,}?"); ... but it is accepting commas when I paste them into my text box: e.g. 1234, 5678 5874, 3478 Can someone please tell me what I'm doing wrong? Thanks

    Read the article

  • regular expressions for class name

    - by user576701
    i need a regular expressions string to get all anchor tags in a page with a specific css class name, in c#/vb.net this is what i got so far "<a.*?href=""(.*?)"".*?>(.*?)</a>" but my attempts to add "class=name" isnt working, also is it possible to find links where the class name appears either before or after the href with one expression ? i am familiar with 3rd party html libraries, but thats an overkill for what i have in mind, so is the webbrowser control.

    Read the article

  • Regular Expression Fails

    - by Meander365
    Anyone help? When I run this I get " invalid quantifier ?<=href= " var aHrefMatch = new RegExp("(?<=href\=")[^]+?(?=")"); var matchedLink = mystring.match(aHrefMatch); But I know the regular expression is valid. Any ideas?

    Read the article

  • Regular Expression

    - by Blanca
    Hi! i would like to avoid texts like this one: height="49" with a regular expresion. I tought in .replaceAll("\s*="*"",""); (replaceAll is used as a method in a java class), but eclipse don't allowed me to do that. Any other suggestion?? tx!

    Read the article

  • Regular Expression Routes in Rails

    - by Kevin Sylvestre
    I am looking to create a rails route that is capable of accepting requests using a regular expression. Specifically, I need optional paths. As an example: "(/first)?(/second)?" Would match: /first /second /first/second But not: /second/first Is this possible? Thanks.

    Read the article

  • Regular expression - starting and ending with a letter, accepting only letters, numbers and _

    - by jreid9001
    I'm trying to write a regular expression which specifies that text should start with a letter, every character should be a letter, number or underscore, there should not be 2 underscores in a row and it should end with a letter or number. At the moment, the only thing I have is ^[a-zA-Z]\w[a-zA-Z1-9_] but this doesn't seem to work properly since it only ever matches 3 characters, and allows repeated underscores. I also don't know how to specify requirements for the last character.

    Read the article

  • Finding C#-style unescaped strings using regular expressions

    - by possan
    I'm trying to write a regular expression that finds C#-style unescaped strings, such as string x = @"hello world"; The problem I'm having is how to write a rule that handles double quotes within the string correctly, like in this example string x = @"before quote ""junk"" after quote"; This should be an easy one, right?

    Read the article

  • Regular Expression not disappearing

    - by user2439019
    I have 3 phone fields and any one is required. SO i had a custom validation class to make any one of them is required. And i am calling those class as follows [RegularExpression(@"^\(?([0-9]{3})\)?. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [AtLeastOneRequired("PhoneHome", "PhoneMobile", "PhoneOffice", ErrorMessage = "Please provide either of PhoneHome or PhoneMobile or phoneOffice. ")] public string PhoneHome { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneOffice", ResourceType = typeof(ResContactItems))] public string PhoneOffice { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneMobile", ResourceType = typeof(ResContactItems))] public string PhoneMobile { get; set; } The problem is with only "PhoneHome " field , if i enter incorrect format, it will display error message based ont he regular expression given .But the regular expression message is not disappearing wwhen we enter the correct format too.It will disappear only in f the field is empty.Other two fields are showing properly. Is this due to the custom class i am calling.? Please help me to sort out this issue Thanks, Vidya

    Read the article

  • regular expression breaking on new line

    - by shyam
    I'm trying to use a regular expression as below: preg_match_all('|<table.*</table>|',$html,$matches, PREG_SET_ORDER); But this is not working, and I think the problem is the new line inside the string $html. Could someone tell me a work around?

    Read the article

  • .NET regular expression

    - by vert
    How would I write a regular expression (C#) which will check a given string to see if any of its characters are characters OTHER than the following: a-z A-Z Æ æ Å å Ø ø - '

    Read the article

  • Regular expression to process key value pairs

    - by user677680
    I am attempting to write a regular expression to process a string of key value(s) pairs formatted like so KEY/VALUE KEY/VALUE VALUE KEY/VALUE A key can have multiple values separated by a space. I want to match a keys values together, so the result on the above string would be VALUE VALUE VALUE VALUE I currently have the following as my regex [A-Z0-9]+/([A-Z0-9 ]+)(?:(?!^[A-Z0-9]+/)) but this returns VALUE KEY as the first result.

    Read the article

  • Regular expression to remove one parameter from query string

    - by Kip
    I'm looking for a regular expression to remove a single parameter from a query string, and I want to do it in a single regular expression if possible. Say I want to remove the foo parameter. Right now I use this: /&?foo\=[^&]+/ That works as long as foo is not the first parameter in the query string. If it is, then my new query string starts with an ampersand. (For example, "foo=123&bar=456" gives a result of "&bar=456".) Right now, I'm just checking after the regex if the query string starts with ampersand, and chopping it off if it does. Example edge cases: Input | Output -------------------------+----------------- foo=123 | (empty string) foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 Edit OK as pointed out in comments there are there are way more edge cases than I originally considered. I got the following regex to work with all of them: /&foo(\=[^&]*)?(?=&|$)|^foo(\=[^&]*)?(&|$)/ This is modified from Mark Byers's answer, which is why I'm accepting that one, but Roger Pate's input helped a lot too. Here is the full suite of test cases I'm using, and a Perl script which tests them. Input | Output -------------------------+------------------- foo | foo&bar=456 | bar=456 bar=456&foo | bar=456 abc=789&foo&bar=456 | abc=789&bar=456 foo= | foo=&bar=456 | bar=456 bar=456&foo= | bar=456 abc=789&foo=&bar=456 | abc=789&bar=456 foo=123 | foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 xfoo | xfoo xfoo&bar=456 | xfoo&bar=456 bar=456&xfoo | bar=456&xfoo abc=789&xfoo&bar=456 | abc=789&xfoo&bar=456 xfoo= | xfoo= xfoo=&bar=456 | xfoo=&bar=456 bar=456&xfoo= | bar=456&xfoo= abc=789&xfoo=&bar=456 | abc=789&xfoo=&bar=456 xfoo=123 | xfoo=123 xfoo=123&bar=456 | xfoo=123&bar=456 bar=456&xfoo=123 | bar=456&xfoo=123 abc=789&xfoo=123&bar=456 | abc=789&xfoo=123&bar=456 foox | foox foox&bar=456 | foox&bar=456 bar=456&foox | bar=456&foox abc=789&foox&bar=456 | abc=789&foox&bar=456 foox= | foox= foox=&bar=456 | foox=&bar=456 bar=456&foox= | bar=456&foox= abc=789&foox=&bar=456 | abc=789&foox=&bar=456 foox=123 | foox=123 foox=123&bar=456 | foox=123&bar=456 bar=456&foox=123 | bar=456&foox=123 abc=789&foox=123&bar=456 | abc=789&foox=123&bar=456 Test script (Perl) @in = ('foo' , 'foo&bar=456' , 'bar=456&foo' , 'abc=789&foo&bar=456' ,'foo=' , 'foo=&bar=456' , 'bar=456&foo=' , 'abc=789&foo=&bar=456' ,'foo=123' , 'foo=123&bar=456' , 'bar=456&foo=123' , 'abc=789&foo=123&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); @exp = ('' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); print "Succ | Input | Output | Expected \n"; print "-----+--------------------------+--------------------------+-------------------------\n"; for($i=0; $i <= $#in; $i++) { $out = $in[$i]; $out =~ s/_PUT_REGEX_HERE_//; $succ = ($out eq $exp[$i] ? 'PASS' : 'FAIL'); #if($succ eq 'FAIL') #{ printf("%s | %- 24s | %- 24s | %- 24s\n", $succ, $in[$i], $out, $exp[$i]); #} }

    Read the article

  • Silverlight 4 application failing to build in Blend 4 Beta..

    - by loyalpenguin
    Hi, I'm creating a simple silverlight application using Silverlight 4 and Expression Blend 4 Beta, but when I run the Application I get the following Error: C:\Users\WebDevelop1\Documents\Expression\Blend 4 Beta\Projects\SilverlightApplication1\SilverlightApplication1.sln.metaproj : error MSB4126: The specified solution configuration "Debug|HPD" is invalid. Please specify a valid solution configuration using the Configuration and Platform properties (e.g. MSBuild.exe Solution.sln /p:Configuration=Debug /p:Platform="Any CPU") or leave those properties blank to use the default solution configuration. Done building project "SilverlightApplication1.sln" -- FAILED. Build failed. I'm relatively new to silverlight and not really sure where to start. This has happened with every project I have created in Blend, but when I run it in VS2010 it runs perfect. Is this a known issue with the Beta release or am I possibly missing something? Thanks in advance.

    Read the article

< Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >