Search Results

Search found 2945 results on 118 pages for 'reverse tunnel'.

Page 32/118 | < Previous Page | 28 29 30 31 32 33 34 35 36 37 38 39  | Next Page >

• Django: reverse lookup URL of feeds?

  - by Santa

  I am having trouble doing a reverse URL lookup for Django-generated feeds. I have the following setup in urls.py: feeds = { 'latest': LatestEntries, } urlpatterns = patterns('', # ... # enable feeds (RSS) url(r'^feeds/(?P<url>.*)/$', 'django.contrib.syndication.views.feed', {'feed_dict': feeds}, name='feeds_view'), ) I have tried using the following template tag: <a href="{% url feeds_view latest %}">RSS feeds</a> But the resulting link is not what want (http://my.domain.com/feeds//). It should be http://my.domain.com/feeds/latest/. For now, I am using a hack to generate the URL for the template: <a href="http://{{ request.META.HTTP_HOST }}/feeds/latest">RSS feeds</a> But, as you can see, it clearly is not DRY. Is there something I am missing?

  Read the article

• How to find the longest contiguous subsequence whose reverse is also a subsequence

  - by iecut

  Suppose I have a sequence x1,x2,x3.....xn, and I want to find the longest contiguous subsequence xi,xi+1,xi+2......xi+k, whose reverse is also a subsequence of the given sequence. And if there are multiple such subsequences, then I also have to find the first. ex:- consider the sequences: abcdefgedcg here i=3 and k=2 aabcdddd here i=5, k=3 I tried looking at the original longest common subsequence problem, but that is used to compare the two sequences to find the longest common subsequence.... but here is only one sequence from which we have to find the subsequences. Please let me know what is the best way to approach this problem, to find the optimal solution.

  Read the article

• How to find the longest continuous subsequence whose reverse is also a subsequence

  - by iecut

  Suppose I have a sequence x1,x2,x3.....xn, and I want to find the longest continuous subsequence xi,xi+1,xi+2......xi+k, whose reverse is also a subsequence of the given sequence. And if there are multiple such subsequences, then I also have to find the first. ex:- consider the sequences: abcdefgedcg here i=3 and k=2 aabcdddd here i=5, k=3 I tried looking at the original longest common subsequence problem, but that is used to compare the two sequences to find the longest common subsequence.... but here is only one sequence from which we have to find the subsequences. Please let me know what is the best way to approach this problem, to find the optimal solution.

  Read the article

• Using key().id() on GAE Datastore and reverse geocoding

  - by Ivan Slaughter

  I have 6000 data of district, subdistrict. I need to represent this on dependent dropdown. The datamodel is for example; class Location(db.Model): location_name = db.StringProperty() location_parent = db.IntegerProperty() location_parent is reference to key() or id()? Still cannot decide which one is good. When i use key() as reference then using JSON to create jquery dependent drop down. My page loading/query and rendering time the dropdown is quite slow? Can i use key().id() as drop down option value to lighten up the page load? Any better solution for this parent/child reference for the drop down? For example: for the district record/entities the location-parent is null, for sub district record location_name will contain reference to parent district record. Other issue is to reverse geocoding the location to store or display geoPoint (lat,long)? Is google MAP API always find the exact lat,long of specific region boundaries or any error checking for the result?

  Read the article

• reverse colortransform alpha AS3

  - by Chris Porter

  I'm fading out a Bitmap in AS3 by repeatedly applying a ColorTransform every frame to its BitmapData; _bitmap.colorTransform(_bitmap.rect, new ColorTransform(1, 1, 1, .9, 0, 0, 0, 1)); When applying the apparent reverse to fade it back in I get a discoloured image. _bitmap.colorTransform(_bitmap.rect, new ColorTransform(1, 1, 1, 1.1, 0, 0, 0, 1)); The problem appears to occur only to fully faded-out images. If I only go part way it is recoverable. fading out: faded back

  Read the article

• doctrine behaviors , if i did it like this , would be correct ??

  - by tawfekov

  Hi , I am doing a web application in ZF + Doctrine 1.2.3 but i had an old database , it had pretty good structure so i think i can reverse engineer it with doctrine commad ./dcotrine generate-models-db , its amazing but i stopped when i wanted to use some doctrine behaviors like : searchable as an example , my question : if i went to my model and added these two lines : $this->actAs('Searchable', array( 'fields' => array('title', 'content') ) ); i am not sure if that enough and would work as expected , if you had any more tips about creating other behaviors like (versionable , i18n , sluggable or soft delete ) manually or reverse engineer it with doctrine behaviors , could you please list them

  Read the article

• PHP regex help -- reverse search?

  - by Ian Silber

  So, I have a regex that searches for HTML tags and modifies them slightly. It's working great, but I need to do something special with the last closing HTML tag I find. Not sure of the best way to do this. I'm thinking some sort of reverse reg ex, but haven't found a way to do that. Here's my code so far: $html = "<div id="test"><p style="hello_world">This is a test.</p></div>"; $pattern = array('/<([A-Z][A-Z0-9]*)(\b[^>]*)>/i'); $replace = array('<tag>'); $html = preg_replace($pattern,$replace,$html); // Outputs: <tag><tag>This is a test</p></div> I'd like to replace the last occurance of "" with something special, say for example, "". Any ideas?

  Read the article

• paket drop and splits in udp tunnel

  - by sr-dusad

  hi guys ! Currently I am working on video conferencing project.For this i m using pwnat for nat traversing. pwnat is based on udp tunneling.I m using the TCP connection for data transmission. My problem is that when i send a packet , it does not reach properly at its destination side . Sometime it drops the packet and many times it breaks ( split ) the packet into pieces. Please Help me .. How can i send and recieve a packet into single piece. So, i can draw image properly and play sound. Any kind of help will be appriciated . Thanks in advance

  Read the article

• Best way to reverse bitmap data that is upside down

  - by Wladimir

  Hello, I have a method that I call and it returns bitmap data from a capture device. It returns a pointer to the buffer data as an IntPtr and the buffer length as an int. I know in advance that this bitmap is a 24bpp and its width and height. The problem is that the buffer contains the bitmap data upside down and I need this data to be in the right order (reverse it). What I do is create a for loop and using CopyMemory, I copy each line (stride) of this data from bottom to up to a newly allocated memory space. Is there any way to make it faster than creating more memory each time I receive a new frame? It makes the application get a bit slow and consumes more memory as each bitmap is pretty big. I do this because I use another component that analyses the bitmaps and it doesn't work propertly if the bitmaps are upside down. I'm using .net, c# thanks!

  Read the article

• How to create list of numbers and append its reverse to it efficiently in Ruby

  - by Kiwi

  Given a minimum integer and maximum integer, I want to create an array which counts from the minimum to the maximum by two, then back down (again by two, repeating the maximum number). For example, if the minimum number is 1 and the maximum is 9, I want [1, 3, 5, 7, 9, 9, 7, 5, 3, 1]. I'm trying to be as concise as possible, which is why I'm using one-liners. In Python, I would do this: range(1, 10, 2) + range(9, 0, -2) In Ruby, which I'm just beginning to learn, all I've come up with so far is: (1..9).inject([]) { |r, num| num%2 == 1 ? r << num : r }.reverse.inject([]) { |r, num| r.unshift(num).push(num) } Which works, but I know there must be a better way. What is it?

  Read the article

• NTLM Authentication fails ONLY with IE against 2k8 App server behind 2k8 IIS7 Reverse Proxy

  - by CptSkippy

  I'm developing an ASP.NET application for an intranet site that is using Windows/NTLM/WIA/whatever authentication. The application is hosted on a Windows 2k8 server but is accessed through a Reverse Proxy using IIs7 on another 2k8 machine. Authentication works fine in FireFox, Chrome and Safari but fails in IE8. If I circumvent the Proxy and access the application server directly then it works fine so it has something to do with proxy. There's nothing in the Event Viewer on any of the 3 machines to indicate what might be happening. If you connect using IE8 it prompts for your credentials instead of automatically passing them, yes I've setup an explicit trust over an above the domain trust, but it still errors out with a 401 error returned from the proxy. Any ideas where to start troubleshooting this?

  Read the article

• Howto Plot "Reverse" Cumulative Frequency Graph With ECDF

  - by neversaint

  I have no problem plotting the following cumulative frequency graph plot like this. library(Hmisc) pre.test <- rnorm(100,50,10) post.test <- rnorm(100,55,10) x <- c(pre.test, post.test) g <- c(rep('Pre',length(pre.test)),rep('Post',length(post.test))) Ecdf(x, group=g, what="f", xlab='Test Results', label.curves=list(keys=1:2)) But I want to show the graph in forms of the "reverse" cumulative frequency of values x ? (i.e. something equivalent to what="1-f"). Is there a way to do it? Other suggestions in R other than using Hmisc are also very much welcomed.

  Read the article

• Torrents: Can I protect my software by sending wrong bytes?

  - by Martijn Courteaux

  Hi, It's a topic that everyone interests. How can I protect my software against stealing, hacking, reverse engineering? I was thinking: Do my best to protect the program for reverse engineering. Then people will crack it and seed it with torrents. Then I download my own cracked software with a torrent with my own torrent-software. My own torrent-software has then to seed incorrect data (bytes). Of course it has to seed critical bytes. So people who want to steal my software download my wrong bytes. Just that bytes that are important to startup, saving and loading data, etc... So if the stealer download from me (and seed it later) can't do anything with it, because it is broken. Is this idea relevant? Maybe, good torrent-clients check hashes from more peers to check if the packages (containing my broken bytes) I want to seed are correct or not? Thanks

  Read the article

• How can I reverse ruby's include function.

  - by Glen

  I'll explain what i'm looking for in code as thats probably the most succinct: module Mixin def method puts "Foo" end end class Whatever include Mixin end w = Whatever.new w.method => "Foo" # some magic here w2 = Whatever.new w.method => NoMethodError I had tried just undefining the Mixin module using remove_const, but this doesn't seem to make any difference to Whatever. I had assumed that #include just added a reference to the module into the class's method resolution chain - but this behaviour doesn't agree with that. Can anyone tell me what include actually does behind the scenes, and how to reverse this?

  Read the article

• recursively reverse linked list.

  - by Amanda

  I am implementing a function to recursively reverse a linked-list, but getting seg-fault. typedef struct _node { int data; struct _node *next; } Node, *NodeP; NodeP recursiveReverseList(NodeP first){ if(first == NULL) return NULL; if(first->next == NULL) return head; NodeP rest = recursiveReverseList(head->next); rest->next = first; first->next = NULL; return first; } Can you please help. P.S. The iterative version is working fine though. Its not homework. Just practicing C.

  Read the article

• Creating a New Reverse Java Array

  - by mandir08

  Given an array of ints length 3, return a new array with the elements in reverse order, so {1, 2, 3} becomes {3, 2, 1}. public int[] reverse3(int[] nums) { int[] values = new int[3]; for(int i=0; i<=nums.length-1; i++) { for(int j=nums.length-1; j>=0; j--) { values[i]=nums[j]; } } return values; } I cant get this to work properly, usually the last int in the array, becomes every single int in the new array

  Read the article

• info about intel Cos embedded i86 os

  - by Tim Williscroft

  I've got some old Intel printer (Etherexpress XL ) print servers and they seem to be running an Intel OS called Cos aka Intel Client Os i86 I've found out that much just looking in the update files from Intel. It was at least partly written in C. How do I make a custom software image Intel Cos's boot loader will understand ? I know a host PC xmodem's the image to the client device, and I was wondering if anyone had already either reverse-engineered this or had original info ? or is my only recousre to reverse engineer the update file format ?

  Read the article

• Core Data not-reverse relationship subquery

  - by user561485

  Hi, I have the following entities in CoreData: Village - villageID Bookmark - (relation) village There are multiple villages with each an unique villageID. I have a entity Bookmark which only has a relation to a Village entity; it isn't possible to make a reverse relation. Now I would like to get the village entities where there exists a Bookmark relation. I've red something about subqueries, but I can't get it right for this situation. It must be something like: Village.villageID IN (Bookmark.village.villageID) It isn't possible to get first all the Bookmarks and then loop to get all the Villages, because of the design of the framework. Can this be done in CoreData (I presume the answer is "Yes, of course!") and how?

  Read the article

• undo or reverse argsort(), python

  - by Vincent

  Given an array 'a' I would like to sort the array by columns "a.sort(axis=0)" do some stuff to the array and then undo the sort. By that I don't mean re sort but basically reversing how each element was moved. I assume argsort() is what I need but it is not clear to me how to sort an array with the results of argsort() or more importantly apply the reverse/inverse of argsort() Here is a little more detail I have an array a, shape(a) = rXc I need to sort each column aargsort = a.argsort(axis=0) # May use this later aSort = a.sort(axis=0) now average each row aSortRM = asort.mean(axis=1) now replace each col in a row with the row mean. is there a better way than this aWithMeans = ones_like(a) for ind in range(r) # r = number of rows aWithMeans[ind]* aSortRM[ind] Now I need to undo the sort I did in the first step. ????

  Read the article

• How to reverse a dictionary that it has repeated values (python)

  - by Galois

  Hi guys! So, I have a dictionary with almost 100,000 (key, values) pairs and the majority of the keys map to the same values. For example imagine something like that: dict = {'a': 1, 'c': 2, 'b': 1, 'e': 2, 'd': 3, 'h': 1, 'j': 3} What I want to do, is to reverse the dictionary so that each value in dict is going to be a key at the reverse_dict and is going to map to a list of all the dict.keys that used to map to that value at the dict. So based on the example above I would get: reversed_dict = {1: ['a', 'b', 'h'], 2:['e', 'c'] , 3:['d', 'j']} I came up with a solution that is very expensive and I would really want to hear any ideas more efficient than mine. my expensive solution: reversed_dict = {} for value in dict.values(): reversed_dict[value] = [] for key in dict.keys(): if dict[key] == value: if key not in reversed_dict[value]: reversed_dict[value].append(key) Output >> reversed_dict = {1: ['a', 'b', 'h'], 2: ['c', 'e'], 3: ['d', 'j']} I would really appreciate to hear any ideas better and more efficient than than mine. Thanks!

  Read the article

• Error while trying to reverse a char array

  - by mpminnich

  Hi, I'm trying to get better at C++ (I know a little). I'm working on character arrays. I found an exercise where the objective is to reverse a character array (after I convert it from an integer). I'm getting the following error (using VS2005): Run-Time Check Failure #2 - Stack around the variable 'revBuffer' was corrupted. When I step through the code, I notice the following: revBuffer = 0x0012fe40 "100899ÌÌÌÌÌÌÌÌÌÌ998001" The relevant code is below. char buffer[5]; char revBuffer[5]; int i; int j=5; long number = 998001; itoa(number, buffer, 10); for(i=0; i<strlen(buffer);i++) { revBuffer[j] = buffer[i]; j--; } Any help would be great. TIA!

  Read the article

• question on reverse array

  - by davit-datuashvili

  we know algorithm how reverse array of n integers for (int i=0;i<n/2;i++){ swap(a[i],a[n-1-i]): } is this method better according the speed of algorithm or not because swap using xor is more fast then in other method here is code public class swap { public static void main(String[]args){ int a[]=new int[]{2,4,5,7,8,11,13,12,14,24}; System.out.println(" array at the begining:"); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } for (int j=0;j<a.length/2;j++){ a[j]^=a[a.length-1-j]; a[a.length-1-j]^=a[j]; a[j]^=a[a.length-1-j]; } System.out.println("reversed array:"); for (int j=0;j<a.length;j++){ System.out.println(a[j]); } } } Result: array at the begining: 2 4 5 7 8 11 13 12 14 24 reversed array: 24 14 12 13 11 8 7 5 4 2

  Read the article

• Error while trying to reverse a char array in C++

  - by mpminnich

  Hi, I'm trying to get better at C++ (I know a little). I'm working on character arrays. I found an exercise where the objective is to reverse a character array (after I convert it from an integer). I'm getting the following error (using VS2005): Run-Time Check Failure #2 - Stack around the variable 'revBuffer' was corrupted. When I step through the code, I notice the following: revBuffer = 0x0012fe40 "100899ÌÌÌÌÌÌÌÌÌÌ998001" The relevant code is below. char buffer[5]; char revBuffer[5]; int i; int j=5; long number = 998001; itoa(number, buffer, 10); for(i=0; i<strlen(buffer);i++) { revBuffer[j] = buffer[i]; j--; } Any help would be great. TIA!

  Read the article

• DNS lookup failures while accessing my website some proxy error

  - by Bond

  Here is a situation until today morning,every thing has been working perfectly fine with me. From past 6 months many of my domains wer accessible as http://site1.myserver.com http://site2.myserver.com http://site3.myserver.com http://site4.myserver.com All these were Reverse Proxy configurations. I have some applications on each of them. until today morning some people reported me that http://site1.myserver.com/app1 is not working but http://site1.myserver.com is accessible but http://site2.myserver.com is accessible but http://site3.myserver.com is accessible but http://site4.myserver.com not accessible In past 6 months I have not changed any of these Apache configurations (things were working perfectly so) The error which can be seen in browser are while accessing http://site1.myserver.com/app1 Proxy Error The proxy server received an invalid response from an upstream server. The proxy server could not handle the request GET /app1. Reason: DNS lookup failure for: myserver.com and same is the error for http://site4.myserver.com So what should I check in I have checked all the apache logs to an extent which I could see and 192.168.1.25 - - [10/Jan/2011:14:50:48 +0530] "GET /app1 HTTP/1.1" 502 531 "-" "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3" Mon Jan 10 14:27:42 2011] [error] (113)No route to host: proxy: HTTP: attempt to connect to 192.168.1.3:80 (192.168.1.3) failed [Mon Jan 10 14:27:42 2011] [error] ap_proxy_connect_backend disabling worker for (192.168.1.3) [Mon Jan 10 14:27:44 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:44 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:44 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:45 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:46 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:47 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:48 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:48 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:27:48 2011] [error] proxy: HTTP: disabled connection for (192.168.1.3) [Mon Jan 10 14:35:29 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:35:30 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:35:30 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:50:30 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 [Mon Jan 10 14:50:48 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: myserver.com returned by /app1 and for site4.myserver.com I get [Mon Jan 10 14:57:40 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 14:57:40 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 14:57:43 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 15:02:38 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by / [Mon Jan 10 15:03:04 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:03:04 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 15:03:08 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:03:08 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /favicon.ico [Mon Jan 10 15:03:10 2011] [error] [client <some external IP>] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:06:21 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by / [Mon Jan 10 15:06:31 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /, referer: http://site4.myserver.com/ [Mon Jan 10 15:26:03 2011] [error] [client 192.168.1.25] proxy: DNS lookup failure for: site4.myserver.com returned by /

  Read the article

• what's wrong with my Ubuntu 11.10 bind9 configuration?

  - by John Bowlinger

  I've followed several tutorials on installing your own nameservers and I'm pretty much at my wit's end, because I cannot get them to resolve. Note, the actual domain and ip address has been changed for privacy to example.com and 192.168.0.1. My named.conf.local file: zone "example.com" { type master; file "/var/cache/bind/example.com.db"; }; zone "0.168.192.in_addr.arpa" { type master; file "/var/cache/bind/192.168.0.db"; }; My named.conf.options file: options { forwarders { 192.168.0.1; }; auth-nxdomain no; # conform to RFC1035 listen-on-v6 { any; }; }; My resolv.conf file: search example.com. nameserver 192.168.0.1 My Forward DNS file: ORIGIN example.com. $TTL 86400 @ IN SOA ns1.example.com. root.example.com. ( 2012083101 ; Serial 604800 ; Refresh 86400 ; Retry 2419200 ; Expire 3600 ) ; Negative Cache TTL example.com. NS ns1.example.com. example.com. NS ns2.example.com. example.com. MX 10 mail.example.com. @ IN A 192.168.0.1 ns1.example.com IN A 192.168.0.1 ns2.example.com IN A 192.168.0.2 mail IN A 192.168.0.1 server1 IN A 192.168.0.1 gateway IN CNAME ns1.example.com. headoffice IN CNAME server1.example.com. smtp IN CNAME mail.example.com. pop IN CNAME mail.example.com. imap IN CNAME mail.example.com. www IN CNAME server1.example.com. sql IN CNAME server1.example.com. And my reverse DNS: $ORIGIN 0.168.192.in-addr.arpa. $TTL 86400 @ IN SOA ns1.example.com. root.example.com. ( 2009013101 ; Serial 604800 ; Refresh 86400 ; Retry 2419200 ; Expire 3600 ) ; Negative Cache TTL 1 PTR mail.example.com. 1 PTR server1.example.com. 2 PTR ns1.example.com. Yet, when I restart bind9 and do: host ns1.example.com localhost I get: Using domain server: Name: localhost Address: 127.0.0.1#53 Aliases: Host ns1.example.com.example.com not found: 2(SERVFAIL) Similarly, for: host 192.168.0.1 localhost I get: ;; connection timed out; no servers could be reached Anybody know what's going on? Btw, my domain name "www.example.com" that I've used in this question is being forwarded to my ISP's nameservers. Would that affect my bind9 configuration? I want to learn how to do set up nameservers on my own for learning, so that is why I'm going through all this trouble.

  Read the article

< Previous Page | 28 29 30 31 32 33 34 35 36 37 38 39  | Next Page >