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  • Python: Problem Importing Function From Another Module

    - by Rafid K. Abdullah
    I have a module called nbemail.py and in this module I want to use the function package_post defined in the module main.py. I am using this statement: from api.main import package_post But I am getting this error: ImportError: cannot import name package_post I really don't know why I am getting this error! I do have _init_.py files in the api directory (which contains the files nbemail.py and main.py) and I do have the function package_post defined in main.py. Any idea to help fixing this problem?

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  • associating a filetype with a batch script, and getting parameters passed to file of that type.

    - by Carson Myers
    Sorry for the cryptic title. I have associated python scripts with a batch file that looks like this: python %* I did this because on my machine, python is installed at C:\python26 and I prefer not to reinstall it (for some reason, it won't let me add a file association to the python interpreter. I can copy the executable to Program Files and it works -- but nothing out of Program Files seems to work). Anyways, I can do this, so far: C:\py django-admin C:\py python "C:\python26\Lib\site-packages\django\bin\django-admin.py" Type 'django-admin.py help' for usage. C:\py django-admin startproject myProj C:\py python "C:\python26\Lib\site-packages\django\bin\django-admin.py" Type 'django-admin.py help' for usage. but the additional parameters don't get passed along to the batch script. This is getting very annoying, all I want to do is run python scripts :) How can I grab the rest of the parameters in this situation?

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  • Is there a performance gain from defining routes in app.yaml versus one large mapping in a WSGIAppli

    - by jgeewax
    Scenario 1 This involves using one "gateway" route in app.yaml and then choosing the RequestHandler in the WSGIApplication. app.yaml - url: /.* script: main.py main.py from google.appengine.ext import webapp class Page1(webapp.RequestHandler): def get(self): self.response.out.write("Page 1") class Page2(webapp.RequestHandler): def get(self): self.response.out.write("Page 2") application = webapp.WSGIApplication([ ('/page1/', Page1), ('/page2/', Page2), ], debug=True) def main(): wsgiref.handlers.CGIHandler().run(application) if __name__ == '__main__': main() Scenario 2: This involves defining two routes in app.yaml and then two separate scripts for each (page1.py and page2.py). app.yaml - url: /page1/ script: page1.py - url: /page2/ script: page2.py page1.py from google.appengine.ext import webapp class Page1(webapp.RequestHandler): def get(self): self.response.out.write("Page 1") application = webapp.WSGIApplication([ ('/page1/', Page1), ], debug=True) def main(): wsgiref.handlers.CGIHandler().run(application) if __name__ == '__main__': main() page2.py from google.appengine.ext import webapp class Page2(webapp.RequestHandler): def get(self): self.response.out.write("Page 2") application = webapp.WSGIApplication([ ('/page2/', Page2), ], debug=True) def main(): wsgiref.handlers.CGIHandler().run(application) if __name__ == '__main__': main() Question What are the benefits and drawbacks of each pattern? Is one much faster than the other?

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  • Django, url tag in template doesn't work: NoReverseMatch

    - by Lukasz Jocz
    I've encountered a problem with generating reverse url in templates in django. I'm trying to solve it since a few hours and I have no idea what the problem might be. URL reversing works great in models and views: # like this in models.py @models.permalink def get_absolute_url(self): return ('entry', (), { 'entry_id': self.entry.id, }) # or this in views.py return HttpResponseRedirect(reverse('entry',args=(entry_id,))) but when I'm trying to make it in template I get such an error: NoReverseMatch at /entry/1/ Reverse for ''add_comment'' with arguments '(1L,)' and keyword arguments '{}' not found. My file structure looks like this: project/ +-- frontend ¦   +-- models.py ¦   +-- urls.py ¦   +-- views.py +-- settings.py +-- templates ¦   +-- add_comment.html ¦   +-- entry.html +-- utils ¦   +-- with_template.py +-- wsgi.py My urls.py: from project.frontend.views import * from django.conf.urls import patterns, include, url urlpatterns = patterns('project.frontend.views', url(r'^entry/(?P<entry_id>\d+)/', 'entry', name="entry"), (r'^entry_list/', 'entry_list'), Then entry_list.html: {% extends "base.html" %} {% block content %} {% for entry in entries %} {% url 'entry' entry.id %} {% endfor %} {% endblock %} In views.py I have: @with_template def entry(request, entry_id): entry = Entry.objects.get(id=entry_id) entry.comments = entry.get_comments() return locals() where with_template is following decorator(but I don't think this is a case): class TheWrapper(object): def __init__(self, default_template_name): self.default_template_name = default_template_name def __call__(self, func): def decorated_func(request, *args, **kwargs): extra_context = kwargs.pop('extra_context', {}) dictionary = {} ret = func(request, *args, **kwargs) if isinstance(ret, HttpResponse): return ret dictionary.update(ret) dictionary.update(extra_context) return render_to_response(dictionary.get('template_name', self.default_template_name), context_instance=RequestContext(request), dictionary=dictionary) update_wrapper(decorated_func, func) return decorated_func if not callable(arg): return TheWrapper(arg) else: default_template_name = ''.join([ arg.__name__, '.html']) return TheWrapper(default_template_name)(arg) Do you have any idea, what may cause the problem? Great thanks in advance!

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  • How to make Chrome open bookmarks and URLs in new tabs?

    - by MBraedley
    I principally use Firefox both at home and at work, but on occasion I use Chrome. I have Firefox working the way I like it by having it open bookmarks in a new tab when left clicked, as well, URLs open in new tabs. Although having URLs open in a new tab can be annoying if I type a bad URL, I still prefer it, but that's neither here nor there. I would like to replicate this behaviour in Chrome, and can't seem to find anything relavent in the settings. Is there any way of doing this without an extension? If not, can you point me towards an appropriate extension (I've already done a search and can't find what I'm looking for)?

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  • Django tutorial says I haven't set DATABASE_ENGINE setting yet... but I have

    - by Joe
    I'm working through the Django tutorial and receiving the following error when I run the initial python manage.py syncdb: Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 362 in execute_manager utility.execute() File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 351, in handle return self.handle_noargs(**options) File "/Library/Python/2.6/site-packages/django/core/management/commands/syncdb.py", line 49, in handle_noargs cursor = connection.cursor() File "/Library/Python/2.6/site-packages/django/db/backends/dummy/base.py", line 15, in complain raise ImproperlyConfigured, "You haven't set the DATABASE_ENGINE setting yet." django.core.exceptions.ImproperlyConfigured: You haven't set the DATABASE_ENGINE setting yet. My settings.py looks like: DATABASES = { 'default': { 'ENGINE': 'django.db.backends.mysql', # Add 'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'. 'NAME': 'dj_tut', # Or path to database file if using sqlite3. 'USER': '', # Not used with sqlite3. 'PASSWORD': '', # Not used with sqlite3. 'HOST': '', # Set to empty string for localhost. Not used with sqlite3. 'PORT': '', # Set to empty string for default. Not used with sqlite3. } } I'm guessing this is something simple, but why isn't it seeing the ENGINE setting?

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  • Python accessing modules from package that is distributed over different directories

    - by chaindriver
    Hi, I have a question regarding one single module that is distributed over multiple directories. Let's say I have these two file and directories: ~/lib/python xxx __init__.py util __init__.py module1.py module2.py ~/graphics/python xxx __init__.py misc __init__.py module3.py module4.py So then in my Python modules, I did this: import sys pythonlibpath = '~/lib/python' if pythonlibpath not in sys.path: sys.path.append(pythonlibpath) import xxx.util.module1 which works. Now, the problem is that I need xxx.misc.module3, so I did this: import sys graphicslibpath = '~/graphics/python' if graphicslibpath not in sys.path: sys.path.append(graphicslibpath) import xxx.misc.module3 but I get this error: ImportError: No module named misc.module3 It seems like it somehow still remembers that there was a xxx package in ~/lib/python and then tries to find misc.module3 from there. How do I get around this issue?

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  • How to make Chrome open bookmarks and URLs in new tabs?

    - by MBraedley
    I principally use Firefox both at home and at work, but on occasion I use Chrome. I have Firefox working the way I like it by having it open bookmarks in a new tab when left clicked, as well, URLs open in new tabs. Although having URLs open in a new tab can be annoying if I type a bad URL, I still prefer it, but that's neither here nor there. I would like to replicate this behaviour in Chrome, and can't seem to find anything relavent in the settings. Is there any way of doing this without an extension? If not, can you point me towards an appropriate extension (I've already done a search and can't find what I'm looking for)?

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  • Django: Create custom template tag -> ImportError

    - by Alexander Scholz
    I'm sorry to ask this again, but I tried several solutions from stack overflow and some tutorials and I couldn't create a custom template tag yet. All I get is ImportError: No module named test_tag when I try to start the server via python manage.py runserver. I created a very basic template tag (found here: django templatetag?) like so: My folder structure: demo manage.py test __init__.py settings.py urls.py ... templatetags __init__.py test_tag.py test_tag.py: from django import template register = template.Library() @register.simple_tag def test_tag(input): if "foo" == input: return "foo" if "bar" == input: return "bar" if "baz" == input: return "baz" return "" index.html: {% load test_tag %} <html> <head> ... </head> <body> {% cms_toolbar %} {% foobarbaz "bar" %} {% foobarbaz "elephant" %} {% foobarbaz "foo" %} </body> </html> and my settings.py: INSTALLED_APPS = ( ... 'test_tag', ... ) Please let me know if you need further information from my settings.py and what I did wrong so I can't even start my server. (If I delete 'test_tag' from installed apps I can start the server but I get the error that test_tag is not known, of course). Thanks

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  • Python: NameError: 'self' is not defined

    - by Rosarch
    I must be doing something stupid. I'm running this in Google App Engine: def render(self, template_name, template_data): path = os.path.join(os.path.dirname(__file__), 'static/templates/%s.html' % template_name) self.response.out.write(template.render(path, template_data)) This gives an error: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3192, in _HandleRequest self._Dispatch(dispatcher, self.rfile, outfile, env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3135, in _Dispatch base_env_dict=env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 516, in Dispatch base_env_dict=base_env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2394, in Dispatch self._module_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2304, in ExecuteCGI reset_modules = exec_script(handler_path, cgi_path, hook) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2200, in ExecuteOrImportScript exec module_code in script_module.__dict__ File "main.py", line 22, in <module> class MainHandler(webapp.RequestHandler): File "main.py", line 38, in MainHandler self.writeOut(template.render(path, template_data)) NameError: name 'self' is not defined What am I doing wrong?

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  • Importing package as a submodule

    - by wecac
    Hi, I have a package 3rd party open source package "foo"; that is in beta phase and I want to tweak it to my requirements. So I don't want to get it installed in /usr/local/lib/python or anywhere in current sys.path as I can't make frequent changes in top level packages. foo/ __init__.py fmod1.py import foo.mod2 fmod2.py pass I want to install the the package "foo" as a sub package of my namespace say "team.my_pkg". So that the "fullname" of the package becomes "team.my_pkg.foo" without changing the code in inner modules that refer "team.my_pkg.foo" as "foo". team/ __init__.py my_pkg/ __init__.py foo/ fmod1.py import foo.mod2 fmod2.py pass One way to do this is to do this in team.my_pkg.init.py: import os.path import sys sys.path.append(os.path.dirname(__file__)) But I think it is very unsafe. I hope there is some way that only fmod1.py and fmod2.py can call "foo" by its short name everything else should use its complete name "team.my_pkg.foo" I mean this should fail outside team/my_pkg/foo: import team.my_pkg import foo But this should succeed outside team/my_pkg/foo: import team.my_pkg.foo

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  • Python NameError when attempting to use a user-defined class

    - by Michael Herold
    I'm getting a weird instance of a NameError when attempting to use a class I wrote. In a directory, I have the following file structure: dir/ ReutersParser.py test.py reut-xxx.sgm Where my custom class is defined in ReutersParser.py and I have a test script defined in test.py. The ReutersParser looks something like this: from sgmllib import SGMLParser class ReutersParser(SGMLParser): def __init__(self, verbose=0): SGMLParser.__init__(self, verbose) ... rest of parser if __name__ == '__main__': f = open('reut2-short.sgm') s = f.read() p = ReutersParser() p.parse(s) It's a parser to deal with SGML files of Reuters articles. The test works perfectly. Anyway, I'm going to use it in test.py, which looks like this: from ReutersParser import ReutersParser def main(): parser = ReutersParser() if __name__ == '__main__': main() When it gets to that parser line, I'm getting this error: Traceback (most recent call last): File "D:\Projects\Reuters\test.py", line 34, in <module> main() File "D:\Projects\Reuters\test.py", line 19, in main parser = ReutersParser() File "D:\Projects\Reuters\ReutersParser.py", line 38, in __init__ SGMLParser.__init__(self, verbose) NameError: global name 'sgmllib' is not defined For some reason, when I try to use my ReutersParser in test.py, it throws an error that says it cannot find sgmllib, which is a built-in module. I'm at my wits' end trying to figure out why the import won't work. What's causing this NameError? I've tried importing sgmllib in my test.py and that works, so I don't understand why it can't find it when trying to run the constructor for my ReutersParser.

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  • How can I set clean urls (enable rewrite) if I don't have a domain ?

    - by Patrick
    In order to enable clean urls in Drupal, I add the lines below to the lighttpd configuration file. However I'm now working on a local server and I don't have a domain available. So I need to work with this address http://local.ip/Sites/mywebsite I've tried to replace ["host"] with ["socket"] and replace the domain with ip and subfolders (see address above), but unsuccessfully. How can I set the configuration file to set clean urls even if I don't have a domain ? thanks $HTTP["host"] =~ "(^|\.)mywebsite\.com" { server.document-root = "/var/www/sites/mywebsite" server.errorlog = "/var/log/lighttpd/mywebsite/error.log" server.name = "mywebsite.com" accesslog.filename = "/var/log/lighttpd/mywebsite/access.log" include_shell "./drupal-lua-conf.sh mywebsite.com" url.access-deny += ( "~", ".inc", ".engine", ".install", ".info", ".module", ".sh", "sql", ".theme", ".tpl.php", ".xtmpl", "Entries", "Repository", "Root" ) # "Fix" for Drupal SA-2006-006, requires lighttpd 1.4.13 or above # Only serve .php files of the drupal base directory $HTTP["url"] =~ "^/.*/.*\.php$" { fastcgi.server = () url.access-deny = ("") } magnet.attract-physical-path-to = ("/etc/lighttpd/drupal-lua-scripts/p-.lua") }

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  • How do I get vmbuilder to progress?

    - by Avery Chan
    I've used the following command to create my vm: vmbuilder kvm ubuntu --verbose --suite=precise --flavour=virtual --arch=amd64 -o --libvirt=qemu:///system --tmpfs=- --ip=192.168.2.1 --part=/home/shared/vm1/vmbuilder.partition --templates=/home/shared/vm1/templates --user=vadmin --name=VM-Administrator --pass=vpass --addpkg=vim-nox --addpkg=unattended-upgrades --addpkg=acpid --firstboot=/home/shared/vm1/boot.sh --mem=256 --hostname=chameleon --bridge=br0 I've been trying to follow the direction here. My system just outputs this and it hangs at the last line: 2012-06-26 18:08:29,225 INFO : Mounting tmpfs under /tmp/tmpJbf1dZtmpfs 2012-06-26 18:08:29,234 INFO : Calling hook: preflight_check 2012-06-26 18:08:29,243 INFO : Calling hook: set_defaults 2012-06-26 18:08:29,244 INFO : Calling hook: bootstrap How can I get vmbuilder to continue the process instead of dying right here? I'm running 12.04. EDIT: Adding some additional output details When I ^C to get out of the hang I see this: ^C2012-06-26 18:19:29,622 INFO : Unmounting tmpfs from /tmp/tmpJbf1dZtmpfs Traceback (most recent call last): File "/usr/bin/vmbuilder", line 24, in <module> cli.main() File "/usr/lib/python2.7/dist-packages/VMBuilder/contrib/cli.py", line 216, in main distro.build_chroot() File "/usr/lib/python2.7/dist-packages/VMBuilder/distro.py", line 83, in build_chroot self.call_hooks('bootstrap') File "/usr/lib/python2.7/dist-packages/VMBuilder/distro.py", line 67, in call_hooks call_hooks(self, *args, **kwargs) File "/usr/lib/python2.7/dist-packages/VMBuilder/util.py", line 165, in call_hooks getattr(context, func, log_no_such_method)(*args, **kwargs) File "/usr/lib/python2.7/dist-packages/VMBuilder/plugins/ubuntu/distro.py", line 136, in bootstrap self.suite.debootstrap() File "/usr/lib/python2.7/dist-packages/VMBuilder/plugins/ubuntu/dapper.py", line 269, in debootstrap run_cmd(*cmd, **kwargs) File "/usr/lib/python2.7/dist-packages/VMBuilder/util.py", line 113, in run_cmd fds = select.select([x.file for x in [mystdout, mystderr] if not x.closed], [], [])[0]

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  • Duplicate content issue after URL-change with 301-redirects

    - by David
    We got the following problem: We changed all URLs on our page from oldURL.html to newURL.html and set up 301-redirects (ca. 600 URLs) Google re-crawled our page, indexed all the new URLs (newURL.html), but didn't crawl the old URLs (oldURL.html) again, as there were no internal links pointing at those domains anymore after the URL-change. This resulted in massive ranking-drops, etc. because (i) Google thought oldURL.html has exactly the same content as newURL, causing duplicate content issues, and (ii) Google did not transfer the juice from oldURL to newURL, because the 301-redirect was never noticed. Now we reset all internal Links to the old URLs again, which then redirect to the newURLs, in the hope that Google would re-crawl the pages, once there are internal links pointing at them. This is partially happening, but at a really low speed, so it would take multiple months to notice all-redirects. I guess, because Google thinks: "Aah, I already know oldURL.html, so no need to re-crawl it. Possible solutions we thought of are ... Submitting as many of the old URLs to the index as possible via Webmaster Tools, to manually trigger a crawl. Doing that already Submitting a sitemap with all old URLs - but not sure if good idea, because Google does not seem to like 301-redirects in a sitemap ... Both solutions are not perfect - and we cannot wait for three months, just to regain our old rankings. What are your ideas? Best, David

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  • Can Ubuntu-One be installed on Ubuntu 10.04?

    - by crivello
    I have installed ubuntu-one by the several ways on a 10.04-TLS, it appears on my System Preference Ubuntu One. however, Clicking one it , nothing happens. On a terminal, the command : ~$ ubuntuone-launch doe not working too, and the following command ~$ ubuntuone-preferences leads to an error message, given below, that made me crazy. Does somebody has an idea one a solution to solve that ? Many thanks. \jcc Traceback (most recent call last): File "/usr/bin/ubuntuone-preferences", line 63, in <module> from desktopcouch.replication_services import ubuntuone as dcouch File "/usr/lib/python2.6/dist-packages/desktopcouch/__init__.py", line 20, in <module> from desktopcouch.start_local_couchdb import process_is_couchdb, read_pidfile File "/usr/lib/python2.6/dist-packages/desktopcouch/start_local_couchdb.py", line 38, in <module> from desktopcouch import local_files File "/usr/lib/python2.6/dist-packages/desktopcouch/local_files.py", line 300, in <module> xdg_base_dirs.save_config_path("desktop-couch")) File "/usr/lib/python2.6/dist-packages/desktopcouch/local_files.py", line 235, in __init__ self.couch_exec_command = [COUCH_EXE, self.couch_chain_ini_files(), File "/usr/lib/python2.6/dist-packages/desktopcouch/local_files.py", line 274, in couch_chain_ini_files stdout=subprocess.PIPE) File "/usr/lib/python2.6/subprocess.py", line 633, in __init__errread, errwrite) File "/usr/lib/python2.6/subprocess.py", line 1139, in _execute_child raise child_exception OSError: [Errno 13] Permission denied

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  • juju bootstrap key error?

    - by mxdog
    I followed the guides the best as i could. there is some information missing like do as root or as regular user ..formatting, quotes no quotes..what the password or paraphrase for ssh should be ..couple other trivial things. that im sure add up to where im at (stuck!) so i have a working mass server on mx-nas-01 and 3 nodes and have been trying to get juju to start. I have tried this as both root and my regular account, sudo no-sudo and here is the output i get from juju bootstrap (however i try it) I don't know if this could be a host,domain,account issue or what i will mention i did have to shut off my dhcp server and install masq (all defaults) to get the maas pxe to work for the nodes mxdog@mx-nas-01:/$ juju bootstrap Traceback (most recent call last): File "/usr/bin/juju", line 8, in main(sys.argv[1:]) File "/usr/lib/python2.7/dist-packages/juju/control/init.py", line 183, in main env_config.load_or_write_sample() File "/usr/lib/python2.7/dist-packages/juju/environment/config.py", line 229, in load_or_write_sample self.load() File "/usr/lib/python2.7/dist-packages/juju/environment/config.py", line 115, in load self.parse(file.read(), path) File "/usr/lib/python2.7/dist-packages/juju/environment/config.py", line 138, in parse config = SCHEMA.coerce(config, []) File "/usr/lib/python2.7/dist-packages/juju/lib/schema.py", line 266, in coerce new_dict[k] = self.schema[k].coerce(v, path) File "/usr/lib/python2.7/dist-packages/juju/lib/schema.py", line 233, in coerce new_subvalue = self.value_schema.coerce(subvalue, value_path) File "/usr/lib/python2.7/dist-packages/juju/lib/schema.py", line 301, in coerce return self.schemas[selected].coerce(value, path) KeyError: 'mass' environments: maas: type: mass mass-server: http://192.168.0.30:80/MAAS mass-oauth: tDRdtJeEKVARBh93eT:N5dK5HSZBsA45cBdx9:S8wMNrfkT9PeYvQN9YrnbHGxmKARv8vb admin-secret: ########## default-series: precise

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  • Can't install software by terminal

    - by behnam mohammadi
    I don't know what packages i have installed that i no longer can get and install packages in terminal. e.g. when trying to install Prozgui, i got this error: Traceback (most recent call last): File "/usr/bin/add-apt-repository", line 60, in <module> sp = SoftwareProperties() File "/usr/lib/python2.7/dist-packages/softwareproperties/SoftwareProperties.py", line 90, in __init__ self.reload_sourceslist() File "/usr/lib/python2.7/dist-packages/softwareproperties/SoftwareProperties.py", line 538, in reload_sourceslist self.distro.get_sources(self.sourceslist) File "/usr/lib/python2.7/dist-packages/aptsources/distro.py", line 91, in get_sources raise NoDistroTemplateException("Error: could not find a " aptsources.distro.NoDistroTemplateException: Error: could not find a distribution template and it happens for all others too. Plus, my Software Center has been disabled and doesn't start. I get this error for that too: Traceback (most recent call last): File "/usr/bin/software-center", line 111, in <module> from softwarecenter.app import SoftwareCenterApp File "/usr/share/software-center/softwarecenter/app.py", line 40, in <module> from softwarecenter.db.application import Application, DebFileApplication File "/usr/share/software-center/softwarecenter/db/application.py", line 30, in <module> from softwarecenter.distro import get_distro File "/usr/share/software-center/softwarecenter/distro/__init__.py", line 151, in <module> distro_instance=_get_distro() File "/usr/share/software-center/softwarecenter/distro/__init__.py", line 140, in _get_distro module = __import__(distro_id, globals(), locals(), [], -1) ImportError: No module named OPTIMOS Can anyone please help me with this? Thank you in advance!

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  • Using local repository with vmbuilder and https

    - by Onitlikesonic
    I seem to be having problems using vmbuilder with a local https mirror "--mirror=https:///archive.ubuntu.com/ubuntu/" as shown below: Process (['/usr/sbin/debootstrap', '--arch=amd64', 'precise', '/tmp/tmpYc0cOktmpfs', '<my_internal_server>/ubuntu/']) returned 1. stdout: I: Retrieving Release E: Failed getting release file <my_internal_server>/ubuntu/dists/precise/Release , stderr: 2012-10-18 10:36:36,429 INFO : Unmounting tmpfs from /tmp/tmpYc0cOktmpfs Traceback (most recent call last): File "/usr/bin/vmbuilder", line 24, in <module> cli.main() File "/usr/lib/python2.7/dist-packages/VMBuilder/contrib/cli.py", line 216, in main distro.build_chroot() File "/usr/lib/python2.7/dist-packages/VMBuilder/distro.py", line 83, in build_chroot self.call_hooks('bootstrap') File "/usr/lib/python2.7/dist-packages/VMBuilder/distro.py", line 67, in call_hooks call_hooks(self, *args, **kwargs) File "/usr/lib/python2.7/dist-packages/VMBuilder/util.py", line 165, in call_hooks getattr(context, func, log_no_such_method)(*args, **kwargs) File "/usr/lib/python2.7/dist-packages/VMBuilder/plugins/ubuntu/distro.py", line 136, in bootstrap self.suite.debootstrap() File "/usr/lib/python2.7/dist-packages/VMBuilder/plugins/ubuntu/dapper.py", line 269, in debootstrap run_cmd(*cmd, **kwargs) File "/usr/lib/python2.7/dist-packages/VMBuilder/util.py", line 120, in run_cmd raise VMBuilderException, "Process (%s) returned %d. stdout: %s, stderr: %s" % (args.__repr__(), status, mystdout.buf, mystderr.buf) VMBuilder.exception.VMBuilderException: Process (['/usr/sbin/debootstrap', '--arch=amd64', 'precise', '/tmp/tmpYc0cOktmpfs', '<my_internal_server>/ubuntu/']) returned 1. stdout: I: Retrieving Release E: Failed getting release file <my_internal_server>/ubuntu/dists/precise/Release , stderr: I've checked that the files are in the correct place and i'm able to setup this using http instead of https. However this server will be providing https access only to the repos, the http is only temporarily open. This might be due to the certificate not being valid on the https (since it's self signed) or due to the fact that vmbuilder doesn't support https? In either case how can i get this to work? (If it's the case of the invalid certificate I don't mind ignoring any checks)

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  • Quickly ubuntu-application + indicator template don't work

    - by aliasbody
    I've started to work with quickly and python (because I wanted to have some GTk3 integration and create and appindicator), and so I create the projecto like this : quickly create ubuntu-application ualarm cd ualarm quickly run And the application launched. But then I tried to add the appindicator like this : quickly add indicator And since then the application doesn't start anymore and this error appear : aliasbody@BodyUbuntu-PC:~/Projectos/ualarm$ quickly run (ualarm:8515): Gtk-WARNING **: Theme parsing error: gnome-panel.css:28:11: Not using units is deprecated. Assuming 'px'. /usr/lib/python2.7/dist-packages/gi/overrides/Gtk.py:391: Warning: g_object_set_property: construct property "type" for object `Window' can't be set after construction Gtk.Window.__init__(self, type=type, **kwds) Traceback (most recent call last): File "bin/ualarm", line 33, in <module> ualarm.main() File "/home/aliasbody/Projectos/ualarm/ualarm/__init__.py", line 33, in main window = UalarmWindow.UalarmWindow() File "/home/aliasbody/Projectos/ualarm/ualarm_lib/Window.py", line 35, in __new__ new_object.finish_initializing(builder) File "/home/aliasbody/Projectos/ualarm/ualarm/UalarmWindow.py", line 24, in finish_initializing super(UalarmWindow, self).finish_initializing(builder) File "/home/aliasbody/Projectos/ualarm/ualarm_lib/Window.py", line 75, in finish_initializing self.indicator = indicator.new_application_indicator(self) File "/home/aliasbody/Projectos/ualarm/ualarm/indicator.py", line 52, in new_application_indicator ind = Indicator(window) File "/home/aliasbody/Projectos/ualarm/ualarm/indicator.py", line 20, in __init__ self.indicator = AppIndicator3.Indicator('ualarm', '', AppIndicator3.IndicatorCategory.APPLICATION_STATUS) TypeError: GObject.__init__() takes exactly 0 arguments (3 given) How can I solve this problem ?

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  • Why do some websites add "Slugs" to the end of URLs?

    - by Dave Webb
    Many websites, including this one, add what are apparently called slugs - descriptive but as far as I can tell useless bits of text - to the end of URLs. For example, the URL the site gives for this question is: http://stackoverflow.com/questions/47427/why-do-some-websites-add-slugs-to-the-end-of-urls But the following URL works just as well: http://stackoverflow.com/questions/47427/ Is the point of this text just to somehow make the URL more user friendly or are there some other benefits?

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  • What is the best way to format Django urls for two parameters, either of which are optional?

    - by Parker
    I'm designing a gallery application for viewing vehicle pictures and there are two parameters: Manufacturer Vehicle type Right now you can view either, but not both. Urls go like so: /manufacturer/# /type/# Where # is an ID number. How/can I format my URLs so it can accept both? My current solution is to do: /both/#/# but this requires some retooling since the application doesn't know when you want to filter by both. Any insight would be appreciated.

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