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  • Testing if string is sha1 in PHP

    - by SGWebsNow
    I'm planning on storing the passwords as a sha1, so I need a way to validate that it is a sha1 at another point in my website. I was planning on using preg_match, but I do not know how to make regex patterns. Could someone help me out with one? Thanks

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  • php - How do I get rid of this strange "empty delimiter" message

    - by Steven
    I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

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  • PHP turn off errors - in one file only

    - by Industrial
    Hi! I am well aware about error_reporting(0); & ini_set('display_errors', "Off"); to make error messages go away. What would be an appropriate way to do this - for a specific file or part of code only? Surpressing errors with @'s seems like a bad idea since it apparently slows the code down... Thanks!

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  • PHP string parsing

    - by tmatthews
    I am trying to parse a list of operating system instances with their unique identifiers. I am looking for a solution to parse a text string, and pass the values into two variables. The string to be parsed is as followed: "Ubuntu 9.10" {40f2324d-a6b2-44e4-90c3-0c5fa82c987d}

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  • downloading security related problem in php

    - by pareek-rohit
    hi i have to upload a video.but i want to gives permission only authenticate user to download .but i have a problem in that.because if any body type the video detail in browser.(ex http://sitename/folder_name/videoname) then browser download that video.but i don't want this .please suggest me how can i resolve this problem.either i should generate the video name randomly or make a temporary folder in which video reside only for specific time,after this video will be delete. Or if any other ideas you have please let me know Thanks in advance

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  • Create a PHP cache system in MySQL database?

    - by Zach Smith
    I'm creating a web service that often scrapes data from remote web pages. After scraping this data, I have a simple multidimensional array of information to use. The scraping process is fairly taxing on my server, and the page load takes a while. I was considering adding a simple cache system using a MySQL database, where I create one row per remote web page with a the array of information pulled from it stored as a JSON encoded string. Is this a good enough system? Or would something like a text file per web page be a better idea?

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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  • PHP : If...Else...Query

    - by Rachel
    I am executing this statement under while (($data=fgetcsv($this->fin,5000,";"))!==FALSE) Now what I want in else loop is to throw exception only for data value which did not satisfy the if condition. Right now am displaying the complete row as I am not sure how to throw exception only for data which does not satisfy the value. Code if ((strtotime($data[11]) &&strtotime($data[12])&&strtotime($data[16]))!==FALSE && ctype_digit($data[0]) && ctype_alnum($data[1]) && ctype_digit($data[2]) && ctype_alnum($data[3]) && ctype_alnum($data[4]) && ctype_alnum($data[5]) && ctype_alnum($data[6]) && ctype_alnum($data[7]) && ctype_alnum($data[8]) && $this->_is_valid($data[9]) && ctype_digit($data[10]) && ctype_digit($data[13]) && $this->_is_valid($data[14])) { //Some Logic } else { throw new Exception ("Data {$data[0], $data[1], $data[2], $data[3], $data[4], $data[5], $data[6], $data[7], $data[8], $data[9], $data[10], $data[11], $data[12], $data[13], $data[14], $data[16]} is not in valid format"); } Guidance would be highly appreciated as to how can I throw exception only for data which did not satisfy the if value.

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  • PHP Multiple form tokens

    - by Juddling
    I understand the idea of generating a form token and storing it in a session, and also putting it as a hidden input in my forms. But how could I make this work if I have pages with multiple forms, is it still safe to use the same token for each form? And I still feel weary about bots and stuff on my website, can these form tokens really safely replace CAPTCHAs?

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  • REST Authentication in PHP (CodeIgniter)

    - by zidane
    I writing REST API form my web application. Application is written using CodeIgniter framework. Application itself is working fine, but I'm stuck on making REST Authentication. I think that basic Http Authentication will be good enough for some time. Public API is not yet planned. Is there any code example how to achieve REST Authentication so after user is authenticated he can freely call all protected methods.

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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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  • Add a + sign to a +ve number in PHP

    - by user318466
    I need to design a function to return -ve numbers unchanged but should add a + sign at the start of the number if its alreay no present. Example: Input Output ---------------- +1 +1 1 +1 -1 -1 It will get only numeric input. function formatNum($num) { # something here..perhaps a regex? } This function is going to be called several times in echo/print so the quicker the better.

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  • Mail php function does'nt send the email

    - by Mamadou
    Hello everybody, I have the following code wich work on some server and does not work in an other: $Name = "myname"; //senders name $email_sender = "[email protected]"; //senders e-mail adress $recipient = $email; //recipient $mail_body = "The text for the mail..."; //mail body $subject = "Subject for reviever"; //subject $header = "From: ". $Name . " <" . $email_sender . ">\r\n"; $status = mail($recipient, $subject, $mail_body, $header); print('ENVOI '. $status); the $status variable is true but i dont see any email.

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  • Merge array in a different way in PHP

    - by user2984974
    I have these two arrays: $array1 = array( '0' => 'apple', '1' => '' , '2' => 'cucumber' ); $array2 = array( '0' => '', '1' => 'bmw', '2' => 'chrysler' ); if I do this to merge these arrays: $result_arr = array_merge($array1, $array2); print_r( count ( array_filter($result_arr) ) ); the output would be 4. However, I need to get the number 3. So, when there are two things on the same position (same key) count it only once. Is it possible to merge/count elements in arrays like that?

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  • How can I "flip" an image using PHP?

    - by learner
    Here's what I've tried: $image = "images/20100609124341Chrysanthemum.jpg"; $degrees = 40; // Content type header('Content-type: image/jpeg'); // Load $source = imagecreatefromjpeg($filename); // Rotate $rotate = imagerotate($source, $degrees, 0); // Output imagejpeg($rotate); ...But I get no output. Can anyone tell me what's wrong with this?

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • login/logout problem in PHP

    - by user356170
    i have a question. I have a website in which i am giving security like login id and password( as usual). No what i want is that, 1) I don't want to allow a single user to login in different machine at the same time. 2) For this i am using a column in database which is keeping the current status of user(i.e. loging/logout). I am allowing user to login only when has session has not closed and status is login. 3) So my problem is that when i am logging out manually. it is closing the session as well as updating the database with status "logout". 4) but when i am closing the window from Cross buttonat top right corner. it is closing the ssion but table data is still "login". so later on i can't be able to login into the same user. 5) So how could i solve this problem. Please help me!

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • PHP - Patterns within Arrays

    - by Toby
    I am trying to create a function which maps a recurring pattern of integers using an array. As an example if I have a starting array of (0,1,3) and I know that I want to stop the pattern when I hit 15. The pattern gets incremented by a fixed integer each time (lets say 4) so my final pattern should be.. 0 1 3 4 (0 + 4) 5 (1 + 4) 7 (2 + 4) 8 (4 + 4) 9 (5 + 4) 11(7 + 4) 12(8 + 4) 13(9 + 4) 15(11+ 4) Does anyone have any pointers on how this can be achieved? My current implementation works but is stupidly inefficient which something like this... $array = array(0,1,3); $inc = 4; $end = end($array); $final = 15; while($end < $final) { $tmp = array(); foreach($array AS $row) { $tmp = $row + $inc; } $array = merge($tmp, $array); $end = end($array); }

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