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  • PHP Datediff days involved

    - by user3549835
    I need to know how many days are involved in a date diff. \For example: <? $start = new DateTime('2014-06-29 14:00:00'); $ende = new DateTime('2014-07-02 05:45:00'); $diff = $start->diff($ende); echo $diff->format('%R'); echo $diff->days; ?> The above code echos +2 My desired result would be 4, because the 29th, 30th, 1st and 2nd of July are "touched". I have no idea to achieve that with the given functions. Coding a day-subtraction seems to bean open door for errors.

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  • PHP Array - some further problems with displaying elements in the array

    - by Homer_J
    Hi again, Thanks in advance for the help. Here is my array based on $rowq: Array ( [0] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [1] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [2] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [3] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [4] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [5] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [6] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [7] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) ) I would like to display elements of the array using (i think) the foreach statement but I can't get it working, ideally, I would like to echo something like this echo "<tr>".$rowq[qnum]." is the questions number and the question text is ".$rowq[qtext].". The page and q values are ".$rowq[page]." and ".$rowq[questions]." respectively."; And that link of text would appear how however many rows the array has in it. Any and all advice appreciated - I'm struggling like heck to get my head around multi-dimensional arrays :( Homer.

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  • PHP fails silently when function not defined?

    - by John Isaacks
    I am migrating from PHP4 to PHP5 I have this in my .htaccess: php_flag display_errors on php_value error_reporting 2039 Which used to show all errors. I am still getting some errors but I used to get an error when I called a function that was not defined, but now it stops where it is at and send the client everything up to the error and nothing after. With no error message. Here is what phpinfo is telling me: Directive Local Value Master Value display_errors On Off error_reporting 2039 6143 I would like to be able to see my error messages for trouble shooting purposes. Can someone tell me what I need to do? Thanks!!

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  • php - How do I get rid of this strange "empty delimiter" message

    - by Steven
    I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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  • PHP SimpleXML, how to set attributes ?

    - by Jahmaica
    Hi, if you've got something like, <hello id="1" name="myName1"> <anotherTag title="Hello"> </anotherTag> </hello> <hello id="2" name="myName2"> <anotherTag title="Hi"> </anotherTag> </hello> How to change the attributes of, for example, hello id 2, to name="William" ? Or the title hi to hello ? Thanks a lot for your atention, H'

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  • case insensitive highlighting in php

    - by fusion
    i'm using this function to highlight the results from mysql query: function highlightWords($string, $word) { $string = str_replace($word, "<span class='highlight'>".$word."</span>", $string); /*** return the highlighted string ***/ return $string; } .... $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); the problem is, if i type in 'good', it will only show my search results with a lower-case 'g'ood and not 'Good'. how do i rectify this?

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  • How to write ½ in php

    - by skarama
    Hi everyone, Quick question, how can I make this valid : if($this->datos->bathrooms == "1½"){$select1 = JText::_( 'selected="selected"' );} The ½ doesn't seem to be recognized. I tried to write it as &#189; but then it looks for &#189; literally, and not the ½ sign. Any ideas?

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • Add multiple IF tags in php

    - by Andy
    Hi , I would like to add this condition : {if $profile.sex == 1 || $profile.sex == 4} {/if} To this code : case 'friendlist': if ( app_Features::isAvailable( 14 ) ) { $_output = '<div class="memhome_link">'; $_output.= '<a href="'.SK_Navigation::href( 'profile_friend_list' ).'" '.$class.'>'.$lang_section->text( 'href_my_friendlist').'</a>'; $_output.= ' ('.app_FriendNetwork::countFriends( SK_HttpUser::profile_id() ).')'; $_output.= '</div>'; } break; Can anybody give me any help , please ? Thanks for all the help .

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  • read XML tag id from php

    - by Sakthivel
    Hi friends i am have the following XML file <?xml version="1.0" encoding="iso-8859-1"?> <Message Id="Language">German</Message> <Message Id="LangEnglish">German</Message> <Message Id="TopMakeHomepage"> Mache 4W Consulting Webseite zu deiner Starseite! </Message> <Message Id="TopLinkEmpSec"> 4W Mitarbeiter </Message> <Message Id="TopLinkFeedback"> Feedback </Message> <Message Id="TopLinkSiteMap"> Site Map </Message> <Message Id="TopLinkContactUs"> Kontakt </Message> <Message Id="TopSetLangEn"> ins Englische </Message> <Message Id="TopSetLangDe"> ins Deutsche </Message> <Message Id="TopSetLangEs"> ins Spanische </Message> <Message Id="MenuLinks"> !~|4W Starseite|Company|Über uns|Kontakt|4W anschließen|Services|Kunden Software Entwicklung|Altsystem Neugestalltung &amp; Umwandlung|Altsystem Dokumentation|Daten Umwandlung &amp; Migration|Erstellen von Datenbeschreibungsverzeichnis|System- &amp; Anwendungs Support|Projekt Management &amp; Planunng|Personal Erweiterung|Projekt Ausgliederung|Mitarbeiter Ausbildung|Technologie|Intersystems Caché|M / MUMPS|Zusätzliche Technologien|Methodologie|Feedback|~! </Message> </MsgFile> in this XML file i need to fetch the contents using the tagid . Please help me to find out this . Thanks in advance

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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  • Mail php function does'nt send the email

    - by Mamadou
    Hello everybody, I have the following code wich work on some server and does not work in an other: $Name = "myname"; //senders name $email_sender = "[email protected]"; //senders e-mail adress $recipient = $email; //recipient $mail_body = "The text for the mail..."; //mail body $subject = "Subject for reviever"; //subject $header = "From: ". $Name . " <" . $email_sender . ">\r\n"; $status = mail($recipient, $subject, $mail_body, $header); print('ENVOI '. $status); the $status variable is true but i dont see any email.

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  • Merge array in a different way in PHP

    - by user2984974
    I have these two arrays: $array1 = array( '0' => 'apple', '1' => '' , '2' => 'cucumber' ); $array2 = array( '0' => '', '1' => 'bmw', '2' => 'chrysler' ); if I do this to merge these arrays: $result_arr = array_merge($array1, $array2); print_r( count ( array_filter($result_arr) ) ); the output would be 4. However, I need to get the number 3. So, when there are two things on the same position (same key) count it only once. Is it possible to merge/count elements in arrays like that?

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • Login system and sessions (php)

    - by Jonathan
    I've created a login page and registration page and now I want to use that to password protect pages and have pages which show information specific to that user. Would storing the user ID of the user logged in in a Session variable be a safe and correct way of doing this? How easy would it be for a user to change the session variable to a different ID and access another user's information, and not having to type the users login details in?

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  • login/logout problem in PHP

    - by user356170
    i have a question. I have a website in which i am giving security like login id and password( as usual). No what i want is that, 1) I don't want to allow a single user to login in different machine at the same time. 2) For this i am using a column in database which is keeping the current status of user(i.e. loging/logout). I am allowing user to login only when has session has not closed and status is login. 3) So my problem is that when i am logging out manually. it is closing the session as well as updating the database with status "logout". 4) but when i am closing the window from Cross buttonat top right corner. it is closing the ssion but table data is still "login". so later on i can't be able to login into the same user. 5) So how could i solve this problem. Please help me!

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  • PHP - Patterns within Arrays

    - by Toby
    I am trying to create a function which maps a recurring pattern of integers using an array. As an example if I have a starting array of (0,1,3) and I know that I want to stop the pattern when I hit 15. The pattern gets incremented by a fixed integer each time (lets say 4) so my final pattern should be.. 0 1 3 4 (0 + 4) 5 (1 + 4) 7 (2 + 4) 8 (4 + 4) 9 (5 + 4) 11(7 + 4) 12(8 + 4) 13(9 + 4) 15(11+ 4) Does anyone have any pointers on how this can be achieved? My current implementation works but is stupidly inefficient which something like this... $array = array(0,1,3); $inc = 4; $end = end($array); $final = 15; while($end < $final) { $tmp = array(); foreach($array AS $row) { $tmp = $row + $inc; } $array = merge($tmp, $array); $end = end($array); }

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  • php: parsing and converting array structure

    - by mwb
    I need to convert one array structure into another array structure. I hope someone will find it worthy their time to show how this could be done in a simple manner. It's a little above my array manipulation skills. The structure we start out with looks like this: $cssoptions = array( array( 'group' => 'Measurements' , 'selector' => '#content' , 'rule' => 'width' , 'value' => '200px' ) // end data set , array( 'group' => 'Measurements' , 'selector' => '#content' , 'rule' => 'margin-right' , 'value' => '20px' ) // end data set , array( 'group' => 'Colors' , 'selector' => '#content' , 'rule' => 'color' , 'value' => '#444' ) // end data set , array( 'group' => 'Measurements' , 'selector' => '.sidebar' , 'rule' => 'margin-top' , 'value' => '10px' ) // end data set ); // END $cssoptions It's a collection of discreet datasets, each consisting of an array that holds two key = value pairs describing a 'css-rule' and a 'css-rule-value'. Further, each dataset holds a key = value pair describing the 'css-selector-group' that the 'css-rule' should blong to, and a key = value pair describing a 'rule-group' that should be used for structuring the rendering of the final css into a neat css code block arranged by the kind of properties they describe (colors, measurement, typography etc..) Now, I need to parse that, and turn it into a new structure, where the: 'rule' => 'rule-name' , 'value' => 'value-string' for each dataset is converted into: 'rule-name' => 'value-string' ..and then placed into a new array structure where all 'rule-name' = 'value-string' pairs should be aggregated under the respective 'selector-values' Like this: '#content' => array( 'width' => '200px' , 'margin-right' => '20px' ) // end selecor block ..and finally all those blocks should be grouped under their respective 'style-groups', creating a final resulting array structure like this: $css => array( 'Measurements' => array( '#content' => array( 'width' => '200px' , 'margin-right' => '20px' ) // end selecor block , '.sidebar' => array( 'margin-top' => '10px' ) // end selector block ) // end rule group , 'Colors' => array( '#content' => array( 'color' => '#444' ) // end selector block ) // end rule group ); // end css

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  • Make HTTP/1.1 request with PHP

    - by ejunker
    My code is using file_get_contents() to make GET requests to an API endpoint. It looks like it is using HTTP/1.0 and my sysadmin says I need to use HTTP/1.1. How can I make an HTTP/1.1 request? Do I need to use curl or is there a better/easier way?

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