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  • PHP : apc_store doesn't work as intended

    - by Industrial
    Hi everyone, I have started to try APC to store some specific data on each webserver as an complement to memcached. However, the following code piece is giving me headaches: echo apc_store('key', 'value'); echo apc_store('key', 'newvalue'); echo apc_fetch('key'); Result: value Why is apc_store not working as properly?

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  • php won't detect all spaces in a string...

    - by user296516
    Hi guys, I've got a string that comes from a POST form where I want to replace all spaced with some other character. Here's that I did: $cdata = str_replace(" ","#",$cdata); And I got this. --- Contact-ID#=#148 [10274da8]#Sinhronizacija#=#private [1000137d]#Uzvards#=#Zom [1000137c]#Vards#=#Tana [1000130e]#Talrunis#=#3333 [1000130e]#Mobilais#=#5555 As you can see, spaced before "[10..." are still there. Any ideas what could be the problem?

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  • PHP loop position

    - by Jordan Pagaduan
    Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: $dbc = mysql_connect("localhost" , "root" , "") or die (mysql_error()); mysql_select_db('blog_data') or die (mysql_error()); $sql = "SELECT * FROM img_uploaded"; $result = mysql_query($sql); while($rows=mysql_fetch_array($result)) { if ($rows) { echo "<tr><td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td></tr>"; } else { echo "<td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td>"; } }

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  • How to display XML in HTML in PHP?

    - by tomaszs
    Hello, I have a string with XML: $string = " <shoes> <shoe> <shouename>Shoue</shouename> </shoe> </shoes> "; And would like display it on my website like this: This is XML string content: <shoes> <shoe> <shouename>Shoue</shouename> </shoe> </shoes> So I would like to do it: on site, not in textbox without external libraries, frameworks etc. formatted with proper new lines formatted with tabs without colors etc., only text So how to do it in plain and simple way?

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  • MySQL/PHP Search Efficiency

    - by iMaster
    Hi! I'm trying to create a small search for my site. I've tried using full-text index search, but I could never get it to work. Here is what I've come up with: if(isset($_GET['search'])) { $search = str_replace('-', ' ', $_GET['search']); $result = array(); $titles = mysql_query("SELECT title FROM Entries WHERE title LIKE '%$search%'"); while($row = mysql_fetch_assoc($titles)) { $result[] = $row['title']; } $tags = mysql_query("SELECT title FROM Entries WHERE tags LIKE '%$search%'"); while($row = mysql_fetch_assoc($tags)) { $result[] = $row['title']; } $text = mysql_query("SELECT title FROM Entries WHERE entry LIKE '%$search%'"); while($row = mysql_fetch_assoc($text)) { $result[] = $row['title']; } $result = array_unique($result); } So basically, it searches through all the titles, body-text, and tags of all the entries in the DB. This works decently well, but I'm just wondering how efficient would it be? This would only be for a small blog, too. Either way I'm just wondering if this could be made any more efficient.

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  • Super fast getimagesize in php

    - by Sir Lojik
    Hi all, im trying to get image size(DIMENSIONS) of hundreds of remote images and getimagesize is way too slow. ive done some reading and found out the quickest way would be to use get_file_contents to read a certain aount of bytes from the images and examining the size within the binary data. Anyone attempted this before? How would i examine different formats. Seen any library for this? please let me know

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • PHP - getting content of the POST request

    - by user364622
    I have problem with getting the content. I don't know the names of the post variables so I can't do this using = $_Post['name'] because I don't know the "name". I want to catch all of the variables send by POST method. How can I get keys of the $_Post[] array and the values related with them?

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  • PHP preg_match Math Function

    - by Matt
    I'm writing a script that will allow a user to input a string that is a math statement, to then be evaluated. I however have hit a roadblock. I cannot figure out how, using preg_match, to dissallow statements that have variables in them. Using this, $calc = create_function("", "return (" . $string . ");" ); $calc();, allows users to input a string that will be evaluated, but it crashes whenever something like echo 'foo'; is put in place of the variable $string.

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  • PHP Array - some further problems with displaying elements in the array

    - by Homer_J
    Hi again, Thanks in advance for the help. Here is my array based on $rowq: Array ( [0] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [1] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [2] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [3] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [4] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [5] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [6] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [7] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) ) I would like to display elements of the array using (i think) the foreach statement but I can't get it working, ideally, I would like to echo something like this echo "<tr>".$rowq[qnum]." is the questions number and the question text is ".$rowq[qtext].". The page and q values are ".$rowq[page]." and ".$rowq[questions]." respectively."; And that link of text would appear how however many rows the array has in it. Any and all advice appreciated - I'm struggling like heck to get my head around multi-dimensional arrays :( Homer.

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  • PHP uploads and checking

    - by user147685
    Hi all, I want to update/insert file by using upload box to the database but before that it will check for the file type thats only pdf can be upload. Somthing wrong with the codes and i dont know what..Please help here are part of my updates codes: $id=$rs['id']; $qry = "SELECT a.faillampiran FROM {$CFG->prefix}ptk_lampiran a, {$CFG->prefix}ptk b WHERE a.ptkid=$id and b.id=$id"; $sql = get_records_sql($qry); if($_POST['check']){ $ext = pathinfo($faillampiran,PATHINFO_EXTENSION); $err = "Upload Only PDF File. "; if ($ext =='pdf'){ $qry="UPDATE {$CFG->prefix}ptk_lampiran SET faillampiran='".$faillampiran."' WHERE ptkid='".$_GET['id']."'"; $sql=mysql_query($qry); $qry = "SELECT a.faillampiran FROM {$CFG->prefix}ptk_lampiran a, {$CFG->prefix}ptk b WHERE b.id = '".$rs[id]."' AND a.ptkid = '".$rs[id]."' "; $sql = get_records_sql($qry); foreach($sql as $rs){ ?> <?=basename($rs->faillampiran); ?><br> <? } ?> <tr><td></td><td></td><td> <input type="file" size="50" name="faillampiran" alt="faillampiran" value= "<?=$faillampiran;?>" /> <input type="submit" name="edit" value="Muat naik fail ini" /><br /> </td></tr> } else { echo "<script>alert('$err')</script>"; } } else { foreach($sql as $rs){ ?> <?=basename($rs->faillampiran); ?><br> <? } ?> <input type="file" size="50" name="faillampiran" alt="faillampiran" value= "<?=$faillampiran;?>" /> <input type="submit" name="edit" value="Muat naik fail ini" /><br /> <?} Sori bout the messiness of the codes, im still a beginner in this languages. thx

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  • generating images by user id php + mysql

    - by jay
    function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • Need help with transferring data between MySQL db's using PHP

    - by JM4
    In one of the sites I manage, the client has decided to take on ACH/Bank Account administration where it was previously outsourced. As a result, the information submitted in our online form which used to simply store in a single database for processing now must sit in 'limbo' until the funds used for payment have been verified. My original plan is as follows: At the end of an enrollment, all form data is collected and stored in a single MySQL database. Our internal administrator will receive an email notification reminding him enrollments have taken place. He will process the ACH information collected and wait the 3-4 business days needed for payment to clear. Once the payment information has been returned as Good (haven't considered what I will do with the 'bad' yet), the administrator can log into a secure portal which allows him to click a button to 'process' the full information once compared and verified. the process is simplified as: Enrollment complete: data stored in DB 'A' Funds verified and link clicked: data from 'A' is copied to DB 'B' and 'A' is deleted. I have run similar processes with CSV output before and simply used //transfers old data to archive $transfer = mysql_query('INSERT INTO '.$archive.' SELECT * FROM '.$table) or die(mysql_error()); //empties existing table $query = mysql_query('TRUNCATE TABLE '.$table) or die(mysql_error()); but in those cases, ALL data returned was copied and deleted. I only want to copy and delete a single record. Any idea how to accomplish this?

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  • PHP mail script html formatting

    - by Jimbly2
    someone kindly posted this code for me but it only returns in the resulting email - any ideas? Does it need a closing html tag? $mailHeader .= "Content-type: text/html; charset=iso-8859-1\r\n"; $formcontent ="<table border='1'>"; foreach ($_POST as $field=>$value) { $formcontent.="<tr>"; $formcontent .= "<td>$field:</td> <td>$value</td>"; $formcontent.="</tr>"; } $formcontent .= '<tr><td>User-Agent: </td><td>'.$_SERVER['HTTP_USER_AGENT'].'</td>'; $formcontent ="</table>"; Thanks, JIm

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  • What pattern is this? php

    - by user151841
    I have several classes that are basically interfaces to database rows. Since the class assumes that a row already exists ( __construct expects a field value ), there is a public static function that allows creation of the row and returns an instance of the class. Here's an example ( without the actual database inserts ): class selfStarter { public $type; public function __construct( $type ) { $this->type = $type; } public static function create( $type ) { if ( ! empty($type) ) { $starter = & new selfStarter($type); return $starter; } } } $obj1 = selfStarter::create( "apple" ); $obj2 = & new selfStarter( "banana" ); What is this pattern called?

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  • php array problem ..need expert

    - by user295189
    I have tried this in another post but trying my luck again. My current array that I am making produce a different result than I am wanting. I want to have this kind of out put Row: 0: Column: 1: ID 1 Row: 1: Column: 1: ID 1 Row: 0: Column: 2: ID 2 Row: 1: Column: 2: ID 2 Row: 2: Column: 2: ID 2 Row: 3: Column: 2: ID 2 Row: 0: Column: 3: ID 3 Row: 1: Column: 3: ID 3 As you can see the Rows and columns change based on the ID. So if the ID is same it just go to next row in the same column. However if id is changed it goes to next column and rows start. Currently I my code looks like this for($i=0;$i<count($pv->rawData); $i++) { $relative=0; $relativeTypeID = -1; if ($pv->rawData[$i]->relativeTypeID != $relativeTypeID) { $relativeTypeID = $pv->rawData[$i]->relativeTypeID; $iTypeCount++; } if(!empty($pv->rawData[$i]->description)) { $pv->results[$i][$iTypeCount][0] = $pv->rawData[$i]->description; echo "Row: ".$i.": Column: ".$iTypeCount.": ID".$relativeTypeID." <br>"; } } It gives me the following output Row: 0: Column: 1: ID1 Row: 1: Column: 2: ID1 Row: 2: Column: 3: ID2 Row: 3: Column: 4: ID2 Row: 4: Column: 5: ID2 Row: 5: Column: 6: ID2 Row: 6: Column: 7: ID2 Row: 7: Column: 8: ID2 Row: 8: Column: 9: ID2 Row: 9: Column: 10: ID2 Row: 10: Column: 11: ID2 Row: 11: Column: 12: ID2 Row: 12: Column: 13: ID2 …. …. As you can see the Row and Columns are changing but not with ID number. I appreciate your help Thanks

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  • How can I "flip" an image using PHP?

    - by learner
    Here's what I've tried: $image = "images/20100609124341Chrysanthemum.jpg"; $degrees = 40; // Content type header('Content-type: image/jpeg'); // Load $source = imagecreatefromjpeg($filename); // Rotate $rotate = imagerotate($source, $degrees, 0); // Output imagejpeg($rotate); ...But I get no output. Can anyone tell me what's wrong with this?

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