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  • Why are my \n not working in PHP?

    - by Strawberry
    I'm playing with SAX and noticed it's not line breaking properly. I have no iea why. function flush_data() { global $level, $char_data; $char_data = trim($char_data); if( strlen( $char_data ) > 0 ) { print "\n"; $data = split("\n", wordwrap($char_data, 76 - ($level*2))); foreach($data as $line) { print str_repeat(' ', ($level +1)) . "[".$line."]"."\n"; } } $char_data = ''; }

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  • Add multiple IF tags in php

    - by Andy
    Hi , I would like to add this condition : {if $profile.sex == 1 || $profile.sex == 4} {/if} To this code : case 'friendlist': if ( app_Features::isAvailable( 14 ) ) { $_output = '<div class="memhome_link">'; $_output.= '<a href="'.SK_Navigation::href( 'profile_friend_list' ).'" '.$class.'>'.$lang_section->text( 'href_my_friendlist').'</a>'; $_output.= ' ('.app_FriendNetwork::countFriends( SK_HttpUser::profile_id() ).')'; $_output.= '</div>'; } break; Can anybody give me any help , please ? Thanks for all the help .

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  • PHP fails silently when function not defined?

    - by John Isaacks
    I am migrating from PHP4 to PHP5 I have this in my .htaccess: php_flag display_errors on php_value error_reporting 2039 Which used to show all errors. I am still getting some errors but I used to get an error when I called a function that was not defined, but now it stops where it is at and send the client everything up to the error and nothing after. With no error message. Here is what phpinfo is telling me: Directive Local Value Master Value display_errors On Off error_reporting 2039 6143 I would like to be able to see my error messages for trouble shooting purposes. Can someone tell me what I need to do? Thanks!!

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  • How to escape $ in php using preg_replace ?

    - by sakura
    Hi, I am using preg_replace to escape special characters... $tmpStr=preg_replace("/\?/", "\?", $tmpStr); $tmpStr=preg_replace("/\#/", "\#", $tmpStr); $tmpStr=preg_replace("/\^/", "\^", $tmpStr); $tmpStr=preg_replace("/\&/", "\&", $tmpStr); $tmpStr=preg_replace("/\*/", "\*", $tmpStr); $tmpStr=preg_replace("/\(/", "\(", $tmpStr); $tmpStr=preg_replace("/\)/", "\)", $tmpStr); $tmpStr=preg_replace("/\//", "\/", $tmpStr); but i am not able to escape $ using the same function $tmpStr=preg_replace("/\$/", "\$", $tmpStr); and also when i use the above statement all the spaces get replaced by $ and $ is not getting escaped....someone please help me with this....

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  • php - Loop output in two diffrent divs?

    - by Stan
    I want to output my sql rows on each side of a line, without breaking the line. Forexample the html/css code i would like to end up with is something like this: <div id='container'> <div style='float:left;'> Even loops here.. </div> <div id='line' style='float:left;'> </div> <div style='float:right;'> Uneven loops here.. </div> <div style='clear:both;'></div> </div> Is there a way to output the sql rows in two diffrent divs?

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  • PHP Array - some further problems with displaying elements in the array

    - by Homer_J
    Hi again, Thanks in advance for the help. Here is my array based on $rowq: Array ( [0] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [1] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [2] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [3] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [4] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [5] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [6] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [7] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) ) I would like to display elements of the array using (i think) the foreach statement but I can't get it working, ideally, I would like to echo something like this echo "<tr>".$rowq[qnum]." is the questions number and the question text is ".$rowq[qtext].". The page and q values are ".$rowq[page]." and ".$rowq[questions]." respectively."; And that link of text would appear how however many rows the array has in it. Any and all advice appreciated - I'm struggling like heck to get my head around multi-dimensional arrays :( Homer.

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  • PHP GD Incredibly Strange Problem

    - by ThinkingInBits
    if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { die("success"); } if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { $image_width = imagesx($img); $image_height = imagesy($img); $target_width = 150; $target_height = 150; if ($image_width > $image_height) { $percentage = ($target_width / $image_width); } else { $percentage = ($target_height / $image_height); } $new_image_width = round($image_width * $percentage); $new_image_height = round($image_height * $percentage); $imgResized = imagecreatetruecolor($new_image_width, $new_image_height); imagecopyresampled($imgResized, $img, 0, 0, 0, 0, $new_image_width, $new_image_height, $image_width, $image_height); imagejpeg($imgResized, $this->path, 100); imagedestroy($img); imagedestroy($imgResized); $this->storeThumbnailLocation(); } else { die ("image was not created or saved"); } The first if statement dies and echos success. If I take out the first if statement, the second one echos "image could not be created or saved" If honestly run out of ideas on this one, the code is identical

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  • PHP Multiple form tokens

    - by Juddling
    I understand the idea of generating a form token and storing it in a session, and also putting it as a hidden input in my forms. But how could I make this work if I have pages with multiple forms, is it still safe to use the same token for each form? And I still feel weary about bots and stuff on my website, can these form tokens really safely replace CAPTCHAs?

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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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  • case insensitive highlighting in php

    - by fusion
    i'm using this function to highlight the results from mysql query: function highlightWords($string, $word) { $string = str_replace($word, "<span class='highlight'>".$word."</span>", $string); /*** return the highlighted string ***/ return $string; } .... $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); the problem is, if i type in 'good', it will only show my search results with a lower-case 'g'ood and not 'Good'. how do i rectify this?

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  • PHP: exif_imagetype() not working?

    - by Karem
    I have this extension checker: $upload_name = "file"; $max_file_size_in_bytes = 8388608; $extension_whitelist = array("jpg", "gif", "png", "jpeg"); /* checking extensions */ $path_info = pathinfo($_FILES[$upload_name]['name']); $file_extension = $path_info["extension"]; $is_valid_extension = false; foreach ($extension_whitelist as $extension) { if (strcasecmp($file_extension, $extension) == 0) { $is_valid_extension = true; break; } } if (!$is_valid_extension) { echo "{"; echo "error: 'ext not allowed!'\n"; echo "}"; exit(0); } And then i added this: if (exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_GIF OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_JPEG OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_PNG) { echo "{"; echo "error: 'This is no photo..'\n"; echo "}"; exit(0); } As soon when I added this to my imageupload function, the function stops working. I dont get any errors, not even the one i made myself "this is no photo", what could be wrong? Just checked with my host. They support the function exif_imagetype()

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  • php won't detect all spaces in a string...

    - by user296516
    Hi guys, I've got a string that comes from a POST form where I want to replace all spaced with some other character. Here's that I did: $cdata = str_replace(" ","#",$cdata); And I got this. --- Contact-ID#=#148 [10274da8]#Sinhronizacija#=#private [1000137d]#Uzvards#=#Zom [1000137c]#Vards#=#Tana [1000130e]#Talrunis#=#3333 [1000130e]#Mobilais#=#5555 As you can see, spaced before "[10..." are still there. Any ideas what could be the problem?

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  • PHP Session Array Value keeps showing as "Array"

    - by Nerathas
    Hello, When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number. The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array. (A 2-Dimensional Table is used) Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ? $test1 = $_SESSION["table"][0]; $test2 = $_SESSION["table"][1]; $test3 = $_SESSION["table"][2]; $test4 = $_SESSION["table"][3]; $test5 = $_SESSION["table"][4]; What exactly is this, and how can i fix this? Is it some sort of override that needs to happen? Best Regards.

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  • php - How do I get rid of this strange "empty delimiter" message

    - by Steven
    I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • Php dynamic class construction

    - by pistacchio
    Hi to all, I'm trying to avoid the use of eval. I can dynamically instantiate a class like this: class myclass {} $my_class_name = 'myclass'; $obj = new $myclass(); If the constructor is like follows: class myclass { public function __construct( $argument1, $argument2 ) {} } and i have the values of the arguments in an array, how can i dynamically instantiate the class and pass it dynamic arguments? Mind that I have no way to modify the class, so I have to work on the way of using it. Thanks

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  • PHP mail script html formatting

    - by Jimbly2
    someone kindly posted this code for me but it only returns in the resulting email - any ideas? Does it need a closing html tag? $mailHeader .= "Content-type: text/html; charset=iso-8859-1\r\n"; $formcontent ="<table border='1'>"; foreach ($_POST as $field=>$value) { $formcontent.="<tr>"; $formcontent .= "<td>$field:</td> <td>$value</td>"; $formcontent.="</tr>"; } $formcontent .= '<tr><td>User-Agent: </td><td>'.$_SERVER['HTTP_USER_AGENT'].'</td>'; $formcontent ="</table>"; Thanks, JIm

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  • Mail php function does'nt send the email

    - by Mamadou
    Hello everybody, I have the following code wich work on some server and does not work in an other: $Name = "myname"; //senders name $email_sender = "[email protected]"; //senders e-mail adress $recipient = $email; //recipient $mail_body = "The text for the mail..."; //mail body $subject = "Subject for reviever"; //subject $header = "From: ". $Name . " <" . $email_sender . ">\r\n"; $status = mail($recipient, $subject, $mail_body, $header); print('ENVOI '. $status); the $status variable is true but i dont see any email.

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  • downloading security related problem in php

    - by pareek-rohit
    hi i have to upload a video.but i want to gives permission only authenticate user to download .but i have a problem in that.because if any body type the video detail in browser.(ex http://sitename/folder_name/videoname) then browser download that video.but i don't want this .please suggest me how can i resolve this problem.either i should generate the video name randomly or make a temporary folder in which video reside only for specific time,after this video will be delete. Or if any other ideas you have please let me know Thanks in advance

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • generating images by user id php + mysql

    - by jay
    function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

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