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  • sampling integers uniformly efficiently in python using numpy/scipy

    - by user248237
    I have a problem where depending on the result of a random coin flip, I have to sample a random starting position from a string. If the sampling of this random position is uniform over the string, I thought of two approaches to do it: one using multinomial from numpy.random, the other using the simple randint function of Python standard lib. I tested this as follows: from numpy import * from numpy.random import multinomial from random import randint import time def use_multinomial(length, num_points): probs = ones(length)/float(length) for n in range(num_points): result = multinomial(1, probs) def use_rand(length, num_points): for n in range(num_points): rand(1, length) def main(): length = 1700 num_points = 50000 t1 = time.time() use_multinomial(length, num_points) t2 = time.time() print "Multinomial took: %s seconds" %(t2 - t1) t1 = time.time() use_rand(length, num_points) t2 = time.time() print "Rand took: %s seconds" %(t2 - t1) if __name__ == '__main__': main() The output is: Multinomial took: 6.58072400093 seconds Rand took: 2.35189199448 seconds it seems like randint is faster, but it still seems very slow to me. Is there a vectorized way to get this to be much faster, using numpy or scipy? thanks.

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  • Please help - sorting integers in structs

    - by maja k.
    I have a struct like this: struct db { string name,sur; int num; }; And declared an array of db structs: struct db a[10]; and every member of a[] is filled with a name, surname and a number but there can be the same number appearing multiple times. I need to sort the numbers, and print the results, i.e. sort by the num of each struct and the print the name, sur and the num in each line starting from the smallest num going down to the largest. I don't know how to do this, please help me.

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  • Modal view becomes partly transparent when dismissing?

    - by Jaanus
    A completely ordinary setup: UIViewController where I push another UIVC: BlahVc *blah = [[BlahVc alloc] initWithNibName:@"Blah" bundle:nil]; UINavigationController *nav = [[UINavigationController alloc] initWithRootViewController:blah]; blah.delegate = self; [self presentModalViewController:nav animated:YES]; [nav release]; [blah release]; Details about Blah: to support both landscape and portrait with least effort, I built Blah.xib so that inside Blah's main view, call it view A, there is another view B, with width fixed to 320px, that positions itself in the centre of the screen. With portrait iPhone it fills up the whole screen, with landscape there are margins on the side. So far, so good. Autorotate etc works well. Now, to dismiss blah, I use the recommended setup: inside Blah, I do: [self.delegate blahDidCancel:self]; And in the parent VC, I have: - (void)blahDidCancel:(Blah *)blah { [self dismissModalViewControllerAnimated:YES]; } Both view A's and B's backgrounds are opaque white. Problem: as soon as it hits the dismissModalViewControllerAnimated line, view A seems to become transparent, while view B remains white. This is not a problem in portrait since view B still fills up the screen. But in landscape, the result is that view B is still opaque, but has see-through transparent margins on the side (where view A used to be that has now mysteriously become transparent), from where the parent view contents comes through during the dismissing animation. Why does it seem like view A becomes transparent upon dismissing the modal VC?

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  • How to extracting individual dimensions from $node->content['dimensions'] in Drupal's Ubercart?

    - by Walden
    On my Ubercart node-product.tpl.php page, I am trying to extract the individual product dimensions (height, weight, length) from the more generic: print $node->content['dimensions'] ['#value']; which returns "Dimensions: 72in. × 42in. × 30in." Using var_dump(get_defined_vars()); I'm able to see that the dimensions are being outputted independently, but can't seem to get them to print. on the page. What is the proper way to call the dimensions individually?

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  • Find out 20th, 30th, nth prime number. (I'm getting 20th but not 30th?) [Python]

    - by gsin
    The question is to find the 1000th prime number. I wrote the following python code for this. The problem is, I get the right answer for the 10th , 20th prime but after that each increment of 10 leaves me one off the mark. I can't catch the bug here :( count=1 #to keep count of prime numbers primes=() #tuple to hold primes candidate=3 #variable to test for primes while count<20: for x in range(2,candidate): if candidate%x==0: candidate=candidate+2 else : pass primes=primes+(candidate,) candidate=candidate+2 count=count+1 print primes print "20th prime is ", primes[-1] In case you're wondering, count is initialised as 1 because I am not testing for 2 as a prime number(I'm starting from 3) and candidate is being incremented by 2 because only odd numbers can be prime numbers. I know there are other ways of solving this problem, such as the prime number theorem but I wanna know what's wrong with this approach. Also if there are any optimisations you have in mind, please suggest. Thank You

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  • How to make scipy.interpolate give a an extrapolated result beyond the input range?

    - by Salim Fadhley
    I'm trying to port a program which uses a hand-rolled interpolator (developed by a mathematitian colleage) over to use the interpolators provided by scipy. I'd like to use or wrap the scipy interpolator so that it has as close as possible behavior to the old interpolator. A key difference between the two functions is that in our original interpolator - if the input value is above or below the input range, our original interpolator will extrapolate the result. If you try this with the scipy interpolator it raises a ValueError. Consider this program as an example: import numpy as np from scipy import interpolate x = np.arange(0,10) y = np.exp(-x/3.0) f = interpolate.interp1d(x, y) print f(9) print f(11) # Causes ValueError, because it's greater than max(x) Is there a sensible way to make it so that instead of crashing, the final line will simply do a linear extrapolate, continuing the gradients defined by the first and last two pouints to infinity. Note, that in the real software I'm not actually using the exp function - that's here for illustration only!

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  • Add xcode-select to PATH vs. Install Xcode Command Line Tools?

    - by MattDiPasquale
    Now with Xcode 4.5, is it OK to just add the following line to my ~/.bash_profile rather than installing the Xcode Command Line Tools? export PATH="$PATH:`xcode-select -print-path`/usr/bin:`xcode-select -print-path`/Toolchains/XcodeDefault.xctoolchain/usr/bin" Note: Xcode says the following about Command Line Tools: Before installing, note that from within Terminal you can use the XCRUN tool to launch compilers and other tools embedded within the Xcode application. Use the XCODE-SELECT tool to define which version of Xcode is active. Type "man xcrun" from within Terminal to find out more.

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  • MySQL INSERT data does not get stored in proper db, only temporary?

    - by greye
    I'm having trouble with MySQL or Python and can't seem to isolate the problem. INSERTs only seem to last the run of the script and are not stored in the database. I have this script: import MySQLdb db = MySQLdb.connect(host="localhost", user="user", passwd="password", db="example") dbcursor = db.cursor() dbcursor.execute("select * from tablename") temp = dbcursor.fetchall() print 'before: '+str(temp) dbcursor.execute('INSERT INTO tablename (data1, data2, data3) VALUES ("1", "a", "b")') dbcursor.execute("select * from tablename") temp = dbcursor.fetchall() print 'after: '+str(temp) The first time I run it I get the expected output: >>> before: () after: ((1L, 'a', 'b'),) The problem is that if I run it again, the before comes out empty when it should already have the entry in it and the after doesn't break (data 1 is primary key). >>> before: () after: ((1L, 'a', 'b'),) >>> before: () after: ((1L, 'a', 'b'),) >>> before: () after: ((1L, 'a', 'b'),) If I try running the insert command twice in the same script it will break ("Duplicate entry for PRIMARY KEY") Any idea what might be happening here?

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  • printing uid of a file on linux system

    - by neo730
    i am learning c programming. I am trying to make my own program similar to ls command but with less options.what i am doing is taking input directory/file name as argument and then gets all directory entry with dirent struct(if it is directory) . After it i use stat() to take all information of the file but here is my problem when i use write() to print these value its fine but when i want to print these with printf() i get warninng : format ‘%ld’ expects type ‘long int’, but argument 2 has type ‘__uid_t’. I don't know what should use at place of %ld and also for other special data types.

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  • Copy and Store LPTSTR in class causes crash

    - by Jake M
    I am attempting to copy a LPTSTR and store that string as a member variable in an object. But my attempts to copy the LPTSTR seem to fail and when I go to access/print the value of the copied LPTSTR I get a program crash. Is it possible to copy a LPTSTR and store it in my class below or is it better to just use a TCHAR*? class Checkbox { private: LPTSTR text; HWND hwnd; public: Checkbox(HWND nHwnd, LPTSTR nText) { lstrcpy(checkText, text); } void print() { // Causes a crash MessageBox(hwnd, text, text, MB_OK); } };

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  • web2py server-side comments

    - by MikeWyatt
    In a web2py view, how do I comment out server-side code? In ASP.NET, I can surround any HTML or code tags with <%-- and --% and that block will not be compiled or sent to the client. Velocity does the same thing with #* and *#. Is there an equivalent in web2py? ASP.NET <div> <p><%=foo.bar%></p> <%-- don't print twice! <p><%=foo.bar%></p> --%> </div> web2py <div> <p><%=foo.bar%></p> ??? don't print twice! <p><%=foo.bar%></p> ??? </div>

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  • How can this closure test be written in other languages?

    - by Jian Lin
    I wonder how the following closure test can be written in other languages, such as C and Java. Can the same result be expected also in Perl, Python, and PHP? Ideally, we don't need to make a new local variable such as x and assign it the value of i inside the loop, but just so that i has a new copy in the new scope each time. (if possible). (some discussion is in this question.) The following is in Ruby, the "1.8.6" on the first line of result is the Ruby version which can be ignored. p RUBY_VERSION $foo = [] (1..5).each do |i| $foo[i] = lambda { p i } end (1..5).each do |j| $foo[j].call() end the print out is: [MacBook01:~] $ ruby scope.rb "1.8.6" 1 2 3 4 5 [MacBook01:~] $ Contrast that with another test, with i defined outside: p RUBY_VERSION $foo = [] i = 0 (1..5).each do |i| $foo[i] = lambda { p i } end (1..5).each do |j| $foo[j].call() end the print out: [MacBook01:~] $ ruby scope2.rb "1.8.6" 5 5 5 5 5 [MacBook01:~] $

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  • Can not access android /data folder?

    - by fonter
    try { Runtime rt = Runtime.getRuntime(); Process pcs = rt.exec("ls -l /data"); BufferedReader br = new BufferedReader(new InputStreamReader(pcs .getInputStream())); String line = null; while ((line = br.readLine()) != null) { Log.e("line","line="+line); } br.close(); pcs.waitFor(); int ret = pcs.exitValue(); Log.e("ret","ret="+ret); } catch (Exception e) { Log.e("Exception", "Exception", e); } only print "ret=0",How to print the correct path?

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  • Finding File WIth Fixed File Size (>0) in Unix/Linux

    - by neversaint
    I have a list of file that looks like this 4 -rw-r--r-- 1 neversaint hgc0746 53 May 1 10:37 SRX016372-SRR037477.est_count 4 -rw-r--r-- 1 neversaint hgc0746 53 May 1 10:34 SRX016372-SRR037478.est_count 4 -rw-r--r-- 1 neversaint hgc0746 53 May 1 10:41 SRX016372-SRR037479.est_count 0 -rw-r--r-- 1 neversaint hgc0746 0 Apr 27 11:16 SRX003838-SRR015096.est_count 0 -rw-r--r-- 1 neversaint hgc0746 0 Apr 27 11:32 SRX004765-SRR016565.est_count What I want to do is to find files that has exactly size 53. But why this command failed? $ find . -name "*.est_count" -size 53 -print It works well though if I just want to find file of size 0 with this command: $ find . -name "*.est_count" -size 0 -print

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  • Help writing emacs lisp for emacs etags search

    - by user535707
    I'm looking for some help developing what I think should be an easy program. I want something similar to Emacs tags-search command, but I want to collect all search results into a buffer. (I want to see all results of M-,) I'm thinking this python style pseudo code should work, but I have no idea how to do this in emacs lisp? Any help would be greatly appreciated. def myTagsGrep(searchValue): for aFile in the tag list: result = grep aFile seachValue if len(result) > 0: print aFile # to the buffer print result # to the buffer I would like to be able to browse through the buffer with the same features tags-apropos does. Note that a similar question has been asked before: Is there a way to get emacs tag-search command to output all results to a buffer?

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  • PHP Dynamic Breadcrumb

    - by Adrian M.
    Hello, I got this code from someone and it works very well, I just want to remove the link from the last element of the array: //get rid of empty parts $crumbs = array_filter($crumbs); $result = array(); $path = ''; foreach($crumbs as $crumb){ $path .= '/' . $crumb; $name = ucfirst(str_replace(array(".php","_"),array(""," "), $crumb)); $result[] = "<a href=\"$path\">$name</a>"; } print implode(' > ', $result); This will output for example: Content Common File I just want a to remove the link from the last item - "File" to be just plain text.. I tried myself to count the array items and then if the array item is the last one then to print as plain text the last item.. but I'm still noob, I haven't managed to get a proper result.. Thank you!

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  • Retrieving data from MySQL in one SQL statement

    - by james.ingham
    Hi all, If I'm getting my data from Mysql like so: $result = $dbConnector->Query("SELECT * FROM branches, businesses WHERE branches.BusinessId = businesses.Id ORDER BY businesses.Name"); $resultNum = $dbConnector->GetNumRows($result); if($resultNum > 0) { for($i=0; $i < $resultNum; $i++) { $row = $dbConnector->FetchArray($result); // $row['businesses.Name']; // $row['branches.Name']; echo $row['Name']; } } Does anyone know how to print the field Name in businesses and how to print the name from branches? My only other alternative is to rename the fields or to call Mysql with two seperate queries. Thanks in advance

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  • PHP & MySQL Undefined variable problem

    - by comma
    I keep getting the following error Undefined variable: id on line 91 can some one help me correct this problem? The error is on this line. $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; MySQL database tables. CREATE TABLE tags ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill VARCHAR(255) NOT NULL, experience VARCHAR(255) NOT NULL, years VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); CREATE TABLE users_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, date_created DATETIME UNSIGNED NOT NULL, PRIMARY KEY (id) ); Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { if (isset($_POST['skill']) && trim($_POST['skill'])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill . "', '" . $experience . "', '" . $years . "')"); if (mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND years='" . $years . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; } }

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  • Calling subactivity from subactivity

    - by yogsma
    I have three activities in my android app. First activity is main application screen which gives option to open second screen containing second activity. But when I click on the button on second activity which was supposed to open third activity screen, I get "Application has stopped unexpectedly" error. <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="org.anddev.android.SampleApp" android:versionCode="1" android:versionName="1.0"> <application android:icon="@drawable/icon" android:label="@string/app_name"> <activity android:name=".FirstActivity" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name=".SecondActivity" android:label="@string/app_name" > </activity> <activity android:name=".ThirdActivity" android:label="@string/app_name" > </activity> </application>

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  • Using jQuery's ajax get request with parameters, returning page content

    - by Stevie Jenowski
    Thank you for looking at my question, as I appreciate your time. Okay, so I'm trying to use jQuery's get function to call my php script which ultimately returns a variable which is a built template of the main content of my page minus my static header/footer, for which I would like to replace the "old" page content without the page reloading. Can anyone point me in the right direction as to where I'm going wrong here? My code is as follows... jQuery: function getData(time, type) { $.ajax({ type: "GET", url: "getData.php", data: "time=" + time + "&type=" + type, success: function(data){ $('#pageContent').fadeOut("slow"); $('#pageContent').html(data); $('#pageContent').fadeIn("slow"); } }); return false; } getData.php(paraphrased): .... $time = empty($_GET['time']) ? '' : $_GET['time']; $type = empty($_GET['type']) ? '' : $_GET['type']; echo getData($time, $type); function getData($time, $type) ...... ..... $tmpl = new Template(); $tmpl->time= $time; $tmpl->type = $type; $builtpage = $tmpl->build('index.tmpl'); return $builtpage; ..... ...... jQuery function call: <a href="#" onclick="getData("<?php print $tmpl->time; ?>", "Orange")">Orange</a> <a href="#" onclick="getData("<?php print $tmpl->time; ?>", "Apple")">Apple</a> <a href="#" onclick="getData("<?php print $tmpl->time; ?>", "Banana")">Banana</a> When I click any link, the ajax seems to run fine, and the page does refuse to reload, but the content still remains unchanged... Anyone happen to know what's up?

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  • How to add columns to sqlite3 python?

    - by user291071
    I know this is simple but I can't get it working! I have no probs with insert,update or select commands, Lets say I have a dictionary and I want to populate a table with the column names in the dictionary what is wrong with my one line where I add a column? ##create con = sqlite3.connect('linksauthor.db') c = con.cursor() c.execute('''create table linksauthor (links text)''') con.commit() c.close() ##populate author columns allauthors={'joe':1,'bla':2,'mo':3} con = sqlite3.connect('linksauthor.db') c = con.cursor() for author in allauthors: print author print type(author) c.execute("alter table linksauthor add column '%s' 'float'")%author ##what is wrong here? con.commit() c.close()

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  • What causes subprocess.call to output blank file when attempting db export with mysqldump?

    - by caldazar
    I am having some problems using subprocess.call to export a database using mysqldump. I'm using Python 3.1 installed on Windows 7. from time import gmtime, strftime import subprocess DumpDir = "c:/apps/sqlbackup/"; DumpFile = "mysqldump-" + strftime("%Y-%m-%d-%H-%M-%S", gmtime()) + ".sql"; params = [r"mysqldump --user root --password=mypassword --force --flush-privileges --compress --comments mydatabase --result-file=" + DumpDir + DumpFile]; subprocess.call(params, shell=True); The above code causes a blank file to be created in the DumpDir. I've tried getting python to print the command so I can test it via the CMD prompt using: print(subprocess.list2cmdline(params)); If I paste the output to the CMD prompt and execute it, everything works fine. Any ideas? I'm new to Python, so I am sure the answer is simple but I've tried so many variations to get this working that I just can't figure this out.

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  • R: How can I use apply on rows of a data.frame and get out $column_name?

    - by John
    I'm trying to access $a using the following example: df<-data.frame(a=c("x","x","y","y"),b=c(1,2,3,4)) > df a b 1 x 1 2 x 2 3 y 3 4 y 4 test_fun <- function (data.frame_in) { print (data.frame_in[1]) } I can now access $a if I use an index for the first column: apply(df, 1, test_fun) a "x" a "x" a "y" a "y" [1] "x" "x" "y" "y" But I cannot access column $a with the $ notation: error: "$ operator is invalid for atomic vectors" test_fun_2 <- function (data.frame_in) { print (data.frame_in$a) } >apply(df, 1, test_fun_2) Error in data.frame_in$a : $ operator is invalid for atomic vectors Is this not possible?

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  • How to read line by line a CR-only file with Perl?

    - by Subb
    Hi, I'm trying to read a file which has only CR as line delimiter. I'm using Mac OS X and Perl v.5.8.8. This script should run on every platform, for every kind of line delimiter (CR, LF, CRLF). My current code is the following : open(FILE, "test.txt"); while($record = <FILE>){ print $record; } close(TEST); This currently print only the last line (or worst). What is going on? Obvisously, I would like to not convert the file. Is it possible?

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