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  • How do I use the html 'title' attribute with Html.Encode()?

    - by Kai
    Hello, I've been tryin to find an example of the syntax for getting an html 'title' for a string when using Html.Encode(). I want to display the full name in the mouseover title, if it's too long. Is there a way to do this without wrapping the string in a < span , i.e. <span title = "<%=Html.Encode(model.Name) %>"> //displays the full name on mouseover <%=Html.Encode(model.Name.Substring(0, 10))%>... //displays the name up to a max length </span> Or should I just do it this way? Thanks!

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  • Getting the first image elements id within an unordered list using JQuery

    - by Roland
    I'm trying to get the id of the first element of an unordered list using JQuery. Here's the list <ul class="list"> <li><img id="1" src="image1.jpg" name="image1" /></li> <li><img id="2" src="image2.jpg" name="image2" /></li> <li><img id="3" src="image3.jpg" name="image3" /></li> <li><img id="4" src="image4.jpg" name="image4" /></li> <li><img id="5" src="image5.jpg" name="image5" /></li> </ul> JQuery var id = $('.list li img'):first.attr('id');

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  • Parsing a dynamic value with Lift-JSON

    - by Surya Suravarapu
    Let me explain this question with an example. If I have a JSON like the following: {"person1":{"name": "Name One", "address": {"street": "Some Street","city": "Some City"}}, "person2":{"name": "Name Two", "address": {"street": "Some Other Street","city": "Some Other City"}}} [There is no restriction on the number of persons, the input JSON can have many more persons] I could extract this JSON to Persons object by doing var persons = parse(res).extract[T] Here are the related case classes: case class Address(street: String, city: String) case class Person(name: String, address: Address, children: List[Child]) case class Persons(person1: Person, person2: Person) Question: The above scenario works perfectly fine. However the need is that the keys are dynamic in the key/value pairs. So in the example JSON provided, person1 and person2 could be anything, I need to read them dynamically. What's the best possible structure for Persons class to account for that dynamic nature.

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  • java.lang.reflect.InvocationTargetException in Java

    - by manoj
    if(locs!=null) { System.out.println("location are not null"); Iterator ite = locs.iterator(); DefaultComboItem locObj = null; ArrayList locCode = null; String cod=null; String name=null; while(ite.hasNext()) { locCode = (ArrayList) ite.next(); Iterator iter = locCode.iterator(); while(iter.hasNext()) { cod=(String)iter.next(); System.out.println("Code="+cod); name=(String)iter.next(); System.out.println("name="+name); locObj = new DefaultComboItem(cod, name); colRet.add(locObj); } } } on executing above code i am getting "java.lang.reflect.InvocationTargetException" Please help me

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  • Get the lua command when a c function is called

    - by gamernb
    Supposed I register many different function names in Lua to the same function in C. Now, everytime my C function is called, is there a way to determine which function name was invoked? for example: int runCommand(lua_State *lua) { const char *name = // getFunctionName(lua) ? how would I do this part for(int i = 0; i < functions.size; i++) if(functions[i].name == name) functions[i].Call() } int main() { ... lua_register(lua, "delay", runCommand); lua_register(lua, "execute", runCommand); lua_register(lua, "loadPlugin", runCommand); lua_register(lua, "loadModule", runCommand); lua_register(lua, "delay", runCommand); } So, how do I get the name of what ever function called it?

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  • Objective-C Custom extend

    - by ryanjm.mp
    I have a couple classes that have nearly identical code. Only a string or two is different between them. What I would like to do is to make them from another class that defines those functions and then uses constants or something else to define those strings that are different. I'm not sure if "___" is inheritance or extending or what. That is what I need help with. For example: objectA.m: -(void)helloWorld { NSLog("Hello %@",child.name); } objectBob.m: #define name @"Bob" objectJoe.m #define name @"Joe" (I'm not sure if it's legal to define strings, but this gets the point across) It would be ideal if objectBob.m and objectJoe.m didn't have to even define the methods, just their relationship to objectA.m. Is there any way to do something like this? If all else fails I'll just make objectA.m: -(void)helloWorld:(NSString *name) { NSLog("Hello %@",name); } And have the other files call that function (and just #import objectA.m).

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  • jquery validate check at least one checkbox

    - by Omu
    I have something like this: <form> <input id='roles' name='roles' type='checkbox' value='1' /> <input id='roles' name='roles' type='checkbox' value='2' /> <input id='roles' name='roles' type='checkbox' value='3' /> <input id='roles' name='roles' type='checkbox' value='4' /> <input id='roles' name='roles' type='checkbox' value='5' /> <input type='submit' value='submit' /> <form> I would like to validate that at least one checkbox (roles) should be checked, is it possible with jquery.validate ?

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  • Why the followind upload if condition does not work?

    - by Ole Media
    So I have an upload script, and I want to check the file type that is being uploaded. I only want pdf, doc, docx and text files So I have: $goodExtensions = array('.doc','.docx','.txt','.pdf', '.PDF'); $name = $_FILES['uploadFile']['name']; $extension = substr($name, strpos($name,'.'), strlen($name)-1); if(!in_array($extension,$goodExtensions) || (($_FILES['uploadFile']['type'] != "applicatioin/msword") || ($_FILES['uploadFile']['type'] != "application/pdf"))){ $error['uploadFile'] = "File not allowed. Only .doc, .docx, .txt and pdf"; } Why I'm getting the error when testing and including correct documents?

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  • How to get the values from post method to the codehind file

    - by SmartestVEGA
    I have created a Webpage which will post as "post" method..not as "get" method. <html> <head> </head> <body> <FORM action="RetrieveData_Post.asp" id=form1 method=post name=form1> First Name: <br> <INPUT id="txtFirstName" name="txtFirstName" > <br> Last Name: <br> <INPUT id="txtLastName" name="txtLastName" > <br> <INPUT type="submit" value="Submit"> </FORM> </body> </html> i want to retieve the values in the textboxes in the code behind of another form. Please help me.

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  • MVC Razor Engine For Beginners Part 1

    - by Humprey Cogay, C|EH, E|CSA
    I. What is MVC? a. http://www.asp.net/mvc/tutorials/older-versions/overview/asp-net-mvc-overview II. Software Requirements for this tutorial a. Visual Studio 2010/2012. You can get your free copy here Microsoft Visual Studio 2012 b. MVC Framework Option 1 - Install using a standalone installer http://www.microsoft.com/en-us/download/details.aspx?id=30683 Option 2 - Install using Web Platform Installer http://www.microsoft.com/web/handlers/webpi.ashx?command=getinstallerredirect&appid=MVC4VS2010_Loc III. Creating your first MVC4 Application a. On the Visual Studio click file new solution link b. Click Other Project Type>Visual Studio Solutions and on the templates window select blank solution and let us name our solution MVCPrimer. c. Now Click File>New and select Project d. Select Visual C#>Web> and select ASP.NET MVC 4 Web Application and Enter MyWebSite as Name e. Select Empty, Razor as view engine and uncheck Create a Unit test project f. You can now view a basic MVC 4 Application Structure on your solution explorer g. Now we will add our first controller by right clicking on the controllers folder on your solution explorer and select Add>Controller h. Change the name of the controller to HomeController and under the scaffolding options select Empty MVC Controller. i. You will now see a basic controller with an Index method that returns an ActionResult j. We will now add a new View Folder for our Home Controller. Right click on the views folder on your solution explorer and select Add> New Folder> and name this folder Home k. Add a new View by right clicking on Views>Home Folder and select Add View. l. Name the view Index, and select Razor(CSHTML) as View Engine, All checkbox should be unchecked for now and click add. m. Relationship between our HomeController and Home Views Sub Folder n. Add new HTML Contents to our newly created Index View o. Press F5 to run our MVC Application p. We will create our new model, Right click on the models folder of our solution explorer and select Add> Class. q. Let us name our class Customer r. Edit the Customer class with the following code s. Open the HomeController by double clickin HomeController of our Controllers folder and edit the HomeControllerusing System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc;   namespace MyWebSite.Controllers {     public class HomeController : Controller     {         //         // GET: /Home/           public ActionResult Index()         {             return View();         }           public ActionResult ListCustomers()         {             List<Models.Customer> customers = new List<Models.Customer>();               //Add First Customer to Our Collection             customers.Add(new Models.Customer()                     {                         Id = 1,                         CompanyName = "Volvo",                         ContactNo = "123-0123-0001",                         ContactPerson = "Gustav Larson",                         Description = "Volvo Car Corporation, or Volvo Personvagnar AB, is a Scandinavian automobile manufacturer founded in 1927"                     });                 //Add Second Customer to Our Collection             customers.Add(new Models.Customer()                     {                         Id = 2,                         CompanyName = "BMW",                         ContactNo = "999-9876-9898",                         ContactPerson = "Franz Josef Popp",                         Description = "Bayerische Motoren Werke AG,  (BMW; English: Bavarian Motor Works) is a " +                                       "German automobile, motorcycle and engine manufacturing company founded in 1917. "                     });                 //Add Third Customer to Our Collection             customers.Add(new Models.Customer()             {                 Id = 3,                 CompanyName = "Audi",                 ContactNo = "983-2222-1212",                 ContactPerson = "Karl Benz",                 Description = " is a multinational division of the German manufacturer Daimler AG,"             });               return View(customers);         }     } } t. Let us now create a view for this Class, But before continuing Press Ctrl + Shift + B to rebuild the solution, this will make the previously created model on the Model class drop down of the Add View Menu. Right click on the views>Home folder and select Add>View u. Let us name our View as ListCustomers, Select Razor(CSHTML) as View Engine, Put a check mark on Create a strongly-typed view, and select Customer (MyWebSite.Models) as model class. Slect List on the Scaffold Template and Click OK. v. Run the MVC Application by pressing F5, and on the address bar insert Home/ListCustomers, We should now see a web page similar below.   x. You can edit ListCustomers.CSHTML to remove and add HTML codes @model IEnumerable<MyWebSite.Models.Customer>   @{     Layout = null; }   <!DOCTYPE html>   <html> <head>     <meta name="viewport" content="width=device-width" />     <title>ListCustomers</title> </head> <body>     <h2>List of Customers</h2>     <table border="1">         <tr>             <th>                 @Html.DisplayNameFor(model => model.CompanyName)             </th>             <th>                 @Html.DisplayNameFor(model => model.Description)             </th>             <th>                 @Html.DisplayNameFor(model => model.ContactPerson)             </th>             <th>                 @Html.DisplayNameFor(model => model.ContactNo)             </th>         </tr>         @foreach (var item in Model) {         <tr>             <td>                 @Html.DisplayFor(modelItem => item.CompanyName)             </td>             <td>                 @Html.DisplayFor(modelItem => item.Description)             </td>             <td>                 @Html.DisplayFor(modelItem => item.ContactPerson)             </td>             <td>                 @Html.DisplayFor(modelItem => item.ContactNo)             </td>                   </tr>     }         </table> </body> </html> y. Press F5 to run the MVC Application   z. You will notice some @HTML.DisplayFor codes. These are called HTML Helpers you can read more about HTML Helpers on this site http://www.w3schools.com/aspnet/mvc_htmlhelpers.asp   That’s all. You now have your first MVC4 Razor Engine Web Application . . .

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  • Accessing variables of an object of a particular class through a different class within the construc

    - by Haxed
    class Student { private String name; public Student(String name){ this.name = name; } public String getName(){ return name; } } class StudentServer { public StudentServer(){ Student[] s = new Student[30]; s[0] = new Student("Nick"); System.out.println(s[0]); // LINE 01:But this compiles, although prints junk System.out.println(s[0].getName()); // LINE 02:I get a error called cannot find symbol } public static void main(){ new StudentServer(); } } Hey, there are two lines, I want the reader to focus on, the first line prints junk as usual, but suprizingly the second one gives me an error. Do you know why ? Many Thanks

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  • SQL query to return data from two separate rows in a table joined to a master table

    - by Ali
    I have a TWO tables of data with following fields table1=(ITTAG,ITCODE,ITDESC,SUPcode) table2=(ACCODE,ACNAME,ROUTE,SALMAN) This is my customer master table that contains my customer data such as customer code, customer name and so on... Every Route has a supervisor (table1=supcode) and I need to know the supervisor name in my table which both supervisor name and code exist in one table. table1 has contain all names separated by ITTAG. For example, supervisor's name has ITTAG='K'; also salesman's name has ITTAG='S'. ITTAG ITCODE ITDESC SUPCODE ------ ------ ------ ------- S JT JOHN TOMAS TF K WK VIKI KOO NULL Now this is the result which I want ACCODE ACNAME ROUTE SALEMANNAME SUPERVISORNAME ------- ------ ------ ------------ --------------- IMC1010 ABC HOTEL 01 JOHN TOMAS VIKI KOO I hope this this information is sufficient to get the query..

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  • listview tile layout problem (vb.net)

    - by Matt Facer
    hi guys, I have a listview which displays (eventually) an album cover of an itunes play list with the album name under it. the problem I am having is that I cannot get the album art (currently a blank square) ABOVE the album name. It always is on the side... how do I do it? I've tried adding column headers and alsorts... code to set up the listview Dim myImageList As ImageList albumList.View = View.Tile albumList.TileSize = New Size(120, 150) ' Initialize the item icons. myImageList = New ImageList() myImageList.Images.Add(Image.FromFile("c:/test.jpg")) myImageList.ImageSize = New Size(80, 80) albumList.LargeImageList = myImageList I then do a loop to display each album name which uses Dim item0 As New ListViewItem(New String() _ {Albums(i).Name}, 0) albumList.Items.Add(item0) the output is http://i111.photobucket.com/albums/n122/mfacer/Screenshot2010-05-02at164815.png but as i said, I want the album name under the orange box.... any ideas?? Thanks for any info!

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  • Http Geocoder (Google) Accuracy level

    - by sushruth
    I am geocoding a large amount of user entered addresses and interested in the accuracy levels returned. My GOAL is to get the BEST POSSIBLE ACCURACY score for a given address. I call the geocder api following way http://maps.google.com/maps/geo?q={address}&output=csv&sensor=false&key=xx now the accuracy levels returned for same address with/without premise name q = Key Arena, 305 Harrison Street, Seattle, WA 98109 (Accuracy is 5) q = 305 Harrison Street Seattle, WA 98109 (Accuracy is 8) q = Key Arena, Seattle, WA 98109 (Accuracy is 9.) Its obvious from the above that the google servers does not return the best accuracy when street name is appended with premise/venue. the question is :) is there a way to pass the complete address ( with premise name / i.e case 1 ) and get the Max Accuracy. ( or how can tell the google server that the address is passed with premise/building name and street name) ( if you are thinking why not just use case 3, the answer is these are user entered addresses, they could enter "my moms's house" for premise, with accurate street address. in which case i want the accuracy to be 8 not 5)

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  • Chrome and Safari strange behaviour in Javascript

    - by mck89
    Hi, i've written this peace of code: var a=function(){ }; a.name="test"; a.prop="test2"; Now if i debug the code with the console: console.log(a.name); console.log(a.prop); In Firefox i get a.name="test" and a.prop="test2", while in Safari and Chrome i get a.prop="test2" but a.name="". It seems that there's no way to assign a "name" property on a function in Webkit browsers. Do you know why? But the most important thing is, do you know a workaround for that?

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  • jQuery inserting comment help

    - by StealthRT
    Hey all, i am trying to learn how to insert a comment within some html code without having to refresh the page. I know jQuery is capable of inserting a comment into a div area but i am having problems finding an example like that with fading in. Here is my comment code: <div id="CommentBox122" style="width:80%; padding:2px; margin-left:25px;"> <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> <div id="stylized" class="myform" align="center"> <form id="CommentForm122" name="CommentForm122"> <div align="center" style="text-align:center; color:#F00; font-family:Arial, Helvetica, sans-serif; font-weight:bold;">Would you like to leave a comment, Robert?</div> <textarea name="txtComment" class="box" id="txtComment"></textarea> <input name="txtpostid" type="text" id="txtpostid" style="visibility:hidden; display:none; height:0px; width:0px;" value="Demo43639" /> <div class="buttons" align="center"> <button type="button" id="Button122" name="Button122" class="positive" onclick="doStuff();"><img name="Submit" src="img\buttonimgComment.png" alt="" />Post Comment</button> </div> </form> </div> </div> The code i need to insert again would be: <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> But again, i am unable to find an example using jQuery to automatically insert that part of the code under the other "table /table" box.. So after its inserted by jQuery, the code should look like this: <div id="CommentBox122" style="width:80%; padding:2px; margin-left:25px;"> <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> <div id="stylized" class="myform" align="center"> <form id="CommentForm122" name="CommentForm122"> <div align="center" style="text-align:center; color:#F00; font-family:Arial, Helvetica, sans-serif; font-weight:bold;">Would you like to leave a comment, Robert?</div> <textarea name="txtComment" class="box" id="txtComment"></textarea> <input name="txtpostid" type="text" id="txtpostid" style="visibility:hidden; display:none; height:0px; width:0px;" value="Demo43639" /> <div class="buttons" align="center"> <button type="button" id="Button122" name="Button122" class="positive" onclick="doStuff();"><img name="Submit" src="img\buttonimgComment.png" alt="" />Post Comment</button> </div> </form> </div> </div> As always, any help would be great! :o) David

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  • print hierarchy data(adjacency list model) in a list(ul/ol/li)

    - by adi
    I have adjacency list model like on the page http://dev.mysql.com/tech-resources/articles/hierarchical-data.html i have make a full table containing all data ordered by level using this SELECT t1.name AS lev1, t2.name as lev2, t3.name as lev3, t4.name as lev4 FROM category AS t1 LEFT JOIN category AS t2 ON t2.parent = t1.category_id LEFT JOIN category AS t3 ON t3.parent = t2.category_id LEFT JOIN category AS t4 ON t4.parent = t3.category_id WHERE t1.name = 'ELECTRONICS'; ORDER by ..... I want to make an unordered list using php from the table Anyone can help me...

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  • jquery - add to hidden input field on keypress?

    - by Simpson88Keys
    I've got a hidden input field that I want to append text to depending upon what a user enters in two other fields. So, <input type="hidden" name="name" value="" /> <input type="text" name="first" value="" /> <input type="text" name="second" value="" /> If the user types First in the first input field and Second in the second input field, I want the name input field to be "First Second"... Tried using keyup and keypress, but can't get it to append to what's already there?

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  • Easiest way to rename a model using Django/South?

    - by vaughnkoch
    Hi everyone, I've been hunting for an answer to this on South's site, google, and SO, but couldn't find a simple way to do this. I want to rename a Django model using South. Say you have the following: class Foo(models.Model): name = models.CharField() class FooTwo(models.Model): name = models.CharField() foo = models.ForeignKey(Foo) and you want to convert Foo to Bar, namely class Bar(models.Model): name = models.CharField() class FooTwo(models.Model): name = models.CharField() foo = models.ForeignKey(Bar) To keep it simple, I'm just trying to change the name from Foo to Bar, but ignore the 'foo' member in FooTwo for now. What's the easiest way to do this using South? a) I could probably do a data migration, but that seems pretty involved. b) Write a custom migration, e.g. db.rename_table('city_citystate', 'geo_citystate'), but I'm not sure how to fix the foreign key in this case. c) An easier way that you know? Thanks!

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  • js regex replace multiple words

    - by Raghav
    I need to replace ${conferance name} with ABC, ${conference day} with Monday in the following sentence. Could some one help me with the regex. var text = "<td>${conference name}</td><td>${conference day}</td>" var list = ["${conferance name}", "${conference day}" ] for (var j = 1; j < list.length; j++) { //Extracting the col name var colName = list[j].split("${"); colName = colName.split("}")[0]; //Replacing the col name text = text.replace(new RegExp('\\$\\{' + colName + '\\}', 'g'), "ABC"); } The above code repalces fine if i have ${conference_name}, but it fails when i have a space in between. The list is a dynamic array. And the Replace statements are also dynamic. I just simulated them as objects here for fitting them in the Regex Statement. Thanks in Advance.

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  • WPF Binding : Object in a object

    - by Philippe
    I have a form in WPF with 2 textbox : <TextBox Name="txtName" Text="{Binding Contact.Name}"/> <TextBox Name="txtAddressNumber" Text="{Binding Contact.Address.Number}"/> and I have 2 class : public class ContactEntity { public string Name {get;set;} public AddressEntity Address {get;set;} } public class AddressEntity { public int Number {get;set} } The Name property binds fine. But the Number property of the Address object inside the Contact object does not binds. What I'm doing wrong ?

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  • Files and filegroups sql server 2005

    - by Dhivagar
    Can we move default file to another filegroup. sample code is given below Sample code create database EMPLOYEE ON PRIMARY ( NAME = 'PRIMARY_01', FILENAME = 'C:\METADATA\PRIM01.MDF', SIZE = 5 MB , MAXSIZE =50 MB, FILEGROWTH = 2 MB), ( NAME = 'SECONDARY_02', FILENAME = 'C:\METADATA\SEC02.NDF' ), FILEGROUP EMPLOYEE_dETAILS ( NAME = 'EMPDETILS_01', FILENAME = 'C:\METADATA\EMPDET01.NDF', SIZE = 5 MB , MAXSIZE =50 MB, FILEGROWTH = 2 MB), ( NAME = 'EMPDETILS_02', FILENAME = 'C:\METADATA\EMPDET02.NDF', SIZE = 5 MB , MAXSIZE =50 MB, FILEGROWTH = 2 MB) LOG ON ( NAME = 'TRANSACLOG', FILENAME ='c:\METADATA\TRAS01.LDF', SIZE = 5 MB , MAXSIZE =50 MB, FILEGROWTH = 2 MB ) now i want to move the FILENAME = 'C:\METADATA\SEC02.NDF' from deault primary file to the FILEGROUP EMPLOYEE_dETAILS ? need assist ??

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  • Struts Tiles application

    - by rav83
    Am trying a tiles application.Below is my code tiles-defs.xml </tiles-definitions> <definition name="${YOUR_DEFINITION_HERE}"> </definition> <definition name="commonPage" path="/jsps/template.jsp"> <put name="header" value="/jsps/header.jsp" /> <put name="menu" value="/jsps/menu.jsp" /> <put name="body" value="/jsps/homebody.jsp" /> <put name="footer" value="/jsps/footer.jsp" /> </definition> <definition name="aboutUsPage" extends="commonPage"> <put name="body" value="/jsps/aboutUsBody.jsp" /> </definition> </tiles-definitions> struts-config.xml <action path="/aboutus" type="java.com.mbest.core.action.AboutUsAction" parameter="method"> <forward name="success" path="aboutUsPage"/> <forward name="failure" path="aboutUsPage"/> </action> </action-mappings> template.jsp <%@ taglib uri="/WEB-INF/struts-tiles.tld" prefix="tiles" %> <html> <head><title></title></head> <body> <table border="1" cellspacing="0" cellpadding="0" style="width: 98%; height: 100%"> <tr> <td colspan="2"> <tiles:insert attribute="header"/> </td> </tr> <tr style="height: 500px"> <td valign="top" style="width: 200px"> <tiles:insert attribute="menu"/> </td> <td valign="baseline" align="left"> <tiles:insert attribute="body"/> </tr> <tr> <td colspan="2"> <tiles:insert attribute="footer"/> </td> </tr> </table> </body> </html> homebody.jsp <%@ taglib uri="/WEB-INF/struts-bean.tld" prefix="bean" %> <%@taglib uri="/WEB-INF/struts-html.tld" prefix="html"%> <%@taglib uri="/WEB-INF/struts-tiles.tld" prefix="tiles" %> <html> <head> <title></title> <style type="text/css"> <%@include file="../css/helper.css"%> <%@include file="../css/dropdown.css" %> <%@include file="../css/default.ultimate.css" %> </style> </head> <body> <div id="header"> <ul id="nav" class="dropdown dropdown-horizontal"> <li><span class="dir"><html:link page="/aboutus.do?method=aboutUsPage" >About Us</html:link></span></li> <li><span class="dir"><a href="./">Products</a></span></li> <li><span class="dir"><a href="./">Infrastructure</a></span></li> <li><span class="dir"><a href="./">Pharmaceutical Formulations</a></span></li> <li><span class="dir"><a href="./">Contact Us</a></span></li> </ul> </div> </body> </html> AboutUsAction.java package java.com.mindbest.core.action; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.struts.action.ActionForm; import org.apache.struts.action.ActionForward; import org.apache.struts.action.ActionMapping; import org.apache.struts.actions.DispatchAction; public class AboutUsAction extends DispatchAction { public ActionForward aboutUsPage(ActionMapping mapping,ActionForm form, HttpServletRequest request,HttpServletResponse response)throws Exception { return mapping.findForward("success"); } } aboutUsBody.jsp hello In my above code if i try to access the app using (domainname)/example/aboutus.do its giving 500 error.Can anyone help me figure this out?

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  • PUT parameters not working in python / google app engine

    - by magegu
    hi, i'm working on a simple RESTful webservice with python with the webapp framework on the google app engine. Basically i'm sending all request via AJAX/jquery - for POST it works like a charm, but when I'm sending data with PUT, the parameters are empty / not processed. this is my PUT: $.ajax({ type: "PUT", url: "/boxes", data: { name: this.name, archived: this.archived }, success: function(msg){ } }); firebug saids i'm putting: Parameter application/x-www-form-urlencoded archived false name 123112323asdasd but using this python code: from google.appengine.ext import webapp from google.appengine.ext.webapp import util, template from google.appengine.ext import db from google.appengine.api.datastore_types import * from django.utils import simplejson as json import cgi import datetime class BoxHandler(webapp.RequestHandler): def post(self): #working print "test" self.response.out.write(self.request.get("name")) def put(self): print "test" #not working self.response.out.write(self.request.get("name")) will just return test Status: 200 OK Content-Type: text/html; charset=utf-8 Cache-Control: no-cache Expires: Fri, 01 Jan 1990 00:00:00 GMT Content-Length: 0 so .. hm, is there anything i'm missing here? cheers, Martin

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  • How to order results based on number of search term matches?

    - by Travis
    I am using the following tables in mysql to describe records that can have multiple searchtags associated with them: TABLE records ID title desc TABLE searchTags ID name TABLE recordSearchTags recordID searchTagID To SELECT records based on arbitrary search input, I have a statement that looks sort of like this: SELECT recordID FROM recordSearchTags LEFT JOIN searchTags ON recordSearchTags.searchTagID = searchTags.ID WHERE searchTags.name LIKE CONCAT('%','$search1','%') OR searchTags.name LIKE CONCAT('%','$search2','%') OR searchTags.name LIKE CONCAT('%','$search3','%') OR searchTags.name LIKE CONCAT('%','$search4','%'); I'd like to ORDER this resultset, so that rows that match with more search terms are displayed in front of rows that match with fewer search terms. For example, if a row matches all 4 search terms, it will be top of the list. A row that matches only 2 search terms will be somewhere in the middle. And a row that matches just one search term will be at the end. Any suggestions on what is the best way to do this? Thanks!

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