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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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  • How to create PHP method linking?

    - by Kerry
    I've seen other objects that do this: $obj->method1()->method2(); How do I do that? Is each function just modifying the pointer of an object or returning a pointer? I don't know the proper term for this style -- if anyone could help me with that, it would be great.

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  • Add multiple IF tags in php

    - by Andy
    Hi , I would like to add this condition : {if $profile.sex == 1 || $profile.sex == 4} {/if} To this code : case 'friendlist': if ( app_Features::isAvailable( 14 ) ) { $_output = '<div class="memhome_link">'; $_output.= '<a href="'.SK_Navigation::href( 'profile_friend_list' ).'" '.$class.'>'.$lang_section->text( 'href_my_friendlist').'</a>'; $_output.= ' ('.app_FriendNetwork::countFriends( SK_HttpUser::profile_id() ).')'; $_output.= '</div>'; } break; Can anybody give me any help , please ? Thanks for all the help .

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  • PHP: extract email and name from data file

    - by pi-2r
    I need to extract the name and the e-mail from one data file. the file contains more than 500 lines and I want to extract this two informations almost all the data. I would like to use preg_match_all, but my function doesn't work ... $chaine = " ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata1 ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata2 * ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata3 "; //$chaine =" #76:50#89:1#86:50#49:1#84:22"; $motif="/MAIL([a-z]{2,4}+)NAME([a-z]{2,4}+)/"; preg_match_all($motif,$chaine,$out); $nb=count($out[0]); for($i=0;$i<$nb;$i++) { echo $out[0][$i].'<br/>'; }

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  • How to reformat date in PHP?

    - by Lisa
    I am pulling the dates of various posts from a database. The dates are in the following format: 2009-08-12 Numeric Year - Numeric Month - Numeric Day How can I reformat these dates to something more user friendly like: August 12, 2009 Numeric Month Numeric Date, Numeric Year Assuming that the date gotten from the mysql database is stored in a variable called: $date = $row['date_selected'];

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  • PHP GD Incredibly Strange Problem

    - by ThinkingInBits
    if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { die("success"); } if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { $image_width = imagesx($img); $image_height = imagesy($img); $target_width = 150; $target_height = 150; if ($image_width > $image_height) { $percentage = ($target_width / $image_width); } else { $percentage = ($target_height / $image_height); } $new_image_width = round($image_width * $percentage); $new_image_height = round($image_height * $percentage); $imgResized = imagecreatetruecolor($new_image_width, $new_image_height); imagecopyresampled($imgResized, $img, 0, 0, 0, 0, $new_image_width, $new_image_height, $image_width, $image_height); imagejpeg($imgResized, $this->path, 100); imagedestroy($img); imagedestroy($imgResized); $this->storeThumbnailLocation(); } else { die ("image was not created or saved"); } The first if statement dies and echos success. If I take out the first if statement, the second one echos "image could not be created or saved" If honestly run out of ideas on this one, the code is identical

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  • PHP: Check if 0?

    - by tarnfeld
    Hi, I am using a class which returns me the value of a particular row and cell of an excel spreadsheet. To build up an array of one column I am counting the rows and then looping through that number with a for() loop and then using the $array[] = $value to set the incrementing array object's value. This works great if none of the values in a cell are 0. The class returns me a number 0 so it's nothing to do with the class, I think it's the way I am looping through the rows and then assigning them to the array... I want to carry through the 0 value because I am creating graphs with the data afterwards, here is the code I have. // Get Rainfall $rainfall = array(); for($i=1;$i<=$count;$i++) { if($data->val($i,2) != 'Rainfall') // Check if not the column title { $rainfall[] = $data->val($i,2); } } For your info $data is the excel spreadsheet object and the method $data->val(row,col) is what returns me the value. In this case I am getting data from column 2. Screenshot of spreadsheet http://cl.ly/1Dmy Thanks! All help is very much appreciated!

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • Need help with transferring data between MySQL db's using PHP

    - by JM4
    In one of the sites I manage, the client has decided to take on ACH/Bank Account administration where it was previously outsourced. As a result, the information submitted in our online form which used to simply store in a single database for processing now must sit in 'limbo' until the funds used for payment have been verified. My original plan is as follows: At the end of an enrollment, all form data is collected and stored in a single MySQL database. Our internal administrator will receive an email notification reminding him enrollments have taken place. He will process the ACH information collected and wait the 3-4 business days needed for payment to clear. Once the payment information has been returned as Good (haven't considered what I will do with the 'bad' yet), the administrator can log into a secure portal which allows him to click a button to 'process' the full information once compared and verified. the process is simplified as: Enrollment complete: data stored in DB 'A' Funds verified and link clicked: data from 'A' is copied to DB 'B' and 'A' is deleted. I have run similar processes with CSV output before and simply used //transfers old data to archive $transfer = mysql_query('INSERT INTO '.$archive.' SELECT * FROM '.$table) or die(mysql_error()); //empties existing table $query = mysql_query('TRUNCATE TABLE '.$table) or die(mysql_error()); but in those cases, ALL data returned was copied and deleted. I only want to copy and delete a single record. Any idea how to accomplish this?

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  • PHP: exif_imagetype() not working?

    - by Karem
    I have this extension checker: $upload_name = "file"; $max_file_size_in_bytes = 8388608; $extension_whitelist = array("jpg", "gif", "png", "jpeg"); /* checking extensions */ $path_info = pathinfo($_FILES[$upload_name]['name']); $file_extension = $path_info["extension"]; $is_valid_extension = false; foreach ($extension_whitelist as $extension) { if (strcasecmp($file_extension, $extension) == 0) { $is_valid_extension = true; break; } } if (!$is_valid_extension) { echo "{"; echo "error: 'ext not allowed!'\n"; echo "}"; exit(0); } And then i added this: if (exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_GIF OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_JPEG OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_PNG) { echo "{"; echo "error: 'This is no photo..'\n"; echo "}"; exit(0); } As soon when I added this to my imageupload function, the function stops working. I dont get any errors, not even the one i made myself "this is no photo", what could be wrong? Just checked with my host. They support the function exif_imagetype()

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  • case insensitive highlighting in php

    - by fusion
    i'm using this function to highlight the results from mysql query: function highlightWords($string, $word) { $string = str_replace($word, "<span class='highlight'>".$word."</span>", $string); /*** return the highlighted string ***/ return $string; } .... $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); the problem is, if i type in 'good', it will only show my search results with a lower-case 'g'ood and not 'Good'. how do i rectify this?

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  • Php dynamic class construction

    - by pistacchio
    Hi to all, I'm trying to avoid the use of eval. I can dynamically instantiate a class like this: class myclass {} $my_class_name = 'myclass'; $obj = new $myclass(); If the constructor is like follows: class myclass { public function __construct( $argument1, $argument2 ) {} } and i have the values of the arguments in an array, how can i dynamically instantiate the class and pass it dynamic arguments? Mind that I have no way to modify the class, so I have to work on the way of using it. Thanks

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  • downloading security related problem in php

    - by pareek-rohit
    hi i have to upload a video.but i want to gives permission only authenticate user to download .but i have a problem in that.because if any body type the video detail in browser.(ex http://sitename/folder_name/videoname) then browser download that video.but i don't want this .please suggest me how can i resolve this problem.either i should generate the video name randomly or make a temporary folder in which video reside only for specific time,after this video will be delete. Or if any other ideas you have please let me know Thanks in advance

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  • PHP mail script html formatting

    - by Jimbly2
    someone kindly posted this code for me but it only returns in the resulting email - any ideas? Does it need a closing html tag? $mailHeader .= "Content-type: text/html; charset=iso-8859-1\r\n"; $formcontent ="<table border='1'>"; foreach ($_POST as $field=>$value) { $formcontent.="<tr>"; $formcontent .= "<td>$field:</td> <td>$value</td>"; $formcontent.="</tr>"; } $formcontent .= '<tr><td>User-Agent: </td><td>'.$_SERVER['HTTP_USER_AGENT'].'</td>'; $formcontent ="</table>"; Thanks, JIm

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  • PHP turn off errors - in one file only

    - by Industrial
    Hi! I am well aware about error_reporting(0); & ini_set('display_errors', "Off"); to make error messages go away. What would be an appropriate way to do this - for a specific file or part of code only? Surpressing errors with @'s seems like a bad idea since it apparently slows the code down... Thanks!

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  • Optimizing PHP code (trying to determine min/max/between case)

    - by Swizzh
    I know this code-bit does not conform very much to best coding practices, and was looking to improve it, any ideas? if ($query['date_min'] != _get_date_today()) $mode_min = true; if ($query['date_max'] != _get_date_today()) $mode_max = true; if ($mode_max && $mode_min) $mode = "between"; elseif ($mode_max && !$mode_min) $mode = "max"; elseif (!$mode_max && $mode_min) $mode = "min"; else return; if ($mode == "min" || $mode == "between") { $command_min = "A"; } if ($mode == "max" || $mode == "between") { $command_max = "B"; } if ($mode == "between") { $command = $command_min . " AND " . $command_max; } else { if ($mode == "min") $command = $command_min; if ($mode == "max") $command = $command_max; } echo $command;

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  • php - How do I get rid of this strange "empty delimiter" message

    - by Steven
    I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

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  • PHP uploads and checking

    - by user147685
    Hi all, I want to update/insert file by using upload box to the database but before that it will check for the file type thats only pdf can be upload. Somthing wrong with the codes and i dont know what..Please help here are part of my updates codes: $id=$rs['id']; $qry = "SELECT a.faillampiran FROM {$CFG->prefix}ptk_lampiran a, {$CFG->prefix}ptk b WHERE a.ptkid=$id and b.id=$id"; $sql = get_records_sql($qry); if($_POST['check']){ $ext = pathinfo($faillampiran,PATHINFO_EXTENSION); $err = "Upload Only PDF File. "; if ($ext =='pdf'){ $qry="UPDATE {$CFG->prefix}ptk_lampiran SET faillampiran='".$faillampiran."' WHERE ptkid='".$_GET['id']."'"; $sql=mysql_query($qry); $qry = "SELECT a.faillampiran FROM {$CFG->prefix}ptk_lampiran a, {$CFG->prefix}ptk b WHERE b.id = '".$rs[id]."' AND a.ptkid = '".$rs[id]."' "; $sql = get_records_sql($qry); foreach($sql as $rs){ ?> <?=basename($rs->faillampiran); ?><br> <? } ?> <tr><td></td><td></td><td> <input type="file" size="50" name="faillampiran" alt="faillampiran" value= "<?=$faillampiran;?>" /> <input type="submit" name="edit" value="Muat naik fail ini" /><br /> </td></tr> } else { echo "<script>alert('$err')</script>"; } } else { foreach($sql as $rs){ ?> <?=basename($rs->faillampiran); ?><br> <? } ?> <input type="file" size="50" name="faillampiran" alt="faillampiran" value= "<?=$faillampiran;?>" /> <input type="submit" name="edit" value="Muat naik fail ini" /><br /> <?} Sori bout the messiness of the codes, im still a beginner in this languages. thx

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • PHP Session Array Value keeps showing as "Array"

    - by Nerathas
    Hello, When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number. The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array. (A 2-Dimensional Table is used) Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ? $test1 = $_SESSION["table"][0]; $test2 = $_SESSION["table"][1]; $test3 = $_SESSION["table"][2]; $test4 = $_SESSION["table"][3]; $test5 = $_SESSION["table"][4]; What exactly is this, and how can i fix this? Is it some sort of override that needs to happen? Best Regards.

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