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  • Prototype: Form.serialize missing some inputs (due to table?)

    - by Chris
    I'm using JavaScript Prototype (through Ruby on Rails) to handle some Ajax calls; but in one particular case I'm missing a field from the form. I have a layout like this: +---------+---------+ | Thing 1 | Thing 2 | +---------+---------+-----------+ | o Opt 1 | o Opt 1 | <Confirm> | | o Opt 2 | o Opt 2 | | +---------+---------+-----------+ Opt 1 and 2 are Radio buttons, Confirm is a button. The entire table is wrapped in a form, with code like: <form action="javascript:void(0)"> <input type="hidden" name="context" value="foo" /> <input type="hidden" name="subcontext" value="bar" /> <table> <tr><td>Thing 1</td><td>Thing2</td></tr> <tr><td> <input type="radio" name="choice" value="1.1" />Opt 1<br /> <input type="radio" name="choice" value="1.2" />Opt 2<br /> </td><td> <input type="radio" name="choice" value="2.1" />Opt 1<br /> <input type="radio" name="choice" value="2.2" />Opt 2<br /> </td><td> <input name="choice_btn" type="button" value="Confirm" onclick="new AJAX.Updater('my_form', '/process_form', {asynchronous:true, evalScripts:true, parameters:Form.serialize(this.form)}); return false;" /> </td></tr> </table> </form> But I can see that the POST generated by clicking the Confirm button contains the foo and bar values for the hidden fields, but not the choice of the radio buttons. Is this because I've got a table inside my form? How can I get around this?

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  • 'table' undeclared (first use this in a function)

    - by user2318083
    So I'm not sure why this isn't working, I'm creating a new table and setting it to the variable 'table' Is there something I'm doing wrong? This is the error I get when trying to run it: src/simpleshell.c:19:3: error: ‘table’ undeclared (first use in this function) src/simpleshell.c:19:3: note: each undeclared identifier is reported only once for each function it appears in My code is as follows: #include "parser.h" #include "hash_table.h" #include "variables.h" #include "shell.h" #include <stdio.h> int main(void) { char input[MAXINPUTLINE]; table = Table_create(); signal_c_init(); printf("\nhlsh$ "); while(fgets(input, sizeof(input), stdin)){ stripcrlf(input); parse(input); printf("\nhlsh$ "); } Table_free(table); return 0; } Then this is my create a table in the hash_table file: struct Table *Table_create(void){ struct Table *t; t = (struct Table*)calloc(1, sizeof(struct Table)); return t; } From the hash_table.c: #include "hash_table.h" #include "parser.h" #include "shell.h" #include "variables.h" #include <stdio.h> #include <sys/resource.h> #include <sys/wait.h> #include <sys/types.h> #include <stdlib.h> #include <string.h> #include <unistd.h> #include <pwd.h> #include <fcntl.h> #include <limits.h> #include <signal.h> struct Table *table; unsigned int hash(const char *x){ int i; unsigned int h = 0U; for (i=0; x[i]!='\0'; i++){ h = h * 65599 + (unsigned char)x[i]; } return h % 1024; }

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  • Gparted can't create partition table

    - by William
    Here's what the problem is. About a day or so ago I used Gparted live cd to create 3 NTFS primary partitions on my external 500 gig Goflex and one extended with 2 logical partitiones. I had planned to install windows 8 on the first partition, then ubuntu and kubuntu on the other 2. After I finished partitioning my drive with gparted, I booted into windows vista to make my bootable windows 8 usb to install it with, I also decided to check to make sure all my partitions were working properly. Then I found they were, and they weren't. My 50 gig first partition I had planned to install windows on showed up normal and the 300 gigs of space left in the extended partition did as well, the rest showed up as raw. So I figured alright, something went awal while making the partitions, so I booted up gparted once again. Then to my surprise gparted showed the entire drive as unallocated, and when I refreshed the list, it showed as all the partitions I had made earlier, buy with a exclamation mark by them all. So I figured ok, might be a problem with the partition table as I'd seen a similar problem in past on a drive that was not partitioned at all, so I decided to create a new partition table and take the time out again to sit and wait. Then I got a message saying gparted could not create the partition table, followed by it showing the entire drive as formatted into ntfs. After that I figured ok I'll take a break, come back in a hour, maybe it's something I did. So a hour later I came back after having booted up windows, plugged the drive in to see if by some miracle windows could access the drive. In disk management when I plugged the drive in, it would freeze attempting to read the drive, as I'd seen in the past with raw disks, yet when I unplugged it I got a glimpse of disk management showing it as a perfectly fine ntfs file system on the drive followed by a "you must format disk K in order to use it". So I then was assured the disk was raw as that is what had happened in the past, followed by a new partition table through gparted to fix the problem and a 10 hour format in windows. So I once again booted up gparted, to get the message "error fsyncing/closing/dev/sdg:input/output error" followed by "error opening dev/sdg No such file in directory" after I refreshed and somehow saw the disk show up as perfectly fine ntfs and then tried to create a new partition table to try to wipe out all my problems and start over again. And not gparted only shows the drive there about 1/10 refreshes the rest I get the directory error. If anybody can assist me in any way shape or form I will be thankful.

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  • How do I sort a hash table in javascript?

    - by Colen
    I have a javascript hash table, like so: var things = [ ]; things["hello"] = {"name" : "zzz I fell asleep", "number" : 7}; things["one"] = {"name" : "something", "number" : 18}; things["two"] = {"name" : "another thing", "number" : -2}; I want to sort these into order by name, so if I iterate through the hash table it will go in order another thing something zzz I fell asleep I tried doing this: function compareThings(thing1, thing2) { var name1 = thing1["name"].toLowerCase(); var name2 = thing2["name"].toLowerCase(); if (name1 < name2) { return -1; } if (name1 > name2) { return 1; } return 0; } things.sort(compareThings); But it doesn't seem to work. Edit: it occurs to me that perhaps a sorted hash table is an oxymoron. If so, what's the best way to get access to a sorted list of the things here?

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  • SQLite Modify Column

    - by Nathan
    I need to modify a column in a SQLite database but I have to do it programatically due to the database already being in production. From my research I have found that in order to do this I must do the following. Create a new table with new schema Copy data from old table to new table Drop old table Rename new table to old tables name That seems like a ridiculous amount of work for something that should be relatively easy. Is there not an easier way? All I need to do is change a constraint on a existing column and give it a default value.

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  • How to add rows in middle of a table with jQuery?

    - by understack
    I've a table which has customers names along with the products they purchased with their prices. So there are multiple records for each customer. This table is simple 3 column table : name, product and price. What I wanna do is: Put all records belonging to one customer together (I've done it) and just after these rows add one new extra row which would just show total price of all the products each customer has purchased. This row would have empty cell in name and product column. And would have total in price column.

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  • How can I transform this haml into a table?

    - by mmr
    I have the following haml code: - @theLinks.each_index do |x| %br %form{:action=>'/Download', :method=>"post",:enctype=>"multipart/form-data"} %input{:type=>"submit", :name=>"#{@theLinks[x].url}", :value=>"Name: #{@theLinks[x].Name} Study Time: #{@theLinks[x].studyTime} Comments: #{@theLinks[x].comments}"} Basically, for each person, list the time they participated in a study and the comments on the study. Right now, this renders as a set of buttons. I'd like to render it as a table, with each row clickable in the same way (ie, using the 'post' method, so that only the haml file has to be edited without touching the rest of the files). Ideally, I'd also like to be able to sort the table by name, time, or comments, but that might be getting ahead of myself. So how can I change this list of buttons into a table with clickable rows?

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  • SQL Server Table Partitioning, what is happening behind the scenes?

    - by user404463
    I'm working with table partitioning on extremely large fact table in a warehouse. I have executed the script a few different ways. With and without non clustered indexes. With indexes it appears to dramatically expand the log file while without the non clustered indexes it appears to not expand the log file as much but takes more time to run due to the rebuilding of the indexes. What I am looking for is any links or information as to what is happening behind the scene specifically to the log file when you split a table partition.

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  • alter prettyphoto to pull from div or span, not title

    - by Jason
    Here's the section of code from prettyphoto.js that I need to alter. What I am trying to achieve is have each photo have a following hidden div or span that holds the description for the photo. This way I can include html in the description. Possible? Thanks! var images = new Array(), titles = new Array(), descriptions = new Array(); if(theGallery){ $('a[rel*='+theGallery+']').each(function(i){ if($(this)[0] === $(_self)[0]) setPosition = i; // Get the position in the set images.push($(this).attr('href')); titles.push($(this).find('img').attr('alt')); descriptions.push($(this).attr('title')); }); }else{ images = $(this).attr('href'); titles = ($(this).find('img').attr('alt')) ? $(this).find('img').attr('alt') : ''; descriptions = ($(this).attr('title')) ? $(this).attr('title') : ''; } $.prettyPhoto.open(images,titles,descriptions); return false; });

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  • Subsonic: Select on a View, locks the table update?

    - by Jay
    Hi, I have a Web site live and running now. I am using the Subsonic to handle the database connections etc. I am getting time out expired error while updating a table (say Employee). When I check sp_who2, I see the suspended connection for the PID which is updating with a block by anothor pid, so I run the profiler and found out when ever this suspended connection occur, the blocked pid is a select statement on the view (say ActiveEmployees, which is the same as the table but with some where conditions). Anyone know why a Select statement on the view could cause failure in update. If it is other (like select fails due to update) may be reasonable. Is there any way for me to make select on a view without locking the table? PS: I am using the Sql server 2005 and subsonic 2.2. Thanks

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  • New Skool Crosstabbing

    - by Tim Dexter
    A while back I spoke about having to go back to BIP's original crosstabbing solution to achieve a certain layout. Hok Min has provided a 'man' page for the new crosstab/pivot builder for 10.1.3.4.1 users. This will make the documentation drop but for now, get it here! The old, hand method is still available but this new approach, is more efficient and flexible. That said you may need to get into the crosstab code to tweak it where the crosstab dialog can not help. I had to do this, this week but more on that later. The following explains how the crosstab wizard builds the crosstab and what the fields inside the resulting template structure are there for. To create the crosstab a new XDO command "<?crosstab:...?>" has been created. XDO Command: <?crosstab: ctvarname; data-element; rows; columns; measures; aggregation?> Parameter Description Example Ctvarname Crosstab variable name. This is automatically generated by the Add-in. C123 data-element This is the XML data element that contains the data. "//ROW" Rows This contains a list of XML elements for row headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the row header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "Region{,o=a,t=t}, District{,o=a,t=t}" In the example, the first row header is "Region". It is sort by "Region", order is ascending, and type is text. The second row header is "District". It is sort by "District", order is ascending, and type is text. Columns This contains a list of XML elements for columns headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the column header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" In the example, the first column header is "ProductsBrand". It is sort by "ProductsBrand", order is ascending, and type is text. The second column header is "PeriodYear". It is sort by "District", order is ascending, and type is text. Measures This contains a list of XML elements for measures. "Revenue, PrevRevenue" Aggregation The aggregation function name. Currently, we only support "sum". "sum" Using the Oracle BI Publisher Template Builder for Word add-in, we are able to construct the following Pivot Table: The generated XDO command for this Pivot Table is as follow: <?crosstab:c547; "//ROW";"Region{,o=a,t=t}, District{,o=a,t=t}"; "ProductsBrand{,o=a,t=t},PeriodYear{,o=a,t=t}"; "Revenue, PrevRevenue";"sum"?> Running the command on the give XML data files generates this XML file "cttree.xml". Each XPath in the "cttree.xml" is described in the following table. Element XPath Count Description C0 /cttree/C0 1 This contains elements which are related to column. C1 /cttree/C0/C1 4 The first level column "ProductsBrand". There are four distinct values. They are shown in the label H element. CS /cttree/C0/C1/CS 4 The column-span value. It is used to format the crosstab table. H /cttree/C0/C1/H 4 The column header label. There are four distinct values "Enterprise", "Magicolor", "McCloskey" and "Valspar". T1 /cttree/C0/C1/T1 4 The sum for measure 1, which is Revenue. T2 /cttree/C0/C1/T2 4 The sum for measure 2, which is PrevRevenue. C2 /cttree/C0/C1/C2 8 The first level column "PeriodYear", which is the second group-by key. There are two distinct values "2001" and "2002". H /cttree/C0/C1/C2/H 8 The column header label. There are two distinct values "2001" and "2002". Since it is under C1, therefore the total number of entries is 4 x 2 => 8. T1 /cttree/C0/C1/C2/T1 8 The sum for measure 1 "Revenue". T2 /cttree/C0/C1/C2/T2 8 The sum for measure 2 "PrevRevenue". M0 /cttree/M0 1 This contains elements which are related to measures. M1 /cttree/M0/M1 1 This contains summary for measure 1. H /cttree/M0/M1/H 1 The measure 1 label, which is "Revenue". T /cttree/M0/M1/T 1 The sum of measure 1 for the entire xpath from "//ROW". M2 /cttree/M0/M2 1 This contains summary for measure 2. H /cttree/M0/M2/H 1 The measure 2 label, which is "PrevRevenue". T /cttree/M0/M2/T 1 The sum of measure 2 for the entire xpath from "//ROW". R0 /cttree/R0 1 This contains elements which are related to row. R1 /cttree/R0/R1 4 The first level row "Region". There are four distinct values, they are shown in the label H element. H /cttree/R0/R1/H 4 This is row header label for "Region". There are four distinct values "CENTRAL REGION", "EASTERN REGION", "SOUTHERN REGION" and "WESTERN REGION". RS /cttree/R0/R1/RS 4 The row-span value. It is used to format the crosstab table. T1 /cttree/R0/R1/T1 4 The sum of measure 1 "Revenue" for each distinct "Region" value. T2 /cttree/R0/R1/T2 4 The sum of measure 1 "Revenue" for each distinct "Region" value. R1C1 /cttree/R0/R1/R1C1 16 This contains elements from combining R1 and C1. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand". Therefore, the combination is 4 X 4 è 16. T1 /cttree/R0/R1/R1C1/T1 16 The sum of measure 1 "Revenue" for each combination of "Region" and "ProductsBrand". T2 /cttree/R0/R1/R1C1/T2 16 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "ProductsBrand". R1C2 /cttree/R0/R1/R1C1/R1C2 32 This contains elements from combining R1, C1 and C2. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand", and two distinct values of "PeriodYear". Therefore, the combination is 4 X 4 X 2 è 32. T1 /cttree/R0/R1/R1C1/R1C2/T1 32 The sum of measure 1 "Revenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". T2 /cttree/R0/R1/R1C1/R1C2/T2 32 The sum of measure 2 "PrevRevenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". R2 /cttree/R0/R1/R2 18 This contains elements from combining R1 "Region" and R2 "District". Since the list of values in R2 has dependency on R1, therefore the number of entries is not just a simple multiplication. H /cttree/R0/R1/R2/H 18 The row header label for R2 "District". R1N /cttree/R0/R1/R2/R1N 18 The R2 position number within R1. This is used to check if it is the last row, and draw table border accordingly. T1 /cttree/R0/R1/R2/T1 18 The sum of measure 1 "Revenue" for each combination "Region" and "District". T2 /cttree/R0/R1/R2/T2 18 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "District". R2C1 /cttree/R0/R1/R2/R2C1 72 This contains elements from combining R1, R2 and C1. T1 /cttree/R0/R1/R2/R2C1/T1 72 The sum of measure 1 "Revenue" for each combination of "Region", "District" and "ProductsBrand". T2 /cttree/R0/R1/R2/R2C1/T2 72 The sum of measure 2 "PrevRevenue" for each combination of "Region", "District" and "ProductsBrand". R2C2 /cttree/R0/R1/R2/R2C1/R2C2 144 This contains elements from combining R1, R2, C1 and C2, which gives the finest level of details. M1 /cttree/R0/R1/R2/R2C1/R2C2/M1 144 The sum of measure 1 "Revenue". M2 /cttree/R0/R1/R2/R2C1/R2C2/M2 144 The sum of measure 2 "PrevRevenue". Lots to read and digest I know! Customization One new feature I discovered this week is the ability to show one column and sort by another. I had a data set that was extracting month abbreviations, we wanted to show the months across the top and some row headers to the side. As you may know XSL is not great with dates, especially recognising month names. It just wants to sort them alphabetically, so Apr comes before Jan, etc. A way around this is to generate a month number alongside the month and use that to sort. We can do that in the crosstab, sadly its not exposed in the UI yet but its doable. Go back up and take a look a the initial crosstab command. especially the Rows and Columns entries. In there you will find the sort criteria. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" Notice those leading commas inside the curly braces? Because there is no field preceding them it means that the crosstab should sort on the column before the brace ie PeriodYear. But you can insert another column in the data set to sort by. To get my sort working how I needed. <?crosstab:c794;"current-group()";"_Fund_Type_._Fund_Type_Display_{_Fund_Type_._Fund_Type_Sort_,o=a,t=n}";"_Fiscal_Period__Amount__._Amt_Fm_Disp_Abbr_{_Fiscal_Period__Amount__._Amt_Fiscal_Month_Sort_,o=a,t=n}";"_Execution_Facts_._Amt_";"sum"?> Excuse the horribly verbose XML tags, good ol BIEE :0) The emboldened columns are not in the crosstab but are in the data set. I just opened up the field, dropped them in and changed the type(t) value to be 'n', for number, instead of the default 'a' and my crosstab started sorting how I wanted it. If you find other tips and tricks, please share in the comments.

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  • Oracle pl\sql question for my homework in oracle 11G class [migrated]

    - by Bjolds
    I am new to oracle 11G programming and i have run into a tough situation with pl\sql funtions and automation. I ame unsure how to create the function for the automation of Registration system for a College registration system. Here is what i want to do. I want to automate the registrations system so that it automaticly registers students. Then I want a procedure to automate the grading system. I have included the code that i am written to make most of this assignment work which it does but unsure how to incorporate Pl\SQL automated fuctions for the registrations system, and the grading system. So Any help or Ideas I would greatly appreciate please. set Linesize 250 set pagesize 150 drop table student; drop table faculty; drop table Course; drop table Section; drop table location; DROP TABLE courseInstructor; DROP TABLE Registration; DROP TABLE grade; create table student( studentid number(10), Lastname varchar2(20), Firstname Varchar2(20), MI Char(1), address Varchar2(20), city Varchar2(20), state Char(2), zip Varchar2(10), HomePhone Varchar2(10), Workphone Varchar2(10), DOB Date, Pin VARCHAR2(10), Status Char(1)); ALTER TABLE Student Add Constraint Student_StudentID_pk Primary Key (studentID); Insert into student values (1,'xxxxxxxx','xxxxxxxxxx','x','xxxxxxxxxxxxxxx','Columbus','oh','44159','xxx-xxx-xxxx','xxx-xxx-xxxx','06-Mar-1957','1211','c'); create table faculty( FacultyID Number(10), FirstName Varchar2(20), Lastname Varchar2(20), MI Char(1), workphone Varchar2(10), CellPhone Varchar2(10), Rank Varchar2(20), Experience Varchar2(10), Status Char(1)); ALTER TABLE Faculty ADD Constraint Faculty_facultyId_PK PRIMARY KEY (FacultyID); insert into faculty values (1,'xxx','xxxxxxxxxxxx',xxx-xxx-xxxx','xxx-xxx-xxxx','professor','20','f'); create table Course( CourseId number(10), CourseNumber Varchar2(20), CourseName Varchar(20), Description Varchar(20), CreditHours Number(4), Status Char(1)); ALTER TABLE Course ADD Constraint Course_CourseID_pk PRIMARY KEY(CourseID); insert into course values (1,'cit 100','computer concepts','introduction to PCs','3.0','o'); insert into course values (2,'cit 101','Database Program','Database Programming','4.0','o'); insert into course values (3,'Math 101','Algebra I','Algebra I Concepts','5.0','o'); insert into course values (4,'cit 102a','Pc applications','Aplications 1','3.0','o'); insert into course values (5,'cit 102b','pc applications','applications 2','3.0','o'); insert into course values (6,'cit 102c','pc applications','applications 3','3.0','o'); insert into course values (7,'cit 103','computer concepts','introduction systems','3.0','c'); insert into course values (8,'cit 110','Unified language','UML design','3.0','o'); insert into course values (9,'cit 165','cobol','cobol programming','3.0','o'); insert into course values (10,'cit 167','C++ Programming 1','c++ programming','4.0','o'); insert into course values (11,'cit 231','Expert Excel','spreadsheet apps','3.0','o'); insert into course values (12,'cit 233','expert Access','database devel.','3.0','o'); insert into course values (13,'cit 169','Java Programming I','Java Programming I','3.0','o'); insert into course values (14,'cit 263','Visual Basic','Visual Basic Prog','3.0','o'); insert into course values (15,'cit 275','system analysis 2','System Analysis 2','3.0','o'); create table Section( SectionID Number(10), CourseId Number(10), SectionNumber VarChar2(10), Days Varchar2(10), StartTime Date, EndTime Date, LocationID Number(10), SeatAvailable Number(3), Status Char(1)); ALTER TABLE Section ADD Constraint Section_SectionID_PK PRIMARY KEY(SectionID); insert into section values (1,1,'18977','r','21-Sep-2011','10-Dec-2011','1','89','o'); create table Location( LocationId Number(10), Building Varchar2(20), Room Varchar2(5), Capacity Number(5), Satus Char(1)); ALTER TABLE Location ADD Constraint Location_LocationID_pk PRIMARY KEY (LocationID); insert into Location values (1,'Clevleand Hall','cl209','35','o'); insert into Location values (2,'Toledo Circle','tc211','45','o'); insert into Location values (3,'Akron Square','as154','65','o'); insert into Location values (4,'Cincy Hall','ch100','45','o'); insert into Location values (5,'Springfield Dome','SD','35','o'); insert into Location values (6,'Dayton Dorm','dd225','25','o'); insert into Location values (7,'Columbus Hall','CB354','15','o'); insert into Location values (8,'Cleveland Hall','cl204','85','o'); insert into Location values (9,'Toledo Circle','tc103','75','o'); insert into Location values (10,'Akron Square','as201','46','o'); insert into Location values (11,'Cincy Hall','ch301','73','o'); insert into Location values (12,'Dayton Dorm','dd245','57','o'); insert into Location values (13,'Springfield Dome','SD','65','o'); insert into Location values (14,'Cleveland Hall','cl241','10','o'); insert into Location values (15,'Toledo Circle','tc211','27','o'); insert into Location values (16,'Akron Square','as311','28','o'); insert into Location values (17,'Cincy Hall','ch415','73','o'); insert into Location values (18,'Toledo Circle','tc111','67','o'); insert into Location values (19,'Springfield Dome','SD','69','o'); insert into Location values (20,'Dayton Dorm','dd211','45','o'); Alter Table Student Add Constraint student_Zip_CK Check(Rtrim (Zip,'1234567890-') is null); Alter Table Student ADD Constraint Student_Status_CK Check(Status In('c','t')); Alter Table Student ADD Constraint Student_MI_CK2 Check(RTRIM(MI,'abcdefghijklmnopqrstuvwxyz')is Null); Alter Table Student Modify pin not Null; Alter table Faculty Add Constraint Faculty_Status_CK Check(Status In('f','a','i')); Alter table Faculty ADD Constraint Faculty_Rank_CK Check(Rank In ('professor','doctor','instructor','assistant','tenure')); Alter table Faculty ADD Constraint Faculty_MI_CK2 Check(RTRIM(MI,'abcdefghijklmnopqrstuvwxyz')is Null); Update Section Set Starttime = To_date('09-21-2011 6:00 PM', 'mm-dd-yyyy hh:mi pm'); Update Section Set Endtime = To_date('12-10-2011 9:50 PM', 'mm-dd-yyyy hh:mi pm'); alter table Section Add Constraint StartTime_Status_CK Check (starttime < Endtime); Alter Table Section Add Constraint Section_StartTime_ck check (StartTime < EndTime); Alter Table Section ADD Constraint Section_CourseId_FK FOREIGN KEY (CourseID) References Course(CourseId); Alter Table Section ADD Constraint Section_LocationID_FK FOREIGN KEY (LocationID) References Location (LocationId); Alter Table Section ADD Constraint Section_Days_CK Check(RTRIM(Days,'mtwrfsu')IS Null); update section set seatavailable = '99'; Alter Table Section ADD Constraint Section_SeatsAvailable_CK Check (SeatAvailable < 100); Alter Table Course Add Constraint Course_CreditHours_ck check(CreditHours < = 6.0); update location set capacity = '99'; Alter Table Location Add Constraint Location_Capacity_CK Check(Capacity < 100); Create Table Registration ( StudentID Number(10), SectionID Number(10), Constraint Registration_pk Primary key (studentId, Sectionid)); Insert into registration values (1, 2); Insert into Registration values (2, 3); Insert into registration values (3, 4); Insert into registration values (4, 5); Insert into registration values (5, 6); Insert into registration values (6, 7); Insert into registration values (7, 8); Insert into registration values (8, 9); insert into registration values (9, 10); insert into registration values (10, 11); insert into registration values (9, 12); insert into registration values (8, 13); insert into registration values (7, 14); insert into registration values (6, 15); insert into registration values (5, 17); insert into registration values (4, 18); insert into registration values (3, 19); insert into registration values (2, 20); insert into registration values (1, 21); insert into registration values (2, 22); insert into registration values (3, 23); insert into registration values (4, 24); insert into registration values (5, 25); Insert into registration values (6, 24); insert into registration values (7, 23); insert into registration values (8, 22); insert into registration values (9, 21); insert into registration values (10, 20); insert into registration values (9, 19); insert into registration values (8, 17); Create Table courseInstructor( FacultyID Number(10), SectionID Number(10), Constraint CourseInstructor_pk Primary key (FacultyId, SectionID)); insert into courseInstructor values (1, 1); insert into courseInstructor values (2, 2); insert into courseInstructor values (3, 3); insert into courseInstructor values (4, 4); insert into courseInstructor values (5, 5); insert into courseInstructor values (5, 6); insert into courseInstructor values (4, 7); insert into courseInstructor values (3, 8); insert into courseInstructor values (2, 9); insert into courseInstructor values (1, 10); insert into courseInstructor values (5, 11); insert into courseInstructor values (4, 12); insert into courseInstructor values (3, 13); insert into courseInstructor values (2, 14); insert into courseInstructor values (1, 15); Create table grade( StudentID Number(10), SectionID Number(10), Grade Varchar2(1), Constraint grade_pk Primary key (StudentID, SectionID)); CREATE OR REPLACE TRIGGER TR_CreateGrade AFTER INSERT ON Registration FOR EACH ROW BEGIN INSERT INTO grade (SectionID,StudentID,Grade) VALUES(:New.SectionID,:New.StudentID,NULL); END TR_createGrade; / CREATE OR REPLACE FORCE VIEW V_reg_student_course AS SELECT Registration.StudentID, student.LastName, student.FirstName, course.CourseName, Registration.SectionID, course.CreditHours, section.Days, TO_CHAR(StartTime, 'MM/DD/YYYY') AS StartDate, TO_CHAR(StartTime, 'HH:MI PM') AS StartTime, TO_CHAR(EndTime, 'MM/DD/YYYY') AS EndDate, TO_CHAR(EndTime, 'HH:MI PM') AS EndTime, location.Building, location.Room FROM registration, student, section, course, location WHERE registration.StudentID = student.StudentID AND registration.SectionID = section.SectionID AND section.LocationID = location.LocationID AND section.CourseID = course.CourseID; CREATE OR REPLACE FORCE VIEW V_teacher_to_course AS SELECT courseInstructor.FacultyID, faculty.FirstName, faculty.LastName, courseInstructor.SectionID, section.Days, TO_CHAR(StartTime, 'MM/DD/YYYY') AS StartDate, TO_CHAR(StartTime, 'HH:MI PM') AS StartTime, TO_CHAR(EndTime, 'MM/DD/YYYY') AS EndDate, TO_CHAR(EndTime, 'HH:MI PM') AS EndTime, location.Building, location.Room FROM courseInstructor, faculty, section, course, location WHERE courseInstructor.FacultyID = faculty.FacultyID AND courseInstructor.SectionID = section.SectionID AND section.LocationID = location.LocationID AND section.CourseID = course.CourseID; SELECT * FROM V_reg_student_course; SELECT * FROM V_teacher_to_course;

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  • Handling deleted users - separate or same table?

    - by Alan Beats
    The scenario is that I've got an expanding set of users, and as time goes by, users will cancel their accounts which we currently mark as 'deleted' (with a flag) in the same table. If users with the same email address (that's how users log in) wish to create a new account, they can signup again, but a NEW account is created. (We have unique ids for every account, so email addresses can be duplicated amongst live and deleted ones). What I've noticed is that all across our system, in the normal course of things we constantly query the users table checking the user is not deleted, whereas what I'm thinking is that we dont need to do that at all...! [Clarification1: by 'constantly querying', I meant that we have queries which are like: '... FROM users WHERE isdeleted="0" AND ...'. For example, we may need to fetch all users registered for all meetings on a particular date, so in THAT query, we also have FROM users WHERE isdeleted="0" - does this make my point clearer?] (1) continue keeping deleted users in the 'main' users table (2) keep deleted users in a separate table (mostly required for historical book-keeping) What are the pros and cons of either approach?

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  • Dualboot Asus n56v (ubuntu / win 7 x64) - ubuntu doesn't detect partition table made by windows

    - by user76439
    I have an Asus n56v and I've got troubles installing Ubuntu 12.04 x64. I already have installed Windows 7 x64! The hard drive is: Hitachi HTS547575A9E384 My problem: The installation program doesn't recognize the already existing partitions and is offering only options where there are partitions. Can someone help me out? Is this an ACPI/IDE conflict, missing driver or conflict with Windows 7? (I'm not an expert on Linux, only working sometimes with it.) I now tried out some options concerning EFI with a GTP-table. Everything worked but I wasn't able to fix a dual boot (Windows boot loader) nor with GRUB2. The laptop is still having a BIOS, but is able to boot DVDs/CDs in EFI-mode. Now I try to avoid EFI and GTP using the old windows MBR style. I reinstalled Windows, so far no problem. When I want to try to install Ubuntu, it doesn't detect the already existing partition table. It is just showing me an empty space for the whole disk. Other threads like Ubuntu 12.04 does not see windows already install on my computer (dual installation) don't help me out. os-prober shows me a correct result. I don't know how to deal with gdisk as shown in Installer doesn't detect existing partition table/windows 7 partition. I have 750GB for the whole disk. I'm using: 90GB for Windows reserved partition + system partition, 500GB for data and the rest should be for SWAP and linux-system. How can I make Ubuntu detect the partition table?

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  • SQL Server 2005 Table Alter History

    - by Kayes
    Hi. Does SQL Server maintains any history to track table alterations like column add, delete, rename, type/ length change etc? I found many suggest to use stored procedures to do this manually. But I'm curious if SQL Server keeps such history in any system tables? Thanks.

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  • IE7 is making my life miserable! Getting gaps between html table columns (w/ colspan) with css togg

    - by Art Peterson
    Copy/paste this html code snippet and try it out in IE7. When you toggle the hidden columns it leaves a gap between the columns. In Firefox it works fine, the columns touch when minimized. Haven't tried IE8 yet, would be curious to hear how it works there. Any ideas? I've tried a bunch of things in the CSS like table-layout:fixed but no luck. Note: Not looking for a different toggling method because the table I'm really dealing with is 50+ columns wide and 4000+ rows so looping/jquery techniques are too slow. Here's the code - if someone can re-post a working version of it I'll instantly give them the check and be forever in your debt! <DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <script> function toggle() { var tableobj = document.getElementById("mytable"); if (tableobj.className == "") { tableobj.className = "hide1 hide2"; } else { tableobj.className = ""; } } </script> <style> table { border-collapse: collapse; } td, th { border: 1px solid silver; } .hide1 .col1 { display: none; } .hide2 .col2 { display: none; } </style> </head> <body> <input type="button" value="toggle" onclick="toggle();" /> <table id="mytable"> <tr> <th>A</th> <th colspan="2">B</th> <th colspan="2" class="col1">B1</th> <th colspan="2">C</th> <th colspan="2" class="col2">C1</th> </tr> <tr> <td>123</td> <td>456</td> <td>789</td> <td class="col1">123</td> <td class="col1">456</td> <td>789</td> <td>123</td> <td class="col2">456</td> <td class="col2">789</td> </tr> </table> </body> </html>

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  • Sorting the columns of an HTML table using JQuery

    - by nikolaosk
    In this post I will show you how easy is to sort the columns of an HTML table. I will use an external library,called Tablesorter which makes life so much easier for developers. ?here are other posts in my blog regarding JQuery.You can find them all here. You can find another post regarding HTML tables and JQuery here. We will demonstrate this with a step by step example. I will use Visual Studio 2012 Ultimate. You can also use Visual Studio 2012 Express Edition. You can also use VS 2010 editions.   1) Launch Visual Studio. Create an ASP.Net Empty Web application. Choose an appropriate name for your application. 2) Add a web form, default.aspx page to the application. 3) Add a table from the HTML controls tab control (from the Toolbox) on the default.aspx page 4) Now we need to download the JQuery library. Please visit the http://jquery.com/ and download the minified version.Then we need to download the Tablesorter JQuery plugin. Please donwload it, here. 5) We need to reference the JQuery library and the external JQuery Plugin. In the head section ? add the following lines.   <script src="jquery-1_8_2_min.js" type="text/javascript"></script>  <script src="jquery.tablesorter.js" type="text/javascript"></script>6) We need to type the HTML markup, the HTML table and its columns <body>    <form id="form1" runat="server">    <div>        <h1>Liverpool Legends</h1>        <table style="width: 50%;" border="1" cellpadding="10" cellspacing ="10" class="liverpool">            <thead>                <tr><th>Defenders</th><th>MidFielders</th><th>Strikers</th></tr>            </thead>            <tbody>            <tr>                <td>Alan Hansen</td>                <td>Graeme Souness</td>                <td>Ian Rush</td>            </tr>            <tr>                <td>Alan Kennedy</td>                <td>Steven Gerrard</td>                <td>Michael Owen</td>            </tr>            <tr>                <td>Jamie Garragher</td>                <td>Kenny Dalglish</td>                <td>Robbie Fowler</td>            </tr>            <tr>                <td>Rob Jones</td>                <td>Xabi Alonso</td>                <td>Dirk Kuyt</td>            </tr>                </tbody>        </table>            </div>    </form></body> 7) Inside the head section we also write the simple JQuery code.   <script type="text/javascript"> $(document).ready(function() { $('.liverpool').tablesorter(); }); </script> 8) Run your application.This is how the HTML table looks before the table is sorted on the basis of the selected column.   9) Now I will click on the Midfielders header.Have a look at the picture below  Tablesorter is an excellent JQuery plugin that makes sorting HTML tables a piece of cake. Hope it helps!!!

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  • How to Plug a Small Hole in NetBeans JSF (Join Table) Code Generation

    - by MarkH
    I was asked recently to provide an assist with designing and building a small-but-vital application that had at its heart some basic CRUD (Create, Read, Update, & Delete) functionality, built upon an Oracle database, to be accessible from various locations. Working from the stated requirements, I fleshed out the basic application and database designs and, once validated, set out to complete the first iteration for review. Using SQL Developer, I created the requisite tables, indices, and sequences for our first run. One of the tables was a many-to-many join table with three fields: one a primary key for that table, the other two being primary keys for the other tables, represented as foreign keys in the join table. Here is a simplified example of the trio of tables: Once the database was in decent shape, I fired up NetBeans to let it have first shot at the code. NetBeans does a great job of generating a mountain of essential code, saving developers what must be millions of hours of effort each year by building a basic foundation with a few clicks and keystrokes. Lest you think it (or any tool) can do everything for you, however, occasionally something tosses a paper clip into the delicate machinery and makes you open things up to fix them. Join tables apparently qualify.  :-) In the case above, the entity class generated for the join table (New Entity Classes from Database) included an embedded object consisting solely of the two foreign key fields as attributes, in addition to an object referencing each one of the "component" tables. The Create page generated (New JSF Pages from Entity Classes) worked well to a point, but when trying to save, we were greeted with an error: Transaction aborted. Hmm. A quick debugger session later and I'd identified the issue: when trying to persist the new join-table object, the embedded "foreign-keys-only" object still had null values for its two (required value) attributes...even though the embedded table objects had populated key attributes. Here's the simple fix: In the join-table controller class, find the public String create() method. It will look something like this:     public String create() {        try {            getFacade().create(current);            JsfUtil.addSuccessMessage(ResourceBundle.getBundle("/Bundle").getString("JoinEntityCreated"));            return prepareCreate();        } catch (Exception e) {            JsfUtil.addErrorMessage(e, ResourceBundle.getBundle("/Bundle").getString("PersistenceErrorOccured"));            return null;        }    } To restore balance to the force, modify the create() method as follows (changes in red):     public String create() {         try {            // Add the next two lines to resolve:            current.getJoinEntityPK().setTbl1id(current.getTbl1().getId().toBigInteger());            current.getJoinEntityPK().setTbl2id(current.getTbl2().getId().toBigInteger());            getFacade().create(current);            JsfUtil.addSuccessMessage(ResourceBundle.getBundle("/Bundle").getString("JoinEntityCreated"));            return prepareCreate();        } catch (Exception e) {            JsfUtil.addErrorMessage(e, ResourceBundle.getBundle("/Bundle").getString("PersistenceErrorOccured"));            return null;        }    } I'll be refactoring this code shortly, but for now, it works. Iteration one is complete and being reviewed, and we've met the milestone. Here's to happy endings (and customers)! All the best,Mark

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  • How to add a default value to an already existing column?

    - by Earlz
    I have an existing column in my SQL Server database. I have tried about everything I can think of but can not get a default value to be added to the column. What works in every other database is alter table mytable alter column mycolumn set default(now()) --mycolumn is a datetime How do I do this in SQL Server? The error I get for that exact syntax is incorrect syntax near the keyword 'set'

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  • How to change the primary key to be non-clustered?

    - by AngryHacker
    Part-time reluctant DBA here. I want to change an existing primary key index from clustered to non-clustered. And the syntax is escaping me. This is how it's scripted out right now. ALTER TABLE [dbo].[Config] WITH NOCHECK ADD CONSTRAINT [PK_Config] PRIMARY KEY CLUSTERED ( [ConfigID] ) ON [PRIMARY] I am not seeing an ALTER CONSTRAINT statement in the online docs.

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  • tcpdf table header in each page

    - by DragoN
    i am using tcpdf to create pdf files with rows of table in the first page of pdf i display some info like : List of table .... and header of table after that i display the rows in table if there much rows it contiunes in the next page without the info [List of table... and header of table] i want to display the header of table only in the next pages here is my code $pdf->SetFont('aefurat', '', 15); $pdf->AddPage('P', 'A4'); $pdf->SetFontSize(17); $pdf->Cell(0, 13, 'List of the Byan Table,'C'); $pdf->SetFont('dejavusans', '', 14); $htmlpersian = 'In / Out List'; $pdf->WriteHTML($htmlpersian, true, 0, true, 0); $pdf->setRTL(false); $pdf->SetFontSize(11); $pdf->setRTL(true); Connect(); $resultsc = mysql_query("SELECT * FROM byan Order By Date "); while($r = mysql_fetch_array($resultsc)) { $printresult .= ' <tr> <td ><center>'.$r['Date'].'</center></td> <td ><center>'.$r['In'].'</center></td> <td ><center>'.$r['Out'].'</center></td> <td ><center>'.$r['Balance'].'</center></td> <td ><center>'.$r['Info'].'</center></td> <td ><center>'.$r['Number'].'</center></td> </tr>'; } $tbl = ' <table cellspacing="0" cellpadding="1" border="1" align="center"> <tr> <td style="width: 13%; background-color:black; color:white;"><center>Date</center></td> <td style="width: 11%; background-color:black; color:white;"><center>In</center></td> <td style="width: 11%; background-color:black; color:white;"><center>Out</center></td> <td style="width: 12%; background-color:black; color:white;"><center>Balance</center></td> <td style="width: 45%; background-color:black; color:white;"><center>Info</center></td> <td style="width: 11%; background-color:black; color:white;"><center>Number</center></td> </tr> '.$printresult.' </table> '; $pdf->writeHTML($tbl, true, false, true, false, ''); the output is First Page: List of the Byan Table In / Out List Table Header rows Second Page: Rows Third Page: Rows i want the output to be like that First Page: List of the Byan Table In / Out List Table Header Rows Second Page: Table Header Rows Third Page: Table Header Rows

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  • Joins in single-table queries

    - by Rob Farley
    Tables are only metadata. They don’t store data. I’ve written something about this before, but I want to take a viewpoint of this idea around the topic of joins, especially since it’s the topic for T-SQL Tuesday this month. Hosted this time by Sebastian Meine (@sqlity), who has a whole series on joins this month. Good for him – it’s a great topic. In that last post I discussed the fact that we write queries against tables, but that the engine turns it into a plan against indexes. My point wasn’t simply that a table is actually just a Clustered Index (or heap, which I consider just a special type of index), but that data access always happens against indexes – never tables – and we should be thinking about the indexes (specifically the non-clustered ones) when we write our queries. I described the scenario of looking up phone numbers, and how it never really occurs to us that there is a master list of phone numbers, because we think in terms of the useful non-clustered indexes that the phone companies provide us, but anyway – that’s not the point of this post. So a table is metadata. It stores information about the names of columns and their data types. Nullability, default values, constraints, triggers – these are all things that define the table, but the data isn’t stored in the table. The data that a table describes is stored in a heap or clustered index, but it goes further than this. All the useful data is going to live in non-clustered indexes. Remember this. It’s important. Stop thinking about tables, and start thinking about indexes. So let’s think about tables as indexes. This applies even in a world created by someone else, who doesn’t have the best indexes in mind for you. I’m sure you don’t need me to explain Covering Index bit – the fact that if you don’t have sufficient columns “included” in your index, your query plan will either have to do a Lookup, or else it’ll give up using your index and use one that does have everything it needs (even if that means scanning it). If you haven’t seen that before, drop me a line and I’ll run through it with you. Or go and read a post I did a long while ago about the maths involved in that decision. So – what I’m going to tell you is that a Lookup is a join. When I run SELECT CustomerID FROM Sales.SalesOrderHeader WHERE SalesPersonID = 285; against the AdventureWorks2012 get the following plan: I’m sure you can see the join. Don’t look in the query, it’s not there. But you should be able to see the join in the plan. It’s an Inner Join, implemented by a Nested Loop. It’s pulling data in from the Index Seek, and joining that to the results of a Key Lookup. It clearly is – the QO wouldn’t call it that if it wasn’t really one. It behaves exactly like any other Nested Loop (Inner Join) operator, pulling rows from one side and putting a request in from the other. You wouldn’t have a problem accepting it as a join if the query were slightly different, such as SELECT sod.OrderQty FROM Sales.SalesOrderHeader AS soh JOIN Sales.SalesOrderDetail as sod on sod.SalesOrderID = soh.SalesOrderID WHERE soh.SalesPersonID = 285; Amazingly similar, of course. This one is an explicit join, the first example was just as much a join, even thought you didn’t actually ask for one. You need to consider this when you’re thinking about your queries. But it gets more interesting. Consider this query: SELECT SalesOrderID FROM Sales.SalesOrderHeader WHERE SalesPersonID = 276 AND CustomerID = 29522; It doesn’t look like there’s a join here either, but look at the plan. That’s not some Lookup in action – that’s a proper Merge Join. The Query Optimizer has worked out that it can get the data it needs by looking in two separate indexes and then doing a Merge Join on the data that it gets. Both indexes used are ordered by the column that’s indexed (one on SalesPersonID, one on CustomerID), and then by the CIX key SalesOrderID. Just like when you seek in the phone book to Farley, the Farleys you have are ordered by FirstName, these seek operations return the data ordered by the next field. This order is SalesOrderID, even though you didn’t explicitly put that column in the index definition. The result is two datasets that are ordered by SalesOrderID, making them very mergeable. Another example is the simple query SELECT CustomerID FROM Sales.SalesOrderHeader WHERE SalesPersonID = 276; This one prefers a Hash Match to a standard lookup even! This isn’t just ordinary index intersection, this is something else again! Just like before, we could imagine it better with two whole tables, but we shouldn’t try to distinguish between joining two tables and joining two indexes. The Query Optimizer can see (using basic maths) that it’s worth doing these particular operations using these two less-than-ideal indexes (because of course, the best indexese would be on both columns – a composite such as (SalesPersonID, CustomerID – and it would have the SalesOrderID column as part of it as the CIX key still). You need to think like this too. Not in terms of excusing single-column indexes like the ones in AdventureWorks2012, but in terms of having a picture about how you’d like your queries to run. If you start to think about what data you need, where it’s coming from, and how it’s going to be used, then you will almost certainly write better queries. …and yes, this would include when you’re dealing with regular joins across multiples, not just against joins within single table queries.

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  • Configuration data: single-row table vs. name-value-pair table

    - by Heinzi
    Let's say you write an application that can be configured by the user. For storing this "configuration data" into a database, two patterns are commonly used. The single-row table CompanyName | StartFullScreen | RefreshSeconds | ... ---------------+-------------------+------------------+-------- ACME Inc. | true | 20 | ... The name-value-pair table ConfigOption | Value -----------------+------------- CompanyName | ACME Inc. StartFullScreen | true (or 1, or Y, ...) RefreshSeconds | 20 ... | ... I've seen both options in the wild, and both have obvious advantages and disadvantages, for example: The single-row tables limits the number of configuration options you can have (since the number of columns in a row is usually limited). Every additional configuration option requires a DB schema change. In a name-value-pair table everything is "stringly typed" (you have to encode/decode your Boolean/Date/etc. parameters). (many more) Is there some consensus within the development community about which option is preferable?

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  • Use alpha or opacity on a table row using CSS [migrated]

    - by mserin
    I have a CSS stylesheet for a webpage. The webpage has a table with a background color of white (set in the rows, not the table). I would like to set the opacity or alpha to 50%. I have tried so many variations, but come up with no luck. A typical row in the HTML file is: <tr> <td>&nbsp;</td> <td>Twitter</td> </tr> The CSS settings for table rows (which works perfectly) is: tr { font-family: Arial, Helvetica, sans-serif; background:rgb(255,255,255); } To get the alpha, I tried tr { font-family: Arial, Helvetica, sans-serif; background-color:rgba(255,255,255,0.5); } I have also tried background-color-opacity: 0.5; Any other suggestions?

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  • Learning PostgreSql: old versions of rows are stored right in the table

    - by Alexander Kuznetsov
    PostgreSql features multi-version concurrency control aka MVCC. To implement MVCC, old versions of rows are stored right in the same table, and this is very different from what SQL Server does, and it leads to some very interesting consequences. Let us play with this thing a little bit, but first we need to set up some test data. Setting up. First of all, let us create a numbers table. Any production database must have it anyway: CREATE TABLE Numbers ( i INTEGER ); INSERT INTO Numbers ( i ) VALUES...(read more)

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