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  • Django - transactions in the model?

    - by orokusaki
    Models (disregard typos / minor syntax issues. It's just pseudo-code): class SecretModel(models.Model): some_unique_field = models.CharField(max_length=25, unique=True) # Notice this is unique. class MyModel(models.Model): secret_model = models.OneToOneField(SecretModel, editable=False) # Not in the form spam = models.CharField(max_length=15) foo = models.IntegerField() def clean(self): SecretModel.objects.create(some_unique_field=self.spam) Now if I go do this: MyModel.objects.create(spam='john', foo='OOPS') # Obviously foo won't take "OOPS" as it's an IntegerField. #.... ERROR HERE MyModel.objects.create(spam='john', foo=5) # So I try again here. #... IntegrityError because SecretModel with some_unique_field = 'john' already exists. I understand that I could put this into a view with a request transaction around it, but I want this to work in the Admin, and via an API, etc. Not just with forms, or views. How is it possible?

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  • Inline Form Validation in Django

    - by allanhenderson
    Newbie request that seems difficult to implement. I would like to make an entire inline formset within an admin change form compulsory.. so in my current scenario when I hit save on an Invoice form (in Admin) the inline Order form is blank. I'd like to stop people creating invoices with no orders associated. Anyone know an easy way to do that? Normal validation like (required=True) on the model field doesn't appear to work in this instance. Thanks!!

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  • Multiprogramming in Django, writing to the Database

    - by Marcus Whybrow
    Introduction I have the following code which checks to see if a similar model exists in the database, and if it does not it creates the new model: class BookProfile(): # ... def save(self, *args, **kwargs): uniqueConstraint = {'book_instance': self.book_instance, 'collection': self.collection} # Test for other objects with identical values profiles = BookProfile.objects.filter(Q(**uniqueConstraint) & ~Q(pk=self.pk)) # If none are found create the object, else fail. if len(profiles) == 0: super(BookProfile, self).save(*args, **kwargs) else: raise ValidationError('A Book Profile for that book instance in that collection already exists') I first build my constraints, then search for a model with those values which I am enforcing must be unique Q(**uniqueConstraint). In addition I ensure that if the save method is updating and not inserting, that we do not find this object when looking for other similar objects ~Q(pk=self.pk). I should mention that I ham implementing soft delete (with a modified objects manager which only shows non-deleted objects) which is why I must check for myself rather then relying on unique_together errors. Problem Right thats the introduction out of the way. My problem is that when multiple identical objects are saved in quick (or as near as simultaneous) succession, sometimes both get added even though the first being added should prevent the second. I have tested the code in the shell and it succeeds every time I run it. Thus my assumption is if say we have two objects being added Object A and Object B. Object A runs its check upon save() being called. Then the process saving Object B gets some time on the processor. Object B runs that same test, but Object A has not yet been added so Object B is added to the database. Then Object A regains control of the processor, and has allready run its test, even though identical Object B is in the database, it adds it regardless. My Thoughts The reason I fear multiprogramming could be involved is that each Object A and Object is being added through an API save view, so a request to the view is made for each save, thus not a single request with multiple sequential saves on objects. It might be the case that Apache is creating a process for each request, and thus causing the problems I think I am seeing. As you would expect, the problem only occurs sometimes, which is characteristic of multiprogramming or multiprocessing errors. If this is the case, is there a way to make the test and set parts of the save() method a critical section, so that a process switch cannot happen between the test and the set?

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  • Formwizards for editing in Django

    - by Espen Christensen
    Hi, I am in the process of making a webapp, and this webapp needs to have a form wizard. The wizard consists of 3 ModelForms, and it works flawlessly. But I need the second form to be a "edit form". That is, i need it to be a form that is passed an instance. How can you do this with a form wizard? How do you pass in an instance of a model? I see that the FormWizard class has a get_form method, but isnt there a documented way to use the formwizard for editing/reviewing of data?

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  • Joining different models in Django

    - by Andrew Roberts
    Let's say I have this data model: class Workflow(models.Model): ... class Command(models.Model): workflow = models.ForeignKey(Workflow) ... class Job(models.Model): command = models.ForeignKey(Command) ... Suppose somewhere I want to loop through all the Workflow objects, and for each workflow I want to loop through its Commands, and for each Command I want to loop through each Job. Is there a way to structure this with a single query? That is, I'd like Workflow.objects.all() to join in its dependent models, so I get a collection that has dependent objects already cached, so workflows[0].command_set.get() doesn't produce an additional query. Is this possible?

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  • Django and json request

    - by Hulk
    In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

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  • Django: Overriding ModelAdmin save_model not working

    - by tufelkinder
    Even after obj.save(), the obj still does not have an id, so I cannot access or manipulate the m2m records. Just keep getting a "instance needs to have a primary key value before a many-to-many relationship can be used" error. def save_model(self, request, obj, form, change): obj.save() # this doesn't work super(Table2Admin, self).save_model(request, obj, form, change) # still doesn't save for tb1 in obj.table1.all: tb1_obj = ThroughTable.objects.get(table1=bk, table2=obj) # do other stuff What am I doing wrong? Why do I need to do to save this model?

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  • In Django, why is user.is_authenticated a method and not a member variable like is_staff

    - by luc
    Hello all, I've lost some time with a bug in my app due to user authentication. I think that it's a bit confusing but maybe someone can explain the reason and it will appear to me very logical. The user.is_staff is a member variable while user.is_authenticated is a method. However is_authenticated only returns True or False depending if the class is User or AnonymousUser (see http://docs.djangoproject.com/en/dev/topics/auth/) Is there a reason for that? Why user.is_authenticated is a method? Thanks in advance

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  • In plain English, what are Django generic views?

    - by allyourcode
    The first two paragraphs of this page explain that generic views are supposed to make my life easier, less monotonous, and make me more attractive to women (I made up that last one): http://docs.djangoproject.com/en/dev/topics/generic-views/#topics-generic-views I'm all for improving my life, but what do generic views actually do? It seems like lots of buzzwords are being thrown around, which confuse more than they explain. Are generic views similar to scaffolding in Ruby on Rails? The last bullet point in the intro seems to indicate this. Is that an accurate statement?

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  • how to save django object using dictionary?

    - by shahjapan
    is there a way that I can save the model by using dictionary for e.g. this is working fine, p1 = Poll.objects.get(pk=1) p1.name = 'poll2' p1.descirption = 'poll2 description' p1.save() but what if I have dictionary like { 'name': 'poll2', 'description: 'poll2 description' } is there a simple way to save the such dictionary direct to Poll

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  • Django: FloatField or DecimalFied for Currency ?

    - by Hellnar
    I am curious which one would be better fitting as a currency field ? I will do simple operations such as taking difference, the percentage between old and new prices. I plan to keep two digits after the zero (ie 10.50) and majority of the time if these digits are zero, I will be hiding these numbers and display it as "10"

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  • Django show manytomanyfield on form when definition is on other model

    - by John
    Hi I have the definition for my manytomany relationship on one model but want to display the field on a form for the other model. How do I do this? for example: # classes class modelA(models.Model): name = models.CharField(max_length=300) manytomany = models.ManyToManyField(modelA) class modelB(models.Model): name = models.CharField(max_length=300) # forms class modelBForm(forms.ModelForm): class Meta: model = modelB I want to use the form modelBForm but show a select box with a list from modelA (just how it would work if the model was set to modelA in the form class). How can I do this? Thanks

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  • How do I make nested regroups in Django?

    - by Marcio Cruz
    I've got the following situation in this system: Each category of products has many subcategories, and each subcategory has many products under it. I'm trying to make a product searh, which returns a list, and in my template, I show an overview of the results, like this: Cellphones Dumbphones (2 results) Smartphones (3 results) Monitors CRT (1 result) LCD (3 results) I'm my template I have only the list of products. I've tryed many combinations of nested regroups, without success. Any ideas?

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  • SelectDateWidget in Django Admin?

    - by Maria
    Can i change default AdminDateWidget to SelectDateWidget in my models? How can i do this? I try: class RespondentAdmin(admin.ModelAdmin): formfield_overrides = { models.DateField: {'widget': SelectDateWidget}, } but it doesn't work

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  • Django url tag multiple parameters

    - by Overdose
    I have two similar codes. The first one works as expected. urlpatterns = patterns('', (r'^(?P<n1>\d)/test/', test), (r'', test2), {% url testapp.views.test n1=5 %} But adding the second parameter makes the result return empty string. urlpatterns = patterns('', (r'^(?P<n1>\d)/test(?P<n2>\d)/', test), (r'', test2),) {% url testapp.views.test n1=5, n2=2 %} Views signature: def test(request, n1, n2=1):

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  • Django sys.path.append for project *and* app needed under WSGI

    - by GerardJP
    Hi all, Could somebody give me a pointer on why I need to add my project root path to the python path as well as the application itself in my WSGI file? Project base is called 'djapp', the application is called 'myapp'. sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/..') sys.path.append(os.path.dirname(os.path.abspath(__file__)) + '/../djapp') os.environ['DJANGO_SETTINGS_MODULE'] = 'djapp.settings' If I omit the line with "/../djapp/" the log tells my that 'myapp' can not be imported, even though 'djapp.settings' is. (validating 'djapp' was imported) It al runs properly with the ./manage.py command. there's a __init__ in the project folder. For testings sake, I see the same issue using addsitedir: site.addsitedir('/home/user/web/project/') site.addsitedir('/home/user/web/project/djapp') Thanx a lot. Gerard.

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  • Django save method

    - by Marijus
    So I have a model with a FileField for excel spreadsheet. What I need to do this add another column in this spreadsheet, in each row let user pick from a drop-down list then save it and display it in html. All the picking and uploading will happen through the admin interface. So I have figured out way how to display a spreadsheet in html, however I have no idea how to write this save method. I could really use some hints and tips..

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  • how to display fixed dropdown in django admin?

    - by FurtiveFelon
    Hi all, I would like to display priority information in a drop down. Currently i am using a integer field to store the priority, but i would like to display high/medium/low instead of letting user type in a priority. A way to approximate this is to use a Priority database which stores 3 elements, 1:high, 2:medium, 3:low, but it seems like an overkill. Any easier way would be much appreciated! Jason

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  • Django: Serializing models in a nested data structure?

    - by Rosarch
    It's easy to serialize models in an iterable: def _toJSON(models): return serializers.serialize("json", models, ensure_ascii=False) What about when I have something more complicated: [ (Model_A_1, [Model_B_1, Model_B_2, Model_B_3]), (Model_A_2, [Model_B_3, Model_B_4, Model_B_5, Model_B_59]), (Model_A_3, [Model_B_6, Model_B_7]), ] I tried serializing each model as it was added to the structure, then serializing the whole thing with simplejson.dumps, but that causes the JSON defining each model to be escaped. Is there a better way to do this?

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  • Django: How can I protect against concurrent modification of data base entries

    - by Ber
    If there a way to protect against concurrent modifications of the same data base entry by two or more users? It would be acceptable to show an error message to the user performing the second commit/save operation, but data should not be silently overwritten. I think locking the entry is not an option, as a user might use the "Back" button or simply close his browser, leaving the lock for ever.

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  • Django get_FOO_display and distinct()

    - by datakid
    I've seen answers to both halves of my question, but I can't work out how to marry the two. I have a book model, and a translatedBook model. The translatedBook has a langage set up as model choices in the usual way: LANGUAGES = ( (u'it', u'Italian'), (u'ja', u'Japanese'), (u'es', u'Spanish'), (u'zh-cn', u'Simplified Chinese'), (u'zh-tw', u'Traditional Chinese'), (u'fr', u'French'), (u'el', u'Greek'), (u'ar', u'Arabic'), (u'bg', u'Bulgarian'), (u'bn', u'Bengali'), etc I know that to get "Italian" I have to do translatedBook.get_language_display on a Book object. But how do I get a list of distinct languages in their long format? I've tried: lang_avail = TargetText.objects.values('language').distinct().order_by('language') lang_avail = TargetText.objects.distinct().order_by('language').values('language'). lang_avail = TargetText.objects.all().distinct('language').order_by('language') but I can't seem to get what I want - which is a list like: "English, Italian, Simplified Chinese, Spanish" The final lang_avail listed above didn't return the list of 5, it returned the list of 355 (ie, # of books) with multiple repeats....

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