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  • Is there a BitTorrent client that can download files "in sequence"?

    - by Bob M
    Is there a BitTorrent client that can download files "in sequence"? For example, download clip 01.avi (high priority) clip 02.avi (normal priority) clip 03.avi (low priority) clip 04.avi (low) clip 05.avi (low) then when clip 01.avi is done, it will automatically make it: clip 01.avi (high priority) clip 02.avi (high priority) clip 03.avi (normal priority) clip 04.avi (low priority) clip 05.avi (low) this can be useful when download *.rar as well, since download clip.rar, and then clip.r00, r01, r02, in sequence can allow previewing the file by using RAR to recompose the file (even though incomplete file, but will allow previewing). Update: will making all files active still considered a bad use of BT?

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  • How can I compare between web development technologies?

    - by Steve
    I would like experts to explain for me how can I compare between web development tools or technologies in order to be able to choose the right one. I'm tired from searching always in the regular way: X Technology vs Y Technology. I'm tired from peoples' biased opinions and usually I don't find a fair comparison. I have decided to put my question here about how can I compare them so you may identify to me the main standards for comparisons so I can compare them by myself and becoming able to choose the technology that is appropriate for the project I will develop. Note: in web development technologies I mean server side languages (e.g. PHP). One important requirement for me that can be defined as major one is cost efficiency and I mean that I don't care about the cost in the near future or the current cost, but what is more important for me is the cost in the future. If, for example, the site becomes one of the most 100 visited sites.   So, how can I compare the cost of different technologies for a future status of a site (such as being very famous site) so I can scale my option easily without missing a good technology like what happened with some sites when they chose not the most effective tool.

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  • News Flash: Hong Kong Housing Society Improves Governance Control, Reduces Costs by 25%, Speeds up Approval by 30%

    - by Ruma Sanyal
    “We selected Oracle Fusion Middleware for its superior local support, higher performance, availability, reliability, and flexible enterprise architecture to cost-effectively integrate with existing Oracle applications", said Mr. C.W. Miao, Head of Information Technology, Hong Kong Housing Society in a press release today. To address the challenge of frequent downtime during peak periods and increasing cost in maintaining its legacy systems, Hong Kong Housing Society replaced its legacy systems with Oracle's WebLogic Suite, BPM Suite, and the ADF Framework. The Fusion Middleware solutions provide Hong Kong Housing Society with a flexible, reliable and cost-effective enterprise architecture that enables integration with existing Oracle applications including JD Edwards EnterpriseOne and PeopleSoft. The cost savings and performance results clearly demonstrate significant benefits. Read the PR for complete details.

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  • 7 Steps To Cut Recruiting Costs & Drive Exceptional Business Results

    - by Oracle Accelerate for Midsize Companies
    By Steve Viarengo, Vice President Product Management, Oracle Taleo Cloud Services  Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 In good times, trimming operational costs is an ongoing goal. In tough times, it’s a necessity. In both good times and bad, however, recruiting occurs. Growth increases headcount in good times, and opportunistic or replacement hiring occurs in slow business cycles. By employing creative recruiting strategies in tandem with the latest technology developments, you can reduce recruiting costs while driving exceptional business results. Here are some critical areas to focus on. 1.  Target Direct Cost Savings Total recruiting process expenses are the sum of external costs plus internal labor costs. Most organizations can reduce recruiting expenses with direct cost savings. While additional savings on indirect costs can be realized from process improvement and efficiency gains, there are direct cost savings and benefits readily available in three broad areas: sourcing, assessments, and green recruiting. 2. Sourcing: Reduce Agency Costs Agency search firm fees can amount to 35 percent of a new employee’s annual base salary. Typically taken from the hiring department budget, these fees may not be visible to HR. By relying on internal mobility programs, referrals, candidate pipelines, and corporate career Websites, organizations can reduce or eliminate this agency spend. And when you do have to pay third-party agency fees, you can optimize the value you receive by collaborating with agencies to identify referred candidates, ensure access to candidate data and history, and receive automatic notifications and correspondence. 3. Sourcing: Reduce Advertising Costs You can realize significant cost reductions by placing all job positions on your corporate career Website. This will allow you to reap a substantial number of candidates at minimal cost compared to job boards and other sourcing options. 4.  Sourcing: Internal Talent Pool Internal talent pools provide a way to reduce sourcing and advertising costs while delivering improved productivity and retention. Internal redeployment reduces costs and ramp-up time while increasing retention and employee satisfaction. 5.  Sourcing: External Talent Pool Strategic recruiting requires identifying and matching people with a given set of skills to a particular job while efficiently allocating sourcing expenditures. By using an e-recruiting system (which drives external talent pool management) with a candidate relationship database, you can automate prescreening and candidate matching while communicating with targeted candidates. Candidate relationship management can lower sourcing costs by marketing new job opportunities to candidates sourced in the past. By mining the talent pool in this fashion, you eliminate the need to source a new pool of candidates for each new requisition. Managing and mining the corporate candidate database can reduce the sourcing cost per candidate by as much as 50 percent. 6.  Assessments: Reduce Turnover Costs By taking advantage of assessments during the recruitment process, you can achieve a range of benefits, including better productivity, superior candidate performance, and lower turnover (providing considerable savings). Assessments also save recruiter and hiring manager time by focusing on a short list of qualified candidates. Hired for fit, such candidates tend to stay with the organization and produce quality work—ultimately driving revenue.  7. Green Recruiting: Reduce Paper and Processing Costs You can reduce recruiting costs by automating the process—and making it green. A paperless process informs candidates that you’re dedicated to green recruiting. It also leads to direct cost savings. E-recruiting reduces energy use and pollution associated with manufacturing, transporting, and recycling paper products. And process automation saves energy in mailing, storage, handling, filing, and reporting tasks. Direct cost savings come from reduced paperwork related to résumés, advertising, and onboarding. Improving the recruiting process through sourcing, assessments, and green recruiting not only saves costs. It also positions the company to improve the talent base during the recession while retaining the ability to grow appropriately in recovery. /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";} Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";}

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  • external disk dont work on ubuntu

    - by Skirki
    i have problem with in my ubuntu: when i connect external imation apollo disc i dont see a file system. Disk is working because in windows OS on this same computer it works as well. when i typed dmesg i got following logs [12913.260078] usb 4-1: new low speed USB device using ohci_hcd and address 15 [12913.440072] usb 4-1: device descriptor read/64, error -62 [12913.730058] usb 4-1: device descriptor read/64, error -62 [12914.020085] usb 4-1: new low speed USB device using ohci_hcd and address 16 [12914.200082] usb 4-1: device descriptor read/64, error -62 [12914.490150] usb 4-1: device descriptor read/64, error -62 [12914.780064] usb 4-1: new low speed USB device using ohci_hcd and address 17 [12915.200070] usb 4-1: device not accepting address 17, error -62 [12915.380081] usb 4-1: new low speed USB device using ohci_hcd and address 18 [12915.800065] usb 4-1: device not accepting address 18, error -62 [12915.800100] hub 4-0:1.0: unable to enumerate USB device on port 1 i trying to fix that by use commands: cd /sys/bus/pci/drivers/ehci_hcd echo -n "0000:00:02.1" unbind but it did not match the result and i don't have any other idea

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  • Estimating costs in a GOAP system

    - by fullwall
    I'm currently developing a GOAP system in Java. An explanation of GOAP can be found at http://web.media.mit.edu/~jorkin/goap.html. Essentially, it's using A* to plot between Actions that mutate the world state. To provide a fair chance for all Actions and Goals to execute, I'm using a heuristic function to estimate the cost of doing something. What is the best way to estimate this cost so that it is comparable to all the other costs? As an example, estimating the cost of running away from an enemy versus attacking it - how should the cost be calculated to be comparable?

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  • How to make the most of GWT's "Search queries"?

    - by DisgruntledGoat
    I've been looking at the "Search queries" section in Google Webmaster Tools recently, and it seems like there is a lot of potential there in finding which pages on a site need improvement. I'm trying to figure out exactly what to sort or filter on. Do I look at pages with a low average position? Low impressions but high clicks? Pages that are rising up/falling down the rankings? What is the low-hanging fruit here?

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  • Database Insider - December 2012 issue

    - by Javier Puerta
    The December issue of the Database Insider newsletter is now available. (Full newsletter here) Big Data: From Acquisition to Analysis 2012 will likely be remembered as the year of big data, as a new generation of technologies enables organizations to acquire, organize, and analyze the exponentially growing and typically less-structured data generated from a variety of new sources. Oracle has produced a series of five short videos that offer a quick and compelling high-level introduction to big data. Read More Total Cost of Ownership Comparison: Oracle Exadata vs. IBM P-Series Read the research that found that over three years, the IBM hardware running Oracle Database cost 31 percent more in total cost of ownership than Oracle Exadata. Webcast - Oracle Exadata Database Machine X3 Learn about Oracle’s next-generation database machine, Oracle Exadata X3, that combines massive memory and low-cost disks to deliver the highest performance at the lowest cost. Available in an eight-rack configuration, it allows you to start small and grow.    Maximum Availability with Oracle GoldenGate Discover how to eliminate not only unplanned downtime but also planned downtime resulting from database upgrades, migrations, and consolidation.Thursday, December 1319:00 CET / 6 pm. UK   

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  • 3000 videos songs... some are loud in voice & some low.. I want to make them equal (equal in volume only)

    - by Mister.9
    I have thousands Video flv/avi files, which are all songs only. Some of them are high in volume and some are low. Every time the song ends I have to up or down the volume at once..to escape my ears ruined by headphones... and by woofers, save my life from my neighbor sleeping after hard-earning all the day long. :-( Any idea to make all files sound equal? Does such kind of application/software exist? Any converter that may convert all audio files into same volume? I know iTunes has sound-check option but can it convert? If I want to write CDs, does any burner have the feature like this, to burn in equal sound? If yes, suggest something for me... For, I am really really worried... It would be a great help..... Hoping your kind reply, Thanks in advance! (I am I am John.martin188@yahoo for having mails also in this regard)

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  • Increase Query Speed in PostgreSQL

    - by Anthoni Gardner
    Hello, First time posting here, but an avid reader. I am experiancing slow query times on my database (all tested locally thus far) and not sure how to go about it. The database itself has 44 tables and some of them tables have over 1 Million records (mainly the movies, actresses and actors tables). The table is made via JMDB using the flat files on IMDB. Also the SQL query that I am about to show is from that said program (that too experiances very slow search times). I have tried to include as much information as I can, such as the explain plan etc. "QUERY PLAN" "HashAggregate (cost=46492.52..46493.50 rows=98 width=46)" " Output: public.movies.title, public.movies.movieid, public.movies.year" " - Append (cost=39094.17..46491.79 rows=98 width=46)" " - HashAggregate (cost=39094.17..39094.87 rows=70 width=46)" " Output: public.movies.title, public.movies.movieid, public.movies.year" " - Seq Scan on movies (cost=0.00..39093.65 rows=70 width=46)" " Output: public.movies.title, public.movies.movieid, public.movies.year" " Filter: (((title)::text ~~* '%Babe%'::text) AND ((title)::text !~~* '""%}'::text))" " - Nested Loop (cost=0.00..7395.94 rows=28 width=46)" " Output: public.movies.title, public.movies.movieid, public.movies.year" " - Seq Scan on akatitles (cost=0.00..7159.24 rows=28 width=4)" " Output: akatitles.movieid, akatitles.language, akatitles.title, " Filter: (((title)::text ~~* '%Babe%'::text) AND ((title)::text !~~* '""%}'::text))" " - Index Scan using movies_pkey on movies (cost=0.00..8.44 rows=1 width=46)" " Output: public.movies.movieid, public.movies.title, public.movies.year, public.movies.imdbid" " Index Cond: (public.movies.movieid = akatitles.movieid)" SELECT * FROM ((SELECT DISTINCT title, movieid, year FROM movies WHERE title ILIKE '%Babe%' AND NOT (title ILIKE '"%}')) UNION (SELECT movies.title, movies.movieid, movies.year FROM movies INNER JOIN akatitles ON movies.movieid=akatitles.movieid WHERE akatitles.title ILIKE '%Babe%' AND NOT (akatitles.title ILIKE '"%}'))) AS union_tmp2; Returns 612 Rows in 9078ms Database backup (plain text) is 1.61GB It's a really complex query and I am not fully cognizant on it, like I said it was spat out by JMDB. Do you have any suggestions on how I can increase the speed ? Regards Anthoni

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  • Direct invocation vs indirect invocation in C

    - by Mohit Deshpande
    I am new to C and I was reading about how pointers "point" to the address of another variable. So I have tried indirect invocation and direct invocation and received the same results (as any C/C++ developer could have predicted). This is what I did: int cost; int *cost_ptr; int main() { cost_ptr = &cost; //assign pointer to cost cost = 100; //intialize cost with a value printf("\nDirect Access: %d", cost); cost = 0; //reset the value *cost_ptr = 100; printf("\nIndirect Access: %d", *cost_ptr); //some code here return 0; //1 } So I am wondering if indirect invocation with pointers has any advantages over direct invocation or vice-versa. Some advantages/disadvantages could include speed, amount of memory consumed performing the operation (most likely the same but I just wanted to put that out there), safeness (like dangling pointers) , good programming practice, etc. 1Funny thing, I am using the GNU C Compiler (gcc) and it still compiles without the return statement and everything is as expected. Maybe because the C++ compiler will automatically insert the return statement if you forget.

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  • MySQL - How do I inner join sorting the joined data

    - by Gary
    I'm trying to write a report which will join a person, their work, and their hourly wage at the time of work. I cannot seem to figure out the best way to join the person's cost when the date is less than the date of the work. Let's say a person cost $30 per hour at the start of the year then got a $10 raise o Feb 5 and another on Mar 1. 01/01/2010 $30.00 (per hour) 02/05/2010 $40.00 03/01/2010 $45.00 The person put in hours several days which span the rasies. 01/05/2010 10 hours (should be at $30/hr) 01/27/2010 5 hours (again at $30) 02/10/2010 10 hours (at $40/hr) 03/03/2010 5 hours (at $45/hr) I'm trying to write one SQL statement which will pull the hours, the cost per hour, and the hours*cost. The cost is the hourly rate last entered into the system so the cost date is less than the work date, ordered by cost date limit 1. SELECT person.id, person.name, work.hours, person_costs.value, work.hours * person_costs.value AS value FROM person INNER JOIN work ON (person.id = work.person_id) INNER JOIN person_costs ON (person.id = person_costs.person_id AND person_costs.date < work.date) WHERE person.id = 1234 ORDER BY work.date ASC The problem I'm having, the person_costs isn't ordered by date in descending order. It's pulling out "any" value (naturally sorted by record position) which matches the condition. How do I select the first person_cost value which is older than the work date? Thanks!

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  • extra storage merge sort

    - by davit-datuashvili
    I need make a merge sort using an additional array. Here is my code: public class extra_storage{ public static void main(String[]args) { int x[]=new int[]{12,9,4,99,120,1,3,10}; int a[]=new int[x.length]; mergesort(x,0,x.length-1,a); for (int i=0;i<x.length;i++){ System.out.println(x[i]); } } public static void mergesort(int x[],int low,int high, int a[]){ if (low>=high) { return; } int middle=(low+high)/2; mergesort(x,low,middle,a); mergesort(x,middle+1,high,a); int k; int lo=low; int h=high; for (k=low;k<high;k++) if ((lo<=middle ) && ((h>high)||(x[lo]<x[h]))){ a[k]=x[lo++]; } else { a[k]=x[h++]; } for (k=low;k<=high;k++){ x[k]=a[k]; } } } But something is wrong. When I run it the output is this: 1 0 3 0 4 0 9 0 What is the problem?

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  • Sharing Bandwidth and Prioritizing Realtime Traffic via HTB, Which Scenario Works Better?

    - by Mecki
    I would like to add some kind of traffic management to our Internet line. After reading a lot of documentation, I think HFSC is too complicated for me (I don't understand all the curves stuff, I'm afraid I will never get it right), CBQ is not recommend, and basically HTB is the way to go for most people. Our internal network has three "segments" and I'd like to share bandwidth more or less equally between those (at least in the beginning). Further I must prioritize traffic according to at least three kinds of traffic (realtime traffic, standard traffic, and bulk traffic). The bandwidth sharing is not as important as the fact that realtime traffic should always be treated as premium traffic whenever possible, but of course no other traffic class may starve either. The question is, what makes more sense and also guarantees better realtime throughput: Creating one class per segment, each having the same rate (priority doesn't matter for classes that are no leaves according to HTB developer) and each of these classes has three sub-classes (leaves) for the 3 priority levels (with different priorities and different rates). Having one class per priority level on top, each having a different rate (again priority won't matter) and each having 3 sub-classes, one per segment, whereas all 3 in the realtime class have highest prio, lowest prio in the bulk class, and so on. I'll try to make this more clear with the following ASCII art image: Case 1: root --+--> Segment A | +--> High Prio | +--> Normal Prio | +--> Low Prio | +--> Segment B | +--> High Prio | +--> Normal Prio | +--> Low Prio | +--> Segment C +--> High Prio +--> Normal Prio +--> Low Prio Case 2: root --+--> High Prio | +--> Segment A | +--> Segment B | +--> Segment C | +--> Normal Prio | +--> Segment A | +--> Segment B | +--> Segment C | +--> Low Prio +--> Segment A +--> Segment B +--> Segment C Case 1 Seems like the way most people would do it, but unless I don't read the HTB implementation details correctly, Case 2 may offer better prioritizing. The HTB manual says, that if a class has hit its rate, it may borrow from its parent and when borrowing, classes with higher priority always get bandwidth offered first. However, it also says that classes having bandwidth available on a lower tree-level are always preferred to those on a higher tree level, regardless of priority. Let's assume the following situation: Segment C is not sending any traffic. Segment A is only sending realtime traffic, as fast as it can (enough to saturate the link alone) and Segment B is only sending bulk traffic, as fast as it can (again, enough to saturate the full link alone). What will happen? Case 1: Segment A-High Prio and Segment B-Low Prio both have packets to send, since A-High Prio has the higher priority, it will always be scheduled first, till it hits its rate. Now it tries to borrow from Segment A, but since Segment A is on a higher level and Segment B-Low Prio has not yet hit its rate, this class is now served first, till it also hits the rate and wants to borrow from Segment B. Once both have hit their rates, both are on the same level again and now Segment A-High Prio is going to win again, until it hits the rate of Segment A. Now it tries to borrow from root (which has plenty of traffic spare, as Segment C is not using any of its guaranteed traffic), but again, it has to wait for Segment B-Low Prio to also reach the root level. Once that happens, priority is taken into account again and this time Segment A-High Prio will get all the bandwidth left over from Segment C. Case 2: High Prio-Segment A and Low Prio-Segment B both have packets to send, again High Prio-Segment A is going to win as it has the higher priority. Once it hits its rate, it tries to borrow from High Prio, which has bandwidth spare, but being on a higher level, it has to wait for Low Prio-Segment B again to also hit its rate. Once both have hit their rate and both have to borrow, High Prio-Segment A will win again until it hits the rate of the High Prio class. Once that happens, it tries to borrow from root, which has again plenty of bandwidth left (all bandwidth of Normal Prio is unused at the moment), but it has to wait again until Low Prio-Segment B hits the rate limit of the Low Prio class and also tries to borrow from root. Finally both classes try to borrow from root, priority is taken into account, and High Prio-Segment A gets all bandwidth root has left over. Both cases seem sub-optimal, as either way realtime traffic sometimes has to wait for bulk traffic, even though there is plenty of bandwidth left it could borrow. However, in case 2 it seems like the realtime traffic has to wait less than in case 1, since it only has to wait till the bulk traffic rate is hit, which is most likely less than the rate of a whole segment (and in case 1 that is the rate it has to wait for). Or am I totally wrong here? I thought about even simpler setups, using a priority qdisc. But priority queues have the big problem that they cause starvation if they are not somehow limited. Starvation is not acceptable. Of course one can put a TBF (Token Bucket Filter) into each priority class to limit the rate and thus avoid starvation, but when doing so, a single priority class cannot saturate the link on its own any longer, even if all other priority classes are empty, the TBF will prevent that from happening. And this is also sub-optimal, since why wouldn't a class get 100% of the line's bandwidth if no other class needs any of it at the moment? Any comments or ideas regarding this setup? It seems so hard to do using standard tc qdiscs. As a programmer it was such an easy task if I could simply write my own scheduler (which I'm not allowed to do).

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  • HP to Cisco spanning tree root flapping

    - by Tim Brigham
    Per a recent question I recently configured both my HP (2x 2900) and Cisco (1x 3750) hardware to use MSTP for interoperability. I thought this was functional until I applied the change to the third device (HP switch 1 below) at which time the spanning tree root started flapping causing performance issues (5% packet loss) between my two HP switches. I'm not sure why. HP Switch 1 A4 connected to Cisco 1/0/1. HP Switch 2 B2 connected to Cisco 2/0/1. HP Switch 1 A2 connected to HP Switch 2 A1. I'd prefer the Cisco stack to act as the root. EDIT: There is one specific line - 'spanning-tree 1 path-cost 500000' in the HP switch 2 that I didn't add and was preexisting. I'm not sure if it could have the kind of impact that I'm describing. I'm more a security and monitoring guy then networking. EDIT 2: I'm starting to believe the problem lies in the fact that the value for my MST 0 instance on the Cisco is still at the default 32768. I worked up a diagram: This is based on every show command I could find for STP. I'll make this change after hours and see if it helps. Cisco 3750 Config: version 12.2 spanning-tree mode mst spanning-tree extend system-id spanning-tree mst configuration name mstp revision 1 instance 1 vlan 1, 40, 70, 100, 250 spanning-tree mst 1 priority 0 vlan internal allocation policy ascending interface TenGigabitEthernet1/1/1 switchport trunk encapsulation dot1q switchport mode trunk ! interface TenGigabitEthernet2/1/1 switchport trunk encapsulation dot1q switchport mode trunk ! interface Vlan1 no ip address ! interface Vlan100 ip address 192.168.100.253 255.255.255.0 ! Cisco 3750 show spanning tree: show spanning-tree MST0 Spanning tree enabled protocol mstp Root ID Priority 32768 Address 0004.ea84.5f80 Cost 200000 Port 53 (TenGigabitEthernet1/1/1) Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Bridge ID Priority 32768 (priority 32768 sys-id-ext 0) Address a44c.11a6.7c80 Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Interface Role Sts Cost Prio.Nbr Type ------------------- ---- --- --------- -------- -------------------------------- Te1/1/1 Root FWD 2000 128.53 P2p MST1 Spanning tree enabled protocol mstp Root ID Priority 1 Address a44c.11a6.7c80 This bridge is the root Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Bridge ID Priority 1 (priority 0 sys-id-ext 1) Address a44c.11a6.7c80 Hello Time 2 sec Max Age 20 sec Forward Delay 15 sec Interface Role Sts Cost Prio.Nbr Type ------------------- ---- --- --------- -------- -------------------------------- Te1/1/1 Desg FWD 2000 128.53 P2p Cisco 3750 show logging: %LINEPROTO-5-UPDOWN: Line protocol on Interface Vlan1, changed state to down %LINEPROTO-5-UPDOWN: Line protocol on Interface Vlan100, changed state to down %LINEPROTO-5-UPDOWN: Line protocol on Interface Vlan1, changed state to up %LINEPROTO-5-UPDOWN: Line protocol on Interface Vlan100, changed state to up %LINEPROTO-5-UPDOWN: Line protocol on Interface Vlan1, changed state to down %LINEPROTO-5-UPDOWN: Line protocol on Interface Vlan1, changed state to up HP Switch 1: ; J9049A Configuration Editor; Created on release #T.13.71 vlan 1 name "DEFAULT_VLAN" untagged 1-8,10,13-16,18-23,A1-A4 ip address 100.100.100.17 255.255.255.0 no untagged 9,11-12,17,24 exit vlan 100 name "192.168.100" untagged 9,11-12,17,24 tagged 1-8,10,13-16,18-23,A1-A4 no ip address exit vlan 21 name "Users_2" tagged 1,A1-A4 no ip address exit vlan 40 name "Cafe" tagged 1,4,7,A1-A4 no ip address exit vlan 250 name "Firewall" tagged 1,4,7,A1-A4 no ip address exit vlan 70 name "DMZ" tagged 1,4,7-8,13,A1-A4 no ip address exit spanning-tree spanning-tree config-name "mstp" spanning-tree config-revision 1 spanning-tree instance 1 vlan 1 40 70 100 250 password manager password operator HP Switch 1 show spanning tree: show spanning-tree Multiple Spanning Tree (MST) Information STP Enabled : Yes Force Version : MSTP-operation IST Mapped VLANs : 2-39,41-69,71-99,101-249,251-4094 Switch MAC Address : 0021f7-126580 Switch Priority : 32768 Max Age : 20 Max Hops : 20 Forward Delay : 15 Topology Change Count : 363,490 Time Since Last Change : 14 hours CST Root MAC Address : 0004ea-845f80 CST Root Priority : 32768 CST Root Path Cost : 200000 CST Root Port : 1 IST Regional Root MAC Address : 0021f7-126580 IST Regional Root Priority : 32768 IST Regional Root Path Cost : 0 IST Remaining Hops : 20 Root Guard Ports : TCN Guard Ports : BPDU Protected Ports : BPDU Filtered Ports : PVST Protected Ports : PVST Filtered Ports : | Prio | Designated Hello Port Type | Cost rity State | Bridge Time PtP Edge ----- --------- + --------- ---- ---------- + ------------- ---- --- ---- A1 | Auto 128 Disabled | A2 10GbE-CX4 | 2000 128 Forwarding | 0021f7-126580 2 Yes No A3 10GbE-CX4 | Auto 128 Disabled | A4 10GbE-SR | Auto 128 Disabled | HP Switch 1 Logging: I removed the date / time fields since they are inaccurate (no NTP configured on these switches) 00839 stp: MSTI 1 Root changed from 0:a44c11-a67c80 to 32768:0021f7-126580 00839 stp: MSTI 1 Root changed from 32768:0021f7-126580 to 0:a44c11-a67c80 00842 stp: MSTI 1 starved for an MSTI Msg Rx on port A4 from 0:a44c11-a67c80 00839 stp: MSTI 1 Root changed from 0:a44c11-a67c80 to 32768:0021f7-126580 00839 stp: MSTI 1 Root changed from 32768:0021f7-126580 to 0:a44c11-a67c80 00839 stp: MSTI 1 Root changed from 0:a44c11-a67c80 to ... HP Switch 2 Configuration: ; J9146A Configuration Editor; Created on release #W.14.49 vlan 1 name "DEFAULT_VLAN" untagged 1,3-17,21-24,A1-A2,B2 ip address 100.100.100.36 255.255.255.0 no untagged 2,18-20,B1 exit vlan 100 name "192.168.100" untagged 2,18-20 tagged 1,3-17,21-24,A1-A2,B1-B2 no ip address exit vlan 21 name "Users_2" tagged 1,A1-A2,B2 no ip address exit vlan 40 name "Cafe" tagged 1,13-14,16,A1-A2,B2 no ip address exit vlan 250 name "Firewall" tagged 1,13-14,16,A1-A2,B2 no ip address exit vlan 70 name "DMZ" tagged 1,13-14,16,A1-A2,B2 no ip address exit logging 192.168.100.18 spanning-tree spanning-tree 1 path-cost 500000 spanning-tree config-name "mstp" spanning-tree config-revision 1 spanning-tree instance 1 vlan 1 40 70 100 250 HP Switch 2 Spanning Tree: show spanning-tree Multiple Spanning Tree (MST) Information STP Enabled : Yes Force Version : MSTP-operation IST Mapped VLANs : 2-39,41-69,71-99,101-249,251-4094 Switch MAC Address : 0024a8-cd6000 Switch Priority : 32768 Max Age : 20 Max Hops : 20 Forward Delay : 15 Topology Change Count : 21,793 Time Since Last Change : 14 hours CST Root MAC Address : 0004ea-845f80 CST Root Priority : 32768 CST Root Path Cost : 200000 CST Root Port : A1 IST Regional Root MAC Address : 0021f7-126580 IST Regional Root Priority : 32768 IST Regional Root Path Cost : 2000 IST Remaining Hops : 19 Root Guard Ports : TCN Guard Ports : BPDU Protected Ports : BPDU Filtered Ports : PVST Protected Ports : PVST Filtered Ports : | Prio | Designated Hello Port Type | Cost rity State | Bridge Time PtP Edge ----- --------- + --------- ---- ---------- + ------------- ---- --- ---- A1 10GbE-CX4 | 2000 128 Forwarding | 0021f7-126580 2 Yes No A2 10GbE-CX4 | Auto 128 Disabled | B1 SFP+SR | 2000 128 Forwarding | 0024a8-cd6000 2 Yes No B2 | Auto 128 Disabled | HP Switch 2 Logging: I removed the date / time fields since they are inaccurate (no NTP configured on these switches) 00839 stp: CST Root changed from 32768:0021f7-126580 to 32768:0004ea-845f80 00839 stp: IST Root changed from 32768:0021f7-126580 to 32768:0024a8-cd6000 00839 stp: CST Root changed from 32768:0004ea-845f80 to 32768:0024a8-cd6000 00839 stp: CST Root changed from 32768:0024a8-cd6000 to 32768:0004ea-845f80 00839 stp: CST Root changed from 32768:0004ea-845f80 to 32768:0024a8-cd6000 00435 ports: port B1 is Blocked by STP 00839 stp: CST Root changed from 32768:0024a8-cd6000 to 32768:0021f7-126580 00839 stp: IST Root changed from 32768:0024a8-cd6000 to 32768:0021f7-126580 00839 stp: CST Root changed from 32768:0021f7-126580 to 32768:0004ea-845f80

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  • Why is textbox.focus throwing the lostfocus event?

    - by cost
    I've seen a few similar questions on SO but nothing that seems to actually address the issue. Here's a simplified version of the function. Private Sub Check_Quantity(sender As System.Object, e As System.Windows.RoutedEventArgs) _ Handles textbox_quantity.LostFocus Dim worked As Boolean = Integer.TryParse(textbox_quantity.Text, quantity) If Not worked Then MsgBox("Enter a valid number for the quantity") textbox_quantity.Focus() textbox_quantity.SelectAll() quantity = 0 End If End Sub It's important to note that this is WPF. What I want to do is very simple. When someone finishes with the textbox the program checks that what they entered is a number. If it does it sticks this in an integer. If not, it tells them to fix it and keeps the focus on the textbox. The issue is a few things, but what it comes down to is this function runs in an infinite loop. This same function works fine in WinForms, but not in WPF. On some other questions people have said that the messagebox appearing causes focus to be lost, but in testing this isn't true. It still loops regardless of if the messagebox is called or not. The problem is the call to textbox_quantity.Focus(). Without that it works fine. Regardless of whether it's there or not though, focus is not set to the textbox, though textbox_quantity.Focus() still returns a value of true. Any thought of what's going on and maybe how I could fix it?

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  • Solving the NP-complete problem in XKCD

    - by Adam Tuttle
    The problem/comic in question: http://xkcd.com/287/ I'm not sure this is the best way to do it, but here's what I've come up with so far. I'm using CFML, but it should be readable by anyone. <cffunction name="testCombo" returntype="boolean"> <cfargument name="currentCombo" type="string" required="true" /> <cfargument name="currentTotal" type="numeric" required="true" /> <cfargument name="apps" type="array" required="true" /> <cfset var a = 0 /> <cfset var found = false /> <cfloop from="1" to="#arrayLen(arguments.apps)#" index="a"> <cfset arguments.currentCombo = listAppend(arguments.currentCombo, arguments.apps[a].name) /> <cfset arguments.currentTotal = arguments.currentTotal + arguments.apps[a].cost /> <cfif arguments.currentTotal eq 15.05> <!--- print current combo ---> <cfoutput><strong>#arguments.currentCombo# = 15.05</strong></cfoutput><br /> <cfreturn true /> <cfelseif arguments.currentTotal gt 15.05> <cfoutput>#arguments.currentCombo# > 15.05 (aborting)</cfoutput><br /> <cfreturn false /> <cfelse> <!--- less than 15.05 ---> <cfoutput>#arguments.currentCombo# < 15.05 (traversing)</cfoutput><br /> <cfset found = testCombo(arguments.currentCombo, arguments.currentTotal, arguments.apps) /> </cfif> </cfloop> </cffunction> <cfset mf = {name="Mixed Fruit", cost=2.15} /> <cfset ff = {name="French Fries", cost=2.75} /> <cfset ss = {name="side salad", cost=3.35} /> <cfset hw = {name="hot wings", cost=3.55} /> <cfset ms = {name="moz sticks", cost=4.20} /> <cfset sp = {name="sampler plate", cost=5.80} /> <cfset apps = [ mf, ff, ss, hw, ms, sp ] /> <cfloop from="1" to="6" index="b"> <cfoutput>#testCombo(apps[b].name, apps[b].cost, apps)#</cfoutput> </cfloop> The above code tells me that the only combination that adds up to $15.05 is 7 orders of Mixed Fruit, and it takes 232 executions of my testCombo function to complete. Is there a better algorithm to come to the correct solution? Did I come to the correct solution?

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  • Django: Summing values

    - by Anry
    I have a two Model - Project and Cost. class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() I must return the sum of costs for each project. view.py: from mypm.costs.models import Project, Cost from django.shortcuts import render_to_response from django.db.models import Avg, Sum def index(request): #... return render_to_response('index.html',... How?

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  • What's the non brute force way to filter a Python dictionary?

    - by Thierry Lam
    I can filter the following dictionary like: data = { 1: {'name': 'stackoverflow', 'traffic': 'high'}, 2: {'name': 'serverfault', 'traffic': 'low'}, 3: {'name': 'superuser', 'traffic': 'low'}, 4: {'name': 'mathoverflow', 'traffic': 'low'}, } traffic = 'low' for k, v in data.items(): if v['traffic'] == traffic: print k, v Is there an alternate way to do the above filtering?

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  • Book: Confessions of a Public Speaker: Scott Berkun

    - by Greg Low
    It's probably apparent that I've been travelling again a lot lately as the number of posts related to books has gone up. One book that I picked up along the way and really enjoyed was Scott Berkun's Confessions of a Public Speaker . I could relate to so much of what Scott was talking about and there are quite a few solid nuggets of advice in the book. It's very important when you are regularly giving technical presentations to spend time learning about the "presenting" part of the task, not just...(read more)

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  • #SQLMug - Like a collectors set of 5 x geeky SQL Mugs?

    - by Greg Low
    Hi Folks,For a while, I've been wanting to get some great SQL mugs printed for SQL Down Under but I need further inspiration so here's your chance to get a collectors set of 5 SQL mugs:Send me (greg @ sqldownunder . com) a great line to go onto the mugs, along with your country and a delivery address. I'll pick the best 5 and get mugs printed with those sayings. If you're one of the 5, I'll send you a collectors set with one of each of the 5. Simple enough?Here are some ideas I've already received to get you started:Chuck Norris gets NULL. Nothing compares to him either.ALTER MUG  SET SINGLE_USER  WITH ROLLBACK IMMEDIATE;DENY CONTROL  ON OBJECT::MUG  TO public;knock knock who's there? sp_ sp_who? spid 1, spid 2, spid 3, spid 4... ALTER DATABASE CriticalDB SET ChuckNorrisMode = ON WITH NOWAIT;I'll probably cut off new entries around the end of April.

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  • Performance tuning of tabular data models in Analysis Services

    - by Greg Low
    More and more practical information around working with tabular data models is starting to appear as more and more sites get deployed.At SQL Down Under, we've already helped quite a few customers move to tabular data models in Analysis Services and have started to collect quite a bit of information on what works well (and what doesn't) in terms of performance of these models. We've also been running a lot of training on tabular data models.It was great to see a whitepaper on the performance of these models released today.Performance Tuning of Tabular Models in SQL Server 2012 Analysis Services was written by John Sirmon, Greg Galloway, Cindy Gross and Karan Gulati. You'll find it here: http://msdn.microsoft.com/en-us/library/dn393915.aspx

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  • SQL Down Under podcast 60 with SQL Server MVP Adam Machanic

    - by Greg Low
    I managed to get another podcast posted over the weekend. Late last week, I managed to get a show recorded with Adam Machanic. Adam's always fascinating. In this show, he's talking about what he's found regarding increasing query performance using parallelism. Late in the show, he gives his thoughts on a number of topics related to the upcoming SQL Server 2014.Enjoy!The show is online now: http://www.sqldownunder.com/Podcasts 

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  • SolidQ Journal for January (free and available now)

    - by Greg Low
    I've been travelling in Tasmania for a week or so and didn't get to post about the SolidQ Journal for January. It's our free monthly journal at: http://www.solidq.com/sqj . I promised to write a part two on controlling the security context of stored procedures but didn't get time to write this month. I'll rectify that very soon. However, in the meantime, the rest of the team have done a great job again. Guillermo Bas has described how to access SharePoint 2010 data through Windows Phone 7. Marino...(read more)

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