Search Results

Search found 9988 results on 400 pages for 'tv less in jersey'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 33/400 | < Previous Page | 29 30 31 32 33 34 35 36 37 38 39 40  | Next Page >

  • UDP packets are dropped when its size is less than 12 byte in a certain PC. how do i figure it out the reason?

    - by waan
    Hi. i've stuck in a problem that is never heard about before. i'm making an online game which uses UDP packets in a certain character action. after i developed the udp module, it seems to work fine. though most of our team members have no problem, but a man, who is my boss, told me something is wrong for that module. i have investigated the problem, and finally i found the fact that... on his PC, if udp packet size is less than 12, the packet is never have been delivered to the other host. the following is some additional information: 1~11 bytes udp packets are dropped, 12 bytes and over 12 bytes packets are OK. O/S: Microsoft Windows Vista Business NIC: Attansic L1 Gigabit Ethernet 10/100/1000Base-T Controller WSASendTo returns TRUE. loopback udp packet works fine. how do you think of this problem? and what do you think... what causes this problem? what should i do for the next step for the cause? PS. i don't want to padding which makes length of all the packets up to 12 bytes.

    Read the article

  • What 20 Lines (or less) of code did you find really useful?

    - by Ygam
    You can share your code or other's code. Here's a snippet from an array function in Kohana: public static function rotate($source_array, $keep_keys = TRUE) { $new_array = array(); foreach ($source_array as $key => $value) { $value = ($keep_keys === TRUE) ? $value : array_values($value); foreach ($value as $k => $v) { $new_array[$k][$key] = $v; } } return $new_array; } It was helpful when I was uploading multiple images using multiple file upload forms. It turned this array array('images' => array( 'name' => array( 0 => 'img1', 1 => 'img0', 2 =>'img2' ), 'error' => array( 0 => '', 1 => '', 2 => '' into : array('images' => array( 0 => array( 'name' => 'img1' 'error' => '' ),//rest goes here How about you? What 20 or less lines of code did you find useful?

    Read the article

  • Nvidia Ion HDMI output problems.

    - by Techfeeler
    I bought ACERREVO, first I connected it to the SONY TV Via HDMI output for few days it worked very well and one fine day when switch the computer on it boots and TV screen becomes black and message on the TV shows -no input signal. I connect it to Samsung LED TV, it did the same. What do you guys think the problem is how to tackle this issue. Any help is deepley appreciated.

    Read the article

  • How do I prevent windows opening on one of my desktops?

    - by frankster
    I have 2 monitors and a tv screen connected to my computer. The tv is angled so I can watch it in bed but is facing away from my desk (and usually switched off). Sometimes applications open on the monitor and I have to fiddle around with the "Move" menu option to bring them back to one of the screens I can see. I don't want to disable the tv as I will just have to reenable it when I want to watch something on it, so how can I prevent applications opening on the tv?

    Read the article

  • How to react to an office harassment based on my profession ? [closed]

    - by bob from jersey
    A lot of my co-workers (not developers, people from the other departments) who are framing me in the classical "nerd" stereotype, and with that acting disturbing towards me. Of course they are not aggressive or anything, since we are in a work environment having rules on it's own, plus we are all grownups now, but they are on a "quite war" against me (not particularly against me, they are against all developers, but I am the only one who dares to speak about it). I hear names, "nerd", "geek", "cyborg", "outsider" and so on, it's really inappropriate. Of course, nothing is said in our faces, but, you know, "you hear things over". Also this general feeling of "them not liking us at all" can be sensed in the air all the time. And while it is not a problem for a few weeks, a larger duration of constant office harassment (going for months now), can be really annoying and can cause a serious drop in the development performance, which will (inevitably) lead to problems with the management (maybe getting me fired). I want to know, should I continue with my current defensive strategy (passively ignoring their inappropriate labels) or should I switch into a more aggressive maneuvers, like giving them logical reasons why their antisocial behavior should be banned?

    Read the article

  • Upgrading PS1 Light Gun [on hold]

    - by Nathan Taylor
    Is There any possible way to upgrade the retro G-con Light Gun for PS1 to allow it to interact with HD TV's? I am aware that they were Designed purely for Tube TV's but I would be happy to know of any hardware that would maybe convert the light to hit the Pixels on an LCD TV. If not is there any other Light gun that would work on PS1 games but has the newer light gun hardware that can interact with a higher Pixel LCD TV?

    Read the article

  • The remote server returned an error: (400) Bad Request - uploading less 2MB file size?

    - by fiberOptics
    The file succeed to upload when it is 2KB or lower in size. The main reason why I use streaming is to be able to upload file up to at least 1 GB. But when I try to upload file with less 1MB size, I get bad request. It is my first time to deal with downloading and uploading process, so I can't easily find the cause of error. Testing part: private void button24_Click(object sender, EventArgs e) { try { OpenFileDialog openfile = new OpenFileDialog(); if (openfile.ShowDialog() == System.Windows.Forms.DialogResult.OK) { string port = "3445"; byte[] fileStream; using (FileStream fs = new FileStream(openfile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read)) { fileStream = new byte[fs.Length]; fs.Read(fileStream, 0, (int)fs.Length); fs.Close(); fs.Dispose(); } string baseAddress = "http://localhost:" + port + "/File/AddStream?fileID=9"; HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create(baseAddress); request.Method = "POST"; request.ContentType = "text/plain"; //request.ContentType = "application/octet-stream"; Stream serverStream = request.GetRequestStream(); serverStream.Write(fileStream, 0, fileStream.Length); serverStream.Close(); using (HttpWebResponse response = request.GetResponse() as HttpWebResponse) { int statusCode = (int)response.StatusCode; StreamReader reader = new StreamReader(response.GetResponseStream()); } } } catch (Exception ex) { MessageBox.Show(ex.Message); } } Service: [WebInvoke(UriTemplate = "AddStream?fileID={fileID}", Method = "POST", BodyStyle = WebMessageBodyStyle.Bare)] public bool AddStream(long fileID, System.IO.Stream fileStream) { ClasslLogic.FileComponent svc = new ClasslLogic.FileComponent(); return svc.AddStream(fileID, fileStream); } Server code for streaming: namespace ClasslLogic { public class StreamObject : IStreamObject { public bool UploadFile(string filename, Stream fileStream) { try { FileStream fileToupload = new FileStream(filename, FileMode.Create); byte[] bytearray = new byte[10000]; int bytesRead, totalBytesRead = 0; do { bytesRead = fileStream.Read(bytearray, 0, bytearray.Length); totalBytesRead += bytesRead; } while (bytesRead > 0); fileToupload.Write(bytearray, 0, bytearray.Length); fileToupload.Close(); fileToupload.Dispose(); } catch (Exception ex) { throw new Exception(ex.Message); } return true; } } } Web config: <system.serviceModel> <bindings> <basicHttpBinding> <binding> <readerQuotas maxDepth="32" maxStringContentLength="8192" maxArrayLength="2097152" maxBytesPerRead="4096" maxNameTableCharCount="2097152" /> <security mode="None" /> </binding> <binding name="ClassLogicBasicTransfer" closeTimeout="00:05:00" openTimeout="00:05:00" receiveTimeout="00:15:00" sendTimeout="00:01:00" allowCookies="false" bypassProxyOnLocal="false" hostNameComparisonMode="StrongWildcard" maxBufferPoolSize="67108864" maxReceivedMessageSize="67108864" messageEncoding="Mtom" textEncoding="utf-8" useDefaultWebProxy="true"> <readerQuotas maxDepth="32" maxStringContentLength="8192" maxArrayLength="67108864" maxBytesPerRead="4096" maxNameTableCharCount="67108864" /> <security mode="None"> <transport clientCredentialType="None" proxyCredentialType="None" realm="" /> <message clientCredentialType="UserName" algorithmSuite="Default" /> </security> </binding> <binding name="BaseLogicWSHTTP"> <security mode="None" /> </binding> <binding name="BaseLogicWSHTTPSec" /> </basicHttpBinding> </bindings> <behaviors> <serviceBehaviors> <behavior> <!-- To avoid disclosing metadata information, set the value below to false and remove the metadata endpoint above before deployment --> <serviceMetadata httpGetEnabled="true" /> <!-- To receive exception details in faults for debugging purposes, set the value below to true. Set to false before deployment to avoid disclosing exception information --> <serviceDebug includeExceptionDetailInFaults="true" /> </behavior> </serviceBehaviors> </behaviors> <serviceHostingEnvironment multipleSiteBindingsEnabled="true" aspNetCompatibilityEnabled="true" /> </system.serviceModel> I'm not sure if this affects the streaming function, because I'm using WCF4.0 rest template which config is dependent in Global.asax. One more thing is this, whether I run the service and passing a stream or not, the created file always contain this thing. How could I remove the "NUL" data? Thanks in advance. Edit public bool UploadFile(string filename, Stream fileStream) { try { FileStream fileToupload = new FileStream(filename, FileMode.Create); byte[] bytearray = new byte[10000]; int bytesRead, totalBytesRead = 0; do { bytesRead = fileStream.Read(bytearray, totalBytesRead, bytearray.Length - totalBytesRead); totalBytesRead += bytesRead; } while (bytesRead > 0); fileToupload.Write(bytearray, 0, totalBytesRead); fileToupload.Close(); fileToupload.Dispose(); } catch (Exception ex) { throw new Exception(ex.Message); } return true; }

    Read the article

  • Aamir Khan’s Satyamev Jayate stirs a movement

    - by Gopinath
    Bollywood actor Aamir Khan is known for his dedication and hard work in inspiring millions of viewers though movies by discussing social problems and motivating people to solve them. His movie Rang De Basanthi seeded Indian anti-corruption movement, Tare Zameen Par touched the problems faced by few challenged kids and the latest movie 3 idiots exposed how education institutions in India are producing lakhs of Donkeys out of colleges every year. He extended his dedication of serving the society to small screen with the launch of reality TV show Satyamev Jayate. Before you start misjudging it as one of those non sense drama / entertaining reality shows, let me tell you that it is not a typical music, games, fight or dance reality show. Satyamev Jayate is all about the real people of India, their problems and how to tackle them.  This is not just a reality show, its movement to educate people about the social evils. Its been many years since I spent couple of hours  in front of TV as most of the programs are too cynical or does not add much value.  In my childhood I use to anxiously wait for Mahabarath or He-Man TV shows to start but after a two decades I waited anxiously for the start of Satyamev Jayate. The wait was worth and the 1 hours 30 minutes spent watching it meaningful. When was the last time you were so satisfied after watching a TV show and inspired to do something? I don’t remember. Today, the show focused on female foeticide and its impact. It showed women who were tortured and forced to abort female foetuses. On the show few brave women shared their experiences of giving birth to girl babies and rough times they are going through with their in-laws & husbands. The show not only focused on the problem but also on the root cause of the evil,  inspiring people working to tackle it and what every individual can do his part to solve it.  The best part of the show is,  its not a blame game. When there is a problem most of the people quickly get into identifying who is wrong and start blaming them instead of solve the actual problem.  Aamir did not blame anyone for female foeticide – neither the government who don’t impose strict rules, nor the doctors who abort girl babies to make money or the mother-in-laws & husbands who torcher girl baby mothers are blamed. He careful highlighted the problem, showed horrifying statistics and their impact on the future society and few inspiring people working to tackle the problem.  He touched heart and stirred a movement against the issue. First time ever I voted for a reality show through SMS and it’s for Satyamev Jayate. I’m proud to do so. Here are the few reactions of popular people, activists & media about the program @aamir_khan absolutely the best program I have seen on TV in recent past. Thanku for converting an idiot box into an inspirationsl medium — Kiran Bedi (@thekiranbedi) May 6, 2012 Satyamev Jayate proves tht TV 2 can b a tool of social change. — Shekhar Kapur (@shekharkapur) May 6, 2012 i absolutely loved #satyamevjayate. at least aamir is doing what all of us only talk about. — Harsha Bhogle (@bhogleharsha) May 6, 2012 Now Television will no longer be called an idiot box,the VISION of Television broadens up with#SatyamevJayate !!! — Madhur Bhandarkar (@mbhandarkar268) May 6, 2012 The Sunday 11am slot seems to have come back with a bang… #SatyamevJayate — atul kasbekar (@atulkasbekar) May 6, 2012   I was spellbound, says Prasoon Joshi – It’s a unique show. I was completely bowled over by it. It’s a never-done before concept Aamir Khan strikes the right chord with Satyamev Jayate – The format is quite crisp. Talking about the emotional connect, there are moments when your eyes well up with tears, but the various segments ensure there’s more content than emotional drama ‘Satyamev Jayate’ gutsy, sensible show: Viewers – From filmmakers to clinical psychologists to professors – everyone has given the thumbs up to Aamir Khan’s television show ‘Satyamev Jayate’, saying it is a gutsy, hard-hitting and sensible programme that strikes an emotional chord with the audiences. Aamir Khan’s TV debut ‘Satyamev Jayate’ takes Twitter by storm – The roads of the capital sported a deserted look around 11 am on Sunday morning, as everyone was hooked on to their TV sets. Did you watch the program? What is your opinion? I’m waiting for next 11 AM of next Sunday. Are you?

    Read the article

  • Radeon 5850 Why am I not getting 3 monitors up as a choice ??

    - by Jan
    Ive just bought the top end ATI Radeon card with 2 normal monitor ports and a HDMI. The idea was to continue using my dual screen setup as always and to use the last plug, the HDMI on my TV. I got a new 52 inch HD TV with all the necessary bits. This should work fine. But.. in Display Properties I still get only my 2 monitors up as options. Not the Digital TV. When I unplug 1 monitor and restart the computer, I get the TV and the other monitor. But never all 3 at the same time. Why is this ? Where can I go to tell it that I need all 3 screens at the same time. Also I get a message saying my gfx card also gives sound through the HDMI cable.. But the TV tells me its recieving a sound format that it does not understand. Any ideas on that too while were at it ?

    Read the article

  • Mini-DisplayPort to HDMI Adapter Sound Stopped Working

    - by jimdrang
    I have cancelled cable and want to watch the NCAA tournament games on my TV tonight through my 2011 Macbook Pro where I can stream the game in a browser. I have a cheap Mini-DisplayPort to HDMI converter that I have connected to my TV in the past and had no issues with audio or video, the problem is the audio has stopped working since the last time I used it a few months ago and now just keeps playing through the laptop speakers, but the video works fine. Everything with my setup is the same and when I try to force the audio output to the TV in the Audio system settings, my TV is not listed as an output option at all. I have tried various combinations of power cycling, replugging-in both devices and making sure the TV options are set properly to receive audio through HDMI but no luck. Anyone know what the issue could be?

    Read the article

  • How do I keep second monitor (HDTV) from auto-disabling in XP when it is turned off?

    - by ThantiK
    I have a new 32" TV that I hooked up to the HDMI port on the back of my video card to use as a second monitor. I used an HDMI/DVI cable to hook it to the TV, and whenever I turn my TV off, XP disables the device tied to the TV so each time I want to use the TV as the monitor, I have to go into my display properties and enable it; it gets pretty annoying. How do I turn this 'feature' off? -- I have an NVidia card should it be specific to the nvidia control panel.

    Read the article

  • ATI Radeon 5850 I cant seem to get 3 monitors up at the same time. 2 Monitors and a HDTV but still.

    - by Jan
    Ive just bought the top end ATI Radeon card with 2 normal monitor ports and a HDMI. The idea was to continue using my dual screen setup as always and to use the last plug, the HDMI on my TV. I got a new 52 inch HD TV with all the necessary bits. This should work fine. But.. in Display Properties I still get only my 2 monitors up as options. Not the Digital TV. When I unplug 1 monitor and restart the computer, I get the TV and the other monitor. But never all 3 at the same time. Why is this ? Where can I go to tell it that I need all 3 screens at the same time. Also I get a message saying my gfx card also gives sound through the HDMI cable.. But the TV tells me its recieving a sound format that it does not understand. Any ideas on that too while were at it ?

    Read the article

  • Multiple monitors showing same screen but different resolutions

    - by Luis Alvarado
    Is it possible to have 2 or more monitors showing the same screen, for example the same desktop but with different resolutions. Like the clone option in Nvidia or the mirror option using the Display settings in Ubuntu but instead of showing the same output with the same resolution, the both show the same output using a resolution that is native for each monitor connected. In my case if I have a netbook that has max resolution of 1360x768 and a TV that has 1280x1024, the would both show the same desktop but each with their own resolution that is compatible for each device. This would help in trying to find a resolution that works on both monitors and in cases like a mini netbook and a huge TV it would solve issues like having max 800x600 in one monitor and min 1024x768 in the other. In the case I tested I was using an HDMI cable but this question also involves VGA and any other connection. I have 3 tests scenarios for this: Scenario 1 - Laptop HP DV6000 (Intel Integrated Video) with 1360x760 connected to a Samsung LED 42 TV that has 1280x900. Scenario 2 - Laptop EEE with 1024x600 (Intel Integrated Video) connected to Sony LCD TV that supports 1280x900. Scenario 3 - Intel Desktop with Nvidia 440 GT with HDMI connected to Soneview 32' TV that supports 1920x1080 and VGA connected to an Epson Video Beam that supports 1280x1024 max. In this 3 scenarios I need to be able to show the same desktop and same views but on different resolutions for each output device. UPDATE: Tested with Xubuntu and the way it handles multiple monitors is precisely what I am asking. The ability to handle the resolution of different monitors showing the same thing.

    Read the article

  • How can I change the default screen resolution?

    - by TheWackerly
    Here's the scoop: I have a crappy VisionQuest TV that I am currently using as a monitor on my computer running XBMCbuntu. It defaults to 1280x768 which the TV will not display correctly. It appears to be the correct size, but the screen is panned WAY to the left. The TV works fine on 1024x768 with the screen sitting in the right spot. Problem is, I have to change the resolution to 1024x768 every time I boot up. Any ideas?

    Read the article

  • Google I/O Sandbox Case Study: MOVL

    Google I/O Sandbox Case Study: MOVL We interviewed MOVL at the Google I/O Sandbox on May 10, 2011 and they explained to us the benefits of developing on the Google TV Platform. MOVL develops gaming applications that people can play on their Google TV's, using their mobile phones as the controllers. For more information on developing on Google TV, visit: code.google.com For more information on MOVL, visit: movl.com From: GoogleDevelopers Views: 19 0 ratings Time: 02:03 More in Science & Technology

    Read the article

  • How do I force the system to look for new sound devices?

    - by John Zeringue
    I have a small flat screen TV (Toshiba) that I often connect via HDMI to my laptop (an HP Pavilion dv4) and use as a computer monitor. When I do this, I prefer to use the TV's speakers, particularly when I'm watching video, because the sound quality is much better. However, when I connect the HDMI cable after turning on my computer (rather than having it plugged in before booting up), Sound Settings does not list the TV as an output device, and I am forced to reboot. I was curious if there is an easier solution to this, perhaps a CLI command to check for new sound outputs. Does anyone know of something like this or have another solution? To clarify, I believe this is a software problem. The HDMI always works, and I can switch my desktop over to the TV at any time. The issue is that, if the HDMI wasn't connected during start up, the TV will not appear as an output option in the Sound Settings GUI. So, unless I'm mistaken, my question is not HDMI specific, but rather a general usage question about manipulating sound settings from the command line.

    Read the article

  • Placing component on Glass Pane

    - by Chris Lieb
    I have a subclass of JLabel that forms a component of my GUI. I have implemented the ability to drag and drop the component from one container to another, but without any visual effects. I want to have this JLabel follow the cursor during the drag of the item from one container to another. I figured that I could just create a glass pane and draw it on there. However, even after I add the component to the glass pane, set the component visible, and set the glass pane visible, and set the glass pane as opaque, I still so not see the component. I know the component works because I can add it to the content pane and have it show up. How do I add a component to the glass pane? package wpics509s10t7.view; import javax.swing.*; import wpics509s10t7.model.Tile; import java.awt.*; import java.awt.dnd.DragSource; import java.awt.event.AWTEventListener; import java.awt.event.MouseEvent; /** * GlassPane tutorial * "A well-behaved GlassPane" * http://weblogs.java.net/blog/alexfromsun/ * <p/> * This is the final version of the GlassPane * it is transparent for MouseEvents, * and respects underneath component's cursors by default, * it is also friedly for other users, * if someone adds a mouseListener to this GlassPane * or set a new cursor it will respect them * * @author Alexander Potochkin */ public class GlassPane extends JPanel implements AWTEventListener { private static final long serialVersionUID = 1L; private final JFrame frame; private TileView tv; // subclass of JLabel private Point point; private WordStealApp wsa; public GlassPane(JFrame frame, WordStealApp wsa) { super(null); this.wsa = wsa; this.frame = frame; setOpaque(true); setLayout(null); setVisible(true); composite = AlphaComposite.getInstance(AlphaComposite.SRC_OVER, 0.5f); } public void beginDrag(Tile t, Point p) { this.tv = new TileView(t, null, this.wsa, true); this.add(this.tv); System.out.println("Starting point: x=" + p.getX() + ",y=" + p.getY()); this.tv.setLocation((int)p.getX(), (int)p.getY()); this.tv.setVisible(true); } public void endDrag(Point p) { System.out.println("Ending point: x=" + p.getX() + ",y=" + p.getY()); this.remove(this.tv); this.tv.setVisible(false); this.tv = null; } public void eventDispatched(AWTEvent event) { if (event instanceof MouseEvent) { MouseEvent me = (MouseEvent) event; if (!SwingUtilities.isDescendingFrom(me.getComponent(), frame)) { return; } if (me.getID() == MouseEvent.MOUSE_EXITED && me.getComponent() == frame) { if (tv != null) { tv.setVisible(false); } point = null; } else { MouseEvent converted = SwingUtilities.convertMouseEvent(me.getComponent(), me, frame.getGlassPane()); point = converted.getPoint(); } repaint(); } } /** * If someone adds a mouseListener to the GlassPane or set a new cursor * we expect that he knows what he is doing * and return the super.contains(x, y) * otherwise we return false to respect the cursors * for the underneath components */ @Override public boolean contains(int x, int y) { if (getMouseListeners().length == 0 && getMouseMotionListeners().length == 0 && getMouseWheelListeners().length == 0 && getCursor() == Cursor.getPredefinedCursor(Cursor.DEFAULT_CURSOR)) { return false; } return super.contains(x, y); } }

    Read the article

  • Embed Youtube in UIWebView behind transparent img. Wmode transparent and z-index doesn't work

    - by Allisone
    I'm using this code: - (void)embedYouTube:(NSString *)urlString frame:(CGRect)frame { NSString *embedHTML = @"\ <html><head>\ <style type=\"text/css\">\ body {\ background-color: black;\ }\ #container{\ position: relative;\ z-index:1;\ }\ #video,#videoc{\ position:absolute;\ z-index: 1;\ border: none;\ }\ #tv{\ background: transparent url(tv.png) no-repeat;\ width: 320px;\ height: 205px;\ position: absolute;\ top: 0;\ z-index: 999;\ }\ </style>\ </head><body style=\"margin:0\">\ <div id=\"tv\"></div>\ <object id=\"videoc\" width=\"240\" height=\"160\">\ <param name=\"movie\" value=\"%@\"></param>\ <param name=\"wmode\" value=\"transparent\"></param>\ <embed wmode=\"transparent\" id=\"video\" src=\"%@\" type=\"application/x-shockwave-flash\" \ width=\"240\" height=\"160\"></embed>\ </object>\ </body></html>"; NSString *path = [[NSBundle mainBundle] bundlePath]; NSURL *baseURL = [NSURL fileURLWithPath:path]; NSString *html = [NSString stringWithFormat:embedHTML, urlString,urlString]; UIWebView *videoView = [[UIWebView alloc] initWithFrame:frame]; [videoView loadHTMLString:html baseURL:baseURL]; [self.view addSubview:videoView]; [videoView release]; } Its the first time that I use UIWebView and the first time that I use video in iPhone. The video plays, so that's working BUT: I want to have an old school tv (round corners) in foreground with switches and so on. The tv is an image with transparent pixels in the middle, so that a video lying behind the tv will shine through as if the video would be shown on the tv. But first of all the video has a border that I can't remove and second it's always in the foreground. In Safari and in Firefox and Mac it's working. So is it an iPhone thing, could it be that it simply won't work on iPhone ? Or do I have some css/html typos ?

    Read the article

  • 4096 MiB SD card in Android Emulator... less than 9MB?

    - by Izhido
    Every time I attempt to create a new AVD with the latest Android SDK (under Eclipse), I can't actually specify SD Card Sizes greater than 1024 MiB. Any attempt to specify higher numbers gets me always the same message: "SD Card Size must be at least 9MB" What gives? Any idea why this could be happening?

    Read the article

  • bundle .NET dlls to run application in .NET-less machine?

    - by Camilo Martin
    AFAIK, ngen turns MSIL into native code (also reffered to as pre-JIT), however I never payed too much attention at it's startup performance impact. Ngen'd applications still require the .NET base class libraries (the runtime). Since the base class libraries have everything our .NET assemblies need (correct?) would it be possible to ship the framework's DLLs with my ngen'd application so that it does not require the runtime to be installed? (e.g., the scenario for most Windows XP machines) Oh, and please don't bother mentioning Remotesoft's Salamander Linker or Xenocode's Postbuild. They are not for my (and many's) current budget (and they seem to simply bundle the framework in a virtualized enviroinment, which means big download sizes and slow startup times I believe) EDIT: I know now, ngen doesn't do what I thought it did. But is it possible to bundle the .NET files with an application, without using a VM?

    Read the article

  • How does the linux kernel manage less than 1GB physical memory ?

    - by TheLoneJoker
    I'm learning the linux kernel internals and while reading "Understanding Linux Kernel", quite a few memory related questions struck me. One of them is, how the Linux kernel handles the memory mapping if the physical memory of say only 512 MB is installed on my system. As I read, kernel maps 0(or 16) MB-896MB physical RAM into 0xC0000000 linear address and can directly address it. So, in the above described case where I only have 512 MB: How can the kernel map 896 MB from only 512 MB ? What about user mode processes in this situation? Where are user mode processes in phys RAM? Every article explains only the situation, when you've installed 4 GB of memory and the kernel maps the 1 GB into kernel space and user processes uses the remaining amount of RAM. I would appreciate any help in improving my understanding. Thanks..!

    Read the article

  • trying to make this code less messy in android, can anyone help?

    - by clayton33
    i know that there must be a simpler way of doing this, i just don't understand how java works well enough, and i am struggling. could someone perhaps point me in the right direction? ImageButton image = (ImageButton) findViewById(R.id.card1); ImageButton image2 = (ImageButton) findViewById(R.id.card2); ImageButton image3 = (ImageButton) findViewById(R.id.card3); ImageButton image4 = (ImageButton) findViewById(R.id.card4); ImageButton image5 = (ImageButton) findViewById(R.id.card5); ImageButton image6 = (ImageButton) findViewById(R.id.card6); ImageButton image7 = (ImageButton) findViewById(R.id.card7); ImageButton image8 = (ImageButton) findViewById(R.id.card8); ImageButton image9 = (ImageButton) findViewById(R.id.card9); ImageButton image10 = (ImageButton) findViewById(R.id.card10); ImageButton image11 = (ImageButton) findViewById(R.id.card11); ImageButton image12 = (ImageButton) findViewById(R.id.card12); ImageButton image13 = (ImageButton) findViewById(R.id.card13); ImageButton image14 = (ImageButton) findViewById(R.id.card14); ImageButton image15 = (ImageButton) findViewById(R.id.card15); //image.setImageResource(R.drawable.test2); Bitmap bMap = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled = Bitmap.createScaledBitmap(bMap, buttonSize, buttonSize, true); Bitmap bMap2 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled2 = Bitmap.createScaledBitmap(bMap2, buttonSize, buttonSize, true); Bitmap bMap3 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled3 = Bitmap.createScaledBitmap(bMap3, buttonSize, buttonSize, true); Bitmap bMap4 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled4 = Bitmap.createScaledBitmap(bMap4, buttonSize, buttonSize, true); Bitmap bMap5 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled5 = Bitmap.createScaledBitmap(bMap5, buttonSize, buttonSize, true); Bitmap bMap6 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled6 = Bitmap.createScaledBitmap(bMap6, buttonSize, buttonSize, true); Bitmap bMap7 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled7 = Bitmap.createScaledBitmap(bMap7, buttonSize, buttonSize, true); Bitmap bMap8 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled8 = Bitmap.createScaledBitmap(bMap8, buttonSize, buttonSize, true); Bitmap bMap9 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled9 = Bitmap.createScaledBitmap(bMap9, buttonSize, buttonSize, true); Bitmap bMap10 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled10 = Bitmap.createScaledBitmap(bMap10, buttonSize, buttonSize, true); Bitmap bMap11 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled11 = Bitmap.createScaledBitmap(bMap11, buttonSize, buttonSize, true); Bitmap bMap12 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled12 = Bitmap.createScaledBitmap(bMap12, buttonSize, buttonSize, true); Bitmap bMap13 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled13 = Bitmap.createScaledBitmap(bMap13, buttonSize, buttonSize, true); Bitmap bMap14 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled14 = Bitmap.createScaledBitmap(bMap14, buttonSize, buttonSize, true); Bitmap bMap15 = BitmapFactory.decodeResource(getResources(), R.drawable.vraag); Bitmap bMapScaled15 = Bitmap.createScaledBitmap(bMap15, buttonSize, buttonSize, true); image.setImageBitmap(bMapScaled); image2.setImageBitmap(bMapScaled2); image3.setImageBitmap(bMapScaled3); image4.setImageBitmap(bMapScaled4); image5.setImageBitmap(bMapScaled5); image6.setImageBitmap(bMapScaled6); image7.setImageBitmap(bMapScaled7); image8.setImageBitmap(bMapScaled8); image9.setImageBitmap(bMapScaled9); image10.setImageBitmap(bMapScaled10); image11.setImageBitmap(bMapScaled11); image12.setImageBitmap(bMapScaled12); image13.setImageBitmap(bMapScaled13); image14.setImageBitmap(bMapScaled14); image15.setImageBitmap(bMapScaled15);

    Read the article

  • use ngen and bundle .NET dlls to run application in .NET-less machine?

    - by Camilo Martin
    AFAIK, ngen turns MSIL into native code (also reffered to as pre-JIT), however I never payed too much attention at it's startup performance impact. Ngen'd applications still require the .NET base class libraries (the runtime). Since the base class libraries have everything our .NET assemblies need (correct?) would it be possible to ship the framework's DLLs with my ngen'd application so that it does not require the runtime to be installed? (e.g., the scenario for most Windows XP machines) Oh, and please don't bother mentioning Remotesoft's Salamander Linker or Xenocode's Postbuild. They are not for my (and many's) current budget (and they seem to simply bundle the framework in a virtualized enviroinment, which means big download sizes and slow startup times I believe)

    Read the article

  • Calling function using 'new' is less expensive than without it?

    - by Matthew Taylor
    Given this very familiar model of prototypal construction: function Rectangle(w,h) { this.width = w; this.height = h; } Rectangle.prototype.area = function() { return this.width * this.height; }; Can anyone explain why calling "new Rectangle(2,3)" is consistently 10x FASTER than calling "Rectangle(2,3)" without the 'new' keyword? I would have assumed that because new adds more complexity to the execution of a function by getting prototypes involved, it would be slower. Example: var myTime; function startTrack() { myTime = new Date(); } function stopTrack(str) { var diff = new Date().getTime() - myTime.getTime(); println(str + ' time in ms: ' + diff); } function trackFunction(desc, func, times) { var i; if (!times) times = 1; startTrack(); for (i=0; i<times; i++) { func(); } stopTrack('(' + times + ' times) ' + desc); } var TIMES = 1000000; trackFunction('new rect classic', function() { new Rectangle(2,3); }, TIMES); trackFunction('rect classic (without new)', function() { Rectangle(2,3); }, TIMES); Yields (in Chrome): (1000000 times) new rect classic time in ms: 33 (1000000 times) rect classic (without new) time in ms: 368 (1000000 times) new rect classic time in ms: 35 (1000000 times) rect classic (without new) time in ms: 374 (1000000 times) new rect classic time in ms: 31 (1000000 times) rect classic (without new) time in ms: 368

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 29 30 31 32 33 34 35 36 37 38 39 40  | Next Page >