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  • How do I get long command lines to wrap to the next line?

    - by BrianH
    Edit It was my .bashrc file. I've copied the same profile from machine to machine, and I used special characters in my $PS1 that are somehow throwing it off. I'm now sticking with the standard bash variables for my $PS1. Thanks to @ændrük for the tip on the .bashrc! ...End Edit... Something I have noticed in Ubuntu for a long time that has been frustrating to me is when I am typing a command at the command line that gets longer (wider) than the terminal width, instead of wrapping to a new line, it goes back to column 1 on the same line and starts over-writing the beginning of my command line. (It doesn't actually overwrite the actual command, but visually, it is overwriting the text that was displayed). It's hard to explain without seeing it, but let's say my terminal was 20 characters wide (Mine is more like 120 characters - but for the sake of an example), and I want to echo the English alphabet. What I type is this: echo abcdefghijklmnopqrstuvwxyz But what my terminal looks like before I hit the key is: pqrstuvwxyzghijklmno When I hit enter, it echos abcdefghijklmnopqrstuvwxyz so I know the command was received properly. It just wrapped my typing after the "o" and started over on the same line. What I would expect to happen, if I typed this command in on a terminal that was only 20 characters wide would be this: echo abcdefghijklmno pqrstuvwxyz Background: I am using bash as my shell, and I have this line in my ~/.bashrc: set -o vi to be able to navigate the command line with VI commands. I am currently using Ubuntu 10.10 server, and connecting to the server with Putty. In any other environment I have worked in, if I type a long command line, it will add a new line underneath the line I am working on when my command gets longer than the terminal width and when I keep typing I can see my command on 2 different lines. But for as long as I can remember using Ubuntu, my long commands only occupy 1 line. This also happens when I am going back to previous commands in the history (I hit Esc, then 'K' to go back to previous commands) - when I get to a previous command that was longer than the terminal width, the command line gets mangled and I cannot tell where I am at in the command. The only work-around I have found to see the entire long command is to hit "Esc-V", which opens up the current command in a VI editor. I don't think I have anything odd in my .bashrc file. I commented out the "set -o vi" line, and I still had the problem. I downloaded a fresh copy of Putty and didn't make any changes to the configuration - I just typed in my host name to connect, and I still have the problem, so I don't think it's anything with Putty (unless I need to make some config changes) Has anyone else had this problem, and can anyone think of how to fix it? Thanks in advance! Brian

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  • background process outputs to the console

    - by broiyan
    Suppose test.sh is a bash script that is empty or contains only exit 0. When the script is backgrounded, what is the significance of the 1 and 16320 printed to the console? b@sam:~/Documents/bashscripts$ ./test.sh & [1] 16320 b@sam:~/Documents/bashscripts$ [1]+ Done ./test.sh b@sam:~/Documents/bashscripts$ Then if user hits ENTER at the command prompt, as illustrated above, another line appears and it shows this [1]+ Done ./test.sh What is the significance of the 1 digit and the + symbol?

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  • How to execute a script as super user first checking the user and getting pass from askpass if not super user

    - by pahnin
    thers a similar question out there How can I determine whether a shellscript runs as root or not? I have the same doubt with different result Is it possible to, within the BASH script prior to everything being run, check if the script is being run as superuser, and if not, print a message saying You must be superuser to use this script, then subsequently get pass from the user using askpass or something like tht then execute the saem script as superuser?

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  • alias/function with command line arguments

    - by Agzam
    I'm tired of typing manage.py startserver 10.211.55.4:4000, so decided to make an alias for that. Only thing is: the port sometime changes. So I did this in bash profile: function runserver() { python manage.py runserver 10.211.55.4:$1 } But then when I call it: runserver 3000, it starts it, but immediately stops saying: "Error: That IP address can't be assigned-to". However if I type the same thing right into command line it works with no complains.

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  • Git pull auto complete OSX

    - by vodkhang
    Follow some instruction on this site http://denis.tumblr.com/post/71390665/adding-bash-completion-for-git-on-mac-os-x-leopard . I can do git auto complete for MAC OS. However, when I type git pull origin ma (for master), and then tab it takes a long time for git to auto complete to become git pull origin master . I think it connect to the server to get the branch, but I am not sure, is there any way to make it faster and only get the branch on local machine cd /tmp git clone git://git.kernel.org/pub/scm/git/git.git cd git git checkout v`git --version | awk '{print $3}'` cp contrib/completion/git-completion.bash ~/.git-completion.bash cd ~ rm -rf /tmp/git echo -e "source ~/.git-completion.bash" >> .profile

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  • Why does cd print when run in command substitution?

    - by reasgt
    If I use the 'cd' BASH built-in in a command substitution, it prints extra stuff to stdout, but only when piped to, eg., less. $ echo `cd .` # The output is a single newline, appended by echo. $ echo `cd .` | less # less displays: ESC]2;my.hostname.com - tmp/testenv^G (END) What's going on there? This behavior isn't documented in the bash man page for cd. Obviously, running just 'cd' in a command substitution is silly, but something like NEWDIR=`cd mypath; pwd` could be useful. I solved this by instead using NEWVAR=`cd mypath > /dev/null 2>&1; pwd` but I still want to know what's going on. Bash Version: GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu) Copyright (C) 2005 Free Software Foundation, Inc. Distro: Scientific Linux SL release 5.5 (Boron)

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  • Cron Permission Denied

    - by worldthreat
    good day, I have a bash script in my home directory that works properly from the command line (file structure is default media temple DV. < noted for certain permission issues) but receive this error from cron: "/home/myFile.sh: line 2: /var/www/vhosts/domain.com/subdomains/techspatch/installation.sql: Permission denied" NOTICE: it's just line 2... it writes to the local server just fine. Below is the Bash File: #!/bin/bash mysqldump -uUSER -pPASSWORD -hHOST dbName> /var/www/vhosts/domain.com/subdomains/techspatch/installation.sql mysql -uadmin -pPASSWORD -hlocalhost dbName< /var/www/vhosts/domain.com/subdomains/techspatch/installation.sql can't chmod from bash (lol, yeah i tried). writing the file there and setting the permissions before the transfer is useless... i have googled the heck out of this situation and this one still seems unique.... any insight is appreciated

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  • mac cron can't use the shell correctly

    - by carneades
    I've set up cron to run a simple hello world shell script, but it's giving me an error that Google isn't helping me resolve. I've got to be missing something really simple! Here's my crontab: [email protected] SHELL=/bin/bash 30 * * * * * $HOME/hello.sh Here's hello.sh: #!/bin/bash echo HELLO WORLD! I get this error email: /bin/bash: 555: command not found I have tried setting shell to /bin/sh but it makes no difference. I still get an analogous error message.

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  • How to automatically define functions and aliases on remote server after ssh login

    - by Ramon
    I want to define bash functions and aliases in my remote shell automatically on login. I can't put the definitions into .profile or similar because the users I log in as are often shared with others who use the same systems and I don't have control of this. What I'm trying to do is execute a few bash function definitions in the remote process and then continue as a login shell. I tried this but it did not work: cat ~/.profile - | ssh -tt user@host bash -l Any ideas?

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  • Colored PS1 string

    - by Will Vousden
    Clarification: I want __foo to be executed each time the PS1 string is presented in the terminal, not when the PS1 string is constructed (hence its being in quotes). __foo contains logic that examines the current directory, so its execution must be deferred. I'm trying to use different colours in my Bash PS1 string from within a Bash function: LIGHTRED="\033[1;31m" LIGHTGREEN="\033[1;32m" RESET="\033[m" __foo () { # Do some stuff and genereate a string to echo in different colours: echo -n '\['$1'\]firstcolour \['$2'\]secondcolour' } PS1='$(__foo '$LIGHTRED' '$LIGHTGREEN')\['$RESET'\] \$' Essentially I want __foo to generate part of the PS1 in a bunch of different colours. My attempt doesn't seem to work, though; it produces the following output: -bash: 31m: command not found -bash: 32m: command not found \[]firstcolour \[\]secondcolour $ What gives, and how can I fix it?

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  • Shell script for replacing string in all PHP-files, for each user

    - by Mads Skjern
    Each user has some php-files using a shared database commondb. I want to iterate over all users (in users.csv), and in their home folder (e.g. /home/joe) find all php files recursively, and replace each occurrence of "commondb" with their own databasename, e.g. "joedb" for "joe". I have tried the following: #!/bin/bash # Execute like this: # bash localize.bash users.csv OLDIFS=$IFS IFS="," while read name dummy do echo $name find /home/${name} -name '*.php' -exec sed -i '' 's/commondb/${name}db/g' "{}" \; done < $1 IFS=$OLDIFS for users.csv joe, Joe J george, George G It does not fail, but the files are unchanged. I am quite weak in bash, and I can't figure out how to debug it :/ Can my script be fixed to work?

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  • Cronjob terminates early

    - by TheBigO
    In my crontab file I execute a script like so (I edit the crontab using sudo crontab -e): 01 * * * * bash /etc/m/start.sh The script runs some other scripts like so: sudo bash -c "/etc/m/abc.sh --option=1" & sleep 2 sudo bash -c "/etc/m/abc.sh --option=2" & When cron runs the script start.sh, I do ps aux | grep abc.sh and I see the abc.sh script running. After a couple of seconds, the script is no longer running, even though abc.sh should take hours to finish. If I do sudo bash /etc/m/start.sh & from the command line, everything works fine (the abc.sh scripts run for hours in the background until they complete). How do I debug this? Is there something I'm doing that is preventing these scripts from running in the background until they are done?

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  • Chrooted user does not start in his home directory and does not load his bash_profiles

    - by Stuffy
    If the users logs in, he starts in / of the chroot (Which is /var/jail on the real machine). I would like him to start in his home-dir. Also, he seems not to load any of his profile-files (.bash.rc etc). I followed this tutorial to create the chroot environment. This is what my /etc/passwd looks like: test:x:1004:1008:,,,:/var/jail/home/test:/bin/bash this is what my /var/jail/etc/passwd file looks like: test:x:1004:1008:,,,:/home/test:/bin/bash I also found out that, if I remove Match User test ChrootDirectory /var/jail AllowTCPForwarding no X11Forwarding no from my /etc/ssh/sshd_config, the user starts in his correct home-folder and with his bash-settings loaded. However, he is able to leave the chroot-environment if I remove that part. This question I asked before is somewhat related, since I think the wrong look of the commandline is caused from the not loaded profile-files. So any ideas how to fix this?

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  • How to call bash process from within django / wsgi?

    - by chang
    I'm using mod_wsgi apache2 adapter for a django site and I like to call some bash process within a view, using the usual ... p = subprocess.Popen("/home/example.com/restart-tomcat.sh", shell=True) sts = os.waitpid(p.pid, 0)[1] ... This code works perfectly from within a usual python shell but does nothing (I can trace right now) when called within django. Am I missing some wsgi constraints? The script has 755 perms, so it should be executable. Thanks.

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  • Why is the value of this string, in a bash script, being executing?

    - by Ross
    Hello Why is this script executing the string in the if statement: #!/bin/bash FILES="*" STRING='' for f in $FILES do if ["$STRING" = ""] then echo first STRING='hello' else STRING="$STRING hello" fi done echo $STRING when run it with sh script.sh outputs: first lesscd.sh: line 7: [hello: command not found lesscd.sh: line 7: [hello hello: command not found lesscd.sh: line 7: [hello hello hello: command not found lesscd.sh: line 7: [hello hello hello hello: command not found lesscd.sh: line 7: [hello hello hello hello hello: command not found hello hello hello hello hello hello p.s. first attempt at a shell script thanks

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  • How can I rename files from a list in bash?

    - by GeoffreyF67
    I have a file that contains filenames like this: my_cool_file.xxx my_cool_file2.xxx my_cool_file3.xxx I have a folder that has: some_file.xxx some_file2.xxx some_file3.xxx I would like to have a bash script to take one line from the filename file and rename one file in the folder. Is there a way to do this?

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  • How to pass parameters to a Linux Bash script?

    - by chun
    I have a Linux bash script 'myshell'. I want it to read two dates as parameters, for example: myshell date1 date2. I am a Java programmer, but don't know how to write a script to get this done. The rest of the script is like this: sed "s/$date1/$date2/g" wlacd_stat.xml >tmp.xml mv tmp.xml wlacd_stat.xml

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  • How to pass an associative array as argument to a function in Bash?

    - by niksfirefly
    How do you pass an associative array as an argument to a function? Is this possible in Bash? The code below is not working as expected: function iterateArray { local ADATA="${@}" # associative array for key in "${!ADATA[@]}" do echo "key - ${key}" echo "value: ${ADATA[$key]}" done } Passing associative arrays to a function like normal arrays does not work: iterateArray "$A_DATA" or iterateArray "$A_DATA[@]"

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