Search Results

Search found 3988 results on 160 pages for 'collision resolution'.

Page 34/160 | < Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >

• Getting max. screen resolution with Group By

  - by Quandary

  Question: I have a website where I gather browser statistics. I have an SQL table (T_Visits), with the following columns: uniqueidentifier Visit_UID, uniqueidentifier User_UID, datetime Visit_DateTime, float Screen_w, float Screen_h, float Resolution = Screen_w * Screen_h varchar resolutionstring = screen_w + ' x ' + screen_h Now I want to get the maximum/minimum resolution each user had: Select User_UID, max(resolution) from T_Visits GROUP BY User_UID How can I get the corresponding resolution string ? I mean I can get the max(screen_w) and max(screen_h), but there's no guarantee that the corresponding resolutionstring would be max(screen_w) +' x '+ max(screen_h)

  Read the article

• Problem to match font size to the screen resolution in libgdx

  - by Iñaki Bedoya

  I'm having problems to show text on my game at same size on different screens, and I did a simple test. This test consists to show a text fitting at the screen, I want the text has the same size independently from the screen and from DPI. I've found this and this answer that I think should solve my problem but don't. In desktop the size is ok, but in my phone is too big. This is the result on my Nexus 4: (768x1280, 2.0 density) And this is the result on my MacBook: (480x800, 0.6875 density) I'm using the Open Sans Condensed (link to google fonts) As you can see on desktop looks good, but on the phone is so big. Here the code of my test: public class TextTest extends ApplicationAdapter { private static final String TAG = TextTest.class.getName(); private static final String TEXT = "Tap the screen to start"; private OrthographicCamera camera; private Viewport viewport; private SpriteBatch batch; private BitmapFont font; @Override public void create () { Gdx.app.log(TAG, "Screen size: "+Gdx.graphics.getWidth()+"x"+Gdx.graphics.getHeight()); Gdx.app.log(TAG, "Density: "+Gdx.graphics.getDensity()); camera = new OrthographicCamera(); viewport = new ExtendViewport(Gdx.graphics.getWidth(), Gdx.graphics.getWidth(), camera); batch = new SpriteBatch(); FreeTypeFontGenerator generator = new FreeTypeFontGenerator(Gdx.files.internal("fonts/OpenSans-CondLight.ttf")); font = createFont(generator, 64); generator.dispose(); } private BitmapFont createFont(FreeTypeFontGenerator generator, float dp) { FreeTypeFontGenerator.FreeTypeFontParameter parameter = new FreeTypeFontGenerator.FreeTypeFontParameter(); int fontSize = (int)(dp * Gdx.graphics.getDensity()); parameter.size = fontSize; Gdx.app.log(TAG, "Font size: "+fontSize+"px"); return generator.generateFont(parameter); } @Override public void render () { Gdx.gl.glClearColor(1, 1, 1, 1); Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT); int w = -(int)(font.getBounds(TEXT).width / 2); batch.setProjectionMatrix(camera.combined); batch.begin(); font.setColor(Color.BLACK); font.draw(batch, TEXT, w, 0); batch.end(); } @Override public void resize(int width, int height) { viewport.update(width, height); } @Override public void dispose() { font.dispose(); batch.dispose(); } } I'm trying to find a neat way to fix this. What I'm doing wrong? is the camera? the viewport? UPDATE: What I want is to keep the same margins in proportion, independently of the screen size or resolution. This image illustrates what I mean.

  Read the article

• Automatically change resolution when not in dock

  - by jwir3

  I have Ubuntu 11.04 (yep, I know it's old news) on my Lenovo W520. At home, I have a dock with dual monitors. I have a pretty decent setup - things work almost perfectly (hence the reason I'm reluctant to upgrade... that and I'm not 100% sold on Unity). Anyway, the only annoyance I have is that when I'm on travel, I use the laptop screen. When I un-dock the laptop, I need to manually go into nvidia x-server settings and change the resolution from 'Auto' to 1920x1200, or it will think I have two screens, and my mouse pointer will be able to go way off the left side of the screen. This isn't a big deal, but I need to do it every time I restart the x-server (so if I reboot, or have to kill it, etc...) What would be really nice is if there was a way for it to automatically detect whether or not there is external monitors (which it seems to do already), and switch into the mode I select, depending on which monitors are connected. Is there any way to accomplish this? I've posted my xorg.conf file for reference. # nvidia-settings: X configuration file generated by nvidia-settings # nvidia-settings: version 270.29 (buildd@allspice) Fri Feb 25 14:42:07 UTC 2011 # nvidia-xconfig: X configuration file generated by nvidia-xconfig # nvidia-xconfig: version 275.19 ([email protected]) Tue Jul 12 18:35:38 PDT 2011 #Section "Monitor" # Identifier "Monitor1" # VendorName "Lenovo" # ModelName "ThinkpadLCD" # #HorizSync 28.0 - 33.0 # #VertRefresh 43.0 - 72.0 # #Option "DPMS" #EndSection Section "ServerLayout" Identifier "Layout0" Screen 0 "Screen0" 0 0 InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" Option "Xinerama" "0" EndSection Section "InputDevice" Identifier "Mouse0" Driver "mouse" Option "Protocol" "auto" Option "Device" "/dev/psaux" Option "Emulate3Buttons" "no" Option "ZAxisMapping" "4 5" EndSection Section "InputDevice" # generated from default Identifier "Keyboard0" Driver "kbd" EndSection Section "Monitor" Identifier "Monitor0" VendorName "Unknown" ModelName "DELL U2410" HorizSync 30.0 - 81.0 VertRefresh 56.0 - 76.0 Option "DPMS" EndSection Section "Device" Identifier "Device0" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "Quadro 1000M" Option "RegistryDwords" "EnableBrightnessControl=1" EndSection Section "Screen" # Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+120, DFP-6: nvidia-auto-select +1920+0" # Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+120, DFP-5: nvidia-auto-select +1920+0" # Removed Option "metamodes" "DFP-0: nvidia-auto-select +1920+419, DFP-5: nvidia-auto-select +3840+0, DFP-6: nvidia-auto-select +0+0" # Removed Option "metamodes" "DFP-5: nvidia-auto-select +0+0, DFP-6: 1920x1200 +1920+0" Identifier "Screen0" Device "Device0" Monitor "Monitor0" DefaultDepth 24 Option "NoLogo" "True" Option "TwinViewXineramaInfoOrder" "DFP-0" Option "TwinView" "1" Option "metamodes" "DFP-5: nvidia-auto-select +1920+0, DFP-6: 1920x1200 +0+0" SubSection "Display" Depth 24 EndSubSection EndSection

  Read the article

• Points on lines where the two lines are the closest together

  - by James Bedford

  Hey guys, I'm trying to find the points on two lines where the two lines are the closest. I've implemented the following method (Points and Vectors are as you'd expect, and a Line consists of a Point on the line and a non-normalized direction Vector from that point): void CDClosestPointsOnTwoLines(Line line1, Line line2, Point* closestPoints) { closestPoints[0] = line1.pointOnLine; closestPoints[1] = line2.pointOnLine; Vector d1 = line1.direction; Vector d2 = line2.direction; float a = d1.dot(d1); float b = d1.dot(d2); float e = d2.dot(d2); float d = a*e - b*b; if (d != 0) // If the two lines are not parallel. { Vector r = Vector(line1.pointOnLine) - Vector(line2.pointOnLine); float c = d1.dot(r); float f = d2.dot(r); float s = (b*f - c*e) / d; float t = (a*f - b*c) / d; closestPoints[0] = line1.positionOnLine(s); closestPoints[1] = line2.positionOnLine(t); } else { printf("Lines were parallel.\n"); } } I'm using OpenGL to draw three lines that move around the world, the third of which should be the line that most closely connects the other two lines, the two end points of which are calculated using this function. The problem is that the first point of closestPoints after this function is called will lie on line1, but the second point won't lie on line2, let alone at the closest point on line2! I've checked over the function many times but I can't see where the mistake in my implementation is. I've checked my dot product function, scalar multiplication, subtraction, positionOnLine() etc. etc. So my assumption is that the problem is within this method implementation. If it helps to find the answer, this is function supposed to be an implementation of section 5.1.8 from 'Real-Time Collision Detection' by Christer Ericson. Many thanks for any help!

  Read the article

• AABB Sweeping, algorithm to solve "stacking box" problem

  - by Ivo Wetzel

  I'm currently working on a simple AABB collision system and after some fiddling the sweeping of a single box vs. another and the calculation of the response velocity needed to push them apart works flawlessly. Now on to the new problem, imagine I'm having a stack of boxes which are falling towards a ground box which isn't moving: Each of these boxes has a vertical velocity for the "gravity" value, let's say this velocity is 5. Now, the result is that they all fall into each other: The reason is obvious, since all the boxes have a downward velocity of 5, this results in no collisions when calculating the relative velocity between the boxes during sweeping. Note: The red ground box here is static (always 0 velocity, can utilize spatial partitioning ), and all dynamic static collisions are resolved first, thus the fact that the boxes stop correctly at this ground box. So, this seems to be simply an issue with the order the boxes are sweept against each other. I imagine that sorting the boxes based on their x and y velocities and then sweeping these groups correctly against each other may resolve this issues. So, I'm looking for algorithms / examples on how to implement such a system. The code can be found here: https://github.com/BonsaiDen/aabb The two files which are of interest are [box/Dynamic.lua][3] and [box/Manager.lua][4]. The project is using Love2D in case you want to run it.

  Read the article

• Finding the normals of an oriented bounding box?

  - by Milo

  Here is my problem. I'm working on the physics for my 2D game. All objects are oriented bounding boxes (OBB) based on the separate axis theorem. In order to do collision resolution, I need to be able to get an object out out of the object it is penetrating. To do this I need to find the normal of the face(s) that the other OBB is touching. Example: The small red OBB is a car lets say, and the big OBB is a static building. I need to determine the unit vector that is the normal of the building edge(s) the car is penetrating to get the car out of there. Here are my questions: How do I determine which edges the car is penetrating. I know how to determine the normal of an edge, but how do I know if I need (-dy, dx) or (dy, -dx)? In the case I'm demonstrating the car is penetrating 2 edges, which edge(s) do I use to get it out? Answers or help with any or all of these is greatly appreciated. Thank you

  Read the article

• Updating physics for animated models

  - by Mathias Hölzl

  For a new game we have do set up a scene with a minimum of 30 bone animated models.(shooter) The problem is that the update process for the animated models takes too long. Thats what I do: Each character has ~30 bones and for every update tick the animation gets calculated and every bone fires a event with the new matrix. The physics receives the event with the new matrix and updates the collision shape for that bone. The time that it takes to build the animation isn't that bad (0.2ms for 30 Bones - 6ms for 30 models). But the main problem is that the physic engine (Bullet) uses a diffrent matrix for transformation and so its necessary to convert it. Code for matrix conversion: (~0.005ms) btTransform CLEAR_PHYSICS_API Mat_to_btTransform( Mat mat ) { btMatrix3x3 bulletRotation; btVector3 bulletPosition; XMFLOAT4X4 matData = mat.GetStorage(); // copy rotation matrix for ( int row=0; row<3; ++row ) for ( int column=0; column<3; ++column ) bulletRotation[row][column] = matData.m[column][row]; for ( int column=0; column<3; ++column ) bulletPosition[column] = matData.m[3][column]; return btTransform( bulletRotation, bulletPosition ); } The function for updating the transform(Physic): void CLEAR_PHYSICS_API BulletPhysics::VKinematicMove(Mat mat, ActorId aid) { if ( btRigidBody * const body = FindActorBody( aid ) ) { btTransform tmp = Mat_to_btTransform( mat ); body->setWorldTransform( tmp ); } } The real problem is the function FindActorBody(id): ActorIDToBulletActorMap::const_iterator found = m_actorBodies.find( id ); if ( found != m_actorBodies.end() ) return found->second; All physic actors are stored in m_actorBodies and thats why the updating process takes to long. But I have no idea how I could avoid this. Friendly greedings, Mathias

  Read the article

• Efficient mapping layout in 2D side-scroller, and collisions between character and the world

  - by Jack

  I haven't touched Visual Studio for a couple months now, but I was playing a game from the '90s toady and had an epiphany: I was looking for something what i didn't need, and I wasn't using what I knew correctly. One of those realizations was collision, so let me tell you a bit about my project that I was working on. The project's graphics looks like Mario or Dangerous Dave, etc., you get the idea - old-school pixels. So anyway I remember trying to think of something else than AABB for character form, but I couldn't think of anything. Perhaps I could get a suggestion for this? Another thing is the world - I don't want it to be just linear world, I want mountains, etc.. My idea is to use triangles, and no idea yet what to do if I want just part of the cube, say 3/4 or 2/4 or whatever. Hard-coding such things seems inefficient. P.S. I am not looking at the precision level offered by Box2D. Actually I remember trying to implement it at first, but I failed as my understanding of C++ wasn't advanced enough, as it'll be mentioned below. P.P.S. I am programming in C++, and I haven't done it for a couple months now. I have no means of testing it either, as my PC is broken down, and this one can barely run games from late '90s, not to speak about a compiler or a program with inefficient resource management... I am also not an expert (obviously), I don't even know if I can consider myself an average programmer. In short, I am simply curious about my thoughts and my past experience when programming the game. I may come back to it when my PC is fixed, I'm already filling a note about these things.

  Read the article

• Getting an OBB out of another OBB?

  - by Milo

  I'm working on collision resolution for my game. I just need a good way to get an object out of another object if it gets stuck. In this case a car. Here is a typical scenario. The red car is in the green object. How do I correctly get it out so the car can slide along the edge of the object as it should. I tried: if(buildings.size() > 0) { Entity e = buildings.get(0); Vector2D vel = new Vector2D(); vel.x = vehicle.getVelocity().x; vel.y = vehicle.getVelocity().y; vel.normalize(); while(vehicle.getRect().overlaps(e.getRect())) { vehicle.setCenter(vehicle.getCenterX() - vel.x * 0.1f, vehicle.getCenterY() - vel.y * 0.1f); } colided = true; } But that does not work too well. Is there some sort of vector I could calculate to use as the vector to move the car away from the object? Thanks

  Read the article

• Resultant Vector Algorithm for 2D Collisions

  - by John

  I am making a Pong based game where a puck hits a paddle and bounces off. Both the puck and the paddles are Circles. I came up with an algorithm to calculate the resultant vector of the puck once it meets a paddle. The game seems to function correctly but I'm not entirely sure my algorithm is correct. Here are my variables for the algorithm: Given: velocity = the magnitude of the initial velocity of the puck before the collision x = the x coordinate of the puck y = the y coordinate of the puck moveX = the horizontal speed of the puck moveY = the vertical speed of the puck otherX = the x coordinate of the paddle otherY = the y coordinate of the paddle piece.horizontalMomentum = the horizontal speed of the paddle before it hits the puck piece.verticalMomentum = the vertical speed of the paddle before it hits the puck slope = the direction, in radians, of the puck's velocity distX = the horizontal distance between the center of the puck and the center of the paddle distY = the vertical distance between the center of the puck and the center of the paddle Algorithm solves for: impactAngle = the angle, in radians, of the angle of impact. newSpeedX = the speed of the resultant vector in the X direction newSpeedY = the speed of the resultant vector in the Y direction Here is the code for my algorithm: int otherX = piece.x; int otherY = piece.y; double velocity = Math.sqrt((moveX * moveX) + (moveY * moveY)); double slope = Math.atan(moveX / moveY); int distX = x - otherX; int distY = y - otherY; double impactAngle = Math.atan(distX / distY); double newAngle = impactAngle + slope; int newSpeedX = (int)(velocity * Math.sin(newAngle)) + piece.horizontalMomentum; int newSpeedY = (int)(velocity * Math.cos(newAngle)) + piece.verticalMomentum; for those who are not program savvy here is it simplified: velocity = v(moveX² + moveY²) slope = arctan(moveX / moveY) distX = x - otherX distY = y - otherY impactAngle = arctan(distX / distY) newAngle = impactAngle + slope newSpeedX = velocity * sin(newAngle) + piece.horizontalMomentum newSpeedY = velocity * cos(newAngle) + piece.verticalMomentum My Question: Is this algorithm correct? Is there an easier/simpler way to do what I'm trying to do?

  Read the article

• What causes player box/world geometry glitches in old games?

  - by Alexander

  I'm looking to understand and find the terminology for what causes - or allows - players to interfere with geometry in old games. Famously, ID's Quake3 gave birth to a whole community of people breaking the physics by jumping, sliding, getting stuck and launching themselves off points in geometry. Some months ago (though I'd be darned if I can find it again!) I saw a conference held by Bungie's Vic DeLeon and a colleague in which Vic briefly discussed the issues he ran into while attempting to wrap 'collision' objects (please correct my terminology) around environment objects so that players could appear as though they were walking on organic surfaces, while not clipping through them or appear to be walking on air at certain points, due to complexities in the modeling. My aim is to compose a case study essay for University in which I can tackle this issue in games, drawing on early exploits and how techniques have changed to address such exploits and to aid in the gameplay itself. I have 3 current day example of where exploits still exist, however specifically targeting ID Software clearly shows they've massively improved their techniques between Q3 and Q4. So in summary, with your help please, I'd like to gain a slightly better understanding of this issue as a whole (its terminology mainly) so I can use terms and ask the right questions within the right contexts. In practical application, I know what it is, I know how to do it, but I don't have the benefit of level design knowledge yet and its technical widgety knick-knack terms =) Many thanks in advance AJ

  Read the article

• What kind of physics to choose for our arcade 3D MMO?

  - by Nick

  We're creating an action MMO using Three.js (WebGL) with an arcadish feel, and implementing physics for it has been a pain in the butt. Our game has a terrain where the character will walk on, and in the future 3D objects (a house, a tree, etc) that will have collisions. In terms of complexity, the physics engine should be like World of Warcraft. We don't need friction, bouncing behaviour or anything more complex like joints, etc. Just gravity. I have managed to implement terrain physics so far by casting a ray downwards, but it does not take into account possible 3D objects. Note that these 3D objects need to have convex collisions, so our artists create a 3D house and the player can walk inside but can't walk through the walls. How do I implement proper collision detection with 3D objects like in World of Warcraft? Do I need an advanced physics engine? I read about Physijs which looks cool, but I fear that it may be overkill to implement that for our game. Also, how does WoW do it? Do they have a separate raycasting system for the terrain? Or do they treat the terrain like any other convex mesh? A screenshot of our game so far:

  Read the article

• Checking for collisions on a 3D heightmap

  - by Piku

  I have a 3D heightmap drawn using OpenGL (which isn't important). It's represented by a 2D array of height data. To draw this I go through the array using each point as a vertex. Three vertices are wound together to form a triangle, two triangles to make a quad. To stop the whole mesh being tiny I scale this by a certain amount called 'gridsize'. This produces a fairly nice and lumpy, angular terrain kind of similar to something you'd see in old Atari/Amiga or DOS '3D' games (think Virus/Zarch on the Atari ST). I'm now trying to work out how to do collision with the terrain, testing to see if the player is about to collide with a piece of scenery sticking upwards or fall into a hole. At the moment I am simply dividing the player's co-ordinates by the gridsize to find which vertex the player is on top of and it works well when the player is exactly over the corner of a triangle piece of terrain. However... How can I make it more accurate for the bits between the vertices? I get confused since they don't exist in my heightmap data, they're a product of the GPU trying to draw a triangle between three points. I can calculate the height of the point closest to the player, but not the space between them. I.e if the player is hovering over the centre of one of these 'quads', rather than over the corner vertex of one, how do I work out the height of the terrain below them? Later on I may want the player to slide down the slopes in the terrain.

  Read the article

• Normalizing the direction to check if able to move

  - by spartan2417

  i have a a room with 4 walls along the x and z axis respectively. My player who is in first person (therefore the camera) should have collision detection with these walls. I'm relatively new to this so please bare with me. I believe the way to do this is to calculate the direction and distance to the wall from the camera and then normalize the directions. However i can only get this far before i dont know what to do. I think you should work out the angle and direction your facing? where _dx and _dz is the small buffer in front of the camera. float CalcDirection(float Cam_x, float Cam_z, float Wall_x, float Wall_z) { //Calculate direction and distance to obstacle. float ob_dirx = Cam_x + _dx - Wall_x; float ob_dirz = Cam_z + _dz - Wall_z; float ob_dist = sqrt(ob_dirx*ob_dirx + ob_dirz*ob_dirz); //Normalise directions float ob_norm = sqrt(ob_dirx*ob_dirx + ob_dirz*ob_dirz); ob_dirx = (ob_dirx)/ob_norm; ob_dirz = (ob_dirz)/ob_norm; can anyone explain in laymen's terms how i work out the angle?

  Read the article

• BoundingSpheres move when they should not

  - by NDraskovic

  I have a XNA 4.0 project in which I load a file that contains type and coordinates of items I need to draw to the screen. Also I need to check if one particular type (the only movable one) is passing in front or trough other items. This is the code I use to load the configuration: if (ks.IsKeyDown(Microsoft.Xna.Framework.Input.Keys.L)) { this.GraphicsDevice.Clear(Color.CornflowerBlue); Otvaranje.ShowDialog(); try { using (StreamReader sr = new StreamReader(Otvaranje.FileName)) { String linija; while ((linija = sr.ReadLine()) != null) { red = linija.Split(','); model = red[0]; x = red[1]; y = red[2]; z = red[3]; elementi.Add(Convert.ToInt32(model)); podatci.Add(new Vector3(Convert.ToSingle(x), Convert.ToSingle(y), Convert.ToSingle(z))); sfere.Add(new BoundingSphere(new Vector3(Convert.ToSingle(x), Convert.ToSingle(y), Convert.ToSingle(z)), 1f)); } } } catch (Exception ex) { Window.Title = ex.ToString(); } } The "Otvaranje" is an OpenFileDialog object, "elementi" is a List (determines the type of item that would be drawn), podatci is a List (determines the location where the items will be drawn) and sfere is a List. Now I solved the picking algorithm (checking for ray and bounding sphere intersection) and it works fine, but the collision detection does not. I noticed, while using picking, that BoundingSphere's move even though the objects that they correspond to do not. The movable object is drawn to the world1 Matrix, and the static objects are drawn into the world2 Matrix (world1 and world2 have the same values, I just separated them so that the static elements would not move when the movable one does). The problem is that when I move the item I want, all boundingSpheres move accordingly. How can I move only the boundingSphere that corresponds to that particular item, and leave the rest where they are?

  Read the article

• Point in Polygon, Ray Method: ending infinite line

  - by user2878528

  Having a bit of trouble with point in polygon collision detection using the ray method i.e. http://en.wikipedia.org/wiki/Point_in_polygon My problem is I need to give an end to the infinite line created. As with this infinite line I always get an even number of intersections and hence an invalid result. i.e. ignore or intersection to the right of the point being checked what I have what I want My current code based of Mecki awesome response for (int side = 0; side < vertices.Length; side++) { // Test if current side intersects with ray. // create infinite line // See: http://en.wikipedia.org/wiki/Linear_equation a = end_point.Y - start_point.Y; b = start_point.X - end_point.X; c = end_point.X * start_point.Y - start_point.X * end_point.Y; //insert points of vector d2 = a * vertices[side].Position.X + b * vertices[side].Position.Y + c; if (side - 1 < 0) d1 = a * vertices[vertices.Length - 1].Position.X + b * vertices[vertices.Length - 1].Position.Y + c; else d1 = a * vertices[side-1].Position.X + b * vertices[side-1].Position.Y + c; // If points have opposite sides, intersections++; if (d1 > 0 && d2 < 0 ) intersections++; if (d1 < 0 && d2 > 0 ) intersections++; } //if intersections odd inside = true if ((intersections % 2) == 1) inside = true; else inside = false;

  Read the article

• Drivers for Ubuntu 13.10 [on hold]

  - by Fernando De Souza Martins

  I just installed Ubuntu 13.10, my screen resolution is not fitting my screen as the ubuntu interface is all around stretching over the screen, so i thought i might install nvidia's driver that i know can let me adjust the exact resolution i need. So i began a 2 hour quest, i downloaded the driver hoping i would have a wizard to instal it, but yeah, so i tried to do a bit of research and i found that feature, i think its called in english additional drivers, but it wont show the nvidia drivers, i tried the terminal, but once i write the commands i found it asks for a password but i cant type anything once the password is asked. So, my question, obviously, how do i install this driver? I am not sure if this is appropriate, but why doesnt ubuntu have a wizard to install things? I feel like im working for the OS, when it should be the other way around, but i love the concept of linux, so im pushing forward and trying to use it. Another thing is, i had to install a bunch of drivers and applications for the drivers in windows, do i need to install any other driver? I cant change my mouse's sensibility in the os, it seems, so how do i do it? I'm sorry i'm asking all of this, but it seems necessary.

  Read the article

• Unity Greeter login screen cuts off login options

  - by ammianus

  I have a pretty newly installed Ubuntu 12.04, using Unity. My external monitor is 1920x1080 max resolution. In the Unity desktop itself everything looks great. I have an NVidia graphics card. When I start my computer and get to the Unity greeter login screen the display is oddly formatted and the resolution seems off. It looks like a zoomed view on the larger 1920x1080 screen. As such it crops the login options off to the left hand side of the screen. So I can only just see the edge of the password box for the user I want to log in with. I can log in with one account by default by blindly typing the password, but I am unable to switch to other accounts. Is there anything I can do to fix the log in screen display so that I can see the normal login options? Note: I first noticed it when I changed my desktop background and the next time I logged in I saw the issue.

  Read the article

• Latest update to Ubuntu 13.10 broke Intel graphics drivers

  - by James Davies

  I'm running a copy of Ubuntu 13.10 on an i7-4771 w/ Intel HD4600 Graphics using a Dell Ultrasharp 1440p monitor via Displayport. Up until today this configuration has been working perfectly, however the latest update appears to have broken my graphics configuration, and xorg is now refusing to go above 1280p resolution. Running xrandr it appears the driver incorrectly thinks my monitor is plugged into the HDMI port and is detecting a max resolution of 1920x1200 instead of 2560x1440. (It's actually plugged in via Displayport). Based on the apt history.log, the latest update was for the kernel. I'm presuming the issue is that the official Intel driver hasn't been updated to support this version? Is there any way to resolve this, or will I need to upgrade to 14.10 to get the latest driver from Intel? Start-Date: 2014-05-28 11:30:57 Commandline: aptdaemon role='role-commit-packages' sender=':1.473' Install: linux-image-extra-3.11.0-22-generic:amd64 (3.11.0-22.38), linux-image-3.11.0-22-generic:amd64 (3.11.0-22.38), linux-headers-3.11.0-22:amd64 (3.11.0-22.38), linux-headers-3.11.0-22-generic:amd64 (3.11.0-22.38)

  Read the article

• How can I replicate the look and limitations of the Super NES?

  - by Mikalichov

  I am looking to produce graphics with the same limitations / look that in the Super Nes era. I am specifically looking for graphics similar to Chrono Trigger / FF6. It would be a lot easier to do if I had an idea of the resolution / dpi I am supposed to use. I found that the technical specs for the SNES are: Progressive: 256 × 224, 512 × 224, 256 × 239, 512 × 239 Interlaced: 512 × 448, 512 × 478 But even by using these resolutions, it is pointless if I set it at 72dpi, as I will still have possibly very detailed graphics (that is the main thing, I don't want detailed graphics, I want to go pixelated). I figured it might be related to the sprite size limit, i.e.: Sprites can be 8 × 8, 16 × 16, 32 × 32, or 64 × 64 pixels, each using one of eight 16-color palettes and tiles from one of two blocks of 256 in VRAM. Up to 32 sprites and 34 8 × 8 sprite tiles may appear on any one line. This would work for sprites (characters, objects), but what about maps? Are they built entirely from 8x8 tiles? And then, at what resolution is the end result displayed? It might seem like I am giving the question and answers at the same time, but all of these are suppositions I am making, so could someone confirm or correct them?

  Read the article

• Your Job Search Should be More Than Just a New Year's Resolution

  - by david.talamelli

  I love the beginning of a new year, it is a great chance to refocus and either re-evaluate goals you are working to or even set new ones. I don't have any statistics to measure this but I am sure that one of the more popular new year's resolutions in the general workforce is to either get a new job or work to further develop one's career. I think this is a good idea, in today's competitive work force people should have a plan of what they want to do, what role they are after and how to get there. One common mistake I think many people make though is that a career plan shouldn't be a once a year thought. When people finish with the holiday season with their new year's resolution to find a new job fresh in their mind, you can see the enthusiasm and motivation a person has to make something happen. Emails are sent, calls are made, applications are made, networking is happening, etc..... Finding the right role that you are after however can be difficult, while it would be great if that dream role was available just at the time you happened to be looking for it - in reality this is not always the case. Job Seekers need to keep reminding themselves that while sometimes that dream job they are after is available at the same time they are looking, that also a Job search can be a difficult and long process. Many people who set out with the best of intentions in January to find a new job can soon lose interest in a job search if they do not immediately find a role. Just like the Christmas decorations are put away and the photos from New Year's are stored away - a Job Seeker's motivation may slowly decrease until that person finds themselves 12 months later in the same situation in same role and looking for that new opportunity again. Rather than just "going for it" and looking for a role in the month of January, a person's job search or career plan should be an ongoing activity and thought process that is constantly updated and evaluated over the course of the year. It can be hard to stay motivated over an extended period of time, especially when you are newly motivated and ready for that new role and the results are not immediate. Rather than letting your job search fall down the priority list and into the "too hard basket" a few ideas that may keep your enthusiasm fresh Update your resume every 6 months, even if you are not looking for a job - it is easy to forget what you have accomplished if you don't keep your details updated. Also it is good to be prepared and have a resume ready to go in case you do get an unexpected phone call for that 'dream job' you have been hoping for. Work out what you want out of your next role before you begin your job search - rather than aimlessly searching job ads or talking to people - think of the organisations or type of role you would like before you search. If you know what you are looking for it will be much easier to work out how to get there than if you do not know what you want. Don't expect immediate results once you decide to look for another job, things don't always fall into place. Timing and delivery can be important pieces of being selected for a role, companies don't hire every role in January. Have an open mind - people you meet or talk to may not result in immediate results for your job search but every connection may help you get a bit closer to what you are after . These actions will not guarantee a positive result, but in today's competitive work force every little of extra preparation and planning helps. All the best for 2011 and I hope your career plan whatever it may be is a success.

  Read the article

• How to detect collisions in AS3?

  - by Gabriel Meono

  I'm trying to make a simple game, when the ball falls into certain block, you win. Mechanics: The ball falls through several obstacles, in the end there are two blocks, if the ball touches the left block you win, the next level will contain more blocks and less space between them. Test the movie (click on the screen to drop the ball): http://gabrielmeono.com/downloads/Lucky_Hit_Alpha.swf These are the main variables: var winBox:QuickObject;//You win var looseBox:QuickObject;//You loose var gameBall:QuickObject;//Ball dropped Question: How do I trigger a collision function if the ball hits the winBox? (Win message/Next level) Thanks, here is the full code: package { import flash.display.MovieClip; import com.actionsnippet.qbox.*; import flash.events.MouseEvent; [SWF(width = 600, height = 600, frameRate = 60)] public class LuckyHit extends MovieClip { public var sim:QuickBox2D; var winBox:QuickObject; var looseBox:QuickObject; var gameBall:QuickObject; /** * Constructor */ public function LuckyHit() { sim = new QuickBox2D(this); //sim.createStageWalls(); winBox = sim.addBox({x:5,y:600/30, width:300/30, height:10/30, density:0}); looseBox = sim.addBox({x:15,y:600/30, width:300/30, height:10/30, density:0}); // make obstacles for (var i:int = 0; i<(stage.stageWidth/50); i++){ //End sim.addCircle({x:1 + i * 1.5, y:16, radius:0.1, density:0}); sim.addCircle({x:2 + i * 1.5, y:15, radius:0.1, density:0}); //Mid End sim.addCircle({x:0 + i * 2, y:14, radius:0.1, density:0}); sim.addCircle({x:0 + i * 2, y:13, radius:0.1, density:0}); sim.addCircle({x:0 + i * 2, y:12, radius:0.1, density:0}); sim.addCircle({x:0 + i * 2, y:11, radius:0.1, density:0}); sim.addCircle({x:0 + i * 2, y:10, radius:0.1, density:0}); //Middle Start sim.addCircle({x:0 + i * 1.5, y:09, radius:0.1, density:0}); sim.addCircle({x:1 + i * 1.5, y:08, radius:0.1, density:0}); sim.addCircle({x:0 + i * 1.5, y:07, radius:0.1, density:0}); sim.addCircle({x:1 + i * 1.5, y:06, radius:0.1, density:0}); } sim.start(); stage.addEventListener(MouseEvent.CLICK, _clicked); } /** * .. * @param e MouseEvent.CLICK */ private function _clicked(e:MouseEvent) { gameBall = sim.addCircle({x:(mouseX/30), y:(1), radius:0.25, density:5}); } } }

  Read the article

• x axis detection issues platformer starter kit

  - by dbomb101

  I've come across a problem with the collision detection code in the platformer starter kit for xna.It will send up the impassible flag on the x axis despite being nowhere near a wall in either direction on the x axis, could someone could tell me why this happens ? Here is the collision method. /// <summary> /// Detects and resolves all collisions between the player and his neighboring /// tiles. When a collision is detected, the player is pushed away along one /// axis to prevent overlapping. There is some special logic for the Y axis to /// handle platforms which behave differently depending on direction of movement. /// </summary> private void HandleCollisions() { // Get the player's bounding rectangle and find neighboring tiles. Rectangle bounds = BoundingRectangle; int leftTile = (int)Math.Floor((float)bounds.Left / Tile.Width); int rightTile = (int)Math.Ceiling(((float)bounds.Right / Tile.Width)) - 1; int topTile = (int)Math.Floor((float)bounds.Top / Tile.Height); int bottomTile = (int)Math.Ceiling(((float)bounds.Bottom / Tile.Height)) - 1; // Reset flag to search for ground collision. isOnGround = false; // For each potentially colliding tile, for (int y = topTile; y <= bottomTile; ++y) { for (int x = leftTile; x <= rightTile; ++x) { // If this tile is collidable, TileCollision collision = Level.GetCollision(x, y); if (collision != TileCollision.Passable) { // Determine collision depth (with direction) and magnitude. Rectangle tileBounds = Level.GetBounds(x, y); Vector2 depth = RectangleExtensions.GetIntersectionDepth(bounds, tileBounds); if (depth != Vector2.Zero) { float absDepthX = Math.Abs(depth.X); float absDepthY = Math.Abs(depth.Y); // Resolve the collision along the shallow axis. if (absDepthY < absDepthX || collision == TileCollision.Platform) { // If we crossed the top of a tile, we are on the ground. if (previousBottom <= tileBounds.Top) isOnGround = true; // Ignore platforms, unless we are on the ground. if (collision == TileCollision.Impassable || IsOnGround) { // Resolve the collision along the Y axis. Position = new Vector2(Position.X, Position.Y + depth.Y); // Perform further collisions with the new bounds. bounds = BoundingRectangle; } } //This is the section which deals with collision on the x-axis else if (collision == TileCollision.Impassable) // Ignore platforms. { // Resolve the collision along the X axis. Position = new Vector2(Position.X + depth.X, Position.Y); // Perform further collisions with the new bounds. bounds = BoundingRectangle; } } } } } // Save the new bounds bottom. previousBottom = bounds.Bottom; }

  Read the article

• How to detect which edges of a rectange touch when they collide in iOS

  - by Mike King

  I'm creating a basic "game" in iOS 4.1. The premise is simple, there is a green rectangle ("disk") that moves/bounces around the screen, and red rectangle ("bump") that is stationary. The user can move the red "bump" by touching another coordinate on the screen, but that's irrelevant to this question. Each rectangle is a UIImageView (I will replace them with some kind of image/icon once I get the mechanics down). I've gotten as far as detecting when the rectangles collide, and I'm able to reverse the direction of the green "disk" on the Y axis if they do. This works well when the green "disk" approaches the red "bump" from top or bottom, it bounces off in the other direction. But when it approaches from the side, the bounce is incorrect; I need to reverse the X direction instead. Here's the timer I setup: - (void)viewDidLoad { xSpeed = 3; ySpeed = -3; gameTimer = [NSTimer scheduledTimerWithTimeInterval:0.05 target:self selector:@selector(mainGameLoop:) userInfo:nil repeats:YES]; [super viewDidLoad]; } Here's the main game loop: - (void) mainGameLoop:(NSTimer *)theTimer { disk.center = CGPointMake(disk.center.x + xSpeed, disk.center.y + ySpeed); // make sure the disk does not travel off the edges of the screen // magic number values based on size of disk's frame // startAnimating causes the image to "pulse" if (disk.center.x < 55 || disk.center.x > 265) { xSpeed = xSpeed * -1; [disk startAnimating]; } if (disk.center.y < 55 || disk.center.y > 360) { ySpeed = ySpeed * -1; [disk startAnimating]; } // check to see if the disk collides with the bump if (CGRectIntersectsRect(disk.frame, bump.frame)) { NSLog(@"Collision detected..."); if (! [disk isAnimating]) { ySpeed = ySpeed * -1; [disk startAnimating]; } } } So my question is: how can I detect whether I need to flip the X speed or the Y speed? ie: how can I calculate which edge of the bump was collided with?

  Read the article

• How does the method overload resolution system decide which method to call when a null value is passed?

  - by Joan Venge

  So for instance you have a type like: public class EffectOptions { public EffectOptions ( params object [ ] options ) {} public EffectOptions ( IEnumerable<object> options ) {} public EffectOptions ( string name ) {} public EffectOptions ( object owner ) {} public EffectOptions ( int count ) {} public EffectOptions ( Point point ) {} } Here I just give the example using constructors but the result will be the same if they were non-constructor methods on the type itself, right? So when you do: EffectOptions options = new EffectOptions (null); which constructor would be called, and why? I could test this myself but I want to understand how the overload resolution system works (not sure if that's what it's called).

  Read the article

< Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >