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  • ClassCastException in iterating list returned by Query using Hibernate Query Language

    - by Tushar Paliwal
    I'm beginner in hibernate.I'm trying a simplest example using HQL but it generates exception at line 25 ClassCastException when i try to iterate list.When i try to cast the object returned by next() methode of iterator it generates the same problem.I could not identify the problem.Kindly give me solution of the problem. Employee.java package one; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class Employee { @Id private Long id; private String name; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } public Employee(Long id, String name) { super(); this.id = id; this.name = name; } public Employee() { } } Main2.java package one; import java.util.Iterator; import java.util.List; import org.hibernate.Query; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.Transaction; import org.hibernate.cfg.Configuration; public class Main2 { public static void main(String[] args) { SessionFactory sf=new Configuration().configure().buildSessionFactory(); Session s1=sf.openSession(); Query q=s1.createQuery("from Employee "); Transaction tx=s1.beginTransaction(); List l=q.list(); Iterator itr=l.iterator(); while(itr.hasNext()) { Object obj[]=(Object[])itr.next();//Line 25 for(Object temp:obj) { System.out.println(temp); } } tx.commit(); s1.close(); sf.close(); } }

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  • Alter Index All Tables

    - by Derek Dieter
    This script comes in handy when needing to alter all indexes in a database and rebuild them. This will only work on SQL Server 2005+. It utilizes the ALL keyword in the Alter index statement to rebuild all the indexes for a particular table. This script retrieves all base tables and stores [...]

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  • Jobs - are your SQL Agent jobs talking to you enough?

    - by fatherjack
    Most DBAs will have at least a couple of servers that have SQL Agent jobs that are scheduled to do various things on a regular basis. There is a whole host of supporting configuration settings for these jobs but some of the most important are notifications. Notification settings are there to keep you up to date on how your job executions went. You have options on types of notification - email, pager, net send, or an entry in the SQL Server Event Log and you get options on when each of these channels...(read more)

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  • Shrinking a Linux OEL 6 virtual Box image (vdi) hosted on Windows 7

    - by AndyBaker
    v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} Recently for a customer demonstration there was a requirement to build a virtual box image with Oracle Enterprise Manager Cloud Control 12c. This meant installing OEL Linux 6 as well as creating an 11gr2 database and Oracle Enterprise Manager Cloud Control 12c on a single virtual box. Storage was sized at 300Gb using dynamically allocated storage for the virtual box and about 10Gb was used for Linux and the initial build. After copying over all the binaries and performing all the installations the virtual box became in the region of 80Gb used size on the host operating system, however internally it only really needed around 20Gb. This meant 60Gb had been used when copying over all the binaries and although now free was not returned to the host operating system due to the growth of the virtual box storage '.vdi' file.  Once the ‘vdi’ storage had grown it is not shrunk automatically afterwards. Space is always tight on the laptop so it was desirable to shrink the virtual box back to a minimal size and here is the process that was followed. Install 'zerofree' Linux package into the OEL6 virtual box The RPM was downloaded and installed from a site similar to below; http://rpm.pbone.net/index.php3/stat/4/idpl/12548724/com/zerofree-1.0.1-5.el5.i386.rpm.html A simple internet search for ’zerofree Linux rpm’ was easy to perform and find the required rpm. Execute 'zerofree' package on the desired Linux file system To execute this package the desired file system needs to be mounted read only. The following steps outline this process. As root: # umount /u01 As root:# mount –o ro –t ext4 /u01 NOTE: The –o is options and the –t is the file system type found in the /etc/fstab. Next run zerofree against the required storage, this is located by a simple ‘df –h’ command to see the device associated with the mount. As root:# zerofree –v /dev/sda11   NOTE: This takes a while to run but the ‘-v’ option gives feedback on the process. What does Zerofree do? Zerofree’s purpose is to go through the file system and zero out any unused sectors on the volume so that the later stages can shrink the virtual box storage obtaining the free space back. When zerofree has completed the virtual box can be shutdown as the last stage is performed on the physical host where the virtual box vdi files are located. Compact the virtual box ‘.vdi’ files The final stage is to get virtual box to shrink back the storage that has been correctly flagged as free space after executing zerofree. On the physical host in this case a windows 7 laptop a DOS window was opened. At the prompt the first step is to put the virtual box binaries onto the PATH. C:\ >echo %PATH%   The above shows the current value of the PATH environment variable. C:\ >set PATH=%PATH%;c:\program files\Oracle\Virtual Box;   The above adds onto the existing path the virtual box binary location. C:\>cd c:\Users\xxxx\OEL6.1   The above changes directory to where the VDI files are located for the required virtual box machine. C:\Users\xxxxx\OEL6.1>VBoxManage.exe modifyhd zzzzzz.vdi compact  NOTE: The zzzzzz.vdi is the name of the required vdi file to shrink. Finally the above command is executed to perform the compact operation on the ‘.vdi’ file(s). This also takes a long time to complete but shrinks the VDI file back to a minimum size. In the case of the demonstration virtual box OEM12c this reduced the virtual box to 20Gb from 80Gb which was a great outcome to achieve.

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  • PASS Summit 2012, Day 1

    - by KKline
    One of the most positive experiences I can have, as a former leader of the PASS organization, is when I see a neophyte become a passionate support and champion for the community. On my first day in Seattle, before the event had even begun, I was stopped several by people who'd attended their first PASS Summit last year. But this year, they were excited to tell me that they'd started user groups in their own community, spoken for the first time at a PASS event, or even helped launch a SQL Saturday...(read more)

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  • What to leave when you're leaving

    - by BuckWoody
    There's already a post on this topic - sort of. I read this entry, where the author did a good job on a few steps, but I found that a few other tips might be useful, so if you want to check that one out and then this post, you might be able to put together your own plan for when you leave your job.  I once took over the system administrator (of which the Oracle and SQL Server servers were a part) at a mid-sized firm. The outgoing administrator had about a two- week-long scheduled overlap with me, but was angry at the company and told me "hey, I know this is going to be hard on you, but I want them to know how important I was. I'm not telling you where anything is or what the passwords are. Good luck!" He then quit that day. It took me about three days to find all of the servers and crack the passwords. Yes, the company tried to take legal action against the guy and all that, but he moved back to his home country and so largely got away with it. Obviously, this isn't the way to leave a job. Many of us have changed jobs in the past, and most of us try to be very professional about the transition to a new team, regardless of the feelings about a particular company. I've been treated badly at a firm, but that is no reason to leave a mess for someone else. So here's what you should put into place at a minimum before you go. Most of this is common sense - which of course isn't very common these days - and another good rule is just to ask yourself "what would I want to know"? The article I referenced at the top of this post focuses on a lot of documentation of the systems. I think that's fine, but in actuality, I really don't need that. Even with this kind of documentation, I still perform a full audit on the systems, so in the end I create my own system documentation. There are actually only four big items I need to know to get started with the systems: 1. Where is everything/everybody?The first thing I need to know is where all of the systems are. I mean not only the street address, but the closet or room, the rack number, the IU number in the rack, the SAN luns, all that. A picture here is worth a thousand words, which is why I really like Visio. It combines nice graphics, full text and all that. But use whatever you have to tell someone the physical locations of the boxes. Also, tell them the physical location of the folks in charge of those boxes (in case you aren't) or who share that responsibility. And by "where" in this case, I mean names and phones.  2. What do they do?For both the servers and the people, tell them what they do. If it's a database server, detail what each database does and what application goes to that, and who "owns" that application. In my mind, this is one of hte most important things a Data Professional needs to know. In the case of the other administrtors or co-owners, document each person's responsibilities.   3. What are the credentials?Logging on/in and gaining access to the buildings are things that the new Data Professional will need to do to successfully complete their job. This means service accounts, certificates, all of that. The first thing they should do, of course, is change the passwords on all that, but the first thing they need is the ability to do that!  4. What is out of the ordinary?This is the most tricky, and perhaps the next most important thing to know. Did you have to use a "special" driver for that video card on server X? Is the person that co-owns an application with you mentally unstable (like me) or have special needs, like "don't talk to Buck before he's had coffee. Nothing will make any sense"? Do you have service pack requirements for a specific setup? Write all that down. Anything that took you a day or longer to make work is probably a candidate here. This is my short list - anything you care to add? Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • Bringing Alerts and Operators together with Notifications

    - by fatherjack
    I have covered SQL Server Alerts (Alerts are good, arent they?) on this blog before and I more recently did a post regarding Notifications (Are your Jobs talking to you) and how they should be configured. Now we need to check that these things are linked up so that when an Alert condition is met that you get the appropriate Notifications sent to Operators. Straight into the code we need and then a review of what it does ... DECLARE @ChosenOperator SYSNAME DECLARE @FailSafeOp TABLE ...(read more)

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  • Write a SQL to meet my requirement.

    - by rgksugan
    I have been trying to solve this problem for a lot of days. But wouldn't. Please help me. I need a SQL to list product_code, product_name, qty_sold, last_order_date for all the products that have been sold within a date range sorted by the number of quantity sold. My Table structure: tbl_product(product_id,product_code,product_name) tbl_order_detail(order_item_id,order_id,product_id,quantity) tbl_order(order_id,order_date)

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  • MySQL query against pseudo-key-value pair data in WordPress custom query

    - by andrevr
    I'm writing a custom WordPress query to use some of the data which the Woothemes Diarise theme creates. Diarise is an event planner theme with calendar blah, blah... and uses custom fields to store the event start and end dates in WP custom fields in the *wp_postmeta* table, which implements a key-value store. So for each post in the "event" category, there are 2 records in *wp_postmeta*, named *event_start_date* and *event_end_date* that I'm interested in. The task is to compare a tourist's arrival and departure dates with the start and end dates of events, yielding a what's on list of events available. We thought we'd killed it with a grand flash of logic, that goes like this: Disregard any event that ends before the tourist arrives, and any that begin after the departure date. I wrote this query: SELECT wposts.* FROM wp_posts wposts LEFT JOIN wp_postmeta wpostmeta ON wposts.ID = wpostmeta.post_id LEFT JOIN wp_term_relationships ON (wposts.ID = wp_term_relationships.object_id) LEFT JOIN wp_term_taxonomy ON (wp_term_relationships.term_taxonomy_id = wp_term_taxonomy.term_taxonomy_id) WHERE wp_term_taxonomy.taxonomy = 'category' AND wp_term_taxonomy.term_id IN(3,4) AND ( wpostmeta.meta_key = 'event_start_date' AND NOT ( concat(subst(wpostmeta.meta_value,7,4),'-',subst(wpostmeta.meta_value,4,2),'-',subst(wpostmeta.meta_value,1,2) > '2010-07-31' ) ) AND ( wpostmeta.meta_key = 'event_end_date' AND NOT ( concat(subst(wpostmeta.meta_value,7,4),'-',subst(wpostmeta.meta_value,4,2),'-',subst(wpostmeta.meta_value,1,2) < '2010-05-01' ) ) ) ORDER BY wpostmeta.meta_value ASC And, of course it returns no records. The problem I believe is in the dual reference to wpostmeta.meta_key, but how to get around that?

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  • Command Query Separation

    - by Liam McLennan
    Command query separation is a strategy, proposed by Bertrand Meyer, that each of an object’s methods should be either a command or a query. A command is an operation that changes the state of a system, and a query is an operation that returns a value. This is not the same thing as CQRS, hence why I think that CQRS is poorly named. An Example of Command Query Separation Consider a system that models books and shelves. There is a rule that a shelf may not be removed if it holds any books. One way to implement the removal is to write a method Shelf.Remove() that internally checks to make sure that the shelf is empty before removing it. If the shelf is not empty then it is not removed and an error is returned. To implement this feature following the principle of command query separation would require two methods, one to query the shelf and determine if it is empty and a second method to remove the shelf. Separating the query from the command makes the shelf class simpler to use because the state change is clear and explicit.

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  • Copy Table to Another Database

    - by Derek Dieter
    There are few methods of copying a table to another database, depending on your situation. Same SQL Server Instance If trying to copy a table to a database that is on the same instance of SQL Server, The easiest solution is to use a SELECT INTO while using the fully qualifed database names.SELECT * INTO Database2.dbo.TargetTable FROM Database1.dbo.SourceTableThis will [...]

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  • oracle select query - index on multiple columns

    - by CC
    Hello. I'm working on a sql query, and trying to optimise it, because it takes too long to execute. I have a few select and UNION between. Every select is on the same table but with different condition in WHERE clause. Basically I have allways something like : select * from A where field1 <"toto" and field2 IN (...) UNION select * from A where field1 >"toto2" and field2 =(...) UNION .... I have a index on field1 (it a date field, and field2 is a number). Now, when I do the select and if I put only WHERE field1 <'12/12/2010' it does not use the index. I'm using Toad to see the explain plain and it said: SELECT STAITEMENT Optimiser Mode = CHOOSE TABLE ACCESS FULL It is a huge table, and the index on this column is there. Any idea about this optimiser ? And why it does not uses the index ? Another question is , if I have where clause on field1 and field2 , I have to create only one index, or one index for each field ? Thanks alot.

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  • How to specify multiple values in where with AR query interface in rails3

    - by wkhatch
    Per section 2.2 of rails guide on Active Record query interface here: which seems to indicate that I can pass a string specifying the condition(s), then an array of values that should be substituted at some point while the arel is being built. So I've got a statement that generates my conditions string, which can be a varying number of attributes chained together with either AND or OR between them, and I pass in an array as the second arg to the where method, and I get: ActiveRecord::PreparedStatementInvalid: wrong number of bind variables (1 for 5) which leads me to believe I'm doing this incorrectly. However, I'm not finding anything on how to do it correctly. To restate the problem another way, I need to pass in a string to the where method such as "table.attribute = ? AND table.attribute1 = ? OR table.attribute1 = ?" with an unknown number of these conditions anded or ored together, and then pass something, what I thought would be an array as the second argument that would be used to substitute the values in the first argument conditions string. Is this the correct approach, or, I'm just missing some other huge concept somewhere and I'm coming at this all wrong? I'd think that somehow, this has to be possible, short of just generating a raw sql string.

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  • Oracle for the SQL Server DBA guides?

    - by MattK
    I am looking for a reference for a SQL Server DBA who has to come up to speed on basic Oracle 11 DBA tasks: backup, recovery, user administration, etc. There seems to be some material on the web for the reverse: Oracle - SQL Server, but the only potentially useful resource I have found in a few searches is yet to be published: http://www.amazon.com/Oracle-Database-Administration-Microsoft-Osborne/dp/0071744312 Can anyone provide references to something currently available?

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  • SQL Selecting from one table OR another then joining the two

    - by Cyprus106
    So this is interesting, and apparently beyond my SQL skillset. I need to select a particular record where an ID="0003" (or whatever) from either table1 or table2 if table1 doesn't have that record. Then I need to join table1 and table2 on a mutual field they both have (field name is Product_ID) I was playing with all sorts of variations of the following, (no, it doesn't work) but after 2 days of groping through the internet and a big SQL book I still can't figure anything out. SELECT ProductStock.Product_ID AS PSID, Products.ID AS PID, ProductStock.*, Products.* FROM ProductStock, Products LEFT JOIN (Products AS Pr) ON Pr.ID=ProductStock.Product_ID WHERE (ProductStock.ID="6003" OR Products.ID="6003")

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  • How to Truncate the Log File

    - by Derek Dieter
    Sometimes after one or more large transactions, the t-log (transaction log) will become full. In these particular cases you may receive an error message indicating the transaction log is full. In order to alleviate this issue, you need to find the names of the transaction logs on your system and then shrink them. To find the [...]

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  • Hibernate CreateSQL Query Problem

    - by Shaded
    Hello All I'm trying to use hibernates built in createsql function but it seems that it doesn't like the following query. List =hibernateSession.createSQLQuery("SELECT number, location FROM table WHERE other_number IN (SELECT f.number FROM table2 AS f JOIN table3 AS g on f.number = g.number WHERE g.other_number = " + var + ") ORDER BY number").addEntity(Table.class).list(); I have a feeling it's from the nested select statement, but I'm not sure. The inner select is used elsewhere in the code and it returns results fine. This is my mapping for the first table: <hibernate-mapping> <class name="org.efs.openreports.objects.Table" table="table"> <id name="id" column="other_number" type="java.lang.Integer"> <generator class="native"/> </id> <property name="number" column="number" not-null="true" unique="true"/> <property name="location" column="location" not-null="true" unique="true"/> </class> </hibernate-mapping> And the .java public class Table implements Serializable { private Integer id;//panel_facility private Integer number; private String location; public Table() { } public void setId(Integer id) { this.id = id; } public Integer getId() { return id; } public void setNumber(Integer number) { this.number = number; } public Integer number() { return number; } public String location() { return location; } public void setLocation(String location) { this.location = location; } } Any suggestions? Edit (Added mapping)

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  • Query with UDF works in Access but gives Undefined function in expression (Err 3085) in Excel

    - by ronwest
    I have an Access table with a date/time field. I wanted to make a composite Key field out of the date/time field and 3 other text fields in the same format as the matching Key field in another database. So I concatenated the 3 text fields and wrote a User-Defined-Function in a Module to output the date field as a string in the format "YYYYMMDD". Public Function YYYYMMDD(dteDate As Date) As String YYYYMMDD = Format(dteDate, "YYYYMMDD") End Function I can then successfully run my queries in Access and it all works fine. But when I set up some DAO code in Excel and try to run the query that works fine within Access... db.Execute "qryMake_tblValsDailyAccount" ...Excel gives me the "Undefined function in expression. (Error 3085)" error. To me this is a bug in Excel and/or Access, because the (Excel) client shouldn't need to know anything about the internal calculations that normally take place perfectly in the (Access) server when in isolation. Excel should send the querydef (name with no parameters) to the server, let the server do its work then receive the answers. Why does it need to get involved with a function internal to the server? Does anyone know a way around this?

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  • SQL Server query

    - by carrot_programmer_3
    Hi, I have a SQL Server DB containing a registrations table that I need to plot on a graph over time. The issue is that I need to break this down by where the user registered from (e.g. website, wap site, or a mobile application). the resulting output data should look like this... [date] [num_reg_website] [num_reg_wap_site] [num_reg_mobileapp] 1 FEB 2010,24,35,64 2 FEB 2010,23,85,48 3 FEB 2010,29,37,79 etc... The source table is as follows... UUID(int), signupdate(datetime), requestsource(varchar(50)) some smple data in this table looks like this... 1001,2010-02-2:00:12:12,'website' 1002,2010-02-2:00:10:17,'app' 1003,2010-02-3:00:14:19,'website' 1004,2010-02-4:00:16:18,'wap' 1005,2010-02-4:00:18:16,'website' Running the following query returns one data column 'total registrations' for the website registrations but I'm not sure how to do this for multiple columns unfortunatly.... select CAST(FLOOR(CAST([signupdate]AS FLOAT ))AS DATETIME) as [signupdate], count(UUID) as 'total registrations' FROM [UserRegistrationRequests] WHERE requestsource = 'website' group by CAST(FLOOR(CAST([signupdate]AS FLOAT ))AS DATETIME)

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  • Do you have a data roadmap?

    - by BuckWoody
    I often visit companies where they asked me “What is SQL Server’s Roadmap?” What they mean is that they want to know where Microsoft is going with our database products. I explain that we’re expanding not only the capacities in SQL Server but the capabilities – we’re trying to make an “information platform”, rather than just a data store. But it’s interesting when I ask the same question back. “What is your data roadmap?” Most folks are surprised by the question, thinking only about storage and archival. To them, data is data. Ah, not so. Your data is one of the most valuable, if not the most valuable asset in your organization. And you should be thinking about how you’ll acquire it, how it will be distributed, how you’ll archive it (which includes more than just backing it up) and most importantly, how you’ll leverage it. Because it’s only when data becomes information that it is truly useful. to be sure, the folks on the web that collect lots of data have a strategy for it – do you? Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • MySQL query problem

    - by Luke
    Ok, I have the following problem. I have two InnoDB tables: 'places' and 'events'. One place can have many events, but event can be created without entering place. In this case event's foreign key is NULL. Simplified structure of the tables looks as follows: CREATE TABLE IF NOT EXISTS `events` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) COLLATE utf8_bin NOT NULL, `places_id` int(9) unsigned DEFAULT NULL, PRIMARY KEY (`id`), KEY `fk_events_places` (`places_id`), ) ENGINE=InnoDB; ALTER TABLE `events` ADD CONSTRAINT `events_ibfk_1` FOREIGN KEY (`places_id`) REFERENCES `places` (`id`) ON DELETE CASCADE ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS `places` ( `id` int(9) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) COLLATE utf8_bin NOT NULL, PRIMARY KEY (`id`), ) ENGINE=InnoDB; Question is, how to construct query which contains name of the event and name of the corresponding place (or no value, in case there is no place assigned?). I am able to do it with two queries, but then I am visibly separating events which have place assigned from the ones that are without place. Help really appreciated.

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  • SQL query for the latest record for each day

    - by Mac
    I've got an Oracle 10g database with a table with a structure and content very similar to the following: CREATE TABLE MyTable ( id INTEGER PRIMARY KEY, otherData VARCHAR2(100), submitted DATE ); INSERT INTO MyTable VALUES (1, 'a', TO_DATE('28/04/2010 05:13', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (2, 'b', TO_DATE('28/04/2010 03:48', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (3, 'c', TO_DATE('29/04/2010 05:13', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (4, 'd', TO_DATE('29/04/2010 17:16', ''DD/MM/YYYY HH24:MI)); INSERT INTO MyTable VALUES (5, 'e', TO_DATE('29/04/2010 08:49', ''DD/MM/YYYY HH24:MI)); What I need to do is query the database for the latest record submitted on each given day. For example, with the above data I would expect the records with ID numbers 1 and 4 to be returned, as these are the latest each for 28 April and 29 April respectively. Unfortunately, I have little expertise as far as SQL is concerned. Could anybody possibly provide some insight as to how to achieve this? Thanks in advance!

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  • sql query selecting one name no matter how many rows it was mentioned in

    - by Baruch
    Basically what I'm trying to do is get the information from column x no matter how many times it was mentioned. means that if I have this kind of table: x | y | z ------+-------+-------- hello | one | bye hello | two | goodbye hi | three | see you so what I'm trying to do is create a query that would get all of the names that are mentions in the x column without duplicates and put it into a select list. my goal is that I would have a select list with TWO not THREE options, hello and hi this is what I have so far which isn't working. hope you guys know the answer to that: function getList(){ $options="<select id='names' style='margin-right:40px;'>"; $c_id = $_SESSION['id']; $sql="SELECT * FROM names"; $result=mysql_query($sql); $options.="<option value='blank'>-- Select something --</option>" ; while ($row=mysql_fetch_array($result)) { $name=$row["x"]; $options.="<option value='$name'>$name</option>"; } $options.= "</SELECT>"; return "$options"; } Sorry for confusing... i edited my source

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  • Advance Query with Join

    - by user1462589
    I'm trying to convert a product table that contains all the detail of the product into separate tables in SQL. I've got everything done except for duplicated descriptor details. The problem I am having all the products have size/color/style/other that many other products contain. I want to only have one size or color descriptor for all the items and reuse the "ID" for all the product which I believe is a Parent key to the Product ID which is a ...Foreign Key. The only problem is that every descriptor would have multiple Foreign Keys assigned to it. So I was thinking on the fly just have it skip figuring out a Foreign Parent key for each descriptor and just check to see if that descriptor exist and if it does use its Key for the descriptor. Data Table PI Colo Sz OTHER 1 | Blue | 5 | Vintage 2 | Blue | 6 | Vintage 3 | Blac | 5 | Simple 4 | Blac | 6 | Simple =================================== Its destination table is this =================================== DI Description 1 | Blue 2 | Blac 3 | 5 4 | 6 6 | Vintage 7 | Simple ============================= Select Data.Table Unique.Data.Table.Colo Unique.Data.Table.Sz Unique.Data.Table.Other ======================================= Then the dual part of the questions after we create all the descriptors how to do a new query and assign the product ID to the descriptors. PI| DI 1 | 1 1 | 3 1 | 4 2 | 1 2 | 3 2 | 4 By figuring out how to do this I should be able to duplicate this pattern for all 300 + columns in the product. Some of these fields are 60+ characters large so its going to save a ton of space. Do I use a Array?

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