Search Results

Search found 22224 results on 889 pages for 'point of sale'.

Page 34/889 | < Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >

  • what is the point of return in ruby?

    - by Sam
    What is the difference between return and just putting a variable such as the following: return def write_code(number_of_errors) if number_of_errors > 1 mood = "WTF" else mood = "No Problem" end mood end no return def write_code(number_of_errors) if number_of_errors > 1 mood = "WTF" else mood = puts "No Problem" end return mood end

    Read the article

  • Doing arithmetic with up to two decimal places in Python?

    - by user248237
    I have two floats in Python that I'd like to subtract, i.e. v1 = float(value1) v2 = float(value2) diff = v1 - v2 I want "diff" to be computed up to two decimal places, that is compute it using %.2f of v1 and %.2f of v2. How can I do this? I know how to print v1 and v2 up to two decimals, but not how to do arithmetic like that. The particular issue I am trying to avoid is this. Suppose that: v1 = 0.982769777778 v2 = 0.985980444444 diff = v1 - v2 and then I print to file the following: myfile.write("%.2f\t%.2f\t%.2f\n" %(v1, v2, diff)) then I will get the output: 0.98 0.99 0.00, suggesting that there's no difference between v1 and v2, even though the printed result suggests there's a 0.01 difference. How can I get around this? thanks.

    Read the article

  • Is it possible to read Fortran formatted data in Python?

    - by Werner
    I get output files from very old Fortran programs, which look like: 0.81667E+00 -0.12650E+01 -0.69389E-03 0.94381E+00 -0.11985E+01 -0.11502E+00 0.96064E+00 -0.11333E+01 -0.17616E+00 0.10202E+01 -0.12435E+01 -0.93917E-01 0.10026E+01 -0.10904E+01 -0.15108E+00 0.90516E+00 -0.11030E+01 -0.19139E+00 0.98624E+00 -0.11598E+01 -0.22970E+00 Is it possible to read this in Python and convert the numbers to "normal" floats?

    Read the article

  • Float Conversion Issue

    - by user1407570
    I have an issue after converted a float from a string, the result of my operation is null The NSLogs give the right value but vitesseMoyenne is equal to null -(void)setVitesseMoyenne:(float)uneDistanceTotale:(NSString*)unTempsTotal { //float tempEnFloat = [unTempsTotal floatValue]; NSLog(@"%@",unTempsTotal); float calculVitesseMoyenne = uneDistanceTotale / [unTempsTotal floatValue]; NSLog(@"%f",calculVitesseMoyenne); vitesseMoyenne = [NSString stringWithFormat:@"%f", calculVitesseMoyenne]; } Can you see what is wrong ?

    Read the article

  • MySQL float values jumping around on insert?

    - by dubayou
    So i have a SQL table setup as such CREATE TABLE IF NOT EXISTS `points` ( `id` int(11) NOT NULL auto_increment, `lat` float(10,6) NOT NULL, `lng` float(10,6) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM; And im inserting stuff like INSERT INTO `points` (`lat`, `lng`) VALUES ('89.123456','-12.123456'); Gives me a row with lat and lng being 89.123459 and -12.123455 Whats up?

    Read the article

  • Create all directories up to a point?

    - by Stefan Kendall
    I need to be able to build all directories up to and including the directory specified by my File object. For example, suppose I have something like this: File file = new File( "/var/a/b/c/d/" ); But only /var/ exists. I need a method that builds up to d, and I was wondering if there was a method in a java io library somewhere that does this already.

    Read the article

  • AspectJ join point with simple types

    - by Jon
    Hi! Are there defined join points in arithmetics that I can catch? Something like: int a = 4; int b = 2; int c = a + b; Can I make a pointcut that catches any one of those lines? And what context will I be able to get? I would like to add a before() to all int/float/double manipulation done in a particular method on a class, is that possible. I see in the AspectJ docs that there are defined join points for object initialization and method calls. Is declaring an int an object initialization and does the + operator count as a method call? Thanks!

    Read the article

  • JavaScript: Rounding to two decimal places. Not less than two

    - by Abs
    Hello all, I have this line of code which rounds my numbers to 2 decimal places. But the thing is I get numbers like this. 10.8, 2.4 etc. These are not my idea of 2 decimal places so how I can improve this: Math.round(price*Math.pow(10,2))/Math.pow(10,2); I want numbers like 10.80, 2.40 etc. Use of JQuery is fine with me. Thanks for any help.

    Read the article

  • How to point to jdni.properties file to set properties in Java

    - by prosseek
    I can use System.getProperties() method to set properties in Java. System.getProperties().put("java.naming.factory.initial", "fr.dyade.aaa.jndi2.client.NamingContextFactory"); System.getProperties().put("java.naming.factory.host", "localhost"); System.getProperties().put("java.naming.factory.port", "16400"); How can I get the same effect by reading the properties stored in a file? When I have a jdni.properties with the following content: java.naming.factory.initial fr.dyade.aaa.jndi2.client.NamingContextFactory java.naming.factory.host localhost java.naming.factory.port 16400 How can I teach Java to read them as properties?

    Read the article

  • Why does ghci say that 1.1 + 1.1 + 1.1 > 3.3 is True?

    - by Frerich Raabe
    I've been going through a Haskell tutorial recently and noticed this behaviour when trying some simple Haskell expressions in the interactive ghci shell: Prelude> 1.1 + 1.1 == 2.2 True Prelude> 1.1 + 1.1 + 1.1 == 3.3 False Prelude> 1.1 + 1.1 + 1.1 > 3.3 True Prelude> 1.1 + 1.1 + 1.1 3.3000000000000003 Does anybody know why that is?

    Read the article

  • Can anyone explain this strange behaviour?

    - by partizan
    Hi, guys. Here is the example with comments: class Program { // first version of structure public struct D1 { public double d; public int f; } // during some changes in code then we got D2 from D1 // Field f type became double while it was int before public struct D2 { public double d; public double f; } static void Main(string[] args) { // Scenario with the first version D1 a = new D1(); D1 b = new D1(); a.f = b.f = 1; a.d = 0.0; b.d = -0.0; bool r1 = a.Equals(b); // gives true, all is ok // The same scenario with the new one D2 c = new D2(); D2 d = new D2(); c.f = d.f = 1; c.d = 0.0; d.d = -0.0; bool r2 = c.Equals(d); // false! this is not the expected result } } So, what do you think about this?

    Read the article

  • JQuery: Floating share box like Mashable?

    - by Prashant
    I am looking for a jQuery plugin which can serve me the floating share box functionality just like mashable implement in their new design: http://mashable.com/2010/03/12/flickr-co-founders-startup-hunch-raises-10-million/. On the page above in the left side mashable has sharing options which stays on the screen when you scroll the page. I want to implement same kind of functionality in my application, using a jQuery plugin.

    Read the article

  • Why does GLSL's arithmetic functions yield so different results on the iPad than on the simulator?

    - by cheeesus
    I'm currently chasing some bugs in my OpenGL ES 2.0 fragment shader code which is running on iOS devices. The code runs fine in the simulator, but on the iPad it has huge problems and some of the calculations yield vastly different results, I had for example 0.0 on the iPad and 4013.17 on the simulator, so I'm not talking about small differences which could be the result of some rounding errors. One of the things I noticed is that, on the iPad, float1 = pow(float2, 2.0); can yield results which are very different from the results of float1 = float2 * float2; Specifically, when using pow(x, 2.0) on a variable containing a larger negative number like -8, it seemed to return a value which satified the condition if (powResult <= 0.0). Also, the result of both operations (pow(x, 2.0) as well as x*x) yields different results in the simulator than on the iPad. Used floats are mediump, but I get the same stuff with highp. Is there a simple explanation for those differences? I'm narrowing the problem down, but it takes so much time, so maybe someone can help me here with a simple explanation.

    Read the article

  • Does the pointer to free() have to point to beginning of the memory block, or can it point to the interior?

    - by Lambert
    The question is in the title... I searched but couldn't find anything. Edit: I don't really see any need to explain this, but because people think that what I'm saying makes no sense (and that I'm asking the wrong questions), here's the problem: Since people seem to be very interested in the "root" cause of all the problem rather than the actual question asked (since that apparently helps things get solved better, let's see if it does), here's the problem: I'm trying to make a D runtime library based on NTDLL.dll, so that I can use that library for subsystems other than the Win32 subsystem. So that forces me to only link with NTDLL.dll. Yes, I'm aware that the functions are "undocumented" and could change at any time (even though I'd bet a hundred dollars that wcstombs will still do the same exact thing 20 years from now, if it still exists). Yes, I know people (especially Microsoft) don't like developers linking to that library, and that I'll probably get criticized for the right here. And yes, those two points above mean that programs like chkdsk and defragmenters that run before the Win32 subsystem aren't even supposed to be created in the first place, because it's literally impossible to link with anything like kernel32.dll or msvcrt.dll and still have NT-native executables, so we developers should just pretend that those stages are meant to be forever out of our reaches. But no, I doubt that anyone here would like me to paste a few thousand lines of code and help me look through them and try to figure out why memory allocations that aren't failing are being rejected by the source code I'm modifying. So that's why I asked about a different problem than the "root" cause, even though that's supposedly known to be the best practice by the community. If things still don't make sense, feel free to post comments below! :)

    Read the article

  • Double multiplied by 100 and then cast to long is giving wrong value

    - by xyz
    I have the following code: Double i=17.31; long j=(long) (i*100); System.out.println(j); O/P : 1730 //Expected:1731 Double i=17.33; long j=(long) (i*100); System.out.println(j); O/P : 1732 //Expected:1733 Double i=17.32; long j=(long) (i*100); System.out.println(j); O/P : 1732 //Expected:1732{As expected} Double i=15.33; long j=(long) (i*100); System.out.println(j); O/P : 1533 //Expected:1533{as Expected} I have tried to Google but unable to find reason.I am sorry if the question is trivial.

    Read the article

  • Understanding C++ pointers (when they point to a pointer)

    - by Stephano
    I think I understand references and pointers pretty well. Here is what I (think I) know: int i = 5; //i is a primitive type, the value is 5, i do not know the address. int *ptr; //a pointer to an int. i have no way if knowing the value yet. ptr = &i; //now i have an address for the value of i (called ptr) *ptr = 10; //go get the value stored at ptr and change it to 10 Please feel free to comment or correct these statements. Now I'm trying to make the jump to arrays of pointers. Here is what I do not know: char **char_ptrs = new char *[50]; Node **node_ptrs = new Node *[50]; My understanding is that I have 2 arrays of pointers, one set of pointers to chars and one to nodes. So if I wanted to set the values, I would do something like this: char_ptrs[0] = new char[20]; node_ptrs[0] = new Node; Now I have a pointer, in the 0 position of my array, in each respective array. Again, feel free to comment here if I'm confused. So, what does the ** operator do? Likewise, what is putting a single * next to the instantiation doing (*[50])? (what is that called exactly, instantiation?)

    Read the article

  • WinMain not called before main (C/C++ Program Entry Point Issue)

    - by BT
    I was under the impression that this code #include <windows.h> #include <stdio.h> int WINAPI WinMain (HINSTANCE hInstance, HINSTANCE hPrevInstance, PSTR szCmdLine, int iCmdShow) { printf("WinMain\n"); return 0; } int main() { printf("main\n"); return 0; } would output WinMain, but of course nothing ever works how you expects. Anyways, could somebody please tell me how to get this program to run WinMain first (I do have a reason for using both). I'm running windows 7 with mingw if that helps anything.

    Read the article

  • Check the code n point the mistake

    - by Vibha
    here is the code: Ext.onReady(function(){ alert("inside onReady"); Ext.QuickTips.init(); var employee = Ext.data.Record.create([ {name:'firstname'}, {name:'lastname'}]); var myReader = new Ext.data.JsonReader({ root:"EmpInfo", },employee); var store = new Ext.data.JsonStore({ id:'ID' ,root:'EmpInfo' ,totalProperty:'totalCount' ,url:'test.php' ,autoLoad:true ,fields:[ {name:'firstname', type:'string'} ,{name:'lastname', type:'string'} ] }); var myPanel = new Ext.grid.GridPanel({ store: store ,columns:[{ dataIndex:'firstname' ,header:'First Name' ,width:139 },{ dataIndex:'lastname' ,header:'Middle Name' ,width:139 } ] }); var myWindow = new Ext.Window({ width:300, height:300, layout:'fit', closable:false, resizable:false, items:[myPanel] }); myWindow.show(); }); And php code is: true, "data" = array( "firstname" = "ABC" , "lastname" = "MNO") ); $_SESSION["err"] = isset($_SESSION["err"]) ? !$_SESSION["err"] : true; header("Content-Type: application/json"); echo json_encode($o); ? I want to print the values ABC and MNO in the grid panel. i'm using extjs 2.3. please help me out. Thanks

    Read the article

< Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >