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• struct assignment operator on arrays

  - by Django fan

  Suppose I defined a structure like this: struct person { char name [10]; int age; }; and declared two person variables: person Bob; person John; where Bob.name = "Bob", Bob.age = 30 and John.name = "John",John.age = 25. and I called Bob = John; struct person would do a Memberwise assignment and assign Johns's member values to Bob's. But arrays can't assign to arrays, so how does the assignment of the "name" array work?

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• Can nested attributes be used in combination with inheritance?

  - by FoxDemon

  I have the following classes: Project Person Person Developer Person Manager In the Project model I have added the following statements: has_and_belongs_to_many :people accepts_nested_attributes_for :people And of course the appropriate statements in the class Person. How can I add an Developer to a Project through the nested_attributes method? The following does not work: @p.people_attributes = [{:name => "Epic Beard Man", :type => "Developer"}] @p.people => [#<Person id: nil, name: "Epic Beard Man", type: nil>] As you can see the type attributes is set to nil instead of Developer.

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• NSPredicate by NSManagedObject for many-to-one lookups

  - by niklassaers

  Hi guys, I've got the scenario with two NSManagedObjects, Arm and Person. Between them is a many-to-one relationship Person.arms and inverse Arm.owner. I'd like to write a simple NSPredicate where I've got the NSManagedObject *arm and I'd like to fetch the NSManagedObject *person that this arm belongs to. I could make a textual representation and look for that, but is there a better way where I can look it up by identity? Something like this perhaps? NSEntityDescription *person = [NSEntityDescription entityForName:@"Person" inManagedObjectContext:MOC]; NSPredicate *personPredicate = [NSPredicate predicateWithFormat:@"%@ IN arms", arm]; Cheers Nik

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• Setting the initial value of a property when using DataContractSerializer

  - by Eric

  If I am serializing and later deserializing a class using DataContractSerializer how can I control the initial values of properties that were not serialized? Consider the Person class below. Its data contract is set to serialize the FirstName and LastName properties but not the IsNew property. I want IsNew to initialize to TRUE whether a new Person is being instantiate as a new instance or being deserialized from a file. This is easy to do through the constructor, but as I understand it DataContractSerializer does not call the constructor as they could require parameters. [DataContract(Name="Person")] public class Person { [DataMember(Name="FirstName")] public string FirstName { get; set; } [DataMember(Name = "LastName")] public string LastName { get; set; } public bool IsNew { get; set; } public Person(string first, string last) { this.FirstName = first; this.LastName = last; this.IsNew = true; } }

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• Linq to NHibernate using Queryable.Where predicate

  - by Groo

  I am querying an SQLite database using LINQ to NHibernate. Person is an entity containing an Id and a Name: public class Person { public Guid Id { get; private set; } public string Name { get; private set; } } Let's say my db table contains a single person whose name is "John". This test works as expected: var query = from item in session.Linq<Person>() where (item.Name == "Mike") select item; // no such entity should exist Assert.IsFalse(query.Any()); but this one fails: var query = from item in session.Linq<Person>() select item; query.Where(item => item.Name == "Mike"); // following line actually returns the // "John" entry Assert.IsFalse(query.Any()); What am I missing?

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• Data Modeling Help - Do I add another table, change existing table's usage, or something else?

  - by StackOverflowNewbie

  Assume I have the following tables and relationships: Person - Id (PK) - Name A Person can have 0 or more pets: Pet - Id (PK) - PersonId (FK) - Name A person can have 0 or more attributes (e.g. age, height, weight): PersonAttribute _ Id (PK) - PersonId (FK) - Name - Value PROBLEM: I need to represent pet attributes, too. As it turns out, these pet attributes are, in most cases, identical to the attributes of a person (e.g. a pet can have an age, height, and weight too). How do I represent pet attributes? Do I create a PetAttribute table? PetAttribute Id (PK) PetId (FK) Name Value Do I change PersonAttribute to GenericAttribute and have 2 foreign keys in it - one connecting to Person, the other connecting to Pet? GenericAttribute Id (PK) PersonId (FK) PetId (FK) Name Value NOTE: if PersonId is set, then PetId is not set. If PetId is set, PersonId is not set. Do something else?

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• Check for Existence of a Result in Linq-to-xml

  - by NateD

  I'm using Linq-to-XML to do a simple "is this user registered" check (no security here, just making a list of registered users for a desktop app). How do I handle the result from a query like this: var people = from person in currentDoc.Descendants("Users") where (string)person.Element("User") == searchBox.Text select person; I understand the most common way to use the result would be something like foreach (var line in people){ //do something here } but what do you do if person comes back empty, which is what would happen if the person isn't registered? I've looked around on this site and on MSDN and haven't found a really clear answer yet. Extra credit: Give a good explanation of what people contains.

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• How can you query for an object using one of its properties' id

  - by James Smith

  I have two entities, say, House and People, where multiple people can live in one house. It's a unidirectional link where each Person has a field for which House they belong to, so the Person table has a column named house_id. I need to be able to return all the Person objects who belong to a certain House, but I only have the id of the house. This can be done like this: House house = houseDAO.findById(houseId); List people = session.createCriteria(Person.class).add(Restrictions.eq("house", house)).list(); But since I don't need the house, that's adding an unnecessary query. I've tried to do: session.createCriteria(Person.class).add(Restrictions.eq("house_id", houseId)).list(); But that doesn't work because house_id is not a property, it's a database column. I could just add an sql restriction, but is there a hibernate way of doing this?

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• Popuplating an NSPopupButton with the contents of two NSArrayControllers

  - by ndg

  I'm looking to populate an NSPopupButton with the contents of two NSArrayControllers. The NSArrayControllers are both bound to my Core Data Managed Object Context and represent separate entities (in this example: Person and Department). Within my NSPopupButton, I would like a list of departments, and the people that work under them. Like so: Department 1 Person 1 Person 2 Department 2 Person 3 Person 4 All departments would need to be disabled by default, meaning that users should only be able to select people listed within the dropdown. I'm lost as to how I would go about doing something like this. The concept of manually populating an NSPopupButton seems fairly trivial, but I'm a bit shaky as to best to populate the element with Core Data objects. Essentially, I'm just looking for someone to point me in the right direction. I imagine there's a right way to do this, and a number of very wrong ways.

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• JPA One to Many using JoinTable Error

  - by user553015

  I am trying to model 1:N (Person & Address) relationship using a junction table (Person_Address). 1.Person (personId PK) 2.Address (addressId PK) 3.PersonAddress ( personId, addressId composite PK, personId FK references Person, addressid FK references Address ) @Entity public class Person { @OneToMany @JoinTable( name="PersonAddress", joinColumns = @JoinColumn( name="personId"), inverseJoinColumns = @JoinColumn( name="addressId") ) public Set<Address> getAddresses() {...} ... } I encounter following error. Not able to find any solution. Caused by: org.hibernate.MappingException: Could not determine type for: com.realestate.details.Address, at table: Person, for columns: [org.hibernate.mapping.Column(address)] at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:269) at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:253) at org.hibernate.mapping.Property.isValid(Property.java:185) at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:440) at org.hibernate.mapping.RootClass.validate(RootClass.java:192) at org.hibernate.cfg.Configuration.validate(Configuration.java:1108) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1293)

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• SQL one table aggrigation

  - by Lostdrifter

  Ok, for the last few days I have been attempting to find a method to pull a very important set of information form a table that contains what I call daily counts. I have a table that is setup as follows. person|company|prod1|prod2|prod3|gen_date Each company has more then one person, and each person can have different combination of products that they have purchased. What I have been trying to figure out is a SQL statement that will list the number of people that have bought a particular product per company. So an output similar to this: Comp ABC | 13 Prod1 | 3 Prod2 | 5 Prod 3 Comp DEF | 2 Prod1 | 15 Prod2 | 0 Prod 3 Comp HIJ | 0 Prod1 | 0 Prod2 | 7 Prod 3 Currently if a person did not select a product the value being stored is NULL. Best I have right now is 3 different statements that can produce this information if run on there own. SELECT Count(person) as puchases, company FROM Sales WHERE prod1 = '1' and gendate = '3/24/2010' Group BY company

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• How to deserialize from json to ActiveRecord objects with associations?

  - by Carmine Paolino

  In my Rails application there is a model that has some has_one associations (this is a fabricated example): class Person::Admin < ActiveRecord::Base has_one :person_monthly_revenue has_one :dude_monthly_niceness accepts_nested_attributes_for :person_monthly_revenue, :dude_monthly_niceness end class Person::MonthlyRevenue < ActiveRecord::Base belongs_to :person_admin end class Dude::MonthlyNiceness < ActiveRecord::Base belongs_to :person_admin end The application talks to a backend that computes some data and returns a piece of JSON like this: { "dude_monthly_niceness": { "february": 1.1153232569518972, "october": 1.1250217200558268, "march": 1.3965786869658541, "august": 1.6293418014601631, "september": 1.4062771500697835, "may": 1.7166279693955291, "january": 1.0086401628086725, "june": 1.5711510228365859, "april": 1.5614525597326563, "december": 0.99894169970474289, "july": 1.7263264324994585, "november": 0.95044938418509506 }, "person_monthly_revenue": { "february": 10.585596551505297, "october": 10.574823016656749, "march": 9.9125274764852787, "august": 9.2111604702328922, "september": 9.7905249446675153, "may": 9.1329712474607962, "january": 10.479614016604238, "june": 9.3710235926961936, "april": 9.5897372624830304, "december": 10.052587677671438, "july": 8.9508877843925561, "november": 10.925339756096172 }, } To deserialize it, I use ActiveRecord's from_json, but instead of a Person::Admin object with all the associations in place, I get this error: >> Person::Admin.new.from_json(json) NameError: uninitialized constant Person::Admin::DudeMonthlyNiceness Am I doing something wrong? Is there a better way to deserialize data? (I can modify the backend easily)

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• In CouchDB, how to get documents limited on value in related document? In terms of SQL, how to make WHERE on JOINed table

  - by amorfis

  Crossposting from [email protected] Assume we have two kind of documents in CouchDB. Person and Car: Person: _id firstname surname position salary Car: _id person_id reg_number brand So there is one to many relationship. One person can have many cars. I can construct map function to get every person and his/her car next to each other. In such case key is array [person.id, 0] and [car.person_id, 1]. What I can't do, is limiting this view to owners of specific brand only, e.g. if I need salaries of owners of Ferrari.

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• Need a Count, but Multiple other fields

  - by user3727752

  I have a table that looks like this: person trip_id date home destination joe 1 3/10 chicago new york joe 2 4/10 chicago l.a. joe 3 5/10 chicago boston luther 4 3/12 new york chicago luther 5 3/18 new york boston I want to get a result like person trips firstDate home joe 3 3/10 chicago luther 2 3/12 new york Currently I've got Select person, count(trip_id) as trips, min(date) as firstDate from [table] group by person order by firstDate I can't figure out how to get home in there as well. Home is always unique to the person. But my DBMS doesn't know that. Is there an easy way around this problem? Appreciate it.

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• How binding each column to other data source..

  - by liran

  hello, i have datagridview and Object data source : public class Data { public general general { get; set; } public Person Person { get; set; } } public class general { public int Id { get; set; } public int Name { get; set; } } public class Person { public int Tag { get; set;} } } i want to bind first column to general.id and second to person.Tag, how i do this, its is possible to bind each column to other dataSource without add any code in data, person or general classes. maybe need to add column manually? Thanks

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• Custom Sorting (IComparer on three fields)

  - by Kave

  I have a person class with three fields, Title, Name, Gender and I would like to create a Custom Sort for it to sort it first by Title, then by Name and then by Gender ascending: public class SortPerson : IComparer { public int Compare(object x, object y) { (…) } } I know how to do this for only one variable to compare against: But How would I have to proceed with three? public class SortPerson : IComparer { int IComparer.Compare(object a, object b) { Person p1=(Person)a; Person p2=(Person)b; if (p1.Title > p2.Title) return 1; if (p1.Title < p2.Title) return -1; else return 0; } } Many Thanks,

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• The type{0} does not support direct content - WPF / XAML

  - by Levo

  Hi there: I defined in my code two classes: a "Person" class with public "Age" and "Name" property, and a "People" class that inherits from Generic.List(of T). The code for People class is as followed: Public Class People Inherits Collections.Generic.List(Of Person) ... End Class What I want to achieve is to directly initialize the People class, and add individual Person to it in XAML, i.e.: <local:People x:Key="Familty"> <local:Person Age="11" Name="John" /> <local:Person Age="12" Name="John2" /> ... </local:People> But I keep getting an error in XAML saying: The type 'People' does not support direct content. Any idea as for how to solve this problem? Thank you very much!

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• Correct way to add objects to an ArrayList

  - by ninjasense

  I am trying to add an object to an arraylist but when I view the results of the array list, it keeps adding the same object over and over to the arraylist. I was wondering what the correct way to implement this would be. public static ArrayList<Person> parsePeople(String responseData) { ArrayList<Person> People = new ArrayList<Person>(); try { JSONArray jsonPeople = new JSONArray(responseData); if (!jsonPeople.isNull(0)) { for (int i = 0; i < jsonPeople.length(); i++) { Person.add(new Person(jsonPeople.getJSONObject(i))); } } } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (Exception e) { } return People; } I have double checked my JSONArray data and made sure they are not duplicates. It seems to keep adding the first object over and over.

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• Constructors for C++ objects

  - by sasquatch

  I have class Person as following : class Person { char* name; int age; }; Now I need to add two contructors. One taking no arguments, that inserts field values to dynamically allocated resources. Second taking (char*, int) arguments initialized by initialization list. Last part is to define a destructor showing information about destroying objects and deallocating dynamically allocated resources. How to perform this task ? That's what I already have : class Person { char* name; int age; public: Person(){ this->name = new *char; this->age = new int; } Person(char* c, int i){ } };

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• how does an object knows about its parent in javascript

  - by alter

  Lets suppose I made a class called Person. var Person = function(fname){this.fname = fname;}; pObj is the object I made from this class. var pObj = new Person('top'); now I add one property to Person class, say lname. Person.prototype.lname = "Thomsom"; now pObj.lname gets me "Thomson". My question is that, when pObj didn't find the property lname in it, how does it know where to look for.

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• hibernate jpa criteriabuilder ignore case queries

  - by user373201

  How to do a like ignore case query using criteria builder. For description property I want to do something like upper(description) like '%xyz%' I have the following query CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder(); CriteriaQuery<Person> personCriteriaQuery = criteriaBuilder.createQuery(Person.class); Root<Person> personRoot = personCriteriaQuery.from(Person.class); personCriteriaQuery.select(personRoot); personCriteriaQuery.where(criteriaBuilder.like(personRoot.get(Person_.description), "%"+filter.getDescription().toUpperCase()+"%")); List<Person> pageResults = entityManager.createQuery(personCriteriaQuery).getResultList();

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• Getting the last member of a group on an intermediary M2M

  - by rh0dium

  If we look at the existing docs, what is the best way to get the last member added? This is similar to this but what I want to do is to be able to do this. group = Group.objects.get(id=1) group.get_last_member_added() #This is by ('-date_added') <Person: FOO> I think the best way is through a manager but how do you do this on an intermediary model? class Person(models.Model): name = models.CharField(max_length=128) def __unicode__(self): return self.name class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(Person, through='Membership') def __unicode__(self): return self.name class Membership(models.Model): person = models.ForeignKey(Person) group = models.ForeignKey(Group) date_joined = models.DateField() invite_reason = models.CharField(max_length=64)

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• programming help

  - by user208639

  class Person holds personal data Its constructor receives 3 parameters, two Strings representing first and last names and an int representing age public Person(String firstName, String lastName, int age) { its method getName has no parameters and returns a String with format "Lastname, Firstname" its method getAge takes no parameters and returns an int representing the current age its method birthday increases age value by 1 and returns the new age value Create the class Person and paste the whole class into the textbox below public class Person { public Person(String first, String last, int age) { getName = "Lastname, Firstname"; System.out.print(last + first); getAge = age + 1; return getAge; System.out.print(getAge); birthday = age + 1; newAge = birthday; return newAge; } } im getting errors such as "cannot find symbol - variable getName" but when i declare a variable it still not working, i also wanted to ask if i am heading in the right direction or is it all totally wrong? im using a program called BlueJ to work on.

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• Oracle Internet Directory 11gR1 11.1.1.6 Certified with E-Business Suite

  - by Elke Phelps (Oracle Development)

  Oracle E-Business Suite comes with native user authentication and management capabilities out-of-the-box. If you need more-advanced features, it's also possible to integrate it with Oracle Internet Directory and Oracle Single Sign-On or Oracle Access Manager, which allows you to link the E-Business Suite with third-party tools like Microsoft Active Directory, Windows Kerberos, and CA Netegrity SiteMinder.  For details about third-party integration architectures, see either of these article for EBS 11i and 12: In-Depth: Using Third-Party Identity Managers with E-Business Suite Release 12 In-Depth: Using Third-Party Identity Managers with the E-Business Suite Release 11i Oracle Internet Directory 11.1.1.6 is now certified with Oracle E-Business Suite Release 11i, 12.0 and 12.1.  OID 11.1.1.6 is part of Oracle Fusion Middleware 11g Release 1 Version 11.1.1.6.0, also known as FMW 11g Patchset 5.  Certified E-Business Suite releases are: EBS Release 11i 11.5.10.2 + ATG PH.H RUP 7 and higher EBS Release 12.0.6 and higher EBS Release 12.1.1 and higher Supported Configurations Oracle Internet Directory 11.1.1.5.0 can be integrated with two single sign-on solutions for EBS environments: Oracle Internet Directory and Directory Integration Platform from Fusion Middleware 11gR1 Patchset 5 (11.1.1.6.0) with Oracle Access Manager 10g (10.1.4.3) with an existing Oracle E-Business Suite system (Release 11i or 12.1.x). Oracle Internet Directory and Directory Integration Platform from Fusion Middleware 11gR1 Patchset 5 (11.1.1.6.0) with Oracle Access Manager 11gR1 (11.1.1.5) with an existing Oracle E-Business Suite system (Release 12.0.6 or higher or 12.1.x). Oracle Internet Directory (OID) and Directory Integration Platform (DIP) from Oracle Fusion Middleware 11gR1 Patchset 5  (11.1.1.6.0) with Oracle Single Sign-On Server and Oracle Delegated Administration Services Release 10g (10.1.4.3.0) with an existing Oracle E-Business Suite system (Release 11i, 12.0.6 or 12.1.x) Oracle Access Manager strongly recommended Oracle has two single sign-on solutions: Oracle Single Sign-On Server (OSSO) and Oracle Access Manager (OAM). Oracle strongly recommends that all new single sign-on implementations use Oracle Access Manager. Oracle Access Manager is the preferred solution going forward, and forms the basis of Oracle Fusion Middleware 11g. OSSO is no longer being actively developed and will not be ported to Oracle WebLogic Server. Platform certifications Oracle Internet Directory is certified to run on any operating system for which Oracle WebLogic Server 11g is certified. Refer to the Oracle Fusion Middleware 11g System Requirements for more details.For information on operating systems supported by Oracle Internet Directory and its components, refer to the Oracle Identity and Access Management 11gR1 certification matrix.Integration with Oracle Internet Directory involves components spanning several different suites of Oracle products. There are no restrictions on which platform any particular component may be installed so long as the platform is supported for that component.References Overview of Single Sign-On Integration Options for Oracle E-Business Suite Note 1388152.1 Using the Latest Oracle Internet Directory 11gR1 Patchset with Oracle Single Sign-on and Oracle E-Business Suite (Note 876539.1) Integrating Oracle E-Business Suite with Oracle Access Manager 11g using Oracle E-Business Suite AccessGate (Note 1309013.1) Integrating Oracle E-Business Suite with Oracle Access Manager 10g using Oracle E-Business Suite AccessGate (Note 975182.1) Migrating Oracle Single Sign-On 10gR3 to Oracle Access Manager 11g with Oracle E-Business Suite (Note 1304550.1) Oracle Fusion Middleware Download, Installation & Configuration Readme Oracle Fusion Middleware Installation Guide for Oracle Identity Management 11g Release 1 (11.1.1) (Part Number E12002-09) Oracle Fusion Middleware Upgrade Guide for Oracle Identity Management 11g Release 1 (11.1.1) (Part Number E10129-09) Oracle Fusion Middleware Upgrade Planning Guide 11g Release 1 (11.1.1) (Part Number E10125-06) Oracle Fusion Middleware Patching Guide 11g Release 1 (11.1.1) (Part Number E16793-12) Related Articles Understanding Options for Integrating Oracle Access Manager with E-Business Suite In-Depth: Using Third-Party Identity Managers with E-Business Suite Release 12 In-Depth: Using Third-Party Identity Managers with the E-Business Suite Release 11i Oracle Access Manager 10gR3 Certified with E-Business Suite Portal 11.1.1.4 Certified with E-Business Suite Discoverer 11.1.1.4 Certified with E-Business Suite

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• Something for the weekend - Whats the most complex query?

  - by simonsabin

  Whenever I teach about SQL Server performance tuning I try can get across the message that there is no such thing as a table. Does that sound odd, well it isn't, trust me. Rather than tables you need to consider structures. You have 1. Heaps 2. Indexes (b-trees) Some people split indexes in two, clustered and non-clustered, this I feel confuses the situation as people associate clustered indexes with sorting, but don't associate non clustered indexes with sorting, this is wrong. Clustered and non-clustered indexes are the same b-tree structure(and even more so with SQL 2005) with the leaf pages sorted in a linked list according to the keys of the index.. The difference is that non clustered indexes include in their structure either, the clustered key(s), or the row identifier for the row in the table (see http://sqlblog.com/blogs/kalen_delaney/archive/2008/03/16/nonclustered-index-keys.aspx for more details). Beyond that they are the same, they have key columns which are stored on the root and intermediary pages, and included columns which are on the leaf level. The reason this is important is that this is how the optimiser sees the world, this means it can use any of these structures to resolve your query. Even if your query only accesses one table, the optimiser can access multiple structures to get your results. One commonly sees this with a non-clustered index scan and then a key lookup (clustered index seek), but importantly it's not restricted to just using one non-clustered index and the clustered index or heap, and that's the challenge for the weekend. So the challenge for the weekend is to produce the most complex single table query. For those clever bods amongst you that are thinking, great I will just use lots of xquery functions, sorry these are the rules. 1. You have to use a table from AdventureWorks (2005 or 2008) 2. You can add whatever indexes you like, but you must document these 3. You cannot use XQuery, Spatial, HierarchyId, Full Text or any open rowset function. 4. You can only reference your table once, i..e a FROM clause with ONE table and no JOINs 5. No Sub queries. The aim of this is to show how the optimiser can use multiple structures to build the results of a query and to also highlight why the optimiser is doing that. How many structures can you get the optimiser to use? As an example create these two indexes on AdventureWorks2008 create index IX_Person_Person on Person.Person (lastName, FirstName,NameStyle,PersonType) create index IX_Person_Person on Person.Person(BusinessentityId,ModifiedDate)with drop_existing    select lastName, ModifiedDate   from Person.Person  where LastName = 'Smith' You will see that the optimiser has decided to not access the underlying clustered index of the table but to use two indexes above to resolve the query. This highlights how the optimiser considers all storage structures, clustered indexes, non clustered indexes and heaps when trying to resolve a query. So are you up to the challenge for the weekend to produce the most complex single table query? The prize is a pdf version of a popular SQL Server book, or a physical book if you live in the UK.  

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