Search Results

Search found 30258 results on 1211 pages for 'open ended'.

Page 340/1211 | < Previous Page | 336 337 338 339 340 341 342 343 344 345 346 347  | Next Page >

  • Release another user's lock obtained with sp_getapplock on SQL Server

    - by joshperry
    We have a system that uses sp_getapplock to create an exclusive mutex any time someone opens an order in the GUI. This is used to prevent multiple people from making changes to an order simultaneously. Sometimes people will open an order and go home, leaving it open. This effectively blocks anyone from being able to make changes to the order. I then get emails, calls and end up doing a kill <spid> in enterprise manager. Obviously I've gotten sick of this and want to make a quick self-service webform. The main problem I've run into is that kill requires sysadmin privileges, which I do not want to give to the user that the our website runs as. I have tried sp_releaseapplock but this doesn't let you release another user's lock (even when calling it as a sysadmin). So, finally my question; does anyone know of an alternative method to release a lock that was obtained by another user using sp_getapplock?

    Read the article

  • sharpziplib + Whenever i try to add a file to existing archive, it overwrites previous contents

    - by schmoopy
    I am trying to add files to an existing zip file. Whenever i do, the new one contains the new list of files im passing in, but all of the previous ones are wiped out. I have also tried the code here: http://stackoverflow.com/questions/1356003/c-sharpziplib-adding-file-to-existing-archive -- same results Any idea why i cannot add files to an existing zip while maintaining the previous files? Here is the code: public static void AddFileToZip(string currentZipPath, List<string> files, bool includeFullPathInEntry, int compressionLevel) { ZipOutputStream zipStrm = new ZipOutputStream(File.Open(currentZipPath, FileMode.Open, FileAccess.ReadWrite)); zipStrm.SetLevel(compressionLevel); foreach (string str in files) { string entryName = str; if (!includeFullPathInEntry) entryName = new FileInfo(str).Name; ZipEntry entry = new ZipEntry(entryName); zipStrm.PutNextEntry(entry); Byte[] b = File.ReadAllBytes(str); zipStrm.Write(b, 0, b.Length); } zipStrm.Finish(); zipStrm.Close(); }

    Read the article

  • ASP.NET Windows Authentication

    - by Jason M
    Hi All I have an ASP.NET website set up using Windows authentication. Each time I open IE and try to access the webpage I get a windows authentication screen. Once I have logged in I can see the website fine. My problem is that every time I open a new IE browser I have to re-enter my username and password. I have heard about thew double hop issue, is this what it could be. If so how many ip fix this. Any ideas how i can stop this box showing up each time? I have ticked the "remember my username/password" tick box but still no joy. I am using Windows Server 2003, IIS 6.0 and .NET 4.0. Thanks JM

    Read the article

  • Need PHP script to decompress and loop through zipped file.

    - by Jim H.
    I am using a fairly straight-forward script to open and parse several xml files that are gzipped. I also need to do the same basic operation with a ZIP file. It seems like it should be simple, but I haven't been able to find what looked like equivalent code anywhere. Here is the simple version of what I am already doing: $import_file = "source.gz"; $sfp = gzopen($import_file, "rb"); ///// OPEN GZIPPED data while ($string = gzread($sfp, 4096)) { //Loop through the data /// Parse Output And Do Stuff with $string } gzclose($sfp); What would do the same thing for a zipped file?

    Read the article

  • Creating excel template 2003 in C# on a machine with both 2003 and 2007 installed.

    - by Ragha J
    I have both 2003 and 2007 Excel versions installed on my machine. The current source code uses Office11 (2003) interop assembly Microsoft.Office.Interop.Excel.dll to create the Excel template. When I create the template and open in Excel 2007, it opens perfectly. The same template when I open in 2003 I get the message "File format is not valid". _excel = new Excel.Application(); _workbooks = _excel.Workbooks; _excel.Visible = false; _excel.DisplayAlerts = false; // create and add a workbook with 1 worksheet named "Sheet1" _workbook = _workbooks.Add(Excel.XlWBATemplate.xlWBATWorksheet); _sheet = (Excel.Worksheet)_workbook.ActiveSheet;

    Read the article

  • Emacs: annoying Flymake dialog box.

    - by baol
    Hello I have the following lines in my ~/.emacs.d/init.el (custom-set-variables '(flymake-allowed-file-name-masks (quote ( ("\\.cc\\'" flymake-simple-make-init) ("\\.cpp\\'" flymake-simple-make-init))))) (add-hook 'find-file-hook 'flymake-find-file-hook) When I open a cc/cpp file that has a Makefile with the following content in the same folder I get proper on-the-fly compilation and error reporting (Flymake will check the syntax and report errors and warnings during code editing) .PHONY: check-syntax check-syntax: $(CXX) -Wall -Wextra -pedantic -fsyntax-only $(CHK_SOURCES) The problem is that when I open a .cc file that has no corresponding Makefile i get an annoying dialog box that warns me about flymake being disabled for every file opened. Is there some hook I can use to disable that warning? Can you provide sample elisp code and explanation on how you found the proper hook?

    Read the article

  • XML url link in Flash

    - by Vickyboy
    Hi, I am new to XML and am having a small problem in Flash. I have a number of buttons. Each of these buttons need to open up a different URL which is in a xml file (I have added only one button for now (banstead), as I wasn´t sure how to add more). My XML: <?xml version="1.0" encoding="utf-8"?> <banstead targ="_self" href="http://www.marca.com"> </banstead> My AS: weblinkXML = new XML(); weblinkXML.ignoreWhite = true; weblinkXML.load("xml/counties.xml"); weblinkXML.onLoad = function (success) { var url = weblinkXML.firstChild.attributes.href; banstead.onRelease = function () { getURL(weblinkXML.url); } } For some reason when I test the movie and click on the button it doesn´t open the URL I requested. Appreciate any help

    Read the article

  • Good implementations of reinforced learning?

    - by Paperino
    For an ai-class project I need to implement a reinforcement learning algorithm which beats a simple game of tetris. The game is written in Java and we have the source code. I know the basics of reinforcement learning theory but was wondering if anyone in the SO community had hands on experience with this type of thing. What would your recommended readings be for an implementation of reinforced learning in a tetris game? Are there any good open source projects that accomplish similar things that would be worth checking out? Thanks in advanced Edit: The more specific the better, but general resources about the subject are welcomed. Follow up: Thought it would be nice if I posted a followup. Here's the solution (code and writeup) I ended up with for any future students :). Paper / Code

    Read the article

  • python coockie,request another page

    - by polovinamozga
    #!/usr/bin/python # -*- coding: utf-8 -*- import urllib2 import urllib import httplib import Cookie import cookielib Login = 'user' Password = 'password' Domain = 'inbox.ru' Auth = 'https://auth.mail.ru/cgi-bin/auth' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'Login' : Login, 'Domain' :Domain, 'Password' : Password }) opener.open('https://auth.mail.ru/cgi-bin/auth', login_data) resp = opener.open('https://auth.mail.ru/cgi-bin/auth').read() print resp.decode('cp1251') #output page in cp1251 When script sucessfully executed i see in print resp.decode('cp1251') my page with auth. But when a try to request another page for example http://my.mail.ru i see autorization request. How i can use cookie with another page?

    Read the article

  • Django : presenting a form very different from the model and with multiple field values in a Django-

    - by sebpiq
    Hi ! I'm currently doing a firewall management application for Django, here's the (simplified) model : class Port(models.Model): number = models.PositiveIntegerField(primary_key=True) application = models.CharField(max_length=16, blank=True) class Rule(models.Model): port = models.ForeignKey(Port) ip_source = models.IPAddressField() ip_mask = models.IntegerField(validators=[MaxValueValidator(32)]) machine = models.ForeignKey("vmm.machine") What I would like to do, however, is to display to the user a form for entering rules, but with a very different organization than the model : Port 80 O Not open O Everywhere O Specific addresses : --------- delete field --------- delete field + add address field Port 443 ... etc Where Not open means that there is no rule for the given port, Everywhere means that there is only ONE rule (0.0.0.0/0) for the given port, and with specific addresses, you can add as many addresses as you want (I did this with JQuery), which will make as many rules. Now I did a version completely "handmade", meaning that I create the forms entirely in my templates, set input names with a prefix, and parse all the POSTed stuff in my view (which is quite painful, and means that there's no point in using a web framework). I also have a class which aggregates the rules together to easily pre-fill the forms with the informations "not open, everywhere, ...". I'm passing a list of those to the template, therefore it acts as an interface between my model and my "handmade" form : class MachinePort(object): def __init__(self, machine, port): self.machine = machine self.port = port @property def fully_open(self): for rule in self.port.rule_set.filter(machine=self.machine): if ipaddr.IPv4Network("%s/%s" % (rule.ip_source, rule.ip_mask)) == ipaddr.IPv4Network("0.0.0.0/0"): return True else : return False @property def partly_open(self): return bool(self.port.rule_set.filter(machine=self.machine)) and not self.fully_open @property def not_open(self): return not self.partly_open and not self.fully_open But all this is rather ugly ! Do anyone of you know if there is a classy way to do this ? In particular with the form... I don't know how to have a form that can have an undefined number of fields, neither how to transform these fields into Rule objects (because all the rule fields would have to be gathered from the form), neither how to save multiple objects... Well I could try to hack into the Form class, but seems like too much work for such a special case. Is there any nice feature I'm missing ?

    Read the article

  • Opening pop up in Joomla

    - by user258100
    I am trying to have people be able to open HTML widgets by clicking on a button in my Joomla page. All the widgets are different sizes. The code is entered as HTML in Jumi. Currently I have the action set to: "On click open in new window without browser navigation." The problem is this this always opens in a full screen size with the widget showing up in a corner. How do I control the size of this new window for each widget? Thanks

    Read the article

  • EXcel VBA : Excel Macro to create table in a PowerPoint

    - by Balaji.N.S
    Hi friends, My requirement is I have a Excel which contains some data. I would like to select some data from the excel and open a PowerPoint file and Create Table in PowerPoint and populate the data in to it Right now I have succeeded in collecting the data from excel opening a PowerPoint file through Excel VBA Code. Code for Opening the PowerPoint from Excel. Set objPPT = CreateObject("Powerpoint.application") objPPT.Visible = True Dim file As String file = "C:\Heavyhitters_new.ppt" Set pptApp = CreateObject("PowerPoint.Application") Set pptPres = pptApp.Presentations.Open(file) Now how do I create the table in PowerPoint from Excel and populate the data. Timely help will be very much appreciated. Thanks in advance,

    Read the article

  • Inline & not-inline

    - by anon
    Suppose I have: struct Vec3 { double x; double y; double z; } ; inline double dot(const Vec3& lhs, const Vec3& rhs) { return lhs.x * rhs.x + lhs.y * rhs.y + lhs.z * rhs.z ; } Is it possible to have "dot" also exist in a non-inlined version, so that it can be in the *.so , so that when I dl open it I can call it? I.e. I want files that include the above header to use the inlined version, but I also want the function to exist in a *.so, so I can dl open it and call it dynamically.

    Read the article

  • How to get full control of umask/PAM/permissions?

    - by plua
    OUR SITUATION Several people from our company log in to a server and upload files. They all need to be able to upload and overwrite the same files. They have different usernames, but are all part of the same group. However, this is an internet server, so the "other" users should have (in general) just read-only access. So what I want to have is these standard permissions: files: 664 directories: 771 My goal is that all users do not need to worry about permissions. The server should be configured in such a way that these permissions apply to all files and directories, newly created, copied, or over-written. Only when we need some special permissions we'd manually change this. We upload files to the server by SFTP-ing in Nautilus, by mounting the server using sshfs and accessing it in Nautilus as if it were a local folder, and by SCP-ing in the command line. That basically covers our situation and what we aim to do. Now, I have read many things about the beautiful umask functionality. From what I understand umask (together with PAM) should allow me to do exactly what I want: set standard permissions for new files and directories. However, after many many hours of reading and trial-and-error, I still do not get this to work. I get many unexpected results. I really like to get a solid grasp of umask and have many question unanswered. I will post these questions below, together with my findings and an explanation of my trials that led to these questions. Given that many things appear to go wrong, I think that I am doing several things wrong. So therefore, there are many questions. NOTE: I am using Ubuntu 9.10 and therefore can not change the sshd_config to set the umask for the SFTP server. Installed SSH OpenSSH_5.1p1 Debian-6ubuntu2 < required OpenSSH 5.4p1. So here go the questions. 1. DO I NEED TO RESTART FOR PAM CHANGS TO TAKE EFFECT? Let's start with this. There were so many files involved and I was unable to figure out what does and what does not affect things, also because I did not know whether or not I have to restart the whole system for PAM changes to take effect. I did do so after not seeing the expected results, but is this really necessary? Or can I just log out from the server and log back in, and should new PAM policies be effective? Or is there some 'PAM' program to reload? 2. IS THERE ONE SINGLE FILE TO CHANGE THAT AFFECTS ALL USERS FOR ALL SESSIONS? So I ended up changing MANY files, as I read MANY different things. I ended up setting the umask in the following files: ~/.profile -> umask=0002 ~/.bashrc -> umask=0002 /etc/profile -> umask=0002 /etc/pam.d/common-session -> umask=0002 /etc/pam.d/sshd -> umask=0002 /etc/pam.d/login -> umask=0002 I want this change to apply to all users, so some sort of system-wide change would be best. Can it be achieved? 3. AFTER ALL, THIS UMASK THING, DOES IT WORK? So after changing umask to 0002 at every possible place, I run tests. ------------SCP----------- TEST 1: scp testfile (which has 777 permissions for testing purposes) server:/home/ testfile 100% 4 0.0KB/s 00:00 Let's check permissions: user@server:/home$ ls -l total 4 -rwx--x--x 1 user uploaders 4 2011-02-05 17:59 testfile (711) ---------SSH------------ TEST 2: ssh server user@server:/home$ touch anotherfile user@server:/home$ ls -l total 4 -rw-rw-r-- 1 user uploaders 0 2011-02-05 18:03 anotherfile (664) --------SFTP----------- Nautilus: sftp://server/home/ Copy and paste newfile from client to server (777 on client) TEST 3: user@server:/home$ ls -l total 4 -rwxrwxrwx 1 user uploaders 3 2011-02-05 18:05 newfile (777) Create a new file through Nautilus. Check file permissions in terminal: TEST 4: user@server:/home$ ls -l total 4 -rw------- 1 user uploaders 0 2011-02-05 18:06 newfile (600) I mean... WHAT just happened here?! We should get 644 every single time. Instead I get 711, 777, 600, and then once 644. And the 644 is only achieved when creating a new, blank file through SSH, which is the least probable scenario. So I am asking, does umask/pam work after all? 4. SO WHAT DOES IT MEAN TO UMASK SSHFS? Sometimes we mount a server locally, using sshfs. Very useful. But again, we have permissions issues. Here is how we mount: sshfs -o idmap=user -o umask=0113 user@server:/home/ /mnt NOTE: we use umask = 113 because apparently, sshfs starts from 777 instead of 666, so with 113 we get 664 which is the desired file permission. But what now happens is that we see all files and directories as if they are 664. We browse in Nautilus to /mnt and: Right click - New File (newfile) --- TEST 5 Right click - New Folder (newfolder) --- TEST 6 Copy and paste a 777 file from our local client --- TEST 7 So let's check on the command line: user@client:/mnt$ ls -l total 8 -rw-rw-r-- 1 user 1007 3 Feb 5 18:05 copyfile (664) -rw-rw-r-- 1 user 1007 0 Feb 5 18:15 newfile (664) drw-rw-r-- 1 user 1007 4096 Feb 5 18:15 newfolder (664) But hey, let's check this same folder on the server-side: user@server:/home$ ls -l total 8 -rwxrwxrwx 1 user uploaders 3 2011-02-05 18:05 copyfile (777) -rw------- 1 user uploaders 0 2011-02-05 18:15 newfile (600) drwx--x--x 2 user uploaders 4096 2011-02-05 18:15 newfolder (711) What?! The REAL file permissions are very different from what we see in Nautilus. So does this umask on sshfs just create a 'filter' that shows unreal file permissions? And I tried to open a file from another user but the same group that had real 600 permissions but 644 'fake' permissions, and I could still not read this, so what good is this filter?? 5. UMASK IS ALL ABOUT FILES. BUT WHAT ABOUT DIRECTORIES? From my tests I can see that the umask that is being applied also somehow influences the directory permissions. However, I want my files to be 664 (002) and my directories to be 771 (006). So is it possible to have a different umask for directories? 6. PERHAPS UMASK/PAM IS REALLY COOL, BUT UBUNTU IS JUST BUGGY? On the one hand, I have read topics of people that have had success with PAM/UMASK and Ubuntu. On the other hand, I have found many older and newer bugs regarding umask/PAM/fuse on Ubuntu: https://bugs.launchpad.net/ubuntu/+source/gdm/+bug/241198 https://bugs.launchpad.net/ubuntu/+source/fuse/+bug/239792 https://bugs.launchpad.net/ubuntu/+source/pam/+bug/253096 https://bugs.launchpad.net/ubuntu/+source/sudo/+bug/549172 http://bugs.debian.org/cgi-bin/bugreport.cgi?bug=314796 So I do not know what to believe anymore. Should I just give up? Would ACL solve all my problems? Or do I have again problems using Ubuntu? One word of caution with backups using tar. Red Hat /Centos distributions support acls in the tar program but Ubuntu does not support acls when backing up. This means that all acls will be lost when you create a backup. I am very willing to upgrade to Ubuntu 10.04 if that would solve my problems too, but first I want to understand what is happening.

    Read the article

  • Opening popup links in UIWebView, possible?

    - by Jasarien
    Hey guys, I have a UIWebView which I'm using as an embedded browser within my app. I've noticed that links in webpages that open new windows are ignored without any call into my code. I've tried breakpointing on - (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType and then selecting a link that would open a popup window, and the breakpoint is never hit. Is there anything I can do to intercept that selection of the popup link and get the URL and just load it normally? I'm not interested in displaying a popup window in the app itself, I just want the URL of whatever is going to be loaded in the popup window to load in the main webview itself. Is this possible? Thanks!

    Read the article

  • Number of lines in csv.DictReader

    - by Alan Harris-Reid
    Hi there, I have a csv DictReader object (using Python 3.1), but I would like to know the number of lines/rows contained in the reader before I iterate through it. Something like as follows... myreader = csv.DictReader(open('myFile.csv', newline='')) totalrows = ? rowcount = 0 for row in myreader: rowcount +=1 print("Row %d/%d" % (rowcount,totalrows)) I know I could get the total by iterating through the reader, but then I couldn't run the 'for' loop. I could iterate through a copy of the reader, but I cannot find how to copy an iterator. I could also use totalrows = len(open('myFile.csv').readlines()) but that seems an unnecessary re-opening of the file. I would rather get the count from the DictReader if possible. Any help would be appreciated. Alan

    Read the article

  • RuntimeException: Could not start Selenium session: Internal Server Error

    - by user79685
    I am trying to detect a midair collision problem (simultaneous editin) using selenium. So I start a selenium session A with following (Super Class) selenium = new MASSelenium(serverHost, serverPort, *iexplore, browserURL); selenium.start(); selenium.open("index.cgi"); then I try starting a different selenium session B pointing to a different browser from the superclass (Sub Class): selenium2 = new MASSelenium(getServerHost(), getServerPort(), *firefox, getBrowserURL()); selenium2.start(); selenium2.open("index.cgi"); It works fine on my local machine (behaves as expected) but then when i run this same test on a remote machine (using bamboo build tool), i get this exception: java.lang.RuntimeException: Could not start Selenium session: Internal Server Error at com.thoughtworks.selenium.DefaultSelenium.start(DefaultSelenium.java:89) at gov.baba.arc.mas.selenium.tests.SimultaneousEditingConflictDetected.setUp(SimultaneousEditingConflictDetected.java:78) Caused by: com.thoughtworks.selenium.SeleniumException: Internal Server Error at com.thoughtworks.selenium.HttpCommandProcessor.throwAssertionFailureExceptionOrError(HttpCommandProcessor.java:97) at com.thoughtworks.selenium.HttpCommandProcessor.getCommandResponseAsString(HttpCommandProcessor.java:168) at com.thoughtworks.selenium.HttpCommandProcessor.executeCommandOnServlet(HttpCommandProcessor.java:104) at com.thoughtworks.selenium.HttpCommandProcessor.doCommand(HttpCommandProcessor.java:86) Any idea why this is happening?

    Read the article

  • How to play sound in Python WITHOUT interrupting music/other sounds from playing

    - by Morlock
    I'm working on a timer in python which sounds a chime when the waiting time is over. I use the following code: from wave import open as wave_open from ossaudiodev import open as oss_open def _play_chime(): """ Play a sound file once. """ sound_file = wave_open('chime.wav','rb') (nc,sw,fr,nf,comptype, compname) = sound_file.getparams( ) dsp = oss_open('/dev/dsp','w') try: from ossaudiodev import AFMT_S16_NE except ImportError: if byteorder == "little": AFMT_S16_NE = ossaudiodev.AFMT_S16_LE else: AFMT_S16_NE = ossaudiodev.AFMT_S16_BE dsp.setparameters(AFMT_S16_NE, nc, fr) data = sound_file.readframes(nf) sound_file.close() dsp.write(data) dsp.close() It works pretty good, unless any other device is already outputing sound. How could I do basically the same (under linux) without having the prerequisite that no sound is being played? If you think the process would require an API to ensure software mixing, please suggest a method :) Thx for the support

    Read the article

  • fstream - correct error checking after output

    - by Truncheon
    What's the correct way to check for a general error when sending data to an fstream? I have the following code, which seems a bit overkill. int Saver::output() { save_file_handle.open(file_name.c_str()); if (save_file_handle.is_open()) { save_file_handle << save_str.c_str(); if (save_file_handle.bad()) { x_message("Error - failed to save file"); return 0; } save_file_handle.close(); if (save_file_handle.bad()) { x_message("Error - failed to save file"); return 0; } return 1; } else { x_message("Error - couldn't open save file"); return 0; } }

    Read the article

  • take out objects from randomizer obj c

    - by David Pollak
    hello everyone, I'm a new "developer" trying to build some iPhone app I'm making an app which gets text from a list of objects in a NSArray and then randomizes them and display one in a TextView, here's the code: - (IBAction)azione{ NSArray *myArray= [NSArray arrayWithObjects: @"Pasta",@"Pizza",@"Wait",@"Go", nil]; int length = [myArray count]; int chosen = arc4random() % length; testo.text = [myArray objectAtIndex: chosen]; } what I want to do now, is when I open the app and get a random object, to take it out from the list, so that it won't be picked again ex. I open the appI get "Pizza"Do the action againI don't get "Pizza" anymore, only "Pasta" "Wait" and "Go" What should I do ? Which code should I use ? Thanks for answers

    Read the article

  • MVC Site - Ensuring the default entry view is always correct

    - by Klaptrap
    I have a MVC site with AD authorization. This is all working fine. I publish the site to the webserver and call the site directly (http://intranet). If I have not logged in for a while (I have an authorised cookie with a 30 minute TTL), I am prompted to log-in and if successful I am redirected to the homeController's index view. This is great and as expected. If I keep the session open (browser open) and browse away from the site, if I then browse back to http://intranet, I am not challenged as I have recently authenticated but the default page is from a different controller and not the home page view. How can I stop this from happening? It cannot be a session setting as this is not a new session and the routes appear correct - they are not beng called at this point anyhow. Please MVC guru's advise....!

    Read the article

  • File Uploads with Turbogears 2

    - by William Chambers
    I've been trying to work out the 'best practices' way to manage file uploads with Turbogears 2 and have thus far not really found any examples. I've figured out a way to actually upload the file, but I'm not sure how reliable it us. Also, what would be a good way to get the uploaded files name? file = request.POST['file'] permanent_file = open(os.path.join(asset_dirname, file.filename.lstrip(os.sep)), 'w') shutil.copyfileobj(file.file, permanent_file) file.file.close() this_file = self.request.params["file"].filename permanent_file.close() So assuming I'm understanding correctly, would something like this avoid the core 'naming' problem? id = UUID. file = request.POST['file'] permanent_file = open(os.path.join(asset_dirname, id.lstrip(os.sep)), 'w') shutil.copyfileobj(file.file, permanent_file) file.file.close() this_file = file.filename permanent_file.close()

    Read the article

  • RMagick returns nil reading JPEG

    - by ysproduction
    When I try to open a JPEG format file in Rails using RMagick, it always return nil with any jpg file. Other file formats open well. $ script/console Loading development environment (Rails 2.3.4) >> require 'RMagick' >> img = Image.read("1.gif").first => 1.gif GIF 230x100 230x100+0+0 PseudoClass 256c 8-bit 2kb >> img = Image.read("1.png").first => 1.png PNG 1280x800 1280x800+0+0 DirectClass 8-bit 156kb >> img = Image.read("1.jpg").first => nil Why this happens?

    Read the article

< Previous Page | 336 337 338 339 340 341 342 343 344 345 346 347  | Next Page >