Search Results

Search found 39577 results on 1584 pages for 'temp files'.

Page 342/1584 | < Previous Page | 338 339 340 341 342 343 344 345 346 347 348 349  | Next Page >

  • Return popupmenu selection in MATLAB using one line of code

    - by Doresoom
    I have a GUI which uses a selection from a popupmenu in another callback. Is there a way to return the selected value of the popupmenu in only one line without creating any temporary variables? I've tried several solutions, but I've only managed two lines with one temporary variable: Three lines: list=get(handles.popupmenu1,'String'); val=get(handles.popupmenu1,'Value'); str=list{val}; Two lines: temp=get(handles.popupmenu1,{'String','Value'}); str=temp{1}{temp{2}}; Can anyone shave it down to one? PS, It's a dynamic menu, so I can't just use get(handles.popupmenu1,'Value') and ignore the string component altogether.)

    Read the article

  • cross-platform frameworks for storage + metadata?

    - by Jason S
    I don't quite know what to use for terminology, so bear with me... Are there any cross-platform frameworks out there that facilitate a kind of "virtual file storage" to encapsulate adding files along with a database of metadata? I'm thinking about something along the lines of iTunes or iPhoto, where the program manages a whole bunch of files (in those cases audio or image files) and has a database of metadata so you can organize/find those files easily. I'd like to cobble together something along those lines for files in general. edit: I am hesitant to store files in a database alone, e.g. MySQL, as there would be potentially tens of gigabytes in my application (this issue has been mentioned in several SO posts, see this one that gives several links to others). I'm looking at CouchDB though and maybe it has promise....

    Read the article

  • evaluation strategy examples

    - by Boontz
    Assuming the language supports these evaluation strategies, what would be the result for call by reference, call by name, and call by value? void swap(int a; int b) { int temp; temp = a; a = b; b = temp; } int i = 3; int A[5]; A[3] = 4; swap (i, A[3]);

    Read the article

  • How to select number of lines from large text files?

    - by MiNdFrEaK
    I was wondering how to select number of lines from a certain text file. As an example: I have a text file containing the following lines: branch 27 : rect id 23400 rect: -115.475609 -115.474907 31.393650 31.411301 branch 28 : rect id 23398 rect: -115.474907 -115.472282 31.411301 31.417351 branch 29 : rect id 23396 rect: -115.472282 -115.468033 31.417351 31.427151 branch 30 : rect id 23394 rect: -115.468033 -115.458733 31.427151 31.438181 Non-Leaf Node: level=1 count=31 address=53 branch 0 : rect id 42 rect: -115.768539 -106.251556 31.425039 31.717550 branch 1 : rect id 50 rect: -109.559479 -106.009361 31.296721 31.775299 branch 2 : rect id 51 rect: -110.937401 -106.226143 31.285870 31.771971 branch 3 : rect id 54 rect: -109.584412 -106.069092 31.285240 31.775230 branch 4 : rect id 56 rect: -109.570961 -106.000954 31.296721 31.780769 branch 5 : rect id 58 rect: -115.806213 -106.366188 31.400450 31.687519 branch 6 : rect id 59 rect: -113.173859 -106.244057 31.297440 31.627750 branch 7 : rect id 60 rect: -115.811478 -106.278252 31.400450 31.679470 branch 8 : rect id 61 rect: -109.953888 -106.020111 31.325319 31.775270 branch 9 : rect id 64 rect: -113.070969 -106.015968 31.331841 31.704750 branch 10 : rect id 68 rect: -113.065689 -107.034576 31.326300 31.770809 branch 11 : rect id 71 rect: -112.333344 -106.059860 31.284081 31.662920 branch 12 : rect id 73 rect: -115.071083 -106.309677 31.267879 31.466850 branch 13 : rect id 74 rect: -116.094414 -106.286308 31.236290 31.424770 branch 14 : rect id 75 rect: -115.423264 -106.286308 31.229691 31.415510 branch 15 : rect id 76 rect: -116.111656 -106.313110 31.259390 31.478300 branch 16 : rect id 77 rect: -116.247467 -106.309677 31.240231 31.451799 branch 17 : rect id 78 rect: -116.170792 -106.094543 31.156429 31.391781 branch 18 : rect id 79 rect: -116.225723 -106.292709 31.239960 31.442850 branch 19 : rect id 80 rect: -116.268013 -105.769913 31.157240 31.378111 branch 20 : rect id 82 rect: -116.215424 -105.827202 31.198441 31.383421 branch 21 : rect id 83 rect: -116.095734 -105.826439 31.197460 31.373819 branch 22 : rect id 84 rect: -115.423264 -105.815018 31.182640 31.368891 branch 23 : rect id 85 rect: -116.221527 -105.776512 31.160931 31.389830 branch 24 : rect id 86 rect: -116.203369 -106.473831 31.168350 31.367611 branch 25 : rect id 87 rect: -115.727631 -106.501587 31.189100 31.395941 branch 26 : rect id 88 rect: -116.237289 -105.790756 31.164780 31.358959 branch 27 : rect id 89 rect: -115.791344 -105.990044 31.072620 31.349529 branch 28 : rect id 90 rect: -115.736847 -106.495079 31.187969 31.376900 branch 29 : rect id 91 rect: -115.721710 -106.000130 31.160351 31.354601 branch 30 : rect id 92 rect: -115.792236 -106.000793 31.166620 31.378811 Leaf Node: level=0 count=21 address=42 branch 0 : rect id 18312 rect: -106.412270 -106.401367 31.704750 31.717550 branch 1 : rect id 18288 rect: -106.278252 -106.253387 31.520321 31.548361 I just want those lines which are in between Non-Leaf Node level=1 to Leaf Node Level=0 and also there are a lot of segments like this and I need them all.

    Read the article

  • Is there a programmatic way to transform a sequence of image files into a PDF?

    - by Salim Fadhley
    I have a sequence of JPG images. Each of the scans is already cropped to the exact size of one page. They are sequential pages of a valuable and out of print book. The publishing application requires that these pages be submitted as a single PDF file. I could take each of these images and just past them into a word-processor (e.g. OpenOffice) - unfortunately the problem here is that it's a very big book and I've got quite a few of these books to get through. It would obviously be time-consuming. This is volunteer work! My second idea was to use LaTeX - I could make a very simple document that consists of nothing more than a series of in-line image includes. I'm sure that this approach could be made to work, it's just a little on the complex side for something which seems like a very simple job. It occurred to me that there must be a simpler way - so any suggestions? I'm on Ubuntu 9.10, my primary programming language is Python, but if the solution is super-simple I'd happily adopt any technology that works.

    Read the article

  • can I prohibit users from loading swf files by AS3 / Flash Loader.load() and only allow loading imag

    - by EndangeringSpecies
    I want to have an AS3 app load images from url supplied by the user. But I don't want a malicious user to be able to load an SWF file in place of the image, such as with an altered extension "maliciousSwf.png". Well, not sure how big a security threat that is above and beyond the ability of the hacker to decompile swf, but I think that ideally such behavior should not be allowed. So, is there any way to prevent this? When people allow users to load images in their Flash apps, do they somehow guard against loading of SWF? Or is this really absolutely no big deal?

    Read the article

  • Reading Excel Files In C# Always Results In System.__ComObject?

    - by Soo
    This is the code I'm using to read an xls file: Microsoft.Office.Interop.Excel.Application excelApp = new Microsoft.Office.Interop.Excel.Application(); Microsoft.Office.Interop.Excel.Workbook excelWorkbook = excelApp.Workbooks.Open(filePath, 0, true, 5, "", "", true, Microsoft.Office.Interop.Excel.XlPlatform.xlWindows, "\t", false, false, 0, true, 1, 0); Microsoft.Office.Interop.Excel.Sheets excelSheets = excelWorkbook.Worksheets; Microsoft.Office.Interop.Excel.Worksheet excelSheet = (Microsoft.Office.Interop.Excel.Worksheet)excelSheets.get_Item(1); MessageBox.Show(excelSheet.Cells[1,1].ToString()); Which results in a message box with: System.__ComObject Not sure what's going on, I'd really appreciate any help, thanks!

    Read the article

  • What is the best approach to use different CFLAGS for the same source files?

    - by evilsocket
    Hello, i need to build the same source tree twice, 1 - with normal cflags to build the project binary 2 - with cflags plus -fPIC to build a static library that would be some sort of SDK to develop project dynamic modules. Using only one Makefile, what is the best approach to accomplish this? It would be nice to do some sort of : all: $(OBJECTS) lib_rule: $(OBJECTS) CFLAGS += -fPIC .cpp.o: $(CC) -c $< -o $@ $(CFLAGS) But obviously it can't be done. Thanks

    Read the article

  • PHP exec not working with gcc

    - by teehoo
    I just spent a few hours pulling my hair out over this. I'm trying to get gcc to compile a file from within PHP. $command = "/usr/bin/gcc /var/www/progpad/temp/tNu7rq.c -o /var/www/progpad/temp/tNu7rq.out"; exec($command, $output, $returnVal); echo $returnVal."<br />"; //returns 1 echo json_encode($output); //returns [] I'm running this on my own ubuntu server and both /var/www/progpad/ /var/www/progpad/temp/ have chmod 777 set. If I copy and paste the command string, and paste it into the terminal it works perfectly. Also if I replace the command string with something like $command = "echo test > test.txt"; Then this has no problem creating the text file. What could I possibly be doing wrong here???

    Read the article

  • what is mistakes/errors in this code c++ tell me the correction ??

    - by jeje
    hello all here in this code the compiler print error : 132 C:.... `createlist' undeclared (first use this function) (Each undeclared identifier is reported only once for each function it appears in.) and repeat it again in all calls in main function :( what's the problem ?? plzzzz help me #include<iostream> #include<string> using namespace std; template <typename T> struct Node { T num; struct Node<T> *next; // to craet list nodes void createlist(Node<T> *p) { T data; for( ; ; ) // its containue until user want to stop { cout<<"enter data number or '#' to stop\n"; cin>>data; if(data == '#') { p->next =NULL; break; } else { p->num= data; p->next = new Node<T>; p=p->next; } } } //count list to use it in sort function int countlist (Node<T> *p) { int count=0; while(p->next != NULL) { count++; p=p->next; } return count; } // sort list void sort( Node<T> *p) { Node<T> *p1, *p2; //element 1 & 2 to compare between them int i, j , n; T temp; n= countlist(p); for( i=1; i<n ; i++) { // here every loop time we put the first element in list in p1 and the second in p2 p1=p; p2=p->next; for(j=1; j<=(n-i) ; j++) { if( p1->num > p2->num) { temp=p2->num; p2->num=p1->num; p1->num=temp; } } p1= p1->next; p2= p2->next; } } //add new number in any location the user choose void insertatloc(Node<T> *p) { T n; //read new num int loc; //read the choosen location Node<T> *locadd, *newnum, *temp; cout <<" enter location you want ..! \n"; cin>>loc; locadd=NULL; //make it null to checked if there is location after read it from user ot not while(p->next !=NULL) { if( p->next==loc) { locadd=p; break; } p=p->next; } if (locadd==NULL) {cout<<" cannot find the location\n";} else //if location is right {cout<<" enter new number\n"; // new number to creat also new location for it cin>>n; newnum= new Node/*<T>*/; newnum->num=n; temp= locadd->next; locadd->next=newnum; newnum->next=temp; } locadd->num=sort(locadd); // call sort function } // display all list nodes void displaylist (Node<T> *p) { while (p->next != NULL) { cout<<" the list contain:\n"; cout<<p->num<<endl; p=p->next; } } };//end streuct int main() { cout<<"*** Welcome in Linked List Sheet 2****\n"; // defined pointer for structer Node // that value is the address of first node struct Node<int>*mynodes= new struct Node<int>; // create nodes in mynodes list cout<<"\nCreate nodes in list"; createlist(mynodes); // insert node in location insertatloc(mynodes); /* count the number of all nodes nodescount = countlist(mynodes); cout<<"\nThe number of nodes in list is: "<<nodescount;*/ // sort nodes in list sort(mynodes); // Display nodes cout<<"\nDisplay all nodes in list:\n"; displaylist(mynodes); system("pause"); return 0; }

    Read the article

  • concatenate multi values in one record without duplication

    - by mikehjun
    I have a dbf table like below which is the result of one to many join from two tables. I want to have unique zone values from one Taxlot id field. table name: input table tid ----- zone 1 ------ A 1 ------ A 1 ------ B 1 ------ C 2 ------ D 2 ------ E 3 ------ C Desirable output table table name: input table tid ----- zone 1 ------ A, B, C 2 ------ D, E 3 ------ C I got some help but couldn't make it to work. inputTbl = r"C:\temp\input.dbf" taxIdZoningDict = {} searchRows = gp.searchcursor(inputTbl) searchRow = searchRows.next() while searchRow: if searchRow.TID in taxIdZoningDict: taxIdZoningDict[searchRow.TID].add(searchRow.ZONE) else: taxIdZoningDict[searchRow.TID] = set() #a set prevents dulpicates! taxIdZoningDict[searchRow.TID].add(searchRow.ZONE) searchRow = searchRows.next() outputTbl = r"C:\temp\output.dbf" gp.CreateTable_management(r"C:\temp", "output.dbf") gp.AddField_management(outputTbl, "TID", "LONG") gp.AddField_management(outputTbl, "ZONES", "TEXT", "", "", "20") tidList = taxIdZoningDict.keys() tidList.sort() #sorts in ascending order insertRows = gp.insertcursor(outputTbl) for tid in tidList: concatString = "" for zone in taxIdZoningDict[tid] concatString = concatString + zone + "," insertRow = insertRows.newrow() insertRow.TID = tid insertRow.ZONES = concatString[:-1] insertRows.insertrow(insertRow) del insertRow del insertRows

    Read the article

  • how do you load files in windows phone 7?

    - by matt
    do you seriously have to make your own content pipeline project for every single type of file you want to load? Microsoft just seem to be pretending that the iphone doesn't exist (even though they are now paying devs to port between them). I'm trying to port my game from the iphone to winmo7, and I already have a nice asset pipeline set up for exporting textures in the exact format we want (16 bit fmts ect) I just want to be able to open a file and read it, just like I would on any other platform. I have tried System.IO.File.OpenText("atextfile.txt"), but it says that function is "RESTRICTED!!!!" I have tried just adding the txt file to the content project, setting its properties to "content" and "copy always" and then trying to open it doing this.Content.Load("atextfile.txt"); with and without the extension, says it can't find the file.

    Read the article

  • java shift elements in array

    - by Lightk3ira
    Hey I am trying to shift elements forward sending the last element in the array to data[0]. I did the opposite direction but I can't seem to find my mistake in going in this direction. Pos is users inputed shift times amount temp is the temporary holder. data is the array if(pos 0) { do { temp = data[data.length -1]; for(int i =0; i < data.length; i++) { if(i == data.length-1) { data[0] = temp; } else { data[i+1] = data[i]; } } pos--; }while(pos > 0); } Thanks.

    Read the article

  • Why is it so hard to share resource files (resx) with my Silverlight client?

    - by Jordan
    I'm trying to share a resource file (.resx file) from my web (RIA Service?Silverlight Host) to client (Silverlight) by linking the resource file into my client. When I try to access resources using the ResourceManager object I get the following error: System.Resources.MissingManifestResourceException was caught Message=Could not find any resources appropriate for the specified culture or the neutral culture. Make sure "PPCa.Modules.ProjectManager.Client.ViewModels.ResourceStrings.resources" was correctly embedded or linked into assembly "PPCa.Modules.ProjectManager.Client" at compile time, or that all the satellite assemblies required are loadable and fully signed. StackTrace: at System.Resources.ManifestBasedResourceGroveler.HandleResourceStreamMissing(String fileName) at System.Resources.ManifestBasedResourceGroveler.GrovelForResourceSet(CultureInfo culture, Dictionary`2 localResourceSets, Boolean tryParents, Boolean createIfNotExists, StackCrawlMark& stackMark) at System.Resources.ResourceManager.InternalGetResourceSet(CultureInfo requestedCulture, Boolean createIfNotExists, Boolean tryParents, StackCrawlMark& stackMark) at System.Resources.ResourceManager.InternalGetResourceSet(CultureInfo culture, Boolean createIfNotExists, Boolean tryParents) at System.Resources.ResourceManager.GetString(String name, CultureInfo culture) at System.Resources.ResourceManager.GetString(String name) at PPCa.Modules.ProjectManager.Web.Helpers.ResourceHelper.GetEnumText[TResource](ProjectStatus a_projectStatus) InnerException: Edit: When I say I was linking the resource file, I mean I am using the 'Add as Link' option when adding the existing resx file to my project.

    Read the article

  • File in binary form

    - by Abhi
    Dear All I want to write data into the file in binary form. I was trying using the mentioned below FILE *fp = fopen("binaryoutput.rgb888", "ab+"); for(int m=0; m<height; m++) { for (int n=0; n< width; n++) { temp = (pOutputImg+m*3+n*3); // here temp is a pointer to a unsigned char fprintf(fp,"%u",*temp); } } fclose(fp); I am able to get data which is strored at pOutputImg but not in binary form. Can anyone guide me the correct step.. Thanks in advance

    Read the article

< Previous Page | 338 339 340 341 342 343 344 345 346 347 348 349  | Next Page >